Answer:
-5x^3-38x^2-76x-46=0
Due to the accuracy of the tape measure Avani used, the amount of foam needed to cover the play area is
.
Answer:
The length of Due to the accuracy of the tape measure Avani used, the play area is 7.5 meters. The width of the play area is the amount of foam needed to cover the play area is 5.3 meters.
Step-by-step explanation:
Answer:
39.8
Step-by-step explanation:
edge 2022
Find the y-coordinate of the vertex point of y = -4(x - 4)(x + 17
(hope this helps) :)
please hehlp!!!!!!!!!!!!!!!!!!!!!
1. Find the missing side of each right triangle. Side [c] is the hypotenuse. Sides [a] and [b] are the legs. Round your answers to the nearest tenth if necessary. Answer with the number only, NO VARIABLE
a=5.4,b=9.2
2.Find the missing side of each right triangle. Side [c] is the hypotenuse. Sides [a] and [b] are the legs. Round your answers to the nearest tenth if necessary. Answer with the number only, NO VARIABLE *
b=7.7 ,c=15.3
3. Find the missing side of each right triangle. Side [c] is the hypotenuse. Sides [a] and [b] are the legs. Round your answers to the nearest tenth if necessary. Answer with the number only, NO VARIABLE *
a=4,c=7.2
4. Find the missing side of each right triangle. Side [c] is the hypotenuse. Sides [a] and [b] are the legs. Round your answers to the nearest tenth if necessary. Answer with the number only, NO VARIABLE *
a=6.5, b=14.7
5. Find the missing side of each right triangle. Side [c] is the hypotenuse. Sides [a] and [b] are the legs. Round your answers to the nearest tenth if necessary. Answer with the number only, NO VARIABLE *
b=8.2 , c=15.6
Answer:
I think its number 4
Step-by-step explanation:
but im not sure
Step-by-step explanation:
here is your answer hope you will enjoy
please mark me as a brainlist
thank you
A.RIGHT
B.ACUTE
C.EQUIANGULAR
D.OBTUSE
Multiply out and simplify:
(x-8) (x-7)
To expand the brackets, each term in the first bracket must be multiplied by each term in the second bracket and then simplified:
(x-8) (x-7) = (x × x) - (7 × x) - (8 × x) + (8×7)
= x² - 7x - 8x + 56
= x² - 15x + 56
Answer: x^2-15x+56
Step-by-step explanation:
1-Distribute
x(x-7)-8(x-7)
2-Distribute
x^2-7x-8(x-7)
3-Distribute
x^2-7x-8x+56
4-Combine like terms
x^2-15x+56
Find the products in simplest form.
8 5
21 16
23. 15 =
RETRY
Answer:
part A[tex] \frac{8}{21} . \: \frac{5}{16} \\ \\ \frac{5}{42} \\ \\ 0.119[/tex]
part B
[tex] \frac{12}{25} . \: \frac{15}{16} \\ \\ \frac{9}{20} \\ \\ 0.45[/tex]
Answer:
8/21 . 5/16 = 5/42
12/25 . 15/16 = 9/20
Step-by-step explanation:
16 = 2 x 8
8/21 . 5/16
= ( 8 x 5 ) / ( 21 x 16 )
= ( 8 x 5 ) / ( 21 x 2 x 8 )
= 5 / ( 21 x 2 )
= 5/42
12 = 3 x 4
15 = 3 x 5
25 = 5 x 5
16 = 4 x 4
12/25 . 15/16
= ( 3 x 4 ) / ( 5 x 5 ) . ( 3 x 5 ) / ( 4 x 4 )
= ( 3 x 4 x 3 x 5 ) / ( 5 x 5 x 4 x 4 )
= ( 3 x 3 ) / ( 5 x 4 )
= 9/20
If everything in a store is 20% off, and the discounted price of an item is $18.00, what is the regular price?
Answer:
If the REGULAR price of the t-shirt is $18, the SALE price with a 20% discount is $14.40. Hope this helps!
Step-by-step explanation:
f) create a residual plot for your data.
g) does your residual plot show that the linear model from the regression calculator is a good model?
h) using your equation estimate the gpa of a student who studies for 15 hours a week.
PLSSSSS NEED HELP
Answer: Consider the plot created from the residuals of a line of best fit for a set of data. Does the residual plot show that the line of best fit is appropriate for the data? Yes, the points have no pattern.
Step-by-step explanation:
Plz help ,me thx you
Answer:
i think it is a or c
Step-by-step explanation:
I PROMISE BRAINIEST IF YOU HELP ME
Answer:
The associative property
Step-by-step explanation:
:/ wait its u again lol
factorise the following, with steps
Answer:
Step-by-step explanation:
1) Sum = - 9
Product = -36
Factors = -12 , 3 {-12 + 3 = -9 & -12*3 = -36}
3a² - 9a - 12 = 3a² + 3a - 12a - 12
=3a(a + 1) - 12(a + 1)
= (a + 1) (3a - 12)
2) 4a² + 38a - 20 = 4a² + 40a - 2a - 20
=4a(a + 10) - 2(a + 10)
=(a + 10)(4a - 2)
3) 11a² + 30a - 9 = 11a² + 33a - 3a - 9
= 11a(a + 3) - 3(a + 3)
=(a + 3)(11a - 3)
GHD989 guys please you this code for guathmath thank you .
I will do that soon okay I will
A water tank has the shape of a horizontal cylinder with radius 1 meter and length 2 meters. If water is being pumped into the tank at a rate of 5 I cubic meters per minute, find the rate at which the water level is rising when the water is 5 C meters deep. Simplify your answer completely.
Step-by-step explanation:
The answer is dhdt=325πmmin.
With related rates, we need a function to relate the 2 variables, in this case it is clearly volume and height. The formula is:
V=πr2h
There is radius in the formula, but in this problem, radius is constant so it is not a variable. We can substitute the value in:
V=π(5m)2h
Since the rate in this problem is time related, we need to implicitly differentiate wrt (with respect to) time:
dVdt=(25m2)πdhdt
In the problem, we are given 3m3min which is dVdt. So we substitute this in:
dhdt=3m3min(25m2)π=325πmmin
Do you set the legs of an isosceles triangle equal to each other when given one leg and the other is an equation?
Answer:
Yes
Step-by-step explanation:
Both legs of an isosceles triangle are congruent so they can be made to say that one leg=the equation of the other leg.
Hel me please!
Find two points from this graph.
Answer:
-4,-8 : 8,8
Step-by-step explanation:
Fill in the blanks W Two numbers that when multiplied together gives 6 and when added together gives -7 are: and
Answer:
-1 and -6.
Step-by-step explanation:
-1 and -6
-1*-6 = 6
-1 + (-6) = -1-6= -7.
[tex]Simplify: \frac{ 5×(25)^{n+1} - 25 × (5)^{2n}}{5×(5)^{2n+3 }- (25)^{n+1}} \\ [/tex]
Correct answer please
[tex] \green{\large\underline{\sf{Solution-}}}[/tex]
Given expression is
[tex]\rm :\longmapsto\:\dfrac{5 \times {25}^{n + 1} - 25 \times {5}^{2n} }{5 \times {5}^{2n + 3} - {25}^{n + 1} } [/tex]
can be rewritten as
[tex]\rm \: = \: \dfrac{5 \times { {(5}^{2} )}^{n + 1} - {5}^{2} \times {5}^{2n} }{5 \times {5}^{2n + 3} - {( {5}^{2} )}^{n + 1} } [/tex]
We know,
[tex] \purple{\rm :\longmapsto\:\boxed{\tt{ {( {x}^{m} )}^{n} \: = \: {x}^{mn}}}} \\ [/tex]
And
[tex] \purple{\rm :\longmapsto\:\boxed{\tt{ \: \: {x}^{m} \times {x}^{n} = {x}^{m + n} \: }}} \\ [/tex]
So, using this identity, we
[tex]\rm \: = \: \dfrac{5 \times {5}^{2n + 2} - {5}^{2n + 2} }{{5}^{2n + 3 + 1} - {5}^{2n + 2} } [/tex]
[tex]\rm \: = \: \dfrac{{5}^{2n + 2 + 1} - {5}^{2n + 2} }{{5}^{2n + 4} - {5}^{2n + 2} } [/tex]
can be further rewritten as
[tex]\rm \: = \: \dfrac{{5}^{2n + 2 + 1} - {5}^{2n + 2} }{{5}^{2n + 2 + 2} - {5}^{2n + 2} } [/tex]
[tex]\rm \: = \: \dfrac{ {5}^{2n + 2} (5 - 1)}{ {5}^{2n + 2} ( {5}^{2} - 1)} [/tex]
[tex]\rm \: = \: \dfrac{4}{25 - 1} [/tex]
[tex]\rm \: = \: \dfrac{4}{24} [/tex]
[tex]\rm \: = \: \dfrac{1}{6} [/tex]
Hence,
[tex]\rm :\longmapsto\:\boxed{\tt{ \dfrac{5 \times {25}^{n + 1} - 25 \times {5}^{2n} }{5 \times {5}^{2n + 3} - {25}^{n + 1} } = \frac{1}{6} }}[/tex]
(x-y)(x-2y)+7x-10y+3
asap po please thank you po!
Answer:
Step-by-step explanation:
2. Should be 500
8. Should be 290
The rest are correct
Answer:
1. 100 good job
2. 500 round to the nearest hundred either 400 or 500. 500 is closer.
3. 9,000 good job
4. 7,800 good job
5. 250 good job
6. 4,000 good job
7. 6,800 good job
8. 290 round to the nearest 10 either 290 or 300 290 is closer
9. 400 good job
10. 8,000 good job
Step-by-step explanation:
Rounding to the nearest number is up at 5 and below for 4 and less. The same concept applies to larger numbers.
Three years after a tree was planted it was 9 feet tall. Seven years after it was planted it was 17 feet tall. a What is the yearly growth rate of the tree? b. Determine the height of the tree when it was planted.
Answer:
your answer i think is 2/3 sorry if i'm wrong
Step-by-step explanation:
How would you describe the graph for the equation |x|=1
Answer:
it would just be a DOT at positive one on a graph
8x divided by 13x
how do you do this plis give answer
Answer:
8/13
Step-by-step explanation:
8x
------
13x
The x in the numerator and denominator cancel
8/13
What letter comes after f
Answer:
g.....
Step-by-step explanation:
g.....
the letter is g
The letter g comes after the letter f.
What are Alphabets?An alphabet is a set of graphs or characters used to represent the phonemic structure of a language
The english alphabets are a, b, , c, d, e, f, g, h, i, j, k, l, m, n, o, p, q, r, s, t, u , v, w, x, y and z.
The alphabets help to form the basis of our language and communication for a lifetime.
There are twenty six letters in the english alphabets.
As we see the order of alphabets.
The letter g is next to the letter f.
They help to form the basis of our language and communication for a lifetime.
Hence, the letter g comes after the letter f.
To learn more on Alphabets click:
https://brainly.com/question/20261759
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A water tank currently contains 275 gallons of water. The amount of water in the tank will decrease at a constant rate of 15 gallons per week.
Which function can be used to find t, the total number of gallons of water in the tank after w weeks?
F t = 15w - 275
G t = -15w + 275
H t = 275w - 15
J t = -275w + 15
Answer:
I would think its C
Step-by-step explanation:
Since you are subtracting 15 from 275, it would be 275-15
i am assuming you dont need any help on the variables, so I hope this helps :)
If i am wrong, please let me know :DD
have a nice day, *insert preferred referral here*!!
The function that can be used to evaluate 't', the total number of gallons of water in the tank after w weeks is G(t) = 275 - 15w and this can be determined by using the given data.
Given :
A water tank currently contains 275 gallons of water. The amount of water in the tank will decrease at a constant rate of 15 gallons per week.The following steps can be used in order to determine the function that can be used to evaluate 't', the total number of gallons of water in the tank after w weeks:
Step 1 - Let the total number of weeks be 'w'.
Step 2 - So, the total amount of water reduced from the tank is:
= 15w
Step 3 - So, the function that can be used to evaluate 't', the total number of gallons of water in the tank after w weeks is given below:
G(t) = 275 - 15w
Therefore, the correct option is B).
For more information, refer to the link given below:
https://brainly.com/question/25834626
Plz help
A)40
B)30
C)24
Answer:
I think its 30 hope this helps and sorry if I get it wrong
Answer:
B) 30
Ok now that you have the answer......
If you have me, you want to share me.
If you share me, you no longer have me.
WHAT AM I???????
show work
please! this is due tmr
Answer:
-120
Step-by-step explanation:
subtract 45 to both sides
m/8 = -15
multiply by 8 on both sides.
with the fraction just multiply by the bottom number to make m by itself.
m = -15*8
m= -120
Answer:
-120
Step-by-step explanation:
30-45= -15
-15×8= -120
Drag up the correct symbol to make the following relationships true.
9,100
9,200
42,720
42,650
912
738
Find all rational zeros of the given polynomial function.
f(x) = x^3 + 8x^2 + 5x – 14
Answer:
x = 1, -2, -7
Step-by-step explanation:
Just factor, you got this!
Need this answer for this
Answer:
the point (0,6) is the point that is 1/6 of the way
The domen range of the function y = √(x² - 4) is _____.
Please explain with step i need explanation.
[tex] {\large\underline{\sf{Solution-}}}[/tex]
Given function is
[tex]\rm \longmapsto\:y = \sqrt{ {x}^{2} - 4} [/tex]
We know
Domain of a function is defined as set of those real values of x for which function is well defined.
So, y is defined when
[tex]\rm \longmapsto\: {x}^{2} - 4 \geqslant 0[/tex]
[tex]\rm \longmapsto\: {x}^{2} - {2}^{2} \geqslant 0[/tex]
[tex]\rm \longmapsto\: (x - 2)(x + 2) \geqslant 0[/tex]
[tex]\rm\implies \:x \leqslant - 2 \: \: or \: \: x \geqslant 2[/tex]
[tex]\rm\implies \:x \: \in \: ( - \infty , \: - 2] \: \cup \: [2, \: \infty )[/tex]
Now, To find the range of function
We know,
Range of a function is defined as set of those real values which is obtained by assigning the values to x.
So,
[tex]\rm \longmapsto\:y = \sqrt{ {x}^{2} - 4} [/tex]
On squaring both sides, we get
[tex]\rm \longmapsto\: {y}^{2} = {x}^{2} - 4[/tex]
[tex]\rm \longmapsto\: {y}^{2} + 4= {x}^{2}[/tex]
[tex]\rm \longmapsto\:x = \sqrt{ {y}^{2} + 4 } [/tex]
Now, x is defined when
[tex]\rm \longmapsto\: {y}^{2} + 4 \geqslant 0 \: which \: is \: always \: true \: \forall \: y \in \: real \: number[/tex]
But,
[tex]\rm \longmapsto\:y \geqslant 0[/tex]
Hence,
[tex]\rm\implies \:Range \: of \: function \: = [0, \: \infty )[/tex]
So, we have
[tex]\rm\implies \:Domain \: of \: function : x \: \in \: ( - \infty , \: - 2] \: \cup \: [2, \: \infty )[/tex]
and
[tex]\rm\implies \:Range \: of \: function \: = [0, \: \infty )[/tex]