Answers
Focus on vector A. Start at the base of the vector which is at (1,1)
Then notice how we have to move 3 units to the right and 2 units up to get to the tip of the vector where the arrow is located. So this is at (4,3)
The fact that we moved 3 units to the right and 2 units up means that vector A is <3, 2>
So we'll type 3 in the first box and 2 in the second box.
======================================================
We use the same idea for vector B
Start at the base and move to the tip. Doing so has us move 1 unit left and 3 units down.
Vector B = <-1, -3>
We type -1 in the first box, and -3 in the second box.
======================================================
Finally onto vector C
Start at the base (0,0). To move to the tip, we need to go 3 units left and 3 units up
Vector C = <-3, 3>
-3 goes in the first box and 3 goes in the second box
======================================================
In general, vectors are useful to tell us a specific direction in which to go. They're useful in physics to determine how exactly a force is being applied, or how a particle is moving.
Related Questions
What is velocity in science
Answers
Answer:
Velocity is the rate at which the position changes. The average velocity is the displacement or position change (a vector quantity) per time ratio.
Hope this helps! ^-^
Answer:
Velocity is the speed at which something moves in one direction.
Explanation:
Hope this helps : )!!
A 70 kg student is riding on a skateboard at 4m/s. A 60 kg student is also riding a
skateboard at 4 m/s. Which statement below demonstrates an understanding of
Newton's 1st Law of Motion?
A. Since both students are traveling at the same speed they must have the same
inertia
B. Since both students are traveling at the same speed they must have the same
mass
C. One student has more mass and therefore more inertia
Answers
Predict the energy transformation that occurs when Carson sands a piece of wood with sandpaper.
A. chemical energy to heat energy
B. heat energy to mechanical energy
C. mechanical energy to heat energy
D. mechanical energy to chemical energy
Answers
Answer:
C. Mechanical to heat i,m pretty sure
Explanation:
I took the test
Answer:
C or D
Explanation:
not really sure
A car is traveling with a velocity of 20 M/S and has a weight (mass) of 1000 kg. The car has kinetic energy calculate it
Answers
Answer:
200000 joules or 200 kilojoules
Explanation:
Kinetic energy = 1/2m(v^v)
Kinetic energy = 1/2*1000* 20^20
Kinetic energy = 500*400
Kinetic energy = 200000 joules or 200 kilojoules
Helpppp guys plsss help !
Answers
Answer:
with what? I can help but with what
Answer:
2
Explanation:
Waves do NOT carry.
A)Weight
B)Matter
C)Energy
D)Color
(Choose one)
Answers
Determine the acceleration that an unbalanced force of 28 N gives to a 6.8 kg mass.
Answers
Answer:
4.12 m/s^2
Explanation:
unbalanced force means the presence of resultant force (net force)
[tex]net \: force \: = mass \times accleration[/tex]
f = 28N
m = 6.8kg
a = ?
? = 28/6.8
= 4.1176...
approximately = 4.12 m/s^2
Consider the following debate between two students about their answer to the above question.
Student 1: I thought that whenever one object exerts a force on a second object, the second object also exerts a force that is equal in strength, but in the other direction. So even though Earth is bigger and more massive than the Moon, they still pull on each other with a gravitational force of the same strength, just in different directions.
Student 2: I disagree. I said that Earth exerts the stronger force because it is way bigger than the Moon. Because its mass is bigger, the gravitational force Earth exerts has to be bigger too. I think you are confusing Newton's third law with the law of gravity. Do you agree or disagree with either or both of the students?
Answers
Answer:
I agree with student 1
Explanation:
This is because, the magnitude of the gravitational force on both Earth and Moon depends on the product of their masses. Also, both Earth and Moon exert the same force but in opposite directions.
Student 2 is wrong because the gravitational force is the only force acting between the Earth and Moon, and from Newton's third law, it follows an action-reaction pair. But, student 2 got it wrong in the sense that the magnitude of the action and reaction forces are the same and are equal to the gravitational force.
So, the gravitational force acting on each object is the same and doesn't vary for each mass.
We should agree with the student 1.
Gravitational force:
This is to be done due to the magnitude of the force since earth and moon should be based on the masses' product. Moreover, the earth and moon exert a similar force but that should be in inverse directions. Here student 2 should be wrong because the gravitational force is that force that acted between the earth and moon. Based on this, we can say that it should be acted on each object when it is the same also it should not be changed for every mass.
Learn more about newton here: https://brainly.com/question/14379797
When are all the forces acting upon an object balanced?
Answers
Answer:
When two forces acting on an object are equal in size but act in opposite directions, we say that they are balanced forces.
Explanation:
The jogger ran 3km east.
4. Look at the bottom figure. Suppose that a car is 20 km due north of New York City. The car
travels north toward Albany until it is 100 km due north of New York City.
Answers
Answer: d
Explanation:
Which of the following tests uses calipers to assess body composition? A. skinfold test B. sit-and-reach C. arm hang D. curl-up Please select the best answer from the choices provided.
Answers
Answer:A.skinfold test
Explanation:
i just took the test
Answer:
A. Skinfold test
Explanation:
Edg 2020
Please help me with physics homework I just need help with C and D. Picture is included
Answers
Answer:
For C is B and for D is A
Explanation:
B because that's where the b car will do all the force to go up, and A because there the car doesn't have to do any force other than the natural, and it already brings that on it's own.
A metal wire has a circular cross section with radius 0.800 mm. You measure the resistivity of the wire in the following way: you connect one end of the wire to one terminal of a battery that has emf 12.0 V and negligible internal resistance. To the other terminal of the battery you connect a point along the wire so that the length of wire between the battery terminals is d. You measure the current in the wire as a function of d. The currents are small, so the temperature change of the wire is very small. You plot your results as I versus 1/d and find that the data lie close to a straight line that has slope 600 A⋅m.
Required:
What is the resistivity of the material of which the wire is made?
Answers
Answer:
The value is [tex]\rho = 4.02 *10^{-8} \ \Omega \cdot m[/tex]
Explanation:
From the question we are told that
The radius is [tex]r = 0.800 mm = 0.0008 \ m[/tex]
The voltage of the battery is [tex]emf = 12.0 V[/tex]
The slope is [tex]s = 600 \ A \cdot m[/tex]
Generally the resistance is mathematically represented as
[tex]R = \frac{\rho * d }{A }[/tex]
Generally the current is mathematically represented as
[tex]I = \frac{V}{R}[/tex]
=> [tex]I = \frac{V}{\frac{\rho * d }{A }}[/tex]
=> [tex]I = \frac{V * A }{\rho} * \frac{1}{d}[/tex]
Comparing this equation to that of a straight line we see that the slope is
[tex]s = \frac{V * A }{\rho}[/tex]
So [tex] 600 = \frac{V * A }{\rho}[/tex]
Here A is the cross-sectional area of the wire which is mathematically represented as
[tex]A = \pi r^2[/tex]
=> [tex]A = 3.142 * (0.0008 )^2[/tex]
=> [tex]A = 2.011*10^{-6} \ m^2[/tex]
So
[tex] 600 = \frac{12.0 * (2.011*10^{-6}) }{\rho}[/tex]
=> [tex]\rho = \frac{12 * 2.011*10^{-6} }{600}[/tex]
=> [tex]\rho = 4.02 *10^{-8} \ \Omega \cdot m[/tex]
A storm is moving east toward your house at an average speed of 35 km an hour if the storm is currently 80 km from your house and how much time do you expect it to arrive
Answers
Answer: 2 hours 17 minutes
Explanation: 80/35h = 16/7 = 2hrs 17 minutes
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3. A cat is moving at 18 m/s when it accelerates at 4 m/s? for 2 seconds. What is his new
velocity?
Answers
Answer:
26 m/s
Explanation:
v = u + at
Given that,
u(initial speed) = 18 m/sa (acceleration) = 4m/s^2t ( time) = 2sand v ( final velocity) = ?
v = 18 + ( 4 × 2)
v = 18 + 8
v = 26 m/s
A car is pushed and travels 12 m. The same car is then pushed and it travels 15m. What
could have happened? Select 2 answers.
The mass was decreased
The force was increased
The force was decreased
The mass was increased
Answers
=========================================
Explanation:
If the force is kept the same, but the mass was decreased, then the car will travel further. The less mass an object has, the less inertia it has. Inertia is the tendency for the object to stay at rest if it's initially at rest (or the tendency for the object to stay in motion if already in motion).
If the mass is kept the same, but the force was increased, then the object will travel further than before. The same idea applies as discussed in the last paragraph.
------
If the force was decreased and mass kept the same, then there is less push, which results in the object traveling a shorter distance. If the mass is increased but the force kept the same, then the object moves a shorter distance because there's more inertia to overcome. There are more particles needed to be moved and they resist motion if at rest.
A 1.10-kg object slides to the right on a surface having a coefficient of kinetic friction 0.250 (Figure a). The object has a speed of vi = 2.60 m/s when it makes contact with a light spring (Figure b) that has a force constant of 50.0 N/m. The object comes to rest after the spring has been compressed a distance d (Figure c). The object is then forced toward the left by the spring (Figure d) and continues to move in that direction beyond the spring's unstretched position. Finally, the object comes to rest a distance D to the left of the unstretched spring (Figure e).
The right end of a horizontal spring labeled k is attached to a wall. Five images show five configurations as a block labeled m approaches, compresses, and then moves away from the spring.
In figure a, the block is to the left of the spring, and an arrow above the block points to the right.
In figure b, the block is just touching the uncompressed spring, and an arrow labeled vector vi above the block points to the right.
In figure c, the block has compressed the spring by a distance d, and a label indicates vector vf = 0.
In figure d, the block is just touching the uncompressed spring, and an arrow labeled vector v above the block points to the left.
In figure e, the block is a distance D away from the spring, and a label indicates vector v = 0.
(a)
Find the distance of compression d (in m).
m
(b)
Find the speed v (in m/s) at the unstretched position when the object is moving to the left (Figure d).
m/s
(c)
Find the distance D (in m) where the object comes to rest.
m
(d)
What If? If the object becomes attached securely to the end of the spring when it makes contact, what is the new value of the distance D (in m) at which the object will come to rest after moving to the left?
m
Answers
Answer:
(a) Approximately [tex]0.335\; \rm m[/tex].
(b) Approximately [tex]1.86\; \rm m\cdot s^{-1}[/tex].
(c) Approximately [tex]0.707\; \rm m[/tex].
(d) Approximately [tex]0.228\; \rm m[/tex].
Explanation:
[tex]v_i[/tex] denotes the velocity of the object in the first diagram right before it came into contact with the spring. Let [tex]m[/tex] denote the mass of the block. Let [tex]\mu[/tex] denote the constant of kinetic friction between the object and the surface. Let [tex]g[/tex] denote the constant of gravitational acceleration.Let [tex]k[/tex] denote the spring constant of this spring.(a)Consider the conversion of energy in this object-spring system.
First diagram: Right before the object came into contact with the spring, the object carries kinetic energy [tex]\displaystyle \frac{1}{2}\, m \cdot {v_{i}}^2[/tex].
Second diagram: As the object moves towards the position in the third diagram, the spring gains elastic potential energy. At the same time, the object loses energy due to friction.
Third diagram: After the velocity of the object becomes zero, it has moved a distance of [tex]D[/tex] and compressed the spring by the same distance.
Energy lost to friction: [tex]\underbrace{(\mu \cdot m \cdot g)}_{\text{friction}} \cdot D[/tex]. Elastic potential energy that the spring has gained: [tex]\displaystyle \frac{1}{2}\,k\, D^2[/tex].The sum of these two energies should match the initial kinetic energy of the object (before it comes into contact with the spring.) That is:
[tex]\displaystyle \frac{1}{2}\, m \cdot {v_{i}}^{2} = (\mu\cdot m \cdot g) \cdot D + \frac{1}{2}\, k \cdot D^2[/tex].
Assume that [tex]g = 9.81\; \rm m \cdot s^{-2}[/tex]. In the equation above, all symbols other than [tex]D[/tex] have known values:
[tex]m =1.10\; \rm kg[/tex].[tex]v_i = 2.60\; \rm m \cdot s^{-1}[/tex].[tex]\mu = 0.250[/tex].[tex]g = 9.81\; \rm m \cdot s^{-2}[/tex].[tex]k = 50.0\; \rm N \cdot m^{-1}[/tex].Substitute in the known values to obtain an equation for [tex]D[/tex] (where the unit of [tex]D\![/tex] is [tex]m[/tex].)
[tex]3.178 = 2.69775\, D + 25\, D^2[/tex].
[tex]2.69775\, D + 25\, D^2 + 3.178 = 0[/tex].
Simplify and solve for [tex]D[/tex]. Note that [tex]D > 0[/tex] because the energy lost to friction should be greater than zero.
[tex]D \approx 0.335\; \rm m[/tex].
(b)The energy of the object-spring system in the third diagram is the same as the elastic potential energy of the spring:
[tex]\displaystyle \frac{1}{2}\,k\, D^2 \approx 2.81\; \rm J[/tex].
As the object moves to the left, part of that energy will be lost to friction:
[tex](\mu \cdot m \cdot g) \, D \approx 0.905\; \rm J[/tex].
The rest will become the kinetic energy of that block by the time the block reaches the position in the fourth diagram:
[tex]2.81\; \rm J - 0.905\; \rm J \approx 1.91\; \rm J[/tex].
Calculate the velocity corresponding to that kinetic energy:
[tex]\displaystyle v =\sqrt{\frac{2\, (\text{Kinetic Energy})}{m}} \approx 1.86\; \rm m \cdot s^{-1}[/tex].
(c)As the object moves from the position in the fourth diagram to the position in the fifth, all its kinetic energy ([tex]1.91\; \rm J[/tex]) would be lost to friction.
How far would the object need to move on the surface to lose that much energy to friction? Again, the size of the friction force is [tex]\mu \cdot m \cdot g[/tex].
[tex]\displaystyle (\text{Distance Travelled}) = \frac{\text{(Work Done by friction)}}{\text{(Size of the Friction Force)}} \approx0.707\; \rm m[/tex].
(d)Similar to (a), solving (d) involves another quadratic equation about [tex]D[/tex].
Left-hand side of the equation: kinetic energy of the object (as in the fourth diagram,) [tex]1.91\; \rm J[/tex].
Right-hand side of the equation: energy lost to friction, plus the gain in the elastic potential energy of the spring.
[tex]\displaystyle {1.91\; \rm J} \approx (\mu\cdot m \cdot g) \cdot D + \frac{1}{2}\, k \cdot D^2[/tex].
[tex]25\, D^2 + 2.69775\, D - 1.90811\approx 0[/tex].
Again, [tex]D > 0[/tex] because the energy lost to friction is greater than zero.
[tex]D \approx 0.228\; \rm m[/tex].
The energy transferred between the object and the spring as a closed system, therefore, conserved are;
(a) The distance of compression, d ≈ 0.3354 meters
(b) The speed in the un-stretched position wen the object is sliding to the left, v ≈ 1.8623 m/s
(c) The distance where the object comes to rest, D ≈ 0.7071 m
(d) The distance the object will come to rest attached to the spring, D ≈ 0.2278 m
The reason the above values are correct are as follows;
The known parameters are;
Mass of the object, m₁ = 1.10 kg
Coefficient of friction, μ = 0.250
The initial speed of the object, [tex]v_i[/tex] = 2.60 m/s
Force constant of the spring, K = 50.0 N/m
Distance the spring is compressed by the object = d
(a) Conservation of energy principle
[tex]Kinetic \ energy = \dfrac{1}{2} \cdot m\cdot v^2[/tex]
Work done = Force × Distance
Friction force, [tex]F_f[/tex] = W × μ
Weight, W = m·g
Weight = Mass × Acceleration
Energy transferred by object = Work done by spring + Work done by friction
[tex]Energy \ transferred \ by \ object = Kinetic \ energy = \dfrac{1}{2} \times 1.10\times 2.60^2 = 3.718[/tex]
Energy transferred by object = 3.718 J
[tex]Work \ done \ by \ spring = \dfrac{1}{2} \cdot k\cdot x^2[/tex]
[tex]Work \ by \ spring \ to \ bring \ object \ to \ rest, \ W_{spring} = \dfrac{1}{2} \times 50\times d^2[/tex]
[tex]W_{spring}[/tex] = 25·d²
Work done by friction, [tex]W_{friction}[/tex] = 1.10×9.81×0.250×d = 2.69775·d
Therefore;
3.718 = 25·d² + 2.69775·d
25·d² + 2.69775·d - 3.718 = 0
Solving gives
The distance of the compression d ≈ 0.3354 m
(b) The energy given by the spring = 25·d²
The work done by friction, [tex]W_{friction}[/tex] = 2.69775·d
Kinetic energy given to object = 0.55·v²
0.55·v² = 25·d² - 2.69775·d
0.55·v² = 25×0.3354² - 2.69775×0.3354
∴ v = √(3.4682) = 1.8623
The velocity of the object at the un stretched position, v ≈ 1.8623 m/s
(c) The kinetic energy, K.E. of the object on the way left is given as follows;
K.E. = 0.5 × 1.10 kg × 3.4682 m²/s² = 1.90751 J
The work done by friction before object comes to rest = 2.69775·D
[tex]D = \dfrac{1.90751 \, J}{2.69775 \, N} \approx 0.7071 \, m[/tex]
The distance where the object comes to rest, D ≈ 0.7071 m
(d) The work done on spring, [tex]W_{spring}[/tex] = 25·D'²
Work done on friction, [tex]W_{friction}[/tex] = 2.69775·D'
Kinetic energy of object, K.E. ≈ 1.90751 J
K.E. = [tex]W_{spring}[/tex] + [tex]W_{friction}[/tex]
1.90751 ≈ 25·D'² + 2.6775·D'
25·D'² + 2.6775·D' - 1.90751 = 0
Solving with a graphing calculator gives;
D' ≈ 0.2278 m
The new value of the distance D = 0.2278 m
Learn more about the energy conservation principle here:
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A 58.72 kg person holding a steel ball stands motionless on a frozen lake.
The person then throws the ball, which propels the person at 1.05 m/s to the
right and the ball 3.75 m/s to the left. If the initial momentum of the system is
zero, what is the mass of the steel ball?
Answers
Answer: 16.44 kg
Explanation:
can you pls give a question about science. like why does the sky blue? PLS HELPPP ASAP
Answers
Imagine you are outside playing with a dog. The dog runs back and forth, left to right. What is the best way to describe how fast the dog's motion is?
The direction the dog moves.
The distance the dog moves over a certain amount of time.
The distance the dog moves.
Answers
Answer:
It is B.
Explanation:
This is because you want to see how fast the dog moves and the best way to find out is by seeing how fast it moves in a certain amount of time. pls brainly!
Which shows the correct steps in the formation of an ionic bond between these atoms?
A magnesium atom accepts six electrons from the fluorine atoms → Each fluorine atom donates three of the electrons → The magnesium atom becomes a -2 ion → Each fluorine atom becomes a +1 ion
A magnesium atom donates two electrons to the fluorine atoms → Each fluorine atom accepts one of the electrons → The magnesium atom becomes a -2 ion → Each fluorine atom becomes a +1 ion
A magnesium atom accepts two electrons from the fluorine atoms → Each fluorine atom donates one of the electrons → The magnesium atom becomes a -2 ion → Each fluorine atom becomes a +1 ion
A magnesium atom donates two electrons to the fluorine atoms → Each fluorine atom accepts one of the electrons → The magnesium atom becomes a +2 ion → Each fluorine atom becomes a -1 ion
Answers
Answer:
D) A magnesium atom donates two electrons to the fluorine atoms → Each fluorine atom accepts one of the electrons → The magnesium atom becomes a +2 ion → Each fluorine atom becomes a -1 ion
Explanation:
sorry if its a bit late
The correct steps in the formation of an ionic bond are A magnesium atom donates two electrons to the fluorine atoms → Each fluorine atom accepts one of the electrons → The magnesium atom becomes a +2 ion. The correct option is D.
What are ionic bonds?The electrical attraction between two ions with opposing charges creates an ionic bond, also known as an electrovalent bond, in a chemical molecule.
Ionic compounds are created by ionic bonds, while covalent bonds create covalent compounds. Ionic bonds are created by a complete transfer of electrons, whereas covalent bonds are created by sharing electrons.
Covalent bonds are weaker than ionic ones. Ionic compounds have higher melting and boiling points.
Therefore, the correct option is D.
To learn more about ionic bonds, refer to the link:
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Electricity & Magnetism
4
Electricity can be used to produce powerful forces.
What type of energy is electricity converted to in an electromagnet?
A. sound energy
B.
heat energy
C. light energy
D. magnetic energy
Answers
PLEASE HELP 50 POINTS!!!!!!!!!!!!!!!
Andrew and Deshawn are teammates on a high school soccer team. They’ve been playing soccer together for years. They both play the center forward position. Some years, Andrew is better than Deshawn and serves as the team’s starter. Other years, Deshawn is the stronger player and gets the most playing time. They are both very competitive with each other. Although they know each other well, they have never been friends.
In practice yesterday, the team was running drills in the rain. Deshawn slipped in the mud and collided with Andrew. Andrew hurt his knee badly in the fall and will have to sit out for several weeks.
The next day, Andrew told everyone at school that Deshawn hurt him on purpose to get more playing time. Deshawn retaliated by sharing private information about Andrew on social media. Andrew’s best friend Mateo saw the collision. He knows it was a complete accident.
Pick the role of Andrew, Deshawn, or Mateo.
What are the main issues/problems from this person’s perspective?
What ethical issues are involved for this person?
Why are these ethical issues relevant for this person?
How should the person you chose handle the situation?
Answers
Answer:
1. I pick the role of Mateo.
2. The main problems from Mateo's perspective are: He knows that the collision was a complete accident and that Deshawn did not injure Andrew on purpose. Because Andrew told everyone that Deshawn injured him on purpose, Deshawn did something unethical by sharing private information about Andrew on social media.
3. The ethical issues are: Andrew took his hurt and frustration of being injured and missing play time out on Deshawn, so he slandered him by saying that Deshawn hurt him on purpose. Deshawn then retaliated by sharing personal information about Andrew on social media, which is also unethical.
4. These issues are relevant to Mateo because he is Andrew's best friend AND he saw the incident happen and knows it was an accident.
5. If I was Mateo, I would talk to Andrew and explain to him that I know he is mad that he is injured and can't play for several weeks, but telling everyone that Deshawn did it on purpose wasn't right or good sportsmanship. I would encourage Andrew to meet with Deshawn with me and have Andrew apologize to Deshawn for saying it was his fault, and then encourage Andrew to go and tell everyone the real story. I would also encourage Deshawn to apologize for posting private information about Andrew, have Andrew ask him to take it down, and then ask Deshawn to post another post saying why he did it and that he was sorry. I would also encourage them to work together, since they are both star players.
Explanation:
A boy pushes a box with a force of 150 N at an angle of 40 with a flat floor. What component of his force is directed downward , or into the floor . PLEASE ANSWER!!!!!
Answers
Answer:
[tex]F_y=96.4N[/tex]
Explanation:
Hello.
In this case, considering the force diagram shown on the attached picture, we can see that the component of his force is directed downwards is:
[tex]F_y=F\times sin (\theta)[/tex]
Because the other component is the horizontal one:
[tex]F_x=F\times cos(\theta)[/tex]
In this case, the y-component force turns out:
[tex]F_y=150N\times sin (40\°)\\\\F_y=96.4N[/tex]
Moreover, the x-component force is also computed if required:
[tex]F_x=150N\times cos(40\°)\\\\F_x=114.9N[/tex]
Best regards.
A 2070 kg space station orbits Earth at an altitude of 5.37×105 m. Find the magnitude of the force with which the space station attracts Earth. The ma
Answers
Answer:
9.9 × 10^-16N
Explanation:
Given that a 2070 kg space station orbits Earth at an altitude of 5.37×105 m. Find the magnitude of the force with which the space station attracts Earth.
Calculating the gravitational field strength.
g = Gm/R^2
Where G = 6.67408 × 10-11 m3 kg-1 s-2
g =(6.67408 × 10-11 × 2070)/5.37 × 10^5
g = 1.38069×10^-7 / 2.88369^11
g = 4.788×10^-19 m/s
Force F = mg
Substitute g into the formula
F = 2070 × 4.79×10^-19
F = 9.9 × 10^-16N
Two wires A and B made of the same material and having the same lengths are connected across the same voltage source. If the power supplied to wire A is six times the power supplied to wire B, what is the ratio of their diameters
Answers
Answer:
sqrt (3) : sqrt (2)
Explanation:
Given that Two wires A and B made of the same material and having the same lengths are connected across the same voltage source.
Since they are both made of the same material, they will have the same resistivity.
Resistance is directly proportional to the length of the wire and inversely proportional to the cross sectional area.
Resistance R =1/ πr^2
If the power supplied to wire A is six times the power supplied to wire B, that is,
Pa = 6Pb
Where
Power P = IV
Since the same voltage passes through both wires,
P = V^2/R
Substitutes resistance R into the equation .Therefore,
V^2 ÷ 1 / πr^2 = 6( V^2 ÷ 1 / πr^2 )
V will cancel out , leaving
πr^2 = 6πr^2
Pi( π) will also cancel out. And since diameter d = 2r
r = d/2
Substitutes r into the equation
(d/2)^2 = 6( d/2)^2
d^2/4 = 6( d^2/4)
d^2/4 = 3d^2/2
da^2/2 = 3db^2
(Da/Db)^2 = 3/2
Da : Db = sqrt (3) : sqrt (2)
therefore, the ratio of their diameters is
sqrt (3) : sqrt (2)
The ratio of the diameter of Wire A to Wire B is; √6 : 1
What is the power in the wire?Since both wires are made of the same material, they will definitely have the same resistivity.
Formula for the resistance with area is;
R = 1/A = 1/(πr²)
We are told that the power supplied to wire A is six times the power supplied to wire B. Thus;,
Pa = 6Pb
Since the same voltage passes through both wires, then formula for power in both cases is; P = V²/R. Thus;
V² ÷ (1/πr_a²) = 6(V² ÷ (1/πr_b²))
V and π will cancel out to give;
r_a² = 6r_b²
We know that radius; r = d/2
Thus;
(d_a/2)²= 6(d_b/2)²
d_a²/4 = 6(d_b²/4)
(d_a/d_b)² = 6
d_a/d_b = √6 : 1
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The vehicle land-speed record has long been held by rocket cars. These vehicles resemble the high-speed rocket planes that were used in the early days of the space program, but they have heavy metal wheels. On September 5, 1997, the world land-speed record was set by the British-built Thrust SSC rocket car, which had a top recorded speed of 341 m/s. The kinetic energy of the car at this speed is 5.289 × 108 J. What is the car’s mass?
Answers
Answer:
9096.93 Kg
Explanation:
The following data were obtained from the question:
Velocity (v) = 341 m/s
Kinetic energy (KE) = 5.289×10⁸J.
Mass (m) =.?
The mass of the car can be obtained as follow:
KE = ½mv²
5.289×10⁸ = ½ × m × 341²
5.289×10⁸ = ½ × m × 116281
5.289×10⁸ = m × 58140.5
Divide both side by 58140.5
m = 5.289×10⁸ / 58140.5
m = 9096.93 Kg
Therefore, the mass of the car is 9096.93 Kg
Please answer correctly will give brainlist if correct
Before you kick a soccer ball you pull your leg back. For a brief moment, before you kick the ball, your leg is not moving as seen in the image below. At this point, your leg has______
Active Energy
Potential Energy
Conservation of Energy
Kinetic Energy
Answers
Answer:
Kinetic energy
How would natural cycles (day/night, moon phases) change if gravity did not
exist?
Answers
Answer: Eh, we would be dead...
Explanation: First off, the moon is orbiting us for one reason, gravity. and if the switch for gravity just flicked off, poof! The moon would be speeding away at 1,000-2,000 hours! And the reason that we orbit the sun is gravity too. So every planet would fling into space. Everything in the UNIVERSE would fling into space. That much flying debris would eventually smash into earth. Well, if we did survive that, then we would freeze instantly because when we travel too far away from the star that we orbit, the planet would become very life-threateningly cold. And in this case, we are traveling away from the sun, which is the star we orbit. If we still manage to survive THAT, then we...would actually die from the start, cuz what holds our planet together? You guessed it-gravity.
During a baseball game, a hitter strikes the ball with a bat. When this happens, the ball
and the bat exert a force on each other. Why does the ball accelerate away from the bat
more than the bat accelerates away from the ball?
a. The ball has less mass, so it exerts less force on the bat.
b. The bat exerts more force than the ball because the batter is exerting a force
on the bat as it hits the ball.
c. The ball has less mass, so the equal force on the ball and the bat causes
greater acceleration of the ball.
d. The ball has a greater velocity before the collision, so the force affects the ball
more than it affects the bat.
Answers
Answer:
The answer is c
Explanation: