Write the tangent equation to solve for angle f

Answer:

3sqrt3 cm

Step-by-step explanation:

6^2-3^2

36-9=27

sqrt27 = 3sqrt3

Answer:

c. 3 square root ( 3 ) cm

Step-by-step explanation:

C^2 = A^2 + B^2

A^2 = C^2 - B^2

= 6^2 - 3^2

= 36 - 9

A^2 = 27

A = 3√3 cm

Answer:

The value of log 8 is 0.9030

Step-by-step explanation:

To find:

Value of log 8

Solution:

Let we take,

x=log8

x=log (2)^3

x=3log2

x=3*0.3010

x=0.9030

Hence, the value of log 8 is 0.90.

Answer:

B

Step-by-step explanation:

I hope it is correct :)

Answer:

The answer is definitely B

Step-by-step explanation:

I just did this question on my test.

Answer:

it is the bottom answer or if it was labeled it would be D.

Answer:

1, -4, -9, -14, -19, -24, -29, -34, -39, -44, -49, -54 = -318

Step-by-step explanation:

Answer:

The Answer is -318.

Step-by-step explanation:

1 + (-4) + (-9) + (-14) + (-19) + (-24) + (-29) + (-34) + (-39) + (-44) + (-49) + (-54)

Answer:

9.95 cm

Step-by-step explanation:

Volume of a cylinder = pi * r² * h

Volume = 500 cm³

Radius, r = 8cm / 2 = 4cm

500 = 3.14 * 4² * h

500 = 3.14 * 16 * h

500 = 50.24 * h

h = 500 / 50.24

h = 9.952229

Height, h = 9.95 cm

Answer:

Im pretty sure you are correct

Step-by-step explanation:

Belive in urself m8

Answer:

no I don't think this is correct

Step-by-step explanation:

(no btw)

Answer:

A square unit is a small area of a square used to find a total.

Step-by-step explanation:

Answer:

-1/6

Step-by-step explanation:

Hope this helps down below! Pls mark brainliest

Multiply both the numerator and denominator of each fraction by the number that makes its denominator equal the LCD. This is basically multiplying each fraction by 1.

(12×33)−(23×22)=?

Complete the multiplication and the equation becomes

36−46=?

The two fractions now have like denominators so you can subtract the numerators.

Then:

3−46=−16

This fraction cannot be reduced.

Therefore:

12−23=−16

Solution by Formulas

Apply the fractions formula for subtraction, to

12−23

and solve

(1×3)−(2×2)2×3

=3−46

=−16

Therefore:

12−23=−16

See the attached picture:

Answer:  The range of a set of data is the difference between the highest and lowest values in the set. To find the range, first order the data from least to greatest. Then subtract the smallest value from the largest value in the set.

Answer:

A

Step-by-step explanation:

A. (g•f)(x)= log(5x) ( 5x + 4)=5x log(5x) + 4log(5x)

The function 5x log(5x) + 4log(5x) defines (g•f)

We have given that,

A. (g•f)(x)= 5x log(5x) + 4log(5x)

B. (g•f)(x) = 5x + 4 + log(5x)

C. (g•f)(x) = 5x – 4 – log(5x)

D. (g•f)(x) = 5x log(5x) + 4

We have to determine which function defines (g•f)

Where f(x)=log(5x) and g(x)=5x+5

A function from a set X to a set Y assigns to each element of X exactly one element of Y. The set X is called the domain of the function and the set Y is called the codomain of the function. Functions were originally the idealization of how a varying quantity depends on another quantity.

A. (g•f)(x)= log(5x) ( 5x + 4)=5x log(5x) + 4log(5x)

(5x+4)(log(5x))=5x(log(5x))+4(log(5x))

Therefore the option A is correct.

To learn more about the function visit:

https://brainly.com/question/6561461

#SPJ5

Answer:

5 units

Step-by-step explanation:

(4, -2 )  ;   [tex]x_{1}=4[/tex]  and [tex]y_{1} = -2[/tex]

(4 , 3) ;      [tex]x_{2} = 4[/tex]  and  [tex]y_{2}=3[/tex]

distance = [tex]\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}\\[/tex]

              [tex]= \sqrt{(4-4)^{2}+(3-[-2])^{2}}\\\\= \sqrt{0+(3+2)^{2}} \\\\=\sqrt{5^{2}}\\\\= 5 units[/tex]

Answer:

342 units squared

Step-by-step explanation:

since this is a rectangular prism, all we have to do is multiply the values by one of the other values once and multiply that by 2

Answer:

x = -19

Step-by-step explanation:

first isolate x by subtracting 8 on both sides:

179 = -9x + 8

-8              -8

=> 171 = -9x

then divide -9 on both sides to solve for x:

=> x = 171 ÷ -9 = -19

hope it helps ;)

Answer:

207,314

Step-by-step explanation:

V = πr2h =π  · 52·3 ≈ 235.61945 m^3

because 1m^3 = 1000 L, (27,535 / 1000) = the amount of added water in m^3. As this is equal to 27.535, we can substract this from 235.62.

235.62 - 27.535  is about 208.085, or 207.314 because of rounding. As this is in m^3, we multiply by liters to arrive at the answer of 207,314, or option D.

Answer: 0.09375

Step-by-step explanation: divid 3/8 and 1/4 together and you get 0.09375

Answer:

309

Step-by-step explanation:

To determine the estimated free-flow speed

[tex]FFS = 75.4 -f_{LW}-f_{LC} - 3.22 TRD^{0.84}[/tex]

From the table "Adjustment for lane width," which corresponds to a lane width of 12 feet. As a result, [tex]f_{LW}[/tex] equals 0 mi/h.

Take the meaning from the table "Adjustment for right-shoulder lateral clearance," which corresponds to 6 feet of right shoulder lateral clearance and two lanes in one direction.

The [tex]f_{LC} = 0 mi/h[/tex]

[tex]FFS = 75.4 -0-0-3.22 ( \dfrac{5}{6})^{0.84}[/tex]

[tex]= 72.64 \ mi/h[/tex]

[tex]\simeq 73 \ mi/h[/tex]

Determine the peak-hour factor

[tex]PHF = \dfrac{V}{V_{15}\times 4} \\ \\ =\dfrac{1800}{700\times 4}\\ \\ = 0.6429[/tex]

Now, Find the heavy-vehicle adjustment factor.

[tex]v_P = \dfrac{V}{PHF\times N \times f_{HV}\times f_P} --- (1)[/tex]

Take the value for the 15-minute passenger car equivalent flow rate from the table "LOS requirements for freeway segments" for the FFS and LOS C conditions. The free-flow speed is estimated to be 73 miles per hour

[tex]v_p = 1735+ \dfrac{73-70}{75-70}(1775-1735)[/tex]

[tex]v_p = 1759 \ pc/h/In[/tex]

Think about for familiar users the value of f_p = 1.00

Replace all of the values obtained in (1)

[tex]v_p = \dfrac{V}{PHF \times N\times f_{HV}\times f_p}[/tex]

[tex]1759 = \dfrac{1800}{0.6429\times 2 \times f_{HV}\times 1}[/tex]

[tex]f_{HV} = \dfrac{1800}{0.6429\times 2 }\times \dfrac{1}{1759}[/tex]

= 0.795

Calculate the percentage of trucks and buses in the flow of traffic stream.

[tex]f_{HV} = \dfrac{1}{1+P_{\tau}(E_{\tau}-1) + P_R(E_R-1)}[/tex]

Take the values from the table "Passenger car equivalent for extended highway segments" referring to trucks and buses and rolling terrains for passenger car equivalent for trucks and buses and recreational vehicles. As a result, [tex]E_T[/tex] has a value of 2.5 and [tex]E_R[/tex] has a value of 2.0.

Since [tex]P_R[/tex] is zero and there is no recreational vehicle.

Then;

[tex]0.759 = \dfrac{1}{1+ P_T(2.5 -1) +0}[/tex]

[tex]P_T = 0.1719[/tex]

Finally, to estimate the maximum number of large trucks and buses; we have:

[tex]= V\times P_T = 1800 \times 0.1719[/tex]

Maximum number of large trucks and buses = 309

Answer:

RS=5.65

Step-by-step explanation:

Please gimme few minutes

Answer:it’s 1/4

Step-by-step explanation:

Answer:

1:1 or 100% i don't know which you need

Step-by-step explanation:

Answer:

-5x=35            divide both sides by 5

-x=7                multiply both sides by -1

x=-7

Answer:

$1.23

Step-by-step explanation:

9 binders for 11.07, where x = num of binders

9x = 11.07  [Divide both sides by 9]

x = $1.23

Answer:

each binder costs $1.23

Step-by-step explanation:

$11.07 divided by 9 equals $1.23

Answer:

B

Step-by-step explanation:

Period equals pi/2

6. = 0.0000004834

7. = 0.0000506

8. = 0.00098

9. = 64580000

10. = 1398600000