A) 12 and 33 can be divided by 3 so 12:33 = 4:11
B= 20 and 5 can be divided by 5 so 20mm:5mm = 4mm:1mm
Answer:
A. 4: 11
B. 4: 1
Step-by-step explanation:
What are these? These are ratios, which show proportion. For example, for every two dogs, there is one cat. They can be written as words, fractions, or with colons, such as in these problems.
How to simplify: To simplify, think of the highest common factor. If you can't think of the highest, just think of a factor both numbers have in common and keep going until the numbers don't have any factors in common.
In this case, for A, the common factor was 3. 12/3=4 and 33/3=11. This cannot be simplified further because 11 is prime, which means it has no factors besides 1 and 11.
For B, the common factor was 4, so it is 4:1.
If you have a circle with a central angle of 80 degrees, what is the degrees of its inscribed angle?
Answer:
The measure of the inscribed angle is [tex]40^{\circ}[/tex]
Step-by-step explanation:
Recall that the measure of the inscribed angle is one-half the measure of the central angle subtended by the same arc.
So, if the measure of the central angle is [tex]80^{\circ}[/tex], so the measure of the corresponding inscribed angle is:
[tex]\frac{1}{2}\times 80^{\circ}=40^{\circ}[/tex]
Let L = {w ∈ {a, b}^∗| w has twice as many a′s as b′s}. Draw the state diagram of a P DA that accepts language L. Your P DA should not be overly complicated.
The transitions are labeled with the input symbol, the symbol to be pushed onto the stack (ε indicates no symbol is pushed), and the symbol to be popped from the stack (ε indicates no symbol is popped).This PDA accepts strings in L where the number of 'a's is twice the number of 'b's.
To draw the state diagram of a PDA that accepts the language L = {w ∈ {a, b}^∗ | w has twice as many a's as b's}, we can design a simple PDA with two states.
State 1: Initial state
Transition: (a, ε, a) -> State 1
Transition: (b, a, ε) -> State 2
Transition: (ε, ε, ε) -> Accepting state
State 2: Secondary state
Transition: (b, a, ε) -> State 2
Transition: (ε, ε, ε) -> Accepting state
Accepting state: Final state to indicate that the input string is accepted.
Here is the state diagram representation of the PDA:
Note: Find the attached image for the state diagram representation of the PDA.
In this PDA, State 1 is the initial state, and State 2 is the secondary state. The transitions are labeled with the input symbol, the symbol to be pushed onto the stack (ε indicates no symbol is pushed), and the symbol to be popped from the stack (ε indicates no symbol is popped).
The PDA works as follows:
In State 1, for each 'a' encountered, no symbol is pushed onto the stack, and the PDA remains in State 1.In State 1, for each 'b' encountered, 'a' is pushed onto the stack, and the PDA transitions to State 2.In State 2, for each 'b' encountered, 'a' is popped from the stack, and the PDA remains in State 2.If the input string is consumed and the PDA is in State 1 or State 2, it transitions to the accepting state.This PDA accepts strings in L where the number of 'a's is twice the number of 'b's.
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Simplify 4(8x).
A. 8x
B. 4x
C. 32x
D. 8 + 4x
Answer:
32x
Step-by-step explanation: 4(8x)=32x
A function whose graph goes down (falls) as it is followed from left to right is said to be a ____ function.
first two letters de
Bill has 29 more apps on his phone than Sherri, and they have a total of 99 apps. How many apps does each person have?
Sherri has 35 apps on her phone and Bill has 64 apps on his phone.
Let's represent Sherri’s apps with x.
Then, the number of Bill's apps will be x+29 (since he has 29 more apps than Sherri).
Their total number of apps is 99.Thus, the mathematical equation is:x + (x+29) = 99
Simplifying this equation gives:2x + 29 = 99
Subtracting 29 from both sides of the equation gives:2x = 70
Dividing both sides by 2 gives:x = 35
This means Sherri has 35 apps on her phone.
Substituting that into x+29 gives:35+29 = 64
Therefore, Bill has 64 apps on his phone.
Hence, each person has Sherri has 35 apps on her phone and Bill has 64 apps on his phone. The total number of apps between the two of them is 99 apps.
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Ben uses 3/12 pound of strawberries and 2/12 pound of blueberries to make jam. How many pounds of berries does Ben use to make jam?
Answer:
5/12
Step-by-step explanation:
add 3/12 and 2/12 to get 5/12 (decimal form is .416)
Answer:5/12 pounds
Step-by-step explanation: You take the 3 and add it with the 2 and you get 5/12
[tex]\frac{3}{12}[/tex] + [tex]\frac{3}{12}[/tex] = [tex]\frac{5}{12}[/tex]
How to do this with steps please help !
Answer:
126+111+43+8=288
360-288=72
72÷12=6
x=6
Answer:
x=6
Step-by-step explanation:
Step by step explaination attached below.
Please answer correctly! I will Mark you Brainliest!
Answer:
I think the volume of the figure is 60 but I'm not 100 % sure
Step-by-step explanation:
I belive the formula for this figure was (a+b)xh/(2)
So 40x 3 = 120
120/2 = 60
Question 8 of 10 A differential equation is: A. any equation involving a differentiable function. B. any equation involving an integral function. C. any equation involving a derivative. D. any equation involving two or more derivatives. E. any equation involving a derivative where the antiderivative is known.
A differential equation is an equation involving a differentiable function, which is a critical tool in modeling physical phenomena like population growth, radioactive decay, and fluid flow.
A differential equation is an equation that involves a differentiable function. It is an equation in which the variables' derivatives appear. Differential equations are used to model physical phenomena like population growth, radioactive decay, and fluid flow. The order of a differential equation is the highest order of the derivative of the function. A first-order differential equation has the highest order of 1, and a second-order differential equation has the highest order of 2.A differential equation can be classified into three types: Ordinary Differential Equations (ODEs), Partial Differential Equations (PDEs), and Differential Algebraic Equations (DAEs). Ordinary differential equations have a single independent variable and one or more dependent variables that depend on it. Partial differential equations have more than one independent variable and multiple dependent variables that depend on each other. Differential algebraic equations have both derivatives and algebraic equations in them.A differential equation is essential in physics, engineering, and mathematics. It is used to model many natural phenomena and helps in predicting the future. Most differential equations can not be solved analytically, so numerical methods are used to find approximate solutions. In conclusion, A differential equation is an equation involving a differentiable function, which is a critical tool in modeling physical phenomena like population growth, radioactive decay, and fluid flow.
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PLEASE HELP!! DON'T JUST TAKE POINTS :(
The wingspan of a hawk is the distance from the end of one spread-out wing to the end of the other spread-out wing. A scientist measured the wingspans of a random sample of hawks at a national park. Based on the median wingspan of the sample, the scientist estimates that the median wingspan of all hawks in the national park is 40 inches. Which graph most likely represents the data from the scientist's sample?
Answer:
I think the most upright answer would be D
Step-by-step explanation:
The following table shows the number of miles (d) a car travels in t hours while driving at a constant speed of 55 miles per hour.
t 1 2 3 4 5
d 55 110 165 ? 275
How many miles will the car travel in 4 hours?
Answer: 220 miles
Step-by-step explanation:
Car goes 55 miles in 1 hour.
Constant speed.
Formula is 55t = d.
55 x 4 = 220 miles
Answer:
the guy above is right
Step-by-step explanation:
Somebody help me please
Answer:
Other dude is correct
Step-by-step explanation:
Last year, Jackson bought a brand new car for $47,500. If the car depreciates in value by 20% each year, what will the car be worth when it is 8 years old?
Answer:
exponential growth or exponential decay , and what ... The value of a car purchased for $20,000 decreases ... population, P, increases by 20%each year,
how do I solve this??
Answer:
i guess you multiply 3and 30good lu8ck
Step-by-step explanation:
Answer:
3x+30=90 complementary
3x=90-30
x=60/3=20
x=20° is your answer
HELP ME UNSCRAMBLE THESE WORDS PLEASE!!! IGNORE THE SUBJECT I JUST DIDN'T KNOW WHAT TO PICK!! THANK YOU LOVELIES!!!
1) Play
2)Dribble
3)Paint
4)Center
5)Assists
6)Perimeter
7)Benchwarmer
8)Aboard
9)Technical
10)Rebound
11)Penalty
12)screen
13)Overtime
14)guard
15)? Host
16)Quarter
17) Bounce
18)Swish
19)Halftime
20)Backcourt
Hey I'm Chloe Can you Help Me I will give Brainlest, Thank you :)
Pythagoras lived over 2500 years ago. What is his theorem and why do we still use it today?
Answer:
The Pythagorean Theorem is helpful for two-dimensional navigation. You can use it along with two lengths to calculate the shortest path. The lengths north and west will be the triangle's two wings, and the diagonal will be the shortest line separating them. The same principles can be used for air navigation. He is best known in the modern day for the Pythagorean Theorem, a mathematical formula which states that the square of the hypotenuse of a right triangle is equal to the sum of the squares on the other two sides.
- Hope this helps! :)
help me with this plesse
What solid figure is shown below?
Answer:
rectangular prisim
Step-by-step explanation:
Answer:
rectangular prism
Step-by-step explanation:
rectangle shaped box
4. Use polynomial fitting to find the closed form for the sequence 2, 5, 11, 21, 36, ...
The sequence continues as follows:2, 5, 11, 21, 36, 67, ...
Given sequence2 5 11 21 36...
First differences 3 6 10 15...
Second differences 3 4 5...
Third differences 1 1...
The third differences are constant, which means that we can use a cubic polynomial for the fitting.
The formula for a cubic polynomial is
an³ + b
n² + c
n + d
Let us denote the nth term of the sequence by fn. Then, we have
f1 = 2, f2 = 5, f3 = 11, f4 = 21, f5 = 36...
We can write a system of equations using the first four terms of the sequence.
2 = a + b + c + d
5 = 8a + 4b + 2c + d
11 = 27a + 9b + 3c + d
21 = 64a + 16b + 4c + d
Solving this system, we get a = 1/3, b = 1, c = 11/3, and d = 0.
Thus, the closed-form expression for the nth term of the sequence isf(n) = (1/3)n³ + n² + (11/3)n
The next term in the sequence is f(6) = (1/3)(6)³ + (6)² + (11/3)(6) = 67.
Therefore, the sequence continues as follows:2, 5, 11, 21, 36, 67, ...
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there may be several different min-cut sets in a graph. using the analysis of the randomized min-cut algorithm, argue that there can be at most n(n − 1)/2 distinct min-cut sets.
The randomized min-cut algorithm, such as the Karger's algorithm, is an iterative algorithm that repeatedly contracts edges in a graph until only two nodes (or a small number of nodes) remain. At that point, the remaining edges represent a cut in the graph.
In each iteration of the algorithm, an edge is chosen uniformly at random to be contracted. This contraction merges the two nodes connected by the chosen edge into a single super-node. The process continues until only two nodes remain, representing the cut in the graph.
To analyze the algorithm, let's consider a graph with n vertices. At each iteration, the number of vertices decreases by one since two vertices are merged into one. Therefore, after k iterations, there are n - k vertices remaining in the graph.
Now, let's consider the number of distinct cuts that can be formed by the remaining vertices. For n vertices, the total number of possible cuts is [tex]2^(n-1)[/tex]since each vertex can be on one side of the cut or the other. However, some of these cuts may be identical because the order in which the vertices are contracted can change the representation of the cut.
To see why, suppose we have a set of vertices A and a set of vertices B. The order in which the vertices are contracted can result in different representations of the cut. For example, if we contract vertex A before vertex B, the cut might be represented as (A, B). However, if we contract vertex B before vertex A, the cut might be represented as (B, A). Both cuts are essentially the same, but the order of the vertices determines the representation.
Since there are (n-1) edges that need to be contracted to reach the final cut of two vertices, there are (n-1)! possible orders in which the vertices can be contracted. However, each order produces the same cut, so we need to divide by (n-1)! to account for the different representations.
Therefore, the number of distinct cuts that can be formed by the remaining vertices is [tex]2^(n-1)[/tex]/ (n-1)!. Simplifying this expression, we get:
[tex]2^(n-1) / (n-1)! = n(n-1)(n-2)...(2)(1) / (n-1)(n-2)...(2)(1) = n[/tex]
So, there can be at most n distinct min-cut sets in the graph.
In summary, using the analysis of the randomized min-cut algorithm, we can argue that there can be at most n(n - 1)/2 distinct min-cut sets.
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2. Find the inverse Laplace transform. ( 3pts each) 2 1 4 a. F(s) b. F(s) - 52 -28-3 S S
Inverse Laplace transform of f(s) = s³ / (s² + 6s + 13) is
[tex]f(t) = [(-3 + 2i)^{13} / (2i)] e^{(-3 + 2i)t} + [(-3 - 2i)^{13} / (-2i)] e^{(-3 - 2i)t[/tex]
The inverse Laplace transform of f(s) = s¹³ / (s² + 6s + 13) needs to be found.
To find the inverse Laplace transform, we first need to factor the denominator of f(s) using the quadratic formula:
s² + 6s + 13 = 0
s = [-6 ± √(6² - 4(1)(13))] / 2(1)
s = -3 ± 2i
Now we can rewrite f(s) as:
f(s) = s¹³ / [(s + 3 - 2i)(s + 3 + 2i)]
Using partial fraction decomposition, we can write:
f(s) = A / (s + 3 - 2i) + B / (s + 3 + 2i)
where A and B are constants to be determined. Multiplying both sides by the denominator, we get:
s¹³ = A(s + 3 + 2i) + B(s + 3 - 2i)
Substituting s = -3 + 2i, we get:
(-3 + 2i)¹³ = A(2i)
Solving for A, we get:
A = (-3 + 2i)¹³ / (2i)
Similarly, substituting s = -3 - 2i, we can solve for B:
B = (-3 - 2i)¹³ / (-2i)
Now we can write f(s) as:
f(s) = [(-3 + 2i)¹³ / (2i)] / (s + 3 - 2i) + [(-3 - 2i)¹³ / (-2i)] / (s + 3 + 2i)
Taking the inverse Laplace transform of each term separately using the table of Laplace transforms, we get the final answer:
[tex]f(t) = [(-3 + 2i)^{13} / (2i)] e^{(-3 + 2i)t} + [(-3 - 2i)^{13} / (-2i)] e^{(-3 - 2i)t[/tex]
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The given question is incomplete, the complete question is below
Find the inverse Laplace transform. f(s) = s¹³ / (s² + 6s + 13)
what is the distance between (3,-5), (-3,0)
Answer: 11 units
Step-by-step explanation:
-3 and 3 are 6 units apart, so that would be 6 units, and when you add the -5 into the problem, the 6 units become 11 units. Hope this helped :)
Answer:
Exact Form:
√ 61
Decimal Form:
7.81024967 …
You are conducting research using rhesus macaques (monkeys). For ethical reasons as well as limited resources, you decide to use only 9 animals, 3 animals in each of 3 treatment groups. To increase the power of your statistical testing, you take 10 samples from each animal. What statistical test might you use in this instance?
Your graduate student objects, saying that taking multiple samples from each animal cannot increase statistical power. How should you respond?
The response to your graduate student's objection of taking multiple samples from each animal cannot increase statistical power is:
You should respond by saying that taking multiple samples from each animal is a well-known strategy for increasing statistical power.
In addition, increasing the number of observations per group improves the statistical test's accuracy and reliability.
The statistical test that one would use in this instance is the One-way ANOVA, or one-factor ANOVA.
A statistical test that can be used in this instance is the One-way ANOVA, or one-factor ANOVA.
This statistical test is a method used to determine if the average or mean of a numerical variable varies significantly between two or more groups of interest.
For this statistical test, it is best to use multiple samples to increase statistical power.
In addition, ANOVA is used to compare three or more sets of data for statistical significance by testing for variances.
ANOVA's null hypothesis is that all populations are equal, while the alternative hypothesis is that at least one population is different from the others.
The response to your graduate student's objection of taking multiple samples from each animal cannot increase statistical power is:
You should respond by saying that taking multiple samples from each animal is a well-known strategy for increasing statistical power.
In addition, increasing the number of observations per group improves the statistical test's accuracy and reliability.
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What is another way to write -8+5?
Answer:
5-8
Step-by-step explanation:
you just had to move the 8 over
help me
The two major types of metal electrical cable are:
A.wire and fibre
B.twisted pair and coaxial
C.twisted pair and fibre optic
D.coaxial and fibre optic
2. What are the most common forms of wireless connection?
A.infrared beams
B.microwaves
C.radio waves
D.all of the above
3. Wi-fi connections have limited range of :
A.10 metres
B.600 metres
C.20 metres
D.300 metres
Answer:
1.The two major types of metal electrical cable are:
A.wire and fibre
2. What are the most common forms of wireless connection?
C.Radio news
3. Wi-fi connections have limited range of :
D.300 metres
PLEASE HELP ITS DUE TODAY!!
For problems 8-11, write Yes or No whether each figure is a polygon. (1 point each)
Answer:
yes,yes,yes,no :) hope it helps
Step-by-step explanation:
Answer:
1. Yes
2. No
Definition of a Polygon: a plane figure with at least three straight sides and angles, and typically five or more.
The starting salary of a starting teacher is $40,000, which will increase by 2% each year
What is the multiplier (growth factor) for this scenario?
1. .02
2. 1.02
3. 2
4. 1.2
Answer:
Choice B - (1.02)
Step-by-step explanation:
With the teachers starting salary being $40,000, we can rightfully assume that it their salary would not increase with Choice A, $40,000 * 0.2 = $800.
2% otherwise known as 0.02, would make the teachers yearly salary $40,000 * 1 + 0.02, or $40,000 * 1.02. Making the correct answer, Choice B - (1.02). (This would also give the teacher an additional $800 per year!)
The center and a point on a circle are given. Find the circumference to the nearest tenth.
center:(−15, −21);
point on the circle: (0, −13)
The circumference is about ???
Answer:
Circumference ~ 233.7
Step-by-step explanation:
Use the distance formula to find the radius of the circle with the two coordinates given. The radius of this circle is about 37.2. Plug 37.2 into the formula 2(pi)r to find the Circumference. The answer is 233.7 rounded to the nearest tenth.
In a simple random sample of 170 households, the sample mean number of personal computers was1.71. Assume the population standard deviation is σ=0.86.
(a) Construct a 90% confidence interval for the mean number of personal computers. Round the answer to at least two decimal places.
A 90% confidence interval for the mean number of personal computers is _______
(b) If the sample size were 120 rather that 170, would the margin of error be larger or smaller than the result in part (a)? Explain.
The margin of error would be _______, since __________in the sample size will _______ the standard error.
(c) If the confidence levels were 95% rather than 90%, would the margin of error be larger or smaller than the result in part (a)? Explain.
The margin of error would be _______, since __________ in the confidence level will ___________the critical value za/2.
(d) Based on the confidence interval constructed in part (a), is it likely that the mean number of personal computers is greater than 1?
It ________ likely that the mean number of personal computers is greater than1.
The confidence interval using a 90% confidence level is (1.601, 1.819)
Confidence IntervalConfidence Interval = Sample Mean ± Margin of Error
Given the parameters:
Sample Mean (x) = 1.71
Population Standard Deviation (σ) = 0.86
Sample Size (n) = 170
Confidence Level = 90%
The standard Error(SE) is given by:
SE = σ / √n
SE = 0.86 / √170 ≈ 0.0663
The margin of Error is related to standard error by the relation:
ME = Z × SE
ME = 1.645 × 0.0663 ≈ 0.109
Confidence Interval = Sample Mean ± Margin of Error
Confidence Interval = 1.71 ± 0.109
Confidence Interval= (1.601, 1.819)
Part B:A decrease in sample size from 170 to 120 would lead to increase in error margin , since decrease in sample size will increase the standard error.
Part C:If confidence interval were raised from 90% to 95% , the error margin would be larger since increase in confidence interval would increase the critical value
Part D :Based on the confidence interval , it is very likely that the mean number of personal computers is greater than 1.
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An object located at the point (4, 55) on a distance time graph is later located at the point (9, 45). If distance is in metres and time is in seconds, the average speed is: a) -2 m/s b) 5 m/s c) -5 m/s d) 2 m/s
An object located at the point (4, 55) on a distance time graph is later located at the point (9, 45). If distance is in metres and time is in seconds, the average speed is -2 m/s.
To calculate the average speed of an object, we need to find the total distance traveled divided by the total time taken.
Given that the object is located at the point (4, 55) initially and later located at the point (9, 45), we can determine the total distance traveled and the total time taken.
Total distance traveled = Difference in distance = 45 - 55 = -10 meters (negative because the object moved from a higher distance to a lower distance)
Total time taken = Difference in time = 9 - 4 = 5 seconds
Average speed = Total distance traveled / Total time taken = -10 meters / 5 seconds = -2 meters/second
Therefore, the average speed of the object is -2 m/s.
Option (a) -2 m/s is the correct answer.
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