write solutions to the systems of inequalities that should lie on the double- shade region​

Answer:

Possible expressions for the radius of the can and the depth of the paint in the can are [tex]r = \sqrt{9\cdot x^{2}+24\cdot x+16}[/tex] and [tex]h = 2\cdot x[/tex], respectively.

Step-by-step explanation:

Let be the initial volumes of the initial cans represented by these expressions:

[tex]V_{1} = (8\cdot x^{3}+31\cdot x^{2}+32\cdot x)\cdot \pi[/tex] (1)

[tex]V_{2} = (10\cdot x^{3}+17\cdot x^{2})\cdot \pi[/tex] (2)

The resulting volume of the paint can is the sum of the two functions:

[tex]V_{3} = (18\cdot x^{3}+48\cdot x^{2}+32\cdot x)\cdot \pi[/tex] (3)

Then, we proceed to factor the polynomial:

[tex]V_{3} = 2\cdot (9\cdot x^{2}+24\cdot x +16)\cdot x \cdot \pi[/tex]

[tex]V_{3} = \pi\cdot (9\cdot x^{2}+24\cdot x + 16)\cdot (2\cdot x)[/tex] (3b)

By direct comparison with the volume formula for the cylinder we have the following expressions:

[tex]r^{2} = 9\cdot x^{2}+24\cdot x + 16[/tex]

[tex]r = \sqrt{9\cdot x^{2}+24\cdot x+16}[/tex]

[tex]h = 2\cdot x[/tex]

Possible expressions for the radius of the can and the depth of the paint in the can are [tex]r = \sqrt{9\cdot x^{2}+24\cdot x+16}[/tex] and [tex]h = 2\cdot x[/tex], respectively.

For both scenarios, a sample is selected without replacement from a batch of items. In the first scenario, the batch contains 3 defective items ('d') and 10 good items ('g'). The ordered sample space consists of all possible ordered pairs of items: {dd, dg, gd, gg}. In the second scenario, the batch contains the items {a, b, c, d}. The ordered sample space also consists of all possible ordered pairs of items: {aa, ab, ac, ad, ba, bb, bc, bd, ca, cb, cc, cd, da, db, dc, dd}.

In the first scenario, the ordered sample space is derived by considering all possible combinations of the two items selected from the batch. Since the selection is done without replacement, the first item can be either defective ('d') or good ('g'). For each case, the second item can also be defective or good, depending on what was chosen as the first item. Therefore, the ordered sample space consists of four possibilities: dd, dg, gd, and gg.

In the second scenario, the batch consists of four distinct items: a, b, c, and d. Again, the ordered sample space is obtained by considering all possible combinations of the two items selected without replacement. Since there are four items, there are 16 possible combinations. Each combination is represented by an ordered pair of the selected items, such as aa, ab, ac, and so on.

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Answer:

A 3-inch slice of the food item contains 255 calories.

Step-by-step explanation:

Set calories per inch slice as variable x.

2x = 170

x = 85 cal

Since each inch slice of the food item contains 85 calories, a 3-inch slice would contain:

3x = 3(85) = 255 cal

The inverse Laplace transform of X(s) = [tex]1/s^7[/tex] is f(t) =[tex]t^6.[/tex]

To locate the inverse Laplace rework of X(s) =[tex]1/(s^7[/tex]), we are able to use algebraic manipulation and the inverse Laplace transform assets said in Theorem 7.2.1, which permits us to discover the original characteristic while given its Laplace rework.

Using the assets of the Laplace transform, we will rewrite the given expression as:

X(s) = [tex]x^-1(1/s^7) = (1/s^7)[/tex]

We need to locate the feature f(t) such that its Laplace transform is X(s) = [tex]1/s^7[/tex]. By making use of Theorem 7.2.1, we understand that the inverse Laplace remodels of X(s) will give us f(t).

Now, we need to find a characteristic f(t) that has a Laplace transform [tex]1/s^7[/tex]. By examining the Laplace transform a desk or the usage of regarded formulas, we will decide that the Laplace remodel of [tex]t^n[/tex](wherein n is a high-quality integer) is given by means of[tex]n!/s^(n+1).[/tex]

In our case, we're looking for a function whose Laplace remodel is[tex]1/s^7.[/tex]Comparing this with the Laplace transform formulation cited earlier, we see that the exponent within the denominator of sought to be [tex]8 ^(7+1).[/tex]

Hence, f(t) must be t^6 (given that 6+1 = 7), and its Laplace remodel maybe [tex]6!/s^7 = 720/s^7.[/tex]

Therefore, the inverse Laplace transform of X(s) = [tex]1/s^7 is f(t) = t^6.[/tex]

In precis, by applying algebraic manipulation and making use of the inverse Laplace rework assets, we determined that the inverse Laplace transform of [tex]1/s^7 is f(t) = t^6[/tex]. This approach that a unique feature corresponding to the given Laplace rework is [tex]t^6.[/tex].

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An test for divisibility that a 5-digit number "abcde" will be divisible by 11 if and only if "a - b + c - d + e" is divisible by 11.

To show that a 5-digit number "abcde" is divisible by 11 if and only if "a - b + c - d + e" is divisible by 11, the concept of modular arithmetic.

The 5-digit number "abcde" as a sum of its digits multiplied by their respective place values:

"abcde" = a × 10000 + b × 1000 + c × 100 + d × 10 + e

Then express "a - b + c - d + e" in terms of the digits:

a - b + c - d + e = a × (10,000 mod 11) - b × (1,000 mod 11) + c × (100 mod 11) - d × (10 mod 11) + e

examine the patterns of the modulos:

10,000 mod 11 = 1

1,000 mod 11 = 10

100 mod 11 = 1

10 mod 11 = 10

Substituting these values back into the expression,

a - b + c - d + e = a × 1 - b ×10 + c × 1 - d × 10 + e

Simplifying further:

a - b + c - d + e = a - b + c - d + e

observe that the expression "a - b + c - d + e" is equivalent to the original 5-digit number "abcde." This means that if "abcde" is divisible by 11, then "a - b + c - d + e" will also be divisible by 11.

Conversely, if "a - b + c - d + e" is divisible by 11, it implies that the expression and the 5-digit number "abcde" have the same remainder when divided by 11. Since they are equivalent, "abcde" must also be divisible by 11.

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The general solution of the given differential equation 7dy/dx + 56y = 8 is y(x) = -x/8 + C e^(-8x/7), where C is a constant.

To solve the differential equation, we first rearrange it to isolate dy/dx: dy/dx = (8 - 56y)/7. This is a first-order linear differential equation. The integrating factor is e^(∫(-56/7)dx) = e^(-8x/7). Multiplying both sides of the equation by this integrating factor, we obtain e^(-8x/7) dy/dx + 8e^(-8x/7)y = 8e^(-8x/7). The left-hand side can be written as the derivative of y multiplied by e^(-8x/7). Integrating both sides gives ∫d(y e^(-8x/7)) = ∫8e^(-8x/7) dx. Solving these integrals and rearranging, we find the general solution y(x) = -x/8 + C e^(-8x/7), where C is the constant of integration.

The largest interval I over which the general solution is defined is (-∞, ∞) since there are no singular points or restrictions mentioned in the differential equation. This means that the solution is valid for all real values of x.

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Answer: g-7

Step-by-step explanation:

Answer:

Step-by-step explanation:

5 is the correct answer

Answer:

The First choice

Step-by-step explanation:

Answer:

surface area of cuboid=2(lb+bh+hl)

surface area of cuboid=2(12×5+5×2+2×12 )

surface area of cuboid=188in²

Answer:

[tex]y=-\frac{1}{3}[/tex]

Step-by-step explanation:

- 3 + 9y = - 6

- 3 + 3 + 9y = - 6 + 3

9y = - 3

9y ÷ 9 = - 3 ÷ 9

[tex]y=- \frac{1}{3}[/tex]

By classifying sets of three numbers from the interval [0...n] by their maximum element, we have provided a combinatorial proof of the identity 1, 2 + 2.3 + 3.4 + ... + (x - 1)^n = 2^(n+1).

The combinatorial proof of the identity 1, 2 + 2.3 + 3.4 + ... + (x - 1)^n = 2^(n+1) revolves around classifying sets of three numbers from the integer interval [0...n] by their maximum element.

Let's consider the right-hand side of the equation, which is 2^(n+1). This represents the number of subsets of an n-element set. We can think of each element in the set as having two choices: either it is included in a subset or not. Therefore, there are 2 choices for each element, resulting in a total of 2^(n+1) subsets.

Now, let's look at the left-hand side of the equation, which is the sum 1 + 2 + 2.3 + 3.4 + ... + (x - 1)^n. We can interpret each term as follows:

1: Represents the number of subsets with a maximum element of 0, which is only the empty set.

2: Represents the number of subsets with a maximum element of 1, which includes the subsets {0} and {1}.

2.3: Represents the number of subsets with a maximum element of 2, which includes the subsets {0, 1}, {0, 2}, and {1, 2}.

Similarly, for each subsequent term (x - 1)^n, it represents the number of subsets with a maximum element of x-1.

Now, if we add up all these terms, we are essentially counting the total number of subsets from the original set. This matches the right-hand side of the equation, which is 2^(n+1).

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The account balance after 10 years will be approximately $5,259.99.

The balance in Kelly's account after 10 years can be determined using the formula for compound interest which is given as:

A = [tex]P(1 + r/n)^{nt}[/tex]

Where, A is the balance after time t, P is the principal amount (initial deposit), r is the annual interest rate (as a decimal), n is the number of times the interest is compounded per year, and t is the time in years.

Using this formula and substituting the given values, we get:

A = [tex]3000(1 + 0.052/4)^{4 \times 10}[/tex]

= [tex]3000(1.0125)^{40}[/tex] ≈ $5,259.99

Therefore, the account balance after 10 years will be approximately $5,259.99.

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Answer: -633

Explanation:

formula is a0= a1 + (n-1)d

a0 is what ur tryig to find

a1 = -14

n= 60

d = -11

Answer:

Step-by-step explanation:

As,

There is always a gap of -11 in all the proceedings

Hence,

- 14 -11 = -25

-14 -(11 ×2) = -36

So,

60th term

-14 -(11 × 60) = -674 (Ans)

Answer:

x = 50.... 25/50 = 15/30 or 1/2 = 1/2

Step-by-step explanation:

25/x = 15/30

consider the cross multiply

25 * 30 = 15 * x

750 = 15x

divide both sides with 15 to make the co-efficient of x, 1.

x = 50

Answer:

5×15/6

5×5/2

25/2

12.2 is your answer ☺️☺️☺️. If I'm right so,

Please mark me as brainliest. thanks!!!

Answer:

Down below

Step-by-step explanation:

[tex]A=\pi r^2\\A=3.14*(15)^2\\A=3.14*225\\A=706.5[/tex]

Answer:

A= 4.5×10^11

B= 3.5×10^3

Step-by-step explanation:

A

(5×10^3)= 5000

(9×10^7)=90000000

multiply both of them

=450000000000 or 4.5×10^11

B

(7×10^5)=700000

(2×10^2)=200

700000÷200

3500 or 3.5×10^3

The correct answer is b. close to 1.00.  Ratio close to 1.00 indicates that the between-group variation is similar to the within-group variation.

In an ANOVA (Analysis of Variance) model, MSTR refers to the mean square treatment (or between-group variation), while MSE refers to the mean square error (or within-group variation).

If the true means of the k populations are equal, it means that the between-group variation is similar to the within-group variation, and there is no significant difference between the group means.

In this scenario, we would expect the MSTR/MSE ratio to be close to 1.00 (answer b). A ratio close to 1.00 indicates that the between-group variation is similar to the within-group variation, supporting the assumption that the true means of the populations are equal.

Therefore, the correct answer is b. close to 1.00.

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Answer:

The sample is the amount of people because not everyone is getting chosen

Step-by-step explanation:

I also agree, the coach choose certain people to march cuz not everyone is gonna be able to get used.

Answer:

18 Skittles

6 M&Ms

Step-by-step explanation:

Set up an equation:

Variable x = number of skittles

Variable y = number of M&Ms

1.50x + 2y = 39

x + y = 24

In the second equation, isolate a variable:

x = 24 - y

Substitute the value of x for 24 - y in the first equation:

1.50(24 - y) + 2y = 39

Use distributive property

36 - 1.5y + 2y = 39

Combine like terms

36 + 0.5y = 39

Isolate variable y:

0.5y = 3

y = 6

Substitute the value of y for 6 in the second equation:

x + 6 = 24

Isolate variable x:

x = 18

Plug these values into any equation of your choice to see if these values are correct (I'll do both equations just to prove it):

1.50(18) + 2(6) = 39

27 + 12 = 39

39 = 39

Correct

x + y = 24

18 + 6 = 24

24 = 24

Correct

Answer: taake this link,  it has all the answers

Step-by-step explanation:                 https://quizlet.com/183183758/statistical-studies-scatterplots-practiceamdm-flash-cards/

The best option for the points on the graph is points are at (0.4, 7.8), (3.1, 6.0), and (9.8, 0.5).

In two-dimensional Cartesian geometry, two intersecting straight lines are used as reference lines. In three-dimensional Cartesian geometry, three straight lines with a common point are the intersections of the three coordinate reference planes.

From the attached file of scatter plot for the data, it is clear that the for every value of x there is a suitable value of y which was given in the question.

Considering x values and plot the y vale on the graph.

For x = 0.4; y = 7.8

For x = 3.1; y = 6.0

and for x = 9.8; y = 0.5

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The margin of error for a 95% confidence level is 8.2.

The margin of error (ME) is determined using the formula:

ME= z ∗ σ/√n

where:

z is the z-score for the desired confidence level

σ is the population standard deviation

n is the sample size

For a 95% confidence level, the z-score is 1.96. Thus, we have:

z = 1.96

σ  = 13.3

n = 10

Substituting these values into the formula, we have:

ME =  1.96 ∗ 13.3/√10

ME = 8.2

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Answer:

9°C

Step-by-step explanation:

Group the terms and get [tex]24+8-1-10-12[/tex]

Then simplify to get [tex]32-23[/tex]

Subtract and you get 9

So the answer is 9°C.

Hope this helps!

The orthonormal basis for (2, 1), (2, 5) is therefore u1, u2 = (2/5, 1/5), (2/5, -1/5) because u2 = v2_orth/||v2_orth|| = (2/5, -1/5).

In R2, the internal result of the two vectors u and v is as follows: The Gram-Schmidt procedure can be used to request the transformation of (2, 1), (2, 5) into an orthonormal premise. u, v = 2u1v1 + u2v2. An orthonormal premise is made by changing over a bunch of directly free vectors utilizing the Gram-Schmidt process. Our set's principal vector, v1 = (2, 1), should serve as our starting point.

We standardize v1 to obtain our first orthonormal premise vector: We must locate the second vector in our set, v2 = (-2, -5), and we can orthogonalize v2 by deducting its projection from u1: u1 = v1/||v1|| = (2/5, 1/5) proj_u1(v2) = (v2 u1)u1 = (- 8/5, - 4/5)v2_orth = v2 - proj_u1(v2) = (6, - 21/5)Our second orthonormal premise vector is acquired by normalizing v2_orth: The orthonormal reason for (2, 1), (2, 5) is subsequently u1, u2 = (2/5, 1/5), (2/5, - 1/5) in light of the fact that u2 = v2_orth/||v2_orth|| = (2/5, - 1/5).

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Answer:

.5428571 repeating

or 19/35

Answer:

2•15k

Step-by-step explanation:

Answer:

2(15k)

Step-by-step explanation:

PLZZ GIVE BRAINLIEST

Answer:

10 km/h

Step-by-step explanation:

I'm not really sure about this but no ones answering your question and I wanna help.

So basically to calculate the average speed you need to divide the distance travelled by time taken

But you do not have the distance traveled. But it is mentioned that it takes u 30 minutes to walk from home to school when walking at 5 km/h so to find the distance all you have to do is... 30 x 5 = 150 km

Now that we have the time and distance all we have to do is find the average speed.

Average Speed = distance ÷ time

So 150 ÷ 15 = 10 km/h

Answer:

1271.7 inches

Step-by-step explanation:

Given

[tex]d = 27in[/tex]

[tex]Rotations = 15[/tex]

Required

The total distance moved

First, we calculate the circumference of the wheel

[tex]c = \pi *d[/tex]

[tex]c = 3.14 * 27[/tex]

[tex]c = 84.78[/tex]

This represents the distance traveled in one complete rotation.

So, in 15 rotations.

[tex]Total = 15 * 84.78[/tex]

[tex]Total = 1271.7[/tex]

The duration in minutes for 40 consecutive dormant periods are given in the following table:91 82 84 85 80 73 72 84 86 76 51 70 71 83 79 79 67 76 60 81 55 53 51 53 45 49 67 76 86 88 82 68 82 51 51 75 86 575 66.

Assuming that the waiting time follows an exponential distribution with mean parameter A, a uniformly most powerful test of size α = 0.01 for H o λ^2=80 vs H1 A<80 can be developed as follows: The null and alternative hypotheses are as follows:H0:λ^2=80, that is, the mean of the exponential distribution is 80 squared.H1:A<80, which implies that the mean waiting time between eruptions is less than 80 squared.α=0.01 is the level of significance.

The following test statistic T is used: T = [n(λ^2-80)] / 80^2where n is the sample size, and the critical region is the left-tail rejection area. The probability of observing the values in the given sample or a more extreme set of values is calculated as follows: Since we are performing a one-tailed test, we divide α by 2.α/2 = 0.005

The area in the left tail is 0.005, and the corresponding z-score is -2.33.The null hypothesis is rejected if the computed value of the test statistic falls in the critical region, which is in the left-tail rejection region. T < -2.33

Since the test statistic T = -1.91 falls in the non-critical region, we fail to reject the null hypothesis at the α=0.01 level of significance. Therefore, based on this test, we can conclude that there is insufficient evidence to suggest that the mean waiting time between eruptions is less than 80 squared.

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