Write a quadratic function f whose zeros are 2 and 5.

Answer:

65 pictures because 24+36+3+2

Answer:

[tex]0 < x < 6[/tex]

Step-by-step explanation:

This question asks to solve an inequality which can be written as:

[tex]\sqrt{x^2-6x+9} < 3[/tex]

Solve for x:

[tex]\sqrt{x^2-6x+9} < 3\\x^2-6x+9 < 9\\x^2-6x < 0\\x(x-6) < 0[/tex]

From here we can deduce that the inequality is [tex]0[/tex] when:

[tex]x = 0[/tex] or [tex]x = 6[/tex]

We can write the solution as:

[tex]0 < x < 6[/tex]

[tex]\qquad\qquad\huge\underline{{\sf Answer}}[/tex]

Let's evaluate ~

[tex]\qquad \sf  \dashrightarrow \: \sqrt{ {x}^{2} - 6x + 9 } [/tex]

[tex]\qquad \sf  \dashrightarrow \: \sqrt{ {x}^{2} - 3x - 3x+ 9 } [/tex]

[tex]\qquad \sf  \dashrightarrow \: \sqrt{ {x}^{}(x - 3) - 3(x - 3) } [/tex]

[tex]\qquad \sf  \dashrightarrow \: \sqrt{ (x - 3)(x - 3) } [/tex]

[tex]\qquad \sf  \dashrightarrow \: \sqrt{ (x - 3) {}^{2} } [/tex]

[tex]\qquad \sf  \dashrightarrow \: { (x - 3) {}^{} } [/tex]

Now, we have been given that value of x :

[tex]\qquad \sf  \dashrightarrow \:x < 3[/tex]

So, let's plug the value of x as 3 in the given expression ~

[tex]\qquad \sf  \dashrightarrow \:3 - 3[/tex]

[tex]\qquad \sf  \dashrightarrow \:0[/tex]

Therefore, we can conclude that :

[tex]\qquad \sf  \dashrightarrow \: \sqrt{ {x}^{2} - 6x + 9 } < 0[/tex]

Value of the expression should be less than 0

Answer:

4/19

Step-by-step explanation:

Jar a: 3/8

Jar b: 1/11

8+11 = 19

3+1= 4

4/19

Check the picture below.

Answer:

13r+10

Step-by-step explanation:

1. Combine Like Terms

(2r+11r)+(7+3)

13r+10

Answer:

13r+10

Step-by-step explanation:

2r+7+11r+3

collect like terms

2r+11r+7+3

13r+10

Answer:

52 miles

Step-by-step explanation:

since 1 unit is 26 miles and the distance from Daytona beach to Orlando on the map is 2 units just multiply 26 by 2 to get 52 miles

Answer:

A= 77/2 or 38.5 cm^2 and p= 29.5 cm

Step-by-step explanation: Remember the formula for area and perimeter for a triangle A=1/2bh and P= a+b+c. So the equations would look like A=1/2 x 11 x 7 and P= 11 + 11 + 7.5 and that'll result in A= 77/2 or 38.5 cm^2 and p=29.5 cm.

The length of the arc GJ is 17.17 units if the in circle H with m/GHJ = 82 and GH = 12 units.

It is described as a set of points, where each point is at the same distance from a fixed point (called the centre of a circle)

We have angle GHJ = 82 units

Length of GH = 12 units

We know:

s = 2πr(θ/360)

s = (2π)12(82/360)

s = 17.17 units

Thus, the length of the arc GJ is 17.17 units if the in circle H with m/GHJ = 82 and GH = 12 units.

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Answer:

1 23/36

Step-by-step explanation:

hope this helped

Answer:

135 cubes

Step-by-step explanation:

Volume of cuboid :

Volume of a small cube :

Number of cubes :

Answer:

10

Step-by-step explanation:

32 - 12 (because C is 12 years younger) = 20

20 / 2 (because twice Anna's age, so we do the inverse) = 10

Anna is 10 years old.

Hope this helps!

Answer:44

Step-by-step explanation:

See below for the proof of the equation 4h² - 4dh + x² = 0 using the Pythagoras theorem

The Pythagoras theorem states that:

Hypotenuse² = Opposite² + Adjacent²

The question is incomplete, as the figure is not given.

So, I will complete the proof using the following parameters:

Substitute the above values in the following equation

Hypotenuse² = Opposite² + Adjacent²

So, we have:

(2√dh)² = x² + (2h)²

Evaluate the exponents

4dh = x² + 4h²

Subtract 4dh from both sides

0 = x² + 4h² - 4dh

Rewrite as:

4h² - 4dh + x² = 0

Hence, the equation has been proved

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Answer:

32π cm^3.

Step-by-step explanation:

The volume of a cone is 1/3 of the volume of a cylinder with the same base area and height.

So the empty space = 2/3 * 48π

= 32π cm^3.

Answer:

Hope the picture will help you.....................

Answer:

[tex]f(x)=-2\cos(2x)+1[/tex]

Step-by-step explanation:

Recall the general cosine equation

Identify amplitude

[tex]\text{Amplitude}=\frac{\text{Max-Min}}{2}=\frac{3-(-1)}{2}=\frac{4}{2}=2[/tex]

Identify period and solve for b

[tex]\frac{3\pi}{2}-\frac{\pi}{2}=\pi\\ \\\frac{2\pi}{|b|}=\pi\\ \\2\pi=b\pi\\\\2=b[/tex]

Identify midline

[tex]y=d=1[/tex]

Final Equation

[tex]f(x)=-2\cos(2x)+1[/tex]

Also, the reason why [tex]a=-2[/tex] is because a cosine function starts at its maximum, but since it starts at its minimum, the value of [tex]a[/tex] must be negative and causes the wave to flip about the midline.

Answer:

Step-by-step explanation:

Perimeter

Area

Answer:

P(greater than 4 or factor of 5) = 1/3

Step-by-step explanation:

→ let A be the set {the numbers greater than 4}

then A : {5 , 6}

p(A) = 2/6

→ let B be the set {the factors of 5}

then B : {1 , 5}

p(B) = 2/6

P(greater than 4 or factor of 5) = p(A∪B)

Formula =================

p(A∪B) = p(A) + p(B) - p(A∩B)

………………………………………………

A∩B : {5}

then

cardA∩B = 1

Then

p(A∩B) = 1/6

Finally :

p(A∪B) = p(A) + p(B) - p(A∩B)

            = 2/6 + 2/6 - 1/6

            = 3/6

            = 1/3

The sides

12-3a

12-3a

4(2a-5)=8a-40

so for perimeter we + them

(12-3a)+(12-3a)+(8a-40)

=

2a-16

The area of the city park will be equal to 3952 square units.

The Area is defined as the space occupied by the two-dimensional geometry in a plane.

We have the following information:-

In City Park, the playground takes up 3/8 of the area:-

[tex]\rm PGA=\dfrac{3}{8}\times CP[/tex]

The soccer field area is 1/3 of the playground area.

[tex]\rm SF=\dfrac{1}{3}\times PGA[/tex]

The product 13×38 can be used to find the area of the soccer field

SF= 13  x  38=494 square units

Noe the PGA will be:-

PGA =3 x SF

PGA= 3 x494=1482 square unit

Now the area of the city park will be calculated as:-

[tex]\rm CP=\dfrac{8}{3}\times PGA\\\\\\CP=\dfrac{8}{3}\times 1482[/tex]

CP=3952 square unit

Hence the area of the city park will be equal to 3952 square units.

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Answer:

if this is 4.88/16 then the answer is 0.305.

Answer:Angle BCE

Step-by-step explanation:

look across from point C

Answer:

56

Step-by-step explanation:

(-2)(-4)(-1)(-7)(1) =

(8)(-1)(-7)(1) =

(-8)(-7)(1) =

(56)(1) = 56

hope this helps

have a good day

Step-by-step explanation:

Q1. volume of a cylinder

Ans. The way you find a volume of a regular object is multiplying the base area by height Here the base area is a circle so formula would be pi times r square (πr^2). To get the volume multiply it by 4. Final answer would be π(3)^2*4

Yes

Step-by-step explanation:

[tex] \cos( \alpha ) = \frac{base}{hypoteneuse} [/tex]

Its just correct..

Answer:

69500

Step-by-step explanation:

[tex]\frac{695000}{x}=\frac{100\%}{10\%}\\\frac{x}{695000}=\frac{10}{100}\\\Rightarrow x=69500[/tex]

Answer:

One-sample Z-test

Step-by-step explanation:

As the sample size is greater than 30, assuming the data is a simple random sample, and that the data has a normal distribution, the sociologist should conduct a one-sample z-test to calculate the p-value.

Answer:

3

Step-by-step explanation:

1/4 of 12 means (1/4) x 12

=> (1/4)x12

=> 12/4

=>  3

Answer: Heyaa! ~

Your Answer would be 3!

Step-by-step explanation:

We can write 1/4 of 12 as 1/4 × 12

To multiply fractions, follow the given steps:

Multiply the numerators.

Multiply the denominators.

Reduce the resultant fraction to its lowest terms.

Now,

1/4 × 12 = (1 × 12) / 4 = 12/4 = 3

Meaning the answer is.. 1/4 of 12 = 3

Hopefully this helps you!

[tex]v = \frac{4}{3} \pi {r}^{3} [/tex]

[tex]v = \frac{4}{3} \times \pi \times {2}^{3} [/tex]

[tex]v = 33.51 \: {m}^{3} [/tex]

[tex]v = \pi {r}^{2} h[/tex]

[tex]v = \pi \times {2}^{2} \times 6[/tex]

[tex]v = 75.40 \: {m}^{3} [/tex]

[tex]v = 75.40 + 33.51[/tex]

[tex]v = 108.91 \: {m}^{3} [/tex]

Hence, the volume of the given compound shape is 108.91 cubic meters.

sphere:

= 33.51 m^3

cylinder:

= 75.40 m^3

all together:

= 108.91 m^3

If x is between two consecutive integers such that n ≤ x < n + 1, then the greatest integer function [x] maps x to the largest integer smaller than x so that [x] = n.

(i) If x is approaching -2 from above, that means x > -2. As x gets closer to -2, we essentially have -2 < x < -1, so that [x] will approach

[tex]\displaystyle \lim_{x\to-2^+} [x] = \boxed{-2}[/tex]

(ii) However, if x is approaching -2 from below, then x < -2, so that [x] = -3. In other words

[tex]\displaystyle \lim_{x\to-2^-} [x] = -3 \neq -2[/tex]

Because the one-sided limits do not match, the two-sided limit

[tex]\displaystyle \lim_{x\to-2} [x] ~~\boxed{\text{does not exist}}[/tex]

(iii) -2.4 lies between -3 and -2, so

[tex]\displaystyle \lim_{x\to-2.4} [x] = \boxed{-3}[/tex]