Write 2 different equations you could use to solve for side m?

The eigenvalues of A are the complex numbers +2i and -2i.The diagonalized form of the matrix B is [1 0 0; 0 1 0; 0 0 -1]

A. A matrix A can be written in the form of

A = [a b; c d]

The eigenvalues λ of A can be calculated using the following formula:

λ = (a+d ± √(a+d)^2 -4(ad-bc))/2

Substituting the values of A gives

λ = (0 + 0 ± √(0)^2 - 4(-2))/2

λ = 2i and -2i

Since the eigenvalues are complex, the matrix cannot be diagonalized over C.

B. The eigenvalues of B can be calculated using the same formula as above

λ = (a+d ± √(a+d)^2 -4(ad-bc))/2

Substituting the values of B gives

λ = (0 + 1 ± √(1)^2 - 4(0))/2

λ = 1, 0, -1

To diagonalize the matrix, we must find the eigenvectors associated with each eigenvalue. The eigenvectors of B can be calculated using the following formula:

v = (a - λI)x

Substituting the values of B and the eigenvalues gives:

v1 = (0 - 1I)x

v2 = (0 - 0I)x

v3 = (0 - (-1I))x

The eigenvectors are

v1 = [1 0 0]

v2 = [1 0 0]

v3 = [0 1 0]

The diagonalized form of the matrix B is

[1 0 0; 0 1 0; 0 0 -1]

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The probability is 2.54%.

The formula of the favorable outcome over the total outcomes is used to describe probability.

given, There are several marbles of different colors in a bag in front of you. Your job is to select three marbles and record the color of each marble you chose. In the bag, there are 22 blue marbles, 17 red marbles, 8 yellow marbles, and 3 purple marbles.

The final probability if conditions are not dependent on each other is multiple possibilities of happening these events.

Probability of getting desired outcomes = (17 / 50) (8/49) ( 22/48)

Therefore the probability of selecting one red marble, one yellow marble, and a blue marble is 2.54%.

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If the correlation coefficient is 4, the percentage of variation in the dependent variable explained by the estimated regression equation is 16%.

The correlation coefficient is a measure of linear association between two variables, usually denoted by r. A correlation coefficient of 4 indicates a strong positive linear relationship between the two variables.

A correlation coefficient of 4 does not give any indication as to the percentage of variation in the dependent variable explained by the estimated regression equation. To find this percentage, we must use the coefficient of determination, denoted by r2.

The coefficient of determination is the square of the correlation coefficient and can be interpreted as the percentage of the variance in the dependent variable that is explained by the estimated regression equation.

Hence, in this case, r2 would be 16, indicating that the estimated regression equation explains 16% of the variance in the dependent variable.

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By The length of the curve can be found using the formula for the arc length of a parametric curve, the distance traveled by the particle is 30π.

The length of the curve can be found using the formula for the arc length of a parametric curve:

L = ∫0→5p √(dx/dt)2 + (dy/dt)2 dt

We can calculate dx/dt and dy/dt as follows:

dx/dt = 6sin(t)cos(t)

dy/dt = -6sin(t)cos(t)

Substituting these values into the formula for the arc length gives us:

L = ∫0→5p √[(6sin(t)cos(t))2 + (-6sin(t)cos(t))2] dt

= ∫0→5p 6√(sin2(t)cos2(t)) dt

= 6∫0→5p |sin(t)cos(t)| dt

= 6∫0→5p sin(t)cos(t) dt

= 6[(1/2)sin2(t) + (1/2)cos2(t)]5p

= 6[(1/2)(1) + (1/2)(1)]5p

= 6(1)5p

= 30π

Therefore, the distance traveled by the particle is 30π.

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The value of the equation is [tex]A = (\sqrt{63x}^{(11yz)^1^0}[/tex]

What is an Equation?

Equations are mathematical statements with two algebraic expressions flanking the equals (=) sign on either side.

It demonstrates the equality of the relationship between the expressions printed on the left and right sides.

Coefficients, variables, operators, constants, terms, expressions, and the equal to sign are some of the components of an equation. The "=" sign and terms on both sides must always be present when writing an equation.

Given data ,

Let the equation be represented as A

Now , the value of A is given by

Root of 63x to the power of 11 yz to the power of 10

The value of root of 63x = [tex]\sqrt{63x}[/tex]

Now , the value of root of 63x to the power of 11 yz is

The value of root of 63x to the power of 11 yz = [tex](\sqrt{63x}^{(11yz)[/tex]

And ,

The value of root of 63x to the power of 11 yz to the power of 10 is

Value of root of 63x to the power of 11 yz to the power of 10 is [tex](\sqrt{63x}^{(11yz)^1^0}[/tex]

Therefore , the value of A is [tex](\sqrt{63x}^{(11yz)^1^0}[/tex]

Hence , The value of the equation is [tex]A = (\sqrt{63x}^{(11yz)^1^0}[/tex]

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The graph of the linear inequation [tex]y \leq \frac{1}{2}x -5[/tex] has been described below

What is linear inequation?

Inequation shows the comparision between two algebraic expressions by connecting the two algebraic expressions by

[tex]> , < , \geq, \leq[/tex]

A one degree inequation is known as linear inequation.

The given linear inequation is

[tex]y \leq \frac{1}{2}x -5[/tex]

Here equality is maintained. So the line is a solid line

Now, (0, 0) does not satisfy the inequality.

So the solution is below the line

When graphing the inequality above, we will draw a solid line and the solution lies below the line

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Answer to the problem:

4/9, 1/3 x 1/3, 2/3 x 2/3

Answer:

10.3

Step-by-step explanation:

10.29 rounded to the nearest tenth is 10.3.

The indirect proof that defines triangle RVS is not equilateral is explained below.

How triangle look like?

In math, A triangle is a closed, 2-dimensional shape with 3 sides, 3 angles, and 3 vertices and also a polygon.

Here we need to find the indirect proof for the triangle RVS which is not equilateral.

Here we know that, We need to write an indirect proof in paragraph proof.

For, the given statement, △RVT and SVT are equilateral; 

And △RVS is not equilateral.

Then the explanation for this one is written as,

Let us assume temporarily that △RST is equilateral.

And we have given that △RVT and SVT are equilateral, then the sides of △RVT, SVT, and RST are congruent.

Therefore, RV≅VSRS which follows that △RVS is equilateral.

In contradicts the given that △RVS is not equilateral, then the temporary assumption must be false. It follows that △RST is not equilateral.

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As per the estimated percentage, the test statistic is 0.6167 or 61.67%

The term percentage is defined as the number or ratio that can be expressed as a fraction of 100.

Here we have given that in Arkansas than Virginia. the sample results show that, rounded to two decimal places, the estimated percentage of Arkansas residents who were born there is %. the sample results also show that, rounded to two decimal places, the estimated percentage of Virginia residents who were born there is %.

And we need to find the test statistics.

While we looking into the given situation we have identified the following values,

=> H0 : p = 0.577

=> Ha : p ≠ 0.577

Now, we have estimate the proportion of stay-at-home residents in Arkansas is calculated as,

Here the Proportion of stay-at-home residents in Arkansas is written as,

=> p = 74/120 = 0.6167

Therefore, the test statistics is 0.6167.

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The population is the number of children in gymnastic class = 5.

A parameter is the mean number of steps taken by the 5 children.

What is a parameter?

Four parameters, referred to as hybrid or h Parameters, can be used to assess any linear circuit with input and output terminals. These parameters are one measured in ohm, one in mho, and two dimensionless. Hybrid is short for "mixed." These parameters are referred to as hybrid parameters since they have dual dimensions

Here, we have

Given that,

Suppose that there are 5 children in a gymnastics class.

One day, they count the number of steps each person takes while walking on their hands until they lose balance and come down.

The mean number of steps these children took while walking on their hands is 20 steps.

We have to find the population and parameters.

The area of interest is a particular gymnastic class, therefore all individuals or children belonging to this particular gymnastic class make up the population.

Population = number of children in gymnastic class = 5.

Parameter = mean number of steps taken by the 5 children.

Hence, Population is the number of children in gymnastic class = 5.

A parameter is the mean number of steps taken by the 5 children.

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By taking minimum perimeter the value of length and width will both be [tex]\sqrt{5A}[/tex].

Perimeter is basically the sum of all sides of a figure.

The perimeter of a rectangle is 2l + 2w where l = length and w = width of rectangle.

Since the perimeter needed in this question is minimum, the figure must be a square and not a rectangle. For a square, area = a^2

5A = a^2

a = l = w = [tex]\sqrt{5A}[/tex]

Hence, both the length and width are equal to [tex]\sqrt{5A}[/tex].

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Answer:

146

Step-by-step explanation:

the sides of a triangle always equal 180, so just subtract those numbers from 180

The correct option is C ie 3.

D is the midpoint of BC.

What is Congruence of triangles?

Two triangles are said to be congruent if all three corresponding sides are equal and all the three corresponding angles are equal in measure.

What are the congruency properties of a triangle?

SSS (Side-Side-Side)

SAS (Side-Angle-Side)

ASA (Angle-Side-Angle)

AAS (Angle-Angle-Side)

RHS (Right angle-Hypotenuse-Side)

In triangles BAD and CAD,

(i) AD=AD (common)

(ii)∠DAB=∠CAD (Given, AD bisects ∠BAC)

(iii)AB = AC (given)

Thus, by SAS property both the triangles BAD and CAD are congruent .

By cpct , ∠ADB=∠ADC = x (let)

Since ∠ADB and ∠ADC lies in a straight line

So by the property of straight lines the sum is 180°.

Now  ∠ADB+∠ADC= 180°

          ⇒x+x= 180°

          ⇒2x= 180°

          ⇒x=90°

∴AD ⊥ BC

By cpct ,BD=DC

So D is the midpoint of BC.

Hence option C that is 3 is the right answer.

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The 90% confidence interval for the population mean is given as follows:

(18.75, 22.51).

The t-distribution is used when the standard deviation for the population is not known, and the bounds of the confidence interval are given according to the following rule:

[tex]\overline{x} \pm t\frac{s}{\sqrt{n}}[/tex]

In which the variables of the equation are presented as follows:

The critical value, using a t-distribution calculator, for a two-tailed 90% confidence interval, with 16 - 1 = 15 df, is t = 1.7531.

From the sample given in this problem, the parameters are as follows:

[tex]\overline{x} = 20.63, s = 4.3, n = 16[/tex]

Then the lower bound of the interval is given as follows:

20.63 - 1.7531 x 4.3/4 = 18.75.

The upper bound of the interval is of:

20.63 + 1.7531 x 4.3/4 = 22.51.

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In this case, the coefficient of determination is 0.5297, which means that 53% of the sample variation in Final grades is explained by the sample regression equation.

The data file contains the midterm and final scores of 32 students in a statistics course. To estimate a student's final score as a function of their midterm score, we used a regression analysis. The regression equation was Final = 27.5818 + 0.6774 Midterm. This equation can be used to predict the final score of a student based on their midterm score. The standard error of the estimate was 14.947. This indicates the accuracy of the estimated final score. The coefficient of determination was 0.5297, which means that 53% of the sample variation in final grades is explained by the regression equation. This tells us that the regression equation is a relatively good predictor of a student's final score.

Given:

Midterm Score = x

Final Score = y

Regression Equation: y = 27.5818 + 0.6774x

Standard Error of the Estimate = 14.947

Coefficient of Determination = 0.5297

Calculating Final Score:

y = 27.5818 + 0.6774x

y = 27.5818 + 0.6774(x)

y = 27.5818 + 0.6774(x)

y = 27.5818 + 0.6774(x)

y = 27.5818 + 0.6774x

Final Score = 27.5818 + 0.6774(Midterm Score)

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Let X and Y be IID Unif(0, 1). the distance between X and Y.Expected value: 0 and Standard deviation: [tex]$\sqrt{\frac{1}{3}}$[/tex]

Expected value:

E(X-Y)

= E(X) - E(Y) = 0 - 0 = 0

Standard deviation:

Var(X-Y) = Var(X) + Var(Y) = 1 + 1 = 2

SD(X-Y) = [tex]$\sqrt{2}$ \\[/tex] [tex]= $\sqrt{\frac{1}{3}}$[/tex]

The expected value of X-Y is the difference of the expected values of X and Y, which are both 0 since they are both IID Unif(0, 1). The variance of X-Y is the sum of the variances of X and Y, which are both 1. Since the standard deviation is the square root of the variance, the standard deviation of X-Y is the square root of 2

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Answer:

B

Step-by-step explanation:

Subtract $1.95 from $12 to account for the flat rate that Jason must pay, then divide that by 0.55, or the per mile charge. The answer, or the highest amount of miles he can go with $12, is 18.27272727. The answer that best represents the number of miles he can go is B because he can go up to 18 miles, including 18 miles, hence the closed circle.

In triangle PQR , the value of x and y is equal to 90° and 85° respectively.

As given in the question,

In the given triangle PQR,

Measure of ∠R = 5°

From the diagram,

PQ ≅ QR

⇒ ∠P ≅ ∠R

⇒m ∠P = m ∠R

⇒m ∠P = 5°

In ΔPQR,

∠P + ∠Q + ∠R = 180°

⇒ 5° + ∠Q + 5° = 180°

⇒ ∠Q = 170°

From the diagram,

y° = (1/2) ( ∠Q)

 = 170°/2

 = 85°

∠P + y° + x° = 180°

⇒ 5° + 85° + x° = 180°

⇒ x° = 180° - 90°

⇒ x° = 90°

Therefore, in triangle PQR the measure of x° and y° is equal to 90° and 85° respectively.

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Answer:

20=-7

Step-by-step explanation:

j

Answer:

8 Laps

Step-by-step explanation:

This is because one lap is 1/4 so it would take 4 laps to make it a whole, which would be a mile.

We could now times this by two, since 1 mile is half of 2 miles.

4 x 2 = 8

Which would make it 8

Finding the t statistic is necessary to check the normality of a five-class observed frequency distribution.

The t-value gauges the magnitude of the difference in relation to the range of your sample's data. Or to put it another way, T is just the calculated difference shown in units of standard error. The evidence is stronger against the null hypothesis the larger the value of T.

In general, t-values that are more than +2 or less than -2 are acceptable. We are more confident in the coefficient's ability to predict outcomes the higher the t-value. Low t-values are a sign of the predictability of that coefficient's coefficient being unreliable.

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The worker's marginal cost of education when e=0.5 is 6.00. the derivative of the cost function with respect to the amount of education obtained.

The worker's marginal cost of education is the rate of change in the cost of obtaining education with respect to the amount of education obtained. In this case, the worker's cost of obtaining education is given by the equation c(e)=3e². At e=0.5, we can calculate the marginal cost of education by taking the derivative of the cost function with respect to the amount of education obtained. This gives us the equation c'(e)=6. Thus, the worker's marginal cost of education when e=0.5 is 6.00.

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Answer:

The exact value of x so that the greatest possible amount of light is emitted is 8.96ft.

What is the perimeter of a semicircle?

The perimeter of a semicircle is half that of a circle, that is [tex]\pi r[/tex], where r is the radius of the circle.

Step-by-step explanation:

Given the width of the rectangle is x, let the height of the rectangle be y.

The radius of the semicircle is x/2.

The perimeter of the window is equal to [tex]2y+x+\pi \frac{x}{2} =32[/tex].

The area of the window is [tex]xy+\frac{1}{2}(\pi )(\frac{x}{2})^2=xy+\frac{\pi x^2}{8}[/tex].

We can insert into the formula for the area to obtain the area in terms of only x by solving the equation for the perimeter of y in terms of x.

[tex]2y=32-(1+\frac{\pi }{2} )x=32-(\frac{2+\pi }{2} )x\\y=16-(\frac{2+\pi }{4} )x[/tex].

Now the area of the window in terms of only x is:

Area=[tex]16x-(\frac{2+\pi }{4} )x^2+\frac{\pi x^2}{8}[/tex].

Since it is given in the question that maximum light should be admiitted, we will differentiate the Area and set it to 0.

[tex]16-2(\frac{2+\pi }{4} )x+\frac{\pi x}{4}=0\\ 16=x(1+\frac{\pi }{4})\\ x=\frac{16}{1+\frac{\pi }{4}} \\x=8.96ft[/tex].

Therefore the exact value of x is 8.96ft.

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What is K in algebraic?

Algebraic K-theory is a subject area in mathematics with connections to geometry, topology, ring theory, and number theory. Geometric, algebraic, and arithmetic objects are assigned objects called K-groups. These are groups in the sense of abstract algebra.

What does K mean in mathematics?

K is derived from the Greek word kilo, which signifies 1,000. The Greeks similarly referred to a million as M, which stands for Mega. Therefore, if we adhere to the Greek abbreviations, billion would be represented by the letter G. (Giga).

Give some examples of what algebraic expressions are.

image outcome

An expression constructed using integer constants, variables, and algebraic operations is known as an algebraic expression in mathematics (addition, subtraction, multiplication, division and exponentiation by an exponent that is a rational number). A good example of an algebraic expression is 3x2 2xy + c.

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[tex]-2 + 6.45z - 6 + (-3.25z)[/tex]

Combine Like Terms:

[tex](6.45z+-3.25z)+(-2+-6)[/tex]

[tex]\fbox{3.2z - 8}[/tex]

Answer:

x = 1

Step-by-step explanation:

2x + 8 = 10  Subtract 8 from both sides

2x + 8 - 8 = 10 - 8

2x = 2  Divide both sides by 2

[tex]\frac{2x}{2}[/tex] = [tex]\frac{2}{2}[/tex]

x = 1

Check:

2x + 8 = 10

2(1) + 8 = 10

2 + 8 = 10

10 = 10 checks.

function dhdt = propt(t,h) %propt calculates the rate of change of the height of the liquid in the bucket given , %Define the initial condition h0 = 10; %Define the time span tspan = 0:120 with height of the water.

Function file 1:

function dhdt = propt(t,h) %propt calculates the rate of change of the height of the liquid in the bucket given by dhdt = -1.4h %Inputs: %t = time %h = height of the liquid in the bucket %Output: %dhdt = rate of change of the height of the liquid in the bucket dhdt = -1.4*h; end

Function file 2:

function dhdt = toricelli(t,h) %toricelli calculates the rate of change of the height of the liquid in the bucket given by dhdt = -K*sqrt(h) %Inputs: %t = time %h = height of the liquid in the bucket %Output: %dhdt = rate of change of the height of the liquid in the bucket K = 1.4; dhdt = -K*sqrt(h); end

Script file:

clear; close all; clc; %Define the initial condition h0 = 10; %Define the time span tspan = 0:120;

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For states, n = 1, 2, and 3 the probability of finding the particle at left 1/3rd of the box is P₁ = (3/4) * (2/L)²    P₂ = (1/4) * (2/L)²    and    P₃ = (1/3) * (2/L)²  respectively

a.

The wave function for the particle in a rigid box of length L for the state

n = 1, is given by:

|ψ₁(x)|² = (2/L)² * sin²(πx/L)

the wave function for the state n = 2,  is given by:

|ψ₂(x)|² = (2/L)² * sin²(2πx/L)

And the wave function for the state n = 3, is given by:

|ψ₃(x)|² = (2/L)² * sin²(3πx/L)

The graphs of |ψ₁(x)|², |ψ₂(x)|², and |ψ₃(x)|² is attached.

b.

The points of maximum probability density, which occur at x = 0 and       x = L for all three states are the positions at which the particle is most likely to be found.

c.

The points of minimum probability density, occur at x = L/2 for the state

n = 1, and at x = L/4 and x = 3L/4 for the state n = 2. For the state n = 3, the points of minimum probability density occur at x = L/3, x = 2L/3, and

x = L are the positions at which the particle is least likely to be found.

d.

Since the probability density is highest at x = 0, which is in the left one-third of the box for the state n = 1 the probability of finding the particle in the left one-third of the box is greater than 1/3.

Since the probability density is highest at x = 0 and x = L, which are both outside the left one-third of the box for the state n = 2, the probability of finding the particle in the left one-third of the box is less than 1/3.

Since the probability density is highest at x = 0, which is in the left one-third of the box for the state n = 3, the probability of finding the particle in the left one-third of the box is equal to 1/3.

e.

We need to integrate the probability density over the region of interest to calculate the probability that the particle will be found in the left one-third of the box for each of the states n = 1, n = 2, and n = 3.

the probability for the state n = 1,  is given by:

P₁ = ∫ |ψ₁(x)|² dx = (2/L)² * ∫ sin²(πx/L) dx

The probability for the state n = 2,  is given by:

P₂ = ∫ |ψ_2(x)|² dx = (2/L)² * ∫ sin²(2πx/L) dx

The probability for the state n = 3,  is given by:

P₃ = ∫ |ψ₃(x)|² dx = (2/L)² * ∫sin²(3πx/L) dx

Here all integrals have limits 0 and L/3

Solving these integrals gives:

P₁ = (3/4) * (2/L)²

P₂ = (1/4) * (2/L)²

P₃ = (1/3) * (2/L)²

Thus, the probabilities that the particle will be found in the left one-third of the box are:

P₁ = (3/4) * (2/L)²

P₂ = (1/4) * (2/L)²

P₃ = (1/3) * (2/L)²

for the states n = 1, n = 2, and n = 3, respectively.

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