Would someone like to help me with my math homework and the math is College for Readiness?
I will mark you BRAINLIEST

Less than = <

Quotient= Division

4 divided by X(unknown) will be LESS than -1

Answer---> X divided by 4 < -1

Answer:

[tex]C. \frac{1}{2} \times \frac{5}{4} [/tex]

Answer:

3/5

First you would need to find the greatest common factor of 15 and 25

which is 5

Then divide the numerator and denominator by the GCF

15 divided by 5

25 divided by 5

Then simplify your answer is

3/5

Answer:

5/12

Step-by-step explanation:

im finding answers for hegarty maths and i got it wrong and it said 5/12 was the answers

thank me later

Answer:

2/36

Step-by-step explanation:

i found it on another website

Answer:

1/5 or 0.2 of the whole pizza

but it says that theres only 3/4 of the pizza there. so 3/4 of a pizza eaten by 5 people each person would get 0.15 of the pizza

Step-by-step explanation:

Answer: 11. D 12.d 13. A

Step-by-step explanation:

Answer:

Evern though this isn’t a math question, I’ll still help you :)

11. Option D

12. Option D

13. Option B

Hope this helps! :)

Answer: 217 :D I think I did mental math so I might be wrong

Step-by-step explanation:

Answer:

21 (not even joking)

Explanation:

4/6 = .6 repeating

.6 x 32 = 21.3 which rounds to 21

Answer:

[tex]\mathbf{((lnx)(2x^2)) -x^2 +39 =(2y^2 +(\dfrac{4}{3})(8+y^2)^{3/2})}[/tex]

Step-by-step explanation:

Given that:

[tex]x In(x) = y( 1+ \sqrt{8+ y^2}) \ } \ \dfrac{dy}{dx}[/tex]

[tex]xln(x) *dx= (y+y \sqrt{(8+y^2}) \ dy[/tex]

[tex]\int xln(x) dx = \int(y+y\sqrt{(8+y^2})) \ dy[/tex]

[tex]\int lnx (x)dx =(\dfrac{y^2}{2} +\dfrac{1}{3}(8+y^2^{)3/2})[/tex]

[tex](lnx \dfrac{x^2}{2})-\int((\dfrac{x^2}{2})\times \dfrac{1}{x} =(\dfrac{y^2}{2} +\dfrac{1}{3}(8+y^2)^{3/2})[/tex]

[tex]((lnx)(\dfrac{x^2}{2}))-\int(\dfrac{x}{2}) =(\dfrac{y^2}{2} +(\dfrac{1}{3})(8+y^2)^{3/2})[/tex]

[tex]((lnx)(\dfrac{x^2}{2}))-(\dfrac{x^2}{4}) +C= (\dfrac{y^2}{2 }+(\dfrac{1}{3})(8+y^2)^{3/2})[/tex]

For  y(1) = 1

[tex]((ln(1))(\dfrac{1^2}{2}))-(\dfrac{1^2}{4}) +C= (\dfrac{1^2}{2 }+(\dfrac{1}{3})(8+1^2)^{3/2})[/tex]

[tex](0)-(\dfrac{1}{4}) +C =(\dfrac{1}{2} +(\dfrac{1}{3})(3)^3)[/tex]

[tex]C=(\dfrac{19}{2}) +(\dfrac{1}{4})[/tex]

[tex]C=\dfrac{39}{4}[/tex]

[tex]((lnx)(\dfrac{x^2}{2}))-(\dfrac{x^2}{4}) +(\dfrac{39}{4}) = (\dfrac{y^2}{2} +(\dfrac{1}{3})(8+y^2)^{3/2})[/tex]

[tex]\mathbf{((lnx)(2x^2)) -x^2 +39 =(2y^2 +(\dfrac{4}{3})(8+y^2)^{3/2})}[/tex]

Answer:

the is option d cause big number is divided by small ones.

Step-by-step explanation:

hope it's right

Answer:

Step-by-step explanation:

y = 10/4 x

y = 2.5 x

Answer:

Any constant that is set to equal x would have an undefined slope.  For example, x=0 is just a horizontal line, so the slope is undefined.  

Step-by-step explanation:

The slope would be undefined because in a horizontal line, the length could be anything, but there is no distance between x-values.

Answer:

X=0

Step-by-step explanation:

Answer:

Its BELOW sea level

Step-by-step explanation:

The required value is [tex]\csc A=\dfrac{5}{4}[/tex].

Important information:

We need to find the exact value of csc A.

Formulae used: If angle A is in Quadrant I.

[tex]\cos A=\dfrac{1}{\sec A}[/tex]

[tex]\sin A=\sqrt{1-\cos^2 A}[/tex]

[tex]\csc A=\dfrac{1}{\sin A}[/tex]

Using these formulae, we get

[tex]\cos A=\dfrac{3}{5}[/tex]

And,

[tex]\sin A=\sqrt{1-\left(\dfrac{3}{5}\right)^2}[/tex]

[tex]\sin A=\sqrt{1-\dfrac{9}{25}}[/tex]

[tex]\sin A=\sqrt{\dfrac{16}{25}}[/tex]

[tex]\sin A=\dfrac{4}{5}[/tex]

Now,

[tex]\csc A=\dfrac{1}{\sin A}[/tex]

[tex]\csc A=\dfrac{1}{\frac{4}{5}}[/tex]

[tex]\csc A=\dfrac{5}{4}[/tex]

Thus, the required value is [tex]\csc A=\dfrac{5}{4}[/tex].

Find out more about 'Trigonometric Ratios' here:

https://brainly.com/question/2263794

The required value of cscA is 1.25

Given,

[tex]secA=\frac{5}{3}[/tex]

Trigonometrical ratios:

In the first quadrant, all ratios are positives.

[tex]sin A=\frac{P}{H}[/tex]

And the value of hypotenuse is,

[tex]P=\sqrt{H^2-B^2} \\=\sqrt{5^2-3^2} \\=\sqrt{16}\\ P=4[/tex]

So, the sine A is,

[tex]sinA=\frac{P}{H}\\ =\frac{4}{5}[/tex]

So, the rational denominator is,

[tex]cscA=\frac{H}{P}\\ =\frac{5}{4}\\=1.25[/tex]

Learn More about Trigonometrical ratios:

https://brainly.com/question/24349828

Answer:

X = 9

Step-by-step explanation:

Answer:

x = 9

Step-by-step explanation:

Move all terms that don't contain x to the right side and solve.

Answer:

[tex]F' = (-3,-3)[/tex]

[tex]G' = (-3,3)[/tex]

[tex]H' = (6,-3)[/tex]

Step-by-step explanation:

Given

The attached graph

[tex]Scale\ Factor = 1\frac{1}{2}[/tex]

Required

Determine the coordinates of F'G'H'

First, we need to get the coordinate of F, G and H from the graph

[tex]F = (-2,-2)[/tex]

[tex]G = (-2,2)[/tex]

[tex]H = (4,-2)[/tex]

The dilated coordinate is then calculated as:

[tex](FGH)' = (FGH) * Scale\ Factor[/tex]

This gives:

[tex]F' = (-2,-2) * 1\frac{1}{2}[/tex]

[tex]F' = (-2* 1\frac{1}{2},-2* 1\frac{1}{2})[/tex]

[tex]F' = (-3,-3)[/tex]

[tex]G' = (-2,2) * 1\frac{1}{2}[/tex]

[tex]G' = (-2 * 1\frac{1}{2},2 * 1\frac{1}{2})[/tex]

[tex]G' = (-3,3)[/tex]

[tex]H' = (4,-2) * 1\frac{1}{2}[/tex]

[tex]H' = (4 * 1\frac{1}{2},-2 * 1\frac{1}{2})[/tex]

[tex]H' = (6,-3)[/tex]

The equation that represents the amount in dollars that she must pay for using the parking lot that month is y = 2x +10, the correct option is B.

An equation is a mathematical statement formed when two algebraic expressions are equated using an equal sign.

The equations are useful in determination of unknown parameters.

The equations are of various types, such as Trigonometric equations, quadratic equations.

The amount Tanesha pays to use the parking lot is $10

The daily amount she pays to use the parking is $2

Let x represents the days in one month.

Let y represents the amount in dollars that she must pay for using the parking lot that month.

The unknown parameters are x and y

The equation that can be formed is

y = 2x +10

It seems that your question is incomplete, the complete question is as follows:

A .  y = 2x

B. y = 2x +10

C. y = 10x +2

D. y = 10x

To know more about Equation

https://brainly.com/question/10413253

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Answer:

No Solution.

X cannot equal anything in order for these to be equal.

Step-by-step explanation:

Answer:

ok? if the question is how many words does he type in a minute the answer is 72

Step-by-step explanation:

Answer:

72 is right i check

Step-by-step explanation:

he/she comment the same so it was there idea

Answer:

C multiply by 3, then subtract 5      

B

C m<7

Step-by-step explanation:

Answer: 2.5

Step-by-step explanation:

For this problem, we see that 4km is 1/2 of 8km.

So, we will have to find 1/2 of 5km.

1/2 of 5km = 2.5km

Your answer is 2.5km

Answer:

2.48548 Miles or simplified 2.5

Step-by-step explanation:

You Divide by 1.609 to find the answer.  

Answer:

i  need points

Step-by-step explanation:

i need points ,, hope you find your answer

31.286 i think that its 31.286 bc welp me smart

Answer:

Step-by-step explanation:

Dimensions of the diagram:

Nadia is correct as the diagram of 27 cm × 20 cm will fit in A4 paper

Answer:

A

Step-by-step explanation:

Answer:

y = 4 x - 7

The slope is the number multiplied by x, 4

Step-by-step explanation:

;-;

Answer:

The answer is C

Step-by-step explanation:

Using the symbols in the Venn diagram, we want to find A given that

B = 16

C = 15

D = 30

and given that 25 students don't take any of these courses.

There are 200 students total, so we need to have A plus the total number of students given in the diagram sum to 200. This means

(math only) + (English only) + (biology only) + (math and English, no biology) + (math and biology, no English) + (English and biology, no math) + (all three) + (none of the three) = 200

or

12 + 11 + 16 + 30 + A + 16 + 15 + 25 = 200

Solve for A to get A = 75, making the answer C.

Answer:

11

Step-by-step explanation:

Answer:

11

Step-by-step explanation:

Answer:

x = 11

y = 8

z = 42

Step-by-step explanation:

From the given figure

∵ l[tex]_{1}[/tex] and l[tex]_{2}[/tex] intersected at a point

∴ ∠1 and ∠4 are vertically opposite angles

→ Vertically opposite angles are equal in measures

∴ m∠1 = m∠4

∵ m∠1 = 4(3y - 12)°

∵ m∠4 = (8y - 16)°

→ Equate their measures

∵ 4(3y - 12) = 8y - 16

∴ 4(3y) - 4(12) = 8y - 16

∴ 12y - 48 = 8y - 16

→ Subtract 8y from both sides

∵ 12y - 8y - 48 = 8y - 8y - 16

∴ 4y - 48 = -16

→ Add 48 to both sides

∴ 4y - 48 + 48 = -16 + 48

∴ 4y = 32

→ Divide both sides by 4

∴ y = 8

∵ ∠4 and ∠5 formed a pair of linear angles

→ The sum of the measures of the linear angles is 180°

∴ m∠4 + m∠5 = 180°

∵ m∠5 = (12x)°

∵ m∠4 = 8(8) - 16 = 64 - 16 = 48°

→ Add them and equate the sum by 180

∵ 48 + 12x = 180

→ Subtract 48 from both sides

∴ 48 - 48 + 12x = 180 - 48

∴ 12x = 132

→ Divide both sides by 12

∴ x = 11

∵ ∠4, ∠3, and ∠2 formed a line

∴ ∠4, ∠3, and ∠2 are linear angles

→ The sum of the measure of the linear angles is 180°

∴ m∠4 + m∠3 + m∠2 = 180°

∵ m∠4 = 48°

∵ m∠3 = 3(11) + 9 = 33 + 9 = 42°

∵ m∠2 = (2z + 6)

→ Add them and equate the sum by 180

∵ 48 + 42 + 2z + 6 = 180

→ Add the like terms in the left side

∴ 96 + 2z = 180

→ Subtract 96 from both sides

∵ 96 - 96 + 2z = 180 - 96

∴ 2z = 84

→ Divide both sides by 2

∴ z = 42