Within the nebula that was the start of our solar system, a shock wave from an exploding supernova triggered dust particles to be drawn together to form a dense spherical cloud. The accumulation of dust set off a chain reaction. As the core of the cloud attracted more dust, its gravitational pull increased. As this pull increased so did all BUT its

[tex]\rm{\gray{\underline{\underline{\blue{GIVEN:-}}}}}[/tex]

[tex]\rm{\gray{\underline{\underline{\blue{TO\:FIND:-}}}}}[/tex]

[tex]\rm{\gray{\underline{\underline{\blue{SOLUTION:-}}}}}[/tex]

We have know that,

[tex]\green\bigstar\:\rm{\gray{\overbrace{\underbrace{\red{S\:=\:ut\:+\:\dfrac{1}{2}\:at^2\:}}}}}[/tex]

Where,

[Note :- Here, acceleration is ‛acceleration due to gravity’ .]

=> S = 1/2 × 10 × (3)^2

=> S = 5 × 9

=> S = 45m -----(1)

✒ If the ball takes ‛n’ second to fall the ground, then distance covered in nth second is,

[tex]\green\bigstar\:\rm{\gray{\overbrace{\underbrace{\red{S_n\:=\:u\:+\:\dfrac{g}{2}\:(2n\:-\:1)\:}}}}}[/tex]

=> Sn = 0 + 10/2 (2 × n - 1)

=> Sn = 5 (2n - 1)

=> Sn = 10n - 5 -----(2)

Therefore,

=> 10n = 45 + 5

=> n = 50/10

=> n = 5

Now put the value of ‛n = 5’ in equation(2), we get

=> Sn = 10 × 5 - 5

=> Sn = 50 - 5

=> Sn = 45m

[tex]\rm{\pink{\therefore}}[/tex] The height of the journey is “ 45m ” .

Answer:

A) The distance between the stations is 1430m

B) The time it takes the train to go between the stations is 80s

Explanation:

First we will calculate the distance covered for the first 20s.

From one the equations of kinematics for linear motion

[tex]S = ut + \frac{1}{2}at^{2} \\[/tex]

Where [tex]S[/tex] is distance traveled

[tex]u[/tex] is the initial velocity

[tex]t[/tex] is time

and [tex]a[/tex] is acceleration

Since the train starts from rest, [tex]u[/tex] = 0 m/s

Hence,  for the first 20s

[tex]a =[/tex] 1.1 m/s²; [tex]t =[/tex] 20s,  [tex]u[/tex] = 0 m/s

∴ [tex]S = ut + \frac{1}{2}at^{2} \\[/tex] gives

[tex]S = (0)(20) + \frac{1}{2}(1.1)(20)^{2}[/tex]

[tex]S = \frac{1}{2}(1.1)(20)^{2}[/tex]

[tex]S =[/tex] 220m

This is the distance covered in the first 20s.

Now, we will calculate the speed attained here

From

[tex]v = u +at[/tex]

Where [tex]v[/tex] is the final velocity

Hence,

[tex]v = 0 + 1.1(20)[/tex]

[tex]v = 1.1(20)[/tex]

[tex]v =[/tex] 22 m/s

This is the constant speed attained when it proceeds for 1100m

We can calculate the distance covered while slowing down from

[tex]v^{2} = u^{2} + 2as[/tex]

The initial velocity, [tex]u[/tex] here will be the final velocity before it started slowing down

∴[tex]u[/tex] = 22 m/s

The final velocity will be 0, since it came to a stop.

∴ [tex]v[/tex] = 0 m/s

[tex]a = -[/tex]2.2 m/s² ( - indicates deceleration)

Hence,

[tex]v^{2} = u^{2} + 2as[/tex] gives

[tex]0^{2} =22^{2} +2(-2.2)s[/tex]

[tex]0=22^{2} - (4.4)s\\4.4s = 484\\s = \frac{484}{4.4} \\s = 110m[/tex]

This is the distance traveled while slowing down.

A) The distance between the stations is

220m + 1100m + 110m

= 1430m

Hence, the distance between the stations is 1430m

B) The time it takes the train to go between the stations

The time spent while accelerating at 1.1 m/s² is 20s

We will calculate the time spent when it proceeds at a constant speed of 22 m/s for 1100m,

From,

[tex]Speed =\frac{Distance}{Time}\\[/tex]

Then,

[tex]Time = \frac{Distance}{Speed}[/tex]

[tex]Time = \frac{1100}{22}[/tex]

Time = 50 s

And then, the time spent while decelerating (that is, while slowing down)

From,

[tex]v = u + at\\0 = 22 +(-2.2)t\\2.2t = 22\\t = \frac{22}{2.2} \\t= 10 s[/tex]

This is the time spent while slowing down until it stops at the station.

Hence, The time it takes the train to go between the stations is

20s + 50s + 10s = 80s

The time it takes the train to go between the stations is 80s

ANYTHING that's dropped near the Earth's surface and isn't affected by air resistance falls 9.8 m/s faster at any time than it did 1 second earlier.

0.5 second after it was dropped with zero speed, it's falling at

(0.5) x (9.8 m/s)  =  4.9 m/s .

It makes no difference which building it was dropped from.

Answer:

The answer is A.

Explanation:

Electrons are found outside of a nucleus.

Answer:

I am pretty sure its C

Explanation:

Answer:

350 miles

Explanation:

because multiply 70 times 5 and you will get 350

Answer:

35700000

Explanation:

multiply the meter value by 1e+9

Answer:

35700000 nanometers

Explanation:

Answer:

A wave in which the medium vibrates at right angles to the direction of the propagation is called transverse wave.

Answer:

In a closed-loop system, matter is used to generate energy, and the energy generated is used to produce matter, and the cycle goes on without end.

Explanation:

A closed-loop system is one in which materials or energy is recycled without end through a production cycle. This means that a raw material is used to produce a finished product, and the finished product at the end of its use cycle is converted back and used as a raw material to produce more of it again. Energy and matter can also be cycled in the same way in an energy and matter closed-loop system, converting matter to energy, and the energy is put back into the production of more of the matter.

In a closed system loop, the matter has been recycled to provide raw material and form new products. The energy formed by the product has been recycled by being used by the raw materials for the formation of new products.

The closed system loop can be defined as the system in which the products and energy has been recycled continuously to form more products. The energy has been formed in the closed system loop, that can be utilized by the raw materials for the production of energy.

The products formed after reaching the equilibrium of the formation, and dissociation reaches the point, and starts to dissociate to provide the raw material to the system.

Thus, in a closed system loop, the matter has been recycled to provide raw material and form new products. The energy formed by the product has been recycled by being used by the raw materials for the formation of new products.

For more information about a closed system loop, refer to the link:

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Answer:

1.53 m/s²

Explanation:

Given:

Δx = 400 m

v₀ = 0 m/s

v = 35 m/s

Find: a

v² = v₀² + 2aΔx

(35 m/s)² = (0 m/s)² + 2a (400 m)

a = 1.53 m/s²

Answer:

The distance reached is 14.3 m.

Explanation:

To find the distance reached by the diamond first we need to find the flight time:

[tex] t_{v} = \sqrt{\frac{2h}{g}} [/tex]

Where:

h: is the height = 10m

g: si the gravity = 9.81 m/s²

[tex] t_{v} = \sqrt{\frac{2h}{g}} = \sqrt{\frac{2*10 m}{9.81 m/s^{2}}} = 1.43 s [/tex]

Now, we can find the distance reached:

[tex] x = V_{0_{x}}*t_{v} [/tex]

Where:

[tex]V_{0_{x}}[/tex] is the initial horizontal velocity = 10 m/s

[tex] x = V_{0_{x}}*t_{v} = 10 m/s*1.43 s = 14.3 m [/tex]

Therefore, the distance reached is 14.3 m.

I hope it helps you!    

Answer:

4.55 seconds

Explanation:

Speed=distance / Time

So Time = Distance /speed

=1550/340

Average speed = (total distance) / (time to cover the distance)

Speed = (6.6 meters) / (2 seconds)

Speed = 3.3 m/s

Answer:

Explanation:

*Hope this helps*

Answer:

Kindly check explanation

Explanation:

Given the following information :

Distance between Angela and Blake = 15m

Angela's speed = 5m/s at t = 0

Angela's direction = Right = positive

Blake's speed = 3m/s at t = 0

Blake's direction = left = negative

Position or distance = speed × time

Hence,

Combined speed = (3 + 5) = 8m/s

Distance = 15m

Time = distance / speed

Time = 15 / 8

Time they meet = 1.875 seconds

Distance covered by Angela :

Speed × time

= 5 × 1.875 = 9.375 meters

The equation for the distance traveled by Angela is 5t and the distance covered by Angela  is 9.375 m.

The given parameter:

let the time at which Angela and Blake meet = t

The equation for the distance traveled by Angela = 5t

The time (t) at which Angela and Blake meet will be calculated using relative velocity concept:

since they are closing the distance together, we will add their velocities

(i.e they are working together and not against each other)

[tex](V_A +V_B) t = 15\\\\(5 + 3) t = 15\\\\8t = 15\\\\t = \frac{15}{8} \\\\t = 1.875 \ s[/tex]

The distance covered by Angela = 1.875 s x 5 m/s = 9.375 m

The distance covered by Blake = 1.875 x 3 m/s = 5.625 m

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Answer:

Kinetic energy is the energy possessed in a body in motion

Answer:

wind energy is also called kinetic energy

The diameter of the reflecting surface of spherical mirror is called its aperture. Mirrors whose aperture is much smaller than its radius of curvature, we use R=2f.

Answer:

Because concave mirror focus the sunlight at one particular point . At that particular point , amount of sunlight is converged and heat is trapped at that point . This is because , it burn the paper on which the image is focussed .

Answer:

less than 10 inches, or 25 centimeters, of precipitation a year.

Explanation:

PS. the precipitation recieved in the desert can be in the form of either rain or snow.

Answer: Friction is a force that resists the relative motion between two objects or materials. The causes of this resistive force are molecular adhesion, surface roughness, and deformations. Adhesion is the molecular force resulting when two materials are brought into close contact with each other

Answer:

Fats can be identified with a paper without any chemical. Just the food sample in Fats should be placed on the first paper than the rest three papers should be placed on and if any marks are there that shows the quantity of presence in Fats.

Explanation:

Plz Mark me as brainliest

Answer:

Yes, a sled has inertia while sitting still.

Explanation:

From Newton's law of inertia, an object at rest will remain at rest unless it is acted upon by an external force. The reason the object will remain at rest unless an external force acts is because of inertia. Inertia means the resistance of an object to motion.

Thus, a sled hammer at rest will remain at rest unless it is acted upon by an external force. So we can conclude that it has Inertia.

Answer:

C

To convert sunlight into usable sugars

(

Explanation:

Answer:

weight is the mass of an object

it is depends on mass of the body.

Answer:

the force with which an object near the earth on another celestial body is atteracted toward the center of the body by gravity. an objects weight depends on its mass

Answer:

2.05pm.

Explanation:

In the picture.

Answer:

Gravitational potential energy

Explanation:

Gravity would act upon it if it were not suspended.

Answer: Gravitational potential energy

Explanation: I did the quiz! Hope it helped!

Answer:

So B

Explanation:

The statement that the energy involved in diffusion is as follows:

Thus, the correct option is C.

Diffusion may be defined as the process of migration of substances or molecules through a semipermeable membrane from an area of higher concentration to an area of lower concentration.

Diffusion does not require energy because it is classified under the passive transport of materials. Diffusion always works towards the concentration gradient.

Energy is typically involved when the movement occurs against the concentration gradient like active transport.

Therefore, the correct option for this question is C.

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