If a body covers equal distances in equal intervals of time it has uniform speed. If a body covers equal displacement in equal intervals of time it has uniform velocity.
Speed is the rate of change of an object's position with respect to time in any direction. An object will have uniform speed, if the speed of the object remains constant and not varying.
Velocity is the rate of change of an object's position with respect to time in a particular direction. Uniform velocity is a condition in which a body covers equal displacements in equal intervals of time.
Therefore, if a body covers equal distances in equal intervals of time it is said to have uniform speed and if it covers equal displacement in equal intervals of time it is said to have uniform velocity.
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i'm giving 50 points for you to help me out please
i've been stuck on this for a day, please don't troll me!
Answer:
K ≈ 1.10 × 10⁻¹⁸ J
Explanation:
Apply the Photoelectric Equation of Einstein:
h × f = K - W
Where:
h: Planck's constant = 6,62607015 × 10⁻³⁴ m². kg / s;
K: kinetic energy;
W: work function.
So:
h × f = K - W
6,63 × 10⁻³⁴ × 9.62 × 10¹⁴ = K - (2.90 × 1.6×10⁻¹⁹)
K = 6,63 × 10⁻³⁴ × 9.62 × 10¹⁴ + 2.90 × 1.6×10⁻¹⁹
K ≈ 1.10 × 10⁻¹⁸ J
A rocket travels 220 meters directly upward with an average acceleration of 14.7 meters per second squared.
How has the velocity of the rocket changed after 220 meters?
The change in the velocity of the rocket after 220 meters is 80.42 m/s.
What is the velocity of the rocket?
The change in the velocity of the rocket at the given time of motion is calculated as follows;
Apply the following kinematic equation to determine the velocity of the rocket.
v² = u² + 2as
where;
v is the final velocity of the rocketu is the initial velocity of the rocket = 0a is the acceleration of the rockets is the distance travelled by the rocketv² = 2as
v = √2as
v = √(2 x 14.7 x 220)
v = 80.42 m/s
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Has anyone else done this before??
if not i am still confused how to find difference between a radius and the accepted value can be expressed as the percent error. What is a percent error!? My radius was 3486.
The Percentage error is zero.
Formula :-
Percentage error = V₀ - Vᵃ/ V₀ × 100%
V₀ = observed value, given = 3486 km
Vᵃ = accepted value, given = 3486 km
Hence, there is no difference between observed value and accepted value. So the Percentage error is zero.
Percentage error compares an estimate to a correct price and expresses the distinction among them as a percentage. This statistic permits analysts to recognize the scale of the error relative to the real fee. it's also known as percent errors and % error.
Percentage error is the difference between a measured or experiment value and an frequent or known price, divided by way of the known price, accelerated by using 100%.
Percentage error tells you ways large your errors are while you measure some thing in an experiment. Smaller values imply which you are near the well-known or actual fee. for example, a 1% error means that you obtain very close to the familiar value, at the same time as 45% method that you had been quite an extended manner off from the authentic price.
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Of two identical metal balls, one has a charge 5 times greater than the other. The balls touched each other and returned to the previous distance.
How many times has the interaction force changed in the module if:
1) The balls were charged with the same sign
2) Balls were charged with different marks
a 615 n student standing on a scale in an elevator notices that the scale reads 645 n. from this information, the student knows that the elevator must be moving
Yes, it is true. The elevator moves upward because the acceleration is a positive number. If the acceleration is positive, the elevator will move higher.
Here, we can make use of Newton's second law of motion to find the acceleration.
Student mass equals 615/9.81, or 62.7.
The student's weight decreased and increased as a result on the scale.
ma = uarr F
645-615 = 62.7*a
a = 0.478m/s^2
The elevator moves upward because the acceleration is a positive number.
It is real.
The complete question is:
A 615 N student standing on a scale in an elevator notices that the scale reads 645 N. From this information, the student knows that the elevator must be moving upward. True or false?
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Identical balls are dropped from the same initial height and bounce back to half the initial height. In case 1 the ball bounces off a cement floor and in case 2 the ball bounces off a piece of stretchy rubber.
The average force acting on the ball is biggest in the with the cement floor case 2 when in the collision the ball bounce back to half of its initial height.
It is asked that in which case the average net force on the ball is highest.
According to impulse-momentum theorem,
Impulse I = F.Δt
where, F is the net average force and Δt is the time of contact during the collision.
In the case of collision with the rubber piece the time of contact of the ball and the ball increases by large amount while in the case of cement floor the time of contact is very very less.
The change in momentum which is equal to the Impulse is also biggest in the case of cement floor because the transfer of kinetic energy of the ball in the case of cement floor will be almost immediate.
The Bigger change in momentum and the smaller time of contact makes the average force on the ball is biggest in the case of cement floor case.
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how do you apply newtons laws to solve problems?
Answer:
✨Hello mark as branlist Identify the physical principles involved by listing the givens and the quantities to be calculated
Explanation:
What do effective healthcare teams look like? What traits do they have? PLEASE HELP ASAP
First to answer right brainliest
Answer:
There traits are= understanding,fast thinkers,reliable/trustworthy,
Answer:
An effective team is a one where the team members, including the patients, communicate with each other, as well as merging their observations, expertise and decision-making responsibilities to optimize patients
the acceleration of high-speed aircraft is sometimes expressed in g’s (multiple of the standard acceleration of gravity). determine the net upward force, in newtons, that a 90-kg person would experience in an aircraft whose acceleration is 6 g’s straight up. ans.: 6180.3 n
According to Newton's Second Law, an object's net force is equal to the product of its mass and acceleration.
Force (F) can be computed from the 2nd Law of Motion using the following formula:
Fnet = ma( Equation 1 )
due to the fact that the problem did not specify it. We'll suppose the plane is flying straight up.
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Which statement accurately describes the relationship between force and
momentum?
A. As the density of an object decreases, its momentum decreases,
and it takes less force to change its motion.
B. As the mass of an object decreases, its momentum increases, and
it takes more force to change its motion.
C. As the mass of an object decreases, its momentum decreases,
and it takes less force to change its motion.
D. As the density of an object decreases, its momentum increases,
and it takes more force to change its motion.
Answer:
its c my brotha
because if the density decreases so will the mass less mass=less momentum
what is the velocity of an object that travels 100 km in 20 s
Answer: 100km/20s=5km/s
Explanation:because velocity is equal to distance ovet time
a ball is launched up a semicircular chute in such a way that at the top of the chute, just before it goes into free fall, the ball has a centripetal acceleration of magnitude 2g.
Since the chute is semicircular, the ball's velocity shortly before free fall at the top would be horizontal. Given that, starting velocity u=0 As a result, 2R is the distance from the chute's bottom.
We must first determine the speed at which the ball is moving at the top of the shop. Therefore, let's accelerate. Two G are equal to the centripetal acceleration.
In contrast, acceleration is equal to two B squared. Because of this, the speed is equal to two square. The square root of two G is the Rudolph centripetal acceleration times. It's calculated, that. Yeah. So now, mm hmm, mm hmm, we must calculate it.
Approximately 14 m/s and quite close to checkpoint 1 in meters per second. By dividing the object's velocity by the amount of time it takes to go from one location to another, the acceleration velocity can be calculated. Acceleration results from changes in the magnitude of velocity or direction.
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a cd players operating speed is 1600 rad/s. if it starts from rest and has an acceleration of 400 rad/s, how long does it take to reach full speed
The time taken for the cd player to reach the full angular speed is 4 seconds.
What is the time of motion of the cd player?
The time of motion of the cd player is calculated by applying the following kinematic equation as shown below.
ωf = ωi + αt
where;
ωf is the final angular velocityωi is the initial angular velocityα is angular accelerationt is the time of motionSince the cd player started from rest, the initial angular velocity = 0
The time taken for the cd player to reach the full speed is calculated as follows;
1600 = 0 + 440t
1600 = 400t
t = 1600/400
t = 4 seconds
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two people are trying to push a refrigerator. one person is pushing at an angle that is parallel to the floor and 70° to the front plane of the refrigerator with a force of 400 n, and the other is pushing at an angle that is parallel to the floor and 110∘ to the front p
Answer: As friction force is less than the Resultant
force so they will be able to move the fridge
Explanation:
top view of fridge
Angle between forces B= 180- 70- (186-110 )
= 170 - 70 = 40 -
Resultant of forces .
R = 1 ( FOR + ( 82 ) 2 + 2 FIF2 COS B .
J (40B) " + ( 375 ) 2 + 2 x 400 * 375 x Cos 40 "
7 28 - 31 1 N .
() friction force = 600.
As friction force is less than the Resultant
force so they will be able to move the fridge
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There is 728.311N force acting on the front plane. while two individuals attempt to push a refrigerator. Pushing with a force of 400 N, one person is positioned with their back.
Angle between forces B= 180- 70- (186-110 )
= 170 - 70 = 40
R= [tex]\sqrt{(F1^{2} )+(F2^{2})+2F1F2cos\alpha }[/tex]
Here F1= 400
F2=375
alpha = 40
Resultant of forces .
728 . 31 1 N
friction force = 600.
friction force.
The refrigerator can be moved since the friction force is smaller than the resultant force.
Force's Definition. When an object interacts with another object, it experiences a push or pull that is known as a force. Every time two things interact, a force is applied to each of them.
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6. why do the elements in the tubes have to have high voltage electricity run through them before the colored light is emitted? in other words, why don't the cold, un-energized tubes glow?
In order for the electrons to emit photons and leave the ground state, the heat produced by the electricity must be present.
Electron :The electron is a subatomic particle with a negative one elementary charge electric charge. Due to their lack of components or substructure, electrons, which are part of the lepton particle family's first generation, are typically thought to be elementary particles.
Photon :The electromagnetic force is carried by a photon, an elementary particle that is a quantum of the electromagnetic field and includes electromagnetic radiation like light and radio waves. Since photons have no mass, they always move at the 299792458 m/s speed of light in a vacuum.
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Please help will give brainiest!!!
Given the fact that the arrow is in motion, it the follows that the arrow possesses kinetic energy.
What is the kinetic energy?The kinetic energy is the energy that is possessed by a body by virtue of its motion. This is different form the potential energy of the body which is the energy that the body possesses as a result of the fact that the object is located at a particular position. These are actually the two kinds of mechanical energy that we have in the study of physics.
If we consider this matter closely, we would see that the arrow as shown is in motion. The arrow does posses a velocity and such the arrow is in motion. As long as we can see that the arrow is in motion, it the follows that the arrow as we can see does and in fact possesses the kinetic energy.
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calculate the de broglie wavelength of a 1.2-kg rock thrown with a speed of 6.0 m/s into a pond. is this wavelength similar to that of the water waves pro- duced? explain.
The de Broglie wavelength for a particle== 0.92 ×10⁻³⁴m.
de broglie wavelength is the wavelength associated with particle of mass m moving with velocity v.
p= h/ λ
where, p -is the momentum of the atom;
h- Planck's constant - 6.626×10⁻³⁴ m²kg s⁻¹
λ- wavelength;
Momentum can be expressed as
p=m×v
where , m is the mass of the particle;
v - the speed of the particle.
so,
λ = h/(m×v)
= ( 6.626×10⁻³⁴ m²kg s⁻¹)/(1.2kg × 6.0 m/s)
= (6.626×10⁻³⁴ m²kg s⁻¹)/7.2
= 0.92 ×10⁻³⁴ m
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A vector is a way to represent magnitude and direction. Which one of the following vector pairs as equal in direction only?
explained image
a)one short and one longer arrow going towards each other
b)one short and one long arrow going in the same direction
c)one arrow going to the left the other facing down
d)two of the same size arrows going towards eachother
Select one:
a. A
b. B
c. C
d. D
B. The pairs of vectors equal in direction only are one short and one long arrow going in the same direction.
What is direction of a vector?
The direction of a vector can be defined as the measure of the angle it makes with a horizontal line.
The direction of a vector can also be described as the measure of the exact position on the x and y coordinate where a vector can be found.
When we describe the direction of vectors, we don't consider their size or magnitude, rather we focus on the angle of inclination of the vectors above the horizontal.
The magnitude of a vector is defined as the size of the vector.
Vectors pointing or going in the same direction have equal directions despite their size.
Vectors with equal size have the same magnitude despite their directions.
Thus, we can conclude that two vectors going in the same direction will have equal direction.
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if the frequency of a wave was 10 Hz and the speed was 5m/s, find its wavelength
Answer:
[tex]0.5\; {\rm m}[/tex].
Explanation:
The period [tex]T[/tex] of a wave is the reciprocal of its frequency [tex]f[/tex]. In other words, [tex]T = (1/f)[/tex]. Since the frequency of the wave in this question is [tex]f = 10\; {\rm Hz} = 10\; {\rm s^{-1}}[/tex], the period of this wave would be [tex]T = (1/f) = (1/10)\; {\rm s} = 0.1\; {\rm s}[/tex].
The wavelength of a wave is the distance its wavefront travels in one period [tex]T[/tex].
The period of this wave is [tex]T = 0.1\; {\rm s}[/tex]. At a speed of [tex]v = 5\; {\rm m\cdot s^{-1}}[/tex], it would have travelled a distance of [tex]v\, T = (0.1\; {\rm s})\, (5\; {\rm m\cdot s^{-1}}) = 0.5\; {\rm m}[/tex] within one period.
the particle has momentum of magnitude p1 at a certain instant. what is p2 , the magnitude of its momentum δt seconds later? express your answer in terms of any or all of p1 , m , f , and δt .
Seconds later, the amplitude of its momentum, p2, is equal to p1 + (F * Delta t).
What definition of momentum is most precise?A characteristic of an object in motion that it possesses as a result of its mass and motion and which, generally speaking, equals the product of the object's mass and velocity: a feature of an object in motion that determines how long it will take to bring it to rest when subjected to a constant force.
When a certain force is applied for a certain amount of time, a mass's velocity changes.
The following equation expresses this:
Eq. 1: Mass * Force * Time (Final velocity – Initial velocity)
Mass times speed equals momentum.
Eq. 2: Mass * Change in momentum (Final velocity – Initial velocity)
Set Eq1 = Eq2
Force x Time Equals Momentum Change
Equation 3: Final momentum - Initial momentum = Force * time
a mass m particle traveling along the x axis
The particle is being affected by the net force F along the x axis.
A constant force is F.
Eq. 1: Mass * Force * Time (Final velocity – Initial velocity)
Delta t = m * = F (Final velocity – Initial velocity)
Equation 3: Final momentum - Initial momentum = Force * time
p2 = p1 + (F * Delta t) = p2 - p1
Seconds later, the amplitude of its momentum, p2, is equal to p1 + (F * Delta t).
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What is the radius of a planet that has the same mass as earth but on which the free-fall acceleration is 4.90 m/s2 ?
The radius of a planet that has the same mass as earth but on which the free-fall acceleration is 4.90 m/s² is 9 M m
g = G M / R²
g = Acceleration due to gravity
G = Gravitational constant
M = Mass
R = Radius
g = 4.9 m / s²
G = 6.67 * [tex]10^{-11}[/tex] m³ / kg s²
M = 5.97 * [tex]10^{24}[/tex] kg
R² = ( 6.67 * [tex]10^{-11}[/tex] * 5.97 * [tex]10^{24}[/tex] ) / 4.9
R² = 81.3 * [tex]10^{12}[/tex].
R = 9 * [tex]10^{6}[/tex] m
R = 9 M m
Acceleration due to gravity is the acceleration produced by a planet. If an object is falling, it will gain some acceleration due to gravitational force.
Therefore, the radius of a planet is 9 M m
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Derive a relation for time period of simple pendulum from dimensional method
The time period of simple pendulum is 2xpi x (l/g)^1/2 when derived by dimensional method.
What is dimensional method and time period of simple pendulum?Dimensional method is a phenomena we use to derive by using the dimensions of the components given.Here the relation of the time period is 2 pi (l/g)^1/2 where l is the length of the pendulum , g is the gravity.Let 't' the time period be directly proportional to m^a l^b g^c where a, b , c are dimensions.We will us the principle of homogeneity of dimensions to solve this.a= 0b + c = 0 , using this method we calculate the value of dimensionless constant k = 2 pi , t= 2 pi (l/g)^1/2.To know more about dimension visit:
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a car goes around a curve on a road that is banked at an angle of 32.6°. even though the road is slick, the car will stay on the road without any friction between its tires and the road when its speed is 20.8 m/s. what is the radius of the curve?
The radius of curve that a car goes around that is banked at an angle of 32.6° is 69 m
R = v² / g tan θ
R = Radius of the curve
v = Velocity
g = Acceleration due to gravity
θ = Banked angle
R = 20.8² / ( 9.8 * tan 32.6° )
R = 432.64 / ( 9.8 * 0.64 )
R = 432.64 / 6.27
R = 69 m
A banked surface is a surface that is sloped upwards on the outer side of a curve. In race car tracks, the banked angle is usually 12° to 36°.
Therefore, the radius of curve that a car goes around that is banked at an angle of 32.6° is 69 m
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Consider a 0. 5-kg meter stick with a 1. 0 kg mass attached at the 50 cm mark and a 3. 0 kg mass at the very end. Where on the meter stick is the center of mass located?.
The center of mass of the three mass system is at 83cm
Center of mass definition:A position relative to an object or set of objects is known as the center of mass. It is the system's average location, weighted by the mass of each component.
Given the mass of the meter stick is:
M = 0.5kg.
Since the meter stick is uniform, the center of mass of the meter stick is at 50cm or 0.5m.
Let the distance of the meter stick's center of mass from 0cm be x1. Then x1 = 0.5m.
Now a mass m2 = 1kg is attached at 50cm mark.
So the distance of m2 from 0cm is x2 = 50cm = 0.5m.
Similarly a mass m3 = 3kg is attached at the every end or 100cm mark. So the distance of m3 from 0cm is x3 = 100cm = 1m.
Now the position of the three mass system from 0cm is given by,
[tex]X_{CM}=\frac{Mx_{1}+m_{2}x_{2}+m_{3}x_{3}}{M+m_{2}+m_{3}}X_{CM}=\frac{0.5\times 0.5+1\times 0.5+3\times 1}{0.5+1+3}=\frac{3.75}{4.5}=0.83m = 83cm[/tex]
So the center of mass of the three mass system is at 83cm.
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a force in the negative direction of an x axis is applied for 24 ms to a 0.50 kg ball initially moving at 16 m/s in the positive direction of the axis. the force varies in magnitude, and the impulse has magnitude 32.4 n · s.
The force varies in magnitude is 1350 N.
We need to know about momentum to solve this problem. Momentum can be defined as the degree of difficulty to stop a moving object. It can be determined by
P = m . v
where P is momentum, m is mass and v is velocity.
Momentum depends on the Impulse, where
ΔP = I
m (v2 - v1) = F . t
where I is impulse, F is force and t is time
From the question above, we know that:
m = 0.5 kg
t = 24 ms = 0.024 s
v1 = 16 m/s
I = 32.4 Ns
Find the force applied
I = F . t
32.4 = F . 0.024
F = 1350 N
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When you do pull-ups and you hang at rest,
how much of your weight is supported by
each arm?
Doing pull ups and when have a pause at up , there is almost entire body weight just except the weight of the hands.
What is pull ups and how come all the weight be dependent on hands?Doing a pull up is kind of significant exercise , we have always heard of pull ups .And also pull ups can be done by one who have good muscular strength as it takes to have all the weight of the body on muscles of hand .When we pull all the body up there is a pause and the one who is doing pull up always need to have a pause to stretch the stay for better exercise .During the pause it takes to tolerate all the weight of the body except the weight of hands.To know more about pull-ups visit:
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URGENT!! ILL GIVE
BRAINLIEST! AND 100 POINTS
Alex brings a bag of trail mix to school. He empties the bag and measures the total mass of the trail Then he separates the nuts, chocolate, and raisins into individual piles. He eats the chocolate and then measures the mass of the remaining two piles. He records his data in the table
What was the mass of the chocolate that Alex ate?
The mass of the chocolate from the table that we can find in the question is 11 grams.
What was the mass of the chocolate that Alex ate?
We can see that the table as it have been shown gives us both the total number of the trail mix that Alex has brought to the school as well as the various individual components of the trail mix that he has. Looking at this over view would be of a lot of help as we are trying to find out now the number of the mass of the chocolate that Alex ate.
We have the following information;
Mass of nuts = 24 grams
Mass of raisins = 10 grams
Mass of chocolate = unknown grams
We can now have;
Total mass = Mass of nuts + Mass of raisins + Mass of chocolate
Mass of chocolate = Total mass - (Mass of nuts + Mass of raisins)
Mass of chocolate = 45 - (10 + 24)
Mass of chocolate = 11 grams
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A spring has a spring constant of 15 N/cm. Which of the following hanging mass would produce an extension of 3.0 cm?
a. 4.5 kg
b. 5.0 kg
c. 200 g
d. 45 kg
The hanging mass that would produce an extension of 3.0cm is 4.5kg (option A).
How to calculate extension of a spring?The spring constant denoted by K is a measure of the stiffness of the spring. It is different for different springs and materials.
The larger the spring constant, the stiffer the spring and the more difficult it is to stretch.
The spring constant can be calculated using the following formula:
k = F/e
Where;
k = spring constant (Nm-¹)F = force (N)e = extension (cm)F = 15 × 3 = 45N
Since Force = mass × acceleration (10m/s²), the mass can be calculated as follows:
m = 45N ÷ 10m/s² = 4.5kg
Therefore, 4.5kg is the mass of the spring.
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Pls help with the right answer and explanation to this question
Answer: Substance 3 is liquid at room temperature
Explanation: The common room temperature is assumed to be 20-22°C, we need to find the substance that will be in liquid state in that temperature.
For Substance 1, the boiling point is -195.975°C, and hence at room temperature, it would be in vapor phase and all liquid would have turned to gas.
For Substance 2, the boiling point is 3.85°C, and hence at room temperature, it would be in vapor phase and all liquid would have turned to gas in this case too.
For Substance 3, the boiling point is 77.85°C, and melting point is -108.15°C, hence at room temperature, it would be in liquid state.
For Substance 4, the melting point itself is 1800°C, due to which at room temperature it would be in solid state.
If the acceleration of a school bus over a given time interval is zero, how does the instantaneous velocity of that school bus at any instant during that interval compare to its average velocity over the interval?.
Both the average and instantaneous velocities well be same over the given interval if the acceleration is zero.
What is instantaneous velocity?Instantaneous velocity is the rate of differential change of displacement with respect differential change in time. Mathematically -
v = dx/dt
Given is the acceleration of a school bus over a given time interval as zero.
For acceleration over a given time interval to be zero, it must be ensured that the the velocity of the object should remain constant. Mathematically-
a = (v - u)/(t₂ - t₁)
For acceleration [a] = 0, v = u. Therefore -
a = 0
The instantaneous velocity for zero acceleration between the time interval t₁ to t₂ will be equal to initial velocity only -
dx/dt = u
This will be the instantaneous velocity and is equal to (u) at any instant.
Now -
dx = u dt
Integrating both sides, we get -
∫dx = ∫u dt
x = ut
Therefore, the average velocity will be =
v(avg) = x/Δt = ut/Δt
Now -
t = Δt for any specific time interval. Therefore -
v(avg) = ut/t = u
This is the average velocity and it is equal to (u).
Therefore, both the average and instantaneous velocities well be same over the given interval if the acceleration is zero.
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