will the shielding effect be more noticeable in metals or nonmetals? explain your answer.

Answer:

not sure

Explanation:

Goo gle can help for sure lol that's what I do anyway good luck hope you get it right.

Answer:

Scientists were slow to let go of the current theories.

Explanation:

this is correct

Well, the answer is the 4rth one "

50°C"

The answer would be:

In2(SO4)3 (Also known as Indium Solfate).

According to the research, the correct option is false, the statement related to a chemical reaction is false.

They are reactions involving two or more substances (reactants), which change significantly in the process, and can consume or release energy.

Every chemical reaction subjects matter to a chemical transformation, altering its structure and molecular composition.

Therefore, we can conclude that according to the research, the correct option is false, the statement related to a chemical reaction is false.

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Answer:

94 g/mole

Explanation:

The following answer assumes M is molar mass (g/mole):

One mole of Cl is 35.45 grams.  Since 1 mole of MCl is 74.5 grams, one mole of M will be (74.5-35.45 = ) 39.05 grams/mole.  This just so happens to be the molar mass of potassium, K.  That would mean the compound could be KCl.

We learn from this that M has a single bond.  The oxide of M must take into account the fact that oxygen makes 2 bonds per atom.  That would mean that M ocxide would have the formula M2O.  There are two M's per O.  

M2O would have a molar mass of (2x39.05) + 16 = 94.1 g/mole

The most important reaction involved in the reoxidation of NADH is Pyruvate → lactate

Two ATP were generated as a net result of glycolysis, two NAD+ were converted to two NADH + H+, and two glucose molecules were divided into two pyruvate molecules.

Pyruvate will go through a process called fermentation when oxygen is absent.

The NADH + H+ from glycolysis will be recycled back to NAD+ during fermentation, allowing glycolysis to proceed.

NAD+ is converted during the glycolysis process into NADH + H+.

Glycolysis cannot proceed without the presence of NAD+.

The NADH produced during glycolysis will be oxidised to create new NAD+ during aerobic respiration, when it will be used once more in glycolysis.

Pyruvate will undergo oxidation in the absence of oxygen or if an organism is unable to engage in aerobic respiration.

Hence The most important reaction involved in the reoxidation of NADH is Pyruvate → lactate

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Answer: Choices B and D

Explanation: Elements are what you see on the periodic table and compounds are the product of you adding elements together. A good trick to find this is to look at capitalization. If it has more than one upper-case letter, it is most likely a compound. Elements either have only one upper-case letter or one upper-case letter followed by a lower-case letter. If we keep this in mind, we see that answers A and C can easily be dismissed. KBr is made with two elements, Potassium and Bromine. That leaves us with B and D, which are both elements.

Therefore, the correct answers are B. Li and D. Ca.

I hope this helps! Pls give brainliest!! :)

The number of units of NO3 present on the product side is 6.

The given reaction is:

3Cu + 8HNO3 -----> 3Cu(NO3)2 + 2NO + 4H2O

To find:

The number of units of NO3.

Solution:

The given reaction shows that three moles of copper and eight moles of nitric acid react to produce three moles of Cu(NO3)2, two moles of NO and four moles of water.

Each molecule of Cu(NO3)2 contains two units of NO3. As the number of moles of Cu(NO3)2 produced is 3, the total units of NO3 in the product side is 3 x 2 = 6.

Therefore, the correct option is 6.

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Answer: 3. 6

Explanation: to put it simply

The molarity of the potassium hydroxide solution is 0.150 mol/L.

Molar attention is a measure of the attention of a chemical species, in particular of a solute in an answer, in phrases of quantity of substance consistent with the unit extent of solution.

Molarity (M) is the amount of a substance in a sure volume of answer. Molarity is defined as the moles of a solute according to the liters of a solution. Molarity is also referred to as the molar attention of a solution.

Molarity is the wide variety of moles of solute consistent with the liter of answer. For example, in case you dissolve desk salt in water, salt is the solute, and water is the solution. One mole of sodium chloride weighs 58.44 grams. in case you dissolve 58.44 grams of NaCl in a single liter of water, you have got a one molar solution, abbreviated as 1M.

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A silicon atom has four unpaired electrons in its valence shell, two paired electrons in its inner shell, and 14 electrons in all. There are 4 hydrogens it will form covalent bonds with.

The four electrons that make up the "valence" energy level's outermost orbit of the nucleus are given to, taken from, or shared by other atoms. Dependent on their energy level, the electrons orbit the nucleus at various distances. As an illustration, an electron with lower energy would orbit towards the nucleus, whereas an electron with higher energy would orbit farther away. The interaction between the electrons of nearby atoms and those that are the farthest from the nucleus determines how solid structures are created.

The first practical PV devices were made of crystalline silicon, which is still the most used PV material in use today. Grasp how the PV effect functions in crystalline silicon provide us a fundamental understanding of how it functions in all devices, even though various PV materials and designs utilize the effect in slightly different ways.

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So, the total atomic mass is [tex]2(1.00794)+32.06+3(15.9994)=\boxed{82.07408 \text{ g/mol}}[/tex]

The average atomic mass of the atom that has the following isotopes in the following abundances: 20 10Z 30% , 19 10Z10% , 18 10Z 60% is 18.7.

The average atomic mass of an isotopic element is the weighted average of the atomic masses of the naturally occurring isotopes of an element.

According to this question, the atom has the following isotopes in the following abundances: 20 10Z [30%] = 30/100 × 20 = 6

19 10Z [10%] = 10/100 × 19 = 1.9

18 10Z [60%] = 60/100 × 18 = 10.8

The sum of these masses is the average atomic mass and is calculated as follows:

6 + 1.9 + 10.8 = 18.7

Therefore, the average atomic mass of the atom that has the following isotopes in the following abundances: 20 10Z 30% , 19 10Z10% , 18 10Z 60% is 18.7.

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Answer:

c

Explanation:

sugar and water are soluble hence can be separated using distillation

Answer:

K<Mg<P<O

Explanation:

Trend is increasing across period and decreasing down a group

Answer:

k-mg-p-o

Explanation:

thank me later love

Answer:

2.00 g mL -1

Explanation:

2.00 g mL -1

Answer:

19.3 g / ml

Explanation:

The volume of gold is the increase in the cylinder volume

  volume = 2 ml

   mass = 38.6 g

density =   mass / volume = 38.6 / 2 = 19.3 g / cm^3

Answer:

I don't think (NH4)PMo12O40 is written properly, but if it is, there are 4 moles of hydrogen atoms for every 1 mole of (NH4)PMo12O40

Explanation:

1 mole of (NH4)PMo12O40 has 6.02x10^23 molecules of (NH4)PMo12O40.  Each molecule of (NH4)PMo12O40 has 4 hydrogen atoms.  If the molecule is decomposed to just it's elements, there would be 4 moles of hydrogen atoms for every one mole of (NH4)PMo12O40.

The number of moles of hydrogen atoms in one mole of (NH₄)PMo₁₂O₄₀ is 4. Hence, option A is correct.

Moles can be given as the mass of the compound to the molar mass.

Moles = Mass/Molar mass

The subscript to the H in the formula describes the number of hydrogen atom in a molecule.

Thus, 1 molecule of (NH₄)PMo₁₂O₄₀ contains 4 atoms of hydrogen.

1 mole = 6.023*10²³ molecules

1 molecule  (NH₄)PMo₁₂O₄₀ = 4 hydrogen atoms

1 mole  (NH₄)PMo₁₂O₄₀ = 6.023*10²³ * 4 hydrogen atoms

1 mole  (NH₄)PMo₁₂O₄₀ = 4 moles of hydrogen atoms

Thus, the moles of hydrogen atoms present in 1 mole of (NH₄)PMo₁₂O₄₀ is 4. Hence option A is correct.

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The compound that is involved in the reaction with silver nitrate to form silver chloride and iron (III) nitrate is Iron (III) chloride.

The displacement reaction is the one in which the more reactive element displaces the less reactive element from the compound forming a new compound.

The formation of silver chloride and iron (III) nitrate was followed by the double displacement reaction. The silver in silver nitrate was replaced by the iron forming iron(III) nitrate, and the chloride from the Iron chloride reacted with silver forming silver chloride.

Thus, the compound that reacts with Silver nitrate in the double displacement reaction is Iron(III) chloride.

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From the reaction, the volume of the oxygen required is 89.6 L.

The term stoichiometry has to do with the process by which the mass of reactants or products in a reaction is obtained from the  balanced reaction equation.

In this case, the balanced reaction is equation is;

CH₄  +  2 O₂    →    CO₂  +  2 H₂O

Number of moles of CO2 = 88.0 g/44 g/mol = 2 moles

2 moles of O2 produced 1 mole of CO2

x moles of O2 produces 2 moles of CO2

X = 4 moles

1 mole of oxygen occupies 22.4 L hence 4 moles of oxygen occupies 4 * 22.4 L = 89.6 L

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The mole ratio between sodium bicarbonate and that of acetic acid is 1:1

A mole ratio can be defined as that ratio in whole numbers between the amounts in moles of any two compounds involved in a balanced chemical reaction.

In conclusion, the mole ratio between sodium bicarbonate and that of acetic acid is 1:1

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The principal quantum number (n): specifies the principal shell of the orbital.

The answer is option D.

The important quantum number (n) describes the dimensions of the orbital. Orbitals for which n = 2 are larger than those for which n = 1, as an example. Because they have got opposite electric costs, electrons are interested in the nucleus of the atom.

The numerals, called essential quantum numbers, imply strength degrees as well as the relative distance from the nucleus. A 1s electron occupies the energy stage nearest the nucleus.

A 2s electron, less strongly certain, spends most of its time farther far from the nucleus.

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The volume increases and the final volume is 2.1 L

The volume of a gas is directly related to the heat and pressure. If temperature increases, volume increases.

If pressure increases, volume decreases

Based on Boyle's law,

The absolute temperature of a gas is directly proportional to the volume of the gas.

As the balloon change increases its temperature, the volume increases

The Boyle's equation is:

V₁T₂ = V₂T₁

Where,

Replacing :

V₁ = 2.0L

T₂ = 35°C + 273.15 = 308.15K

V₂ = ?

T₁ = 25°C + 273.15 = 298.15 K

2.0L x 308.15 K = V₂ x 298.15 K

2.1 L = V₂

Final volume is 2.1L

Hence, The volume increases and the final volume is 2.1 L

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Answer:

increases, 2.1

Explanation:

I got it right.

Answer:

Los metaloides serían los elementos con propiedades intermedias. No existe una definición estandarizada de elemento metaloide ni un consenso completo sobre los elementos que son metaloides. A pesar de la falta de especificidad en el término, es muy utilizado en los textos químicos, tanto educativos como divulgativos o de investigación.

Explanation:

333.3 milliliters of 0.444 M KOH required to precipitate all of the Pb⁺² ions in 107 mL of 0.699 M Pb(NO₃)₂ solution as Pb(OH)₂.

Stoichiometry helps us use the balanced chemical equation to measure quantitative relationships and it is to calculate the amounts of products and reactants that are given in a reaction.

Molarity (M) is defined as the number of moles of solute dissolved in 1L of solution. Molarity is also known as Molar Concentration. The S.I unit of Molarity is molar (M) or mol/L.

Molarity = [tex]\frac{\text{Number of moles}}{\text{Volume of solution (in L)}}[/tex]

Now put the values in above formula to find the number of moles of Pb(NO₃)₂

Molarity = [tex]\frac{\text{Moles of}\ Pb(NO_{3})_2}{\text{Volume of solution (in L)}}[/tex]

Moles of Pb(NO₃)₂ = Molarity × Volume

                               = 0.699M × 0.107 L       [1ml = 0.001 L]

                               = 0.074 moles

The given balanced chemical equation is

Pb(NO₃)₂(aq) + 2 KOH(aq) → Pb(OH)₂(s) + 2 KNO₃(aq)

The mole ratio of KOH to Pb(NO₃)₂ is 2:1.

The mole of KOH = 0.074 mol × 2

                             = 0.148 moles

Now put the value in above formula to find the volume of KOH  

Molarity = [tex]\frac{\text{Number of moles}}{\text{Volume of solution (in L)}}[/tex]

Volume of KOH = [tex]\frac{\text{Number of mole of KOH}}{\text{Molarity}}[/tex]

Volume of KOH =  [tex]\frac{0.148\ mol}{0.444\ M}[/tex]

                          = 0.333 L

                          = 333.3 mL     [1L = 1000 mL]

Thus from the above conclusion we can say that 333.3 milliliters of 0.444 M KOH required to precipitate all of the Pb⁺² ions in 107 mL of 0.699 M Pb(NO₃)₂ solution as Pb(OH)₂.

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Disclaimer: The question was given incomplete on the portal. Here is the complete question.

Question: Calculate the number of milliliters of 0.444 M KOH required to precipitate all of the Pb⁺² ions in 107 mL of 0.699 M Pb(NO₃)₂ solution as Pb(OH)₂. The equation for the reaction is:

Pb(NO₃)₂(aq) + 2 KOH(aq) → Pb(OH)₂(s) + 2 KNO₃(aq)

_________ mL KOH.

The subscript for H in the empirical formula for this compound is 3.

There are 3 steps involved in the construction of empirical formula.

Calculation of empirical formula is as under as ...

Step 1: Divide the % of each atoms which their atomic weights.

 C = 51.27 / 12 = 4.27

 H = 7.75 / 1 = 7.75

 O = 40.98 / 16 =2.56

Step 2 : Divide all the answers with the smallest answer to get the subscripts for empirical formula.

C = 4.27/ 2.56 ≈ 2

H = 7.75/ 2.56 ≈ 3

O = 2.56 /2.56 = 1

Step 3: Construction of empirical formula by putting subscripts calculated in step 2.

Empirical formula form given data = [tex]C_{2} H_{3} O_{1}[/tex]

Thus , subscript for H in the empirical formula for this compound is 3.

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Strecker synthesis of amino acids:

Aldehyde and ketone are the functional groups that react to form the imine intermediate in the Strecker synthesis of amino acids.

Method of Strecker synthesis:

A method for synthesizing amino acids by the reaction of an aldehyde with ammonia in the presence of potassium cyanide is known as the Strecker amino acid synthesis. α-aminonitrile is produced by the condensation reaction, and this α-aminonitrile is then hydrolyzed to produce the required amino acid. The technique is applied commercially to make racemic methionine from methional.

Although primary and secondary amines also produce substituted amino acids, using ammonium salts only produces unsubstituted amino acids. Similar to this, using ketones in place of aldehydes results in amino acids that are α,α-disubstituted.

Reaction mechanism:

An aldehyde's carbonyl oxygen is protonated in the first phase of the reaction, which is followed by an ammonia nucleophilic attack on the carbonyl carbon. Water is separated from the intermediate iminium ion after a second proton exchange. The iminium carbon is then attacked by a cyanide ion, resulting in an aminonitrile.

The aminonitrile's nitrile nitrogen is protonated in the second step of the Strecker Synthesis, and a water molecule attacks the nitrile carbon. Proton exchange and a nucleophilic attack of water on the former nitrile carbon are followed by the formation of a 1,2-diamino-diol. The protonation of the amino group is then followed by the elimination of ammonia, and eventually, the deprotonation of a hydroxyl group results in the production of amino acids.

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Answer:

1

Explanation:

1.04/MM = 1.04/39.09 = 0.0266 potassium moles

0.7/MM = 0.7/52 = 0.0133 chromium moles

0.86/MM =0.86/16 = 0.05375 oxygen moles

divide all the moles number by the lowest

0.0266/0.0133=2

0.0133/0.0133=1

0.05375/0.133=4

so the empirical formula is K2CrO4

The concentration of the HBr would be 0.09 M

First, let us look at the equation of the reaction:

[tex]HBr + NaOH --- > NaBr + H_2O[/tex]

The mole ratio of HBr to NaOH is 1:1.

Mole of 15 mL, 0.30 M NaOH = 0.30 x 15/1000 = 0.0045 moles

Equivalent mole of HBr - 0.0045 moles

Molarity of HBr = mole/volume = 0.0045/50/1000 = 0.09 M

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As atomic radius decreases, electronegativity increases. This is mostly because a smaller atomic radius represents a stronger hold on the valence electrons.