why is acceleration not constant near the speed of light

Answers

Answer 1

Answer:

because when an object approaches the speed of light, it's mass starts to increase exponentially, and would be infinite at the speed of light. It would therefore require MORE than an infinite amount of energy to accelerate even a single electron to the speed of light


Related Questions

what equation do you use to calculate force from work to distance

Answers

Answer:

Work can be calculated with this equation: Work = Force x Distance. The SI unit for work is the Newton meter (N m). One joule equals the amount of work that is done when 1 N of force moves an object over a distance of 1 m.

Explanation:

PLZ HELP ME FAST A relationship between two variables is called:
A.
observable
.B.
correlation
.C.
causation
D.
finite.

Answers

Answer:

B- Correlation

Explanation:

Answer:

correlation

Explanation:

HELP!!!!
Which statement describes earthquakes?

They release energy.
They are caused by reduced stress in rocks.
They begin at the epicenter.
They result from movement on Earth’s surface.

Answers

Answer:

A

Explanation:

earthquakes release energy

Answer:

i think it begins at the epicenter

Explanation:

i can remember

pls give brainleist

In a game of pool, a cue ball rolls without slipping toward the stationary eight ball with a momentum of 0.23 kg m/s. After the two balls collide, the final momentum of the cue ball is 0.01 kg m/s

Answers

Answer: 0.22

Explanation: Subtract 0.01kg from 0.23kg

how are mass, distance and gpe related

Answers

Answer:

It is direct proportionality. The greater the mass, the greater is the gravitational potential energy. The equation for GPE is : GPE = mgh, where m is the mass, g is the acceleration due to gravity, and h is the height above the ground. As you can see GPE is directly proportional to mass, and height. KT.

Explanation:

Gravitational potential energy is a function of both the mass of your system and the mass of the thing generating the gravity field around your system.

The relationship is linear, which means that if you multiply or divide one of the masses by some number but leave everything else the same, you multiply or divide the potential energy by the same number. A 3kg mass has three times the gravitation potential energy of a 1kg mass, if placed in the same location.

Mars is 7.83x10^10m [^10 is an exponent] from planet earth. The planet Earth is 5.98x10^24kg [^24 is an exponent] while Mars has a mass of 6.42x10^23kg [^23 is an exponent]. What is the gravitational attraction between the two planets? G=6.67×10^-11 (-11 is an exponent)​

Answers

Answer:

Approximately [tex]4.18 \times 10^{16}\; \rm N[/tex].

Explanation:

Consider two objects of mass [tex]m_{1}[/tex] and [tex]m_{2}[/tex]. Let [tex]r[/tex] denote the distance between the center of mass of each object. Let [tex]G[/tex] denote the gravitational constant. ([tex]G \approx 6.67 \times 10^{-11}\; {\rm m^{3}\cdot kg^{-1}\cdot s^{-2}}[/tex].)

By Newton's Law of Universal Gravitation, the size of gravitational attraction between these two objects would be:

[tex]\begin{aligned}F &= \frac{G\, m_{1}\, m_{2}}{r^{2}}\end{aligned}[/tex].

In this question, [tex]m_{1} = 5.98\times 10^{24}\; {\rm kg}[/tex] and [tex]m_{2} = 6.24 \times 10^{23}\; {\rm kg}[/tex] are the mass of the two planets. The distance between the two planets is [tex]r = 7.83 \times 10^{10}\; \rm m[/tex] (approximately the same as the distance between the center of mass of planet Earth and the center of mass of Mars.)

Apply Newton's Law of Universal Gravitation to find the size of gravitational attraction between the two planets:

[tex]\begin{aligned}F &= \frac{G\, m_{1}\, m_{2}}{r^{2}} \\ &= \frac{1}{(7.83 \times 10^{10}\; {\rm m})^{2}} \\ &\quad \times (6.67 \times 10^{11}\; {\rm m^{3} \cdot kg^{-1} \cdot s^{-2}}) \\ &\quad \times (5.98 \times 10^{24}\; {\rm kg}) \\ &\quad \times (6.42 \times 10^{23}\; {\rm kg}) \\ &\approx 4.18 \times 10^{16}\; {\rm kg \cdot m \cdot s^{-2}} \end{aligned}[/tex].

Since  [tex]1\; {\rm kg \cdot m \cdot s^{-2}} = 1\; {\rm N}[/tex], the size of gravitational attraction between the two planets would be approximately [tex]4.18 \times 10^{16}\; {\rm N}[/tex].

Exert a force on the object, what happens to their state of motion​

Answers

The force might make the object move or bring the object to rest or change in direction of motion

Two billiard balls move toward each other on a table. The mass of the number three ball, m1, is 5 g with a velocity of 3 m/s. The mass of the eight ball, m2, is 6 g with a velocity of 1 m/s. After the balls collide, they bounce off each other. The number three ball moves off with a velocity of 5 m/s. What is the final velocity and direction of the eight ball? 8. 6 m/s 5. 7 m/s â€"5. 7 m/s â€"8. 6 m/s.

Answers

This question involves the concepts of the law of conservation of momentum and velocity.

The velocity of the eight ball is "5.7 m/s".

According to the law of conservation of momentum:

[tex]m_1u_1+m_2u_2=m_1v_1+m_2v_2[/tex]

where,

m₁ = mass of number three ball = 5 g

m₂ = mass of the eight ball = 6 g

u₁ = velocity of the number three ball = 3 m/s

u₂ = velocity of the eight ball = - 1 m/s (negative sign due to opposite direction)

v₁ = final velocity of the three number ball = - 5 m/s

v₂ = final velocity of the eight ball = ?

Therefore,

(5 g)(3 m/s) + (6 g)(- 1 m/s) = (5 g)(- 5 m/s) + (6 g)(v₂)

[tex]v_2=\frac{34\ g.m/s}{6\ g}\\\\[/tex]

v₂ = 5.7 m/s

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If the action force is the swimmer pushing water in the leftward direction, what is the reaction force?

PLEASE ANSWER
CORRECTLY PLS

Answers

According to Newton's Third Law of Motion, to every action, there is an equal and opposite reaction; action and reaction act on different bodies.Here, the action force is in the leftward direction, so the reaction will be in the opposite direction.If the action force is the swimmer pushing water in the leftward direction, then the reaction force is in the rightward direction.And the reaction force will be given by the water on the swimmer.

Answer:

The reaction force is the water pushing the swimmer in the rightward direction.

Hope you could get an idea from here.

Doubt clarification - use comment section.

What is the kinetic energy of a toy truck with a mass of 0. 75 kg and a velocity of 4 m/s? (Formula: ) 3 J 6 J 12 J 24 J.

Answers

The kinetic energy of a toy truck with a mass of 0. 75 kg and a velocity of 4m/s is 6J.

HOW TO CALCULATE KINETIC ENERGY:

The kinetic energy of a moving body can be calculated by using the following formula:

K.E = ½mv²

Where;

K.E = kinetic energy (J)m = mass (kg)v = velocity (m/s)

According to this question, a toy truck has a mass of 0.75 kg and a velocity of 4 m/s. The kinetic energy is calculated as follows:

K.E = ½ × 0.75 × 4²

K.E = 8 × 0.75

K.E = 6J

Therefore, the kinetic energy of a toy truck with a mass of 0. 75 kg and a velocity of 4m/s is 6J.

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HELPPP PLEASE
1) if the distance between two masses are 15 meters and the masses are 350kg and 492 kg
respectively; what is the magnitude of gravitational force?

Answers

Answer:

-8

5.092×10

Explanation:

given,

distance (d) =15m

mass (M1) =350kg

mass(M2) = 492kg

Gravitational constant (G)=6.67×10^-11

we know,

gravitational force=(Gm1m2)÷d^2

=(6.67×10^-11×350×492)÷15^2

= (1.14857×10^-5)÷225

= 5.092×10^-8

Read the excerpt from The Building of Manhattan.

A temporary, small narrow-gauge track system was installed on each floor as it was needed. This enabled the material to be moved from the truck at ground level onto dump carts, raised by elevator to the designated floor, wheeled onto the track, and moved quickly to the exact spot needed. Turntables built into the track allowed the carts to be shifted about in any direction.

Which question can be answered only if an illustration accompanies the text?

What did turntables built into the track allow?
How were dump carts raised to designated floors?
When was a track system installed on a floor?
What does a turntable built into a track loo

Answers

Answer: this would be D.) What does a turntable built into a track look like

Explanation:

Someone plz give me some boy advice I really need it.

Answers

If your wanting to know how to talk to them, just act like you know them really well be very causal and be confident in what you say, they also like it when you make the first move to talk to them

HELP ME IM NOT GOOD THAT THIS :))))

Answers

Phosphorus the third one

Pleaseeeee HELPPPP THIS IS TIMED ALSO,
A book slides along a table and comes to a stop. Explain, in detail, all the forces acting on the book.

Answers

Answer:

Friction, normal force, and weight

Explanation:

If the book slows down, it means that there must be friction acting in the opposite direction of the direction the book is moving in.

Weight is caused by the gravitational pull of the Earth on the book, and normal force is the table pushing the book up because the book is pushing down on the table (3rd law.)

Note that weight and normal force is not the 3rd law action-reaction pair. The pair is the force of the book on the table and the force of the table on the book.

how to determine my slope in physics graph​

Answers

Answer:

Determine the coordinates of two points on the line. Calculate the difference between these two locations' y-coordinates (rise). Calculate the x-coordinate difference between these two places (run). Divide the y-coordinate difference by the x-coordinate difference (rise/run or slope).

the system shown above is released from rest. if friction is negligible, the acceleration of the 4.0 kg block sliding on the table shown above is most nearly

Answers

The acceleration of the first block (4 kg) is -9.8 m/s².

The given parameters:

Mass of the first block, m₁ = 4.0 kgMass of the second block, m₂ = 2.0 kg

The net force on the system of the two blocks is calculated as follows;

[tex]m_2 g - T = m_1 a[/tex]

where;

T is the tension in the connecting string due weight of the first block

[tex]m_2 g - m_1 g = m_1 a\\\\a = \frac{m_2 g - m_1g}{m_1} \\\\a = \frac{g(m_2 - m_1)}{m_1} \\\\a = \frac{9.8(2-4)}{2} \\\\a = -9.8 \ m/s^2[/tex]

Thus, the acceleration of the first block (4 kg) is -9.8 m/s².

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I have two questions. I hope anyone can help me <3 Question 8 & Question 9. ​

Answers

Answer:

i have not study it till now

Explanation:

sorry i don't know

A pitcher throws a softball toward home plate. When the ball hits the catcher’s mitt, its horizontal velocity is 32 meters/second. The softball’s velocity goes to 0 meters/second in 0. 8 seconds when caught. If the softball has a mass of 0. 2 kilograms, what’s the force of the impact? Use F = ma, where. The force of the impact is newtons.

Answers

The force of impact of the softball at the given conditions is 8 N.

The given parameters:

Horizontal velocity of the ball, v = 32 m/sChange in time of motion of the ball, Δt = 0.8 sMass of the ball, m = 0.2 kg

The force of impact of the softball is calculated by applying Newton's second law of motion as follows;

[tex]F = ma\\\\F = m \times \frac{\Delta v}{\Delta t} \\\\F = 0.2 \times \frac{32 - 0}{0.8 - 0} \\\\F = \frac{0.2 \times 32}{0.8} \\\\F = 8 \ N[/tex]

Thus, the force of impact of the softball at the given conditions is 8 N.

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is orange orange because its orange or is orange orange because its orange

Answers

Answer:

orange it is lol

Explanation:

Answer:

HELP ORANGE DOESNT LOOK LIKE A WORD ANYMORE

Explanation:

Rafiq has heard that continued exposure to light for 10 days can change the colour of some blue dyes used to colour cotton clothing. He decides to test this. He takes a piece of clothing dyed with a blue dye which is suspected to lose colour on such exposure. He cuts the cloth into two pieces.
Which experiment is likely to help him conclude if the dye indeed can change colour?
He should expose, for 10 days-

A. Both pieces under 2 identical lamps.
B. One piece under a lamp; keep the other in darkness.
C. One piece for 5 days and one for 10 days under identical lamps
D. One piece folded and one piece spread out under 2 identical lamps.

Answers

I think the answer is B

Select the correct answer. What are the directions of an object's velocity and acceleration vectors when the object moves in a circular path with a constant speed? A. The question is meaningless, since the acceleration is zero.
B. The vectors point in opposite directions.
C. Both vectors point in the same direction.
D. The vectors are perpendicular.

Answers

The centripetal acceleration which always  act toward the center of the circle. The vectors are perpendicular. The correct answer for this question, is option D

The speed of an object is always constant in a  circular motion while the object keeps changing direction regularly. The velocity will keep changing because of the change in direction.

Whenever there is a change in velocity, there must be acceleration.

When the object is moving in a circular path with a constant speed, the directions of an object's velocity and acceleration vectors will be perpendicular to each other

The reason is because acceleration is centripetal acceleration which always  act toward the center of the circle.

Therefore, the correct answer for this question, is option D

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Can someone please give me the (Answers) to this? ... please ...

Answers

Answers:

1. Newton's second law states that the force on an object is equal to its mass times its acceleration. Equation: F = ma, or force is equal to mass times acceleration.

2.

a=F/ma= 120N/68kga=(120 kg x m/s^2)/ (68kg)a = 1.8 m/s^2

3. a = 0.25 m/s^2

4. a = 0.4 m/s^2

A textbook is sitting at rest on a desk. Compared to the magnitude of the force of the textbook on the desk, how
would you describe the magnitude of the force of the desk on the book?
o less
O zero
O more
O equal

Answers

Equal because the book is not moving and the forces are balanced/equal

plssss helppppppppppp i need it

Answers

Answer:

D

Explanation:

I don't know how to explain it I just did it

By the way thxs for help on one of my problems

Two gravitational forces act on a
given object. How do you determine the total gravita-
tional force acting on the object?

Answers

Answer:

Explanation:

Depends on the location of the two forces.  If they are aligned on the same side of the object, you would simply add.

X -----------F1 -------F2

X is the object. F1 and F2 are both masses which create a gravitational force. They both are the form of Fx = G * m1 * m2 / r^2. The total force is F1 + F2

If they are are on either side of the object, you subtract.

F1 ---------X ---------F2

Fx = F1 - F2

Any other location of F1 and F2 is much more complicated by the use of trigonometry.

The magnetic field 0. 02 m from a wire is 0. 1 T. What is the magnitude of the magnetic field 0. 01 m from the same wire? 0. 01 T 0. 05 T 0. 1 T 0. 2 T.

Answers

The magnitude of the magnetic field 0.01 m from the same wire is 0.2 T.

Given to us:

Magnetic field, [tex]B_1 = 0.1\ T[/tex]

Radius of wire, [tex]R_1 = 0.02\ m[/tex]

To find out the magnitude of the magnetic field 0. 01 m from the same wire, we need to find out current first. we will use the formula,

[tex]B = \dfrac{\mu_oI }{2\pi R},\\\rn\\where,\\B= magnetic\ field\\\mu_o = 4\pi\times 10^{-7} m\cdot kg\cdot s^{-2} A^{-2}\ is\ the\ magnetic\ constant\\I= current\\R= radius\ of\ the\ wire[/tex]

Putting the values,

[tex]B_1 = \dfrac{\mu_oI }{2\pi R_1},\\\rn\\\\0.1= \dfrac{4\times \pi \times 10^{-7}\times I}{2\times \pi\times0.02}\\\\I=10,000\ A[/tex]

Now, for [tex]B_2[/tex]

[tex]B_2 = \dfrac{\mu_oI }{2\pi R_2},\\\rn\\\\B_2= \dfrac{4\times \pi \times 10^{-7}\times 10,000}{2\times \pi\times0.01}\\\\B_2= 0.2\ T[/tex]

Hence, the magnitude of the magnetic field 0. 01 m from the same wire is 0.2 T.

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_____________ is the study of movement in athletes. A. Sports biomechanics B. Posture C. Dynamics D. Anatomy

Answers

Answer:

I believe its A: Sports biomechanics.

if a big person and a small person run up the stairs at the same time who has more force

Answers

Answer:

a big person

Explanation:

because the big person exerts more force over the same distance

Answer:

the big person exerts the largest force on the stairs because he weighs more

Explanation:

this question answer is ☝️☝️

Question 17 (Essay Worth 5 points)
(02.06 HC)
Choose two spheres of Earth which interact when hot springs are formed. Use complete sentences to explain how they interact during this process
X2
= 12 Source
ус
cM
В І
U S XX T
.
Styles
Format
Font
Size
A- A -
Increase Indent

Answers

Answer:

geosphere and hydrosphere

Explanation:

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