The difference in the acceleration due to gravity on the moon and the Earth are different due to the difference in their masses and radius.
Yes, can shield a gravitational field in a vacuum by coming in between the mass and gravitational source.
What is Newton's law of universal gravitation?
Newton's law of universal gravitation states that every two objects in the universe attracts each other with a force directly proportional to the product of the masses and inversely proportional to the distance between the two objects.
F = GmM/R²
where;
G is universal gravitation constantm and M are the massesR is the distance between the two objectsFrom Newton's second law of motion,
F = mg
where;
g is acceleration due to gravitymg = GmM/R²
g = GM/R²
Thus, the acceleration due to gravity on the moon and the Earth are different because of difference in their masses and radius.
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Compute the density in g/cm3 of a piece of metal that has a mass of 0.350 kg and a volume of 62 cm3.answer in g/cm3
We will haev the following:
[tex]\begin{gathered} \rho=\frac{350g}{62cm^3}\Rightarrow\rho=\frac{175}{31}g/cm^3 \\ \\ \Rightarrow\rho\approx5.6g/cm^3 \end{gathered}[/tex]So, the density of the material is 175/31 g/cm^; that is approximately 5.6 g/cm^3.
module 2 question 3
You drive 5.00 km in a straight line in a direction 20° East of North.
(a) Find the distances you would have to drive straight East and then straight North to arrive at the same point. (This is equivalent to finding the components of the displacement along the East and North directions.)
km East
km North
(b) Show that you still arrive at the same point if the East and North legs are reversed in order.
The distance to drive East is 1.7 km and the distance you would have to drive North is 4.7 km
The North-East, East and North travel distances from a right angled triangle. So trigonometric ratios are applicable.
sin θ = East distance / NE distance
sin 20° = East distance / 5
East distance = 1.7 km
cos θ = North distance / NE distance
cos 20° = North distance / 5
North distance = 4.7 km
Some of the basic trigonometric ratios are:
sin θ = Opposite side / Hypotenusecos θ = Adjacent side / Hypotenusetan θ = Opposite side/ Adjacent sideTherefore, the distance to drive East is 1.7 km and the distance to drive North is 4.7 km
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A 44-kg child steps onto a scale and reads 430N.
A 44 kg child steps onto a scale and reads 430 N so the magnitude of the normal force acting on the child will be 430 N.
What is Normal Force?The normal force is a common force that is experienced when an object is placed on a surface and pushed against it. For instance, the normal force prevents a book from falling through a table when it is placed on one. The book is being pulled downward by gravity, but because it isn't truly falling, something must be pushing it upward. The normal force is what we refer to as. Normal refers to something that is perpendicular to the surface.
According to the question,
Normal Force=Weight of the person
= 430 N
So, the Magnitude of the normal force acting on the child will be 430 N.
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As shown in the figure, a square insulating slab 5.0 mm thick measures 2.0 m ×
2.0 m. It has a charge of 8.0 × 10^-11 C distributed uniformly throughout its volume. Use Gauss’s law to determine the electric field at point P, which is located within the slab, 1.0 mm from the top face.
Assume P is far from the (front, back, left, and right) sides of the slab. (ε0 = 8.85 × 10^-12 C2/N ∙ m2)
The electric field at point P is mathematically given as
E=-6.69n-m^2/c
This is further explained below.
What is the electric field?Generally, the equation for magnetic Flux is mathematically given as
[tex]Flux $=\mathrm{E}.2 \mathrm{~A}\\=\mathrm{Q}_{\text { enc }} / \varepsilon_0$[/tex]
[tex]=\mathrm{E} 2 \mathrm{~A}\\\\=\mathrm{p} * \mathrm{Vol} / \varepsilon_0$[/tex]
[tex]=E 2\left(d x^* d y\right)\\\\=p^*\left(d x^* d y^* 2^* d z\right) / \varepsilon O$[/tex]
E=p^* d z /
Taking into account the fact that Let the permittivity of the slab is approximate:
[tex]$\varepsilon O=8.85^* 10^{\wedge}-12 \mathrm{~F} / \mathrm{m}$[/tex]
Distance from the origin to the point in question:
dz=0.0015m
Charge distribution over the slab is uniform:
[tex]&\mathrm{p}=\mathrm{Q} / \mathrm{vol}=\left(-7.9 * 10^{\wedge}-11\right) \mathrm{C} /\left(0.005^* 2 * 2\right) \mathrm{m}^{\wedge} 3 \\[/tex]
p=-3.95^* 10^-9
[tex]\mathrm{E}=\mathrm{p}^* \mathrm{dz} / \varepsilon 0\\\\=\left(3.95^* 10^{\wedge}-9 * .0015\right) / 8.85^* 10^{\wedge}^{-11} \\[/tex]
E=-6.69n-m^2/c
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1.00 kg of ice at -24.0°C is placed in contact with a 1.00 kg block of a metal at 5.00°C. They come to equilibrium at -8.88°C. What is the specific heat of the metal?
Ice: c = 2000 J/(kg*C)
(Unit = J/(kg*C))
The specific heat of the metal is 2178.7 J/kg⁰C.
What is specific heat capacity?The specific heat capacity of a substance is the quantity of heat needed to raise a unit mass of a substance by 1 kelvin.
The specific heat capacity of the metal is calculated by applying the principle of conservation of energy.
Heat lost by the metal = Heat gained by the ice
m₁c₁(T₁ -T) = m₂c₂(T - T₂)
where;
m₁ is mass of the metalm₂ is mass of the icec₁ is specific heat capacity of the metalc₂ is specific heat capacity of the iceT is the equilibrium temperatureT₁ is the initial temperature of the metalT₂ is the initial temperature of the water(1)(c₁)(5 - -8.88) = (1)(2000)(-8.88 - - 24)
(1)(c₁)(5 + 8.88) = (1)(2000)(-8.88 + 24)
13.88c₁ = 30,240
c₁ = 30,240/13.88
c₁ = 2178.7 J/kg⁰C
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Answer:
2180
Explanation:
trust me bro
Which one is the answer
The graph that shows the relationship between the speed and the kinetic energy is option B.
What is the relationship between kinetic energy and speed?Recall that the kinetic energy is referred to as the speed that a body possess by virtue of its motion. Thus an object that is in motion is said to posses the kinetic energy. The kinetic energy is the energy of an object that has a velocity
The kinetic energy is linearly related to the speed of the object. This implies that the speed is directly proportional to the kinetic energy of the object. If there is a direct relationship, it the follows that the graph of the speed against the kinetic energy of the object ought to be a straight line graph.
As such, the relationship between the kinetic energy and the speed of the object can be seen from the image in option B.
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The components of a 15 meters per second velocity at an angle of 60 above the horizontal are
The components of a 15 meters per second velocity at an angle of 60 above the horizontal are 13.05 m / s and 0.435 m / s
Resolving the velocity into its horizontal and vertical components, it makes a right angled triangle.
Hypotenuse = V = 15 m / s
θ = 60°
Opposite side = components = [tex]V_{y}[/tex]
Adjacent side = Horizontal component = [tex]V_{x}[/tex]
In a right angled triangle,
sin θ = Opposite side / Hypotenuse
cos θ = Adjacent side / Hypotenuse
sin 60° = [tex]V_{y}[/tex] / V
[tex]V_{y}[/tex] = 15 * 0.87
[tex]V_{y}[/tex] = 13.05 m / s
cos 60° = [tex]V_{x}[/tex] / V
[tex]V_{x}[/tex] = 0.5 * 0.87
[tex]V_{x}[/tex] = 0.435 m / s
Therefore,
The horizontal component, [tex]V_{x}[/tex] = 0.435 m / sThe vertical component, [tex]V_{y}[/tex] = 13.05 m / s.To know more about components of velocity
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what is friction with its SI unit
When two surface attach each other a force is produced called friction. It's SI unit is newton
Jerry is unable to pick up the picnic
basket, then he eats spinach and
becomes stronger. Now he can easily lift
up the basket.
This is an example of F=ma
because.
This is an example of F = ma because the net force applied is directly proportional to the weight (mass) of the basket.
What is Newton's Second Law of Motion?Newton's Second Law of Motion states that the acceleration of an object is inversely proportional to its mass and directly proportional to the net force acting on the physical object.
Mathematically, Newton's Second Law of Motion is given by this expression;
F = ma
Where:
F represents the net force.m represents the mass of a physical object.a represents the acceleration of a physical object.In conclusion, the above scenario is an example of the demonstration of Newton's Second Law of Motion.
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A steel cable carries a 3,000 lbs load which is descending with a speed of 12 ft/s. It slows
down uniformly and comes to a halt in 9ft. Compute the tension in the cable during this motion.
The tension in the cable during this motion will be 3750 lbs , when a steel cable carries a 3000 lbs load which is descending with a speed of 12 ft/s.
What is tension and what is speed , and how the tension is calculated out to be 3750 lbs?Tension is specifically the pulling force , when we either pull a rope or an object tension is in action.Here in this question, given 3000 lbs load and speed of 12 ft/s and speed is uniform .The halt is given out to be of 9 ft, for calculating the tension in the cable we will first change units, m = 3000 lbs= 1362 kg , final velocity = v= 12 ft/s = 3.66 m/s, distance= d= 9 ft = 2.745 m.Using the kinematics equation , v^2 = u^2 + 2as , 0^2 - 3.66 ^2 = 2a (2.745), a = -2.44 m/s^2.The tension is calculated by using the equation , mg-T = ma , which equals 3750 lbs.To know more about tension visit:
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Calculate the orbital radius of a geostationary satellite orbiting Saturn, where a day is 10.6 hrs? (MS = 5.7x1026 kg, rS = 5.4x107 m)
In order to find the orbital radius, we need to use Kepler's third law's equation
The formula states:
T^2/R^3 = 4pi^2/G(m)
Since the satellite is geostationary, weknow that the period of the satelitte is going to be 10.6 hours
Plugging in everything we know already
(10.6)^2/R^3 = 4pi^2/G(5.7*10^26)
(10.6)^2/4pi^2/G(5.7*10^26) = R^3
solve for R^3 = 1.08*10^17
R = 476523 m from the surface of Saturn
5.4*10^7 + 476523 = 54476523 meters for the orbital radius
⚠️Please help me!!!⚠️Vector V is 448 m long in a 224 direction. vector W is 336 m long in a 75.9 direction. Find the direction of their vector sum.
The magnitude of the vector sum of the two vectors V and W is determined as 240.84 m.
Resolution of the vectors in x and y axis
The given vector can be resolved into x and y axis as follows;
Vx = Vcosθ
Vx = 448cos(224)
Vx = -322.26
Vy = Vsinθ
Vy = 448 x sin224
Vy = -311.2
Wx = 336 x cos(75.9)
Wx = 81.86
Wy = 336 x sin75.9
Wy = 325.88
∑X = -322.26 + 81.86 = -240.4
∑Y = -311.2 + 325.88 = 14.68
Resultant vector
R = √[(-240.4)² + (14.68)²]
R = 240.84 m
What is vector?In physics, a vector is a quantity with both magnitude and direction. It is often represented by an arrow whose length is proportional to the magnitude of the quantity and whose direction is the same as that of the quantity. A vector does not have position, while having magnitude and direction. In other words, a vector's shape is unaltered if it is shifted parallel to itself as long as its length is unaltered.
Ordinary quantities with a magnitude but no direction are referred to as scalars in contrast to vectors. For instance, while speed, time, and mass are scalars, displacement, velocity, and acceleration are vector values.
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14. A 5.00 kg ball hits a 75.0 kg man standing at rest on ice. The man catches the ball
How fast does the ball need to be moving in order to send the man off at a speed of
3.00 m/s?
Answer:
V₁ = 48 m/s
Explanation:
Using the Conservative Law of Momentum:
∑Qₓ = 0
Q₁ + Q₂ = 0
Q₁ = Q₂ (In absolute values)
Where:
Q₁: right before the impact
Q₂: right after the impact
So:
Q₁ = Q₂
m₁*V₁ + m₂*V₂ = m₁*V + m₂*V (Because both ball and man moves together)
5 * V₁ + 75 * 0 = (5 + 75)*3
5V₁ = 80 * 3
V₁ = 240/5
V₁ = 48 m/s
Three forces act on a moving object. One force has a magnitude of 84.4 N and is directed due north. Another has a magnitude of 42.7 N
and is directed due west. What must be (a) the magnitude and (b) the direction of the third force, such that the object continues to
move with a constant velocity? Express your answer as a positive angle south of east.
The direction of the third force, such that the object continues to
move with a constant velocity is 94.5N at 0.19° south of east.
What is applied force?The force that one thing exerts on another. A barrel being pushed by a human is an illustration of applied force. When the individual pushes the barrel, the barrel experiences an applied force. Newton's second law of motion defines the force formula as follows: A force is equal to an object's mass times its acceleration, or F = m a. You must use SI units when applying this formula: kilograms for mass, meters per second squared for acceleration, and newtons for force. a push or pull that an object has experienced. Here, an object is given a force by a person or any other thing. A chair being pushed to the opposite side of the room, for instance.
For the object to move with constant velocity the total acceleration must be zero.
So,
Total F = [tex]F_{1} +F_{2} +F_{3}[/tex]
ma = 0
[tex]F_{1}[/tex] = 84.4N
[tex]F_{2}[/tex] = 42.7 N
[tex]F_{3} = -F_{1} - F_{2}[/tex]
= 94.58 N
TanФ = 0.19°
Hence [tex]F_{3}[/tex] = 94.5N at 0.19° south of east.
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PLEASE HELP!
1. Terry kicks a soccer ball that is sitting motionless on the field. What is the best description of the energy transfer? (1 point)
A. Kinetic energy is transferred from the soccer ball to Terry's foot
B. Kinetic Energy is Transferred from Terry’s foot to the soccer ball.
C. Kinetic Energy in Terrys Foot is changed to potential energy in the Soccer ball
D. Potential energy is transferred from Terry’s foot to the Soccer ball
2. Which of the Following scenarios best shows the transfer of kinetic energy?
A. a Baseball bat strikes a baseball
B. A baseball player holds a baseball at their side
C. a baseball sits on a bench
D. a baseball flies through the air
3.
A bowling ball is traveling at 7 6 meters per second when it hits a pin. If the bowling ball has a mass of 6 kilograms, how much kinetic energy does it have when it hits the pin?
KB = m²
A. 173.28 J
B. 228 J
C. 346.65 J
D. 693 12 J
4. What happens when a tennis racket hits a ball?
A. Kinetic energy is created.
B. Potential energy in the racket is transferred to the ball.
C.Kinetic energy is transferred from the ball to the racket.
D.Kinetic energy is transferred from the racket to the ball.
Answer:
1. B. Kinetic energy is transferred from Terry's foot to the soccer ball.
2. A. A baseball bat strikes a baseball.
3. A. 173.28J
4. D. Kinetic energy is transferred from the racket to the ball.
Explanation:
I took the quiz and got 100%
Answer:
1. Kinetic energy is transferred from Terry's foot to the soccer ball.
2. A baseball bat stricks a baseball
3. 173.28
4. kinetic energy is transferred from the racket to the ball
5. 1,102.5 J
remember to keep the decimal on the last one
Explanation: They added another question so I decided to give the answer to those who had it.
Atwood machine question: details are in photos attached
First, let's calculate the forces in the 3 kg mass:
[tex]W_1-T=m_1\cdot a[/tex]Then, the forces in the 2 kg mass:
[tex]T-W_2=m_2\cdot a[/tex]From the first equation, let's solve it for T:
[tex]T=W_1-m_1a[/tex]Using this value of T in the second equation, we have:
[tex]\begin{gathered} W_1-m_1a-W_2=m_2\cdot a \\ W_1-W_2=m_2a+m_1a \\ m_1g-m_2g=a\cdot(m_1+m_2)_{} \\ a=g\frac{(m_1-m_2)}{(m_1+m_2)} \end{gathered}[/tex]Finally, using the given values (with g = 10 m/s²), we have:
[tex]a=10\cdot\frac{(3-2)}{(3+2)}=10\cdot\frac{1}{5}=2\text{ m/s2}[/tex]If the acceleration is 2 m/s², after 2 seconds the speed is:
[tex]\begin{gathered} V=V_0+a\cdot t \\ V=0+2\cdot2 \\ V=4\text{ m/s} \end{gathered}[/tex]Therefore the correct option is the second one.
The smooth ER differs from the rough ER in that:
A. The rough ER contains no ribosomes, the smooth ER contains ribosomes.
B. The smooth ER produces carbohydrates and lipids, rough ER produces proteins.
C. The smooth ER produces proteins, rough ER produces lipids.
D. The rough ER is the site of mRNA transcription, smooth ER is the site of protein translation.
An object is launched at a velocity of 28 m/s in a direction making an angle of 23° upward
with the horizontal.
What is the magnitude of the velocity when it hits the ground?
Answer:
Explanation:
Angle:
β = - 23°
( From the symmetry condition)
When light falls on a soap bubble or on the oily film spread on a water puddle, a spectrum of colors is observed. How is this spectrum of colors formed?1) separation of white light by a prism2) absorption of colors in a pigment present3) constructive and destructive interference of light waves4) reflection of light by soap bubble or oil film
When the light falls on a soap bubble spread on a water puddle, and a spectrum of color is observed due to constructive and destructive of light waves which means option (3) is correct. Light waves interfere into each other to produce a spectrum which consists of bright and dark fringes.
a crate is accelerated at .035 m/s for 28.0 s along a conveyor belt. If the crates initial speed is 0.76 m/s what is it's final speed?
The final speed of the crate with an initial speed of 0.76 m / s accelerated at 0.035 m/s for 28.0 s along a conveyor belt is 1.74 m / s
v = u + at
v = Final speed
u = Initial speed
a = Acceleration
t = Time
a = 0.035 m / s²
y = 28 s
u = 0.76 m / s
v = 0.76 + ( 0.035 * 28 )
v = 0.76 + 0.98
v = 1.74 m / s
The equation used to solve the problem is an equation of motion. An equation of motion describes the position of an object using acceleration, displacement, time, initial and final velocities.
Therefore, the final speed of the crate is 1.74 m / s
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A young researcher wants to test how well extremophiles, organisms that thrive in extreme conditions, live in different environments. She will do this by putting extremophiles of different species into different solvents
Because of limited lab space, she can run only one sample at a time, and each sample must remain undisturbed for 7 days. To reduce the total time needed to process all samples, the researcher decides to use two acidic
solutions along with a control. The information below includes the extremophiles and the solvents the researcher will use in her tests.
Solvents
Species of
Extremophiles
T. prosperus
A. aceti
Based on the tables, how many days will all of the researcher's experiments take?
You may use the calculator.
OA. 7
OB. 21
OC. 49
OD. 84
A brierleyi
H. acidophilum
Name
hydrochloric acid
ascorbic acid
water
PH
1.3
4.2
7.0
It will take exactly 84 days with all the researcher's experiments , even after reducing the total time needed to process all samples.
What is an extremophile and how to take the samples and notice their living condition?As is explained in the question as well an extremophile is the kind of organism can better thrive or live in harsh or extreme conditions.Some examples of extremophilic species are polar bears living in extreme cold regions .Here in this question the researcher has taken two samples for reducing the time of results, in which one extremophile takes 7 days to grow.Taking two samples would count to 14 days for one extremophile , and the researcher in the question took 4 samples and three solvents.In the way total of 84 days would be required by the researchers to obtain the result of the change in the living environment of extremophilic species.To know more about extremophile visit:
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pls help, it's due tomorrow!
An electron travels 2.68 m in 6.11 × 10−8 s. How fast does it travel in cm/s? Answer in units of cm/s.
The speed (in cm/s) of the electron, given that it travels 2.68 m in 6.11×10⁻⁸ s is 4.39×10⁵ cm/s
How to determine the speedWe'll begin by defining speed. This is given below.
Speed is defined as the distance travelled per unit.
Speed = distance / time
With the above formula, we can obtain the speed of the electron. Details below
The following data were obtained from the question give above:
Distance = 2.68 m = 2.68 / 100 = 0.0268 cmTime = 6.11×10⁻⁸ sSpeed =?Speed = distance / time
Speed = 0.0268 cm / 6.11×10⁻⁸ s
Speed = 4.39×10⁵ cm/s
Therefore, the speed is 4.39×10⁵ cm/s
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calculate the current that flows through a 60W bulb if the voltage across is 230V
The current flow through a 60W bulb if the voltage across is 230V is 0.26 A.
P = V I
P = Power
V = Voltage
I = Current
P = 60 W
V = 230 V
I = P / V
I = 60 / 230
I = 0.26 A
Ohm's law states that if the temperature across a conductor remains the constant, the ratio of potential difference across the conductor to the current flowing in the conductor will also be constant.
Therefore, the current flow through a 60W bulb if the voltage across is 230V is 0.26 A.
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Calculate the braking distance force for a driver of a 1200kg car traveling at an initial speed of 10m/s above with a braking force of -8000N
The braking distance of the driver of a 1200 kg car traveling at an initial speed of 10m/s is 7.5 m
How to determine the distanceWe'll begin by obtainig the acceleration of the car. This can be obtained as follow:
Mass (m) = 1200 KgForce (F) = -8000 NAcceleration (a) =?Force = mass × acceleration
-8000 = 1200 × a
Divide both sides by 1200
a = -8000 / 1200
a = -6.67 m/s²
Finally, we shall determine the distance. Details below
Initial velocity (u) = 10 m/sFinal velocity (v) = 0 m/s (at maximum height)Acceleration(a) = -6.67 m/s²Distance (s) =?v² = u² + 2as
0² = 10² + (2 × -6.67 × s)
0 = 100 - 13.34s
Collect like terms
0 - 100 = -13.34s
-100 = -13.34s
Divide both side by -13.34
s = -100 / -13.34
s = 7.5 m
From the above calculation, we conclude that the breaking distance is 7.5 m
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Félix baumgartner jumps out of a hot air balloon at a height of 39km. He wears a special suit and his total mass is 120kg. He was the first person to break sound barrier( at a velocity of 343m/s). Calculate how far in km he had fallen to break the sound barrier
The distance in Km he has fallen to break the sound barrier is 6 Km
To obtain the answer to the question, we'll beging by calculating the time taken to break the sound barrier. This can be obtained as follow:
Initial velocity (u) = 0 m/sAcceleration due to gravity (g) = 9.8 m/s²Final velocity (v) = 343Time (t) = ?v = u + gt
343 = 0 + (9.8 × t)
343 = 0 + 9.8t
343 = 9.8t
Divide both sides by 9.8
t = 343 / 9.8
t = 35 s
How to determine the heightFinally, we can obtain the height as follow:
Time (t) = 35 sAcceleration due to gravity (g) = 9.8 m/s²Height (h) =?h = ½gt²
h = ½ × 9.8 × 35²
h = 4.9 × 1225
h = 6002.5
Divide by 1000 to express in Km
h = 6002.5 / 1000
h = 6 Km
Thus, Félix baumgartner broke the sound barrier when he had fallen 6 Km
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A hydraulic lift is used to lift a car. The small piston has a radius of 5 cm and the large piston has a radius of 50 cm. If a driver applies a force of 88 N to the small piston, what is the weight of the car the large piston can support?
Answer:
F = 880 N
Explanation:
Apply Pascal's Principle.
f / a = F / A
Because the pressure (P = F/A) is equal on both sides of the piston.
So, using the International System of Units:
f / a = F / A
88 / 0.05 = F / 0.50
F = (88/0.05) * 0.50
F = 880 N
calculate the net force acting on the box in the following. refer to the screenshot below.
The net force acting on the box is 5N , and it is unbalanced.
since the forces acting on the system is 7N and 2N which is opposite direction.
Explanation:The sum of all forces acting on an object is known as net force. Newton's second law, which states that F = ma, where F is the net force, can be used to calculate the net force. m is the object's mass. a represents acceleration.When two forces act in the same direction on an object, the net force equals the sum of the two forces.In general, when opposing forces act on an object, such as the book on the table, the net force equals the difference between the two forces. In other words, the net force is calculated by subtracting one force from the other. The net force is zero if the opposing forces are equal or balanced.
here given two forces ,
f1 = 7N
f2 = 2N
since both forces are in opposite direction ,
Net force = f1 - f2
= 7N - 2N
= 5N
so the net force that act on the given box is 5N and unbalanced .
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(Figure 1) is the potential-energy diagram for a 500 g
particle that is released from rest at A. What is the particles speed at B?
The particles speed at B is 12 m/s .
What are kinetic and potential energy?Potential energy is the energy that is held in reserve in any system or object as a result of how its components are positioned or assembled. The external environment, such as air or height, is not a factor in this, though. The energy that an object or a system's particles have while in motion, however, is known as kinetic energy. An item or particle's motion gives it kinetic energy, which it might use to move. An item accelerates and gains kinetic energy when work, which transfers energy, is done on it by exerting a net force. Potential energy is a form of stored energy that is dependent on the arrangement of a system's components. In a compressed state, a spring has higher potential energy.
The mass of the particle = 500g
= 0.5 kg
The energy of the particle when it is released
E = 5g
The potential energy at B
= 2 J
Loss in potential energy = gain in kinetic energy.
K.E.= 1/2 × m × v²
Here after putting values we get
speed at B = 12m/s.
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An intergalactic spaceship arrives at a distant planet that rotates on its axis with a period of [tex]T=26 hours[/tex]. The mass of the planet is [tex]M=4.9*10^{25} kg[/tex]. The spaceship enters a circular orbit with an orbital period that is equal to the planet's period for the rotation about its axis, T.
A) Enter an expression for the radius of the spaceship's orbit.
(I tried [tex]R=(T^{2} GM/4pi^{2} )^{1/3}[/tex] but its says incorrect and that's all I've been able to find)
B) Calculate the orbital radius in meters.
The orbital period could be obtained from the question as 8.98 * 10^7 m.
What is the orbital period?We know that the solar system is composed of the sun and the planets. The planets are known to move around the sun in concentric circles. Following the heliocentric model of the solar system, the sun is at the center of the solar system at all times and all the other planets tend to move round the sun at a good distance that is appropriate for each.
Now we have that;
T = √4π^2r^3/GM
T = period of the orbit
r = radius of the orbit
G = gravitational constant
M = mass of the planet
Hence, we have;
R = ∛T^2GM/4π^2
R =∛ (26 * 60 * 60)^2 * 6.67 * 10^-11 * 4.9 * 10^25/ 4 * (3.142)^2
R = ∛2.86 * 10^25/39.49
R = 8.98 * 10^7 m
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How will the electrical force between two charged particles change if thedistance between them is increased by 4 times the amount?
Given that the distance between the two charged particles is increased by 4 times the amout, let's determine how the electrical force between them will change.
The electrical force between two charged particles is determined by the formula:
[tex]F=k\frac{q_1q_2}{r^2}[/tex]Where:
k is the constant
q1 and q2 are the two charged particles
r is the distance between the particles
From the formula, we can see that the electrical force between them is inversely proportional to the the square of the distance between the charged particles.
Thus, in order to increase the electrical force, the distance must be decreased.
If the electrical force is changed by a factor of