WHO EVER ANSWERS FIRST GETS BRAINLIEST I REALLY NEED HELP!!!








simplify... (3/8)^-2(1/3•3/8)^3(1/3)^4

3xcubed y to the fifth over 2

Answer:

After 12 games.

Step-by-step explanation:

Deanna's money after playing 12 games =

15 - (0.75 × 12) = 6$

Lisa's money after playing 12 games =

12 - (0.50 × 12) = 6$

Set [tex]y = f^{-1}(x)[/tex] and [tex]f(y) = x[/tex]

Interchange the variables [tex]x[/tex] and [tex]y[/tex]

[tex]3y + 28 = x\\3y = x - 28\\y = \frac{x - 28}{3} \\\\f^{-1}(x) = \frac{x - 28}{3}[/tex]

The answer is -2 , 0, and 4

Answer:

The equation of any straight line, called a linear equation, can be written as: y = mx + b, where m is the slope of the line and b is the y-intercept. The y-intercept of this line is the value of y at the point where the line crosses the y axis.

Step-by-step explanation:

I had this question not to long ago and got it right

Answer:

it would be translated up.

Step-by-step explanation:

(-2,-2)    (x-3, y+4)

-2-3= -5    -2+4= 2

      (-5,2)

Answer:

C. The student did not put the polynomial in standard form before naming it by the first term. It is a fourth-degree trinomial.

Step-by-step explanation:

A trinomial is a polynomial with three variables. The polynomial -2x³ + 5x⁴ - 3x has three variables hence it is a trinomial.

The degree of a polynomial is the highest degree of a variable in a polynomial equation.

The polynomial -2x³ + 5x⁴ - 3x can be arranged as The polynomial 5x⁴ - 2x³ - 3x, hence the variable with the highest degree is 5x⁴ which has a degree of 4.

Therefore The polynomial -2x³ + 5x⁴ - 3x  has a degree of 4

This means the polynomial -2x³ + 5x⁴ - 3x is a trinomial with a degree of 4

Answer:

Step-by-step explanation:

Given function

Let's try point x = 0

So the vertex moves right

See attached

I think it's TRUE so yeah.

Step-by-step explanation:

yf.bfz

vcg ,kgu nkkgfgvvxvh

Answer:

It would take 2.4 minutes

Step-by-step explanation:

Time span can never be different for the same two people. Therefore in 3 minutes, John's mother would have covered a distance of 15(3) = 45 meters. Respectively John would have covered a distance of 25(3) = 75 meters in the same time.

Distance from 'starting point' to the market: 45 m + 15 m = 60 meters,

Time that John takes to return from market, and meet with his mother

=> 15 / 25 (his speed) = 0.6,

Time it takes John to get to the market: 3 - 0.6 = 2.4 minutes

Answer:

2.4 mins

2mins 24 sec

Step-by-step explanation:

Answer:

10

Step-by-step explanation:

Remember that the formula for the sum of an arithmetic series is:

[tex]S=\frac{k}{2}(a+x_k)[/tex]

Where k is the number of terms, a is the initial term, and x_k is the last term of the series.

We essentially want to find k, the number of terms, given that the sum S is equal to 105. So, substitute 105 into our equation:

[tex]105=\frac{k}{2}(a+x_k)[/tex]

To do so, we need to final term x_k. We don't know what it is yet, but that doesn't matter. All we need to do is to write it in terms of k. First, remember that the standard form for the explicit formula of an arithmetic sequence is:

[tex]x_n=a+d(n-1)[/tex]

Where a is the first term, d is the common difference, and n is the nth term.

From our sequence, we can see that the first term is -3.

Also, we can determine that our common difference is +3, since each subsequent term is 3 more than the previous one. -3+3 is 0, 0+3 is 3, 3+3 is 6, and so on.

Therefore, our explicit formula is:

[tex]x_n=-3+3(n-1)[/tex]

Therefore, our final term, x_k, will be if we substitute k for n. So, we can acquire the equation:

[tex]x_k=-3+3(k-1)[/tex]

Now that we know what x_k is, we can substitute that into our original equation:

[tex]105=\frac{k}{2}(a+x_k)[/tex]

Substitute the equation into x_k. Also, let's substitute -3 (our first term) for a. So:

[tex]105=\frac{k}{2}(-3+(-3+3(k-1)))[/tex]

And now, all we have to do is to solve for k.

First, distribute the 3:

[tex]105=\frac{k}{2}(-3+(-3+3k-3))[/tex]

Add within the parentheses:

[tex]105=\frac{k}{2}(3k-9)[/tex]

Multiply both sides by 2. This removes the fraction on the right:

[tex]210=k(3k-9)[/tex]

Distribute. We will get a quadratic:

[tex]210=3k^2-9k[/tex]

So, let's solve for k. Let's divide everything by 3:

[tex]70=k^2-3k[/tex]

Subtract 70 from both sides:

[tex]0=k^2-3k-70[/tex]

Factor. We can use -10 and 7. So:

[tex]0=(k-10)(k+7)[/tex]

Zero Product Property:

[tex]k-10=0\text{ or } k+7=0[/tex]

Solve for k for each equation:

[tex]k=10\text{ or } k=-7[/tex]

-7 doesn't make sense (we can't have -7 terms). Remove that solution. So, we are left with:

[tex]k=10[/tex]

Therefore, the number of terms we have in our series for our sum to be 105 is 10.

And we're done!

Answer:

  x = 7

Step-by-step explanation:

First, you look at the equation. Identify the locations of variable terms (both sides of the equal sign) and the constant terms (both sides of the equal sign).

If there are any parentheses, it is a good idea to use the distributive property to eliminate them. Here, there are none.

I like to start by subtracting the variable term with the smallest coefficient. Here, that is 3x, so we add -3x to both sides of the equation.

  3x -3x +1 = 5x -3x -13

  1 = 2x -13 . . . . . . . . . . . . combine like terms

Now, we have the only variable term on one side of the equal sign. We want it by itself, so we need to make the -13 go away. We do that by adding its opposite to both sides of the equation:

  1 +13 = 2x -13 +13

  14 = 2x . . . . . . . . . . . . combine like terms

Finally, we want the coefficient of 2 in the x-term to disappear. We make that happen by multiplying both sides of the equation by 1/2, the reciprocal of that coefficient.

  (1/2)(14) = (1/2)(2x)

  7 = x . . . . the solution

__

It is generally a good idea to check your work by seeing if your solution value satisfies the equation:

  3(7) +1 = 5(7) -13 . . . . put 7 where x is in the original equation

  21 +1 = 35 -13

  22 = 22 . . . . . . x = 7 is the solution

_____

Additional comment

By subtracting 3x from 5x, the result is 2x with a positive coefficient. We could solve the equation just as easily by subtracting 5x from 3x. That result would be ...

  -2x +1 = -13

Subtracting 1 would give

  -2x = -14

and you would multiply by -1/2 to get x=7. I personally like to avoid having this many minus signs show up in the problem. That is why I choose to subtract the x-term with the smallest coefficient.

Answer:

[tex]x^{20}[/tex]

Step-by-step explanation:

[tex](x^{2} )^{5}[/tex]·[tex](x^{5})^{2}[/tex]

[tex](x^{10} )[/tex] · [tex](x^{10})[/tex]

[tex]x^{20}[/tex]

Given: 2/3 every 30 seconds

If we cut 2/3 in half, we get 1/3. This would also mean we cut the time in half 30 / 2 = 15 seconds

Therefore, 1/3 of the length every 15 seconds.

15 + 15 + 15 = 45 seconds to go the full length of the path

Answer: 11

Step-by-step explanation: 7+1+1+1+1 = 11

                                            7   8 9 10 11

Divide 30 by 25% to find the full amount:

30/0.25 = 120

Now multiply the full amount by 40%:

120 x 0.40 = 30

Answer:

A= 16

B=?

Step-by-step explanation: srry about the second one im also confused but i tried my best.

Answer:

a) 3.2 cm

b) 6.25 km

Answer:

58

Step-by-step explanation:

I have attached an image with this answer that will help you to visualise this question. I will now explain it.

The smaller number (Number 1) has 1 unit.

The bigger number (Number 2) has 1 unit, and 19.

If you add 19 to the smaller number, you will make two of the bigger number.

[tex]97+19=116[/tex]

This is equivalent to two of the bigger number. (Try to visualise it!)

Hence, divide it by 2 to get one of the bigger number.

[tex]116\div2=58[/tex]

Answer:

58

Step-by-step explanation:

The smaller number (Number 1) has 1 unit.

The bigger number (Number 2) has 1 unit, and 19.

If you add 19 to the smaller number, you will make two of the bigger number.

This is equivalent to two of the bigger number. (Try to visualise it!)

Hence, divide it by 2 to get one of the bigger number.

Answer:

3/8

Step-by-step explanation:

Answer:

153.2 =x

Step-by-step explanation:

Since this is a right triangle, we can use trig functions

cos theta = adjacent side/ hypotenuse

cos 40 = x/200

Multiply each side by 200

200 cos 40 = x/200 * 200

200 cos 40 =x

153.20888886=x

To the nearest tenth

153.2 =x

Answer:

AC = 153.2 m.

Step-by-step explanation:

cos(Ф) = adj / hyp

cos(40) = AC / 200

AC = cos(40) x 200

AC = 153.2 m

Answer:

-19n^4 - 8m^2 - 12m^4n

Step-by-step explanation:

8m^2 + 12m^4n + 9mn

-

19n^4 9mn

------------------------------------------------------------------------

-19n^4 - 8m^2 - 12m^4n

Answer:

The answer is B.) -31m^4n-8m^2

Answer:

t= -0.18

Step-by-step explanation:

Isolate t to get the unknown number:

(-4.5t)(49.5t) = 40

      Multiply (-4.5t)(49.5t):

                     (-4.5t)(49.5t) = -222.75t

      Now, write full equation:

          -222.75t = 40

      Isolate t by dividing -222.75 on both sides:

           [tex]\frac{-222.75}{-222.75}t=\frac{40}{-222.75}[/tex]

      Cancel out left hand side:

            [tex]t=\frac{40}{-222.75}[/tex]

      Simplify your answer:

              [tex]t=-0.17957351[/tex]

      Approximate to 2 decimals:

           [tex]t=-0.18[/tex]

Step-by-step explanation:

acute angle is a tiny angle obtuse is a wide 180 straight is just a straight line and a right angle is a right angle which equals 90 degrees

Answer:

Acute angle refers to angle less than 90

Obtuse angle refers to angle greater than 90 but less than 180

straight line angle is equal to 180

right angle is equal to 90

Answer:

total stick she has = 9*4 = 36

6 sticker is need in 1 page

so page required for 36 stickers = 36/6 = 6pages

Step-by-step explanation:

Complete Question

Find a particular solution to [tex]ty''-(1+t)y'+y=t^2e^t , t > 0[/tex]  

[tex]y_1 = 1 + t , \ y_2 = e^t[/tex]

Answer:

The solution is    [tex]y_p = -e^{2t} + t + \frac{3t^2}{2} + \frac{t^3}{2}[/tex]

Step-by-step explanation:

  Now the given equation is [tex]ty''-(1+t)y'+y=t^2e^t , t > 0[/tex]

             dividing through by  t

       We have  

         [tex]y'' - \frac{1 + t }{t}y' + \frac{1}{t} y = te^t \\\\ let's\ call\ it \ g(t)[/tex]

Now for the given initial value we can generate our Wronskian as follows

        [tex]W(y_1 ,y_2) = | \left y_1} \atop {y_1'}} \right. \left y_2} \atop {y_2'}} \right | = | \left {(1 + t)} \atop {1}} \right. \left e^t} \atop {e^t}} \right | = (1 + t )e^t - e^t = te^t[/tex]

Now applying  method of variation of parameters to obtain the particular solution

So here we assume that

          [tex]y_p = v_1 y_1 + v_2 y_2[/tex]

So

       [tex]v_1 = - \int\limits {\frac{y_2 (t) g(t)}{W(t)} } \, dt = - \int\limits {\frac{e^t te^t}{te^t} } = - \int\limits { e^t} } = -e^t[/tex]

And

    [tex]v_2 = - \int\limits {\frac{y_1 (t) g(t)}{W(t)} } \, dt = - \int\limits {\frac{(1 + t) te^t}{te^t} } = - \int\limits (1 + t) = t + \frac{t^2}{2}[/tex]

So

     [tex]y_p = -e^t * e^t + t + \frac{t^2}{2} * 1 + t[/tex]

     [tex]y_p  =  -e^{2t}   +  t +   \frac{3t^2}{2} + \frac{t^3}{2}[/tex]