Who did the ram caught in the thicket (Genesis 22:13) represent?

Answers

Answer 1

Answer:

I think the answer is goat


Related Questions

Identify the types of motion a) The movement of a snail on the ground b) The strings of the guitar c) The whirling of stone tied with a thread

Answers

Answer:

1. friction, gravity,

Explanation:

If 90J of energy are available for every 30C of charge, what is the potential difference?
Enter your answer as a number
V

Answers

Answer:

3 v

Explanation:

explain how wind erosion changes land forms

Answers

Answer:

the wind carries abrasive materials

Explanation:

such as sand and salt over time theses small particles slowly strip way at the land form sculpting it by eroding the softer layers first

What do these weapon stats mean?

Idle sway control is measured in Fc???

Flinch resistance is measured in N.

Answers

Answer:

its sort of like how Pounds are measured in lbs

Explanation:

Pounds are measured in lbs when they dont sound anything similar, same thing applies to gun technology.

Someone help me please !!!! Will mark Brianliest !!!!!!!!!!!!!!!!

Answers

The answer is the second one, because in exothermic reactions energy is released.

Which ball moved at the same speed as Ball 3?

Answers

Answer:

you forgot to attach the image

4. Protons and neutrons are held together to form this _________

Answers

Answer:

strong nuclear force.

Explanation:

hope this helps you!!

Two 5 kg potted cacti, one in a black pot and one in a blue pot, slide down a sagging shelf in the same direction with
the same speed.
Which two equations correctly model the momentum of the two-cactus system?

Answers

Answer:

Answers A and D are the correct solution.

Explanation:

Both pots have the same mass and the same velocity vector.

the only difference between A and D is the selection of the reference frame positive direction.

The equation (A) and equation (D) correctly model the momentum of the two-cactus system.

What is momentum?

The product of a particle's mass and velocity is called momentum. Being a vector quantity, momentum possesses both magnitude and direction.

According to Isaac Newton's second equation of motion, the force applied on a particle is equal to the time rate of change of momentum.

Given that: mass of each cactus: m = 5 kg.

And they slide down a sagging shelf in the same direction with the same speed.

In equation (A), both velocities of two cacti are in positive direction whereas, in equation (B), both velocities of two cacti is in negative direction.  Hence, equation (A) and equation (D) correctly model the momentum of the two-cactus system.

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13. In which of the following climates does chemical weathering generally occur most
rapidly?
A. Canda
B. Greenland
C. Brazil
D. Algeria

Answers

Brazil would be the correct answer I believe

please help me !!
Gymnasts often practice on foam floors, which increase the collision time when a gymnast falls. What effect does this have on collisions?
A. The change in momentum needed to stop the gymnast is increased.
B. The change in momentum needed to stop the gymnast is decreased.
C. The force exerted by the floor on the gymnast decreases.
D. The force exerted by the floor on the gymnast increases.

Answers

The correct answer is B

How large is the acceleration of a 25 kg mass with a net force of 75 N applied horizontally to it?

Answers

Answer:

Explanation:

F = ma

a = F/m

a = 75/25

a = 3 m/s²

The amplitude of a lightly damped oscillator decreases by 4.2% during each cycle. What percentage of the mechanical energy of the oscillator is lost in each cycle?

Answers

Answer:

V= A ω      maximum KE of object in SHM

V2 / V1 = .958     ratio of amplitudes since ω is constant

KE2 / KE1 = 1/2 m V2^2 / (1/2 m V1^2) = (V2 / V1)^2

KE2 / KE1 = .958^2 = .918

So KE2 = .918 KE1 and .082 = 8.2% of the energy is lost in one cycle

Một chất điểm khối lượng m=200g chuyển
động chậm dần với vận tốc biến đổi theo qui luật
v=30 – 0,4t2 (SI). Lực hãm tác dụng vào chất điểm
lúc t = 5 giây là
A. 8 N B. 0,8 N C. 4 N D. 0,4 N

Answers

Can you please translate to English?

The intensity of a sound wave increases as the wave spreads out from the source of the sound. True or false

Answers

Answer:False

Explanation:

the intensity of the sound wave decreases with increasing distance from the source.

Need quite a bit of help

Answers

When the cart was at Table

Normal reaction (N)=mg

Now acceleration due to gravity acting on the gravity.

When the air comes out of straw it tries to take the cart upwards.But the force is equal to that of acceleration due to gravity but in opposite direction.

Hence.

[tex]\\ \sf\Rrightarrow F_{net}=0N[/tex]

So the cart doesn't move

how long is the photons journey from the milky way to earth

Answers

well i’d love to answer your question but its missing some information. firstly the earth is within the milky way galaxy so something cannot travel “from” but if you said “through” the answer would be 299,792,458 meters a second

How should an artistic statement be written?

ОА.

from your own perspective

OB.

in a non-factual, persuasive manner

O C.

as a lengthy and overly extensive essay

OD. by the artist alone with no outside critique

Answers

An artistic statement should be written from your own perspective.

What is an artistic statement ?

An artist's statement, also known as an artist statement, is a written summary of their creative output. The brief essay serves as an explanation of and a defense of their own work for the spectator. As a result, it is didactic, descriptive, or reflective in nature and seeks to inform, connect with an artistic environment, and reveal the inspiration behind the work.

The writing created by the artist aims to contextualize, justify, extend, and/or explain their body of work. It situates—or tries to situate—the piece in relation to art history, art theory, the contemporary art scene, and the times. The statement also demonstrates that the artist is aware of their aims, their practice, its place within the parameters of art, and the debate that surrounds it.

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a car moves at a speed of 30m/s to the west of 3hr, what is its displacement of the car in km?​

Answers

Answer:

Explanation:

30 m/s • 3 hr •3600 s/hr / 1000 m/km = 324 km west

Velocity is an extensive property of a system. TRUE OR FALSE​

Answers

[tex] \: \: \: [/tex]

[tex] \pink{false}[/tex]

because velocity is neither an intensive nor extensive property

hope it helps

Answer:

False

Explanation:

I hope this helped have a great day!!!

A 1500 kg car has the same momentum as a 2500 kg truck moving at 25 m/s. How fast is the car moving in m/s

Answers

Answer:

41.6m/s

Explanation:

P=mv

2500kg × 25m/s = 62500kgm/s

62500kgm/s ÷ 1500 kg = 41.6m/s

using dimensional analysis find the relation between the velocities of transverse waves produced from the vibration of thin homogeneous string and between the tension in the string and mass per unit length of it.​

Answers

Answer:

[tex]v^2=\frac{T}{M}[/tex]

where v = transverse wave velocity, T = tension in the string, M = mass per unit length.

Explanation:

Dimensional analysis is where you just look at the units and see how they fit within each other.

In this case, all relationships are made using the MLT comparisons, where M stands for Mass, L stands for Length, and T stands for time.

For example, for velocity, we know the SI unit for velocity is [ms⁻¹] which is L¹T⁻¹, we can do the same thing for tension = [N = Kgms⁻²] = M¹L¹S⁻², and for the mass per unit length which we can think of as [Kgm⁻¹] = M¹L⁻¹.

If you play around a little with the powers, you can find a relationship:

[tex]v^2=\frac{T}{M}[/tex]

since:

[L¹T⁻¹]² = L²T⁻² = M¹L¹T⁻² ÷ M¹L⁻¹ = M¹⁻¹L¹⁻⁽⁻¹⁾T⁻² = M⁰L²T⁻² = L²T⁻²

Which one is it??? The question and the choice are in the photo.

Answers

The answer is:

That they are switched on

A sailcraft is stalled on a windless day. A fan is attached to the craft and blows air into the sail which bounces backward upon impact. The boat can what?

Answers

Answer:

Impulse = change in momentum w bounce

There are 2 impulses acting. Recoil of the fan going the negative direction and the impulse of the air bouncing off the sail. The greater impulse will bounce so the direction will be to the right moving the craft.

a
A soccer player kicks a ball horizontally and it travels 150 m. The ball was kicked off of a cliff that was 75 m
high. What speed was the ball kicked at?

Answers

The ball was kicked with a speed of 38.4 m/s.

Using s = ut + 1/2gt², we find the time it takes the ball to reach the ground. Where

s = height of cliff = 75 mu = initial vertical velocity of ball = 0 m/s(since it is kicked horizontally)g = acceleration due to gravity = 9.8 m/s²t = time taken for ball to reach the ground.

Substituting the values of the variables into the equation, we have

s = ut + 1/2gt²

75 m = (0 m/s)t + 1/2 × 9.8 m/s² × t²

75 m = 0 m + (4.9 m/s²) t²

75 m = (4.9 m/s²)t²

Dividing both sides by 4.9, we have

t² = 75 m/4.9 m/s²

t² = 15.306 s²

Taking square-root of both sides, we have

t = √15.306 s²

t = 3.91 s

The horizontal distance covered by the ball d = vt where

v = horizontal speed of ball and, t = time taken for the ball to reach the ground.

Since we require v, we make it subject of the formula.

So, v = d/t

Given that d = 150 m and t = 3.91 s, substituting these into v, we have

v = d/t

v = 150 m/3.91 s

v = 38.4 m/s

So, the ball was kicked with a speed of 38.4 m/s.

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A rock sinks straight down the surface of a pond, starting from rest and accelerating at an average rate of 2m/s^2 for the first 3 seconds of its motion. At the 3-second mark, the rock reaches its terminal speed and continues at that speed for the remaining 30 meters of motion. What is the total time it takes for the rock to sink from the surface to the bottom of the lake?

Answers

Answer:

Explanation:

Terminal speed is

2 m/s²(3 s) = 6 m/s

30 m / 6 m/s = 5 s

total sink time is

3 + 5 = 8 s

The total time taken by the rock to sink would be 8 seconds

What is Velocity?

The total displacement covered by any object per unit of time is known as velocity. It depends on the magnitude as well as the direction of the moving object.

The acceleration of the rock for the first three seconds = 2 meters/second²

The time taken to reach the terminal velocity = 3 seconds

terminal velocity = 2 ×3

                           = 6 meters/second²

The time for which the rock sink at terminal velocity = 30 /6

                                                                                       = 5 seconds

total time is taken by the rock to sink = 3 + 5

                                                           =8 seconds

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The work done by an electric force in moving a charge from point A to point B is 2.70 × 10‒3 J. The electric potential difference between the two points is VA ‒ VB = 50.0 V. What is the charge?

Answers

The charge moved by this electric force is [tex]5.4 \times 10^{-5} \; Coulombs[/tex].

Given the following data:

Work done = [tex]2.70 \times 10^{-3}\;Joules[/tex]Potential difference = 50.0 Volts

To determine the charge:

Mathematically, the work done by an electric force in moving a charge from one point to another is given by the formula:

[tex]W = PQ[/tex]

Where:

W is the work done.P is the electric potential difference.Q is the charge.

Making Q the subject of formula, we have:

[tex]Q =\frac{W}{P}[/tex]

Substituting the given parameters into the formula, we have;

[tex]Q =\frac{2.70 \times 10^{-3}}{50}\\\\Q =5.4 \times 10^{-5} \; Coulombs[/tex]

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Two positive charges of 1 mC and 10 mC are separated by a distance of 10 m. Find the

direction and the magnitude of electrostatic force between the charges. |Describe the

direction in terms of the charges attract each other," or "the charges repel each other."

mili C=1043 C

Answers

Answer:

900N, charges repel

Explanation:

F = KQq/d²

K = 9 × 10^9Nm²/C²

Q= 10mC = 10 × 10^-3C

q = 1mc = 1 × 10^-3C

d = 10m

F = ?

Force = (9 × 10^9 × 10 × 10^-3 × 1 × 10^-3)/10²

= 9 × 10²

= 900N

It will be an electrostatic force of repulsion since like charges(two positive charges) repel

The magnitude and the direction of the electrostatic force between the charges will be 900N and the charges will repel each other.

What is Coulomb's law of forces?

Coulomb's law states that whenever the two charged particles are separated by a particular distance then there will be a force of attraction or repulsion acts between the charge.

The formula of coulomb's force will be given by

[tex]F=k\dfrac{q_1q_2}{d^2}[/tex]

[tex]K=9\times 10^9\ \frac{Nm^2}{C^2}[/tex]

[tex]q_1= 10\times 10^{-3}\ C[/tex]

[tex]q_2=1\times 10^{-3}\ C[/tex]

[tex]\rm Distance \ d=10 \ m[/tex]

Now the force will be calculated as

[tex]F=(9\times 10^9)\dfrac{(10\times 10^{-3})\times (1\times 10^{-3})}{10}[/tex]

[tex]F= 900\ N[/tex]

The charges are positive in nature so they will repel each other

Hence the magnitude and the direction of the electrostatic force between the charges will be 900N and the charges will repel each other.

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The fundamental of a closed organ pipe is 259.6 Hz. The second harmonic of an open organ pipe has the same frequency. What is the length of the closed pipe

Answers

Answer:

A closed organ pipe is λ/4  (node-antinode) long.

λ = speed / frequency = 331.5 / 259.6 = 1.28 m

λ/4 = .319 m     length of closed pipe

An open pipe has a fundamental wavelength of A-N-A or λ/2

The second harmonic would be A-N-A-N-A   or   λ = 1.28 m for the second harmonic   331.5 / 259.6 = 1.28  (the fundamental would be 331.5 / .628

1. An electrically charged atom ___________

Answers

Answer:

Is called an Ion

Explanation:

Answer:

An electrically charged atom is called an ion

URGENTLY NEED HELP

This is a 2 part question

42) You pull downward with a force of 28 N on a rope that passes over a disk-shaped pulley of mass 1.2 kg and radius 0.075 m. The other end of the rope is attached to a 0.67-kg mass. (a) Is the tension in the rope the same on both sides of the pulley? If not, which side has the greater tension? (b) Find the tension in the rope on both sides of the pulley.

Answers

Answer:

The net force on the hanging mass is thus

2 T Mg     18 6.6 N 11.4 N

, enough to accelerate it upward at

17 m/s2

. The angular acceleration of the pulley is thus

   

2 2

Explanation:

The tension in the rope on both sides of the pulley 20.21N.

To solve this problem, we'll need to consider the forces acting on both sides of the pulley and apply Newton's second law of motion. Let's break it down step by step:

(a) Is the tension in the rope the same on both sides of the pulley?

No, the tension in the rope is not the same on both sides of the pulley. The side with the greater mass attached will experience a greater tension in the rope.

(b) Find the tension in the rope on both sides of the pulley:

Calculate the gravitational force on each mass:

Gravitational force on the pulley: Fpulley = mpulley * g, where mpulley is the mass of the pulley and g is the acceleration due to gravity (approximately 9.8 m/s²).

Gravitational force on the hanging mass: Fhanging = mhanging * g, where m_hanging is the mass of the hanging mass.

Calculate the net force on the pulley:

Net force on the pulley is the difference between the tension forces on either side: Fnet = TLeft - Tright.

Apply Newton's second law to the pulley:

For the pulley, Fnet = mpulley * a, where a is the acceleration of the pulley. Since the pulley is assumed to be massless, we can use the relationship a = α * r, where α is the angular acceleration and r is the radius of the pulley.

Use the relationship between linear acceleration and angular acceleration:

α = a / r.

Equate the torque due to the tension to the moment of inertia times the angular acceleration:

τ = I * α, where τ is the torque, I is the moment of inertia of the pulley, and α is the angular acceleration.

Substitute the expression for α and solve for the net tension:

Tnet = (τ / r) = (I * α) / r = (1/2 * mpulley * r² * α) / r = (1/2 * mpulley * r * a).

Now, substitute the expression for a from step 3 and solve for the net tension:

Tnet = (1/2 * mpulley * r * α) = (1/2 * mpulley * r * (a / r)) = (1/2 * mpulley * a).

Substitute the expression for a from step 2 (Fnet = mpulley * a) and solve for the net tension:

Tnet = (1/2 * Fnet).

Now, you can find the tensions on each side of the pulley:

Tleft = Tnet + Fhanging

Tright = Tnet - Fpulle

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