Answer:
Option E
Explanation:
Option E, ie, Radian is not consider to be a fundamental quantity unit and it is used to measure the plane angle.
Seven Fundamental units are:
MetreSecondsKilogramAmpereKelvinCandelaMoleA tv news reporter once stated that a person was electrocuted when 20,000 volts of electricity surged through his body. What is wrong with this description? What was it that surged through his body?.
Answer:
Current doesn't surge or travel like water through the body, instead it is the electrons that move and make current. The signals sent inside our body are also in the form of electric current but meager to what is 20,000v means. In this case, the body couldn't survive and the 'current' formed inside the body met with the resistance of flesh, and as result gave heat burns. But above all the electricity doesn't flow, it's the electrons that move and make current inside the body.
Explanation:
Hope this helps.
explain your observations: what do you think happened to the light from the lightbulb as it passed through the gas cloud before passing through the spectroscopy telescope?
If a gas of hydrogen atoms lies between you (your telescope + spectrograph) and a continuum light source, it will create an absorption line spectra, and if viewed from a different angle, an emission line spectrum.
Absorption lines allude to the propensity of cool atmospheric gas to absorb the same lines of light, whereas emission lines refer to the fact that burning hot gas produces lines of light.
Some of the light at specific wavelengths is scattered when it travels through the atmosphere's gas, producing darker bands. The wavelengths of light released when common materials were heated to form lines that became known as "spectral lines" were recorded.
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Which of the following equipment is not usually involved in the production of electricity?
The equipment that are usually involved in the production of electricity are generators.
The most commonly used electricity generation equipment are Turbines. Different types of turbines are used such as:
Steam turbinesWind turbinesHydroelectric turbineCombustion gas turbinesAn electrical generator is used along with the turbine to convert the mechanical energy produced by the turbine into electricity.
Some of the other equipment used to generate electricity are
Solar photovoltaic cellsInternal combustion enginesFuel cells etc.Therefore, the equipment that are usually involved in the production of electricity are generators.
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Answer:
Non-electric appliances you might already own
Coffee percolator. They make delicious coffee and are convenient for camping trips. ...
French press: This is another coffee maker that is as easy to use as a percolator. ...
Manual mixer. ...
Hand flour mill. ...
Dough maker. ...
Food strainer. ...
Manual food processor. ...
Zeer clay pot fridge.
Explanation:
non-electric equipment are use in the production of a work piece that does not involve the use of electrical equipment
Timmy is playing on a moving walkway like you find in an airport. He wants to have fun and decides to run backward on the moving walkway at 1.6 m/s with respect to the moving walkway he is on. Both Timmy and the moving walkway are going in the opposite directions. The walkway is going at 6.9 m/s. What speed is Timmy going with respect to a person watching this endeavor who is standing on solid ground beside the walkway?
The relative velocity is obtained as 5.3 m/s from the calculation as shown below.
What is motion?We know that motion refers to the change in the position of an object with time. Give that we know that motion is relative and the position of the two objects that are in motion must always be taken into consideration. In this case, we have the situation in which Timmy and his friends are moving backwards and the runway is moving forward thus they are actually moving in opposite directions as seen.
Let us note that velocity is a vector quantity hence we have to assign the forward direction as positive and the backwards direction as negative. Thus we can then take the relative motion between Timmy and his friend and the walk way can be obtained quite conveniently by the use of;
6.9 m/s - 1.6 m/s = 5.3 m/s
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How does a change in the solar constant impact the absorption of shortwave radiation and the emission of longwave radiation by the earth-atmosphere system?.
Solar constant never change, and hence there is no change in shortwave as well as longwave radiation by the earth's atmosphere
Solar constant is the rate at which the solar energy from the sun intercepts the earth's surface. It's value is 1,338watts per square meter.
Long wave radiation is a type of radiation emitted from earth whose wavelength ranges from 4 to 30 micrometers. While shortwave radiation is the radiant energy which is produced by the sun whose wavelength ranges from infrared to ultraviolet through visible.
We know that solar constant never change (constant), and the amount of shortwave that reaches the earth's atmosphere is called solar constant. As the solar constant does not change, there will be no change in shortwave as well as longwave radiation by the earth's atmosphere.
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Share an example from your house or neighborhood that represents a physical change occurring.
An example from my house or neighborhood that represents a physical change occurring is Breaking my mum's favorite drinking glass and melting of ice block to liquid.
What is the physical change?The material involved in a physical change has the same structural properties before as well as after the change. Texture, shape, as well as temperature, and an alteration in the state of matter are examples of a lot of physical changes.
Since Physical changes to matter are those that take place without altering their chemical makeup.
Therefore, Note that by breaking the glass, it is broken down to smaller pieces, which can still be glued together and its revisable.
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A car must be driven a distance of 120 km in 2.5 h. During the first 1.5 h, the average speed was 70 km/h. Calculate the average speed for the remainder of the journey.
The average speed for the remainder of the journey is 15km/h.
How to calculate average speed?Average speed of a moving body can be calculated by dividing the distance moved by the object by the time taken to complete the distance as follows;
Average speed = distance/time
According to this question, a car must be driven a distance of 120 km in 2.5 h, however, during the first 1.5 h, the average speed was 70 km/h.
First, the initial distance moved must be calculated as follows:
Distance = 1.5 hours × 70km/h = 105km
The remaining distance = 120km - 105km = 15km
Average speed for this remaining distance = 15km ÷ 1hr = 15km/h.
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A ball is projected with 40m/s vertically upward. (Ignore air resistance)
Compute A. the total time of flight
B. the maximum height
C. the velocity at t=5s
IN DESPERATE NEED OF HELP!!!
Make us of equation of motion formulas.
a.) the total time of flight = 8.16 s
b.) the maximum height reached = 81.6 m
c.) the velocity at t = 5s = 9 m/s
Motion Under GravityMotion of any object under gravity is the vertical motion of the object under the influence of acceleration due to gravity.
Given that a ball is projected with 40 m/s vertically upward.
A. the total time of flight of the ball will be T = 2t
At maximum height, v = 0.
v = u - gt
0 = 40 - 9.8t
9.8t = 40
t = 40 / 9.8
t = 4.08 s
T = 2 × 4.08
T = 8.16 s
B. the maximum height H can be found by using the formula
v² = u² - 2gH
At maximum height, v = 0
0 = u² - 2 × 9.8 × H
40² = 19.6H
H = 1600/19.6
H = 81.6 m
C. the velocity at t = 5s will be v
v = u - gt
v = 40 - 9.8 × 5
v = 40 - 49
v = - 9 m/s
That is, 9 m/s in the opposite direction ( coming downward )
Therefore, the total time of flight of the ball is 8.16 s, the maximum height reached is 81.6 m and the velocity at t = 5s is 9 m/s
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5. A car moves with an avg velocity of +12.5m/s. If it begins 137m behind the origin, where will it be after 7s?
Displacement = 1/2(Initial Velocity + Final Velocity)Time
If we plug in the values (0 as initial velocity, 12.5 as final velocity, 7 as time), we get 43.75 meters.
According to the given condition we are 137 meters behind the origin. That would mean our initial displacement is -137 meters. After driving for 7 seconds, the car would be 43.75 meters closer to the origin.
-137 + 43.75 = - 93.25 meters (or 93.25 meters behind the origin).
Mary jogs for 15 minutes at 240 m/min, walks the next 10 minutes at 90 m/min, rests for 5
minutes, and jogs back to where she started at -180 m/min. a. Plot a velocity vs. time graph for Mary's exercise run.
b. Find the area under the curve for the first 15 minutes. What does this represent? C. What is the total distance traveled by Mary?
d. What is Mary's displacement from start to finish?
Answer:
B
Explanation:
i hope it hleps
2000 kg car at rest has a net force of 500 N being applied to the left. If the force is applied
for 10 sec, what is the final velocity of the car?
The final velocity of the 2000 kg car with a net force of 500 N being applied to the left for 10 sec is - 2.5 m / s
a = ( v - u ) / t
F = Force
m = Mass
a = Acceleration
v = Final velocity
u = Initial velocity
t = Time
t = 10 s
u = 0
a = ( v - 0 ) / 10
a = v / 10
According to Newton's second law of motion,
F = m a
F = Force
m = Mass
m = 2000 kg
F = - 500 N
- 500 = 2000 * ( v / 10 )
v = - 2.5 m / s ( Negative sign indicate the object is moving towards left )
Therefore, the final velocity of the car is - 2.5 m / s
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after resting for 10 minutes, you decide to perform another explosive, one-time movement such as a standing vertical jump and again, exert maximal effort. you briskly push yourself up from a chair and walk about 1.5 minutes to arrive at a wall where a vertical jump measurement can be made.
In this case, anaerobic metabolism is utilized.
Anaerobic metabolism: What is it?The process of producing ATP anaerobically, also known as without oxygen or in the absence of oxygen, involves the direct phosphate transfer from phosphorylated intermediates like creatine phosphate or glycolytic intermediates to ADP, which in turn produces ATP.
What is the result of anaerobic metabolism?Lactic acid builds up as a result of the anaerobic metabolism of glucose, which causes metabolic acidosis. A base deficit results from the reaction between lactic acid and bicarbonate, which lowers serum bicarbonate levels.
What does aerobic versus anaerobic metabolism mean?Anaerobic metabolism only produces two ATP molecules for every glucose molecule while aerobic metabolism produces more ATP and depends on oxygen.
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Answer explanation pls
The Distance Travels after 5s is 50 m.
What are the equations of motion?First equation of motion: v = u + at.
Second equation of motion: s = ut + 12 at2
Third equation of motion: v2 = u2 + 2as.
A physical system's behavior in terms of how its mobility varies over time is described by equations of motion.
The equations of motion, which are a group of mathematical functions stated in terms of dynamic variables, provide a more thorough description of how a physical system behaves. Space, time, and occasionally components of momentum make up these factors in most cases. The most flexible choice is generalized coordinates, which can represent any meaningful variable present in the physical system. In relativity, curved spaces are employed in place of the Euclidean spaces where the functions are specified in classical mechanics. If the dynamics of a system are known, the equations are the solutions to the differential equations that describe the motion of the dynamics.To learn more about : equations of motion.
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A woman pulls a crate with a force of 66 N at an angle of 39 o with respect to the horizontal. If a frictional force of 3.9 N acts on the crate, what is the total work done on the crate, in joules (J), after it has moved a distance of 5.8 m?
According to the given statement The total work done on the crate in 17.57 J.
What is work done called?When a force is applied to an item, it is deemed to have "done work" if the object travels a distance in the direction of the force. The result of force and displacement are the same. Displacement times Force equals work.
Briefing:Mass of the crate, m = 66kg
Force applied by the worker, F = 3.9 N
Angle to the horizontal, θ = 39°,
Distance moved by crate, d=5.8m
Work = Force * Displacement
Total work done on the crate
W = Fcosθ × d
W = 3.9× cos 39 × 5.8
W = 17.57 J
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a small button placed on a horizontal, rotating platform with diameter 0.320 mm will revolve with the platform when it is brought up to a rotational speed of 40.0 rev/minrev/min, provided the button is no more than 0.140 mm from the axis.
The ratio of friction force to normal force is expressed by the coefficient of friction, a dimensionless number. The platform and button have a friction coefficient of 0.329.
Given that the button's diameter is 0.520 m and its rotational speed is 35.0 rev/min, its distance from the axis is no greater than 0.240 m. This indicates that the button's placement circle's radius R is this.
The calculation for the angular velocity is shown below.
ω=2πf
where f is the revolution's speed.
ω=2*3.14*35/60
ω=3.67 rad/s
The friction coefficient is determined in the manner shown below.
μmg= mω²R
μ=0.329
The friction force between the button and the platform will be equal to the centripetal force acting on the button.
Hence we can conclude that the friction coefficient between the button and the platform is 0.329.
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Starting from rest, a marble first rolls down a steeper hill, then down a less steep hill of the same height. For which is it going faster at the bottom?.
The first and second marble have the same speed at the bottom.
We need to know about the conservation of energy to solve this problem. The energy can not be created or destroyed, the only way is to change to another form. It can be written as
Ei = Ef
where Ei is initial energy and Ef is the final energy
The potential energy of the first marble is the same as the second marble because they have the same height. According to conservation of energy, the potential energy will be converted to kinetic energy and the speed of the marbles will same at the bottom.
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what is the purpose of this experiment?group of answer choicesthe purpose of this experiment is to understand series and parallel circuits, how to calculate their equivalent resistance, and how to construct the laboratory.the purpose of this experiment is to understand circuits.the purpose of this experiment is to comprehend ohm’s law and how to compare their percent difference from their experimental and theoretical values.the purpose of this law is to identify non-ohmic devices and how to convert those devices ohmic.
The purpose of this experiment is to understand series and parallel circuits, how to calculate their equivalent resistance, and how to construct the laboratory.
How do parallel circuits function?There are two or more paths that current to travel through in a parallel circuit. Each element of the parallel circuit has the same voltage applied to that too. The total current flowing from the source is equal to the sum of a currents through each path.
What is a parallel circuit example?When one route is blocked, electricity continues to flow thanks to a parallel circuit. Numerous lighting fixtures are a great example. Even if just one light in the fixture fails, led light stays on.
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Near the end of a bicycle race, Krystal accelerates at 0.36m/s^2 [E] for the final 15.0s. If her initial velocity is 11.0m/s [E], what is her final velocity?
The final velocity of Krystal who accelerated at 0.36m/s² for the final 15.0 s, having an initial velocity of 11.0m/s is 16.4m/s.
What is Krystal final velocity?Velocity is simply the speed at which an object moves in a particular direction.
Acceleration is the rate of change of the velocity of a particle or object with respect to time.
From the first equation of motion;
v = u + at
Where v is final velocity, u is initial velocity, a is acceleration and t is time elapsed.
Given the data in the question;
Acceleration a = 0.36m/s²Elapsed time t = 15.0sInitial velocity u = 11.0m/sFinal velocity v = ?To determine Krystal's final velocity, plug the given values into the equation of motion above and solve for v.
v = u + at
v = 11.0m/s + ( 0.36m/s² × 15.0s )
v = 11.0m/s + ( 0.36ms/s² × 15.0 )
v = 11.0m/s + ( 0.36m/s × 15.0 )
v = 11.0m/s + 5.4m/s
Final velocity v = 16.4m/s
Therefore, Krystal's final velocity for the final 15.0 seconds is 16.4m/s.
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A wide receiver starts at rest at the line of scrimmage and runs vertically towards the end zone for a pass. If the athlete accelerates at a constant rate of 1.7 meters per second^2, approximately how far did the athlete run if the play lasted 5.0 seconds? * 1 point
The distance travelled by the athlete given the play lasted for 5.0 seconds is 21.25 m
How to determine the distanceWe'll begin by listing out the parameters given from the question. This is given below:
Initial velocity (u) = 0 m/sAcceleration (a) = 1.7 m/s²Time (t) = 5 secondsDistance (s) =?From the given parameters, we can determine the distance as follow:
s = ut + ½at²
s = (0 × 5) + (½ × 1.7 × 5²)
s = 0 + 21.25
s = 21.25 m
From the above calculation, we conclude that the athlete ran 21.25 m during the 5 seconds play.
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PLEASE HELP urgently!!!
1.The initial volume of a gas at a pressure of 5 atm is 3.5 L. What will the volume be if the pressure is increased to 6 atm?
Include units.
2. A gas is contained in a 4 L container at a pressure of 2 atm. The container is at a temperature of 15 degrees Celsius. What will the pressure be if the temperature is increased to 30 degrees Celsius?
Include units.
3. Calculate the decrease in temperature when 6.00 L of gas at 20.0 °C is compressed to 4.00 L.
Include units.
4. A 40.0 L tank of ammonia has a pressure of 5.5 atm. Calculate the volume of the ammonia if its pressure is changed to 8.2 atm while its temperature remains constant.
5. Determine the pressure change when a constant volume of gas at 1.5 atm is heated from 18 °C to 32 °C.
Taking into account the Boyle's law, Charles's law and Gay-Lussac's law, you get:
If the pressure is increased to 6 atm, the volume will be 2.92 L.If the temperature is increased to 30 degrees Celsius, the pressure will be 2.104 atm.When 6.00 L of gas at 20.0 °C is compressed to 4.00 L, the temperature will be 195.33 K.If its pressure is changed to 8.2 atm while its temperature remains constant, the volume will be 52.38 L.At 32°C, the pressure will be 1.43 atm.Boyle's lawBoyle's law states that the volume occupied by a given mass of gas at constant temperature is inversely proportional to the pressure: if the pressure increases, the volume decreases, while if the pressure decreases, the volume increases.
Boyle's law is expressed mathematically as
P×V=k
Considering an initial state 1 and a final state 2, it is fulfilled:
P₁×V₁=P₂×V₂
Charles's LawCharles's Law consists of the relationship between the volume and temperature of a certain amount of ideal gas.
This law says that for a given sum of gas at constant pressure, as the temperature increases, the volume of the gas increases, and as the temperature decreases, the volume of the gas decreases: the volume is directly proportional to the temperature of the gas.
Charles's law is expressed mathematically as:
V÷T=k
Considering an initial state 1 and a final state 2, it is fulfilled:
V₁÷T₁=V₂÷T₂
Gay-Lussac's law
Gay-Lussac's law determines that gas pressure is directly proportional to its temperature when the volume is constant: when there is a constant volume, when the temperature increases, the gas pressure increases and when the temperature decreases, the gas pressure decreases.
Gay-Lussac's law is expressed mathematically as:
P÷T=k
Considering an initial state 1 and a final state 2, it is fulfilled:
P₁÷T₁=P₂÷T₂
Exercise 1In this case, you know:
P₁= 5 atmV₁= 3.5 LP₂= 6 atmV₂= ?Replacing in the Boyle's law:
5 atm× 3.5 L= 6 atm×V₂
(5 atm× 3.5 L)÷ 6 atm= V₂
2.92 L= V₂
Finally, the volume will be 2.92 L.
Exercise 2In this case, you know:
T₁= 15°C= 288 KP₁= 2 atmT₂= 30°C= 303 KP₂= ?Replacing in Gay-Lussac's law:
2 atm÷ 288 K=P₂÷ 303 K
(2 atm÷ 288 K)× 303 K=P₂
2.104 atm= P₂
Finally, the pressure will be 2.104 atm.
Exercise 3In this case, you know:
V₁= 6 LT₁= 20 C= 293 KV₂= 4 LT₂= ?Replacing in Charles's law:
6 L÷293 K=4 L÷T₂
(6 L÷293 K)× T₂= 4 L
T₂= 4 L÷ (6 L÷293 K)
T₂= 195.33 K
Finally, the temperature will be 195.33 K.
Exercise 4In this case, you know:
P₁= 5.5 atmV₁= 40 LP₂= 8.2 atmV₂= ?Replacing in the Boyle's law:
5.5 atm× 40 L= 8.2 atm×V₂
(5.5 atm× 40 L)÷ 8.2 atm= V₂
52.38 L= V₂
Finally, the volume will be 52.38 L.
Exercise 5In this case, you know:
T₁= 18°C= 291 KP₁= 1.5 atmT₂= 32°C= 305 KP₂= ?Replacing in Gay-Lussac's law:
1.5 atm÷ 291 K= P₂÷ 305 K
(1.5 atm÷ 291 K)× 305 K=P₂
1.43 atm= P₂
Finally, the pressure will be 1.43 atm.
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Sphere A is located at the origin and has a charge of +2.0 × 10- C. Sphere B is located at +0.60 m on the x-axis and has a charge of -3.6 x 10- C.
Sphere C is located at +0.80 m on the x-axis and has a charge of +4.0 x 10-6 C. Determine the net force on sphere A.
Answer:
F = 0.0675 N
Explanation:
The net force under sphere A is the sum of the force made by sphere B with the force made by sphere C.
By Coulomb's Law of force, we have:
F = k * Q*Q/d²
So:
Force (absolute value) of C on A:
F₁₃ = k * Q₁*Q₃/d²
F₁₃ = 9*10⁹ * (2.0*10⁻⁶)*(4.0*10⁻⁶) / (0.80)²
F₁₃ = 9/80 N = 0.1125 N
The vector:
F₁₃ = 0.1125 N (horizontal direction; pointed to the left side: repulsive)
Force (absolute value) of B on A:
F₁₂ = k * Q₁*Q₂/d²
F₁₂ = 9*10⁹ * (2.0*10⁻⁶)*(3.6*10⁻⁶) / (0.60)²
F₁₂ = 9/50 = 0.18 N
The vector:
F₁₂ = 0.18 N (horizontal direction; pointed to the right side: attractive)
The net force is F₁₂ - F₁₃:
F = 0.180 - 0.1125
F = 0.0675 N
question 14: how long does the eclipse of an earth-like planet take? how much time passes between eclipses? what obstacles would a ground-based mission to detect earth-like planets face?
When the Sun passes through the nodal eclipse zones, the eclipses would last approximately 6 hours, with there being a chance of two solar eclipses every 34.5 days.
How far apart are eclipses?Each year, there are two to five solar eclipses, with a total eclipse occurring roughly every 18 months. You might be able to see that eclipse, depending on where you are in the world. The view of the eclipse and the Moon's shadow on Earth move from west to east as the Earth rotates.
Why are eclipses 6 months apart?This is due to the fact that there are roughly 15 days (or a fortnight) between a full moon and a new moon, and vice versa. There are enough days (30 days) for two more eclipses if one occurs at the start of the season.
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If a car travels 12.0 km south then 5.0 km north in 0.25 h, what is its average velocity? It’s average speed?
The average speed and average velocity of the car is 68 km/h and 28 km/h respectively.
The change in position or displacement divided by the time periods during which the displacement occurs is known as average velocity. Based on the direction of the displacement, the average velocity might either be positive or negative. Average speed is the total distance travelled by an object to the total time taken.
The car travels 12 km then 5.0 km north in 0.25 h. The average speed and average velocity is given below.
Average speed = total distance/time
Average speed = (12+5)/0.25 = 68 km/h
Average velocity = displacement/time
Average velocity = (12-5)/0.25 = 28 km/h
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A shopper walks from the door of the mall towards her car; she walks 165 m south
down one lane of cars, then turns to her left and walks another 55 meters to her
car. What is her displacement?
The displacement of the shopper is 172. 92 m.
What is the process of displacement?"Displacement" describes a change in an object's location. It is a vector quantity since it has a magnitude and a direction. Its emblem is an arrow leading from the starting point to the finishing point. For instance, if an object moves from position A to position B, its position changes.
She travels 165 meters south before turning and traveling a further 55 meters to her left.
If we construct the figure, her displacement will result in the hypotenuse of the triangle.
Therefore according to the question,
Displacement = √ { ( 165)² +(55 )² } m
= √(27225 + 3025) m
=√ 30250 m
= 172. 92 m
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A 900 kg racing car is travelling at a uniform speed of 30m/s around a circular racetrack with a diameter of 360 m. what is the centripetal force acting on the car?
The centripetal force acting on the car is 4500 N
The force that acts on the body to make it follow a circle is known as centripetal Force.
Mass m = 900 kg
speed v = 30 m/s
radius r = diameter/2 = m
To calculate Centripetal force:
[tex]F_{c}[/tex] = mv^2/r
[tex]F_{c}[/tex] = 900×30^2/180
[tex]F_{c}[/tex] = 4500 N
The centripetal force of the car is 4500 N.
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URGENT LAB QUESTIONS
Graded Assignment
Lab Report: Creating and Interpreting Graphs
Answer each question, using complete sentences. When you have finished, submit this assignment to your teacher by the due date for full credit.
Total score: ____ of 25 points
(Score for Question 1: ___ of 6 points)
1. Which variable did you choose for the independent variable? Which variable did you choose for the dependent variable? Explain.
Answer:
(Score for Question 2: ___ of 12 points)
2. How did the masses affect the spring? Which mass stretched the spring the farthest? The least? Explain your answer using your data. Include your data sheet and the graph of your data in your answer.
Answer:
Type your answer here.
(Score for Question 3: ___ of 7 points)
3. Describe your graph, was it linear or nonlinear? What conclusions can you draw based on the shape of the graph?
Answer:
Type your answer here.
Answer:
give the main question as I can not see the information
What is a force that one object can apply to another object without touching it?
in a simple electric circuit, ohm's law states that , where v is the voltage in volts, i is the current in amperes, and r is the resistance in ohms. assume that, as the battery wears out, the voltage decreases at 0.03 volts per second and, as the resistor heats up, the resistance is increasing at 0.01 ohms per second. when the resistance is 100 ohms and the current is 0.02 amperes, at what rate is the current changing? amperes per second
The value of decreasing current is 0.202m/s.
What is Ohm's law and it 's limitations?The relationship between current, voltage, and resistance is known as Ohm's law. German scientist proposed this connection. Ohm's law is referred to as such because of this. According to this, the voltage or potential difference across many different materials will directly affect how much constant current flows through them. As a result, if the voltage V (measured in volts) between two ends of a wire made of one of these materials is tripled, the current I (measured in amperes) also triples, yet the ratio V/I stays the same. A substance's resistance, measured in ohms, is the product of the ratio V/I for that particular piece of material.
We have given here ,
dV/dt= -0.04, dR/dt= 0.04 , R= 200
I= 0.01
From Ohm's law,
V= IR
dV/dt = IdR/dt + RdI/dt differentiating with respect to t ,
by applying values and solving it we get ,
dI/dt =-0.000202
Hence current is decreasing at 0.202 mA/s.
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What is the weight of a 179 kg football player?
The weight of a 179 kg of football player is 1755.99N.
How to calculate weight?Weight is the force on an object due to the gravitational attraction between it and the Earth.
Weight is a function of an object's mass and acceleration due to gravity, hence, can be calculated by multiplying the mass of the object by its acceleration.
According to this question, the mass of a football player is 179 kg is given. The acceleration due to gravity on Earth is 9.81m/s². The weight can be calculated as follows:
Weight = 179kg × 9.81m/s²
Weight = 1755.99N
Therefore, 1755.99N is the weight of the player.
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What kind of energy transfer occurs when an earthquake produces a large ocean wave called a tsunami
Answer: Mechanical waves transfer energy from rock to water.
Explanation: The particles of the medium just vibrate in place. As they vibrate, they pass the energy of the disturbance to the particles next to them, which pass the energy to the particles next to them, and so on. Particles of the medium don't actually travel along with the wave.
Answer:
Mechanical Waves
Explanation:
Mechanical waves are waves that require a medium for the transfer of their energy to occur. Water waves are an example of mechanical waves. Tsunami waves released after an earthquake transfer the energy of the quake to distant shorelines.
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