Answer:A. The gas particles have essentially zero volume and no attraction
for one another.
Explanation:
1AgNO3+1NaBr->1AgBr+1NaNo3
If 15.0g silver nitrite is reacted with excess sodium bromide, how many moles of silver bromide will form?
0.0882 moles of silver bromide (AgBr) will form.
calculating the number of moles of silver nitrate (AgNO₃) used in the reaction:
moles of AgNO₃ = mass / molar mass
The molar mass of AgNO₃ is:
AgNO₃: 107.87 + 14.01 + 3(16.00) = 169.87 g/mol
So, the number of moles of AgNO₃ used is:
moles of AgNO₃ = 15.0 g / 169.87 g/mol = 0.0882 mol
Since the reaction occurs in a 1:1 ratio of AgNO₃ to AgBr, the number of moles of AgBr produced will also be 0.0882 mol.
Therefore, 0.0882 moles of silver bromide (AgBr) will form.
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Which element on the transition metal has the highest tendency to gain.
Elements on the transition metal has the highest tendency to gain are chromium and manganese.
Transition metals typically have the ability to lose electrons to form positive ions, rather than to gain electrons to form negative ions. However, some transition metals can gain electrons under certain conditions.
The tendency to gain electrons (electron affinity) generally increases across a period from left to right on the periodic table, and decreases down a group from top to bottom.
Among the transition metals, the element with the highest electron affinity is usually considered to be either chromium [Cr] or manganese [Mn]. Both of these elements have a relatively high electron affinity due to their electronic configurations and the proximity of their valence electrons to the nucleus.
However, it is important to note that electron affinity values can vary depending on the specific experimental conditions used to measure them.
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The elements on the transition metal that have the highest tendency to gain are chromium and manganese.
Usually, transition metals form positive ions by losing electrons rather than gaining electrons to form negative ions. However, under certain conditions, some transition metals can gain electrons. The tendency to gain electrons is known as electron affinity.
This tendency generally increases as we go across a period from left to right in our periodic table and decreases while going down the group from top to bottom.
The element with the highest electron affinity, among the transition metals, is usually considered to be either manganese [Mn] or chromium [Cr]. Both of them have a relatively high electron affinity because of their electronic configurations and the proximity of their valence electrons to the nucleus.
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What is the mass percentage of C in codeine, CisHziNO,? Provide an answer to two decimal places.
72.21%
16.03%
100%
41 9%
27.73%
Answer: the mass percentage of C in codeine is 72.21%.
Explanation: Molar mass of C = 12.011 g/mol
Molar mass of CisHziNO = 299.368 g/mol (whole of molar masses of all molecules within the compound)
Number of C molecules in codeine = 18
Mass of C in codeine = 12.011 g/mol x 18 = 216.198 g/mol
Mass rate of C in codeine = (216.198 g/mol ÷ 299.368 g/mol) x 100% = 72.21%
Predict which of the following reactions has a positive change in entropy.
l. 2N2(g) + O2(g) → 2N2O(g)
II. CaCO3(s) → CaO(s) + CO2(g)
III. Zn(s) + 2HCl(aq) → ZnCl2(aq) + H2(g)
Several factors can dictate entropy in an equation.
These include:
1. Phase changes
⇒ When a solid turns to a liquid, the entropy increases as the particles have more freedom to move around and thus have a greater ability for 'disorder'. Same goes for a liquid turning to a gas. In a gas, the intermolecular forces are much weaker than that of a solid or liquid, allowing the particles more freedom.
So, going from a solid to liquid to gas increases entropy, and going the other way, from gas to liquid to solid, decreases entropy.
Example:
H₂O(l) -> H₂O(g)
This will have a positive entropy change, as the water molecules are becoming gaseous and thus have more freedom.
2. Dissolution
⇒ Similarly, breaking up particles of a solute when dissolving in a solvent will increase entropy as the particles are no longer bound together.
So, dissolving a solute will increase entropy.
Example:
NaCl(s) -> NaCl(aq)
This will have a positive entropy change, as the NaCl particles are more free after being separated.
3. Number of products and reactants
⇒ Generally, if you have more moles of products than reactants, if they are the same phase then entropy will increase. Note this is not necessarily true if you form a gas from two non-gas reactants, as the gas will still have more entropy.
4. Temperature
⇒ Increasing temperature will increase entropy as the particles have more kinetic energy and are then moving faster.
-------------------------------------------
l. 2N2(g) + O2(g) → 2N2O(g)
3 moles of gas are forming 2 moles of gas. The phase of products and reactants are the same, so since we have less moles of product than reactant, entropy will be negative.
II. CaCO3(s) → CaO(s) + CO2(g)
1 mole of solid is forming 1 mole of solid and 1 mole of gas. There is a phase change from solid to gas, and there are more moles of product than reactant, entropy will be positive.
III. Zn(s) + 2HCl(aq) → ZnCl2(aq) + H2(g)
While 3 moles of reactant are forming only 2 moles product, we are forming a gas from non-gaseous reactants, so entropy will be positive regardless.
Write word equations for the following skeleton equations. 1. AI (s) + O2(g) AI2O3 (s)
Nitric acid is commercially available at a concentration of 15.9 M. What volume of this solution must be diluted to a final volume of 1.00 L to prepare a 4.00 M solution?
For a particular redox reaction, NO−2 is oxidized to NO−3 and Fe3+ is reduced to Fe2+. Complete and balance the equation for this reaction in basic solution. Phases are optional.
The balanced equation for the given redox reaction in basic solution is:
NO2^- + Fe3+ + H2O → NO3^- + Fe2+ + OH^-
What is the redox reaction?Here, NO2^- is oxidized to NO3^-, which means it loses electrons and undergoes an oxidation reaction. Fe3+ is reduced to Fe2+, which means it gains electrons and undergoes a reduction reaction.
To balance the equation in basic solution, we first balance the atoms that are not hydrogen or oxygen. We start with the Fe3+ ion, which is reduced to Fe2+. To balance the iron atoms, we add one electron to the left side of the equation:
Fe3+ + e^- → Fe2+
Next, we balance the nitrogen and oxygen atoms in NO2^- and NO3^- by adding H2O and OH^- to the appropriate sides of the equation:
NO2^- + H2O → NO3^- + OH^-
Finally, we balance the electrons by multiplying the Fe3+ reduction half-reaction by 2, and adding it to the oxidation half-reaction for NO2^-:
2Fe3+ + 2e^- → 2Fe2+
NO2^- + 2Fe3+ + 2H2O → NO3^- + 2Fe2+ + 2OH^-
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PLEASE HELP!!!!!!!!!!!!!!!!!! Oxygen is in the 16th period, and should therefore have a 2- charge. peroxide also has a charge of 2-. Are they supposed to have the same charge? If so in nomenclature, how do I choose which one to use?
Oxygen has oxidation state of -2 in most compounds, but it can have different oxidation states in some compounds. In peroxide (O₂²⁻), oxygen has an oxidation state of -1
What is meant by nomenclature?Nomenclature is the system of naming chemical compounds according to a set of rules.
In peroxide (O₂²⁻), oxygen has an oxidation state of -1. This is because the two oxygen atoms share the two electrons that make up the covalent bond equally, resulting in an oxidation state of -1 for each oxygen atom.
So, while oxygen in peroxide has a charge of 2-, it does not have a 2- charge in general.
As for nomenclature, when naming compounds containing oxygen, the oxidation state of the oxygen atom is usually indicated by using a suffix. For example, the suffix "-ite" indicates a lower oxidation state, while the suffix "-ate" indicates a higher oxidation state.
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5. Given the following standard enthalpies of formation for the following substances,
H,O (1) = -285.8 kJ/mol
H2O (g) = -241.8 kJ/mol
KOH (aq)=-482.4 kJ/mol
KOH(s) =-425.8 kJ/mol
Determine the enthalpy of the reaction,
2 K(s) + 2 H20(1) - > 2 KOH (aq) + H2(g)
a.
b
-197 kJ/mol
d.
-280 kJ/mol
e.
-1538 kJ/mol
-368 kJ/mol
C
-393 kJ/mol
Given the following standard enthalpies of formation for the following substances, H2O (g) = -241.8 kJ/mol KOH (aq)=-482.4 kJ/mol KOH(s) =-425.8 kJ/mol The enthalpy of the reaction is -390.2 kJ/mol.
What is enthalpies of formation ?The standard enthalpy of formation, also known as the standard heat of formation, is the change in enthalpy that occurs during the synthesis of one mole of a substance from its component parts in their reference states, with all substances in their standard states. The IUPAC recommends using the standard pressure value of p = 105 Pa (= 100 kPa = 1 bar), while previous to 1982, the value of 1.00 atm (101.325 kPa) was used.A standard temperature doesn't exist. Its designation is fH. This symbol's superscript Plimsoll denotes that the process has been carried out under typical circumstances at the given temperature (typically 25 °C or 298.15 K).
The enthalpy of the reaction can be calculated using Hess's Law and the standard enthalpies of formation for the reactants and products. First, we need to determine the enthalpy of the reaction, ∆Hrxn. This is the sum of the standard enthalpies of formation for the products minus the sum of the standard enthalpies of formation for the reactants.
∆Hrxn = [2(-482.4) kJ/mol + (-241.8) kJ/mol] - [2(-425.8) kJ/mol + (-285.8) kJ/mol]
∆Hrxn = -390.2 kJ/mol
Therefore, the enthalpy of the reaction is -390.2 kJ/mol.
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The space probe Pioneer 11 was launched on April 5, 1973, and reached Jupiter in December 1974, traveling a distance of 998 million km. How long did it take an electromagnetic signal to travel to Earth from Pioneer 11 when it was near Jupiter?
It took Approximately 52 minutes and 40 seconds for an electromagnetic signal to travel to Earth from Pioneer 11 when it was near Jupiter.
The speed of light, which is the speed at which an electromagnetic signal travels in a vacuum, is approximately 299,792,458 meters per second.
To find out how long it takes for an electromagnetic signal to travel from Pioneer 11 to Earth when it was near Jupiter, we can use the formula:
time = distance / speedThe distance between Pioneer 11 and Earth when it was near Jupiter is approximately 998 million km, or 998,000,000 km.
Converting this distance to meters, we get:
998,000,000 km = 998,000,000,000 metersDividing the distance by the speed of light, we get:
time = 998,000,000,000 / 299,792,458time = 3,330.7249 secondsConverting this time to minutes and seconds, we get:
time = 55 minutes and 30.7249 secondsRounding to the nearest minute and second, we get:
time ≈ 52 minutes and 40 secondsTherefore, it took approximately 52 minutes and 40 seconds for an electromagnetic signal to travel from Pioneer 11 to Earth when it was near Jupiter.
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i need help pleaseee!!!
The number of atoms of each element is now the same on both sides, so the equation is balanced.
On both sides of the equation, are there the same number of atoms for each element?Nothing can be created or destroyed, according to the conservation of matter principle. The quantity of each element's atom in the reactants and the quantity of that same element in the products must match in chemical equations.
When are two atoms equal?As soon as atoms distribute their electrons uniformly, a nonpolar covalent bond is formed. Normally, this happens when two atoms have comparable or identical electron affinities. The greater the attraction, the closer the values of their electron affinities are. This happens in gas molecules, also referred to as diatomic substances.
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Determine the mass in grams of 7.55 × 1021 molecules of water H2O.
a.
7.14 × 10-4 g
d.
22.6 g
b.
2.59 x 102 g
e.
2.59 g
C.
0.226 g
Answer: the mass of 7.55 x 10^21 molecules of water is 0.226 g, which corresponds to option (c).
Explanation: The atomic weight of water (H2O) is:
2(1.008 g/mol) + 15.999 g/mol = 18.015 g/mol
Avogadro's number (NA) is:
6.022 x 10^23 molecules/mol
To calculate the mass of 7.55 x 10^21 particles of water, able to utilize the taking after equation:
mass = (number of atoms / Avogadro's number) x atomic weight
mass = (7.55 x 10^21 / 6.022 x 10^23) x 18.015 g/mol
mass = 0.226 g
If you have 155 mL solution of a 0.762 mL solution of a 0.762 M FeCl3 solution, how many grams of FeCl3 are contained in this sample?
A sodium ion Na+ with a charge of 1.6x10^-19 and a chloride ion Cl- with a charge of -1.6x10^-19 are separated by a distance of 4.95 Nm . How much work would be required to increase the separation of the two ions to an infinite distance?
Answer: , the work required to separate the two ions to an infinite distance is 4.63 x 10^-19 J.
Explanation: One can determine the potential energy of two point charges by utilizing the specified equation:
The value of U is directly proportional to the product of q1 and q2, and inversely proportional to the distance between them (r), where k is a constant factor.
The potential energy denoted by U is determined by the Coulomb constant, k, which has a value of 9 x 10^9 Nm^2/C^2. The calculation of U involves the charges of two particles, q1 and q2, as well as the distance between them, denoted by r.
We have an instance where a sodium ion (Na+) has a charge of 1.6x10^-19 C, and a chloride ion (Cl-) has a charge of -1.6x10^-19 C, positioned 4.95 Nm apart from each other.
Once we insert the given numbers, the result obtained is:
The expression for U can be obtained by utilizing the equation U = (kQq)/r, with k being the Coulomb's constant equal to 9 x 10^9 Nm^2/C^2, Q and q representing the electric charges of -1.6x10^-19 C and -1.6x10^-19 C, respectively, and r being the distance between the charges of 4.95 Nm.
The value of U is negative 4.63 times 10 to the power of negative 19 Joules.
It is important to observe that the negative symbol signifies the negativity of the potential energy, implying that effort must be exerted in order to disassociate the two ions.
2 KCIO; (s) —> 2 KCI(s) + 3 0,(g)
How many moles of O, form if 3.0 mol of KCIO, are totally consumed?
Therefore, if 3.0 moles of Potassium chlorate are completely destroyed, 4.5 moles of oxygen will form.
How many water molecules make up 3.0 moles of water?Therefore, there will be 36=18 moles of water molecules in 3 moles of the material. Keep in mind that there are 6.02 x 1023 molecules in a mole of molecules. Thus, there will be 6.021023181.081025 water molecules in total here.
If 2 moles of Potassium chlorate decompose to form 3 moles of oxygen, then 1 mole of Potassium chlorate will decompose to form 3/2 moles of oxygen.
Therefore, to find out how many moles of oxygen will form from 3.0 moles of Potassium chlorate, we can use the following calculation:
moles of oxygen = moles of Potassium chlorate x (3/2)
[tex]moles of oxygen = 3.0 mol x (3/2)[/tex]
moles of oxygen = 4.5 mol.
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Convert 3.20 bar to atm
Consider the data table as well as the experimental design. Which of the four cans should have the greatest change in temperature after five minutes?
Answer: air
Explanation:would be the most likely candidate for the cans
When lead (II) nitrate reacts with sodium iodide, sodium
nitrate and lead (II) iodide are formed. If you start with 25.0
grams of lead (II) nitrate and 15.0 grams of sodium iodide, how
many grams of sodium nitrate can be formed?
Answer:
20.44 grams of sodium nitrate can be formed
Explanation:
The balanced chemical equation for the reaction between lead (II) nitrate and sodium iodide is:
Pb(NO3)2 + 2NaI → 2NaNO3 + PbI2
If 64.0% of a Ga67 sample remains in the patient 2.33 days after injection, what is the half‑life of Ga67?
The half‑life of Ga67 is 3.67 days.
The half-life of a chemical reaction can be defined as the time taken for the concentration of a given reactant to reach 50% of its initial concentration (i.e. the time taken for the reactant concentration to reach half of its initial value). It is usually expressed in seconds.
Half-lives are characteristic properties of the various unstable atomic nuclei and the particular way in which they decay.
Given,
Let the initial amount be 100, so final amount will be 100 - 64 = 36
time = 2.33 days
= 2.33 × 24 × 60 × 60
= 201312 seconds
k = ( 1÷ t) log ( initial ÷ final)
k = 0.189 s⁻¹
half life = 0.693 ÷ k
= 315286.62 seconds
= 3.67 days
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A-scientist has a 2.5 g-sample of radium-226: How many grams of the sample will decay.in-800
-years if the half-life is 1600-years?
The mass (in grams) of the sample that will decay in 800 years, given that the half-life is 1600-years is 0.78 g
How do i determine the amount that will decay in 800 years?We shall begin our calculation by obtaining the number of half lives that has elapsed after 800 years. Details below:
Half-life (t½) = 1600 yearsTime (t) = 800 yearsNumber of half-lives (n) =?n = t / t½
n = 800 / 1600
n = 0.5
Next, we shall determine the amount remaining after 800 years. Details below:
Original percentage (N₀) = 2.5 gNumber of half-lives (n) = 0.5Amount remaining (N) = ?N = N₀ / 2ⁿ
N = 2.5 / 2^0.5
N = 1.77 g
Finally, we shall obtain the mass of the sample that has decayed in 800 years. Details below:
Original amount (N₀) = 2.5 gAmount remaining (N) = 1.77 gMass that decay =?Mass that decay = N₀ - N
Mass that decay = 2.5 - 1.77
Mass that decay = 0.78 g
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I WILL GIVE 35 POINTS TO THOSE WHO ANSWER THIS QUESTION RIGHT NOOOO SCAMS PLEASE
Use the periodic table to classify each of the elements below:
Calcium:
Vanadium:
Xenon:
Idoine:
Potassium:
Strontium:
Classify them out of the categories: alkali metal, alkaline earth metal, transitional metal, inner transition metal, halogen, noble gas.
Answer: Calcium: Alkaline earth metal
Vanadium: Transitional metal
Xenon: Noble gas
Iodine: Halogen
Potassium: Alkali metal
Strontium: Alkaline earth metal
Explanation:
Do you think there would be any difference in conductivity between a solution, a solution 10x more concentrated, and a solution 10x less concentrated?
Diluting a solution increases the amount of ions in the solution and gives them more room to move about, which increases the mobility of the ions and raises the molar conductivity in the solution at the same time.
What is a remedy?A solute dissolving agent, used to create homogenous mixtures. To create a homogenous mixture, a solute must dissolve in a solvent.Although solutions of both solids and gases are possible, the term "solution" is most frequently used to refer to the liquid condition of matter.
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Calculate the mass of the white solid calcium carbonate that forms with 25.0L of a 0.100 M calcium nitrate solution mixed with 20.0 mL of a 0.15M sodium carbonate solution.
Answer:
The mass of the white solid calcium carbonate that forms is 0.300 g.
Explanation:
To calculate the mass of the white solid calcium carbonate that forms, we first need to determine the limiting reagent in the reaction between calcium nitrate and sodium carbonate. The balanced chemical equation for the reaction is:
Ca(NO3)2(aq) + Na2CO3(aq) → CaCO3(s) + 2NaNO3(aq)
From the equation, we can see that one mole of calcium nitrate reacts with one mole of sodium carbonate to produce one mole of calcium carbonate. Therefore, the limiting reagent is the one that produces the least amount of calcium carbonate.
To determine the limiting reagent, we need to calculate the moles of calcium nitrate and sodium carbonate used in the reaction:
Moles of calcium nitrate = volume of solution (L) x concentration (mol/L) = 25.0 L x 0.100 mol/L = 2.50 mol
Moles of sodium carbonate = volume of solution (L) x concentration (mol/L) = 0.0200 L x 0.150 mol/L = 0.00300 mol
Since the moles of sodium carbonate are much smaller than the moles of calcium nitrate, sodium carbonate is the limiting reagent.
The balanced chemical equation tells us that one mole of calcium carbonate is produced for every mole of sodium carbonate used. Therefore, the moles of calcium carbonate produced are also equal to 0.00300 mol.
Finally, we can calculate the mass of calcium carbonate produced using the molar mass of calcium carbonate:
Mass = moles x molar mass = 0.00300 mol x 100.1 g/mol = 0.300 g
Therefore, the mass of the white solid calcium carbonate that forms is 0.300 g.
What is a product?
A. A substance that is used during a chemical reaction
B. A substance that doesn't change during a chemical reaction
OC. A substance that turns into waste during a chemical reaction
OD. A substance that is produced during a chemical reaction
Answer:
D. something's that's produced during a chemical reaction
Answer:
Explanation:
The answer is Option D.
A substance that is produced during a chemical reaction.
for example in a chemical reaction A+B -----> C
here, reactants A and B react together to produce product C.
Calculate the number of molecules of Freon-12 in 4.75 mg of Freon-12. What is the mass of chlorine in 4.75 mg of Freon-12?
The mass of chlorine in 4.75 mg of Freon-12 is approximately 1.39 x [tex]10^{-3}[/tex]g.
What is Mass?
Mass is a fundamental property of matter that measures the amount of substance or material present in an object. It is a scalar quantity and is typically measured in units such as grams (g) or kilograms (kg) in the metric system, or pounds (lb) or ounces (oz) in the imperial system.
Freon-12, also known as dichlorodifluoromethane, is a chlorofluorocarbon (CFC) compound that was used as a refrigerant and propellant in aerosol products. Its chemical formula is CCl2F2.
The atomic masses of carbon (C), chlorine (Cl), and fluorine (F) are approximately 12.01 g/mol, 35.45 g/mol, and 18.998 g/mol, respectively.
The molar mass of Freon-12 (CCl2F2) is:
Molar mass of Freon-12 = 12.01 g/mol (C) + 2 x 35.45 g/mol (Cl) + 2 x 18.998 g/mol (F)
= 120.91 g/mol
Next, we use the formula:
moles = mass / molar mass
to calculate the number of moles of Freon-12 in 4.75 mg:
moles of Freon-12 = 4.75 mg / 120.91 g/mol
= 3.92 x 10^-5 mol
Finally, we use Avogadro's number to calculate the number of molecules of Freon-12:
Number of molecules = moles of Freon-12 x Avogadro's number
= 3.92 x[tex]10^{-5}[/tex] mol x 6.022 x[tex]10^{23[/tex] molecules/mol
= 2.35 x [tex]10^{19}[/tex] molecules
To calculate the mass of chlorine in 4.75 mg of Freon-12, we can use the molar mass of chlorine (Cl) and the moles of Freon-12 calculated above.
The molar mass of chlorine (Cl) is 35.45 g/mol.
Mass of chlorine in Freon-12 = moles of Freon-12 x molar mass of chlorine
= 3.92 x [tex]10^{-5}[/tex] mol x 35.45 g/mol
= 1.39 x [tex]10^{-3}[/tex] g
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1Li3 + 3H2O -> 1NH3 + 3LiOH
Determine the mass of lithium hydroxide produced when 0.38g of lithium nitride reacts with an excess of water.
0.785 g of lithium hydroxide (LiOH) are produced when 0.38 g of lithium nitride (Li₃N) reacts with an excess of water.
we can see that 3 moles of lithium hydroxide (LiOH) are produced for every 1 mole of lithium nitride (Li₃N) that reacts.
To determine the mass of LiOH produced from 0.38 g of Li₃N, we need to first calculate the number of moles of Li₃N present:
molar mass of Li₃N = 3 x atomic mass of Li + 1 x atomic mass of N
= 3 x 6.94 g/mol + 1 x 14.01 g/mol
= 34.83 g/mol
moles of Li₃N = mass / molar mass
= 0.38 g / 34.83 g/mol
= 0.01093 mol
Since the balanced equation shows that 1 mole of Li₃N produces 3 moles of LiOH, we can calculate the number of moles of LiOH produced:
moles of LiOH = 3 x moles of Li₃N
= 3 x 0.01093 mol
= 0.03279 mol
Finally, we can use the molar mass of LiOH to convert from moles to grams:
molar mass of LiOH = atomic mass of Li + 1 x atomic mass of O + 1 x atomic mass of H
= 6.94 g/mol + 15.99 g/mol + 1.01 g/mol
= 23.94 g/mol
mass of LiOH produced = moles of LiOH x molar mass of LiOH
= 0.03279 mol x 23.94 g/mol
= 0.785 g
Therefore, approximately 0.785 g of lithium hydroxide (LiOH) are produced when 0.38 g of lithium nitride (Li₃N) reacts with an excess of water.
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How to solve question 2A and 2B
2A. The mole of HCl used is 3.2 moles
2B. The moles of each product produced as:
3.2 moles of NaCl3.2 moles of CO₂3.2 moles of H₂OA. How do i determine the mole of HCl used?The mole of HCl used can be obtained as follow:
NaHCO₃ + HCl -> NaCl + CO₂ + H₂O
From the balanced equation above,
1 mole of NaHCO₃ reacted with 1 mole of HCl
Therefore,
3.2 moles of NaHCO₃ will also react to 3.2 moles of HCl
Thus, the number of mole of HCl used is 3.2 moles
2B. How do i determine the mole of each product?The mole of each product produced can be obtain as shown:
For NaCl
NaHCO₃ + HCl -> NaCl + CO₂ + H₂O
From the balanced equation above,
1 mole of NaHCO₃ reacted to produce 1 mole of NaCl
Therefore,
3.2 moles of NaHCO₃ will also react to produce 3.2 moles of NaCl
Thus, the mole of NaCl produced is 3.2 moles
For CO₂
NaHCO₃ + HCl -> NaCl + CO₂ + H₂O
From the balanced equation above,
1 mole of NaHCO₃ reacted to produce 1 mole of CO₂
Therefore,
3.2 moles of NaHCO₃ will also react to produce 3.2 moles of CO₂
Thus, the mole of CO₂ produced is 3.2 moles
For H₂O
NaHCO₃ + HCl -> NaCl + CO₂ + H₂O
From the balanced equation above,
1 mole of NaHCO₃ reacted to produce 1 mole of H₂O
Therefore,
3.2 moles of NaHCO₃ will also react to produce 3.2 moles of H₂O
Thus, the mole of H₂O produced is 3.2 moles
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CHEMISTRY IN INDUSTRY, HEALTH, FOOD, LIFE, and the ENVIRONMENT
This assignment gives us an opportunity for us to engage and continue to dialogue with one another. We will explore the role of chemistry in our everyday life, as it pertains to industry, health, and the environment. Chemistry can help us to understand, monitor, protect, and improve the environment around us. Chemists use analytical tools and techniques to assess and measure air and water pollution due to environmental chemicals. This has helped to build the evidence that shows how our climate has changed over time. In drug and food development chemistry has a major cornerstone to foster the treatment of illnesses and wellness and to foster the availability of food.
Have a look at the following two Figures attached and use the periodic table of elements and natures in addition to your own research and reflect on how you see the chemistry and its application. Your task, select an aspect that is of interest to you and write a short reflection on how you currently perceive chemistry,
Food, clothing, shelter, health, energy, and clean air, water, and soil are all dependent on chemistry. Chemical technologies improve our quality of life in a variety of ways by solving problems in health, materials, and energy utilization.
Chemistry in everyday lifeChemistry is important in the development of technological solutions. Chemists contribute to lower transportation emissions in a variety of ways, from generating cleaner fuels (such as low sulfur fuels) to enhancing engine efficiency.Environmental chemistry examples include: Counting the amount of pollutants in a sample of water or soil. Using chemistry knowledge to offer alternative ecologically acceptable compounds for usage in products. Creating chemicals with functionalities that replace poisons.For more information on chemistry in everyday life kindly visit to
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Consider this unbalanced equation: Pb + HCI -> PbCl2 + H₂
a. If we allow 30g of Hydrogen gas to form (H2), how many moles of HCI were
needed?
b. What if we allowed 9.2 moles of PbCl₂ to form. How many grams of HCI were
needed?
a) Moles of HCI that were needed is 14.88 mol ; b) Grams of HCI that were needed is 670.14 g.
What is meant by balanced equation?Equation where number of atoms of each element in the reactant is equal to the number of atoms of the same element in the products is called as the balanced equation.
a.) 30 g / 2.016 g/mol = 14.88 mol of H₂
From the balanced equation, we can see that one mole of H₂ is produced for every mole of HCl consumed. Therefore, the number of moles of HCl needed is also 14.88 mol.
b.) 2 moles of HCl are consumed for every mole of PbCl₂ produced
So, the number of moles of HCl needed to produce 9.2 moles of PbCl₂ is:
9.2 mol PbCl₂ × 2 mol HCl/mol PbCl₂ = 18.4 mol HCl
18.4 mol × 36.46 g/mol = 670.14 g of HCl
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