Which statement best describes the role of oxygen in cellular respiration?
OA. Oxygen molecules are a waste product of electron flow.
B. Oxygen molecules form as ATP molecules are made.
OC. Oxygen molecules form as sugar molecules are broken down.
OD. Oxygen molecules are used to make water molecules.

Answer:

1,063 grams H₃PO₄

Explanation:

To find the mass of phosphoric acid (H₃PO₄), you should (1) convert molecules to moles (via Avogadro's number) and then (2) convert moles to grams (via molar mass from periodic table).

Molar Mass (H₃PO₄): 3(1.008 g/mol) + 30.974 g/mol + 4(15.998 g/mol)

Molar Mas (H₃PO₄): 97.99 g/mol

6.534 x 10²⁴ molecules H₃PO₄                       1 mole                         97.99 g
---------------------------------------------  x  -------------------------------------  x  --------------
                                                            6.022 x 10²³ molecules          1 mole

= 1,063 grams H₃PO₄

The central oxygen atom is a state of sp3 hybridization having only one available lone pair.

The term hybridization refers to the mixing of two or more atomic orbitals to yield hybrid orbitals that are suitable for bonding.

Looking at the ion H3O^+, we can see that the central oxygen atom is a state of sp3 hybridization having only one available lone pair. The image of the ion is shown here.

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The weather station is a place which contain instrument that collect data of atmospheric pressure, wind, humidity, etc to forecast weather. The weather station is powered by solar power.

A weather station is a place that measure atmospheric conditions, on the basis of temp., pressure, wind speed, etc conditions.

They can be based either in land or sea. They are necessary to forecast any disaster, so we can prepare for the disaster.

Thus, the weather station is a place which contain instrument that collect data of atmospheric pressure, wind, humidity, etc to forecast weather. The weather station is powered by solar power.

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Answer:

When sodium metal is dropped in water, hydrogen gas is evolved. Thus, the reaction is, 2Na+2H2O→H2+2NaOH. In the reaction, sodium hydroxide is formed and hydrogen gas is evolved.

Explanation:

The equilibrium solubility of cadmium carbonate in a solution at constant pH of 11 is 1.65 x 10⁻⁵ mol/dm³.

The equilibrium solubility of cadmium carbonate in a solution at constant pH of 11 is calculated as follows;

H₂CO3 ⇄ 2H⁺  + CO₃²⁻

x         :      2x        x

ksp = (2x)²x

ksp = 4x³

(1.8 x 10⁻¹⁴) = 4x³

(1.8 x 10⁻¹⁴) /4 = x³

4.5 x 10⁻¹⁵ = x³

x = (4.5 x 10⁻¹⁵)^¹/₃

x = 1.65 x 10⁻⁵ mol/dm³

Thus, the equilibrium solubility of cadmium carbonate in a solution at constant pH of 11 is 1.65 x 10⁻⁵ mol/dm³.

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The equilibrium solubility of cadmium carbonate in a solution at constant pH of 11 is 1.65 x 10⁻⁵ mol/dm³.

Solubility is defined as the maximum amount of a substance that will dissolve in a given amount of solvent at a specified temperature.

The equilibrium solubility of cadmium carbonate in a solution at constant pH of 11 is calculated as follows;

H₂CO3 ⇄ 2H⁺  + CO₃²⁻

x         :      2x        x

ksp = (2x)²x

ksp = 4x³

(1.8 x 10⁻¹⁴) = 4x³

(1.8 x 10⁻¹⁴) /4 = x³

4.5 x 10⁻¹⁵ = x³

x = [tex](4.5 X 10^{-15})^{\frac{1}{3} }[/tex]

x = 1.65 x 10⁻⁵ mol/dm³

Thus, the equilibrium solubility of cadmium carbonate in a solution at constant pH of 11 is 1.65 x 10⁻⁵ mol/dm³.

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5.00 grams of solid citric acid (solute) is dissolved in 500.00 ml of water (solvent) to make aqueous citric acid (solution).

A solution is a homogeneous mixture prepared by dissolving a solute in a solvent.

5.00 grams of solid citric acid is dissolved in 500.00 ml of water to make aqueous citric acid.

In this example:

5.00 grams of solid citric acid (solute) is dissolved in 500.00 ml of water (solvent) to make aqueous citric acid (solution).

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Answer:

1.90 M

Explanation:

To find the molarity of the solution, you need to use the molarity equation. This formula looks like this:

Molarity (M) = moles / volume (L)

To use this equation, you need to perform some conversions. You should (1) convert mL to L (by dividing by 1,000), then (2) convert grams NaNO₃ to moles (via molar mass), then (3) plug moles and volume into the molarity equation.

155 mL / 1,000 = 0.155 L

25.0 g NaNO₃           1 mole
---------------------  x  -----------------  = 0.294 moles NaNO₃
                                  85.0 g

Molarity = moles / volume

Molarity = 0.294 moles / 0.155 L

Molarity = 1.8975....

Molarity = 1.90 M

Answer:

Burning of paper and log of wood.

Digestion of food.

Boiling an egg.

Explanation:

Answer:

Discussion: Red cabbage is useful as a pH indicator because the leaves contain a pigment molecule from the family of anthocyanins (shown below) which are responsible for many of the red/purple/blue colors observed in fruits and vegetables. In neutral solutions, the color observed is purple.

hope this helps:3

Answer:

since water boil at 100 °C .so 500gof water Will still boil at 100 °C

Answer:

6.850767 grams is the answer

[tex]0.987 ~ \text{moles of Li} = 0.987 \times \text{Molar mass of Li}\\\\~~~~~~~~~~~~~~~~~~~~~~~=0.987 \times 6.941~ g\\\\~~~~~~~~~~~~~~~~~~~~~~~=6.850767~ g[/tex]

5.1434 contains 5 significant figures and 4 decimals.

All zeros that occur between any two non-zero digits are significant. For example, 108.0097 contains seven significant digits.

Calculation:

5.1234 + 0.033÷ 1.650 = 5.1434

5.1434 contains 5 significant figures and 4 decimals. 5.1434 rounded to 4 sig figs is 5.143, to 3 sig figs is 5.14, and to 2 sig figs is 5.1.

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The rate law depends on only A because it is the reactant in the rate-determining step.

The rate law is a representation of the rate of reaction. The fast reaction is  E+B ------> A+ D. The slow reaction is A + A ----->C + E. The overall reaction is A + B ------> C + D.

We know that the rate law depends  only on the  the slow reaction hence the rate law depends on only A because it is the reactant in the rate-determining step.

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The heat that is released by the combustion of 3.5 moles of methane is 3115 kJ/mol.

A thermochemical equation is a reaction equation that incorporates the amount of heat lost/gained.

In this case, the reaction equation is; CH4 + O2 ----->CO2 + 2H2O dH = -890 kJ/mol

If 1 mole of methane releases 890 kJ/mol

3.5 moles of methane will release 3.5 moles * 890 kJ/mol/1 mole

= 3115 kJ/mol

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Answer:

Copper (Cu2) , Iron (Fe2+ Fe3 +) , and Hydrogen ion (H+)

Explanation:

I hope it helps u dear! ^_^

The correct procedure is:

Dissolving 45 g of NaOH in enough water to make up to 750 mL of solution

This is defined as the mole of solute per unit litre of solution. Mathematically, it can be expressed as:

Molarity = mole / Volume

Mole = Molarity x Volume

Mole of NaOH = 1.5 × 0.75

Mole of NaOH = 1.125 mole

Mass = mole × molar mass

Mass of NaOH = 1.125 × 40

Mass of NaOH = 45 g

Thus, to obtain 750 mL of 1.5 M NaOH solution, 45 g of NaOH will be dissolved in enough water to make up to 750 mL of solution

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Answer:

0.0315 moles CH₂OH

Explanation:

You can find the amount of moles using the molarity equation. This equation looks like this:

Molarity (M) = moles / volume (L)

Once you convert mL to L (by dividing by 1,000), you can plug the molarity and volume into the equation and isolate to find moles. The final answer should have 3 sig figs because the given value with the lowest amount of sig figs (0.210 M) has this amount.

150.0 mL / 1,000 = 0.1500 L

Molarity = moles / volume

0.210 M = moles / 0.1500 L

(0.210 M x 0.1500 L) = moles

0.0315 = moles

The statement that describes what makes a base weak is that the base will be unable to dissociate completely in water.

A base is any of a class of generally water-soluble compounds, having bitter taste, that turn red litmus blue, and react with acids to form salts.

Bases usually dissociate into hydroxide ions (OH-) when in an aqueous solution.

However, a base is termed weak or strong depending on it's ability to dissociate completely. A weak base does not dissociate completely into hydroxide ions when in an aqueous solution.

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No of molecules=26.02×10²³molecules

No of moles

Molar mass

Mass

[tex]\\ \tt{:}\longrightarrow No\:of\:moles=\dfrac{Molecules}{Avagadro\:no}[/tex]

[tex]\\ \tt{:}\longrightarrow No\:of\:moles=\dfrac{26.02\times 10^{23}}{6.023\times 10^{23}}[/tex]

[tex]\\ \tt{:}\longrightarrow No\:of\:moles=4.32mol[/tex]

We need the mass

[tex]\\ \tt{:}\longrightarrow No\:of\:moles\times molar\:mass[/tex]

[tex]\\ \tt{:}\longrightarrow 32(4.32)[/tex]

[tex]\\ \tt{:}\longrightarrow 138.24g[/tex]

Answer:

194 mm Hg or 193.8mm Hg

Explanation:

273+18=291 K

2.35g /44

=0.0534 moles

P=0.0534 mol×0.082×29 / 5L

=0.2548 atm

0.255 × 760

=193.8 mmHg

Answer:

Solid have the lowest entropy

About 80g of KCl will dissolve in 200g of water at 50 degrees.

A saturated solution contains just as must solute as it can normally hold at a given temperature.

Looking at the table we can see that about 40 g of KCl dissolves in 100 g of water at 50 degrees hence about 80g of KCl will dissolve in 200g of water at 50 degrees.

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Answer:

0.625 moles MgCl₂

Explanation:

Since you were given a molarity value and volume, you should use the molarity equation to find moles. The equation looks like this:

Molarity (M) = moles / volume (L)

To find moles, you need to (1) convert mL to L (by dividing by 1,000) and then (2) plug the numbers into the formula and simplify to find moles. The final answer should have 3 sig figs as the lowest amount of sig figs in a given value is 3.

Step 1:

650.0 mL / 1,000 = 0.6500 L

Step 2:

Molarity = moles / volume

0.962 M = moles / 0.6500 L

(0.962 M) x (0.6500 L) = moles

0.625 = moles

The relation between the volume and the pressure of the gas can be given by the ideal gas equation. Warm air has more volume and low pressure that makes them rise above the equator.

Pressure present and exerted by the atmospheric gases are called atmospheric pressure. The volume of the gas is in inverse relation to the pressure of the gas.

Warm air has a high volume compared to cold air. More volume results in low pressure making them rise above the dense layer of the equator region.

Therefore, the warm air rises due to a decrease in pressure.

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By convention, the standard enthalpy of formation of all elements in their standard states are assumed to be zero. Here the enthalpy value for the intermediate formation step is  -572 kJ. The correct option is D.

The standard enthalpy of formation of a compound is defined as the enthalpy change accompanying the formation of one mole of the compound from its constituent elements, all the substances being in their standard states.

The symbol used to represent the standard enthalpy of formation is ΔfH⁰.  The knowledge of standard enthalpies of various substances is useful for calculating the standard enthalpies of a reaction.

The overall energy difference between the reactants and products remains the same no matter how many intermediates there are in the reaction pathway.

The enthalpy value  = 2 × -286 = -572 kJ

Thus the correct option is D.

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Answer:

sdfffffffff

Explanation:

dfffffgsdsdsdsdsdsdsdsdsdsdsdsdsdsdsd

No of moles

[tex]\\ \rm\Rrightarrow \dfrac{No\:of\: molecules}{Avagadro\:no}[/tex]

[tex]\\ \rm\Rrightarrow \dfrac{10.82\times 10^{23}}{6.023\times 10^{23}}[/tex]

[tex]\\ \rm\Rrightarrow 1.80mol[/tex]

So

[tex]\boxed{\sf No\:of\: molecules=No\:of\:moles\times Avagadro\:no}[/tex]

[tex]\\ \tt{:}\longrightarrow 10.82\times 10^{23}=n\times 6.023\times 10^{23}[/tex]

[tex]\\ \tt{:}\longrightarrow n=\dfrac{10.82}{6.023}[/tex]

[tex]\\ \tt{:}\longrightarrow n=1.8mol[/tex]