Which rule describes the composition of transformations that maps triangle BCD to triangle B""C""D""?

Answer:

(d)

Step-by-step explanation:

Given

See attachment for [tex]\triangle BCD[/tex] and [tex]\triangle B"C"D"[/tex]

Required

The transformations

Using B and B"" as points of reference, we have:

[tex]B = (1,4)[/tex]

[tex]B"" = (5,-1)[/tex]

The transformation is as follows:

First, reflect across y axis.

The rule is:

[tex](x,y) \to (-x,y)[/tex]

So, we have:

[tex]B(1,4) \to B'(-1,4)[/tex]

Next, translate 6 units right.

The rule is:

[tex](x,y) \to (x + 6,y)[/tex]

So, we have:

[tex]B' (-1,4) \to B"(-1 + 6,4)[/tex]

[tex]B' (-1,4) \to B"(5,4)[/tex]

Lastly, translate 5 units down

The rule is:

[tex](x,y) \to (x,y-5)[/tex]

So, we have:

[tex]B"(5,4) \to (5,4-5)[/tex]

[tex]B"(5,4) \to (5,-1)[/tex]

Hence; (d) is correct

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