Which one doesn't belong and explain

Which One Doesn't Belong And Explain

Answers

Answer 1

Answer:

The first one

Step-by-step explanation:

The first quotient (7) is different from the other three (0.7)

Hope this helps


Related Questions

Rodney opens a savings account with $75 and also deposits $40 each month. Morgan opens an account with $50 and also deposits $40 each month. Will they have the same amount in their account at any point? If so, after how many months? Explain.
Show an equation

Answers

No, they will not have the same amount in their account at any point of time.

Given that:-

Money deposited by Rodney at the opening of savings account = $ 75

Money deposited by Rodney each month in the account = $ 40

Money deposited by Morgan at the opening of savings account = $ 50

Money deposited by Morgan each month in the account = $ 40

Let us imagine that they will have equal amount of money in their accounts at a particular point of time.

Let us consider x to be the number of months when they will have same amount of money in their account.

Hence, we can write,

75 + 40x = 50 + 40x

We can see that,

75 - 50 = 40x - 40x

25 = 0

But this is not possible.

Hence, they will never have the same amount of money in their accounts at a particular point of time.

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HURRY Consider the equation 3x3 + 14x2 – 14x + 60 = 0. The real solution is –6. What are the nonreal solutions?

Negative 2 i StartRoot 26 EndRoot, 2 i StartRoot 26 EndRoot.
4 minus 2 i StartRoot 26 EndRoot, 4 + 2 i StartRoot 26 EndRoot.
StartFraction negative 2 + i StartRoot 26 EndRoot Over 3 EndFraction, StartFraction negative 2 minus i StartRoot 26 EndRoot Over 3 EndFraction.
StartFraction 2 + i StartRoot 26 EndRoot Over 3 EndFraction, StartFraction 2 minus i StartRoot 26 EndRoot Over 3 EndFraction.

Answers

The non-real solutions are (2 + i√26)/3 and  (2 - i√26)/3

How to determine the non-real solutions?

The equation of the polynomial expression is given as:

3x^3 + 14x^2 - 14x + 60 = 0

From the question, we have

x = -6

This gives

So, we have

x + 6 = 0

The next step is to divide the polynomial equation 3x^3 + 14x^2 - 14x + 60 = 0 by x + 6 = 0

This is represented as

3x^3 + 14x^2 - 14x + 60/x + 6

Using a graphing calculator, we have

3x^3 + 14x^2 - 14x + 60/x + 6 = 3x^2 - 4x + 10

Next, we determine the solution of the quadratic expression 3x^2 - 4x + 10 using a quadratic formula

So, we have

x = (-b ± √(b² - 4ac))/2a

This gives

x = (4 ± √((-4)² - 4 * 3 * 10))/2 * 3

So, we have

x = (4 ± √-104)/6

This gives

x = (4 ± 2√-26)/6

Divide

x = (2 ± √-26)/3

Rewrite as

x = (2 ± i√26)/3

Split

x = (2 + i√26)/3 and  x = (2 - i√26)/3

Hence, the non-real solutions of the polynomial expression are x = (2 + i√26)/3 and  x = (2 - i√26)/3

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Please answer question 8, I’d really appreciate it!!

Answers

Answer:

t = 8

Step-by-step explanation:

1. 2.5(t-2)-6 = 9      =       2.5t-5-6=9

2. add common terms = 2.5t - 11 = 9

3. add 11 on both sides to eliminate the 11

4. 2.5t= 20

5. 20/2.5 = 8

6. t = 8

HELP INTERSECTIONS AND UNIONS!!


Given: A= {0,3,5,7,9,11,12}

B={-3,5,8,9,11,14}

C={-2,1,5,7}


1.) (A ∩ B) U C

2.) (B U C) ∩ A

Answers

The most appropriate choice for sets, union and intesrsection of set will be given by

1) (A ∩ B) U C = {-2, 1, 5, 7, 9, 11}

2)  (B U C) ∩ A = {5, 7, 9, 11}

What is set and union and intersection of set?

Set is a well defined collection of distinct objects. Set can be empty as well as non empty.

Writing all the elements of two or more sets together in one set is known as union of sets.

Writing the common elements of two or more sets in one set is known as intersection of sets.

Given,

A= {0,3,5,7,9,11,12}

B={-3,5,8,9,11,14}

C={-2,1,5,7}

For 1)

(A ∩ B) = {5, 9, 11}

(A ∩ B) U C = {-2, 1, 5, 7, 9, 11}

For 2)

(B U C) = {-3, -2, 1, 5, 7, 8, 9, 11, 14}

(B U C) ∩ A = {5, 7, 9, 11}

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can u pls help me with this question

Answers

Answer:

Explanation:

eight of the bush when it was first planted int he garden = 12cm

After 2 weeks, its height = 120% of Height when it was planted.

[tex]=120\%\text{ of 12cm}[/tex]

We solve for the result.

[tex]\begin{gathered} =\frac{120}{100}\times12 \\ =1.2\times12 \\ =14.4\operatorname{cm} \end{gathered}[/tex]

The bush was 14.4cm tall after two weeks.

write an expression that can be used to find the value of x in the diagram below

Answers

since the angles are opposite by the vertex, we have that the expression to find the value of x is:

[tex]4x-1=55[/tex]

and if we solve it, we obtain:

[tex]4x=54[/tex][tex]x=13.5[/tex]

A person from Switzerland consumes about 9.1 kilograms of chocolate per
year. A person from the United States consumes about 4.7 kilograms of
chocolate per year. How many times as much chocolate will a Swiss
person consume in one year than someone from the United States? Round
your final answer to the nearest tenths

Answers

Answer:

switzerland was the leading country in chocolate consumption per capita in 2017, with citizens eating nearly nine kilos of the sweet stuff in that year. World renowned for the chocolate they produce, it seems the Swiss themselves can’t get enough of the candy. Germany, the country’s neighbor, is equally addicted, importing the largest share of Swiss chocolate of all countries in the world.

Step-by-step explanation:

Answer: a swede would consume 1.9 times as much chocolate as an American.

Step-by-step explanation: 9.1 / 4.7 = 1.93617021. round to the nearest tenth = 1.9.

1.93617021 times 4.7 equals 9.1

I need help on this problem can you help me?

Answers

The incenter is the center of a circumference that can be circumscribed inside the triangle. That means that the distance from the circumcenter to the sides of the triangle is the same. In this case, it means that:

[tex]NK=NL=NM[/tex]

On the other hand, the segments from the circumcenter N to the vertices of the triangle are angle bisectors, and using that fact, it can be proven that the two triangles that form at each vertex from the angle bisectors are congruent. Then, we can also know that:

[tex]HK=HM[/tex]

The congruence that cannot be deduced from the given information is:

[tex]NG\cong NJ[/tex]

help meeeeee plssss with steps​

Answers

Answer:

p = 18, q = 0

Step-by-step explanation:

The expression on the left side of the equation is
[tex]\large \text {$ \dfrac{\sqrt{5}+\:2}{\sqrt{5}-2}+\dfrac{\sqrt{5}-\:2}{\sqrt{5}+2} $}[/tex]

Multiply the denominators to get a common denominator:

[tex]\text{$\left(\sqrt{5}-2\right)\left(\sqrt{5}+2\right)$}[/tex]

= [tex]\left(\sqrt{5}\right)^2-2^2[/tex]                           ∵ (a + b)(a - b) = a² - b²

[tex]=5-4\\\\= 1[/tex]

[tex]\large \text {$ \dfrac{\sqrt{5}+\:2}{\sqrt{5}-2}+\dfrac{\sqrt{5}-\:2}{\sqrt{5}+2} $}\\\\[/tex]

[tex]=\dfrac{\left(\sqrt{5}+2\right)\left(\sqrt{5}+2\right)}{\left(\sqrt{5}-2\right)\left(\sqrt{5}+2\right)} + \dfrac{\left(\sqrt{5} - 2\right)\left(\sqrt{5} - 2\right)}{\left(\sqrt{5}-2\right)\left(\sqrt{5}+2\right)}[/tex]

Since denominator
[tex]\text{$\left(\sqrt{5}-2\right)\left(\sqrt{5}+2\right)$} = 1,[/tex]

the expression becomes

[tex]=\left(\sqrt{5}+2\right)^2 + \left(\sqrt{5}-2\right)^2\\\\= 5 + 4\sqrt{5} + 4 + 5 - 4\sqrt{5} + 4\\\\[/tex]

[tex]= 10 + 8 = 18[/tex]

Therefore  
[tex]\large \text {$ \dfrac{\sqrt{5}+\:2}{\sqrt{5}-2}+\dfrac{\sqrt{5}-\:2}{\sqrt{5}+2} = p + q\sqrt{5}$}\\\\\\= > \large \text{$ 18 = p + q\sqrt{5}$}[/tex]

Now [tex]\sqrt{5}[/tex] is an irrational number and p = rational so since there is no [tex]\sqrt{5}[/tex] term on the left side, q = 0 and p = 18

please help with this

Answers

Answer:

supplementary, not congruent.

a department store buys 300 shirts at a cost of 3600 and sells them at a selling price of $20 each find the percent markup

Answers

We have the following:

To find the percent markup, we must calculate the profits, knowing that there are 300 shirts and they sell them for a total of $ 20

[tex]300\cdot20=6000[/tex]

Now we subtract from what was initially spent and then divide by that same amount and multiplying by 100 we will know the percent markup

[tex]\frac{6000-3600}{3600}\cdot100=66.67\cong67[/tex]

Which means that the percent markup is 67%

In how many ways can the digits in the number 9666111 be​ arranged?

Answers

Answer:   140

========================================================

Explanation:

The unique digits are: 9, 6, 1

9 shows up once6 shows up three times1 shoes up three times

There are 1+3+3 = 7 digits with the repeats mentioned. If we could somehow tell the 6's apart and the 1's apart, then we'd have 7! = 7*6*5*4*3*2*1 = 5040 different permutations.

But because we can't tell the 6's apart, nor the 1's apart, this means we have to divide by (3!*3!). Each 3! represents the number of times the 6's show up and same goes for the 1's.

So (5040)/(3!*3!) = 5040/(6*6) = 5040/36 = 140 is the number of ways to rearrange the digits

If you mix 3 oz of blue paint with 2 oz of yellow paint, and then decide to create 20 oz of the same mixture, how many ounces of yellow paint do you need?

Answers

tata:

• Blue paint (,: B,) 3

,

• ellow poaint (

,

• Mixture obtained ( ),O

,

• Total mixture (), T

,

• Total yellow paint (): , TY

Proportion f Y:

[tex]Y=\frac{2}{5}=0.4[/tex]

TY:

[tex]TY=Y\cdot T=0.4\cdot20=8oz[/tex]

nswer: 8oz

ummary:

0. We got the proportion of yellow paint in the mixture

,

1. We multiply the proportion by the total mixture to know how many ounces of yellow paint is needed.

A local car dealership is trying to sell all of the cars that are on the lot. Currently, there are 725 cars on the lot, and thegeneral manager estimates that they will consistently sell 50 cars per week.1. Write and solve an inequality that can be used to find the number of full weeks, w, it will take for the number ofcars to be fewer than 125. Since w is the number of full or complete weeks, w = 1 means at the end of week 1.

Answers

Number of cars in the lot = 725 cars

W is the number of full or complete weeks

Also, 50 cars per week = 50w;

For every week, the cars will be reducing by 50;

(A) Hence , the inequality is given as;

[tex]725-50w<125[/tex][tex]\begin{gathered} 725-125<50w \\ 600<50w \\ \frac{600}{50}12 \end{gathered}[/tex]

A crane has a cable with a breaking strain of 6400 kg
measured to 2 significant figures.
It is used to lift crates which weigh 90 kg measured to the nearest 10 kg.
What is the
greatest number of crates that can safely be lifted
at one time without breaking the cable?
Some working must be shown.

Answers

The greatest number of crates that can safely be lifted  at one time without breaking the cable is 71.

What is GCF?

The biggest positive integer m that divides both x and y is the GCF of two or more non-zero integers, x, and y. The GCF stands for greatest common factor. In this case, greatest can be changed to highest, and factor to divisor. The highest common factor is often referred to as the biggest common factor, highest common factor, or highest common divisor (GCD). GCF is usually always utilised with fractions, which are frequently employed in daily life. You can obtain the necessary reduced form by determining the GCF of the denominator and numerator of a fraction or ratio.

A crane has a cable with a breaking strain of 6400 kg  measured to 2 significant figures.  It is used to lift crates which weigh 90 kg measured to the nearest 10 kg.

We need to calculate the greatest number of crates that can safely be lifted at one time without breaking the cable.

According to the question,

It is given that, the breaking strain of the crane is 6,400 kilograms and each crate is 90 kilograms.

Thus, to know the number of crates (n) that can safely lift is equal to the weight of the crane is 6,400 kilograms divided by is 90 kilograms.

thus,

[tex]n=\frac{weight of the crane}{weight of each crate}\\ \\n=\frac{6400}{90}[/tex]

so,  n= 71.111≈71

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Hihuvhhhhhvhhhuuibvjj

Answers

Given expression is (a+b)^8 and we need to find the 5th term of this series.

Explanation -

The general binomial expression is given as

[tex](x+y)^n=^nC_0x^ny^0+^nC_1x^{n-1}y^1+^nC_2x^{n-2}y^2+............upto\text{ x}^0[/tex]

So the given expression can be written as

[tex](a+b)^8=^8C_0a^8b^0+^8C_1a^7y^1+^8C_2a^6b^2+^8C_3a^5b^3+^8C_4a^4b^4+...[/tex]

So the 5th term will be

[tex]\begin{gathered} 5th\text{ term = }^8C_4a^4b^4 \\ The\text{ general comb}\imaginaryI\text{nat}\imaginaryI\text{on formula }\imaginaryI\text{s = }^nC_r=\frac{n!}{(n-r)!r!} \end{gathered}[/tex]

Then we have

[tex]\begin{gathered} 5th\text{ term = }\frac{8!}{(8-4)!4!}a^4b^4 \\ 5th\text{ term = }\frac{8\times7\times6\times5}{4!}a^4b^4 \\ 5th\text{ term = }\frac{8\times7\times6\times5}{4\times3\times2\times1}a^4b^4=2\times7\times5\times a^4b^4=70a^4b^4=70(ab)^4 \end{gathered}[/tex]So the final answer is 70(ab)^4

John and Savanah are saving money to go on a trip to Mexico. They need at least $2,545 in order to go. John tutors English and Savanah works as a babysitter to raise money. John charges $15 per hour and Savanah charges $20 per hour. The number of hours that Savanah has scheduled is no more than five times the number of hours John has scheduled. Savanah will babysit at least 40 hours.. Write a set of constraints to model the problem, with x representing the number of hours John tutors and y representing the number of hours Savanah babysits​

Answers

The group of restrictions used to simulate the issue includes

y<5x andy [tex]\geq[/tex] 40hours

How to construct a set of restrictions to represent the issue:

The issue includes the following information.

They require $2,545 split by John's and Savanah's hours. Savanah's hours are no more than five times John's. Savanah will babysit the kids for 40 hours.

The limitations for modeling the problem are as follows: The gap between the number of hours Savanah has reserved and those that John has is no more than five times.

Savanah will provide child care for a minimum of 40 hours, but no longer than that, indicating that it is less than; as a result.

,y<5x

Meaning "at least 40 hours" is "at least 40 hours." 40 hours or more may be expressed as

y ≥ 40 hours

The two necessary restrictions are represented as y< 5x and y=> 40 hours in an inequality model.

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help meeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeee

Answers

Answer:

74.44

Step-by-step explanation:

[tex]P(10)=0.018(10)^3-0.294(10)^2+3.065(10)+55.190 \\ \\ =74.44[/tex]

QUESTION 3After surgery a patient was put on a restricted diet. In the first 2 days after surgery the patient was only allowed to consume•800 Cal/day. In the following 3 days the patient was allowed to consume 1100 Cal/day. In the final 4 days at the hospital thepatient was allowed to consume 1500 Cal/day.a) What was the average energy per day consumed? Round answer to the one if necessary.b) What is the unit symbol for the answer?

Answers

Given the patient consumption rate on his diet:

[tex]\begin{gathered} 1-2\text{days}=\text{ 800 Cal/day} \\ 2-3\text{days}=1100\text{ Cal/day} \\ 3\text{ -4days=1500 Cal/day} \end{gathered}[/tex]

(a) Average energy per day consumed will be since the number of days = 4

[tex]\begin{gathered} =\frac{800+1100+1500}{4} \\ =\frac{3400}{4} \\ =850\text{ Cal} \end{gathered}[/tex]

The average energy per day consumed = 850 Cal(b) The unit symbol for the answer = calorie

Shandra owns a goldfish that currently weighs 0.50 ounces. With each inch that the goldfish grows, the goldfish weighs an additional0.15 ounces.PARTACreate an equation that Shandra can use to find the number of inches, r, it will take for the goldfish to weigh 1.1 ounces.PART BHow many more inches does the goldfish need to grow to weigh 1.1 ounces?inches

Answers

A.

The initial weight of the goldfish is 0.5 ounces.

Then, for each inch it grows, its weight increases by 0.15 ounces.

So, using the variable r to represent the number of inches it grew, we can write the following equation to determine the value of x for a weight of 1.1 ounces:

[tex]0.5+0.15r=1.1[/tex]

B.

Solving the equation for r, we have:

[tex]\begin{gathered} 0.15r=1.1-0.5 \\ 0.15r=0.6 \\ r=\frac{0.6}{0.15} \\ r=4 \end{gathered}[/tex]

It needs to grow 4 more inches.

the sum of two consecutive natural numbers is 313

Answers

answer : 12,13

explanation:

Let the numbers be x and x+1.
x2 + (x+1)2 = 313
2x2 + 2x + 1 = 313
2x2 + 2x - 312 = 0
x2 + x - 156 = 0
x2 + 13x - 12x - 156 = 0
x(x + 13) - 12(x + 13) = 0
(x - 12) (x + 13) = 0
x = 12 or -13. Since x cannot be negative, x = 12. Hence, numbers are 12 and 13.

Answer:

156 and 157

Step-by-step explanation:

Which is greater? -7/10 or -0.66?

Answers

Answer:

-7/10

Step-by-step explanation:

First, we obviously need to convert 0.66 into a fraction.  Since -7/10 cannot be changed, we need to change AND simplify -0.66.

-0.66 is equal to -66/100, but we can still simplify this. We can divide the numerator and denominator by 2.

66 divided by 2 is 33.

100 divided by 2 is 50.

-33/50 CANNOT be simplified anymore.

So -7/10 _ -33/50. Which is greater?

-7/10 is closer to 0 on the number line. -33/50 isnt.

So -7/10 is the answer.

-7/10 > -0.66

In her notebook, Pia wrote these steps to construct a square inscribed in a circle:Use a compass and a straightedge to find chord LM, which is the perpendicular bisector of JK. Then, use a straightedge to draw the four chordsthat make up the square: JL, LK, KM, and MJ.Which instruction is Pia missing?

Answers

We want to draw chord LM such that it is a perpendicular bisector of line JK. The square would be drawn by joining lines JL, KL, KM and MJ

To achieve this, the daigram should look like the one shown below

This diagram is only possible if JK passes through the center of the circle. This means that JK is the diameter of the circle. Thus, the correct option is

B

Answer:

B

Step-by-step explanation:

The airport parking lot charges $2.00 to enter and $3.00 per hour after that. Carmen has N dollars and wants to be able to determine the maximum number of hours she can park. How can Carmen determine the length of time she can afford to park her car in the parking lot? Justify your answer.

Answers

The equation of the time she can afford to park her car is 2 + 3t = N

How to determine the time she can afford to park her car

The given parameters are

Entrance charge = $2.00Rate per hour = $3.00

Assume she stays for t number of hours, the total charges would be

Total = Entrance charge + Rate per hour * Number of hours

This gives

Total = Entrance charge + Rate per hour * t

Substitute the known values in the above equation

So, we have

Total = 2 + 3t

From the question, she has N dollars

So, we have

2 + 3t = N

Hence, the expression of the description is 2 + 3t = N

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Translate the sentence into an equation
Nine times the sum of a number and 7 is equal to 5
Use the variable y for the unknown number

Answers

Answer:
9(y+7)=5

Since there’s the sum of this means that the variable and 7 are stuck together. In this case you will need a bracket. Then you need to multiply the whole equation by 9.

A Sony LCD TV has a selling price of $925 and a 62% markup on selling price. What is the dollar markup and what is the cost?

Answers

Answer

Selling price = $ 925

Mark percentage = 62%

[tex]\begin{gathered} \text{Let's x represent Cost price i.e C. P=x} \\ \text{Selling price =C P +profit} \\ Profit\text{ =}\frac{\text{62x}}{100} \\ \\ S\text{. P =x+}\frac{\text{62x}}{100} \\ S\text{. P=x+0.62x} \\ S\mathrm{}P=1.62x \\ \therefore1.62x=925 \\ \end{gathered}[/tex][tex]\begin{gathered} \therefore1.62x=925 \\ \text{Divide both sides by 1.62} \\ \therefore\frac{1.62x}{1.62}=\frac{925}{1.62} \\ \\ x=570.99 \end{gathered}[/tex]

The cost price is 570.

A car uses 3 1/8 gallons of gasoline per hour when driving on the highway. How many gallons will it use after 4 2/3 hours? It will use _____________ gallons.

Answers

If the car uses 3 1/8 gallons per hour and the number of hours is 4 2/3, we can multiply both values to find the total amount of gallons used in this time.

First, we need to convert 3 1/8 and 4 2/3 into improper fractions:

[tex]\begin{gathered} 4\text{ }\frac{2}{3}=4+\frac{2}{3}=\frac{12}{3}+\frac{2}{3}=\frac{14}{3}\\ \\ 3\text{ }\frac{1}{8}=3+\frac{1}{8}=\frac{24}{8}+\frac{1}{8}=\frac{25}{8} \end{gathered}[/tex]

Now, multiplying the values, we have:

[tex]\frac{25}{8}\cdot\frac{14}{3}=\frac{350}{24}=14.58[/tex]

So the car will use 14.58 gallons.

Jonah studied z hours for a big test. Francesca studied a fourth as long. Write an algebraic expression for long Francesca studied.

Answers

The expression for study hours of Francesca will be ( Z + 4 ) hours.

What is an expression?

The mathematical expression combines numerical variables and operations denoted by addition, subtraction, multiplication, and division signs.

Mathematical symbols can be used to represent numbers (constants), variables, operations, functions, brackets, punctuation, and grouping. They can also denote the logical syntax's operation order and other properties.

Given that Jonah studied z hours for a big test. Francesca studied a fourth as long as Jonah studied.

The expression will be written as Francesca studied 4 hours more than Jonah.

Francesca's study time = ( Z + 4 ) hours

Therefore, the expression for study hours of Francesca will be ( Z + 4 ) hours.

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Find the surface area and volume of the solid. Round each measure to the nearest tenth, if necessary.

Answers

The surface area and volume of the solid are  104 in² and 60 in³

How to determine the volume

It is important to note that the figure takes the shape of a cuboid.

The formula for determining the surface area of a cuboid is expressed as;

SA = 2lw + 2lh + 2hw

Where;

SA is the surface areal is the length of the cuboidw is the width of the cuboidh is the height of the cuboid

Now, let's substitute the values into the formula, we have;

Surface area = 2(5× 2) + 2(5 ×6) + 2(6 × 2)

expand the bracket

Surface area = 2(10) + 2(30) +2 (12)

Surface area = 104 in²

The formula for volume is given as;

Volume = l × w × h

Volume = 5 × 2 × 6

Volume = 60 in³

Thus, the values are  104 in² and  60 in³

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The midpoint of AB is M(6, 3) . If the coordinates of A are (7, 4) , what are the coordinates of B?

Answers

[tex]~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ A(\stackrel{x_1}{7}~,~\stackrel{y_1}{4})\qquad B(\stackrel{x_2}{x}~,~\stackrel{y_2}{y}) \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left(\cfrac{ x +7}{2}~~~ ,~~~ \cfrac{ y +4}{2} \right) ~~ = ~~\stackrel{\textit{\LARGE M}}{(6~~,~~3)} \\\\[-0.35em] ~\dotfill\\\\ \cfrac{ x +7}{2}=6\implies x+7=12\implies \boxed{x=5} \\\\[-0.35em] ~\dotfill\\\\ \cfrac{ y +4}{2}=3\implies y+4=6\implies \boxed{y=2}[/tex]

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