The only planet without an atmosphere is Mercury. But it does have an exosphere, a layer of gases that are released from the terrestrial planet's surface after being absorbed by the solar wind.
What caused the primary atmospheres of the terrestrial planets to disappear?Terrestrial planets' weak gravitational fields rendered their main atmospheres unsupportable. It is well known that these planets have weak gravitational fields. In addition, the atmosphere was lost as a result of the planet's velocity, atomic mass, and surface temperature.
Which terrestrial planet is believed to have lost heat from within the quickest?Mercury, the smallest planet, has already lost the majority of its inner heat due to the different cooling speed.
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maxwell developed his theory of electromagnetism by combining previous discoveries. he added his own original hypothesis that
Maxwell added his own original hypothesis that is Changing electric fields produce magnetic fields.
What is Electromagnetism?
In the process of electromagnetism, electricity is applied to a conductor to create a magnetic field. When a conductor is electrically charged, magnetic lines are created. For instance, if current, or positive charges travelling in a wire, generates the magnetic field along the wire, the Right-Hand Rule can be used to determine the direction of magnetic lines and force. See the graphic for a thorough justification.
We've seen what happens when a conductor receives an electrical charge. Now let's look at what happens when a conductor is placed between the magnet and the magnetic field.
When a conductor is placed or moved through a magnetic field, voltage or electrical current is produced. This idea is known as "electromagnetic induction."
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a pickup truck (2268 kg) and a compact car (1100 kg) have the same momentum. (a) what is the ratio of their kinetic energies? (b) if the same horizontal net force were exerted on both vehicles, pushing them from rest over the sa
A pickup truck (2268 kg) and a compact car (1100 kg) have the same momentum. The ratio of their kinetic energies (truck to car) is 0.485
The formulas for the momentum and the kinetic energy are:
p = m . v
Ek = 1/2 . mv²
Where:
p = momentum
m = mass
Ek = kinetic energy
v = speed or velocity
Ek = 1/2 . mv² = 1/2 . mv . v
= 1/2 . p . v
Since p or momentum of both vehicles are the same, hence, the ratio of their kinetic energies is
Ek_truck : Ek_car = v_truck : v_car
In the given problem:
m_truck = 2268 kg
m_car = 1100 kg
Both have the same momentum, hence,
m_truck x v_truck = m_car x v_car
v_truck / v_car = m_car / m_truck
= 1100 / 2268 = 0.485
Therefore,
Ek_truck / Ek_car = v_truck / v_car = 0.485
Your question is incomplete, but most probably your question was:
A pickup truck (2268 kg) and a compact car (1100 kg) have the same momentum. If the same horizontal net force were exerted on both vehicles, pushing them from rest over the same distance, what is the ratio of their final kinetic energies? (ratio: truck to car)
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A solid 66 kg cylinder has a radius of 0.10 m. What minimum work is required to get the cylinder rolling without slipping at a rotational speed of 20 s−1?
198J minimum work is required to get the cylinder rolling without slipping at a rotational speed of 20 s−1
Work corresponds to a change in energy. So, the work required to make this cylinder roll is equal to its final kinetic energy minus its initial kinetic energy.
W=Kf−Ki
We can assume that this cylinder begins from rest, in which case Ki=0.
W=Kf
What is this cylinder's new kinetic energy? If an object is rolling, it is undergoing both rotational and translational motion. So, the cylinder's kinetic energy is equal to its translational kinetic energy plus rotational kinetic energy.
W=1/2mv2+1/2Iω²
We have values for the cylinder's mass and its rotational speed. What about its translational speed? We can use the conversion formula
v=rω and substitute this into our equation.
W=1/2m(rω)²+1/2Iω²
W=1/2mr²ω²+1/2Iω²
What about the moment of inertia? We can look up in a table that a cylinder has moment of inertia 1/2mr². Plugging this in, our equation becomes:
W=1/2mr²ω²+1/2(1/2mr²)ω²
W=1/2mr²ω²+1/4mr²ω²
W=3/4mr²ω²
Now, let's plug in values for all these variables and get our answer.
W=34(66)(0.1)2(20)2
W=198J
A solid 66 kg cylinder has a radius of 0.10 m. What minimum work is required to get the cylinder rolling without slipping at a rotational speed of 20 s−1?
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a 500.0 lb man is crossing the street when the brakes on 454.5 kg car fail and she hits the gorilla head on at 50.0 mph. if the collision is perfectly inelastic, at what speed will the car and the gorilla travel after the collision?
If the collision is perfectly inelastic, the speed of the car and the gorilla travel after the collision is 14.9m/s.
Perfectly inelastic collision, also known as completely inelastic collision is one in which the maximum amount of kinetic energy has been lost during a collision, making it the most extreme case of an inelastic collision.
From the question given
mass of gorilla man, m = 500lb - 500 * 0.4536 = 226.8kg
Initial speed of the car, u = 50mph = 50 * 0.447 = 22.35 m/s
mass of the car, M = 454.5kg
applying conservation of momentum formula :
(m + M) * V = M * u
(226.8 + 454.5) * V = 454.5 * 22.35
681.3V = 10,158.075
V = 14.9m/s
Therefore, the speed of the car and the gorilla travel after the collision is 14.9 m/s.
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A crazy bus driver launches the bus out of the parking lot with an amazing acceleration of 1.5 m/s^2. He goes an incredible distance of 85 m before reaching the bus's maximum speed. How fast is the bus going after reaching top
speed?
1) 11 m/s
2) 16 m/s
3) 130 m/s
4) 255 m/s
5) Answer not shown
The final speed of the bus after reaching the top is equal to 16 m/s. Therefore, option (2) is correct.
What is the equation of motion?Equations of motion can be utilized to define the concept of the motion of a body such as the velocity, time, position, and acceleration of a body several times.
The three equations of motion can be shown as follows:
[tex]v = u + at\\S = ut +(1/2) at^2\\v^2-u^2= 2aS[/tex]
Given, the initial speed of the bus, u = 0m/s
The distance covered by the bus, S = 85 m
The acceleration in the bus, a = 1.5 m/s²
We can determine the final velocity of the bus from the third equation of motion:
v² - u² = 2aS
v² -0 = 2 ×1.5 × 85
v² = 255
v = 15.97 ≈ 16 m/s
Therefore, the final speed of the bus is 16 m/s.
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An adult inhales about 6.0×10−4 m3 of fresh air during a breath. only 20% of fresh air is oxygen. assume the pressure in the lungs is 1.0×105 pa and the air is at a temperature of 300 k. How many oxygen molecules are in each breath? a. 2.9 times 10^21 b. 4.9 times 10^-4 c. 2.9 times 10^25 d. 1.4 times 10^23
An adult breathes in around 6.0104 m^3 of fresh air per breath, which contains 2.9 times 10^21 oxygen molecules. Oxygen makes up only 20% of fresh air. Assume that the lungs have a pressure of 1.0 x 10-5 pa.
molecules A bridge made of liquid oxygen can hold itself against its own weight between the poles of a strong magnet in laboratory experiments due to the liquid oxygen's extreme magnetic properties. The force perpendicular to an object's surface that is delivered per unit area over that force is known as pressure (symbol: p or P). The gauge pressure, also known as gauge pressure, is the pressure in relation to the surrounding air pressure. To express pressure, a variety of units are employed. The equilibrium of molecules is set.
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the five identical bulbs in the following figure are all glowing. the battery is ideal.(figure 1). What is the order of brightness of the bulbs, from brightest to dimmest? Some may be equal.P = S = T > Q = RP > S = T > Q = RP > Q = R > S = TP = S > Q = R = T
If the five identical bulbs shown in the figure are glowing and the battery provided is ideal then the order of brightness of the bulbs from brightest to dimmest is P > S = T > Q = R.
The energy is dissipated when the current flows through a resistor. The rate of the dissipated energy is the power. It is given as=
= P = ΔV(R) / R
The bulbs are identical, so the resistance will be the same. Calculating the voltage for each bulb. The combination ST is in parallel with the other branch. So, the voltage across the right branch and the middle branch is the same ∈.
For the right branch, the voltage is divided by the two resistors i.e S and T, so the voltage is =
= ΔV(S) = ΔV(T) = ∈/2
Since voltage is same, they will have same brightness.
For the middle branch, the total voltage is ∈, but the combination QR has resistance less than bulb P. So, the bulb P has larger voltage than combination QR. Hence, the voltage of P = 2∈/3 while the combination QR has the voltage of ∈/3.
Thus,
ΔV(P) > ΔV(S) = ΔV(T) > ΔV(Q) = ΔV(R)
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find the force needed to keep a mass m in a circular path of radius r with period t.
Answer:
Explanation: for circular motion centripetal force is involves
as we know, F= mass× acceleration
F= mv²/ r
r = radius
v = 2πr/ t
here t = time and v = velocity/ speed
as we know v= d/ t= 2πr/t
therefore F = m×(2πr/t)²/r
.
What is the main difference between a refracting telescope and a reflecting telescope?
A refracting telescope uses a convex lens to collect light; a reflecting telescope uses a convex mirror to collect light.
A refracting telescope uses a convex lens to collect light; a reflecting telescope uses a concave mirror to collect light.
A refracting telescope uses a concave lens to collect light; a reflecting telescope uses a concave mirror to collect light.
A refracting telescope is a telescope that uses lenses and refraction to redirect light in order to magnify distant objects.
A reflecting telescope uses reflection off of mirrors in order to magnify. A refracting telescope uses lenses. A reflecting telescope uses broadly speaking mirrors, in particular for the primary few optical elements. Astronomical telescopes are generally reflecting because it’s a whole lot less difficult to scale mirrors to big sizes.
consider it in terms of how your eye works. while your student is bigger in darker situations, it collects greater mild allowing you to peer fainter things. That aperture for maximum humans is set 7mm at the biggest.
A telescope, via the truth that it has a good larger aperture than your eye, collects even extra mild than your eye can. So even a 50mm telescope is amassing a long way greater mild than your eye on my own at just 7mm diameter. and then eyepiece focuses that light for your eye to study.
So with greater aperture, fainter gadgets - which includes stars, galaxies and nebulae - can be visible.
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A 40.0-kilogram child exerts a 100.-newton force on a 50.0-kilogram object. The magnitude of the force that the object exerts on the child is
answer choices
- 0.0 N
- 80.0 N
- 100. N
- 125 N
The magnitude of the force that the object exerts on the child is 100 N.
option C is the correct answer.
What is Newton's third law of motion?
Newton's third law of motion states that for every action there is an equal and opposite reaction. In other words, action and reaction are equal and opposite.
Mathematically, Newton's third is given as;
Fa = Fb
where;
Fa is the applied forceFb is the reaction experienced by the objectIf the child exerts 100 N force on the object, the reaction of the object or the upward force exerted on the child by the object is 100 N in opposite direction.
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A 2150 kg car, moving east at 10.0 m/s, collides and joins with a 3250 kg car. The cars move east together at 5.22 m/s.
The momentum during the collision is conserved. Hence, the total initial momentum is equal to the total final momentum. Therefore, the initial velocity of the car with a mass of 3250 Kg was, 2.05 m/s.
What is momentum?Momentum of a body is the product of its mass and velocity. Momentum is a vector quantity having both magnitude and direction.
The momentum during a collision is conserved. Thus,the sum of initial momentum of the colliding bodies is equal to the final momentum of the combined mass.
Given that, mass of car 1 = 2150 Kg
velocity = 10 m/s
Momentum = mass × velocity.
= 10 m/s × 2150 Kg = 21500 kg m/s.
Mass of car 2 = 3250 kg
the combined mass = 3250 + 2150 = 5400 Kg
final velocity = 5.22 m/s
final velocity = 5400 Kg × 5.22 = 28188 kg m/s .
momentum of car 1 + momentum of car 2 = 281888 kg m/s
21500 kg m/s + (3400 Kg × V) = 281888 kg m/s
v = 2.05 m/s.
Therefore, the initial velocity of the car with a mass of 3250 Kg is 2.05 kg m/s.
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Your question is incomplete. But your complete question probably was:
A 2150 kg car, moving east at 10.0 m/s, collides and joins with a 3250 kg car. The cars move east together at 5.22 m/s. What was the initial speed of car with 3250 kg mass.
you're explaining to a youngster at the seashore why the water is cyan colored. the youngster points to the white-caps of overturning waves and asks why they are white. what is your answer?
Water droplets of various sizes can be seen on white wave caps. These droplets disperse variously frequency photons. A type of wave whose value only varies in one spatial direction is referred to as a plane wave.
In other words, its value remains unchanged on a plane oriented perpendicular to that direction. A vector of unit length that indicates the direction in which the wave varies can be used to describe plane waves. The frequency of an event is its repetitions per unit of time. As a contrast to spatial frequency, it is also sometimes referred to as temporal frequency, and as a contrast to angular frequency, it is sometimes referred to as ordinary frequency. The hertz unit is used to measure frequency (Hz).
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A 1750 kg car increases its speed by 3. 5 m/s2 for each second of travel. What is the net force acting on the car?.
The net force acting on the car is equal to 6125 N.
What is force?Force acting on a body can be defined as the effect or influence that changes the body's state of motion or rest. The S.I. unit of measurement of the force is Newton and it is a vector quantity. Force exerted on an object can change the speed and direction of the moving object.
The force exerted on an object can be evaluated from the product of the mass (m) with the acceleration (a) of an object. The equation of the second law of motion for force can be used to calculate force:
F = ma
Given, the mass of the car, m = 1750 Kg
The acceleration of the car for each second of travel, a = 3.5 m/s²
The net force acting on the car can be determined as:
F = ma = 1750 × 3.5 = 6125 N
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Which of the following statement is not correct about the magnetic field?
(a) Magnetic field lines form a continuous closed curve.
(b) Magnetic field line do not interest each other.
(c) Direction of tangent at any point on the magnetic field line curve gives the direction of magnetic field at that point.
(d) Outside the magnet, magnetic field lines go from South to North pole of the magnet.
consider the earth spinning from west to east on its axis. it is slowing down in its rotation due to friction with the air. using the right hand rule, in what direction is the frictional torque?
The frictional torque is in the direction of N pole to S pole according to the right hand rule.
What is the right hand rule?The right hand rule is a hand mnemonic in physics that is used to remember which way three-dimensional axes or parameters point. The right hand rule was developed in the 19th century by British physicist John Ambrose Fleming for electromagnetism applications. When the other two parameters are known, it is most frequently employed to identify the direction of the third parameter (magnetic field, current, magnetic force).
A conductor, like a copper wire, induces an electric current when it passes through a magnetic field (B). Faraday's Law of Induction is a name given to this phenomenon. The directions of the conductor's motion (velocity), magnetic field, and induced current are related if the conductor is moved inside the magnetic field. We can look into Faraday's Law of Induction using Fleming's right hand rule.
emf = -N (ΔФ[tex]_{B}[/tex]/Δt)
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A wire of iron which is 3.14 m long and has a radius of 0.5 mm is connected between
the terminals of a 5 V battery. If the resistivity of the iron is 10-72.m, so the passing
electric current intensity in the wire equals..
(Take: pi=3.14)
Answer:
12.5 A
Explanation:
You want the current intensity in an iron wire 3.14 m long with a radius of 0.5 mm connected to a 5V battery, given the resistivity of iron is 10^-7 Ω·m.
ResistanceThe resistance of the wire is proportional to wire length, and inversely proportional to area:
R = ρl/A
R = (10^-7 Ω·m)(3.14 m)/(3.14·(0.5·10^-3 m)²) = (1/.25)·10^-1 Ω = 0.4 Ω
CurrentThe current is given by Ohm's law:
I = V/R
I = (5 v)/(0.4 Ω) = 12.5 A
The current intensity is 12.5 amperes.
__
Additional comment
The resistivity of iron is 1.0·10⁻⁷ Ω·m, so we presume the 10-72.m in the problem statement is an error in picture-to-text translation.
when the terminal side of an angle in standard position lies along one of the axes, it is called
When a terminal side of an angle in a standard position lies along one of the axes, it is called a quadrantal angle.
If an angle's vertex is at the origin and one of its rays is on the positive x-axis, it is said to be in the standard position.
The starting side refers to the ray on the x-axis, while the terminal side refers to the other ray.
The side that isn't the starting side is known as the terminal side of an angle when it is represented in an angle standard position.
Starting at (1, 0), measure the angle on the unit circle in degrees or radians to get the terminal point (move counter clockwise if the angle is positive and clockwise if the angle is negative.)
The terminal point is the coordinate of the terminus.
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a squirrel on a limb near the top of a tree loses its grip on a nut, so that the nut slips away horizontally at a speed of 2.0 m/s. if the nut lands at a horizontal distance of 8.6 m, how high above the ground is the squirrel?
The nut slips away horizontally at a speed of 2.0 m/s. if the nut lands at a horizontal distance of 8.6 m. The squirrel is on a limb of a tree with the height of 90.6 m above the ground.
The nut experienced a projectile motion. The equation of motion can be divided into vertical and horizontal components below:
- Horizontal motion: the velocity is constant.
s = v x t
Where:
s = distance
v = velocity = speed = 2 m/s
t = time
Hence,
8.6 = 2 t
t = 8.6/2 = 4.3 s
- Vertical motion: it is a free fall motion
h = 1/2 . gt²
Where:
h = height
g = acceleration due to gravity = 9.8 m/s²
Hence,
h = 1/2 x 9.8 x 4.3²
= 90.6 m
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Two 1000 kg cars drive east; the first mov-
ing at 45 m/s, the second at 15 m/s.
What is the magnitude of the total momen-tum of the svstem?
Answer in units of kg • m/s.
Answer:
30000kg.m/s
Explanation:
two cars mass 1000
first moving with 45m/s
second moving with 15m/s
find the total magnitude of momentum = ?
momentum formula=mv
so,
mass is common
mass(v1 -v2)
putting the value
1000(45-15)
30000kg.m/s
Uppoe that a phone i dropped from a light pole 70. 0 meter high. How far will the phone have fallen after 3. 00 econd
The formula for horizontal distance is x = Vx * t, where t is the time. The formula for vertical distance from the ground is y = h + Vy * t - g * t2 / 2, where g is the acceleration of gravity.
What is the free fall equation?
Where g is the acceleration of gravity, vf is equal to g * t. On Earth, the value of g is 9.8 m/s/s. The velocity of the object after being dropped from rest for any given period of time can be calculated using the aforementioned equation.
How is height determined?
At the spot where the ruler, book, or other flat object meets your head, lightly mark the wall with a pencil. Measure the distance from the floor to the mark on the wall using a tape measure, preferably one made of metal that will stay straight.
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a 0.14-kg baseball is dropped from rest from a height of 2.0 m above the ground. what is the magnitude of its momentum just before it hits the ground if there is no air resistance?
The magnitude of its momentum just before it hits the ground is 0.88kg m/s
Momentum is the product of the mass of the body and its velocity. A vector quantity that has magnitude and direction. If m is the mass of an object and v is its velocity (which is also a vector quantity), then the object's momentum p is:
p=mv
In the International System of Units (SI), the unit of measure for momentum is the kilogram meter per second (kg m/s), which is equivalent to the Newton second.(F=ma)
Final velocity:
v^2= u^2+2as
v^2=0+ 2(g) h
v= √(2gh) =√(2×9.8×2.0)
v=6.26 m/s
Momentum:
p=mv =0.14×6.26
p= 0.876= 0.88 kg m/s
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briweaver9564
12/04/2019
Physics
High School
answered • expert verified
Two ropes have equal length and are stretched the same way. The speed of a pulse on rope 1 is 1.4 times the speed on rope 2. Part A Determine the ratio of the masses of the two ropes (m1m2).
the ratio of the masses of the two ropes is 0.51
Calculation :
For a rope, the speed of standing wave is given as
[tex]v = \sqrt{\frac{T}{m/L} }[/tex]
Here, as T and L is same for both the ropes
v1 = 1.4v2
as v1 /v2 = sqrt(m2/m1)
1.4 = sqrt(m2/m1)
m1/m2 = 0.51
the ratio of the masses of the two ropes is 0.51
Mass is an inherent property of an object. Mass is a standard mechanical quantity. Until the discovery of atomic physics and particle physics, it was traditionally thought to be related to the amount of matter in the physical body. are found to have different masses for the same amount of matter. Mass has several definitions in modern physics that are conceptually different but physically equivalent
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a 50-mh inductor is connected across a 10-v rms ac generator, and an rms current of 2.0 ma flows.
The value of the generator frequency of the system will be 15.9 kHz.
Value of the inductor = 50 mh
Voltage = 10 V
As we know,
The value of the frequency can be determined by using the formula:
f = (w/2)*3.14-----(a)
Where, w = wattage (Power)
As wattage can be calculated by using the formula:
w = v*I*L
Where, v = voltage of the system
I = value of the current
L = value of the inductor
So, after putting all the values the expression given in (a) becomes:
f = v/2*3.14*i*L
Now to find the value of the frequency we will put the value of the inductor, current, and voltage given in the question in the above expression.
Thus, we will get it as:
[tex]f = \frac{10}{2}\times 3.14 \times 2\times 10^{-3} \times 50\times 10^{-3}[/tex] = 15.9 kHz
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The complete question should be like:
A 50-mH inductor is connected across a 10-V rms AC generator, and an rms current of 2.0 mA flows. What is the generator frequency?
Owen uses a pulley system to lift a bucket. He pulls the rope with 80 newtons of force. The rope exerts 160 newtons of force on the attached bucket. The mechanical advantage of Owen’s pulley system is
The mechanical advantage of Owen’s pulley system is determined as 2.
What is mechanical advantage?Mechanical advantage is also known as force ratio, it determines the ratio of output force to input force.
It can also be expressed as the ratio of load to to effort applied in overcoming the load.
M.A = load / effort
The given parameters include;
the applied force = 80 Nthe output force or load = 160 NM.A = 160 N / 80 N
M.A = 2
Thus, the mechanical advantage of a machine is the ratio of output force to input force.
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the vast majority of human behavior in society is considered prosocial behavior. state of true or false
- True
- False
Yes it is true ,A broad group of actions with the intention of assisting others includes helping, sharing, providing comfort, contributing or volunteering, and cooperating.
Research on prosocial conduct has looked at the potential causes and effects of these behaviors as well as the various reasons that might be at play. Prosocial Behavior's Type 3. The factors. Actions that "benefit other people or society as a whole," such as assisting, sharing, contributing, cooperating, and volunteering, are considered prosocial conduct, also known as "voluntary behavior intended to benefit another." Evidence demonstrates that prosociality is essential to social groupings' wellbeing on a variety of measures. Empathy has significant evolutionary roots and is a powerful motivator of prosocial action. Children benefit from the development of desirable qualities fostered by prosocial activity.
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true or false: a leaf floating up and down in a pond is an example of a longitudinal wave. a. true b. false
A leaf floating up and down in a pond is an example of a longitudinal wave that is False.
Particle motion is perpendicular to energy motion. Shear waves exhibit wave polarization that longitudinal waves do not. There is a distinct peak-to-valley movement. The node remains stationary. Here you can touch standing waves with a rope without disturbing the waves.
The position on the standing wave of maximum amplitude is known as the antinode. Antinodes occur halfway between nodes. Standing waves are undesirable. Some of the energy is reflected off the ends of the line and actually travels up the line.
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A thin 2.00 kg box rests on a 7.00 kg board that hangs over the end of a table, as shown in (Figure 1). a) How far can the center of the box be from the end of the table before the board begins to tilt?
Based on the principle of moments, the distance from the end of the table should the box be placed before the board begins to tilt is 17.5 cm.
The distance from the end of the table should the box be placed before the board begins to tilt is determined from the principle of moments as follows:
sum of clockwise moments = sum of anticlockwise moments
The block is 30 cm on the table and 20 cm outside it.
The downward force acting on the left-hand side of the box
= 3/5 x 7 = 4.2
This force acts at the center of gravity, 15 cm or 0.15 m away.
Therefore, anticlockwise moments o the left side =4.2 x 0.15 = 0.63 J
Also, the clockwise moment on the right side = Force × distance
Force = 2/5 x 7 = 2.8 N
Distance from the center of gravity = 10 cm or 0.10 m away.
the clockwise moment on the right side due to the board = 2.8 x 0.1 = 0.28.
The moment due to the box with a weight of 2kg at a distance of x meters will be:
the total clockwise moment on the right side = 0.28 + 2x.
When the board is just about to tilt:
0.63 = 0.28 + 2x
2x = 0.63 - 0.28
x = 0.175m or 17.5cm
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an electric device delivers a current of 3 a to a device. how many electrons flow through this device in 7 s? ( e
1.35625x10²⁰ e. Flow through the device in a time of 7 seconds.
Electric current: It is the amount of electric charge that flows each unit of time. Electric current can also be a ratio between voltage and resistance
Electric current occurs due to the movement of electrons due to the difference in potential or voltage (from high potential to low potential) between two points
Electrons will flow through the conducting wire that functions as a conductor. Electric current itself can be divided into direct current (DC) or alternating current (AC)
Can be formulated:
[tex]I=\frac{Q}{t}-------------(1)[/tex]
Where
I define the electric current, Ampere (A)
Q is the electric charge, coulomb (C)
t is time, seconds (s)
An electric device delivers a current of 3 A within 7 s, so the charge is:
Q = I x t
Q = 3 x 7
Q = 21 C
Because 1 electron (e) has a charge of 1.60 × 10⁻¹⁹ C, the total number of electrons flowing:
= [tex]\frac{21C}{1.60*10^-19C}[/tex]
= 1.31625x10¹⁹
N= 1.35625x10²⁰ e.
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Large stars can explode as they finish burning their nuclear fuel, causing a supernova. The explosion blows away the outer layers of the star. According to Newton’s third law, the forces that push the outer layers away have reaction forces that are inwardly directed on the core of the star. These forces compress the core and can cause the core to undergo a gravitational collapse. The gravitational forces keep pulling all the matter together tighter and tighter, crushing atoms out of existence. Under these extreme conditions, a proton and an electron can be squeezed together to form a neutron. If the collapse is halted when the neutrons all come into contact with each other, the result is an object called a neutron star, an entire star consisting of solid nuclear matter. Many neutron stars rotate about their axis with a period of ≈1s and, as they do so, send out a pulse of electromagnetic waves once a second. These stars were discovered in the 1960s and are called pulsars. A) Consider a neutron star with a mass equal to the sun, a radius of 19 km , and a rotation period of 1.0 s. What is the speed of a point on the equator of the star? Express your answer to two significant figures and include the appropriate units. B) What is g at the surface of this neutron star? Express your answer to three significant figures and include the appropriate units. C) A stationary 1.0 kg mass has a weight on earth of 9.8 N. What would be its weight on the star? Express your answer to three significant figures and include the appropriate units. D) How many revolutions per minute are made by a satellite orbiting 1.0 km above the surface? Express your answer to two significant figures and include the appropriate units. E) What is the radius of a geosynchronous orbit about the neutron star? Express your answer to three significant figures and include the appropriate units
A supermassive supergiant star with a total mass of between 10 and 25 solar masses is what is known as a neutron star.
Neutron Star
Neutron stars are the tiniest and densest class of stellar objects currently known, with the exception of black holes and other hypothetical phenomena. Neutron stars are roughly 10 kilometres (6 miles) in diameter and weigh 1.4 solar masses. They are the outcome of a large star's supernova explosion coupled with gravitational collapse, which reduces the core's density to that of atomic nuclei from white dwarf star density.
Once formed, they gradually cool down and stop actively producing heat, although they can still evolve further through collision or accretion. The majority of the fundamental theories for these things suggest that neutron stars are made almost entirely of neutrons. When certain conditions are met, normal matter's electrons and protons unite to form neutrons.
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large stars can explode as they finish burning their nuclear fuel, causing a supernova. the explosion blows away the outer layers of the star. according to newton’s third law, the forces that push the outer layers away have reaction forces that are inwardly directed on the core of the star. these forces compress the core and can cause the core to undergo a gravitational collapse. the gravitational forces keep pulling all the matter together tighter and tighter, crushing atoms out of existence. under these extreme conditions, a proton and an electron can be squeezed together to form a neutron. if the collapse is halted when the neutrons all come into contact with each other, the result is an object called a neutron star, an entire star consisting of solid nuclear matter. many neutron stars rotate about their axis with a period of ≈1s and, as they do so, send out a pulse of electromagnetic waves once a second. these stars were discovered in the 1960s and are called pulsars. A. Consider a neutron star with a mass equal to the sun, a radius of 19 km, and a rotation period of 1.0 s. What is the speed of a point on the equator of the star? B. What is g at the surface of this neutron star?
The acceleration caused by gravity is 1.2 x 1012 m/s2, while the speed of the star is 6.3 x 104 m/s.
(a) Assuming the star's radius (R) is 19 km, = 19 x 10^3 meters
Rotation Duration (T) = 1 s
The star's mass (m) is 1.98 x 10^30 kg.
The star's velocity is determined by (v) = 2πr/T, where
v = 2x3.14x19x 10^3/1 = 11.93 x10^4 m/s.
Consequently, the star's speed is 11.93 x 10^4 m/s
(b) We are aware that the gravitational acceleration can be calculated as follows:
g = Gm/r^2, where G is the gravitational constant and equals
6.67 * 10^11 x1.98 x 10^30/ (19 x 10^3)^2
g = 3.65x10^33 m/s2.
Gravitational acceleration is therefore equal to 3.65x10^33 m/s2.
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