Given:
Commutative law of addition.
[tex]6+5=5+6[/tex]2 only is the correct answer.
what is the product of 24.154 and 0.18
Answer:
4.34772
4.3 with the correct amount of sig figs but you don't really have to worry about that unless you've talked about it in class
Step-by-step explanation:
the product of two numbers is the result of those two numbers being multiplied. So, 24.154 * 0.18 = 4.34772
Write an equation in standard form for the line that passes through the given points.
(1, 2) and (5, 7)
The equation of the line in standard form is represented by - (5 / 3) · x + (4 / 3) · y = 1.
What is the equation of the line that passes through two points?
In this problem we must derive the equation of the line in standard form that passes through the two points. The standard form is described below:
a · x + b · y = 1
Then, we must solve for a and b to determine the coefficients of the line equation:
a + 2 · b = 1
5 · a + 7 · b = 1
By numerical methods, the solution to the system is:
a = - 5 / 3, b = 4 / 3
The equation in standard form - (5 / 3) · x + (4 / 3) · y = 1.
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Find the value of x and the length of ST
x = 13
The length of ST is 78
Explanation:ST and SR are tangents
From the diagram
ST = 9x - 39
SR = 6x
Note that:
Two tangents drawn from the same point external to a circle are equal
That is, ST = SR
9x - 39 = 6x
9x - 6x = 39
3x = 39
x = 39/3
x = 13
ST = 9x - 39
Suubstitute x = 13
ST = 9(13) - 39
ST = 117 - 39
ST = 78
1233558844+12254788-1255+77777
1,233,558,844 + 12,254,788 − 1,255 + 77,777
= 1,245,890,154
Answer:
1245890154 easy, lol
I know this wasn't a real question but if it was good luck, lol
What is the value of (-3)-4?
Answer:
-7
Step-by-step explanation:
-3-4=-7
:]
Answer:
-7
Step-by-step explanation:
180/9 as a whole number
Answer:
20
Step-by-step explanation:
180 ÷ 9 = 20
If one mini Hershey bar weighs 0.3 ounces how many mini candy bars would you have to eat to eat the same amount as a regular size Hershey bar that weighs 1.55 ounces?
Angle 1,7,3 and 5 all those angles has the same equivalent to the angle 5 angle 2 is supplementary to angle 1 so angle 2 is 30 degrees because 150+ 30 is 180 degrees and we use the same thing that I did in the first step that if angle number to is 30 angle 8,4 and 6 is going to be 30
Given:-
To find all angle values.
So from the given image. we get,
[tex]\begin{gathered} \angle5+\angle4=180 \\ \angle7+\angle4=180 \\ \angle7+\angle6=180 \\ \angle6+\angle5=180 \end{gathered}[/tex]Also,
[tex]\begin{gathered} \angle1=\angle7 \\ \angle2=\angle4 \\ \angle8=\angle6 \\ \angle3=\angle5 \end{gathered}[/tex]So now we know angle 5 is 150 degrees. so we get,
[tex]\begin{gathered} \angle5+\angle4=180 \\ 150+\angle4=180 \\ \angle4=180-150 \\ \angle4=30 \end{gathered}[/tex]So angle 4 is 30 degree.
Also,
[tex]\begin{gathered} \angle7+\angle4=180 \\ \angle7+30=180 \\ \angle7=150 \end{gathered}[/tex]So angle 7 is 150 degree.
Also,
[tex]\begin{gathered} \angle6+\angle5=180 \\ \angle6+150=180 \\ \angle6=30 \end{gathered}[/tex]So angle 6 is 30 degree.
So now we equate the values. so we get,
[tex]undefined[/tex]Find WZ if WX = 4a, XY = 28, YZ = 6a - 4 and XZ = 10a + 12
1) In this line segment, we can apply the the addition postulate to solve it and write:
WZ = WX +XY +YZ
10a +12 = (4a +28) +(6a - 4)
10a +12= 10a +24
0a = 12 No solution
2) Since this is a non-solution equation, then we can't solve for a and find the length of WZ
Can a table with same input and output be a function like in the picture:
Yes, because each value of x still corresponds to only one value of y.
Find the area of quadrilateral ABCD. [Hint: the diagonal divides the quadrilateral into two triangles.]A. 28.53 units²B. 26.47 units²C. 27.28 units²D. 33.08 units²
Answer
A. 28.53 units²
Explanation
Finding the area of irregular quadrilateral ABCD, we divide the given figure into shapes (two triangles) as shown below:
Then, we find the area of the two triangles.
Triangle ABD:
[tex]\begin{gathered} Area=\sqrt{s(s-a)(s-b)(s-c)} \\ \\ s=\frac{a+b+c}{2}=\frac{2.89+8.59+8.6}{2}=\frac{20.08}{2}=10.04 \\ \\ Area\text{ }of\text{ }triangle\text{ }ABD=\sqrt{10.04(10.04-2.89)(10.04-8.59)(10.04-8.6)} \\ \\ Area\text{ }of\text{ }triangle\text{ }ABD=\sqrt{10.04(7.15)(1.45)(1.44)} \\ \\ Area\text{ }of\text{ }triangle\text{ }ABD=\sqrt{149.889} \\ \\ Area\text{ }of\text{ }triangle\text{ }ABD=12.24\text{ }unit^2 \end{gathered}[/tex]Triangle ADC:
[tex]\begin{gathered} Area=\sqrt{s(s-a)(s-b)(s-c)} \\ \\ s=\frac{a+b+c}{2}=\frac{4.3+7.58+8.6}{2}=\frac{20.48}{2}=10.24 \\ \\ Area\text{ }of\text{ }triangle\text{ }ADC=\sqrt{10.24(10.24-4.3)(10.24-7.58)(10.24-8.6)} \\ \\ Area\text{ }of\text{ }triangle\text{ }ADC=\sqrt{10.24(5.94)(2.66)(1.64)} \\ \\ Area\text{ }of\text{ }triangle\text{ }ADC=\sqrt{265.346} \\ \\ Area\text{ }of\text{ }triangle\text{ }ADC=16.29\text{ }unit^2 \end{gathered}[/tex]Therefore, the area of the quadrilateral ABCD = the Sum of the two triangles
The area of the quadrilateral ABCD = 12.24 units² + 16.29 units² = 28.53 units²
when trying to find the probability of rolling a number four on a number cube with the number 1 through 6 how many desired outcomes are there
ANSWER
One desired outcome
EXPLANATION
We are trying to roll the number 4 on a number cube with numbers 1 through 6.
Since we are only trying to get one outcome/result from the experiment (4), there is only one desired outcome.
The answer is 1.
Evaluate (2 +40) : 2 when z = 8 answer A 8 B 5C 6D 48
1) Let's solve the equation given the condition
[tex]\frac{\mleft(x+40\mright)}{2^3}\Rightarrow\frac{(8+40)}{8}\Rightarrow\frac{48}{8}=6[/tex]After plugging into the equation, all that's left is to solve it with the PEMDA order of operation.
2) So the answer is C
At many bakeries, there are deals that if you buy twelve donuts, you get a thirteenth one at a discount. Sometimes "13" items is called a baker's dozen. I One store is advertising: Donuts! $1.05 individually, or $13 per baker's dozen. They want to program their cash register to be able to show the exact price for any number of donuts. You will help them by producing a data table, a graph and an algorithm. You will: 1. Fill in and expand the data table 2. Make a scatter plot to show the pattern visually. This means to plot an (x,y) point for every row in the data table. For example the first point can be (1, 1.05) 3. Develop an algorithm to find the cost for any number of donuts. Note: An algorithm is like a set of instructions to solve a problem. They are useful for telling computers or people exactly how to do something. For example, here is an algorithm that finds 15% of a number: Step 1: take any number, callit N.
Table
Number of donuts Price
1 $1.05
2 $ 2.1
3 $3.15
4 $4.2
5 $5.25
6 $6.3
10 $10.5
slope = (10.5 - 1.05) / 10 - 1
= 9.45 / 9
= 1.05
Equation
y - 10.5 = 1.05 (x - 10)
y = 1.05x - 10.5 + 10.5
y = 1.05x
For 40 donuts
y = 1.05(40)
y = $42
X-2y=5 and 2x+3y=10
Hello!
Let's set up some things:
[tex]x-2y=5[/tex] <-- equation 1
[tex]2x+3y = 10[/tex] <-- equation 2
________________
(equation 1) multiplied by 2
[tex]2x - 4y=10[/tex] <-- equation 3
________________
(equation 2) - (equation 3)
7y = 0
y = 0 <-- equation 4
________________
(equation 4)'s value of y into (equation 1)
[tex]x-2(0) = 5\\x = 5[/tex]
Thus x = 5 and y = 0
Hope that helps!
One bag of rice that weighs 3.5 pounds will have enough rice if a recipe calls for 54 ounces of rice. (1 pound = 16 ounces) (3 points)
One bag of rice that weighs 3.5 pounds will have enough rice for the recipe if a recipe calls for 54 ounces of rice . the given statement is True .
In the question ,
it us given that
weight of one bag of rice = 3.5 pounds
given that ,
1 pound [tex]=[/tex] 16 ounces
So, we need to convert 3.5 pounds to ounces first .
we have 3.5 pounds = 16×3.5 ounces
= 56 ounces .
So , yes there will be enough rice for the recipe as only 54 ounces are needed and we have 56 ounces , that is 2 extra ounces of rice .
Therefore , "One bag of rice having weight 3.5 pounds ,will have enough rice for the recipe if a recipe calls for 54 ounces of rice" . the given statement is True .
The given question is incomplete , the complete question is
One bag of rice that weighs 3.5 pounds will have enough rice if a recipe calls for 54 ounces of rice. (1 pound = 16 ounces) . The given statement is TRUE or FALSE ?
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can somebody please help me with this question
Carina has a piece of wire that is 301cm long . She bends the wire to make 6 shapes of the same perimeter . She has 97cm of wire left . What is the perimeter of each shape ?
Answer:
34
Step-by-step explanation:
301 - 97 = 204
204 / 6 = 34
54 is the product of 3 and Janelle's age
Write an equation in point-slope form for the line that passes through the given points.
(-4,7). (6.3)
Answer:
[tex]y=-\frac{2}{5}x+5.4[/tex]
Step-by-step explanation:
Step 1: plot points
Step 2: find the RISE/RUN (-4/10 or -2/5)
Step 3: find where it intersects the y axis (5.4)
y=mx+b where x and y are varables, m is the slope, and b is the y-int
[tex]y=-\frac{2}{5}x+5.4[/tex]
Hope that helps
For each table, determine whether it shows a direct variation.If it does, write its direct variation equation.Not direct variationNot direct varlationXхyу41N1Direct variationEquation:51.2542Direct variationEquation:I78.75105The
For the right table , y/x = constant = k = 0.5
HELP
QUICKOU#FR{PIEWuf'oieud'f'doifu
Apply the Pythagorean Theorem. The Pythagorean Theorem states that in a right triangle, a^2 + b^2 = c^2 where c is the hypotenuse.
a^2 + b^2 = c^2
8^2 + 5^2 = c^2
64 + 25 = c^2
89 = c^2
√89 = √c^2
c = √89
A police car traveling south toward Sioux Falls, Iowa, at 160 km/h pursues a truck traveling east away from Sioux Falls at
140 km/h.
At time t = 0, the police car is 60 km north and the truck is 50 km east of Sioux Falls.
Calculate the rate at which the distance between the vehicles is changing at t = 10 minutes.
(Use decimal notation. Give your answer to three decimal places.)
Using the Pythagorean Theorem, the rate at which the distance between the vehicles is changing at t = 10 minutes is of -20 km/hour.
What is the Pythagorean Theorem?The Pythagorean Theorem relates the length of the legs [tex]l_1[/tex] and [tex]l_2[/tex] of a right triangle with the length of the hypotenuse h, stating that the hypotenuse squared is the sum of the legs squared, according to the equation given below:
[tex]h^2 = l_1^2 + l_2^2[/tex]
In the context of this problem, the distances of the cars from Sioux Falls, considering the initial distances and the velocities, are given as follows:
Police: P(t) = 60 - 160t.Truck: T(t) = 50 + 140t.The distance after t hours is the hypotenuse of a right triangle in which the legs are the functions, hence:
D²(t) = P²(t) + T²(t).
Hence the rate of change of the distance after t hours is:
2D'(t) = 2P'(t) + 2T'(t)
Simplifying by 2:
D'(t) = P'(t) + T'(t).
Applying the exponent rules, the derivatives are given as follows:
P'(t) = -160.T'(t) = 140.Hence the constant rate is:
D'(t) = -160 + 140 = -20 km/hour.
Meaning that the police car is getting 20 km closer to the truck each hour.
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Find an angle e in the interval [0°, 90°) that satisfies each statement. Give answer to the nearest TENTH of a degree. a) sin= 0.3697 degrees b) cos= 0.7265 degrees degrees c) sec= 2.3232 degrees d) csc= 1.1234
first at all, we are gonna solve this using inverse trigonometric functions
like this:
[tex]\begin{gathered} \sin \alpha\text{ = x} \\ \alpha\text{ = }\sin ^{-1}x \end{gathered}[/tex]for the first case:
a)
[tex]\begin{gathered} \sin \alpha\text{ = }0.3697 \\ \alpha=\sin ^{-1}(0.3697) \\ \alpha=21.697\ldots \\ \alpha\cong20 \end{gathered}[/tex]b)
[tex]\begin{gathered} \cos \alpha\text{ = }0.7265 \\ \alpha=\cos ^{-1}(0.7265) \\ \alpha=43.406\ldots \\ \alpha\cong40 \end{gathered}[/tex]c)
In this case, we are going to use the following trigonometric identity:
[tex]\begin{gathered} \sec \alpha=\frac{1}{\cos \alpha} \\ \end{gathered}[/tex]later,
[tex]\begin{gathered} \sec \alpha=2.3232 \\ \frac{1}{\cos \alpha}=2.3232 \\ \cos \alpha=\frac{1}{2.3232} \\ \alpha=\cos ^{-1}(\frac{1}{2.3232}) \\ \alpha=64.504\ldots \\ \alpha\cong60 \end{gathered}[/tex]d)
In this case, we are going to use the following trigonometric identity:
[tex]\begin{gathered} csc\alpha=\frac{1}{sin\alpha} \\ \end{gathered}[/tex]later,
[tex]\begin{gathered} \csc \alpha=1.1234 \\ \frac{1}{sin\alpha}=1.1234 \\ \sin \alpha=\frac{1}{1.1234} \\ \alpha=\sin ^{-1}(\frac{1}{1.1234}) \\ \alpha=62.892\ldots \\ \alpha\cong60 \end{gathered}[/tex]finally, those are your answers.
Part 1: Factorial!2. Explain the steps that you took to calculate it on your calculator.
Given:
a factorial 14! is given
Find:
we have to evaluate the given factorial
Explanation:
we know, the factorial 14! is calculated as following
14! = 14 × 13 × 12 × 11 × 10 × 9 × 8 × 7 × 6 × 5 × 4 × 3 × 2 × 1
14! = 87178291200
or
14! = 8.71783E10
Please help with this question pl
The missing reason 6 of the two column proof that m∠Z = 65° is; Substitution
How to carry out two column proof?The two column proof is as follows;
Statement 1: XYZ is a triangle
Reason 1; Given
Statement 2: m∠x + m∠y + m∠z = 180°
Reason 2: Postulate
Statement 3: m∠y = 50°
Reason 3: Given
Statement 4: ∠X ≅ ∠Z
Reason 4: Given
Statement 5: m∠X = m∠Z
Reason 5: Congruency
Statement 6: m∠Z + m∠Z = 180°
Reason6: Substitution
Statement 7: m∠Z + m∠Z = 130°
Reason 7: ?
Statement 8: 2(m∠Z) = 130°
Reason 8: Algebra
Statement 9: m∠Z = 65°
Reason 9: Division property of equality
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help me with the last question pleaseeeeeeeeeeeeeee
Answer:
Answer:
d
Step-by-step explanation:
The number of years must be non-negative.
This eliminates all of the options except for d.
Enter the corredeach column.4. Madam Malkin owns Madam Malkin's Robes for AllOcassions which is a clothing store. She has abudget of $6000 to restock 200 clothing items.She can buy Hogwarts shirts for $12 each, Robes for$24 each, and Quidditch shirts for $36 each. If shewants to have twice as many Quidditch shirts asRobes, how many of each type of shirt should shebuy?11)223HOW MANY QUIDDITCH SHIRTS DID MADAMMALKIN BUY?445
Let's define some notation first:
H= number of Hogwarts, R= number of robes, Q= number of Quidditch
We can set up the following equation for the total of clothing items:
[tex]H+R+Q=200[/tex]We also know that Q= 2R so we have:
[tex]H+3R=200[/tex]Now we can create an equation for the amount of money and we have:
[tex]12H+24R+36Q=6000[/tex][tex]12H+96R=6000[/tex]Now we can replace H=200-3R and we got:
[tex]12(200-3R)+96R=6000[/tex]And solving for R we got:
[tex]60R=3600[/tex][tex]R=\frac{3600}{60}=60[/tex]And then Q would be:
[tex]Q=2R=120[/tex]Is w = 12 a solution to the inequality below?
Answer:
No
Step-by-step explanation:
No, it is not a solution. You can find this answer by plugging in 12 for 2 for w.
0>12-132/12
132/12=11
12-11=1
0>1
0 is not greater than 1, so the answer is no.
Please find it if needed.-The Area of a Rectangle-The Area of a Triangle-The Area of a Square-Or The Area of a Circleand find the area of the composite figure (andplease put the areas separate)FIND THE AREA OF THE SHADED REGION
First find the area of the rectangle
A = l*w = 9*16 = 144
The unshaded area is a trapezoid
A = 1/2 ( b1+b2) *h = 1/2 ( 5+11) * 4 = 1/2 (16) * 4 =32
The area of the shaded region is
rectangle - trapezoid
144-32
112cm^2
Answer:
112cm²
Step-by-step explanation:
First, let us find the area of the rectangle.
Area = length × width
Area = 16 cm × 9 cm
Area = 144 cm²
Now, let us find the area of the trapezium.
Area = 1/2 ( Sum of the parallel sides ) × height
Area = 1/2 × ( 11 + 5 ) × 4
Area = 1/2 × 16 × 4
Area = 32 cm²
Area of the shaded region.
To find the area of the shaded region, subtract the area of the rectangle from the area of the trapezium.
Area = 144cm² - 32cm²
Area = 112cm²