Answer:
D. Provides higher resolution images
Explanation:
The advantages gained by the use of digital data transmission instead of analog transmission are;
1) Noise do not damage digital signal transmission but they impact on analog signals. Digital signals are therefore more secure than analog signals
2) The bandwidth required for digital signal transmission is much less than the bandwidth required for analog
3) Digital signal allow data transmission to very long distance
4) The rate of transmission with digital signals is higher with digital signals
5) Digital signals allow easy and cost effective methods by which they are replicated
The resolution of an image is a measure of the amount of pixels displayed per inch of the image, such that a high resolution image has more pixel per inch of the image. It is therefore a factor determined at the source of the image based on how much detail is required in an image before transmission
Is all the biomass consumed by a primary consumer, such as a brine shrimp, transferred to the secondary consumer, such as a gull, when the brine shrimp is eaten? For instance, if a brine shrimp eats 10 g of algae in its life before the gull eats it, does the gull get 10 g of biomass when it eats the brine shrimp? Why or why not?
Which weighs more, a ton of bricks or
a ton of feathers? Which has more pieces in it?
Explain How you know.
Answer:
They equal the same
Explanation:
Because A ton of feathers and A ton of bricks. They both equal A ton.
Which of the following best describes asexual reproduction?
it produces offspring with a large amount of genetic variation
it occurs in simple organisms, such as bacteria, but not in multicellular organism such as plants and animals
it allows species to quickly adapt to environmental changes
it can be an advantage to organisms that live in a stable unchanging environment
Answer:
First Choice
it produces offspring with a large amount of genetic variation
Answer: i think this is correct.
Explanation: it occurs in simple organisms, such as bacteria, but not in multicellular organism such as plants and animals
How many representative particles are there in 10.43g of sugar (C12H22011)?
Answer:
10.43 / 342 × 6.02 × 10 ^23 = 18.34 × 10^ 21
what is the variable for the quantity of heat in a system?
Answer:
The heat capacity is the amount of heat, expressed usually in Joules or calories, needed to change the system by 1 degree Celsius. The specific heat capacity is the amount of heat required to raise 1 gram of a substance by 1 degree Celsius.
Explanation:
For example, the specific heat of H2O(l) is 4.18 J/g ° C.
The Himalayan mountain range of India was formed at a ____.
A) convergent boundary
B) divergent boundary
C) hot spot
D) transform boundary
Answer:
its answer is b
Explanation:
divergent boundary
Tritium (hydrogen-3) has a half-life of 12.3 years. How old is a bottle of wine if the tritium content is determined to be 25% in new bottle of wine
Answer:
24.6 years
Explanation:
Applying,
A = (A')[tex]2^{a/n}[/tex]..................... Equation 1
Where A = Original Tritium content in the wine, A' = Tritium content in the wine after decay, a = age of the old bottle, n = half life of Tritium
From the question,
Let A = X, therefore, A' = 0.25X
Given: n = 12.3 years
Substitute these values into equation 1
X = 0.25X([tex]2^{a/n}[/tex])
1 = 0.25×([tex]2^{a/12.3}[/tex])
1/0.25 =
4 = [tex]2^{a/12.3}[/tex]
[tex]2^{a/12.3}[/tex] = 2²
Equation the base,
a/12.3 = 2
a = 12.3×2
a = 24.6 years
17. A scientist determines an unknown metallic sample to have 77 protons and 77 electrons with a mass number of 192. How many neutrons does one
metal atom contain?
Answer:
Ok so hot u hahaha
Explanation:
Hshshhdhdi jsushshshshshhdhdhd hshshshshsh hdhdhdhd hdhdhdhd hdhdh
ANSWER THIS QUESTION FOR 29 POINTS
List several examples of what cells do all day?
I NEED HELP HELP ASAP
Answer:
Explanation:
cells process rna and trna
converting food into energy
the regrowth of cells that have died through out the day
the transcription of dna to rna
hope this helped :)
Study the particle below carefully and answer
the questions that followed.
a)ldentify the particle.
b)Write the electronic configuration of the
particle.
c)State
i.Atomic number
ii.Mass number
iii.Proton number
iv.Electron number
d) Calculate the neutron number
e) State the valency
f)What is the valence electrons?
Answer:
b is the answer hope that helps
Write a chemical equation for the following reaction. (Type your answer using format CH4 for CH4.) In water, iron(III) chloride reacts with sodium hydroxide, producing solid iron(III) hydroxide and sodium chloride.
Answer:
FeCl3(aq) -
3NaOH(aq) 0 Fe(OH)3(s) -
3NaCl(aq)
Explanation:
FeCl3(aq) -
3NaOH(aq) 0 Fe(OH)3(s) -
3NaCl(aq)
Write a quick summary about what we learned about Radioactive Decay. Be sure to include: 1). Structrue of an atom's nucleus 2). Three Types of radioactive decay and what happens with them.
Answer:
Radioactive decay refers to the release of radiation from the nuclei.
Explanation:
Radioactive decay also known as nuclear decay is a type of process in which an unstable atomic nucleus loses energy by radiation. Alpha decay, beta decay, and gamma decay are the three of the most common types of decay, which emitting one or more particles or photons from the unstable nuclei of radioactive atom. Beta decay occurs due to weak force, while the alpha and gamma decay happens due to electromagnetic and strong forces.
1. Predict what will happen when the plastic bag is let go.
Answer:
If its windy it will fly away. If its not windy I think it will float down to the ground
Explanation:
When 1 mol of methane is burned at constant pressure, −890 kJ/mol of energy is released as heat. If a 1.67 g sample of methane is burned at constant pressure, what will be the value of ∆H
Answer:
[tex]\Delta H=-92.7kJ[/tex]
Explanation:
Hello there!
In this case, according to the given information, we can infer that 890 kJ of energy are released when 1 mole of methane is burned; however, to find the total heat when 1.67 grams are burned, we first need to calculate the moles in this mass of methane:
[tex]1.67gCH_4*\frac{1molCH_4}{16.04gCH_4}=0.104molCH_4[/tex]
And thus, for calculating the resulting ∆H, we proceed as follows:
[tex]\Delta H=-890kJ/mol*0.104mol\\\\\Delta H=-92.7kJ[/tex]
Regards!
HELP PLEASE I DONT KNOW WHAT THIS MEANS IM CONFUSED
Explanation:
In an alpha emission, an alpha particle is ejected from a large nucleus. An alpha particle is simply a helium nucleus (atomic number is 2 and mass number is 4) so that means that the atomic number of the emitting nucleus decreases by 2 and its mass number decreases by 4.
Which emission causes the atomic number of a nuclide to decrease by 2 and its mass number to
decrease by 4?
1.
an alpha particle
2.
a beta particle
3.
gamma radiation
4.
a positron
An alpha particle emission causes the atomic number of a nuclide to decrease by 2 and its mass number to decrease by 4.
What is nuclear emission?Nuclear Emission explains the release of energy stored in the nucleus of an atom in the form of particles like alpha particles, beta particles, gamma ray etc.
When a nucleus emits an alpha particle, it loses 2 protons and 2 neutrons, so its atomic number decreases by 2 and its mass number decreases by 4.
Hence, option 1 is correct.
Learn more about alpha particles here:
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What is a zirconium, in your own words but be more detailed.What is a zirconium, in your own words but be more detailed.
Answer:
Zirconium is a silver-gray transition metal, a type of element that is malleable and ductile and easily forms stable compounds. It is also highly resistant to corrosion. It is commonly used in corrosive environments. Zirconium alloys can be found in pipes, fittings, and heat exchangers, according to Chemicool.
Explanation:
Answer: Today this element is widely used, as zircon, as Zirconium oxide and as the metal itself. Zirconium is to be found in ceramics, foundry equipment, glass, chemicals, and metal alloys. Zircon sand is used for heat-resistant linings for furnaces, for giant ladles for molten metal, and to make foundry moulds.
Explanation: Hope it help I think
a gas with a volume of 20.0l at a pressure of 275 kpa is allowed to expand to a volume of 35.0l. what is the pressure in the container if the temperature remains constant?
1. 2.54 kPa
2. 157 kPa
3. 481 kPa
pls help ;(
Answer:
[tex]\boxed {\boxed {\sf 2. \ 157 \ kPa}}[/tex]
Explanation:
Since temperature remains constant, the only variables that change are volume and pressure. Therefore, we are using Boyle's Law. This states that the pressure is inversely proportional to the volume. The formula is:
[tex]P_1V_1=P_2V_2[/tex]
We know the gas starts with a volume of 20.0 liters at a pressure of 275 kPa. We can substitute these values into the left side of the formula.
[tex]275 \ kPa *20.0 \ L=P_2V_2[/tex]
We know the gas expands to a volume of 35.0 Liters, but we do not know the pressure.
[tex]275 \ kPa *20.0 \ L=P_2* 35.0 \ L[/tex]
Since we are solving for the new pressure, we must isolate the variable P₂. It is being multiplied by 35.0 Liters and the inverse of multiplication is division. Divide both sides by 35.0 L.
[tex]\frac {275 \ kPa * 20.0 \ L}{ 35.0 \ L}= \frac{P_2*35.0 \ L}{35.0 \ L}[/tex]
[tex]\frac {275 \ kPa * 20.0 \ L}{ 35.0 \ L}=P_2[/tex]
The units of liters cancel.
[tex]\frac {275 \ kPa * 20.0 }{ 35.0 }=P_2[/tex]
[tex]\frac {5500}{35.0} \ kPa= P_2[/tex]
[tex]157.142857 \ kPa=P_2[/tex]
The original measurements of pressure and volume have 3 significant figures, so our answer must have the same. For the number we calculated, that is the ones place.
The 1 in the tenths place (157.142857) tells us to leave the 7 in the ones place.
[tex]157 \ kPa= P_2[/tex]
If the gas expanded to a volume of 35.0 liters while the temperature remained constant, the pressure in container was approximately 157 kilopascals.
4.
The relationship between how much mass matter has in a given volume is called
A. density
O
B. boiling point
C. melting point
O
D. weight
[tex]\huge{ \mathrm{ \underline{ Answer }\: \: ✓ }}[/tex]
The relationship between mass of matter per unit volume is known as :
[tex] \large \boxed{ \mathrm{density}}[/tex]
_____________________________
[tex]\mathrm{ ☠ \: TeeNForeveR \:☠ }[/tex]
Calculate the amount, in mol, of sodium atoms represented by 1.0x10(to the power of 20) sodium atoms
Explanation:
moles= number of particle or atom / 6.02×10^23
so
[tex] \frac{1.1 \times {10}^{20 } }{6.02 \times {10}^{23} } [/tex]
gives u 1.83×10^-4 moles
hope it make sense :)
Answer:
1.7 * 10^-4 moles
Explanation:
According to Avogadro, one mole of a substance contains 6.02 * 10^23 number of atoms, molecules, ions etc.
Hence;
1 mole of Na contains 6.02 * 10^23 atoms
x moles of Na contains 1.0x10^20 atoms
x = 1.0x10^20 * 1/6.02 * 10^23
x = 1.7 * 10^-4 moles
How many liters of F2 do you have if you are given 100 grams of F2?
please mark all that apply!
Answer:
F G there you go the guy on top is right
Explanation:
F G
How many moles are in a 28.35 g sample of CaCO3?
Answer:
0.2832 moles
Explanation:
mole = mass/ molar mass
mole= 28.35/100.08
mole=0.2832
Which of the following phase changes describes what is
happening in the following endothermic process?
H20 (1) + heat --> H2O (g)
O melting
o freezing
o boiling
O condensing
Answer:
I think the answer is boiling
A container of oxygen gas is at STP. If this sample is put into an oven at 280 C, what would its pressure be, in atmospheres?
Explanation:
Step 1:
Data obtained from the question. This include the following:
Initial pressure (P1) = 1atm
Initial temperature (T1) = 0°C = 0°C + 273 = 273K
Final temperature (T2) = 280°C = 280°C + 273 = 553K
Final pressure (P2) =...?
Step 2:
Determination of the new pressure of the gas.
Since the volume of the gas is constant, the following equation:
P1/T1 = P2/T2
will be used to obtain the pressure. This is illustrated below:
P1/T1 = P2/T2
1/273 = P2 / 553
Cross multiply
273x P2 = 553
Divide both side by 273
P2 = 553/273
P2 = 2.03atm
Therefore, the new pressure of the gas will be 2.03atm
Answer:
[tex]\boxed {\boxed {\sf P_2=2.03 \ atm}}[/tex]
Explanation:
We are concerned with the variables of temperature and pressure, so we use Gay-Lussac's Law, which states the temperature of a gas is directly proportional to the pressure. The formula is:
[tex]\frac{P_1}{T_1}=\frac{P_2}{T_2}[/tex]
We know that the container of gas begins at standard temperature and pressure (STP). This is 1 atmosphere of pressure and 273 Kelvin.
[tex]\frac { 1 \ atm}{ 273 \ K} = \frac{P_2}{T_2}[/tex]
We know the gas is put into an oven at 280 degrees Celsius. We can convert this to Kelvin.
K= °C + 273.15 K= 280 +273.15K= 553.15[tex]\frac { 1 \ atm}{ 273 \ K} = \frac{P_2}{553.15 \ K}[/tex]
We are solving for the new pressure, so we must isolate the variable P₂. It is being divided by 553.15 Kelvin. The inverse of division is multiplication, so we multiply both sides by 553.15 K
[tex]553.15 \ K *\frac { 1 \ atm}{ 273 \ K} = \frac{P_2}{553.15 \ K} * 553.15 \ K[/tex]
[tex]553.15 \ K *\frac { 1 \ atm}{ 273 \ K}= P_2[/tex]
The units of Kelvin cancel.
[tex]553.15 *\frac { 1 \ atm}{ 273 }= P_2[/tex]
[tex]2.02619047619 \ atm = P_2[/tex]
Rounded to the nearest hundredth:
[tex]2.03 \ atm \approx P_2[/tex]
The new pressure is approximately 2.03 atmospheres.
fuerza que ejerce el planeta tierra sobre los cuerpos que en ella se encuentran. Fuerza de distancia Fuerza de Contacto
Answer:
Ver explicacion
Explanation:
La gravedad es una fuerza que actúa a distancia. La fuerza que actúa entre la tierra y los cuerpos en ella es la fuerza gravitacional.
Es un ejemplo típico de una fuerza de acción a distancia.
Por lo tanto, la fuerza tat que existe entre la tierra y los cuerpos que se encuentran en ella es una fuerza de distancia.
To calculate the work that an object does when it moves covering a distance of 3000 meters when it is propelled by a force of 65 Newton, one of the principles of mechanics must be considered.
Physical principle of mechanicsA force does work when there is a displacement of the center of mass of the body on which the force is applied, in the direction of said force.
The work of the force on that body will be equivalent to the energy necessary to displace it, so that:
W = F.d
Force CalculationSubstituting the corresponding values in said formula:
F = 65N
d = 3000m
W = 65 N. 3000 m
W = 195000 W
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ΔU for a van der Waals gas increases by 475 J in an expansion process, and the magnitude of w is 93.0 J.
Complete question:
ΔU for a van der Waals gas increases by 475 J in an expansion process, and the magnitude of w is 93.0 J. calculate the magnitude of q for the process.
Answer:
The magnitude of q for the process 568 J.
Explanation:
Given;
change in internal energy of the gas, ΔU = 475 J
work done by the gas, w = 93 J
heat added to the system, = q
During gas expansion process, heat is added to the gas.
Apply the first law of thermodynamic to determine the magnitude of heat added to the gas.
ΔU = q - w
q = ΔU + w
q = 475 J + 93 J
q = 568 J
Therefore, the magnitude of q for the process 568 J.
The theory of plate tectonics is supported by data collected by scientists. One piece of data includes that earthquakes tend to occur*
a.along plate boundaries
b.along mountain ranges
c.along the banks of rivers
d.along the boundaries of glaciers
Answer:
is that a letter a
Explanation:
that is my answer
Anthony needs to make a solution with a concentration of 2.5m. He begins with 2.0 iters and a 8.0M solution. What final volume does he need. Tally and solve.
Answer:
The final volume is 6.4 L.
Explanation:
Dilution is reducing the concentration of a chemical and is achieved by adding more solvent to the same amount of solute. In other words, dilution is the procedure that is followed to prepare a less concentrated solution from a more concentrated one, and it simply consists of adding more solvent.
In a dilution the amount of solute does not vary, and as only more volume (and mass) of solvent is being added, the concentration of the solute decreases.
In a dilution the expression is used:
Ci*Vi = Cf*Vf
where:
Ci: initial concentration Vi: initial volume Cf: final concentration Vf: final volumeIn this case:
Ci: 8 M Vi: 2 L Cf: 2.5 M Vf: ?Replacing:
8 M* 2 L= 2.5 M* Vf
Solving:
[tex]Vf=\frac{8 M* 2 L}{2.5 M}[/tex]
Vf=6.4 L
The final volume is 6.4 L.
What are three advantages of renewable energy?