Answer:
I think it's light year but there shouldn't be also km/s but km/h
A vertical spring with a spring constant of 420 N/m is mounted on the floor. From directly above the spring, which is unstrained, a 0.15-kg block is dropped from rest. It collides with and sticks to the spring, which is compressed by 3.7 cm in bringing the block to a momentary halt. Assuming air resistance is negligible, from what height above the compressed spring was the block dropped
Answer:
19.53 cm
Explanation:
The computation of the height is as follows:
Here we applied the conservation of the energy formula
As we know that
P.E of the block = P.E of the spring
m g h = ( 1 ÷ 2) k x^2
where
m = 0.15
g = 9.81
k = 420
x = 0.037
So now put the values to the above formula
(0.15) (9.81) (h) = 1 ÷2 × 420 × (0.037)^2
1.4715 (h) = 0.28749
h = 0.19537 m
= 19.53 cm
What is not the ideal location for a radioactive waste storage facility?
A.
in an area that already has a lot of background radiation
B.
in an area that has few earthquakes
C.
far away from ground water
D.
in an area that is unpopulated with people
Answer:
D
Explanation:
what happens when water at 4° celsius is heated further?
Answer:
please give me brainlist and follow
Explanation:
4 degrees C turns out to be the temperature at which liquid water has the highest density. If you heat it or cool it, it will expand. ... Ice floats on top of lakes, preventing evaporation (and convection in the frozen layer), and lakes stay liquid underneath, allowing fish and other life to survive.
Momentum
Project: Egg Drop
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Answer:
get egg and try to make in not crack when it falls by exerting the momentum of the fall into something other than the egg ex. make a box full of bubble wrap and put your egg in it
Explanation:
What is the chemical formula for the molecule modeled?
Answer:
What is the chemical fórmula For the molecule modeled?
Explanation:
C6H12O2
Bonnie has 16 coins in her pocket worth $1.50. What are two different combinations of coins she could have in her pocket?
How are nuclear reactions used to meet the world’s energy needs?
Both fusion and fission are used to generate electricity, but more fission reactors than fusion reactors are in use.
Fission reactors are used to generate electricity, but fusion is not yet practical enough to be used.
Both fusion and fission are used to generate electricity, but more fusion reactors than fission reactors are in use.
Fusion reactors are used to generate electricity, but fission is not yet practical enough to be used.
Answer:
Fission reactors are used to generate electricity, but fusion is not yet practical enough to be used
Explanation:
The nuclear fission process a nucleus of a 235U heavy atom is bombarded with neutrons and disintegrates into two smaller nuclei, releasing some neutrons and energy, which can be used to generate electricity.
In the process of nuclear fusion the union of light nuclear produces heavier nuclei, this process is still in the experimental phase and there are no commercial reactors for the production of electricity.
Checking the different statements is correct :
Fission reactors are used to generate electricity, but fusion is not yet practical enough to be used
Nuclear fission reactors are used to generate electricity, but fusion is not yet practical enough to be used.
What are nuclear reactions?Nuclear reactions are reactions which involves changes in the nucleus of atoms which produces large amounts of energy known as nuclear energy.
The two types of nuclear reactions are:
Nuclear fusion andNuclear fissionNuclear fission reactors are used to generate electricity, but fusion is not yet practical enough to be used.
Therefore, nuclear reactions produce energy by means of fission reactions.
Learn more about nuclear reactions at: https://brainly.com/question/984564
#SPJ3
what does loudness of a sound depend on?
Answer:
Amplitude
Explanation:
The loudness of a sound depends on the amplitude of vibration producing the sound
Application question: In Lancaster county, Pennsylvania, it is common for members of the Amish community to use windmills to pump water from underground to fill a tank for drinking water. The wind causes the turbine blades to spin, rotating a shaft, which is transferred through some gears to operate a pump, which pumps water up from deep below the ground to fill an above ground tank. Identify the energy conversions happening at each step below.
Wind blows______causing the turbine to turn, rotating shaft works pump_____energy.
Motion of water moving up from well______energy.
Water in tank which is positioned 5 feet above the ground level______potential energy.
Answer:
Wind blows__wind energy ____causing the turbine to turn, rotating shaft works pump__mechanical___energy.
Motion of water moving up from well___kinetic energy___energy.
Water in tank which is positioned 5 feet above the ground level______potential energy
Explanation:
Wind has in it wind energy which is then used to rotate the turbine shaft which is a form of mechanical work and hence possess mechanical energy
Moving water posses kinetic energy and when this water is kept at some height it possess potential energy
On a roller coaster, riders can experience a force of up to 4 g. What is the
maximum acceleration of the roller coaster?
O A. 51.7 m/s2
B. 39.2 m/s2
O C. 58.4 m/s2
O D. 45.6 m/s2
SUBMIT
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I hope this helped!+*
Explain the meaning of the constant of proportionality
Answer:
The constant of proportionality is the ratio between two directly proportional quantities. Two quantities are directly proportional when they increase and decrease at the same rate. The constant of proportionality k is given by k=y/x where y and x are two quantities that are directly proportional to each other.
Explanation:
what type of image does
a dilated and a Constricted
pupil produce?
Answer:blue
Explanation:
I read it
Consider a wheel (solid disk) of radius 1.12 m, mass 10 kg and moment of inertia 1 2 M R2 . The wheel rolls without slipping in a straight line in an uphill direction 37◦ above the horizontal. The wheel starts at angular speed 12.0536 rad/s but the rotation slows down as the wheel rolls uphill, and eventually the wheel comes to a stop and rolls back downhill. How far does the wheel roll in the uphill direction before it stops?
Answer:
d= 23.25 m
Explanation:
Assuming no other external forces acting on the disk, total mechanical energy must be conserved.Taking the initial height of the disk as the zero reference for the gravitational potential energy, initially. all the energy is kinetic.This kinetic energy is part translational kinetic energy, and part rotational kinetic energy, as follows:[tex]E_{o} = K_{transo} + K_{roto} (1)[/tex]
When the disk rolling uphill finally comes to an stop, its energy is completely gravitational potential energy, as follows:[tex]E_{f} = m*g*h (2)[/tex]
Since the angle with the horizontal of the track on which the disk is rolling, is 37º, we can express the height h in terms of the distance traveled d and the angle of 37º, as follows:[tex]h = d* sin 37 (3)[/tex]
Replacing (3) in (2):[tex]E_{f} = m*g* d * sin 37 (4)[/tex]
Since the wheel rolls without sleeping, this means that at any time there is a fixed relationship in the translational speed and the angular speed, as follows:[tex]v = \omega * R (5)[/tex]
For a solid disk, as mentioned in the question, the moment of inertia is just 1/2*M*R².The rotational kinetic energy of a rotating rigid body can be written as follows:[tex]K_{rot} = \frac{1}{2}* I * \omega^{2} (6)[/tex]
Replacing I from (6) and ω from (5), and remembering the definition of the translational kinetic energy, we can solve (1) in terms of v, m and r as follows:[tex]E_{o} = K_{transo} + K_{roto} = \frac{1}{2}* m* v^{2} +(\frac{1}{2}* \frac{1}{2}) *m*r^{2}*(\frac{v}{r}) ^{2} = \\ \frac{3}{4} * m * v^{2} (7)[/tex]
Since (4) and (7) must be equal each other, we can solve for d as follows:[tex]d =\frac{3}{4} * \frac{v^{2}}{g*sin37} = \frac{3}{4}*\frac{(\omega*r)^{2}}{g*sin 37} (8)[/tex]
Replacing by the values, we finally get:[tex]d =\frac{3}{4}*\frac{(\omega*r)^{2}}{g*sin 37} = \frac{3}{4} *\frac{(12.0536rad/sec*1.12m)^{2}}{9.8 m/s2*0.601} = 23. 25 m.[/tex]
A ball is thrown straight up from ground level. It passes a 2-m-high window. The bottom of the window is 7.5 m off the ground. The time that elapses from when the ball passes the bottom of the window on the way up, to when it passes the top of the window on the way back down is 1.3 s.
What was the ball’s initial speed, in meters per second?
Answer:
[tex]u=14.48m/s[/tex]
Explanation:
From the question we are told that:
Height of window [tex]h=2m[/tex]
Height of window off the ground [tex]h_g=7.5m[/tex]
Time to fall and drop [tex]t=1.3s[/tex]
Generally the Newton's equation motion is mathematically given by
[tex]s=ut+\frac{1}{2}at^2[/tex]
Where
[tex]h=ut+\frac{1}{2}at^2[/tex]
[tex]2=u1.3-\frac{1}{2}*9.8*1.3^2[/tex]
[tex]2=u1.3-8.281[/tex]
[tex]u=7.91m/s^2[/tex]
Generally the Newton's equation motion is mathematically given by
[tex]2as=v^2-u^2[/tex]
Where
[tex]-2gh_g=v^2-u^2[/tex]
[tex]-2*9.8*7.5=(7.91)^2-u^2[/tex]
[tex]-147=62.5681-u^2[/tex]
[tex]u=\sqrt{209.5681}[/tex]
[tex]u=14.48m/s[/tex]
Therefore the ball’s initial speed
[tex]u=14.48m/s[/tex]
Which of the following quantities are unknown? initial separation of the particles final separation of the particles initial speed of the proton initial speed of the alpha particle final speed of the proton final speed of the alpha particle mass of the proton mass of the alpha particle charge of the proton charge of the alpha particle Enter the letters of all the correct answers in alphabetical order. Do not use commas. For instance, if A, C, and D are unknowns, enter ACD.
ALL of the quantities are unknown, because you haven't bothered to tell us anything that's known.
Light with a wavelength of 700 nm (7×〖10〗^(-7) m) is incident upon a double slit with a separation of 0.30 mm (3 x 10-4 m). A screen is located 1.5 m from the double slit. At what distance from the screen will the first bright fringe beyond the center fringe appear?
Answer:
[tex]0.0035\ \text{m}[/tex]
Explanation:
y = Distance from the center point
d = Separation between slits = 0.3 mm
D = Distance between slit and screen = 1.5 m
[tex]\lambda[/tex] = Wavelength = 700 nm
m = Order = 1
We have the relation
[tex]d\dfrac{y}{D}=m\lambda\\\Rightarrow y=\dfrac{Dm\lambda}{d}\\\Rightarrow y=\dfrac{1.5\times 1\times 700\times 10^{-9}}{0.3\times 10^{-3}}\\\Rightarrow y=0.0035\ \text{m}[/tex]
The distance from the screen at which the first bright fringe beyond the center fringe appear is [tex]0.0035\ \text{m}[/tex].
pls help
What is the frequency range of UV light? Of infrared light?
Answer:
violet region (UV) is wavelength less than 400 nm, the most common is between 200 and 400 nm,
The infrared (IR) range wavelengths greater than 700 nm
Explanation:
The spectral region near the visible is what humans can see with our eyes.
The range of the ultra violet region (UV) is wavelength less than 400 nm, the most common is between 200 and 400 nm, this radiation is responsible for tanning and skin burns.
The infrared (IR) range is a very wide range that begins at wavelengths greater than 700 nm and continues up to approximately 25,000 nm (1012 Hz).
Which is the best analogy of a wave?
A wave is like building a ramp.
A wave is like shaking a hand.
A wave is like water rippling in a pond.
A wave is like knocking down a building.
Answer:
c i think
Explanation:
Answer:
answer is C
Explanation:
a. Why don't we hear the sound of oscillation of second
pendulum?
Answer:
because the frequency is too low for humans to hear.
Explanation:
Answer:
we cannot hear the sound produced due to vibrations of a seconds' pendulum.
Explanation:
This is because the frequency of sound produced as a result of vibrations of seconds' pendulum is 0.5Hz0.5Hz which is infrasonic sound.
The law of conservation of angular momentum states that if no external force acts on an object, then its angular momentum does not change. true or false
Answer:
the answer is false.
Explanation:
i took the test and it is false trust me!!!!!!!!!
An infant's toy has a 120 g wooden animal hanging from a spring. If pulled down gently, the animal oscillates up and down with a period of 0.54 s . His older sister pulls the spring a bit more than intended. She pulls the animal 32 cm below its equilibrium position, then lets go. The animal flies upward and detaches from the spring right at the animal's equilibrium position. Part A If the animal does not hit anything on the way up, how far above its equilibrium position will it go
Answer:
the wooden animal will go 0.7068 m above its equilibrium
Explanation:
Given the data in the question;
mass of wooden animal m = 120 g = 0.12 kg
the animal oscillates up and down, T = 0.54 s
older sister pulls the animal 32 cm below its equilibrium position;
x = 32 cm = 0.32 m
g = 9.81 m/s²
We know that
k = mω²
where ω = 2π/T
So, k = m( 2π/T )²
we substitute
k = 0.12( 2π / 0.54 )²
k = 0.12 × (11.6355)²
k = 0.12 × 135.38486
k = 16.25 N/c
so Also,
kx²/2 = mgh
we solve for h
h = kx² / 2mg
we substitute
h = ( 16.25 × (0.32)²) / ( 2 × 0.12 × 9.81 )
h = 1.664 / 2.3544
h = 0.7068 m
Therefore, the wooden animal will go 0.7068 m above its equilibrium
What is the mass of a dog house on Jupiter if the house weighs 1,040 N and the acceleration due to gravity on Jupiter is 26 m/s??
Your answer:
A. 1.040 kg
B. 0.65 kg
C. 40 kg
D. 1.5 kg
Answer:
40kg
Explanation:
1040/26=40
Suppose we have a vacuum with two metal plates separated by 2 meters. One of the plates has a hole in it so that a charged particle coming from the other one can pass through into empty space. ;The plate with a hole is attached to a voltage source of 5,000,000 V and electrons and muons are introduced near the other plate at 0 V. What energies and velocities do the electrons and muons have when they pass through the hole
Answer:
hello your question has a some missing information below is the missing information
An electron is one of the most fundamental particles in nature. It is everywhere, in all the matter we can see, and it is with electrons that light interacts when it is emitted, absorbed, or scattered in everyday matter. The electron has a more massive cousin called a muon, also with a charge of -1 e, but with a mass of 1.88x10-28 kg. The electron's mass is 9.11x10-31 kg. You can see why a muon is called a "heavy" electron. A muon is also unstable, and left alone at rest in a lab it will turn into an electron, kinetic energy, and two neutrinos with a lifetime of 2.20x10-6 s.
answer :
energy and velocity of Electron : 8*10^-13 J , < 3*10^8 m/s
energy and velocity of Muon : 8*10^-13 J, 9.22 * 10^7 m/s
Explanation:
Determine the energies and velocities of the electrons and Muons when they pass through the hole
i) energy of electron = q1 * V -- ( 1 )
V ( voltage ) = 5 * 10^6 V
q1 ( charge on electron ) = 1.6 * 10^-19 C
back to equation 1 ; energy of electron = ( 1.6 * 10^-19 ) * 5 * 10^6
= 8*10^-13 J
ii) velocity of electron = 1/2 * Me *( Ve)^2
1/2 * Me *( Ve)^2 = 8*10^-13
∴Ve = [tex]\sqrt{(8*10^{-13} )/(9.11*10^{-31} )}[/tex] < 3*10^8 m/s
iii) energy of muon
= Eu = q*v = 8*10^-13 J
iv ) velocity of Muon = [tex]\sqrt{(8*10^{-13} )/(1.88*10^{-28} )}[/tex] = 9.22 * 10^7 m/s
Caroline, a piano tuner, suspects that a piano's G4 key is out of tune. Normally, she would play the key along with her G4 tuning fork and tune the piano to match, but her G4 tuning fork is missing! Instead, she plays the errant key along with her F4 tuning fork (which has a frequency of 349.2 Hz), displays the resulting waveform on a handheld oscilloscope, and measures a beat frequency of 76.7 Hz. Then, she plays the errant key along with her A4 tuning fork (which has a frequency of 440.0 Hz) and measures a beat frequency of 14.1 Hz.
What frequency is being played by the out-of-tune key ?
a. 363.3 Hz
b. 451.1 Hz
c. 33.9 Hz
d. 272.5 Hz
e. 425.9 Hz
Answer:
e. 425.9 Hz
Explanation:
The computation of the frequency is being played by the out-of-tune key is shown below;
Given that
Δf1 = x - 349.2 = 76.7.........(1)
Δf2 = 440 - x = 14.1......(2)
Now solve (1) and (2)
(440 - x) - x + 349.2 = 14.1 - 76.7
789.2 + (-2x) = -62.6
x = 425.9 Hz
Hence, the frequency is being played by the out-of-tune key is 425.9 Hz
Therefore the option e is correct
What order shows increasing frequency for gamma rays, microwaves, visible light, and X-rays?
gamma rays, X-rays, visible light, microwaves
microwaves, visible light, X-rays, gamma rays
visible light, gamma rays, microwaves, X-rays
X-rays, microwaves, gamma rays, visible light
Answer:
B. microwaves, visible light, X-rays, gamma rays
The order that shows increasing frequency for gamma rays, microwaves, visible light, and X-rays is:
microwaves, visible light, X-rays, gamma rays
What are electromagnetic waves?These are waves that can propagate (i.e travel) through space while transferring energy. They travel through space with the speed of light (i.e 3×10⁸ m/s)
Examples of electromagnetic waves includes
Gamma rayX-rayUltraviolet Light Infrared Radio wave MicrowaveFrom the examples given above, it should be noted that gamma ray has the shortest wavelength and the longest frequency.
With the above information in mind, we can conclude that the order that shows increasing frequency for gamma rays, microwaves, visible light, and X-rays is:
microwaves, visible light, X-rays, gamma rays
Learn more about electromagnetic waves:
https://brainly.com/question/8553652
In medieval times it was believed that projectiles were pushed through the air until they reached their impetus.
a. True
b. Fals
Answer:
false
Explanation:
A 06-C charge and a .07-C charge are apart at 3 m apart. What force attracts them?
Answer:
F = 37.8 × 10^(6) N
Explanation:
The charges are 0.06 C and 0.07 C.
Thus;
Charge 1; q1 = 0.06 C
Charge 2; q2 = 0.07 C
Distance between them; r = 3 m
Formula for the force in between them is;
F = kq1•q2/r²
Where k is a constant = 9 × 10^(9) N.m²/C²
Thus;
F = (9 × 10^(9) × 0.06 × 0.07)/3²
F = 37.8 × 10^(6) N
Why does Marx’s workers’ paradise resolve the problems of capitalism?
A. Everything is free, and no one has to work.
B. Workers are divided into three classes, much like in Plato’s ideas.
C. There is no currency in the paradise so no economic problems.
D. People work for their own good instead of a factory owner’s.
A 35.0 g bullet strikes a 50 kg stationary piece of lumber and embeds itself in the wood. The piece of lumber and the bullet fly off together at 8.6 m/s. What was the speed of the ballot before it struck the lumbar? Define the bullet and the wood as a system
Answer:
12294.31 m/s
Explanation:
Momentum = (mass)(velocity)
Momentum before = Momentum after
(momentum of bullet)+(momentum of block)=(momentum of bullet and block)
0.035v+50(0)=(0.035+50)(8.6)
0.035v=430.301
v=12294.3142857m/s