What is the molarity of a nitric acid solution if 49.90 mL of a 0.01 KOH solution is needed to neutralize 20.00 mL of the acid solution?
The question requires us to calculate the molarity (or molar concentration) of a HNO3 solution, given the volume and concentration of a KOH solution used to neutralize a given volume of the acid.
The following information was provided by the question:
molarity of KOH solution = M(KOH) = 0.01 M = 0.01 mol/L
volume of KOH solution = V(KOH) = 49.90 mL
volume of HNO3 solution = V(HNO3) = 20.00 mL
To answer this question, we need to take a look at the neutralization reaction between HNO3 and KOH:
HNO3 + KOH -> KNO3 + H2O
From the reaction, we have that 1 mol of HNO3 is necessary to neutralize 1 mol of KOH. With this information, we can write that, to achieve complete neutralization:
number of moles of HNO3 = number of moles of KOH
Since the molarity of a solution is given by the following equation:
[tex]\text{molarity = }\frac{\text{number of moles (mol)}}{volume\text{ of solution (L)}}\to M=\frac{n}{V}[/tex]We can rearrange it to:
[tex]n=M\times V[/tex]And we can also write the equality between the number of moles of HNO3 and KOH as:
[tex]n_{HNO_3}=n_{KOH}\to M_{HNO_3}\times V_{HNO_3}=M_{KOH}\times V_{KOH}[/tex]And, since the concentration of KOH was provided, as well as the volumes of HNO3 and KOH necessary to achieve neutralization, we can apply these values to calculate the molarity of HNO3 using the equation above:
[tex]M_{HNO_3}\times V_{HNO_3}=M_{KOH}\times V_{KOH}\to M_{HNO_3}=\frac{M_{KOH}\times V_{KOH}}{V_{HNO_3}}[/tex][tex]M_{HNO_3}=\frac{(0.01\text{ mol/L)}\times(49.90\text{ mL)}}{(20.00\text{ mL)}}=0.02495\text{ mol/L}[/tex]Therefore, the molarity of the nitric acid solution is equal to 0.02495 mol/L.
HELP ME CHEMISTRY QUESTION PURE SUBSTANCE OR MIXTURE 100 POINTS
Answer: Bro you can use Bartleby for this answer
Explanation:
Suppose you need to calibrate a calorimeter. You burn 0.744g of a fuel with an enthalpy of combustion of −48.7 kJ/g. If the temperature of water in the calorimeter increases by 10.6∘C during the reaction, what is the heat capacity of the calorimeter in kJ/C°?
suppose you need to calibrate a calorimeter. you burn 0.744 g of a fuel with an enthalpy of combustion of -48.7 kJ/g. if the temperature of water in the calorimeter increases by 106 °C during the reaction . the heat capacity of the calorimeter is 3.417 kJ/ °C.
Heat capacity equation is given by :
q = c ΔT
given that :
change in temperature ΔT = 106 °C
now, q = 0.744 g × ΔH
= 0.744 g × 48.7 kJ/g
q = 36.23 kJ
putting the value in formula :
q = c ΔT
c = q /ΔT
c = 36.23 kJ / 10.6 °C
c = 3.417 kJ/ °C
Thus, suppose you need to calibrate a calorimeter. you burn 0.744 g of a fuel with an enthalpy of combustion of -48.7 kJ/g. if the temperature of water in the calorimeter increases by 106 °C during the reaction . the heat capacity of the calorimeter is 3.417 kJ/ °C.
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An atom of Calcium has 20 protons and 20 electrons. The atom loses 2 electrons.
What will be the charge on the ion that forms?
A +2
B -2
C +18
D -18
Based on the given question about an atom of Calcium and losing electrons, the charge on the ion that forms would be 18.
What is a Proton?This refers to the subatomic particle that is positively charged and can be found in the nucleus of every atom.
Calculations and Parameters
Given that:
Ca^2+ represents an ion with 20 protons and 18 electrons.
A calcium atom has 20 protons and 20 electrons.
The 2+ charge close to the symbol shows a loss of two electrons: 20-2=18.
With this in mind, the charge on the ion that forms would be 18.
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Given the chemical equation: SiO2 (s) + 4KF(g) --> SiF4(g)+ 2H2O(l) Delta H= -184kJ
How much heat is released in the formation of 75.0 g of water?
The heat is released in the formation of 75.0 g of water is 14.78 kJ.
What is chemical equation?Chemical equation is defined as a chemical reactions are represented symbolically in which the reactants and products are expressed in terms of their respective chemical formulae.
There are basically five types of chemical equation.
Combination reactionDecomposition reactionReplacement reactionDouble replacement reactionCombustion reactionSiO2 (s) + 4KF(g) --> SiF4(g)+ 2H2O(l)
According to the reaction
ΔH = -184 / 2 moles of water
N(water) = Q / ΔH
N(water) = 75 / - 184 / 2 moles of water
N(water) = 0.82 mole
M(water) = 18.02 g/mole
M(water) = N(water) = 0.82 x 18.02 g/mole
= 14.78 kJ
Thus, the heat is released in the formation of 75.0 g of water is 14.78 kJ.
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Working with a Copper solution, use a pipette transfers 10.0mL of a 2.63M Cu+ solution to 500mL flask (added H20 to the mark). Then transfer by pipette 5.0mL of the second solution to 100mL flask and enough water to the line mark on the flask.
Calculate concentration of the Cu+2 solution in the 100mL flask.________Molar
The final concentration of the solution is 0.13 M,
What is dilution?The term dilution has to do with a reduction in the concentration of a solution. We ought to note that the term concentration has to do with the amount of substance that we can find in a solution. There are several units that we could use in the measurement of the concentration of a solution and these include;
MolarityMolalityPercentageNormalityNow we are required to be able to obtain the concentration of the solution of the copper I ion that can be found in the flask that has only 100mL. Let us recall that the original solution had only 5 mL of it removed.
Given that;
C1V1 = C2V2
C1 = initial concentration
C2 = Final concentration
V1 = initial volume
V2 = final volume
C2 = C1V1/V2
C2 = 2.63M * 5.0mL/100 mL
C2 = 0.13 M
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Moist air at atmospheric presure, 80 ℃ and relative humidity 40% enters a cooler .
What is the mole fraction yv of H2O in the moist entering air?
How many total moles (air plus water molecules) are in 1m^3 of moist entering air?
How many moles of DA (dry air) ?
The Antoine equation with T in C and p in mm Hg has coefficients for water given by
0 to 60 ℃ : A= 8.10765 B=1750.286 C=235.000
60 to 150℃ : A=7.96681 B=1668.210 C= 228.000
help me i don't know
explain me hahaha
Write the balanced molecular chemical equation for the reaction in aqueous solution for ammonium sulfate and iron(II) chloride. If no reaction occurs, simply write only NR. Be sure to include the proper phases for all species within the reaction.
The balanced molecular chemical equation for the reaction in an aqueous solution for ammonium sulfate and iron(II) chloride is
[tex]2AlCl_3(aq) + 3Na_2S(aq) = Al2S_3(aq) + 6NaCl(aq)[/tex]
This is further explained below.
What is a chemical equation?Generally, Equations are a way to depict chemical processes by using chemical formulas and symbols, and these equations may be found online.
In a chemical equation, the reactants are indicated on the left-hand side of the equation, while the products are shown on the right-hand side.
Generally, the Chemical equation is mathematically given as
AlCl_3 + Na_2S ---> Al2S3 + NaCl.
Hence we balance as
[tex]2AlCl_3 + 3Na2_S = Al2S_3 + 6NaCl,[/tex]
After that, we bring in the states. Because the reaction is taking place in an aqueous solution, we need to inject (aq)
[tex]2AlCl_3(aq) + 3Na_2S(aq) = Al2S_3(aq) + 6NaCl(aq)[/tex]
Thus our required After that, we bring in the states. Because the reaction is taking place in an aqueous solution, we need to inject (aq)is
[tex]2AlCl_3(aq) + 3Na_2S(aq) = Al2S_3(aq) + 6NaCl(aq)[/tex]
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A gas sample is prepared by mixing 15.0 g Cl₂ (70.90 g/mol) with 15.0 g Br2 (159.8 g/mol) to a total pressure of
862 mm Hg. What is the partial pressure in mm Hg of Br2 in the mixture
A gas sample is prepared by mixing 15.0 g Cl₂ (70.90 g/mol) with 15.0 g Cl₂ (159.8 g/mol) to a total pressure of 862 mmHg . The partial pressure in mm Hg of Br₂ in the mixture is 262.91 mmHg.
Dalton's law of partial pressures :
The mole fraction of gas × total pressure = partial pressure
mass of Cl₂ = 15.0 g
molar mass = 70.90 g/mol
no. of moles = mass / molar mass
= 15.0 g / 70.90 g/mol
= 0.211 mol
mass of Br₂ = 15.0 g
molar molar = 159.8 g/mol
no. of moles = mass / molar mass
= 15.0 / 159.8 g/mol
= 0.093 mol
Total moles = 0.211 mol + 0.093 mol
= 0.304 moles
Mole fraction of Br₂ = no. of moles of Br₂ / total moles
= 0.093 / 0.304
= 0.305
Total pressure = 862 mmHg
now putting the values in formula :
partial pressure of Br₂ = mole fraction of Br₂ × total pressure
= 0.305 × 862 mm Hg
= 262.91 mm Hg
Thus, A gas sample is prepared by mixing 15.0 g Cl₂ (70.90 g/mol) with 15.0 g Cl₂ (159.8 g/mol) to a total pressure of 862 mmHg . The partial pressure in mm Hg of Br₂ in the mixture is 262.91 mmHg.
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41
The flow of rivers is affected by natural environmental conditions and human activities.
Which of the following human activities would result in the most impact on the flow of
water in a river?
A. The release of water from a water treatment plant into the river
B. The development of a shopping center along the riverbank
C. Harvesting trees from a forest along the riverbank
D. Constructing a dam in the river
B. The development of a shopping center along the riverbank is the following human activities would result in the most impact on the flow of water in a river
How do factors can impact way water flows?By building dams to store water and by taking water for household, commercial, and agricultural uses, humans actively alter the dynamics of the water cycle. Water demand and supply are expected to be even more impacted by climate change.
Human development, including population increase, reliance on fossil fuels, urbanisation, intercontinental trade, and industrial and agricultural emissions, is typically the cause of environmental changes in rivers.
Acid rain allows nitrous oxide and sulphur dioxide from industries and power plants to infiltrate river systems. In certain places, sewage and wastewater are dumped into rivers. All creatures, from algae to vertebrates, are impacted by pollution when the pH of the water is lowered. As pH falls, biodiversity declines.
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[E2E] question 1646287324361
I'm not able to help you with your question
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[tex]\text{y = ax + b}[/tex]Show the complete ionic and net ionic forms of the following equation. Have your
solubility rules open for this problem.
manganese(II) chloride(aq) + ammonium carbonate(aq) => manganese(II)carbonate(s) +
ammonium chloride(aq)
The complete ionic and net ionic forms of the following equation.
ionic equation :
Mn²⁺ + 2Cl²⁻ + 2NH₄⁺ + CO₃²⁻ -----> MnCO₃ + 2NH₄⁺ + 2Cl⁻
net ionic equation :
Mn²⁺(aq) + CO₃²⁻(aq) ----> MnCO₃(s)
according to question :
MnCl₂ + (NH₄)₂CO₃ ----> MnCO₃ + NH₄Cl
balanced molecular equation : with states
MnCl₂(aq) + (NH₄)₂CO₃(aq ----> MnCO₃(s) + 2NH₄Cl(aq)
the complete ionic equation as follows :
Mn²⁺ + 2Cl²⁻ + 2NH₄⁺ + CO₃²⁻ -----> MnCO₃ + 2NH₄⁺ + 2Cl⁻
Now cancel out the spectator ions on both side of equation , the reactant and the product, we get
Mn²⁺(aq) + CO₃²⁻(aq) ----> MnCO₃(s)
now, the complete net ionic equation is
Mn²⁺(aq) + CO₃²⁻(aq) ----> MnCO₃(s)
Thus, The complete ionic and net ionic forms of the following equation.
ionic equation :
Mn²⁺ + 2Cl²⁻ + 2NH₄⁺ + CO₃²⁻ -----> MnCO₃ + 2NH₄⁺ + 2Cl⁻
net ionic equation :
Mn²⁺(aq) + CO₃²⁻(aq) ----> MnCO₃(s)
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Which option is an example of a closed system?
A bottle contains 2.55L of gas at STP.How many moles of gas are present?mol
Explanation:
We are given: volume = 2.55L
At STP: Temperature = 273.15 K
: Pressure = 1 atm
: R = 0.08205 L.atm/mol.K
Using the ideal gas law:
[tex]\begin{gathered} PV\text{ = nRT} \\ \\ \therefore\text{ n = }\frac{PV}{RT}\text{ = }\frac{1\times2.55}{0.08205\times273.15}\text{ = 0.11 mol} \end{gathered}[/tex]Answer:
n = 0.11 mol
find my title for football,baseball bat,cleats, and bookcase
The above exercise is designed to help the students understand how living things and non-living things are classified. See the solution for this below.
What is the title for each category of the item listed above?The items are classified as follows:
Food:
Sports Items:
FootballBaseball BatcleatsFurniture:
TableBookcaseChairSofaIt is to be noted that The science of living beings or even anything requires classification. It is necessary for understanding the many types of organisms and things. It aids in the identification of different species. It is beneficial to understand the genesis and evolution of organisms.
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Full Question:
In the exercises that follow, arrange the items listed into different groups. Give each group a title indicating what the members of that group have in common.
Steak, football, sausage, chair, table, bacon, sofa, baseball bat, cleats, ham, bookcase
How much energy is required to raise the temperature of 4.0 g of mercury metal from 9.3 oC to 83.0 oC.
From the specific heat capacity of mercury, the amount of heat energy required to raise the temperature of 4.0 g of mercury metal from 9.3 °C to 83.0 °C is 77.792 J.
What is the specific capacity of mercury?The specific heat capacity of a substance is the amount of heat required to raise the temperature of a unit mass of the substance by one degree Celsius or kelvin.
The specific heat capacity of a substance is a constant that can be used to calculate the amount of heat required to raise the temperature of a given mass of a substance to any temperature.
The specific heat capacity of mercury is 0.140 J/g/k.
The formula for calculating specific heat capacity is given below:
Specific heat capacity, c = Δq/mΔT
where;
Δq = heat change
m = mass of the substance
ΔT = temperature change
The Heat required, Δq, will then be:
Δq = m * c * ΔT
Heat required, Δq = 4.0 * 0.140 * (83.0 - 9.3)
Heat required, Δq = 77.792 J
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Daniel and Sanya are scientists. Daniel is studying whether the increasing frequency of tropical storms is affecting coastal erosion. Sanya is investigating whether the discharge from industrial plants has any impact on the pH concentration of freshwater swamps in the surrounding area. Which fields of science are Daniel’s and Sanya’s studies most closely related to?
Daniel’s field of study is related to
science, and Sanya’s field of study is related to
Daniel’s field of study is related to science, and Sanya’s field of study is related to the study of Earth and Space
This is further explained below.
What is Daniel’s field of study?Generally, According to the information that was provided, the researcher named Daniel was doing research on the impact that tropical storms have on the erosion of coastal areas.
These types of research are under the umbrella of the Earth and Space Studies discipline.
Earth, due to the fact that coastal erosions are a part of the study, and Space, due to the fact that storms, which are something that is connected to space, are studied.
When it comes to Sanya, it is quite evident that the emphasis of her research is on the discharges from the industrial facility that have an influence on the freshwater marshes. To be more specific, she is looking into the pH concentration, which is a topic covered in chemistry.
This demonstrates that Daniel majors in Earth and Space Sciences whereas Sanya focuses on Chemistry.
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(30) Using a periodic table, write the full electron configuration of
bromine (Br) so that all the subshells in each principal energy shell
are grouped together.
The electronic configuration of Bromine is 1s²2s²2p⁶3s²3p⁶4s²3d¹⁰4p⁵.
What is the electronic configuration of an element?The electronic configuration of an element refers to the arrangement of electrons in orbitals around the nucleus of an atom of the element.
Electrons in an atom are arranged in orbitals and are fed into the orbitals based on the energy level of the electrons.
The orbitals in which electrons in an atom are placed include:
s-orbital - can take up to 2 electrons
p-orbitals - can take up to six electrons
d-orbital - can take up to 10 electrons
f-orbitals - can take up to 4 electrons
The atomic number of an element determines the electronic configuration of an element.
The atomic number of Bromine is 35.
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What is the shape of a molecule that has 3 atoms bonded to a central atom and no lone pairs of electrons?
Answer and Explanation: A molecule consisting of central atom with three bond pairs and one lone pair of electrons will have trigonal pyramidal shape.
How many moles of BaSO, could be made from 1.25 mol
of Al₂(SO4), provided that sufficient amounts of any
icale are available
Answer: A mole of Aluminium Sulphate contains 12 moles of Oxygen
So
12
1
×0.24
Moles of Aluminium Sulphate contains 0.24 moles of Oxygen
So 2×10
−2
Moles is the answer
Explanation:
If you mix 2.8 mol of A with 2.8 mol of B, what amount (moles) of A2B can be produced?
Answer: 1.4 mol A2B is produced.
Explanation: 2A + B = A2B, so there are 2 moles of A to every one mole of B.
So if 2.8 mol of A is present 1/2 that amount is made in A2B (and there will be extra B left over because A is the limiting reactant and you can't make more product than the least amount of reactant allows.
So 1.4 mole of A2B will be produced.
If 200g of KCIO3 breaks down and produces 135g of KCI, how many grams of O2 are produced?
If 200 g of [tex]KClO_3[/tex] decomposes to produce 135 g of KCl, the amount of oxygen produced should be 65 g.
Law of mass conservationIn every decomposition reaction, the mass of the original substance must be equivalent to the sum of the masses of the products of decomposition.
This is known as the law of mass conservation. If a difference exists between the mass of the decomposing substance and the sum of the masses of the products of its decomposition, then the law of conservation of mass has not been obeyed.
Thus, in the reaction:
[tex]KClO_3 (s) --- > KClO (s) + O_2 (g)[/tex]
Mass of [tex]KClO_3[/tex] = 200 g
Mass of KClO = 135 g
Mass of [tex]KClO_3[/tex] = mass of KClO + mass of [tex]O_2[/tex]
Mass of [tex]O_2[/tex] = mass of [tex]KClO_3[/tex] - mass of KClO
= 200 - 135
= 65 g
Hence, the mass of [tex]O_2[/tex] produced will be 65 g.
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Calculate the theoretical yield in grams All from the complete reaction of 18.3
grams Al according to the following balanced chemical equation:
2 Al(s) + 3 (s) →→
2 All(s)
(s)→ 2
The theoretical yield of aluminum iodide according to the reaction would be 276.5 grams.
Stoichiometric problemWe are looking to get the theoretical yield of aluminum iodide. This can be achieved by first getting the balanced equation of the reaction:
[tex]2Al + 3I_2 --- > 2AlI_3[/tex]
The mole ratio of Al that reacts and the [tex]AlI_3[/tex] that is produced is 1:1.
Recall that: mole = mass/molar mass.
18.3 grams of aluminum completely reacts:
Molar weight of aluminum = 26.98 g/mol
Mole of 18.3 g aluminum = 18.3/26.98
= 0.6782 mole
Since the mole ratio of Al and [tex]AlI_3[/tex] is 1:1, the equivalent mole of [tex]AlI_3[/tex] will also be 0.6782 mole.
Recall that: mass = mole x molar mass
Molar mass of [tex]AlI_3[/tex] = 407.695 g/mol
Mass of 0.6782 [tex]AlI_3[/tex] = 0.6782 x 407.695
= 276.5 grams
In other words, the theoretical yield of [tex]AlI_3[/tex] according to the reaction is 276.5 grams.
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how many atoms are in a tetrahedral molecule?
Answer:
There would be 4 atoms in a tetrahedral molecule.
Explanation:
Answer: 4 atoms
Explanation:
What is the binding energy of a mole of nuclei with a mass defect of 0.00084
kg/mol?
A. 7.56 x 1016 J/mol
B. 7.56 x 1013 J/mol
C. 2.52 x 105 J/mol
D. 2.52 x 108 J/mol
The binding energy of a mole of nuclei with a mass defect of 0.00084kg/mol is 7.56 x 10¹³ J/mol (option B).
How to calculate binding energy?Binding energy is the energy needed to separate the constituent parts of an atom or nucleus; equivalent to the mass defect.
The binding energy of a nucleus can be calculated as follows:
Binding Energy = mass defect x c²
where;
c = speed of light in vacuum (2.9979 x 10⁸ m/s)According to this question, a nuclei with a mass defect of 0.00084kg/mol is given. The binding energy can be calculated as follows:
Binding energy = 0.00084 kg/mol × (2.9979 x 10⁸ )²
= 8.94e16 × 8.4 × 10-⁴
= 7.51 × 10¹³J
Therefore, 7.51 × 10¹³J/mol is the binding energy of the nuclei.
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When menthol, CH3OH, is burned in the presence of oxygen gas, O2, a large amount of heat energy is released. For this reason, it is often used as a fuel in high performance racing cars. The combination of methanol has the balanced, thermochemical equation CH3OH(g) + 3/2O2(g) — CO2(g) + 2H2O(1) DeltaH= -764Kj How much methanol, in grams, must be found to produce 701 kj of heat?
We have the following balanced equation:
[tex]CH_3OH_{(g)}+\frac{3}{2}O_{2\text{ (g)}}\rightarrow CO_{2\text{ (g)}}+2H_2O_{(l)}[/tex]They also give us the heat of reaction equal to -764 kJ, i.e. it is an exothermic reaction.
By observing the reaction, we can deduce that for this heat to be generated, one mole of methanol is needed. Now let's see how many grams that mole of methanol equals. We will use the molecular weight equal to 32.04 g/mol
[tex]\begin{gathered} g\text{ of methanol = 1 mol }\times\text{ 32.04 g/mol} \\ g\text{ of methanol }=\text{ 32.04 g} \end{gathered}[/tex]Now we know the grams of methanol that generate 764 kJ, because the heat of reaction is directly proportional to the mass of the reactants, we can apply a rule of three to know the grams needed to produce a heat of reaction equal to 701 kJ:
[tex]\begin{gathered} \frac{32.04\text{ g of methanol}}{764\text{ kJ}}=\text{ }\frac{x\text{ g of methanol}}{701\text{ kJ}} \\ x\text{ g of methanol = }\frac{32.04\text{ g of methanol }\times\text{ 701 kJ}}{764\text{ kJ}} \\ g\text{ of methanol = 29.4 g} \end{gathered}[/tex]So, 29.4 g of methanol must be found to produce 701 kJ of heat
What type of chemical reaction gives off heat t0 its surroundings
nswer
Explanation
An exothermic reaction is a type of chemical reaction that gives off heat to its surroundings. In an exothermic reaction, energy is released because the total energy of the products is less than the total energy of the reactants.
Answer:An exothermic Chemical Reaction
Explanation:
1. What is the molarity of 245.0 g of H₂SO4 dissolved in 1.00 L of solution?
2. What is the molarity of 5.00 g of NaOH in 750.0 mL of solution?
3. How many moles of NaCl are contained in 100.0 mL of a 0.20 M solution?
4. Determine the number of moles of solute in 16.00 mL of a 0.415-molar Pb(NO3)2 solution.
5. What weight (in grams) of H₂SO4 would be needed to make 750.0 mL of 2.00 M solution?
6. What weight (in grams) of KCI is there in 2.50 liters of 0.50 M KCI solution?
7. What volume (in mL) of 18.0 M H₂SO4 is needed to contain 2.45 g H₂SO4?
8.
Determine the volume in L of the solution with 48.00 grams of PbCl₂ needed to form a 5.0-molar
solution.
9. What volume of 0.250 M KCI is needed to make 100.0 mL of 0.100 M solution?
10. A stock solution of 10.0 M NaOH is prepared. From this solution, you need to make 250.0 mL of
0.375 M solution. How many mL will be required?
The molarity of 245.0 g of H₂SO4 dissolved in 1.00 L of solution is 2.498M. the molarity of 5.00 g of NaOH in 750.0 mL of solution is 0.167M.
Molar ConcentrationA chemical species' concentration in a solution, specifically the amount of a solute per unit volume of solution, is measured by its molar concentration.
The number of moles per liter when denoted by the unit symbol mol/L or mol/dm3 in SI units, is the mostly used unit used for denoting molarity in chemistry. The secret to determining molarity is to keep in mind that it is measured in moles per liter (M).
MV = grams / molar mass
(x)*(1.000 L) = (245.0 g) / (98.0768 g mol¯1)
x = 2.49804235 M
So, calculating it to 4 significant figures, x = 2.498 M
For 2nd question
Applying the same formula, MV = grams / molar mass
(x) (0.7500 L) = 5.00 g / 39.9969 g mol¯1
(x) (0.7500 L) = 0.1250097 mol
x = 0.1666796 M
x = 0.167 M (when calculated to three Significant figures)
For 3rd question,
using variation of the same formula,
0.200 M = x / 0.1000 L
x = 0.0200 mol
For the 4th question,
MV = moles of solute
no of moles x = (0.415 mol L¯1) (0.01600 L)
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Which of the following brings more value to Mussorgsky's work, "Pictures at an Exhibition?"
A. It brought music and art together
B. Many of Hartmann's original pictures no longer exist
C. It complimented Hartmann's work
D. It used a variety of instruments
Mussorgsky dedicated his work Pictures at an Exhibition to a friend, the painter Vladimir Hartmann, who had passed away at the age of 39 at the height of his fame.
What was Modest Mussorgsky's Pictures at an Exhibition inspired by?Mussorgsky through his music, and Hartmann through his images. The Academy of Fine Arts in St. Petersburg organized an exhibition of Hartmann's artwork in 1874. After visiting the exhibit, Mussorgsky was moved to write his piano piece.
Mussorgsky dedicated his work Pictures at an Exhibition to a friend, the painter Vladimir Hartmann, who had passed away at the age of 39 at the height of his fame. The composer and the larger Moscow artistic community were profoundly affected by the loss of both a close friend and an artistic inspiration.
The design of Hartmann's massive, imposing gate, which was intended to honor the fact that Tzar (king) Alexander the II had survived an attempted assassination, served as the inspiration for the Great Gate of Kiev.
Therefore, the correct answer is option C. It complimented Hartmann's work.
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A quantity of 7.181 g of an organic compound is dissolved in water to make 288.0 mL of solution. The
solution has an osmotic pressure of 1.43 atm at 27°C. The analysis of this compound shows that it
contains 41.8 percent C, 4.7 percent H, 37.3 percent O, and 16.3 percent N. Calculate the molecular
formula of the compound.
Answer:
Explanation:
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