Which of the following is an equivalent expression to the expression
a4
A
a12
B
C
7
Q12
2
HELP.

Answer:

[tex]a=2\\\\ b = 20\\\\ c = 47[/tex]

Step by step explanation:

[tex]a(x) = 2(x+5)^2 -3\\\\~~~~~~~=2(x^2 +2 \cdot 5 \cdot x +5^2) -3\\\\~~~~~~~=2(x^2 +10x+25) -3\\\\~~~~~~~=2x^2 +20x +50 -3 \\\\~~~~~~~=2x^2 +20x +47\\\\\text{By comparing}~ 2x^2 +20x +47~ \text{with the standard form}~ ax^2 +bx+c,\\\\a=2,~ b = 20,~ c = 47[/tex]

Answer:

A or 57 7/9ft3

Step-by-step explanation:

13/3x10/3x4/1 = 520/9=57 7/9

Answer:

B. AC > AB

Step-by-step explanation:

AC is the longest line and AB is shorter than AC

Answer:

-1.5

Step-by-step explanation:

h(-1/2)=2 [tex](\frac{-1}{2})^{2}[/tex] -2

h(-1/2)= [tex]\frac{1}{2} -2\\[/tex]

h(-1/2)=-1.5

Answer:

D) None of the choices are correct.

Explanation:

Given triangles AHL and NKG

Sides which are congruent:

So, AHL ≅ NKG. There are no such options.

the answer is 40 minute's 250-210 is 40

[tex]\\ \rm\Rrightarrow g(x)=6(\dfrac{3}{2})^x[/tex]

[tex]\\ \rm\Rrightarrow g(-1)=6(\dfrac{3}{2})^{-1}=6(\dfrac{2}{3})=2(2)=4[/tex]

[tex]\\ \rm\Rrightarrow g(0)=6[/tex]

[tex]\\ \rm\Rrightarrow g(1)=6(\dfrac{3}{2})=3(3)=9[/tex]

[tex]\\ \rm\Rrightarrow g(2)=6\times\dfrac{9}{4}=13.2[/tex]

Attached the graph

Answer:

Given function:

[tex]g(x)=6\left(\dfrac{3}{2}\right)^x[/tex]

To find each of the points, substitute the given values of x into the function:

[tex]x=-1 \implies g(-1)=6\left(\dfrac{3}{2}\right)^{-1}=4[/tex]

[tex]x=0 \implies g(0)=6\left(\dfrac{3}{2}\right)^{0}=6[/tex]

[tex]x=1 \implies g(1)=6\left(\dfrac{3}{2}\right)^{1}=9[/tex]

[tex]x=2 \implies g(2)=6\left(\dfrac{3}{2}\right)^{2}=13.5[/tex]

Therefore:

[tex]\large \begin{array}{| c | c | c | c | c |}\cline{1-5} x & -1 & 0 & 1 & 2 \\\cline{1-5} g(x) & 4 & 6 & 9 & 13.5 \\\cline{1-5} \end{array}[/tex]

As the function is exponential, there is a horizontal asymptote at [tex]y=0[/tex].

Therefore, as [tex]x[/tex] approaches -∞ the curve approaches [tex]y=0[/tex] but never crosses it.

So the end behaviors of the graph are:

Plot the points on the graph and draw a curve through them.

Answer:

line BC

Step-by-step explanation:

Line BC is the only line that doesn’t touch line AG

Step-by-step explanation:

please Mark me brainlist!!

Answer:

Two angles forming a linear pair are always supplementary. Linear pair of angles are formed when two lines intersect each other at a single point, and the sum of angles of a linear pair is always equal to 180°.

Step-by-step explanation:

Two angles forming a linear pair are always supplementary. Linear pair of angles are formed when two lines intersect each other at a single point, and the sum of angles of a linear pair is always equal to 180°.

Question :

Answer :

They are formed when two lines intersect each other at one point and the sum of angles is 180⁰ .

Answer:90 degree

Step-by-step explanation:

Answer:

x = 90°

Step-by-step explanation:

According to the Angle Sum Property of Triangles, the sum of the internal angles is 180°.

Answer:

4

Step-by-step explanation:

Given :

f(x) = x² - 6x + 8

=============================================================

Solving :

Splitting the middle term :

⇒ f(x) = x² - 6x + 8

⇒ f(x) = x² - 2x - 4x + 8

⇒ f(x) = x (x - 2) - 4 (x - 2)

⇒ f(x) = (x - 4)(x - 2)

============================================================

Solutions :

⇒ x - 4 = 0 ⇒ x = 4

⇒ x - 2 = 0 ⇒ x = 2

Polynomial is an expression that consists of indeterminate(variable) and coefficients. The roots of the given polynomial are -2, -1, 0, and 2.

Polynomial is an expression that consists of indeterminate(variable) and coefficient, it involves mathematical operations such as addition, subtraction, multiplication, etc, and non-negative integer exponential.

The roots of the given polynomial when plotted on graph are the point at which the graph intersect the x-axis. Therefore, the roots of the given polynomial is,

x = -2, -1, 0, 2

Hence, the roots of the given polynomial are -2, -1, 0, and 2.

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Answer:

It's A. -2, -1, 0, 2

Step-by-step explanation:

The equation that describes the which gives the area of the pen, A, as a function of x, the length of fence parallel to the barn is A = 130x - x²

The pen is rectangular. Therefore,

area of a rectangle = lw

where

Therefore,

perimeter = 2w + l

perimeter = 2w + x

130 = 2w + x

130 - x = 2w

w = 65 - 1/ 2 x

A = xw

A = x(65 - 1/ 2 x)

A = 65x - 1 / 2 x²

Therefore, the function that represents A, the area of the pen is as follows:

A = 130x - x²

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Answer:

B

Step-by-step explanation:

if

x=3

y=2

-2xy²

3

2³=8

-2×3×8

= -48

Answer:

A its becuase im rewlly smart

Answer:

3.6%

Step-by-step explanation:

Because the two events are independent, their probabilities are multiplied, so the probability of a student being born in March and having a blood type of O+ is 9% * 40% = 0.09 * 0.40 = 0.036 = 3.6%

Answer:

3a

Step-by-step explanation:

Looking at the problem, what we must do to complete this question is to completely factor the expression that was provided.  The expression that was provided is [tex]15c^2 - 5c[/tex].

The first step that we must do is to take a look at the expression and see what the two pieces of the expression have in common.  We can see that both [tex]15c^2[/tex] and [tex]-5c[/tex] have the number 5 and the variable c associated with them so we can factor out those two.

Factor out 5c

Now we have completely factored out the expression that was provided in the problem statement and we came to final answer of [tex]5c(3c - 1)[/tex].

Answer:

5c(3c - 1)

Step-by-step explanation:

Take out the 5c to factor out completely

The attached graph represents the graph of the function f(x) = |x - 3| + 2

The equation of the function is given as:

f(x) = |x - 3| + 2

The above equation is an absolute value function, and it has the following parameter:

Vertex = (3,2)

Next, we plot the graph of the function (see attachment)

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Answer:

[tex]\sf 2 x-5y +25=0[/tex]

Explanation:

Equation:

[tex]\dashrightarrow \sf y - y_1 =m(x - x_1)[/tex]

[tex]\dashrightarrow \sf y - 1 = \dfrac{2}{5} (x - (-10))[/tex]

[tex]\dashrightarrow \sf y = \dfrac{2}{5} x +4 + 1[/tex]

[tex]\dashrightarrow \sf y = \dfrac{2}{5} x +5[/tex]

[tex]\dashrightarrow \sf 5y = 2 x +25[/tex]

Answer: 1/10

Step-by-step explanation:

(1 x 4)/(8x5)

4/40

1/10

Answer: once tom eats 6 candys he will have the same number as sue

Step-by-step explanation:

Answer:

After 6 minutes they will both have 0 candies.

8x+72.8=5x+84.5

8x-5x = 84.5-72.8

3x = 11.7

x = 3.9

x = {3.9}

The price per share of the stock of the high-tech firm that was purchased by Jake is  $50.

Percentage is a measure of frequency that calculates the fraction of an amount out of hundred.

What is the price per share of the stock purchased by Jake = current value / ( 1 + percentage increase)

61 / 1.22 = $50

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Answer:

(2,11)

Step-by-step explanation:

What is substitution method?

The substitution method is where you plug in an expression that defines a variable into the other equation so you are left with one variable in which you can solve for.

In order to use the substitution method, one of the variables must be defined by an expression (e.g. x = 8y + 2 , the x is defined by the expression 8y + 2. )

Rearranging terms to define x or y

We have the two equations 2x + y = 15 and 7x - 2y = -8

The equation we would rearrange would likely be 2x + y = 15 as the y is by itself meaning we could easily change a few things to define it.

2x + y = 15

==> subtract 2x from both sides

2x - 2x + y = 15 - 2x

==> simplify

y = 15 - 2x

Plugging ( or substituting ) y's defined expression into the other equation.

Now that we have rearranged the equation to where "y" is being defined we can plug in the expression defined by y into the other equation and then solve for x.

2nd equation : 7x - 2y = -8

==> plug in y = 15 - 2x

7x - 2(15-2x) = -8

==> distribute the 2

7x - 30 + 4x = -8

==> combine like terms

11x - 30 = -8

==> add 30 to both sides

11x = 22

==> divide both sides by 11

x = 2

Substituing the value of x into one of the equations and then solving for y.

Now that we have calculated the value of x we can calculate the value of y by plugging in the value of x into one of the equations and solving for y.

2x + y = 15

==> plug in x = 2

2(2) + y = 15

==> multiply 2 and 2

4 + y = 15

==> subtract 4 from both sides

y = 11

The solution is (2,11)

Checking our work:

To check our work we can plug in the value of x and y into both equations. If both are true then the solution is correct but if one or both are false then the solution is incorrect.

First equation; 2x + y = 15

==> plug in x = 2 and y = 11

2(2) + 11 = 15

==> multiply 2 and 2

4 + 11 = 15

==> add 4 and 11

15 = 15

Second equation; 7x - 2y = -8

==> plug in x = 2 and y = 11

7(2) - 2(11) = -8

==> multiply 7 by 2 and 11 by -2

14 - 22 = -8

==> subtract 22 from 14

-8 = -8

Both are correct therefore (2,11) is the correct solution

The figure (i) have a distance of 15.996 meters and a displacement of 13.892 meters and (ii) a distance of 480 centimeters and a displacement of 339.411 centimeters

The distance is the sum of the lengths that form a trajectory and the displacement is the distance between the initial and final point of a trajectory. Then, we have the following results for each case:

Case I

Distance

d = 5 m + 0.5π · (7 m)

d ≈ 15.996 m

Displacement

[tex]D = \sqrt{(12\,m)^{2}+(7 m)^{2}}[/tex]

D ≈ 13.892 m

Case II

Distance

d = 8 · (60 cm)

d = 480 cm

Displacement

[tex]D =\sqrt{(240\,cm)^{2}+(240\,cm)^{2}}[/tex]

D ≈ 339.411 cm

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Answer:

Step-by-step explanation:

A:  The expression 4x = 2x - 2 reduces to x = -1.  This is true for all values of y, since y is not a factor in this expression.

The two other equations intersect at point (-1, -4).  See the attached graph (Solutions2)

y = 4x

y = 2x−2

============

Mathematically, we can substitute the value of y from the first equation into the second:

y = 2x−2

(4x) = 2x−2

2x = -2

x = -1

The intersection of this two lines is (-1,-4).  Since x=-1, this is also the solution to 4x=2x-2, as per the above.

B:  See attached Result Table

C:  See GraphEquation2