Which of the following define the same Arithmetic Sequence using a Recursive Formula
and an Explicit Formula?
O a₁ = -23, an = an-1 + 12
and an-23 +12(n-1)
O a₁ = -100, an = an-1 + 1
and an 100-1(n-1)
=
O a₁ = -41, an = an-1 + 12
and an 12-41(n-1)
O a₁ = 50, anan-1-4
and an 50+ 4(n-1)

Answer:

-6,0 & -3,0

Step-by-step explanation:

Answer:

n = 8 or n = −6

Explanation:

First, isolate the absolute value:

5 − |n − 1| = −2

7 − |n − 1| = 0

7 = |n − 1|

Then, split this into two equations, since the result of the absolute value could be positive or negative:

7 = n − 1                           7 = −(n − 1)

8 = n                                7 = −n + 1

                                       n = −6

Answer:

[tex]\{-6\} \cup \{8\}[/tex]

Step-by-step explanation:

[tex]5 - |n - 1| = -2; \\ -|n - 1| = -2 - 5 \\ -|n - 1| = -7 \\ |n - 1| = 7 \\ \left \ [ {{n - 1 = 7} \atop {n - 1 = -7}} \right. \Leftrightarrow \left \ [ {{n = 7 + 1} \atop {n = -7 + 1}} \right. \Leftrightarrow \left \ [ {{n = 8} \atop {n = -6}} \right.[/tex]

Answer:

It's A and C

Step-by-step explanation:

the angles are 45, which is less than 90

Using a system of equations, it is found that the lengths of the sides of the triangle are given as follows:

0.91 feet, 0.73 feet, 1.23 feet.

A system of equations is when two or more variables are related, and equations are built to find the values of each variable.

In this problem, the variables are the lengths, given by x, y and z.

The length of one side of a triangle is 2 feet less than three times the length of its second side, hence:

y = 3x - 2.

The length of the third side is 3/4 of the sum of the lengths of the first two sides, hence:

[tex]z = \frac{3(x + y)}{4} = \frac{3(4x - 2)}{4}[/tex]

The perimeter of the triangle is 17.5 feet, hence:

[tex]x + y + z = 17.5[/tex]

[tex]x + 3x - 2 + \frac{3(4x - 2)}{4} = 17.5[/tex]

[tex]4x + \frac{3(4x - 2)}{4} = 19.5[/tex]

[tex]16x + 12x = 25.5[/tex]

x = 25.5/28

x = 0.91.

Then the other sides are:

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Answer:

24

Step-by-step explanation:

140 times .25 = 35

140 + 35 = 175

4,200 divided by 175 =

24

jobtestprep

The number of TV bought post-raise for $4,200 is 24 if the store manager decides to raise the TV price by 25% in order to increase the store's profits.

It's the ratio of two integers stated as a fraction of a hundred parts. It is a metric for comparing two sets of data, and it is expressed as a percentage using the percent symbol.

We have:

A home appliance store has recently seen an increase in TV sales.

The store manager decides to raise the TV price by 25% in order to increase the store's profits.

Original price of TV = $140

Price after increasing:

= 140 + 25% of 140

= $175

The number of TV bought post-raise for $4,200 = 4200/175

= 24

Thus, the number of TV bought post-raise for $4,200 is 24 if the store manager decides to raise the TV price by 25% in order to increase the store's profits.

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Question 5

Vertical angles are congruent. Therefore, [tex]3y=\boxed{150}[/tex]. The sum of two supplementary angles equals [tex]\boxed{180^{\circ}}[/tex].

Therefore, [tex]6x+150=\boxed{180}[/tex]

Question 6

[tex]\angle b-14=90-\angle b\\\\2\angle b=104\\\\\angle b=\boxed{52^{\circ}}[/tex]

Question 7

[tex]\angle d+32=180-\angle d\\\\2\angle d=146\\\\\angle d=\boxed{73^{\circ}}[/tex]

Question 8

[tex]7x-80=3x\\\\-80=-4x\\\\x=20\\\\\implies \boxed{m\angle 1=m\angle 3=60^{\circ}}[/tex]

Answer:

x = - 3 ± [tex]\sqrt{2}[/tex]

Step-by-step explanation:

x² + 6x + 7 = 0 ( subtract 7 from both sides )

x² + 6x = - 7

using the method of completing the square

add ( half the coefficient of the x- term )² to both sides

x² + 2(3)x + 9 = - 7 + 9

(x + 3)² = 2 ( take square root of both sides )

x + 3 = ± [tex]\sqrt{2}[/tex] ( subtract 3 from both sides )

x = - 3 ± [tex]\sqrt{2}[/tex]

Maribel leaves school at 3:10 to walk home, spent 20 minutes shopping and spent 30 minutes walking

An equation is an expression that shows the relationship between two or more variables and numbers.

Let us assume that Maribel reaches home at 4:00, hence:

Time spent walking = 4:00 - (3:10 + 20 minutes) = 4:00 - 3:30 = 30 minutes

Maribel leaves school at 3:10 to walk home, spent 20 minutes shopping and spent 30 minutes walking

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Answer:

See below

Step-by-step explanation:

x^2 +2x -8   =   (x-2)(x+4)

x^2 + 6x  - 16 = (x + 8)(x-2)        now you can cancel the ( x-2 ) to get

(x+4) / (x+ 8)

The value of b is -16 and the value of ac is 60 after comparing with the standard equation.

Any equation of the form [tex]\rm ax^2+bx+c=0[/tex] where x is variable and a, b, and c are any real numbers where a ≠ 0 is called a quadratic equation.

As we know, the formula for the roots of the quadratic equation is given by:

[tex]\rm x = \dfrac{-b \pm\sqrt{b^2-4ac}}{2a}[/tex]

We have a quadratic function:

= 3x² - 16x + 20

On comparing with standard function:

b = -16

a = 3

c = 20

ac = 3(20) = 60

Thus, the value of b is -16 and the value of ac is 60 after comparing with the standard equation.

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Answer:

18.75

Step-by-step explanation:

[tex]Area=\pi r^{2} \\Area=3(\frac{5}{2} )^{2} \\Area=18.75[/tex]

Answer:

A. 0.068

Step-by-step explanation:

First, 3 inches to miles. 3 inches in a mile is 0.00004735.

The snail moves 0.00004735 miles per minute.

Next, search how many minutes are there in a day. There is 1440 minutes in a day.

Multiply the 1440 and 0.00004735.

1440*0.00004735=0.068

The snail can move 0.068 miles per day if it doesn't take a break.

Hope this helps!

If not, I am sorry.

Answer:

19 inches

Step-by-step explanation:

So the perimeter of a triangle is the sum of the three sides. So the perimeter is [tex]\sqrt{65} + \sqrt{35} + \sqrt{26}[/tex] which is approximately 19.077 inches but in this case the answer is 19 inches

From the given recursive definition,

[tex]a_1 = 3[/tex]

[tex]a_2 = a_1 + 5 = 3 + 5 = 8[/tex]

[tex]a_3 = a_2 + 5 = 8 + 5 = 13[/tex]

[tex]a_4 = a_3 + 5 = 13 + 5 = 18[/tex]

[tex]a_5 = a_4 + 5 = 18 + 5 = 23[/tex]

The amount of bbd received for the given currency exchange rate is 6050  bbd.

The value of one country's currency in relation to the currencies of other countries or economic zones is known as the currency exchange rate.

The majority of currency exchange rates are free-floating and fluctuate according to market supply and demand.

There may be restrictions on some currency exchange rates since they are fixed to the value of other currencies.

According to the question,

Currency exchange rate: $1.00=5.50bbd

So, $1100=1100*5.50 bbd

               =6050 bbd

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the constant variation, K= 4

Step-by-step explanation:

i have replace the constant variation by the letter K

First step is to write down the information

y directly proprotional to x

So, y= Kx

Replace the value given for x and y to find k

y= -4 and x = -1

Kx= y

K( -1) = -4

K = -4 ÷ -1

K= 4

Further answer

if you are asked the connecting equation between y and x just replace the value of K in the equation

y= Kx

y= 4x

The equation of line passing through points (4.5. 0) and (0, 9) is y = -2x + 9.

Suppose the given points are (x_1, y_1) and (x_2, y_2), then the equation of the straight line joining both two points is given by

[tex](y - y_1) = \dfrac{y_2 - y_1}{x_2 - x_1} (x -x_1)[/tex]

The graph of the picture shows two clear points (4.5. 0) and (0, 9)

[tex](y - 0) = \dfrac{9 - 0}{0 - 4.5} (x -4.5)\\\\\\(y - 0) = \dfrac{9 }{- 4.5} (x -4.5)\\\\\\-4.5y = 9(x -4.5)\\\\-4.5y = 9x - 40.5\\\\y = -2x + 9[/tex]

Hence, the equation of line passing through points (4.5. 0) and (0, 9) is y = -2x + 9.

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In order to make the new flag, Lauren decided to triple the sides of the old flag in order to get a new one.

The old triangle is the smaller one. We can see that this triangle has increased by a factor of 3 on all sides.

We have 4 x 3= 12

2 x 3 = 6

7 x 3 = 21

The calculated values above is what produced the new larger flag.

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Answer:

see explanation

Step-by-step explanation:

sinX = [tex]\frac{opposite}{hypotenuse}[/tex] = [tex]\frac{YZ}{XY}[/tex] = [tex]\frac{\sqrt{119} }{12}[/tex]

cosX = [tex]\frac{adjacent}{hypotenuse}[/tex] = [tex]\frac{XZ}{XY}[/tex] = [tex]\frac{5}{12}[/tex]

Answer:

[tex](a)1600f+600w\\\\(b)1600\times2f+600\times2w[/tex]

Answer:

25.5 mph

Step-by-step explanation:

So Bradley's speed can be modeled by the equation y=2x+40 where y=speed, x=time in hours after noon, and b=initial speed

So 12:15 is 15 minutes after noon, which is also 0.25 or 1/4 of an hour after noon. This is the x-value. Plug this into the equation to get his speed at 12:15

y=2(0.25)+40

y=0.5+40

y=40.5

So his speed was 40.5 at the time and since he was going 15 miles over the speed limit, the speed limit is 15 less than his speed

40.5 - 15 = 25.5

Answer:

25.5 mph

Step-by-step explanation:

Given information:

Calculate Bradley's speed at 12.15 pm:

60 minutes = 1 hour

⇒ 15 minutes = 1/4 hour

⇒ speed at 12.15 pm = speed at 12.00pm + 1/4 of 2 mph

                                  = 40 mph + 0.5 mph

                                  = 40.5 mph

If he was 15 miles over the speed limit at 12.15 pm then:

⇒ speed limit = speed at 12.15pm - miles over the limit

                       = 40.5 mph - 15

                       = 25.5 mph

Therefore, the speed limit was 25.5 mph.

The missing step in the given solution to the inequality -x-3 < 13 + 3x is - 4x - 3 < 13

Incorrect steps:

- x - 3 < 13 + 3x

-4x < 16

X > -4

Correct steps:

- x- 3 < 13 + 3x

-x - 3x - 3 < 13

- 4x - 3 < 13

- 4x < 13 + 3

- 4x < 16

x < 16/-4

x > -4

Therefore, the missing step in the given solution to the inequality -x-3 < 13 + 3x is - 4x - 3 < 13

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The equation to model the situation is [tex]\mathbf{y = \dfrac{k}{x^2}}[/tex]. The constant for the variation is 2250.

The intensity of light from a lantern varies inversely to the square of the distance from the lantern.

From the given information:

Then:

[tex]\mathbf{y \alpha \dfrac{1}{x^2} }[/tex]

[tex]\mathbf{y = \dfrac{k}{x^2} }[/tex]   here, k = constant.

2.

If y = 90 W/m² when the distance x = 5m

Then:

[tex]\mathbf{90 = \dfrac{k}{(5)^2}}[/tex]

k = 90 × 25

k = 2250

c.

The equation to model the situation by using the constant variation is:

[tex]\mathbf{y = \dfrac{2250}{x^2}}[/tex]

d.

If the light intensity y = 40, then x is determined as:

[tex]\mathbf{40 = \dfrac{2250}{x^2}}[/tex]

[tex]\mathbf{x = \sqrt{\dfrac{2250}{40}}}[/tex]

x = 7.5 m

e.

The light is needed in (225 × 1000)m = 225000 km of illumination.

f.

The lantern required for the new light estimation is:

y = 2250/225000

y = 0.01 intensity

Therefore, we can conclude that to get an intensity of 1 W/m², we need to put 100 lanterns.

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Answer: Exponential

Step-by-step explanation:

Because every time x increases by 1, y increases by a factor of 3.

6/2 = 3

18/6 = 3

54/18 = 3

162/54 = 3

P.S.: I ANSWERED ONE OF YOUR PROBLEMS WITH EXACTLY THE DATA IN THIS TABLE BY COINCIDENCE HAHA

Hello,

Answer:

x = 13

Step-by-step explanation:

    7x + 5 + 5x + 19 = 180

⇔ 12x + 24 = 180

⇔ 12x = 180 - 24

⇔ 12x = 156

⇔ x = 156/12

⇔ x = 13

The function is C(F) = (F-32) * 5/9
This means the function C, is using variable F to get the output.
C is Celsius, F is Fahrenheit, so the answer is "the temperature of 76.1 degrees Fahrenheit converted to degrees Celsius"

Answer:

a

Step-by-step explanation:

The amount Cindy should increase for each dimension of the scaled model will be 12 meters.

The scale factor is defined as the proportion of the new image's size to that of the previous image. decision-making.

Given that:-

The scale model will be solved as follows:-

Present volume = 2 x 4 x 6 = 48 cubic meters

Let the lengths be increased by x meters now the new volume will be:-

( 2 + x ) ( 4 + x ) ( 6 + x ) = 48 x 84

( x² + 6x + 8 ) ( 6 + x ) = 48 x 84

( x³ + 44x + 12x² - 3984 ) = 0

By solving the cubic equation we will get the value of x = 12 meters.

Therefore the amount Cindy should increase for each dimension of the scaled model will be 12 meters.

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Answer:

Quadrants 1 and 4 EDIT: Quadrants 2 & 4

Step-by-step explanation:

Quadrant 1  : Edit: no

Quadrant 2  : Edit: yes

Quadrant 3 : No

Quadrant 4 : Yes

Answer:

b. x=2, -3

Step-by-step explanation:

So I'm assuming the two equations are: [tex]y=4-x^2[/tex] and [tex]x-y=2[/tex]

Since it's asking to solve to solve for x. Then we need to solve for y in one of the equations, so that's it's defined using x, then substitute that into the other equation, that way the only variable left is going to be the x variable.

So since y is already solved for in the first equation. I'll plug that into the second equation.

Original equation:

[tex]x-y=2[/tex]

Substitute 4-x^2 in as y

[tex]x-(4-x^2)=2[/tex]

Distribute the negative sign

[tex]x-4+x^2=2[/tex]

Organize it so it's in order by degree

[tex]x^2+x-4=2[/tex]

Subtract 2 from both sides

[tex]x^2+x-6=0[/tex]

So now we have a quadratic equation and we're trying to find the zeroes. You can use the quadratic equation, but since the only options are integers, we can easily factor this equation. So you need to look for factors of -6, which add up to 1. I like to think about it as find two numbers with a difference of 1, and then figure out which is going to be positive and which is going to be negative after. So knowing this you can easily see 3 and 2 have a difference of 1. Since the 1 is positive, that means the 3 has to be positive and the 2 has to be negative

Use the factors: 3 and -2 to rewrite the equation:

[tex](x+3)(x-2)[/tex]

Now set each factor equal to 0

x+3 = 0

x=-3

x-2=0

x=2

this gives you the two solutions: -3, and 2