Answer:
What are the choices?
Explanation:
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Explain why your weight would change if you went to the moon, but your mass wouldn’t.
The moon's gravitation force is determined by the mass and the size of the moon. Since the moon has significantly less mass than the Earth, it will not pull objects toward itself at the strength that Earth will.
Describe two similarities and two differences between electric and magnetic field lines. (Consider such things as where they originate and terminate, how they are related to the direction and strength of the field, whether they are closed curves or lines, and whether there's anything you can say about their flux through a closed surface.). Others
Answer:
Please see below as the answer is self- explanatory.
Explanation:
Similarities:The field vector is tangent to the field lines at any point of the trajectory.The density of field lines is proportional to the strength of the field.Differences:Electrostatic Field lines originate in charge distributions of positive charges and end in charge distributions of negative charges.Magnetic Field lines are closed lines, due to there are no isolated magnetic charges discovered yet.Electrostatic Field lines have the direction of the trajectory taken by a positive test charge.Magnetic Field lines have the direction defined by right-hand rule.Vector net flux of electrostatic field lines through a closed surface is equal to the net charge enclosed by the surface.Vector net flux of magnetic field lines through a closed surface is always zero.Similarities
Field vectorDensity of field linesDifferences
Dispersions of positive charges .No separated attractive charges.Electric and Magnetic field lines.Similarities:
The field vector is tangent to the field lines at any point of the trajectory. The density of field lines is relative to the quality of the field.
Differences:
Electrostatic Field lines begin in charge dispersions of positive charges and conclusion in charge dispersions of negative charges.
Magnetic Field lines are closed lines, due to there are no separated attractive charges found yet.
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When a 600 g mass is suspended from a spring, the spring stretches 1.2 cm. What is the spring constant of the spring?
Well first you need to know the formula for the spring force. It’s -1/2k*d
K being the constant
D being the displacement
We can actually find the force on the spring by calculating the weight of the block. It would be mass multiplied by gravity, convert the grams to kilograms first tho.
600/1000 = 0.6kg
0.6kg * 9.8 m/s^2 = 5.88N
Now plug everything into the equation, also convert the centimeters to meters:
1.2/100 = 0.012 meters
5.88 = -1/2k*(0.012)
5.88 = k*(0.006)
We could drop the negative sign because we really just want the magnitude of the spring constant.
K = 980N
1) A rigid tank contains 2 kg of 134a refrigerant at 800 kPa and 120°C. Determine tank volume and total internal energy.
Answer:
V = 0.07525 [m³]
U = 655.74 [kJ]
Explanation:
To solve this problem we must use the superheated refrigerant table for refrigerant 134a. The attached image shows the specific volume and specific internal energy values for a pressure of 800 [kPa] and a temperature of 120 [°C].
m = mass =2 [kg]
the specific volume = v = 0.037625 [m³/kg]
The volume of the tank can be found using the following expression:
V = v*m
V = 0.037625*2 = 0.07525 [m³]
The Specific internal energy = u = 327.87 [kJ/kg]
U = u*m
U = 327.87*2 = 655.74 [kJ]
A 10 [kg] object is dropped from rest. a. How far will it drop in 2 [s]?
Answer:
y=0.5 g t^2
=0.5*10*2^2
=20 m
A sled of mass m is coasting at a constant velocity on the ice covered surface of a lake. Three birds, with a combined mass 0.5m, gently land at the same time on the sled. The sled and birds continue sliding along the original direction of motion. How does the kinetic energy of the sled and birds compare with the initial kinetic energy of the sled before the birds landed
Complete Question
A sled of mass m is coasting at a constant velocity on the ice covered surface of a lake. Three birds, with a combined mass 0.5m, gently land at the same time on the sled. The sled and birds continue sliding along the original direction of motion. How does the kinetic energy of the sled and birds compare with the initial kinetic energy of the sled before the birds landed?
a) The final kinetic energy is one half of the initial kinetic energy.
b) The final kinetic energy is one third of the initial kinetic energy.
c) The final kinetic energy is one quarter of the initial kinetic energy.
d) The final kinetic energy is one ninth of the initial kinetic energy.
e) The final kinetic energy is equal to the initial kinetic energy
Answer:
The correct option is b
Explanation:
From the question we are told that
The mass of the sled is m
The mass of the three birds is [tex]m_b = 0.5 m[/tex]
Generally from the law of momentum conservation,
The initial momentum of the boat = final momentum of the boat
Hence
[tex]m * v = (m_b+ m) * v_2[/tex]
=> [tex]m v = (0.5m+ m) * v_2[/tex]
=> [tex]m v = 1.5m* v_2[/tex]
Here v is the velocity of the boat before the birds landed and [tex]v_2[/tex] is the velocity after the birds landed
So
[tex]v_2 = \frac{2}{3} v[/tex]
Generally the initial velocity of the boat before the birds landed is mathematically represented as
[tex]K_i = \frac{1}{2} * m * v ^2[/tex]
Generally the final velocity of the boat when the birds have landed is mathematically represented as
[tex]K_f = \frac{1}{2} * (m_b + m ) * v_2^2[/tex]
=> [tex]K_f = \frac{1}{2} * (0.5m + m ) * (\frac{2}{3} v)^2[/tex]
=> [tex]K_f = \frac{1}{2} * 1.5m * (\frac{2}{3} v)^2[/tex]
=> [tex]K_f = \frac{1}{2} * 1.5m * \frac{4}{9} v^2[/tex]
=> [tex]K_f = \frac{1}{2}m v^2 * \frac{1}{3}[/tex]
Comparing this equation with that of the initial kinetic energy
=> [tex]K_f = \frac{1}{3} K_i[/tex]
The kinetic energy of the sled and birds is one-third the initial kinetic energy of the sled before the birds landed.
What is kinetic energy?When an object is in motion, then the energy possessed by the object at the state of motion is known as its kinetic energy.
Given data -
The combined mass of three birds is, M = 0.5m.
Let m be the mass of the sled. Then applying the conservation of linear momentum as,
The initial momentum of the boat = final momentum of the boat
mv = (M + m)v'
v is the velocity of the boat before the birds landed and v' is the velocity after the birds landed.
mv = (0.5m + m)v'
mv = 1.5mv'
v = 3/2 v'
or
v' =2/3v
The initial kinetic energy of the boat before the birds landed is mathematically represented as
[tex]K_{1}= \dfrac{1}{2}mv^{2}[/tex]
And the final kinetic energy of the boat when the birds have landed is mathematically represented as,
[tex]K_{2}=\dfrac{1}{2}(M+m)v'^{2}\\\\K_{2}=\dfrac{1}{2}(1.5m) \times 4/9v^{2}\\\\K_{2}=\dfrac{1}{3} \times \dfrac{1}{2}mv^{2}\\\\K_{2}=\dfrac{1}{3} \times K_{1}[/tex]
Thus, we can conclude that the kinetic energy of the sled and birds is one-third the initial kinetic energy of the sled before the birds landed.
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Why is it important to warm up your muscles?
Warming up the muscles increases lactic acid build up
Warming up the muscles increases temperature and flexibility of your muscles Warming up the muscles increases your risk of injury
All of the above
8. In explosives, potential energy is generally
stored in the form of
a thermal energy
b. electromagnetic energy
c. nuclear energy
d. chemical energy
Answer:
In explosives,potential energy is in the stored form of chemical energy.
what are Newton's 3 laws
Answer:
Newton 3 laws
Explanation:
1.object will not change its motion unless a force acts on it . 2.the force on an object is equal to it's time mass on acceleration. 3. When 2 o jecys interact they apply forces to each other of equal.
Glucose is a carbohydrate.
True
0r False
Answer: True
Explanation: Glucose is a carbohydrate.
PLEASE PLEASE HELP PICTURE INCLUDED
Answer:
a is the answer
Explanation:
A ball is thrown upward in the air with an initial velocity of 40 m/s. How long does it take to
reach back to the point it was thrown from?
Answer:
You need the definition of acceleration (a=Vf-Vi/t) and 1 equation of linear motion (deltaX = Vi×t + 1/2×a×t^2). Since you know a is constant (gravity) and you know your initial Vi to be 40 m/s and your final velocity Vf to be zero (maximum height), then you can use thhe definition of acceleration to find time.
-9.81m/s^2 = (0-40m/s)/t
t = (-40)/(-9.81) s
t = 4.077s
Now that you have time, you should know all but deltaX in the equation of linear motion.
dX = (40m/s)(4.077s) + (1/2)(-9.81m/s^2)(4.077s)^2
dX = (163.099m) — (81.549m)
dX = 81.55m
2
A crane has an arm to which is attached a frictionless pulley. A cable passes over the pulley and
supports a load of 10 kN as shown.
frictionless pulley
104N
30
30°
crane arm
load
10 KN
The crane arm exerts a force F on the pulley.
What is the value of F?
C
8.7 KN
10 KN
D
A
17 kN
B
5.0 KN
Answer:
17kN
Explanation:
The force of 10 kN in the cable and the load of 10 kN both have a component along the crane arm.
The force F exerted by the crane arm on the pulley is the sum of these 2 components.
Component of force in cable along the crane arm = 10 cos 30°
Component of load along the crane arm = 10 cos 30°
Considering the forces on the pulley,
F = 10 cos 30° + 10 cos 30°
Force F = 17.32 kN = 17 kN
Can you help me please! Love you
Answer:
I think its B. wait...U love ME?????
define density with a suitable formula
Answer:
ratio between m/v
or d= m/v
m= mass
v= volume
A race car driver travelling at 15m*s^-1 accelerates at a constant value for 10.0s. She is now driving at a speed of 35 m*s^-1 What was her acceleration? Give your answer in m*s^-2 to one significant figure . Do not include units with your answer.
The driver speeds up with acceleration a so that
35 m/s = 15 m/s + a (10.0 s)
Solve for a :
20 m/s = a (10.0 s)
a = (20 m/s) / (10.0 s)
a = 2 m/s²
A yo-yo is attached to the end of a string. A professional yo yo is spinning it by the string around in a circular
motion. All of a sudden he lets go of the string. What direction is the yo yo moving in initially?
Answer:
counter-clockwise
Explanation:
Emmy kicks a soccer ball up at an angle of 45° over a level field. She watches the ball's trajectory and notices that it lands, two seconds after being kicked, about 20 m away to the north. Assume that air resistance is negligible, and plot the horizontal and vertical components of the ball's velocity as a function of time. Consider only the time that the ball is in the air, after being kicked but before landing. Take "north" and "up" as the positive x ‑ and y ‑directions, respectively, and use g≈10 m/s2 for the downward acceleration due to gravity.
Answer:
v_y = 10 - 10t
v_x = 10 m/s
Explanation:
This is a projectile launch where the x axis and y axis will be treated independently.
Now, towards the north on the x-axis, there will be no acceleration and so the speed is constant
So, vₓ = v₀ₓ
Whereas, on the vertical y - axis, the acceleration due to gravity with be negative since it's in a downward direction.
Thus, the equation is;
v_y = v_oy - gt
Now, the initial velocity component will be;
cos 45 = v₀ₓ/v₀
And sin 45 = v_₀y/v₀
Thus, we have;
v₀ₓ = v₀(cos 45)
Also, v_oy = v₀(sin 45)
Now, the initial velocity would be gotten from the equation of range which is;
R = (v₀² × sin 2θ)/g
Making v₀ the subject, we have;
v₀ = √(Rg/sin 2θ)
We are given;
R = 20 m
g = 10 m/s²
θ = 45°
Thus;
v₀ = √[20 × 10/(sin (2 × 45))]
v₀ = √200
v₀ = 14.14 m/s
Thus;
v₀ₓ = 14.14(cos 45) = 10 m/s
v_oy = 14.14(sin 45) = 10 m/s
Earlier we saw that;
v_y = v_oy - gt
Thus;
v_y = 10 - 10t
Also,we saw that;
vₓ = v₀ₓ
Thus;
v_x = 10 m/s
For the graph, we will use times of t = 0, 0.2, 0.4, 0.6, 0.8, 1.0, 1.2
Thus, for each of those values of t, we will have the following values of v_oy
t (s) v_oy (m / s)
0 10
0.2 8
0.4 6
0.6 4
0.8 2
1.0 0
1.2 -2
Graph is attached
A rubber cord catapult has cross-sectional area
25mmand initial length of rubber cord is 10c.
Its is stretched to 5cm and then released to
project a missile of mass 5gm. Taking
Yubber = 5x108N/m² velocity of projected
missile is :
(1) 20ms -
(2) 100ms
(3) 250ms
(4) 200ms)
When a heavy football player and a light one run into each other, who exerts more force?
Answer:
When a heavy football player and a light one run into each other, does the lighter player really exert as much force on the heavy player s the heavy player exerts on the light one. Yes. The interaction between the two players, the force each exerts on the other have equal strength.
Explanation:
which produces wave particles that move and displace one another
Answer:
a guitar?
Explanation:
which graph best demonstrates the general relationship between mass and temperature similar to the trend of thermal energy absorbed by your sand and water samples
Answer: the first one
Explanation: got it right on edg
Answer:
The first graph
Explanation:
Correct on Edge 2022! :]
Add the following vectors:
(a) (12, 5) + (6, 3)
(b) (−3, 8) + (6, −2)
(c) (3, 8, −7) + (7, 2, 17)
(d) (a, b, c) + (d, e, f)
Answer:
a. (18,8)
b. (3, 6)
c. (10, 10, 10)
d. (a+d, b+e, c+f)
Give me brainliest for this... Thanks
This is about acceleration, velocity and all that mumbo jumbo
Which best depicts the data?
1, From 0 to 2 seconds, Anna experienced negative acceleration.
2, From 3 to 6 seconds, Elan accelerated while Anna did not.
3, From 6 to 8 seconds, Elan accelerated faster than Anna.
4, From 8 to 10 seconds, Elan experienced negative acceleration.
Answer:
[tex]3. \: From \: 6 \: to \: 8 \: seconds, \: Elan \: \\ accelerated \: \: faster \: than \: Anna. [/tex]
Which statement describes S waves? A. They move side to side.B.They arrive betore P waves. C. They travel through liquids D. They occur at Earth's surtace.
Answer: they move side to side
Explanation:
i took the test
Planets A and B have the same size, but planet A is half the mass of planet B.
Which statement correctly explains the weight you would experience on each
planet?
A. You would weigh the same on both planets because the planets
are the same size.
B. You would weigh less on planet A because it has less mass than
planet B.
C. You would weigh the same on both planets because your mass
would be the same on both.
D. You would weigh more on planet A because it has less mass than
planet B.
Answer:
B
Explanation:
The more mass an object has, the more gravity it has.
The statement which correctly explains the weight you would experience on each planet is: B. You would weigh less on planet A because it has less mass than planet B.
Weight can be defined as the force acting on a body or an object as a result of gravity.
Mathematically, the weight of an object is given by the formula;
[tex]Weight = mg[/tex]
Where;
m is the mass of the object.g is the acceleration due to gravity.Hence, we can deduce that the weight and gravity acting on an object is highly dependent on the mass of an object.
Therefore, the higher the mass in a planet, the higher the gravity existing there.
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need help ASAP. please and thank you
the graph below represents the relationship between velocity and time for an object moving along a straight line.
What is the magnitude of the object's acceleration?
1. 5.0 m/s^2
2. 8.0 m/s^2
3. 10. m/s^2
4. 20. m/s^2
Answer:
10. m/s^2
Explanation:
40-(-10)= 50
50/5 =10
This question can simply be answered by using the slope of the velocity-time graph.
The correct answer for the magnitude of the acceleration is "3. 10 m/s²".
Since the graph between the velocity and the time is in the form of a straight line. Hence, the acceleration can be calculated as the slope of this line. We will use the first and last point of the line to calculate the slope (acceleration):
[tex]Acceleration = Slope = \frac{v_2 - v_1}{t_2-t_1}[/tex]
where,
v₁ = initial velocity from the graph = - 10 m/s
v₂ = final velocity from the graph = 40 m/s
t₁ = initial time from the graph = 0 s
t₂ = final time from the graph = 5 s
Therefore,
[tex]Acceleration = \frac{40\ m/s\ -\ (-\ 10\ m/s)}{5\ s\ -\ 0\ s}[/tex]
Acceleration = 10 m/s²
The attached picture shows the types of a velocity-time graph.
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why cats cannot run on smoth table
Answer:
bc of their paw pads, they don't get the traction they need in order to be able to get a firm grip to push off of on the table for each bound
Explanation:
Erica is working in the lab. She wants to remove the fine dust particles suspended in a sample of oil. Which method is she most likely to u
Answer: Option A is your answer
Explanation: