which number line represents the solution of 1 - 2x ≥ 3

Step-by-step explanation:

remainder=4

quotient=x+1

divisor=x-2

dividend=x^2 -x +2

Answer:

0 = 20

Step-by-step explanation:

4(2x−3)−2x=6x+8

8−12−2=6+8

combine like terms.

8x−12−2x=6x+8

6−12=6+8

Add 12 to both sides of the equation

6x−12=6x+8

6−12+12=6+8+12.

Answer:

-51

Step-by-step explanation:

Answer:

option d

Step-by-step explanation:

Your should have attached the equation for answer to be explained

Answer:

12 in

Step-by-step explanation:

3in + 3in + 3in + 3in = 12

Answer:

Squaring

Step-by-step explanation:

Answer:

You told me to resolve this question

The height of the tower is 452.66 ft

The situation will form 2 right angle triangle. One above the line of sight

and one below the line of sight.

Therefore,

Using trigonometric ratio,

tan ∅ = opposite / adjacent side

tan 30° = h(top of the tower) / 425

h(top of the tower) = tan 30 × 425 = 245.373864406  

tan 26° = h(bottom of the tower) / 425

h(bottom of the tower) = 425 × tan 26° = 207.28635014

Therefore,

Height of tower = h(top of the tower) + h(bottom of the tower)

Height of tower = 245.37 + 207.29 = 452.66 ft

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Answer:

x + 8

Step-by-step explanation:

Expanding the equation

-4(x-2)+5x = -4(x-2)+5x

= -4x+8+5x

= -4x+5x + 8

= x+8

Answer:

Second test=88

Third test=89    Hope this helps please mark brainliest it helps a lot! Thanks!

Step-by-step explanation:

According to the question, here we got to know that John scored 72 points in the first test

In the second he scored higher than the 1st test

In the third he scored 1 mark more than the second test

His average in the three tests was 83

So,

Let's the marks scored in the 2nd test be x

Hence, in the third test he got x + 1

Average is 83

[tex] \frak{Average = \frac{{1}^{st} \: test + {2}^{nd} \: test + {3}^{rd} \: test }{3} } \\ \\ \dashrightarrow \frak{83 = \frac{72 + x + x + 1}{3}} \\ \\ \dashrightarrow \frak{83 = \frac{73 + 2x}{3}} \\ \\ \dashrightarrow \frak{249 = 73 + 2x } \\ \\ \dashrightarrow \frak{249 - 73 = 2x} \\ \\ \dashrightarrow \frak{249 = 73 + 2x } \\ \\ \dashrightarrow \frak{x = \frac{176}{2} } \\ \\ \dashrightarrow \frak{249 = 73 + 2x } \\ \\ \dashrightarrow \frak{249 - 73 = 2x} \\ \\ \dashrightarrow \frak{249 = 73 + 2x } \\ \\ \star \qquad \boxed{ \green{\frak{x = 88}}} \\ \\ \sf{ \underline{{2}^{nd} \: test }} : \\ \\ \boxed{ \red{88}} \\ \\ \sf{ \underline{{3}^{rd} \: test }} : \\ \\ \rightarrow x + 1 \\ \\ \rightarrow 88 + 1 \\ \\ \boxed{ \red{ 89 }}[/tex]

Answer:

x = - 2

Step-by-step explanation:

Don't let the points disturb you. They are actually meant to confuse you.

Answer:

y = 2x + 2

Step-by-step explanation:

for each rise of 4 in y

there is a run of 2 in x

m = rise/run

m = 4/2

m = 2

when x = 0, y = 2

therefor the y-intercept, b = 2

y = mx + b

y = 2x + 2

Answer:

80o, 60o, 40o

Step-by-step explanation:

The sum has to add up to 180 degrees because of the three sides and this is what matches.

Answer:

Let the given angles of the triangle be 4x, 3x and 2x.

We know that the sum of all interior angles of a triangle is 180°.

Therefore,

Hence, the angles of the triangle are -

If a package is damaged, the probability that it came from Manufacturer A is 62.5%.

Given that two manufacturers supply paper cups to a catering service, and manufacturer A supplied 100 packages and 5 were damaged, while Manufacturer B supplied 50 packages and 3 were damaged, to determine, if a package is damaged, the probability that it came from Manufacturer A, the following calculation must be performed:

Therefore, if a package is damaged, the probability that it came from Manufacturer A is 62.5%.

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Answer:

x = 8, y = 89/9

Step-by-step explanation:

Because of parallel lines, some angles are the same, see the attached image. That also means that (12x-28) + (9y-77) = 180 because they are half of an angle. So:

(12x-28) + (9y-77) = 180 ->

12x + 9y = 185.

Then,

(7x+12) = (12x-28) ->

x = 8.

We can plug that into the last equation:

12(8) + 9y = 185 ->

y = 89/9

:)

Answer:

Given:In quadrilateral WXYZ , and bisect each other at point A.

Prove: Quadrilateral WXYZ is a parallelogram.

Statement

Reason

1. and bisect each other. given

2. WA = YA

XA = ZA

definition of bisection

3. m∠YAZ = m∠XAW

Vertical Angles Theorem

4.

SAS criterion for congruence

5. ∠ YWX ≅ ∠WYZ

Corresponding angles of congruent triangles are congruent.

6. ||

converse of Alternate Interior Angles Theorem

7. m∠XAY = m∠ZAW

Vertical Angles Theorem

8. ∆XAY ≅ ∆ZAW

SAS criterion for congruence

9. ∠XZW ≅ ∠ZXY

Corresponding angles of congruent triangles are congruent.

10. ||

converse of Alternate Interior Angles Theorem

11. Quadrilateral WXYZ is a

parallelogram.

definition of parallelogramTriangles can be similar or congruent. Similar triangles will have congruent angles but sides of different lengths. Congruent triangles will have completely matching angles and sides. Their interior angles and sides will be congruent. Testing to see if triangles are congruent involves three postulates, abbreviated SAS, ASA, and SSS.

Answer:

2/1/2 you need 2and 1/2 of chicken

Answer:

Step-by-step explanation:

A square has an area of base times height which is identical to base.

If x is the length of a side, A = x•x = x²

x² = 25

x = √25

x = 5 yards

Considering that each of 2, 4, and 6 is twice as likely to come up as each of 1, 3, and 5, the probability distribution is given by:

[tex]P(X = 1) = 0.1111[/tex]

[tex]P(X = 2) = 0.2222[/tex]

[tex]P(X = 3) = 0.1111[/tex]

[tex]P(X = 4) = 0.2222[/tex]

[tex]P(X = 5) = 0.1111[/tex]

[tex]P(X = 6) = 0.2222[/tex]

The symbolic distribution is:

[tex]P(X = 1) = y[/tex]

[tex]P(X = 2) = x[/tex]

[tex]P(X = 3) = y[/tex]

[tex]P(X = 4) = x[/tex]

[tex]P(X = 5) = y[/tex]

[tex]P(X = 6) = x[/tex]

The sum of all probabilities is 1, hence:

[tex]3x + 3y = 1[/tex]

Simplifying by 3:

[tex]x + y = 0.3333[/tex]

[tex]y = 0.3333 - x[/tex]

2, 4, and 6 is twice as likely to come up as each of 1, 3, and 5, hence:

[tex]x = 2y[/tex]

[tex]x = 2(0.3333 - x)[/tex]

[tex]3x = 0.6667[/tex]

[tex]x = \frac{0.6667}{3}[/tex]

[tex]x = 0.2222[/tex]

Then:

[tex]y = 0.3333 - x = 0.3333 - 0.2222 = 0.1111[/tex]

Hence, the distribution is:

[tex]P(X = 1) = 0.1111[/tex]

[tex]P(X = 2) = 0.2222[/tex]

[tex]P(X = 3) = 0.1111[/tex]

[tex]P(X = 4) = 0.2222[/tex]

[tex]P(X = 5) = 0.1111[/tex]

[tex]P(X = 6) = 0.2222[/tex]

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Answer:

A

Step-by-step explanation:

so first substitute 2 into the x  so 3*2=6 then and 5+6= 11 then substitute 11 into the y and boom it works. (3,13) doesnt work because if you substitute them in 3*3=9 then 9+5=14 but we needed 13 so only (2,11) works.

Answer:

x = 2

Step-by-step explanation:

The given point is (-2, 2).  A horizontal line passing through this point is x = 2.

Answer:

42.20

Step-by-step explanation:

132 ×0.32

=42.24

rounded off it give 42.20

Answer:

the first recipe

Step-by-step explanation:

We can answer by finding the ratio of nuts to cereal. The one that has the higher ratio of nuts to cereal is the nuttier one.

Recipe 1: 2 1/2 cups of nut per 5 cups of cereal.

nuts to cereal ratio = 2 1/2 : 5 = 1 : 2

Recipe 2: 1 cups of nuts per 3 cups of cereal.

nuts to cereal ratio = 1 : 3

1 : 2 is a higher ratio than 1 : 3

Answer: the first recipe

Answer:

90π

Step-by-step explanation:

282.74 / π

282.74 / 3.14159 = 90

282.74 = 90π

Simplify the coefficient of z on the left side. We do this by rationalizing the denominators and multiplying them by their complex conjugates:

[tex]\dfrac{3-2i}{1+i} - \dfrac{5+3i}{1+2i} = \dfrac{3-2i}{1+i}\cdot\dfrac{1-i}{1-i} - \dfrac{5+3i}{1+2i}\cdot\dfrac{1-2i}{1-2i}[/tex]

[tex]\dfrac{3-2i}{1+i} - \dfrac{5+3i}{1+2i} = \dfrac{(3-2i)(1-i)}{1-i^2} - \dfrac{(5+3i)(1-2i)}{1-(2i)^2}[/tex]

[tex]\dfrac{3-2i}{1+i} - \dfrac{5+3i}{1+2i} = \dfrac{3 - 2i - 3i + 2i^2}{1-(-1)} - \dfrac{5 + 3i - 10i - 6i^2}{1-4(-1)}[/tex]

[tex]\dfrac{3-2i}{1+i} - \dfrac{5+3i}{1+2i} = \dfrac{3 - 5i + 2(-1)}2 - \dfrac{5 - 7i - 6(-1)}5[/tex]

[tex]\dfrac{3-2i}{1+i} - \dfrac{5+3i}{1+2i} = \dfrac{1 - 5i}2 - \dfrac{11 - 7i}5[/tex]

[tex]\dfrac{3-2i}{1+i} - \dfrac{5+3i}{1+2i} = \dfrac{1 - 5i}2\cdot\dfrac55 - \dfrac{11 - 7i}5\cdot\dfrac22[/tex]

[tex]\dfrac{3-2i}{1+i} - \dfrac{5+3i}{1+2i} = \dfrac{5 - 25i - 22 + 14i}{10}[/tex]

[tex]\dfrac{3-2i}{1+i} - \dfrac{5+3i}{1+2i} = -\dfrac{17 + 11i}{10}[/tex]

So, the equation is simplified to

[tex]-\dfrac{17+11i}{10} z = \dfrac12 - \dfrac{2i}5[/tex]

Let's combine the fractions on the right side:

[tex]\dfrac12 - \dfrac{2i}5 = \dfrac12\cdot\dfrac55 - \dfrac{2i}5\cdot\dfrac22[/tex]

[tex]\dfrac12 - \dfrac{2i}5 = \dfrac{5-4i}{10}[/tex]

Then

[tex]-\dfrac{17+11i}{10} z = \dfrac{5-4i}{10}[/tex]

reduces to

[tex]-(17+11i) z = 5-4i[/tex]

Multiply both sides by -1/(17 + 11i) :

[tex]\dfrac{-(17+11i)}{-(17+11i)} z = \dfrac{5-4i}{-(17+11i)}[/tex]

[tex]z = -\dfrac{5-4i}{17+11i}[/tex]

Finally, simplify the right side:

[tex]-\dfrac{5-4i}{17+11i} = -\dfrac{5-4i}{17+11i} \cdot \dfrac{17-11i}{17-11i}[/tex]

[tex]-\dfrac{5-4i}{17+11i} = -\dfrac{(5-4i)(17-11i)}{17^2-(11i)^2}[/tex]

[tex]-\dfrac{5-4i}{17+11i} = -\dfrac{85 - 68i - 55i + 44i^2}{289-121(-1)}[/tex]

[tex]-\dfrac{5-4i}{17+11i} = -\dfrac{85 - 68i - 55i + 44(-1)}{410}[/tex]

[tex]-\dfrac{5-4i}{17+11i} = -\dfrac{41 - 123i}{410}[/tex]

[tex]-\dfrac{5-4i}{17+11i} = -\dfrac{41 - 41\cdot3i}{410}[/tex]

[tex]-\dfrac{5-4i}{17+11i} = -\dfrac{1 - 3i}{10}[/tex]

So, the solution to the equation is

[tex]z = -\dfrac{1-3i}{10} = \boxed{-\dfrac1{10} + \dfrac3{10}i}[/tex]