Which method will NOT get you to the point (4,3.5)?
A. Starting at the origin, go 3.5 spaces to the right and then 4 spaces up.
B. Starting at the origin, go 3.5 spaces up and then 4 spaces to the right.
C. Starting at the origin, go 4 spaces to the right and then 3.5 spaces up.
D. Put one finger on 4 on the x-axis, and put another finger halfway between 3 and 4 on the y-axis. Move the first finger up and the second finger to the right until they meet.

Answers

Answer 1

Answer:

A. Starting at the origin, go 3.5 spaces to the right and then 4 spaces up.

Step-by-step explanation:

if you were to plot this then the point would be (3.5,4) instead of (4,3.5)

Answer 2

Starting at the origin, go 3.5 spaces to the right and then 4 spaces up will not get you to the point (4,3.5) but will get you (3.5, 4). The correct option is A.

What are coordinates?

Coordinates are a pair of integers (Cartesian coordinates), or occasionally a letter and a number, that identify a certain place on a grid, often referred to as a coordinate plane.

We have the point (4, 3.5).

And let the point (x, y).

By comparing,

we get,

x = 4 and y = 3.5

That means, the value in the x coordinate is 4 and y coordinate is 3.5.

As the signed distance from the origin in the direction along the x-axis, the first value x is known as the x-coordinate (or x-component). The x-coordinate indicates the distance from the y-axis to the right (if x is positive) or left (if x is negative).

Additionally, the y-coordinate indicates how many steps are needed to up either positively or negatively on the y-axis.

So, the point is 4 point right from the origin and 3.5 point up from the origin.

Therefore, starting at the origin, go 3.5 spaces to the right and then 4 spaces up will not get you to the point (4,3.5)

To learn more about the coordinates;

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Step-by-step explanation:

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Area of trapezoid is: [tex]\mathbf{11x^3y^2}[/tex]

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Step-by-step explanation:

Image 1:

We need to Find area of trapezoid.

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where h is height and b₁ and b₂ are parallel sides.

Looking at the figure we get:

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[tex]Area=\frac{1}{2}h(b_1+b_2)\\Area=\frac{1}{2}\times 2xy(7x^2y+4x^2y)\\Area=\frac{1}{2}\times 2xy(11x^2y)\\Area=\frac{1}{2}\times 22x^3y^2\\Area=11x^3y^2[/tex]

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Looking at figure:

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[tex]Perimeter = Sum\:of\:lengths\:of\:all\:sides\:of\:triangle\\Perimeter = 3ab+10a^2b+4a^2b\\Perimeter=3ab+14a^2b[/tex]

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How to solve...

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9w + 4 = 2w + 32

       - 4 =        -   4

--------------------------

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---------------------------

     7w = 28

     7w = 7w

---------------------------

       w = 4

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Answers

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