Which line is being represented by the graph?
A
y = 3/4 X -3
B
y = 3/4x + 4
C
y = -3/4x + 4
D
y = -3/4 x - 3

Answer:

x = 61°

Step-by-step explanation:

since the triangle has 2 congruent sides then it is isosceles with the 2 base angle being congruent, both x°

the sum of the 3 angles in the triangle = 180° , then

x + x + 58° = 180°

2x + 58° = 180° ( subtract 58° from both sides )

2x = 122° ( divide both sides by 2 )

x = 61°

Answer:

Zero

Step-by-step explanation:

the line is not going up or down therefore there is no slope

Answer:

Step-by-step explanation:

Note. It is assumed * is x in the function notation.

Substitute the value of x into equation:

Correct answer choice is B

Answer:

14 Minutes

Step-by-step explanation:

1.68 divided by 0.12 is 14 or Multiply 0.12 by 14 and you get 1.68.

Answer:

see the attachment photo!

to get the equation of any straight line, we simply need two points off of it, let's use the provided points in the picture above.

[tex](\stackrel{x_1}{0}~,~\stackrel{y_1}{-3})\qquad (\stackrel{x_2}{1}~,~\stackrel{y_2}{1}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{1}-\stackrel{y1}{(-3)}}}{\underset{run} {\underset{x_2}{1}-\underset{x_1}{0}}} \implies \cfrac{1 +3}{1 +0}\implies 4 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-3)}=\stackrel{m}{4}(x-\stackrel{x_1}{0}) \\\\\\ y+3=4x\implies y=4x-3[/tex]

Answer:

-13.4+2.3c

Step-by-step explanation:

Add the like terms.

-6.5-5.1-1.8=-13.4

-13.4+2.3c

Hope this helps!

If not, I am sorry.

Answer:

-148

Step-by-step explanation:

Hello!

We can evaluate by plugging in -3 for x, and -7 for y in the expression [tex]3x^3 - 2x^2 + 7y[/tex]

The evaluated value is -148.

Answer:

-148

Step-by-step explanation:

there you go hope it helps :)

The combination of the radicals 9√x - 3√x will be equal to 6√x.

The radical is the symbol that is used to represent the root in the expression n√x.

The given radicals can be combined as shown below,

9√x - 3√x

Taking √x as the common term,

= √x(9-3)

= 6√x

Hence, the combination of the radicals 9√x - 3√x will be equal to 6√x.

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To get system B, the second equation in system A was replaced by the sum of that equation and the first equation multiplied by 5. The solution to system B will be the same as the solution to system A.

System A equations:

-x - 2y = 7  ------ (1)

5x - 6y = -3  ------(2)

We multiply the first equation by 5, to get :

-5x - 10y = 35 -----(3)

The sum of equation (2) and equation (3) gives:

-16y = 32

y = 32/-16

y = -2

Thus, solution of system B is;

-x - 2(-2) = 7

-x + 4 = 7

x = -3

So, the solution of system B is (-3, -2), that means the solution of both systems are same.

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Answer:

  0, for q ≠ 0 and q ≠ 1

Step-by-step explanation:

Assuming q ≠ 0, you want to find the value of x such that ...

  q^x = 1

This is solved using logarithms.

__

  x·log(q) = log(1) = 0

The zero product rule tells us this will have two solutions:

  x = 0

  log(q) = 0   ⇒   q = 1

If q is not 0 or 1, then its value is 1 when raised to the 0 power. If q is 1, then its value will be 1 when raised to any power.

_____

Additional comment

The applicable rule of logarithms is ...

  log(a^b) = b·log(a)

Answer:

Mike started off the day with $27.

Step-by-step explanation:

Using the information given to us, we can set up an equation. Knowing that Mike ended the day with $7, and the amount of money that he spent and received can help us set up an equation. The amount of money that he started the day off with, is unknown, and recognized as x.  [tex]7=x-22-3+5[/tex]

To solve this, we can simply solve the numbers that we know on the right hand side, to get this:

[tex]7=x-20[/tex]

Now, to get our final answer we must isolate x. We can do this by simply adding 20 to both sides. This cancels out the -20 on the right, and makes the 7 on the left become 27.

[tex]27=x[/tex]

Therefore, Mike started the day off with $27.

Answer:

its option c (7)

Step-by-step explanation:

trust your bro

Answer:

[tex]C)~ 7[/tex]

Step-by-step explanation:

[tex]\text{Given that,}~~ (x_1,y_1) = (k,3)~ \text{and}~ (x_2 ,y_2) = (2,3)\\\\\text{Distance,}~ \\\\~~~~~~~~d= \sqrt{(x_2 -x_1)^2 + (y_2 -y_1)^2}\\\\\implies 5=\sqrt{(2-k)^2 + (3-3)^2}\\\\\implies 5=\sqrt{(2-k)^2 +0}\\\\\implies 5 = \sqrt{(2-k)^2}\\\\\implies 5=|2-k|\\\\\implies \pm 5=2-k \\\\\implies 2-k =5~~~~~~\text{or}~~~~~~~~2-k = -5\\\\\implies k = 2-5~~~~~~\text{or}~~~~~~~~k = 2+5\\\\\implies k = -3~~~~~~~~~\text{or}~~~~~~~~k = 7[/tex]

Answer:

look at the photo

...................................

Answer:

I need it in English please so I can helps

The appropriate domain of the population function is 0 ≤ t ≤ 14

The function is given as:

P(t) = 3(2)^t

From the question, we understand that the maximum time is 2 weeks.

2 weeks in days is 14 days

This means that the function is valid for 14 days i.e. t = 0 to 14

Hence, the appropriate domain of the population function is 0 ≤ t ≤ 14

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Answer:

Step-by-step explanation:

Limits exist for:

[tex]\lim_{x \to4 \4} \frac{x^2 -x-12}{4-x}[/tex] = [tex]\frac{(x-4)(x+3)}{4-x}[/tex] = ( - 1 )( x + 3 ) = - 7

[tex]\lim_{x \to \ 2} \frac{x^2 +2x-8}{2-x}[/tex] = [tex]\frac{(x+4)(x-2)}{2-x}[/tex] = ( - 1 )( x + 4 ) = - 6

[tex]\lim_{x \to2 } \frac{x^2 +3x - 10}{x^2 -4}[/tex] = [tex]\frac{(x+5)(x-2)}{(x+2)(x-2)}[/tex] = [tex]\frac{x+5}{x+2}[/tex] = [tex]\frac{7}{4}[/tex]

Answer: The correct answer is D.

Step-by-step explanation: A and B are incorrect because you can plug in 5 for x to get 2, and there are multiple values that can be greater than 5. C is incorrect because you cannot reach lower than 2. Therefore, the correct answer is D.

The y values are all greater than or equal to 2.

The correct option is D.

Given,

Function : f(x) = |x − 5| + 2

Here,

A function is a law that relates a dependent and independent variable.

The function is

f(x) = |x − 5| + 2

The domain of the function is all negative and positive integers.

The range is all the possible function values, the function value will always be greater than or equal to 2.

At x = 5 , f(x) = 2

Therefore, the y values are all greater than or equal to 2. The correct option is D.

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Answer:

-2

Step-by-step explanation:

coefficient is the number without a letter next to it

if we paint the tank on the outside, we'll be covering SA of surface area, however we're also painting it on the inside, so the area inside assuming the material thickness is negligible, we'll be covering SA as well, so we'll be needing SA + SA = 2SA ft² of paint to do the whole thing.

so, its diameter is 10, that means its radius is 5.

[tex]\textit{surface area of a cylinder}\\\\ SA=2\pi r(h+r)~~ \begin{cases} r=radius\\ h=height\\[-0.5em] \hrulefill\\ h=12\\ r=5 \end{cases}\implies \begin{array}{llll} SA=2\pi (5)(12+5)\implies SA=170\pi \\\\\\ \stackrel{\textit{twice as much}}{2SA=340\pi } \end{array}[/tex]

now, hmmm we know that 1 gallon can do 200 ft², how many gallons are there in 340π ft²?

[tex]\begin{array}{ccll} gallons&ft^2\\ \cline{1-2} 1 & 200\\ x& 340\pi \end{array} \implies \cfrac{1}{x}~~=~~\cfrac{200}{340\pi } \\\\\\ 340\pi =200x\implies \cfrac{340\pi }{200}=x\implies \stackrel{gallons}{5.34}\approx x[/tex]

The value of the annual premium will be $1134.40

From the information given, the annual base premium will be:

= Liability premium + Collision premium + Comprehensive premium

= $383 + $240 + $86

= $709

The annual premium will be:

= Annual base premium × Driver eating factors

= $709 × 1.60

= $1134.40

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[tex]~~~(2x-6)(2x+6)\\\\=(2x)^2 -6^2~~~~~~~~~~~~~~~~~~~~~;[a^2 -b^2 = (a+b)(a-b)]\\\\=4x^2 -36[/tex]

Answer:

x = -π

Step-by-step explanation:

An asymptote line is a line that the graph does not intercept or pass through but rather approaches it. An asymptote line also is considered to be a line of undefined value of function because if an asymptote is x = a then f(a) is undefined.

The question gives a function y = csc(x) which is in another form, y = 1/sin(x).

We have to find the value of x that turns the function in undefined and that x-value will be your asymptote.

From a unit circle, we know that sin(-π) = -sin(π) = 0. Since sin(-π) = 0 —> y = csc(-π) = 1/sin(-π) = 1/0

Now we find out that at x = -π, csc(x) is not defined and hence, an asymptote is x = -π

Answer: y = 12x - 43

Step-by-step explanation: i hope that helps

The exponential function is given by [tex]I(t) = 50000(1.15)^t[/tex]. The initial investment of $50,000 grows at a rate of about 15% annually.

An equation is an expression that shows the relationship between two or more numbers and variables.

An exponential function is in the form:

y = abˣ

Where a is the initial value and b is the rate of increase per period.

Let I(t) represent Jennifer’s investment account balance after t years, hence:

a = 50000, b = 100% + 15% = 115% = 1.15

[tex]I(t) = 50000(1.15)^t[/tex]

The exponential function is given by [tex]I(t) = 50000(1.15)^t[/tex]. The initial investment of $50,000 grows at a rate of about 15% annually.

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Answer:

1/7

Step-by-step explanation:

The trigonometric function gives the ratio of different sides of a right-angle triangle. The area of the triangle is 55.4256 ft².

The trigonometric function gives the ratio of different sides of a right-angle triangle.

[tex]\rm Sin \theta=\dfrac{Perpendicular}{Hypotenuse}\\\\\\Cos \theta=\dfrac{Base}{Hypotenuse}\\\\\\Tan \theta=\dfrac{Perpendicular}{Base}[/tex]

where perpendicular is the side of the triangle which is opposite to the angle, and the hypotenuse is the longest side of the triangle which is opposite to the 90° angle.

For the given triangle the length of AB and BC can be written as,

[tex]\rm Sin \theta=\dfrac{Perpendicular}{Hypotenuse}\\\\\\Sin(30^o) = \dfrac{AB}{AC}\\\\\\AB = Sin(30^o) \times 16 \\\\\\AB=8\rm\ ft[/tex]

[tex]Cos \theta=\dfrac{Base}{Hypotenuse}\\\\\\Cos(30^o) = \dfrac{BC}{AC}\\\\\\BC = Cos(30^o) \times AC\\\\\\BC = 13.8564\rm\ ft[/tex]

Now, the area of the triangle is,

Area of triangle = 0.5× 8 × 13.8564 = 55.4256 ft²

Hence, the area of the triangle is 55.4256 ft².

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The quotient of 21.49 ÷ 3.76 using compatible numbers is approximately 5.69

Quotients are result derived from the ratio of two rational or integers. Given the expression

21.49 ÷ 3.76

Convert to fraction

21.49 ÷ 3.76 = 2140/100  ÷  376/100
21.49 ÷ 3.76 = 2140/376

21.49 ÷ 3.76 =  5.69

Hence the quotient of 21.49 ÷ 3.76 using compatible numbers is approximately 5.69

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