Answer:
i think its magma ajani i looked it up... and chelsey said u had corona so if its true hope u get better bro
Explanation:
Answer the following question: In a space shuttle, the CO2 that the crew exhales is removed from the air by a reaction within canisters of lithium hydroxide. Let's assume that one astronaut exhales about 825. L of CO2 daily. What mass of water will be produced when this amount reacts with LiOH? The other product of the reaction is Li2CO3. When answering this question include the following:
Have both the unbalanced and balanced chemical equations.
Explain how to find the molar mass of the compounds.
Explain how the balanced chemical equation is used to find the ratio of moles (hint: step 3 in the video).
Explain how many significant figures your answer needs to have.
The numerical answer
Your Answer:
Answer:
See Explanation
Explanation:
The unbalanced reaction equation is;
CO2(g) + LiOH(aq) + Li2CO3(aq) + H2O(l)
The balanced chemical reaction equation;
CO2(g) + 2LiOH(aq) + Li2CO3(aq) + H2O(l)
The molar mass of each compound is the sum of the relative atomic masses of the atoms of the elements that compose the compounds.
For CO2
12 + 16(2) = 12 + 32 = 44 g/mol
For LiOH
7 + 16 + 1 = 24 g/mol
For Li2CO3
2(7) + 12 + 3(16) = 74 g/mol
For H2O
2(1) + 16 = 18 g/mol
From the balanced chemical reaction equation, the mole ratio is 1:2:1:1. This is obtained from the stoichiometric coefficient of each reactant in the balanced chemical reaction equation.
From the question;
1 mole of CO2 occupies 22.4 L
x moles of CO2 occupies 825 L
x = 1 mole * 825 L/22.4 L
x = 36.8 moles
From the reaction equation;
1 mole of CO2 produces 1 mole of water
36.8 moles of CO2 produces 36.8 moles of water
Mass of 36.8 moles of water = 36.8 moles * 18 g/mol
= 662 g of water
The answer must have three significant figures because that is the same number of significant figures to which values were given in the question.
If you dilute 18.8 mL of a 3.5 M solution to make 296.6 mL of solution, what is the molarity of the dilute solution?
Answer:
0.22M
Explanation:
We will be using the law of dilutions. We are simply increasing the amount of solvent to create a larger volume of solution.
So: moles before dilution = moles after dilution & [tex]moles_{concentrated} = moles_{dilute}[/tex]. And M = moles/liter of solution, so if we express this as moles = M x [tex]L_{soln}[/tex].
That is how we derive the formula we will be using: [tex]M_{concentrated} * Vol_{conc} = M_{dilute} * Vol_{dilute}[/tex]
or
[tex]M_{1} * Vol_{1} = M_{2} * Vol_{2}[/tex]
Applying this formula to our problem, we can substitute the variables with the given values to find the molarity of the dilute solution.
M1 = 3.5M
V1 = 18.8mL
M2 = ?
V2 = 296.6mL
Equation: (3.5M)(18.8mL) = (296.6mL)(M2)
==> 65.8M*mL = 296.6mL * M2
==> M2 = (65.8 M*mL)/296.6mL
==> M2 = 0.22M
Why would a doctor most likely restrict a patient's contact with other people while the patient receives internal
radiation?
The patient's stress and anxiety would be eliminated.
High levels of radiation can diffuse through the patient's skin.
Social contact would increase the effect of the radiation treatment.
Radioactive material can leave the patient's body through saliva, sweat, and urine.
D. Radioactive material can leave the patient’s body through saliva, sweat, and urine.
I took the test n got it right ¯\_(ツ)_/¯
1) The Specific Heat Capacity at 25°C of Gold is 0.129 / (g°C)
a) What is the molar Specific Heat Capacity of Gold in J/(mol °C)
Answer:
25.4 J/mol
Explanation:
The specific heat of any substance is referring to the amount of energy required to raise 1 gram of that substance 1 degree kelvin. Molar heat capacity is referring to the amount of energy required to raise 1 mole of that substance 1 degree kelvin. So in order to solve for molar heat capacity of gold we must convert from grams of gold to moles of gold.
( 0.129 J /g) ( 196.97 g/ m o l ) = 25.4 J m o l
196.97 is the molar mass of gold which can be found on the Periodic Table of Elements. Because grams are located on both sides of the denominator they cancel out leaving us with our new units of J/mol.
Identify the correct equilibrium constant expression
for this equation:
C6H1206(s) + 60,(g) <—>6C02(g)+ 6H2O(g)
Answer: Keq= [CO2]^6[H2O]^6/ [O2]^6
Explanation:
The correct equilibrium constant expression for this equation C6H1206(s) + 60,(g) <—>6C02(g)+ 6H2O(g) will be
keq = 6[co2] 6[h2o] / [c6h1206] 6[o].
What is the equilibrium constant?All reactions tend towards the state of chemical equilibrium. It is the point at which both the forward process and the reverse process are taking place at the same rate.
Since the forward and reverse rates are equal, hence the concentrations of the reactants and products will be constant at the equilibrium state. Here, it is important to remember that even though the concentrations are constant at equilibrium.
The double half-arrow sign we use for writing the reversible reaction equations. It is represented as ⇌ a sign of equilibrium.
therefore, the correct equilibrium constant expression will be C6H1206(s) + 60,(g) <—>6C02(g)+ 6H2O(g)
Learn more about the equilibrium constant, here:
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#SPJ2
Which of the following is an example of chemistry in forensic science?
Estimating the trajectory and impact of bullet
Calculating the force needed for a body to have fallen at a specific location Using blood spatter patterns to establish how a body was stabbed
Extending DNA strands to match samples
Answer:
Extending DNA strands to match samples
Due today! Why is it a good idea to have floating cities?
A: We are running out of land
B: We need it for pollution cleanup
C: Oceans are rising
D: It's a sustainable way to live
Answer:
in my opinion I think the answer the be "A"
What is the formula mass of ZrF4?
Answer:
167.217g/mol
Explanation:
Formula mass is defined as the mass in grams that a mole of a molecule weighs. To solve the formula mass of ZrF₄ we require the molar mass of Zr and of F (Molar mass Zr: 91.225g/mol; F: 18.998g/mol)
In this molecule, there is 1 mole of Zr and 4 moles of F. The formula mass is:
Zr = 1*91.225g/mol = 91.225g/mol
F = 4*18.998g/mol = 75.992g/mol
Formula mass: 91.225g/mol + 75.992g/mol
167.217g/molb) A piece of solid gold was heated from 274K to 314K using 55.7J of energy to raise the
temperature. What mass of gold was present?
Answer:
Explanation:
So we know q = mc[tex]\Delta[/tex]T.
q = 55.7 J
c = 0.129j/g°C
and [tex]\Delta[/tex]T = 314-274 = 40°C.
and m is mass which can solve since we got every other variable. We will get m = 10.8g.
Cacti and succulents are better adapted
for surviving in the desert than oak
trees because cacti
A. allow more sunlight to reach the soil
B. prevent the plant from producing
flowers
c. encourage the release of carbon
dioxide from the stems
D. reduce the amount of water lost
through evaporation
Q1
Answer:
answer is C
Explanation:
encourage the release of carbon dioxide from the stems
A beaker contains 0.125 L of a 3.00 M solution. If the volume goes up to 0.325 L, what is the new molarity?
Answer:
1.15 M
Explanation:
Step 1: Given data
Initial volume (V₁): 0.125 LInitial concentration (C₁): 3.00 MFinal volume (V₂): 0.325 LFinal concentration (C₂): ?Step 2: Calculate the final concentration of the solution
We want to prepare a dilute solution from a concentrated one by adding water. We can calculate the concentration of the dilute solution using the dilution rule.
C₁ × V₁ = C₂ × V₂
C₂ = C₁ × V₁/V₂
C₂ = 3.00 M × 0.125 L/0.325 L = 1.15 M
An analytical chemist is titrating 111.0 mL of a 0.3700 M solution of aniline (C6H5NH2) with a 0.3500 M solution of HNO3. The pK_b of aniline is 9.37. Calculate the pH of the base solution after the chemist has added 79.1 mL of the HNO_3 solution to it.
Answer:
The answer is "4.31"
Explanation:
aniline millimoles [tex]= 111 \times 0.37 = 41.07[/tex]
added [tex]HNO_3[/tex] millimoles [tex]= 79.1 \times 0.35 = 27.685[/tex]
[tex]\to 41.07 - 27.685 = 13.385[/tex] millimoles aniline left
[tex]\to 27.685[/tex] millimoles salt formed
total volume[tex]= 111 + 79.1 = 190.1\ mL\\\\[/tex]
[tex]\to [aniline] = \frac{13.385}{190.1} = 0.07 \ M\\\\\to [salt] =\frac{ 27.685}{ 190.1} = 0.146\ M\\\\\to pOH = pKb + \frac{\log [salt]}{ [base]}\\\\\to pOH = 9.37 + \frac{\log [0.146]}{[0.07]}\\\\\to pOH = 9.69\\\\\to pH = 14 - 9.69\\\\\to pH = 4.31\\[/tex]
I NEED HELP WITH THIS ASAPP
Chemical formula for Aluminum Oxide
Answer: Al₂O₃
Explanation:
Learning Task 3: Choose the letter of the correct answer to complete the
statement. Write your answer on your notebook.
a.
1.
is the oldest form where an image is transferred from
one surface to another.
a. Painting
b. Drawing
C. Printmaking
2. Screen frame commonly made of
covered tightly with
a mesh.
Wood
b. Plastic
C. Paper
3.
technique makes use of woven mesh to support an ink-
blocking stencil
a. Silkscreen printing
b. Intaglio printing
c. Photo emulsion printing
4 .
A tool that usually made of vinyl or rubber blade is called
a. Mesh
b. Squeegee
C. Emulsion
The oldest form where an image is transferred from one surface to another is printmaking, Screen frame commonly made of covered tightly with wood, technique makes use of woven mesh to support an ink blocking stencil is Silkscreen printing and A tool that usually made of vinyl or rubber blade is called Squeegee.
What is art?Art is a technique in which we use different kinds of things like paintings, printings, drawings and do exhibition for the decoration purpose.
Print is the oldest art form where an image is transferred from one surface to another surface by applying liquid material on one surface and get the print of that on another surface.Screen frames are generally about 70% of the content of wood material.Silk screen painting is used to transfer ink onto a object, leaving areas made impermeable to the ink by a blocking stencil.In the squeegee paintings, a scrapping implement is used which is made up of rubber blade and vinyl and known as squeegee.Hence C, A, A and B is the correct answers of the given questions.
To know more about paintings, visit the below link:
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What is the reaction of Dimethylamamine + acetic acid
A group of students working in a high school chemistry lab believe they have discovered a new element! How exciting! Upon further testing by scientists (with better equipment), it is found that the new element contains 74 protons and 110 neutrons.
please help illl mark brainlst (no links)
seafloor spreading allows the new formation of rock by:
A ) New rocks floating to the surface of the crust.
B ) The oceanic plates hit each other causing new rocks to fall off.
C ) Magma cooling on the crust.
D ) Seafloor spreading does not create new rocks.
Answer:
A ) New rocks floating to the surface of the crust.
TRUST
Why does understanding the Rock Cycle help us to plan living on the ocean? answer before it's too late!
Answer:
Learning the rock cycle and understanding the processes involved helps all of us. This is how soil forms, through the breakdown of rocks. We need soil to survive—imagine trying to grow vegetables without it. This is an immediate connection to the food chain
How many moles is 30 grams of CO2?
Answer:
68
Explanation:
The table shows characteristics of two plants, Plant A and Plant B.
Answer:
Plant A
Explanation:
what is the formula for tin(III) sulfate
Answer:
SnSO₄
Explanation:
Tin(II) sulfate is a chemical compound. It is a white solid that can absorb enough moisture from the air to become fully dissolved, forming an aqueous solution; this property is known as deliquescence.
Answer:
please give me brainlist and follow
Explanation:
SnSO₄
When iron nail is ground into powder, it’s mass
Answer:
(a) The mass of an object remains the same always. It is independent of its location. In this case, an iron nail is ground into powder.
Explanation:
please mark this answer as brainliest
Opinión personal sobre El Planeta
la tierra nuestro planeta es el único del sistema solar que sabe que mantiene vida: vida que es increíblemente diversa,
Please I will give branliest. The question is in the photo
Answer:
a. Br2(I)+2 KI(aq)》2KBr(aq)+I2
a layer of paint can be used to prevent iron rusting true or false
Answer:
true
Explanation:
This layer will prevent moisture from reaching the metal and therefore prevent rust. oil paint especially
A chemist makes 380. mL of magnesium fluoride (MgF2) working solution by adding distilled water to 20.0 mL of a 18.8 L stock solution of magnesium fluoride in water.
Calculate the concentration of the chemist's working solution.
Round your answer to 3 significant digits
Answer:
0.99 μmol/L
Explanation:
From the question given above, the following data were obtained:
Volume of stock solution (V₁) = 20 mL
Concentration of stock solution (C₁) = 18.8 μmol/L
Volume of diluted solution (V₂) = 380 mL
Concentration of diluted solution (C₂) =?
The concentration of the diluted solution can be obtained as follow:
C₁V₁ = C₂V₂
18.8 × 20 = C₂ × 380
376 = C₂ × 380
Divide both side by 380
C₂ = 376 / 380
C₂ = 0.99 μmol/L
Therefore, the concentration of the diluted solution the chemist is working on is 0.99 μmol/L
what is the mass of 1.5 x 10^21 silicon atoms?
Answer:
0. 070g
Mass of 1 Si atom =28.08/6.022*1023
So mass 1.5 *1021*4.6629*10-23
Answer:
[tex]\boxed {\boxed {\sf 0.070 \ g \ Si}}[/tex]
Explanation:
We are given a value of atoms and asked to find the mass. We can complete this in 2 steps.
1. Convert Atoms to Moles
First, we have to convert atoms to moles. We use Avogadro's Number or 6.022 × 10²³. This is the number of particles (atoms, molecules, formula units, etc.) in 1 mole of a substance.
In this case, the particles are silicon atoms. We can set up a proportion.
[tex]\frac { 6.022 \times 10^{23} \ atom \ Si }{1 \ mol \ Si}[/tex]
Multiply by the value of atoms given.
[tex]1.5 \times 10^{21} \ atom \ Si *\frac { 6.022 \times 10^{23} \ atom \ Si }{1 \ mol \ Si}[/tex]
Flip the ratio. This allows the atoms of silicon units to cancel and leave the moles of silicon.
[tex]1.5 \times 10^{21} \ atom \ Si *\frac {1 \ mol \ Si } {6.022 \times 10^{23} \ atom \ Si}[/tex]
[tex]1.5 \times 10^{21}*\frac {1 \ mol \ Si } {6.022 \times 10^{23} }[/tex]
[tex]\frac {1.5 \times 10^{21} \ mol \ Si } {6.022 \times 10^{23} }[/tex]
[tex]0.002490866822 \ mol \ Si[/tex]
2. Convert Moles to Grams
Next, we convert the moles to grams. We use the molar mass, which is found on the Periodic Table. This value is the number of grams in 1 mole of a substance. Look for silicon (Si).
Si: 28.085 g/molUse this value as a ratio.
[tex]\frac {28.085 \ g \ Si}{1 \ mol \ Si}[/tex]
Multiply by the number of moles we calculated.
[tex]0.002490866822 \ mol \ Si *\frac {28.085 \ g \ Si}{1 \ mol \ Si}[/tex]
The moles of silicon units cancel, so we are left with grams.
[tex]0.002490866822 *\frac {28.085 \ g \ Si}{1}[/tex]
[tex]0.002490866822 *{28.085 \ g \ Si}[/tex]
[tex]0.06995599469 \ g \ Si[/tex]
3. Round
Finally we must round our answer. The original value has 2 significant figures, so our answer must have the same. For the number we calculated, that is the thousandth place.
[tex]0.069\underline95599469 \ g Si[/tex]
The 9 tells us to round the other 9 to a 0, then the 6 to a 7.
[tex]0.070 \ g \ Si[/tex]
The mass of 1.5 × 10²¹ silicon atoms is 0.070 grams of silicon.
A chemist titrates 0.200 M NaOH, strong base, with 50.00 ML of 0.150 M HCI, strong acid. How many mL of NaOH will be required to titrate to the endpoint
[tex](normality \: of \: acid)×(volum \: of \: acid) = (normality \: of \: base)×(volum \: of \: base)[/tex]
0.15N × 50mL = 0.2N × (Vbase)
75mL = Volum of base
37.5mL of NaOH will be required to titrate 0.200 M NaOH, strong base, with 50.00 ML of 0.150 M HCI, strong acid to the endpoint.
How to calculate volume?The volume of a solution can be calculated using the following formula:
C1V1 = C2V2
Where;
C1 = initial concentrationC2 = final concentrationV1 = initial volumeV2 = final volumeC1 = 0.200MC2 = 0.150MV1 = ?V2 = 50mL0.2 × V1 = 0.150 × 50
0.2V1 = 7.5
V1 = 7.5/0.2
V1 = 37.5mL
Therefore, 37.5mL of NaOH will be required to titrate 0.200 M NaOH, strong base, with 50.00 mL of 0.150 M HCI, strong acid to the endpoint.
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Draw a structural formula for the organic product formed by treating butanal with the following reagent: NaBH4 in CH3OH/H2O You do not have to consider stereochemistry. You do not have to explicitly draw H atoms. Do not include lone pairs in your answer. They will not be considered in the grading. Include counter-ions, e.g., Na , I-, in your submission, but draw them in their own separate sketcher. Do not draw organic or inorganic by-products.
Answer:
Please find the solution in the attachment file.
Explanation: