Which is the standard equation for a circle centered at the origin with radius r?

Answer:

No

HOPE THIS HELPS

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Step-by-step explanation:

10+10=20

20+10=30

30+0=30

Answer:

Step-by-step explanation:

3) (21²-6²)½ = 20.1 cm

4) (10²+7²)½ =12.2 cm

5) (6.5²-2.7²)½ = 5.9 cm

Answer:

x = -3

Step-by-step explanation:

Step-by-step explanation:

a) unsuitable - the precision should have been about 0.030 kg (about an ounce)

b) unsuitable - the stopwatch should have a precision of 0.001 s

c) just about right, although I wouldn't mind it if its precision is of 0.05 mm

d) unsuitable - color matching requires much finer control so I would go with 1/8 cup precision.

Answer:

I'm not sure but if you want the answer download Socratic it will definitely help you find the answer.

Answer:

$509.97 is Rosa's regular pay

Answer:

a. 10.08

b. 0.0576

Answer:

J or the last one

Step-by-step explanation:

Other two wouldn't work since -37 is the least and 37% is 0.37 which is less than 0.72

Step-by-step explanation:

Rewrite the expression using only positive exponents. Then, evaluate the expression. 3^{-2}

Answer:

4 tens, 3 twenties

Step-by-step explanation:

4 tens  ($40) and 3 ($60)  twenties work. I’m sorry I don’t have a formula for it though.

Answer:

[tex]\huge\boxed{\sf Probability = \frac{3}{8} }[/tex]

Step-by-step explanation:

[tex]\displaystyle Probability = \frac{Number \ of \ codes \ with \ 2 \ 0s}{Total \ number \ of \ codes}[/tex]

According to the fundamental principle of counting, to find the total number of codes, we need to multiply the number of options we have for each digits by the number of digits. Hence, we have two options for each digit ( 1 and 0 ) and we have 4 digits. So,

= 2 * 2 * 2 * 2

= 16 possible codes (Total)

Now, Codes with two zeroes:

= 0101,0011,1100,1010,1001,0110 (Maximum number of codes for 2 0s)

Hence, The probability:

Probability = 6 / 16

Probability = 3 / 8

[tex]\rule[225]{225}{2}[/tex]

Hope this helped!

Answer:

Solution given:

A triangle PQR is right angled at R, with hypotenuse{h}PQ=80cm

and

base[b]PR=60cm.

perpendicular [P]= QR

by using Pythagoras law

h²=p²+b²

80²=QR²+60²

QR²=80²-60²

QR=[tex]\sqrt{2800}[/tex]

QR=20[tex]\sqrt{7}[/tex]=52.9=53cm

QR=53cm.

Answer:

[tex]\sqrt{a} + \frac{2\sqrt{ya} }{a} - 2\sqrt{y}[/tex]

Step-by-step explanation:

Simplify each term.

The rationalized and simplified form of the expression (√a + 2√y) / (√a - 2√y) is (a + 4√ay + 4y) / (a - 4y).

To rationalize the denominator and simplify the expression (√a + 2√y) / (√a - 2√y), we can use a technique called rationalizing the denominator.

First, we multiply both the numerator and denominator by the conjugate of the denominator, which is (√a + 2√y). This is done to eliminate the square root in the denominator.

(√a + 2√y) / (√a - 2√y) * (√a + 2√y) / (√a + 2√y)

Expanding the numerator and denominator:

(√a * √a) + (√a * 2√y) + (2√y * √a) + (2√y * 2√y) / ((√a * √a) - (√a * 2√y) + (2√y * √a) - (2√y * 2√y))

Simplifying:

a + 2√ay + 2√ay + 4y / (a - 2√ay + 2√ay - 4y)

Combining like terms:

a + 4√ay + 4y / (a - 4y)

Therefore, the rationalized and simplified form of the expression (√a + 2√y) / (√a - 2√y) is (a + 4√ay + 4y) / (a - 4y).

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Answer:  10

Step-by-step explanation:

Arranged data

7,10,10,11,11,12,12,13,13,17

Range= Highest value - Lowest Vlue

Highest value=17

Lowest value =7

Range=17-7

Range=10

Answer:

[tex]Answer:  10

Step-by-step explanation:

Arranged data

7,10,10,11,11,12,12,13,13,17

Range= Highest value - Lowest Vlue

Highest value=17

Lowest value =7

Range=17-7

Range=10 [/tex]

hope it is helpful to you

Answer:

Area of length Vb = 25 square units

Area of segment Vb  = 26 square units

Step-by-step explanation:

Area of length Vb = theta/360 * 2πr  

Area of length Vb = 120/360 * 2*3.14 * 12  

Area of length Vb = 1/3 * 75.36  

Area of length Vb = 25 square units  

Ares of length Vb is 25.1 sq. units

Area of shaded portion = Area of sector VUB - Area of triangle VUB

Area of sector VUB = theta/360 * πr²

Area of sector VUB = 120/360 * 3.14*144

Area of sector VUB = 1/3 * 452.16

Area of sector VUB =150.72

Area of triangle VUB  = r²sintheta

Area of sector VUB = = 12²sin 120

Area of sector VUB = = 144(0.8660)

Area of sector VUB = 124.71

Area of the shaded segment = 150.72 - 124.71

Area of the shaded segment = 26.01

Area of the shaded segment = 26 sq. unitsAnswer:

Area of length Vb = 25 square units

Area of segment Vb  = 26 square units

Step-by-step explanation:

Area of length Vb = theta/360 * 2πr

Area of length Vb = 120/360 * 2*3.14 * 12

Area of length Vb = 1/3 * 75.36

Area of length Vb = 25 square units

Ares of length Vb is 25.1 sq. units

Area of shaded portion = Area of sector VUB - Area of triangle VUB

Area of sector VUB = theta/360 * πr²

Area of sector VUB = 120/360 * 3.14*144

Area of sector VUB = 1/3 * 452.16

Area of sector VUB =150.72

Area of triangle VUB  = r²sintheta

Area of sector VUB = = 12²sin 120

Area of sector VUB = = 144(0.8660)

Area of sector VUB = 124.71

Area of the shaded segment = 150.72 - 124.71

Area of the shaded segment = 26.01

Area of the shaded segment = 26 sq. units

Step-by-step explanation:

x + 7 = 92

x = 92 - 7

x = 85

The value of x is 85

Answer:

42 + 42 + z = 180

Step-by-step explanation:

Note that:

Base angles in an isosceles triangle are equal in measure.

The sum of angles in a triangle is 180°.

Thus, the equation would be

42 + 42 + z = 180

Answer:

8,-1,-9,-18,-27,-36

and so on i would think it would be -27

Step-by-step explanation:

Answer:

-28

Step-by-step explanation:

other answer off by one

Answer:

3 x 10^3

Step-by-step explanation:

1.485 / 4.95 = 0.3

10^6 : 10^2 = 10^(6-2) = 10^4

0.3 x 10^4

3 x 10^3

The quotient of 1.485 x 10^6 and 4.95 x 10^2 expressed in science notation is 3 x 10^3

The number b shows the order, which is the most important figure for which scientific notation is used. It tells us how much order large or small a value is in powers of 10.

Its value in terms of power of 10 is known, which helps in easy comparison of quantities differing by a large value.

WE need to find the quotient of 1.485 x 10^6 and 4.95 x 10^2 expressed in science notation.

So we have;

1.485 / 4.95 = 0.3

Therefore,

10^6 : 10^2

= 10^(6-2)

= 10^4

Hence, the scientific notation written as;

0.3 x 10^4

= 3 x 10^3

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Answer:

4/ 5

cos A = AB/ AC

= 24/ 30

= 4/ 5

that is option A

Answer:

y>-2x-3

Step-by-step explanation:

I think, not sure.

Answer:

X is equal to 4

Answer:

48

Step-by-step explanation:

[tex]a = 12, \ b = 6, \ c = 3\\\\b^2 - c^2 + (a+ b+c) = 6^2 - 3^2 + (12 +6+3) = 36-9+21 = 48[/tex]

Answer:

2-12+(++)

b^{2}-1c^{2}+(a+b+c)

b2−1c2+(a+b+c)

Simplify: 1

Eliminate redundant parentheses

2−12+(++)

b^{2}-1c^{2}+(a+b+c)

b2−1c2+(a+b+c)

2−12+++

b^{2}-1c^{2}+a+b+c

b2−1c2+a+b+c

Solution: 2−12+++

b^{2}-1c^{2}+a+b+c

b2−1c2+a+b+c

Answer:

44

Step-by-step explanation:

the steps are in the pic above

whats the rest of the question?

Answer:

[tex]sin(A+B) = \frac{1431}{1769}[/tex]

Step-by-step explanation:

sin(A+B) = sinA cosB + cosA sinB ------(1)

[tex]given : cos A = \frac{20}{29}, \ sinB = \frac{60}{61}[/tex]

First we will find sinA and cosB

[tex]We \ know \ sin^2 A + cos^2A = 1\\\\sin^2 A = 1 - cos^2A = 1 - (\frac{20}{29})^{2} = \frac{841-440}{841} = \frac{441}{841}\\\\sinA =\frac{21}{29}[/tex]

[tex]sin^2B +cos^2B = 1\\\\cos^2B = 1 - sin^2B = 1 - (\frac{60}{61})^2 = \frac{3721-3600}{3721} = \frac{121}{3721}\\\\cosB = \frac{11}{61}[/tex]

Substitute all values in (1)

[tex]sin(A+B) =sinAcosB + cosAsinB[/tex]

               [tex]=(\frac{21}{29} \times \frac{11}{61} )+ (\frac{20}{29}\times \frac{60}{61})\\\\=\frac{231}{1769} + \frac{1200}{1769}\\\\= \frac{1431}{1769}[/tex]

Hi there!  

»»————-　★　————-««

I believe your answer is:  

[tex]\huge\boxed{2\sqrt{3}}[/tex]

»»————-　★　————-««  

Here’s why:  

[tex]\boxed{\text{Simplifying the square root of 12}}\\\\\rightarrow\sqrt{12}\\\\\text{4 can be factored out of 12.}\\\\\rightarrow\sqrt{4(3)}\\\\\text{Two '2's can be factored out of 4.}\\\\\rightarrow\sqrt{2*2*3}\\\\\rightarrow\sqrt{2^2(3)}\\\\\text{Pulling out the terms from under the radical...}\\\\\rightarrow\boxed{2\sqrt{3}}[/tex]

»»————-　★　————-««  

Hope this helps you. I apologize if it’s incorrect.  

Given :

A motorboat travels 9 miles downstream (with the current) in 30 minutes.

The return trip upstream (against the current) takes 90 minutes.

To Find :

The speed of stream and motorboat.

Solution :

Let, speed of stream is u and speed of motorboat is v.

Now, we know distance is same in both case.

Distance( downstream ) = speed × time

[tex]9 = ( v +u ) \times 0.5\\\\v + u = 18[/tex]....1)

Distance( upstream ) = speed × time

[tex]9 = ( v- u ) \times 1.5\\\\v-u = 6[/tex]....2)

Solving equation 1 and 2 , we get :

v = 12 miles/hour and u = 6 miles/hour

Hence, this is the required solution.

Answer:

The speed of the stream is 6 mph, and the speed of the boat is 12 mph.

Step-by-step explanation:

Downstream:

9 miles in 30 minutes (0.5 hour).

9 mi / 0.5 h = 18 mph

Upstream:

9 miles in 90 minutes (1.5 h).

9 mi / 1.5 h = 6 mph

Let s = speed of stream.

The speed of the stream adds to the speed of the boat downstream and is subtracted fromt he speed of the boat upstream.

Let speed of boat be b.

b + s = 18

b - s = 6

Add the equations.

2b = 24

b = 12

b + s = 18

12 + s = 18

s = 6

The speed of the stream is 6 mph, and the speed of the boat is 12 mph.

Step-by-step explanation:

answer of number 5

length=7cm

breadth=9 cm

height=6 cm

volume=?

we know

v =l×b×h

=7×9×6

=378

so, the volume is 378 cm

Answer:

cone, radius is 3^2 x pi x 7/3 = 65.98

Step-by-step explanation: