which is the area of the region in quadrant i bounded by y = 2x2 and y = 2x3?

Answer:

X° = 72.6459

Step-by-step explanation:

To solve x we must use tan b/c it contain both side,

which is opposite and adjecent

tan ( x°) =16/5

tan ( x°) =16/5tan ( x°) = 3.2

tan ( x°) =16/5tan ( x°) = 3.2X °= tan^-1(3.2)

tan ( x°) =16/5tan ( x°) = 3.2X °= tan^-1(3.2)X° = 72.6459 round to 72.65°

Answer:

32.2

Step-by-step explanation:

Answer:

Step-by-step explanation:

You want the measures of angles A and B in right triangle ABC with hypotenuse AB = 15, and side BC = 8.

The mnemonic SOH CAH TOA reminds you of the relationships between side lengths and trig functions in a right triangle:

  Sin = Opposite/Hypotenuse

  Cos = Adjacent/Hypotenuse

Here, the hypotenuse is given as AB=15. The side opposite angle A is given as BC=8, so we have ...

  sin(A) = 8/15   ⇒   A = arcsin(8/15) ≈ 32°

The side adjacent to angle B is given, so we have ...

  cos(B) = 8/15   ⇒   B = arccos(8/15) ≈ 58°

Of course, angles A and B are complementary, so we can find the other after we know one of them.

  B = 90° -A = 90° -32° = 58°

The measures of the angles are A = 32°, B = 58°.

__

Additional comment

The inverse trig functions can also be called arcsine, arccosine, arctangent, and so on. On a calculator these inverse functions are indicated by a "-1" exponent on the function name—the conventional way an inverse function is indicated when suitable fonts are available.

You will note the calculator is set to DEG mode so the angles are given in degrees.

Answer:  It seems like there might be a mistake in the expression you provided. The variable "n" is not defined, and it does not appear in the summation. It seems like you might have meant to write:

s4 = 4∑k=1 2(3k-1)

Assuming that this is the correct expression, we can evaluate it as follows:

s4 = 4∑k=1 2(3k-1)

= 4 * [2(3(1)-1) + 2(3(2)-1) + 2(3(3)-1) + 2(3(4)-1)]

= 4 * [2(2) + 2(5) + 2(8) + 2(11)]

= 4 * [4 + 10 + 16 + 22]

= 4 * 52

= 208

Therefore, s4 = 208.

$15

$15 because they are asking you to do a subtraction the initial amount used to be $55then you have to substract $40 because they are saying $40 OFF

$15 because they are asking you to do a subtraction the initial amount used to be $55then you have to substract $40 because they are saying $40 OFF55 - 40= 15don't forget to add the $ sign

$15 because they are asking you to do a subtraction the initial amount used to be $55then you have to substract $40 because they are saying $40 OFF55 - 40= 15don't forget to add the $ sign !Hope I helped you

Since A1, A2, ..., Am are mutually exclusive and exhaustive, answers to both parts of the question is;

a) We can use the same argument to show that P(A2) = P(A3) = ... = P(Am) = 1/m.
b) We have proved that if A = A1 ∪ A2 ∪ ... ∪ Ah and (a) holds, then P(A) = h/m.

(a) Since A1, A2, ..., Am are mutually exclusive and exhaustive, we have:

P(S) = P(A1) + P(A2) + ... + P(Am)

Since P(A1) = P(A2) = ... = P(Am), we can rewrite the above equation as:

P(S) = m * P(A1)

Since S is the sample space and its probability is 1, we have:

P(S) = 1

Therefore, we can solve for P(A1) as:

P(A1) = 1/m

Similarly, we can use the same argument to show that P(A2) = P(A3) = ... = P(Am) = 1/m.

(b) Since A1, A2, ..., Am are mutually exclusive and exhaustive, we have:

P(S) = P(A1) + P(A2) + ... + P(Am)

Using (a), we know that P(Ai) = 1/m for i = 1, 2, ..., m. Therefore, we can rewrite the above equation as:

1 = m * (1/m) + P(Ah+1) + ... + P(Am)

Simplifying this equation, we get:

P(Ah+1) + ... + P(Am) = (m - h) * (1/m)

Since A = A1 ∪ A2 ∪ ... ∪ Ah, we can write:

P(A) = P(A1) + P(A2) + ... + P(Ah) = h * (1/m)

Therefore, we have proved that if A = A1 ∪ A2 ∪ ... ∪ Ah and (a) holds, then P(A) = h/m.

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The lower limit of a 95% confidence interval for the population means would be Option B. approximately 176.

To calculate the confidence interval, we need to use the formula:

Confidence interval = sample mean ± (critical value) x (standard error)

The critical value can be found using a t-distribution table with degrees of freedom (df) equal to n-1, where n is the sample size. For a 95% confidence level with 99 degrees of freedom, the critical value is approximately 1.984.

The standard error is calculated as the sample standard deviation divided by the square root of the sample size. In this case, the standard error would be:

standard error = 20 / sqrt(100) = 2

Therefore, the confidence interval would be:

confidence interval = 180 ± (1.984) x (2) = [176.07, 183.93]

Since we are looking for the lower limit, we take the lower value of the interval, which is approximately 176.

In other words, we can say that we are 95% confident that the true population means falls within the interval of [176.07, 183.93].

Therefore, Option B. Approximately 176 is the correct answer.

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The function g(t) = 3t⁵ + 40t⁴ + 150t³ + 120 is concave up on the interval (-∞, -2) and concave down on the interval (-2, ∞). There is an inflection point at t = -2.

1. Find the first derivative, g'(t) = 15t⁴ + 160t³ + 450t².
2. Find the second derivative, g''(t) = 60t³ + 480t² + 900t.
3. Factor out the common term, g''(t) = 60t(t² + 8t + 15).
4. Solve g''(t) = 0 to find critical points. In this case, t = 0 and t = -2.
5. Test the intervals to determine the concavity: For t < -2, g''(t) > 0, so it's concave up. For t > -2, g''(t) < 0, so it's concave down.
6. Since the concavity changes at t = -2, there is an inflection point at t = -2.

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The function y(x) = 2e⁻³ˣ + 8e⁻⁶ˣ + 16xe⁻⁶ˣ + 20x²e⁻⁶ˣ satisfies the given conditions.

To find y(x), we first solve the differential equation y''' - 15y'' + 54y' = 40e^x. The characteristic equation r³ - 15r² + 54r = 0 has roots r1 = 3, r2 = 6, and r3 = 6.

The general solution is y(x) = Ae³ˣ + Be⁶ˣ + Cxe⁶ˣ.

Using the initial conditions y(0) = 26, y'(0) = 18, and y''(0) = 26, we can find the values of A, B, and C. After substituting the initial conditions and solving the system of equations, we obtain A = 2, B = 8, and C = 16. Thus, y(x) = 2e⁻³ˣ + 8e⁻⁶ˣ + 16xe⁻⁶ˣ + 20x²e⁻⁶ˣ.

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The equation for the function, which is f(x) = -4x + 500 and is a linear function, is the answer to the given question based on the function.

A straight line on a graph is represented by a particular kind of mathematical function called a linear function. Two variables that are directly proportional to one another are modelled using linear functions. For instance, the distance-time relationship in a straight line motion is a linear function with speed as the slope.

Let's start by determining whether the function is exponential or linear. Given that Nick can write 120 words in 30 minutes, his word-per-minute rate is 120/30, or 4 words. In order to estimate how many words, he writes in x minutes, we can use this rate:

Write x words in x minutes and multiply by 4 = 4x

Since Nick wants to write 500 words per day, we can create an equation to roughly calculate how many words remain in his writing session after x minutes:

500 - 4x is the number of words remaining needed to meet the target.

Given that there is a constant pace of 4 words per minute between the number of words still needed and the amount of time left, this equation is linear. It can be expressed as a linear function with the formula f(x) = mx + b, where m denotes the slope (rate) and b the y-intercept (value at x=0).

Since Nick needs to write 500 words at the beginning of the writing session, the y-intercept is 500 and the slope is -4 (indicating that the rate of words still needed is falling at a rate of 4 words per minute):

f(x) = -4x + 500

As a result, the function's equation is f(x) = -4x + 500, indicating that it is a linear function.

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Let x be a random variable with pdf f(x) = 1/13, 21 P(X > 30) = 0.31.

We are given that X is a random variable with a probability density function (pdf) of f(x) = 1/13 for the interval 21  x  34.

We are asked to find P(X > 30), which means we need to find the probability of the random variable X being greater than 30. To do this, we will calculate the area under the PDF in the interval [30, 34].

Step 1: Determine the width of the interval [30, 34].
Width = 34 - 30 = 4

Step 2: Calculate the area under the PDF in the interval [30, 34].
Since the pdf is a constant value (1/13) within the given interval, we can calculate the area as follows:
Area = f(x) * width
Area = (1/13) * 4

Step 3: Round off the result to the second decimal place.
Area ≈ 0.31 (rounded to two decimal places)

So, P(X > 30) ≈ 0.31.

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Using proportions, the equation in terms of Tim is given by:

T(t) = 17t.

We have,

A proportion is a fraction of a total amount, and the measures are related using a rule of three. Due to this, relations between variables, either direct(when both increase or both decrease) or inverse proportional(when one increases and the other decreases, or vice versa), can be built to find the desired measures in the problem, or equations to find these measures.

For this problem, we have that:

Isaac sells four times as much as Tim, hence I = 4t.

Hannah sells three times as much as Isaac, hence H = 3I = 3 x 4t = 12t.

Hence the total amount, as a function of Isaac's amount, is given by:

T(t) = I + H + t

T(t) = 4t + 12t + t

T(t) = 17t.

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complete question:

Tim (t), isaac (i), and hannah (h) all sell individual insurance policies. isaac sells four times as much as tim, and hannah sells three times as much as isaac. create an equation in terms of tim (t) in order to find the portion he sells.

The sample size increases, the 95% confidence interval becomes narrower because it provides a more precise estimate of the true population parameter.

Confidence interval is a range of values that estimates the true population parameter with a certain level of confidence. A 95% confidence interval means that if the same population is sampled multiple times, the calculated confidence interval will contain the true population parameter in 95% of the samples.

When the sample size increases, it provides more data points to estimate the population parameter. This increased sample size results in a smaller standard error, which is the standard deviation of the sample mean. A smaller standard error means that the sample mean is likely to be closer to the true population parameter, resulting in a narrower confidence interval.

Mathematically, the formula for the confidence interval is:

Confidence Interval = Sample Mean ± (Critical Value * Standard Error)

Where the critical value depends on the desired level of confidence (e.g., 95%) and the standard error is calculated from the sample size. As the sample size increases, the standard error decreases, which means that the margin of error (the range between the sample mean and the critical value multiplied by the standard error) becomes smaller. Therefore, the confidence interval becomes narrower with a larger sample size.

Therefore, when the sample size increases, the 95% confidence interval becomes narrower because it provides a more precise estimate of the true population parameter.

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The location of all points of inflection of the function f'(x) = (x - 2)(x-4)(x - 5) are option (d) 11- √7/3,  11+ √7/3.

To find the points of inflection of the function f, we need to find its second derivative and set it equal to zero, and then solve for x. If the second derivative changes sign at x, then x is a point of inflection.

Taking the derivative of f'(x), we get

f''(x) = 3x^2 - 22x + 32

Setting f''(x) = 0, we get

3x^2 - 22x + 32 = 0

We can solve this quadratic equation using the quadratic formula

x = [22 ± sqrt(22^2 - 4(3)(32))] / (2*3)

x = [22 ± sqrt(244)] / 6

x = (11 ± sqrt(61))/3

Therefore, the points of inflection of the function f are

x = (11 - sqrt(61))/3 ≈ 0.207

x = (11 + sqrt(61))/3 ≈ 3.793

So the answer is (d) 11- √7/3,  11+ √7/3.

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The location of all points of inflection of the function f'(x) = (x - 2)(x-4)(x - 5) are option (d) 11- √7/3,  11+ √7/3.

To find the points of inflection of the function f, we need to find its second derivative and set it equal to zero, and then solve for x. If the second derivative changes sign at x, then x is a point of inflection.

Taking the derivative of f'(x), we get

f''(x) = 3x^2 - 22x + 32

Setting f''(x) = 0, we get

3x^2 - 22x + 32 = 0

We can solve this quadratic equation using the quadratic formula

x = [22 ± sqrt(22^2 - 4(3)(32))] / (2*3)

x = [22 ± sqrt(244)] / 6

x = (11 ± sqrt(61))/3

Therefore, the points of inflection of the function f are

x = (11 - sqrt(61))/3 ≈ 0.207

x = (11 + sqrt(61))/3 ≈ 3.793

So the answer is (d) 11- √7/3,  11+ √7/3.

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The trigonometric identity tan(π/4 - x) = [1 - tan(x)]/[1 + tan(x)]

Trigonometric identities are mathematical equations that contain trigonometric ratios.

Since we have the trigonometric identity

tan(π/4 - x) = [1 - tan(x)]/[1 + tan(x)]. We want to show that the left-hand-side L.H.S = right-hand-side R.H.S. We proceed as folows

Since we have L.H.S = tan(π/4 - x)

Using the trigonometric identity tan(A - B) = (tanA - tanB)/(1 + tanAtanB). So, comparing with tan(π/4 - x), we have that

So, substituting the values of the variables into the equation, we have that

tan(A - B) = (tanA - tanB)/(1 + tanAtanB)

tan(π/4 - x) = [tanπ/4 - tan(x)]/[1 + tan(π/4)tan(x)].

Since tanπ/4 = 1, we have that

tan(π/4 - x) = [tanπ/4 - tan(x)]/[1 + tan(π/4)tan(x)]

tan(π/4 - x) = [1 - tan(x)]/[1 + 1 × tan(x)]

tan(π/4 - x) = [1 - tan(x)]/[1 + 1 × tan(x)]

= R.H.S

Since L.H.S = R.H.S

So, the trigonometric identity tan(π/4 - x) = [1 - tan(x)]/[1 + tan(x)]

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The distance that the jet would have travelled can be found to be 2,364.98 miles.

To determine how many miles the jet has traveled, we need to calculate the distance traveled during the acceleration phase (first 7 minutes) and the constant speed phase.

Calculate the distance traveled during the acceleration phase:

Distance = Average speed x Time

Distance = 300 miles/hour x 0.1167 hours ≈ 35 miles

The jet continued to travel at a constant speed of 600 miles per hour for the remaining time.

Calculate the distance traveled during the constant speed phase:

Distance = Speed x Time

Distance = 600 miles/hour x 3.8833 hours = 2,329.98 miles

Total distance traveled:

Total distance = Distance during acceleration + Distance during constant speed

Total distance = 35 miles + 2329.98 miles = 2364.98 miles

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From the given choices, only P[{clubs}) = 0.7, P{{diamonds}) = 0.3 satisfies the requirements of the definition of probability.

The choice that fulfills the requirements of the definition of probability is:

P[{clubs}) = 0.7, P{{diamonds}) = 0.3.

For an event A in a sample space S, the probability of A, denoted by P(A), must satisfy the following conditions:

P(A) is a non-negative real number: This means that the probability of an event cannot be negative.

P(S) = 1: The probability of the sample space is always equal to 1. This implies that at least one of the events in the sample space must occur.

If A and B are two mutually exclusive events, then P(A or B) = P(A) + P(B): This means that the probability of either event occurring is equal to the sum of their individual probabilities.

In the given sample space S = {clubs, diamonds}, the probabilities of the two events must add up to 1, since there are only two possible outcomes.

Therefore, the probabilities of the events cannot be negative or greater than 1.

From the given choices, only P[{clubs}) = 0.7, P{{diamonds}) = 0.3 satisfies the requirements of the definition of probability.

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Step-by-step explanation:

school is taller than me

Answer:

x = 13.8 ft

The triangle is obtuse

Step-by-step explanation:

Using the cosine rule to determine x:

[tex]x=\sqrt{(11.7)^{2}+(7.4)^{2} -2(11.7)(7.4) * cos90 } \\=13.8 ft\\[/tex]

Testing whether or not the Pythagoras theorem applies

[tex]r^{2} =x^{2} +y^{2} \\(13.8)^{2} = (7.4)^{2} +(11.7)^{2} \\190.44\neq 191.65[/tex]

Therefore the triangle is obtuse

Answer:

Step-by-step explanation:

1008

16 /- 6 heads in 32 tosses is about as likely as 256 /- 96 heads in 512 tosses. This can be answered by the concept of

Probability.

The missing term can be found by using the same proportion as the first part of the question.

16/-6 heads in 32 tosses is equivalent to approximately 0.0244 or 2.44%.

Using the same proportion, we can find the equivalent number of heads in 512 tosses by setting up the equation:

16/-6 = 256/-x

Solving for x, we get x = -96, which means we need to subtract 96 from 256 to find the equivalent number of heads.

256/-96 heads in 512 tosses is equivalent to approximately 0.0244 or 2.44%.

Therefore, 16 /- 6 heads in 32 tosses is about as likely as 256 /- 96 heads in 512 tosses.

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To analyze how the stability of the system depends on k, simply substitute k for any of the coefficients in the characteristic equation and construct a new Routh array. By analyzing the Routh array for each value of k, you can determine the range of values of k for which the system is stable.

The Routh-Hurwitz criterion is a mathematical tool used to determine the stability of a system. The criterion relies on constructing a table called the Routh array, which consists of rows and columns of coefficients from the system's characteristic equation. The coefficients in the Routh array are used to determine the number of roots of the characteristic equation that lie in the left half of the complex plane, which is a necessary condition for stability.

If you have a system with a characteristic equation of the form:

[tex]a_n s^n + a_{n-1} s^{n-1} + ... + a_1 s + a_0 = 0[/tex]

and you want to analyze how the stability of the system depends on a constant parameter k, you can do so by constructing a series of Routh arrays, each corresponding to a different value of k.

To do this, first write the characteristic equation as:

[tex]s^n + (a_{n-1}/a_n) s^{n-1} + ... + (a_1/a_n) s + (a_0/a_n) = 0[/tex]

Then, construct the first two rows of the Routh array as follows:

[tex]Row 1: a_n a_{n-2} a_{n-4} ...[/tex]

[tex]Row 2: a_{n-1} a_{n-3} a_{n-5} ...[/tex]

For each subsequent row, calculate the coefficients using the following formula:

[tex]a_{i-1} = (1/a_{n-1}) [a_{n-i} a_{n-1} - a_{n-i-1} a_n][/tex]

If at any point in the construction of the Routh array a zero entry is encountered, it indicates that there is at least one root of the characteristic equation with positive real part, and therefore the system is unstable. If all entries in the first column of the Routh array are nonzero and have the same sign, the system is stable.

To analyze how the stability of the system depends on k, simply substitute k for any of the coefficients in the characteristic equation and construct a new Routh array. By analyzing the Routh array for each value of k, you can determine the range of values of k for which the system is stable.

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None of the options A, B, C, or D are the necessary step to verify InB + 2 = -2t as a solution to dB/dt = -2B.

what is differential equations?

Differential equations are mathematical equations that describe the relationship between an unknown function and its derivatives (or differentials).

To verify that InB + 2 = -2t is a solution to dB/dt = -2B, we can substitute InB + 2 for B in the differential equation and check if it satisfies the equation.

So, let's first differentiate InB + 2 with respect to t:

d/dt (InB + 2) = 1/B * dB/dt

Using the given differential equation, we can substitute dB/dt with -2B:

d/dt (InB + 2) = 1/B * (-2B)

Simplifying this expression, we get:

d/dt (InB + 2) = -2

Now, substituting InB + 2 for B in the original differential equation, we get:

dB/dt = -2(InB + 2)

We can differentiate this expression with respect to B to get:

d/dB (dB/dt) = d/dB (-2(InB + 2))

d²B/dt² = -2/B

Since we have already established that d/dt (InB + 2) = -2, we can differentiate this expression with respect to t to get:

d²B/dt² = d/dt (-2) = 0

Therefore, d²B/dt² = -2/B if and only if d/dt (InB + 2) = -2.

Now, let's check if the given solution satisfies this condition. Substituting InB + 2 = -2t in d/dt (InB + 2), we get:

d/dt (InB + 2) = d/dt (In(-2t) + 2) = -2/t

Since -2/t is not equal to -2, the given solution does not satisfy the differential equation dB/dt = -2B, and hence, we cannot verify it as a solution.

Therefore, none of the options A, B, C, or D are the necessary step to verify InB + 2 = -2t as a solution to dB/dt = -2B.

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The volume of the sphere of radius 7 is [tex]1176 * \pi[/tex] cubic units.

To find the volume of a sphere of radius 7 using polar coordinates, we can first observe that the equation of a sphere centered at the origin with radius r is given by:

[tex]x^2 + y^2 + z^2 = r^2[/tex]

In polar coordinates, this equation becomes:

[tex]r^2 = x^2 + y^2 + z^2 = r^2 cos^2(\theta) + r^2 sin^2(\theta) + z^2[/tex]

Simplifying this equation, we get:

[tex]z^2 = r^2 - r^2 sin^2(\theta)[/tex]

The volume of the sphere can be found by integrating the expression for [tex]z^2[/tex] over the entire sphere.

Since the sphere is symmetric about the origin, we can integrate over a single octant (0 <=[tex]\theta[/tex] <= [tex]\pi/2[/tex], 0 <= [tex]\phi[/tex] <=[tex]\pi/2[/tex]) and multiply the result by 8 to obtain the total volume of the sphere.

Thus, we have:

V = 8 * ∫∫[tex](r^2 - r^2 sin^2(\theta))^(1/2) r^2 sin(\theta) dr d(\theta) d(\phi)[/tex]

Since the sphere has a radius of 7, we have r = 7 and the limits of integration are as follows:

0 <= r <= 7

[tex]0 < = \theta < =\pi/2[/tex]

[tex]0 < = \phi < = \pi/2[/tex]

Using these limits and integrating, we get:

V = 8 * ∫∫[tex](49 - 49 sin^2(\theta))^(1/2) (7^2) sin(\theta) dr d(\theta) d(\phi)[/tex]

=[tex]8 * (4/3) * \pi * (49)^2/3[/tex]

= [tex]1176 * \pi[/tex]

Therefore, the volume of the sphere of radius 7 is [tex]1176 * \pi[/tex] cubic units.

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To find the additive order of a modulo n, we need to find the smallest positive solution of the congruence ax = 0 (mod n).

(a) For 8 modulo 12, we need to solve the congruence 8x = 0 (mod 12). The solutions are x = 0, 3, 6, 9. Therefore, the additive order of 8 modulo 12 is 3.

(b) For 7 modulo 12, we need to solve the congruence 7x = 0 (mod 12). The solutions are x = 0, 4, 8. Therefore, the additive order of 7 modulo 12 is 4.

(c) For 21 modulo 28, we need to solve the congruence 21x = 0 (mod 28). The solutions are x = 0, 4. Therefore, the additive order of 21 modulo 28 is 4.

(d) For 12 modulo 18, we need to solve the congruence 12x = 0 (mod 18). The solutions are x = 0, 3, 6, 9, 12, 15. Therefore, the additive order of 12 modulo 18 is 3.
(a) For 8 modulo 12, we need to find the smallest positive integer k such that 8k ≡ 0 (mod 12). The smallest k that satisfies this is 3, since 8*3 = 24, and 24 is divisible by 12. So, the additive order of 8 modulo 12 is 3.

(b) For 7 modulo 12, we need to find the smallest positive integer k such that 7k ≡ 0 (mod 12). The smallest k that satisfies this is 12, since 7*12 = 84, and 84 is divisible by 12. So, the additive order of 7 modulo 12 is 12.

(c) For 21 modulo 28, we need to find the smallest positive integer k such that 21k ≡ 0 (mod 28). The smallest k that satisfies this is 4, since 21*4 = 84, and 84 is divisible by 28. So, the additive order of 21 modulo 28 is 4.

(d) For 12 modulo 18, we need to find the smallest positive integer k such that 12k ≡ 0 (mod 18). The smallest k that satisfies this is 3, since 12*3 = 36, and 36 is divisible by 18. So, the additive order of 12 modulo 18 is 3.

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Answer:

Step-by-step explanation:

Expanding the expression (g+h)(p+q-r) using the distributive property, we get:

(g+h)(p+q-r) = g(p+q-r) + h(p+q-r)

Now, applying the distributive property again, we can simplify this expression to:

(g+h)(p+q-r) = gp + gq - gr + hp + hq - hr

Therefore, the expression (g+h)(p+q-r) is equivalent to:

gp + gq - gr + hp + hq - hr

Answer:

B. The length of the arc is 1.5 times longer than the radius.

C. The ratio of arc length to radius is 1.5.

The given improper integral from 0 to infinity of e^-x cos(3x) dx converges.

We can determine the convergence or divergence of the given improper integral by using the comparison test with a known convergent integral.

First, we note that the integrand, e^-x cos(3x), is a product of two continuous functions on the interval [0, infinity). Thus, the integral is improper due to its unbounded integration limit.

Next, we consider the absolute value of the integrand: |e^-x cos(3x)| = e^-x |cos(3x)|. Since |cos(3x)| is always less than or equal to 1, we have e^-x |cos(3x)| ≤ e^-x. Thus,

integral from 0 to infinity of e^-x |cos(3x)| dx ≤ integral from 0 to infinity of e^-x dx

The right-hand integral is a known convergent integral, equal to 1. Thus, the given integral is also convergent by the comparison test.

To evaluate the integral, we can use integration by parts. Let u = cos(3x) and dv = e^-x dx, so that du/dx = -3 sin(3x) and v = -e^-x. Then, we have:

integral of e^-x cos(3x) dx = -e^-x cos(3x) + 3 integral of e^-x sin(3x) dx

Using integration by parts again with u = sin(3x) and dv = e^-x dx, we get:

integral of e^-x cos(3x) dx = -e^-x cos(3x) - 3 e^-x sin(3x) - 9 integral of e^-x cos(3x) dx

Solving for the integral, we get:

integral of e^-x cos(3x) dx = (-e^-x cos(3x) - 3 e^-x sin(3x))/10 + C

where C is a constant of integration.

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Answer:

Step-by-step explanation:

The mean of a discrete uniform distribution is the average of the minimum and maximum values of the distribution.

In this case, X ranges from 12 to 24, so the minimum value is 12 and the maximum value is 24. Therefore, the mean is:

Mean = (12 + 24) / 2 = 18

So the answer is c. 18.0.

Yes, the mysteries equal 0.06 of the total books.

Marcella said that the mysteries equal 0.06 of the total books.

To check the mysteries equal 0.06 of the total books is correct or not.

We can follow these steps:

1. Identify the total number of books and the number of mysteries: Marcella read 100 books, and 60 of them were mysteries.

2. Calculate the fraction of mysteries: Divide the number of mysteries (60) by the total number of books (100) to find the fraction of mysteries.

3. Compare the fraction with Marcella's claim: If the calculated fraction equals 0.06, then she is correct.

Now let's perform the calculations:

60 mysteries ÷ 100 total books = 0.6

Since 0.6 ≠ 0.06, Marcella's claim that the mysteries equal 0.06 of the total books is incorrect. In reality, mysteries make up 0.6 or 60% of the total books she read.

A model to support this answer could be a pie chart, where the circle represents the 100 books, and the mysteries portion is shaded in. By dividing the circle into 10 equal sections, the mysteries would fill 6 of those sections, which represents 60% of the total books.

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The value of the probability P(3) is 0.250 and P(More than 2) is 0.474

From the question, we have the following parameters that can be used in our computation:

n = 10 questions

x = 3 questions answered correctly

p = 1/4 i.e. the probability of getting a right answer

The probability is then calculated as

P(x = x) = nCr * p^x * (1 - p)^(n - x)

Substitute the known values in the above equation, so, we have the following representation

P(x = 3) = 10C3 * (1/4)^3 * (1 - 1/4)^7

Evaluate

P(x = 3) = 0.250

Hence, the probability is 0.250

This is represented as

P(x > 2) = 1 - P(0) - P(1)  - P(2)

Using a graphing tool, we have

P(x > 2) = 0.474

Hence, the probability is 0.474

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