Which is equivalent to
?
V2
Ο ΑΜΣ
2
OB. 120
2
2x
O
C.
al
OD
x+V2
2
OE V2​

Answer:

13.93

Step-by-step explanation:

use the Pythagorean theorem

Answer:

x=4√−0.45068027,−4√0.45068027

Step-by-step explanation:

Answer:

D. 1.5

Step-by-step explanation:

The median number of excused absences from given data is 1.5.

We have given that,

The dot plot below shows the number of excused absences students in Mr. Beckett's class have.

We have to determine the median

The median is the value separating the higher half from the lower half of a data sample, a population, or a probability distribution. For a data set, it may be thought of as the middle value.

Therefore the median number of excused absences from given data is 1.5.

Therefore option D is correct.

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Answer:

The amplitude is [tex]\frac{1}{2} = 0.5[/tex]

Step-by-step explanation:

Trigonometric function:

A trigonometric function has the following format:

[tex]A\sin{bx}[/tex] or [tex]A\cos[bx}[/tex]

In which the amplitude is A and the period is [tex]\frac{2\pi}{b}[/tex]

Amplitude of y = 1/2 * cos 5x

The multiplier is 1/2, so this is the amplitude.

Answer:

3cm

Step-by-step explanation:

The formula for the volume of the cuboid is [tex]w*l*h=volume[/tex]

We already have the length, width, and volume, so we have to plug it in to the equation.

[tex]15*10*h=450[/tex] (Just a heads up in case you didn't know: the centimeters cubed is just part of the units, so you don't need to worry about it when plugging it in to the equation.)

To solve for h:

1. Multiply 15 and 10

[tex]150*h=450[/tex]

2. Divide both sides by 150

[tex]h = 450/150[/tex]

h = 3

This is in centimeters, so the final answer is 3cm.

The height of a cuboid with a volume of 450cm³ with a length of 10cm and width of 15cm is 3cm.

The volume of a cuboid can be calculated using the following formula:

Volume = length × width × height

According to this question, the volume of a cuboid is 450cm³ and has a length of 10cm and the width is 15cm. The height is as follows:

450cm³ = 15cm × 10cm × h

450cm³ = 150²h

h = 450/150

h = 3

Therefore, the height of a cuboid with a volume of 450cm³ with a length of 10cm and width of 15cm is 3cm.

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Answer:

great job

Step-by-step explanation:

Answer:

[tex]M(y)=10y+10[/tex]

Step-by-step explanation:

what question? where is the question???????????????????????????????????????????????????

Answer:

7200

Step-by-step explanation:

80*90=7200

Answer:

7,200 paper clips

Step-by-step explanation:

80*90=7,200

Answer:Add 3 to both sides and subtract 8x from both sides.Step-by-step explanation:The standard form of a quadratic equation isHere a should not be zero.Now, we have to write the given equation in this formwe have to take 8x and -3 to the left side of the equation in order to write the equation in standard form.Therefore, we have to subtract 8x and add 3 to both sides of the equation.When we do this operation, we'll get the equation in standard form which is given byHence, option is correct.Add 3 to both sides and subtract 8x from both sides.

Answer:

0.155litre

Step-by-step explanation:

55+25+40+35=155cm

100Cm=1litre

155cm_ ?

155cm×1litre/1000cm

0.155Litre

Answer:

l=11

Step-by-step explanation:

w Width

3

h Height

2

V Volume

66

Answer:

A and D

Step-by-step explanation:

for infinitely many solutions, ratio of coefficients should be equal.

since ratio = 1/4 so they will have infinitely many solutions.

Answer:

c

Step-by-step explanation:

c is the only one containing the number three, which is shown on the graph.

Answer:

101

Step-by-step explanation:

Answer:

3

Step-by-step explanation:

For x<=0, f is constant: f(x) =3

-4<0, so f(-4)=3

Answer:

11

Step-by-step explanation:

Answer:

None

See below under Remark.

Step-by-step explanation:

When you shift left, you think of moving in the negative direction. But it is not shown that way. You need to show what happens when you substitute a value in for x. Usually a graphing program helps to show which choice is right.

g(x) = f(x+4) = 2(x + 4)

None of the choices are this result, so we have to assume that the brackets were just omitted.  The graph below shows what the answer given is the correct one.

Remark

Look at the graph carefully. The red line is f(x) = 2x

The blue line is g(x) = f(x-4) = 2(x - 4)

Notice that g(x) has shifted 4 units to the left. The x intercept has gone from 0,0 to (-4,0) and is so labeled.

If you have an answer with brackets around (x + 4) that's the one you choose. It needs the 2 outside the brackets.

Answer:

Step-by-step explanation:

We see 75% of data lies in the interval 0 - 48, and the 120 is the outlier.

We wouldn't use the range as it won't be a representation of variability.

The best measure would be IQR:

Correct choice is C.

Answer:

h=13

Step-by-step explanation:

volume=w*h*l

312=(4)(6)(X)

Answer:

no. of plants frank plants in one garden = x vegetables

no. of plants frank plants in another garden = 3x + 7

total no. of plants frank plants = x + 3x + 7 = 4x + 7

hope this answer helps you.....

please mark as brainliest.. thank you!

Answer:

Value is 2

Step-by-step explanation:

f(3)= 1/4 x  2^(3)      ------- 2 x 2 x 2= 8

1/4 x 8    = 8/4 = 2

Answer:

8cm and 9cm

Step-by-step explanation:

8cm and 9cm would be the two possible lengths for the triangle because for the triangle to work you need the other two other sides when added together needs to be greater then 13. Furthermore 5 + 8 = 13 and as 13 is the same length as the one side that is given, a triangle couldn't possibly be formed as it would just be a straight line. Moreover, this is the same with 6 + 7 which is also 13. 7 + 2 is 9 and because 9<13 a triangle couldn't possibly be formed. Finally, 8 + 9 which equals to 17 are the only two possible lengths for the triangle as 17 > 12.

Step-by-step explanation:

10:

[tex] \sqrt{50} = \sqrt{2 \times 25} = \sqrt{2} \times \sqrt{25} = \: 2 \times \sqrt{5} [/tex]

11:

[tex] \sqrt{88} = \sqrt{4 \times 22} = \sqrt{4} \times \sqrt{22} = \: \: \: \: \: 2 \times \sqrt{22} [/tex]

12:

[tex] \sqrt[3]{54} = \sqrt[3]{ {3}^{3} \times 2} = \sqrt[3]{ {3}^{3} } \times \sqrt[3]{2} = \: \: \: \: \: 3 \times \sqrt[3]{2} [/tex]

Answer:

.85x-5

Step-by-step explanation:

If you say .15x suppose x is 1

.15*1= .15

Is 15% off 1 = .15 no its .85 thats why in these types of problems we do 100%-15%=85% and then .85*x

After deducting the discounts given to the customer, the current price the customer will pay is $(0.85x - 5).

Given parameters:

discount rate of the shirt, = 15%

original price of the shirt, = $x

additional discount on the sales price = $5

To find:

Note:  the original price of the shirt = 100% of x

The current price of the shirt = original price - given discounts

Convert the percentage to decimal by dividing it by 100

Thus, after the discount the customer will pay $(0.85x - 5)

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Answer:

Answer:

C. the graph of f(x) is shifted 7 units down

Answer:

[tex]Median = 90.4[/tex]

[tex]Q_1 = 88.6[/tex]

[tex]Q_3 = 92.2[/tex]

Step-by-step explanation:

Given

The above data

Required

- A stem and leaf display

- The median

- The quartiles

First, determine the range of the data

[tex]Smallest = 83.4[/tex]

[tex]Highest = 100.3[/tex]

Next, group each dataset base on common whole numbers.

So, we have:

[tex]83.4[/tex]

[tex]84.3\ 84.3[/tex]

[tex]85.3[/tex]

[tex]86.7\ 86.7\ 86.7[/tex]

[tex]87.4\ 87.5\ 87.6\ 87.7\ 87.8\ 87.9[/tex]

[tex]88.2\ 88.3\ 88.3\ 88.3\ 88.4\ 88.5\ 88.5\ 88.6\ 88.6\ 88.7\ 88.9[/tex]

[tex]89.0\ 89.2\ 89.3\ 89.3\ 89.6\ 89.7\ 89.8\ 89.8\ 89.9\ 89.9[/tex]

[tex]90.0\ 90.1\ 90.1\ 90.1\ 90.3\ 90.4\ 90.4\ 90.4\ 90.5\ 90.6\ 90.7\ 90.8\ 90.9[/tex]

[tex]91.0\ 91.0\ 91.0\ 91.1\ 91.1\ 91.1\ 91.2\ 91.2\ 91.2\ \ 91.5\ 91.6\ 91.6\ 91.8\ 91.8[/tex]

[tex]92.2\ 92.2\ 92.2\ 92.3\ 92.6\ 92.7\ 92.7\ 92.7[/tex]

[tex]93.0\ 93.2\ 93.3\ 93.3\ 93.4\ 93.7[/tex]

[tex]94.2\ 94.2\ 94.4\ 94.7[/tex]

[tex]96.1\ 96.5[/tex]

[tex]98.8[/tex]

[tex]100.3[/tex]

Next, we construct the stem and leaf plot.

The whole numbers will be the stem while the decimal parts will be the leaf.

So, we have:

[tex]\begin{array}{ccc}{Stem} & {} & {Leaf} & {83} & {|} & {.4} & {84} & {|} & {.3\ .3} & {85} & {|} & {.3} & {86} & {|} & {.7\ .7\ .7} & {87} &{|} & {.4\ .5\ .6\ .7\ .8\ .9} & {88} & {|} & {.2\ .3\ .3\ .3\ .4\ .5\ .5\ .6\ .6\ .7\ .9} &{89} & {|} & {.0\ .2\ .3\ .3\ .6\ .7\ .8\ .8\ .9\ .9} & {90} & {|} &{.0\ .1\ .1\ .1\ .3\ .4\ .4\ .4\ .5\ .6\ .7\ .8\ .9} & {91} &{|}&{.0\ .0\ .0\ .1\ .1\ .1\ .2\ .2\ .2\ .5\ .6\ .6\ .8\ .8} &{92} &{|} &{.2\ .2\ .2\ .3\ .6\ .7\ .7\ .7} \ \end{array}[/tex]

  [tex]\begin{array}{ccc} {93} & {|} & {.0\ .2\ .3\ .3\ .4\ .7} & {94} &{|} & {.2\ .2\ .4\ .7} &{96} & {|} & {.1\ .5} & {98} & {|} & {.8} & {100} &{|} &{.3} \ \end{array}[/tex]

From the above plot,

[tex]n = 83[/tex]

The median is calculated as:

[tex]Median = \frac{n+1}{2}th[/tex]

[tex]Median = \frac{83+1}{2}th[/tex]

[tex]Median = \frac{84}{2}th[/tex]

[tex]Median = 42nd[/tex]

i.e. the median is at the 42nd position.

From the above stem and leaf plot.

The 42nd position is at stem 90 and the leaf  .4

So the median is:

[tex]Median = 90.4[/tex]

The lower quartile (Q) is calculated as:

[tex]Q_1 = \frac{n+1}{4}th[/tex]

[tex]Q_1 = \frac{83+1}{4}th[/tex]

[tex]Q_1 = \frac{84}{4}th[/tex]

[tex]Q_1 = 21st[/tex]

i.e. the lower quartile is at the 21st position.

From the above stem and leaf plot.

The 42nd position is at stem 88 and the leaf .6

So the lower quartile is:

[tex]Q_1 = 88.6[/tex]

The upper quartile (Q3) is calculated as:

[tex]Q_3 = 3 * \frac{n+1}{4}th[/tex]

[tex]Q_3 = 3 * \frac{83+1}{4}th[/tex]

[tex]Q_3 = 3 * \frac{84}{4}th[/tex]

[tex]Q_3 = 3 * 21th[/tex]

[tex]Q_3 = 63rd[/tex]

i.e. the upper quartile is at the 63rd position.

From the above stem and leaf plot.

The 63rd position is at stem 92 and the leaf .2

So the upper quartile is:

[tex]Q_3 = 92.2[/tex]