Which expression is equivalent to (startfraction (3 x y superscript negative 5 baseline) cubed over (x superscript negative 2 baseline y squared) superscript negative 4 baseline) endfraction) superscript negative 2? assume startfraction x superscript 10 baseline y superscript 14 baseline over 729 endfraction.

Answer:

x=1/2 or x=-1/3

Step-by-step explanation:

6x^2-x-1=0

6x^2+2x-3x-1=0

(6x^2+2x)+(-3x-1)=0

2x(3x+1)-1(3x+1)=0

2x(3x+1)-1(3x+1)=0

(2x-1)(3x+1)=0

(2x-1)(3x+1)=0

2x-1=0

or

3x+1=0

x=-1/3

x=1/2

Answer:

Its 1/3 and -1/2

Step-by-step explanation:

opposite sides and diagonals of a parallelogram are equal

+ diagonals of a parallelogram meet eachother in the middle so:

10x+14=x+77

10x-x=77-14

9x=63

x=63÷9

x= 7

y+8=4y-19

y-4y=-19-8

-3y=-27

y=-27÷-3

y=9

2z+3=37

2z=37-3

2z=34

z=34÷2

z=17

Answer:

J(-9,-5)

K(-9,3)

L(0,-2)

M(0,-5)

Answer:

9/1000

Step-by-step explanation:

When writing decimals into fractions, you first take the last digit, (in this case 9), and place it as your numerator, then count how many decimal places there are after 0. <---- in our case we have 3 decimal places which means our denominator has 3 zeros. Hence it is 1000.

Answer:

2

Step-by-step explanation:

-3 (4 - 7) + (2 x 5 - 17)

 -3 (4 - 7) + (10 - 17)

 -3 x (-3) + (-7)

   9 + (-7)

 9 - 7

   =2

Answer:

2 15/28

Step-by-step explanation:

First we will convert both mixed fractions into improper fractions.

5 1/4 becomes 21/4

2 5/7 becomes 19/7

21/4 - 19/7 does not work, so we must make the denominator the same

147/28 - 76/28 = 71/28

Now we convert back to a mixed number:

2 15/28

Answer: [tex]-11\frac{15}{28}[/tex]

Step-by-step explanation:

Convert to Improper fractions

[tex]5\frac{1}{4} = \frac{21}{4} \\2\frac{5}{7} = \frac{19}{7} \\[/tex]

Find a lowest common multiple

lcm(4,7) = 28 (7 * 4)

since they are just multiplying each other, we can cross multiply

[tex]\frac{(21*7) - (19*4)}{4*7} = \frac{147-76}{28} \\= \frac{71}{28} \\=2\frac{15}{28}[/tex]

Answer:

9.42

Step-by-step explanation:

Since the angle shown is 90 degrees we can deduce that the rest of the arc is 270 degrees therefore we can make the fraction:

270/360; 360 being the total angle measurement of a circle

270/360 simplifies to 3/4

The fraction represents how much of the circle that arc covers

Now we have to find the circumference which would be

2(3.14)r

r = 2 therefore: 2(3.14)2 = 12.56

Now that we have the circumference of the WHOLE circle we multiply it by 3/4 to find out the arc length

Which gives us  9.42

Step-by-step explanation:

reduce -28<4w-8

-7<w-2

add +2

-7+2<w-2+2

-5<w

w>-5

Answer:

See below ~

Step-by-step explanation:

Solving the inequality :

Evaluating the given numbers :

-5

5

-9

-1

Answer:

From the diagram you can see that we have constructed a right triangle, with height A and base 15.Length of shadow = 15 feet.Height of flagpole = A.We know the angle of elevation is 40∘. Using this angle and the tangent ratio, we can find A.tan(40∘)=oppositeadjacent=A15∴tan(40∘)=A15Rearranging:A=15tan(40∘)By calculator:A=12.59 feet.  ( 2 d.p.)

Multiply the moduli and add the arguments:

√2/6 cis(3π/5) × √6/4 cis(2π/3)

= (√2/6 × √6/4) cis(3π/5 + 2π/3)

= √3/12 cis(19π/15) … [A]

Answer:

I did the work and uploaded the answers i hope it helped!!

[tex]\large\displaystyle\text{$\begin{gathered}\sf 1) \ \left\{\begin{matrix} 5x-3y-z=1&\\ x+4y-6z=-1& \\ 2x+3y+4z=9& \end{matrix}\right. \end{gathered}$}[/tex]

The coefficient matrix associated with the system is constructed and the columns and rows are reduced.

                [tex]\left ( \begin{array}{ccc|c} 5 & -3 &-1 &1\\ 1 & 4 & -6 &-1\\ 2 & 3 & 4 & 9 \end{array} \right ) \begin{array}{c} \xrightarrow[\textup{F}_3- 2\textup{F}_2]{\textup{F}_1 - 5\textup{F}_2} \end{array} \left ( \begin{array}{ccc|c} 0 & -23& 29 &6\\ 1 & 4& -6 &-1\\ 0 & -5 &16 & 11 \end{array} \right )\\ \ \\ \ \\ \begin{array}{c} \xrightarrow[]{23\textup{F}_3 - 5\textup{F}_1} \end{array} \left ( \begin{array}{ccc|c} 0 & -23& 29 &6\\ 1 & 4& -6 &-1\\ 0 & 0 & 223 & 223 \end{array} \right )[/tex]

So, z=1. Translating the last matrix to the associated system of equations, we have that x=1, y=1, since:

                                       [tex]\large\displaystyle\text{$\begin{gathered}\sf \begin{align*} y&=\dfrac{6-29}{-23}=\dfrac{-23}{-23}=1\\ x = -1+6-4=1 \end{gathered}$}[/tex]

[tex]\large\displaystyle\text{$\begin{gathered}\sf \bf{2) \ \left\{\begin{matrix} x+y=7& \\ x\times y=12& \end{matrix}\right. } \end{gathered}$}[/tex]

Clear an unknown in the first equation and substitute the resulting expression in the second. Next, the quadratic equation is solved.

             [tex]\large\displaystyle\text{$\begin{gathered}\sf \bf{ y=7-x \quad \Longrightarrow \quad 12=x(7-x)=7x-x^2 } \end{gathered}$}[/tex]

                    [tex]\large\displaystyle\text{$\begin{gathered}\sf \bf{ 0=x^2-7x+12=(x-4)(x-3); } \end{gathered}$}[/tex]

                [tex]\large\displaystyle\text{$\begin{gathered}\sf \bf{ x_1=4\qquad x_2=3 \Longrightarrow y_1=3 \qquad y_2=4 } \end{gathered}$}[/tex]

[tex]\large\displaystyle\text{$\begin{gathered}\sf \boldsymbol{3) \ \left\{\begin{matrix} x^2+y^2=169& \\ x+y=17& \end{matrix}\right. } \end{gathered}$}[/tex]

Clear an unknown in the first equation and substitute the resulting expression in the second. Next, the quadratic equation is solved.

[tex]\large\displaystyle\text{$\begin{gathered}\sf \boldsymbol{ y=17-x \quad \Longrightarrow \quad 169=x^2 +(17-x)^2=x^2+x^2 -34x+289 } \end{gathered}$}[/tex]

[tex]\large\displaystyle\text{$\begin{gathered}\sf \boldsymbol{ 0=2x^2-34x+120=2(x^2-17+60)=2(x-12)(x-5); } \end{gathered}$}[/tex]

               [tex]\large\displaystyle\text{$\begin{gathered}\sf \boldsymbol{ x_1=4\qquad x_2=3 \Longrightarrow y_1=3 \qquad y_2=4 } \end{gathered}$}[/tex]

[tex]\large\displaystyle\text{$\begin{gathered}\sf \pmb{4 \ \left\{\begin{matrix} y^2-2y+1=x & \\ \sqrt{x}+y=5 & \end{matrix}\right. } \end{gathered}$}[/tex]

Substitute the expression that represents x into the second equation. Then both sides of the equation are squared and solved.

   [tex]\large\displaystyle\text{$\begin{gathered}\sf \pmb{ \sqrt{y^2-2y+1}+y=5\quad \Longrightarrow\quad \left ( \sqrt{y^2-2y+1} \right )^2=(5-y)^2 } \end{gathered}$}[/tex]

                  [tex]\large\displaystyle\text{$\begin{gathered}\sf \pmb{ y^2-2y+1=y^2-10y+25\quad \Longrightarrow\quad 8y=24; } \end{gathered}$}[/tex]

                                     [tex]\large\displaystyle\text{$\begin{gathered}\sf \pmb{ y=6 \qquad x=4 } \end{gathered}$}[/tex]

Answer:

Step-by-step explanation:

A: Not a Rhombus. Adjacent sides are unequal

B: True. Opposite sides are parallel

C: True. Adjacent sides are unequal in length but it has two sets of parallel lines and at least 1 right angle.

D: Not a square. Not all 4 sides are of equal length

E: It is a quadrilateral. A quadrilateral only requires 4 sides.

F: Not true. It does not have the properties of a trapezoid.

The equations are

Lets solve them through matrix

Let

[tex]\\ \rm\Rrightarrow A=\left[\begin{array}{ccc}\rm 5&\rm 3&\rm 4\\ \rm 2&\rm 5&\rm 5\\ \rm 6&\rm 3&\rm3\end{array}\right][/tex]

[tex]\\ \rm\Rrightarrow X=\left[\begin{array}{c}\rm x\\ \rm y\\ \rm z\end{array}\right][/tex]

[tex]\\ \rm\Rrightarrow B=\left[\begin{array}{c}\rm 67 \\ \rm 56\\ \rm 72\end{array}\right][/tex]

Let solve

Determinant of A

[tex]\\ \rm\Rrightarrow |A|[/tex]

[tex]\\ \rm\Rrightarrow 5\left|\begin{array}{cc}\rm 5&\rm 5\\ \rm 3&\rm 3\end{array}\right|-3\left|\begin{array}{cc}\rm 2&\rm 5\\ \rm 6&\rm 3\end{array}\right|+4\left|\begin{array}{cc}\rm 2&\rm 5\\ \rm 6&\rm 3\end{array}\right|[/tex]

[tex]\\ \rm\Rrightarrow 5(15-15)-3(6-30)+4(6-30)[/tex]

[tex]\\ \rm\Rrightarrow 72-96[/tex]

[tex]\\ \rm\Rrightarrow -24[/tex]

[tex]\\ \rm\Rrightarrow A_{11}=0[/tex]

[tex]\\ \rm\Rrightarrow A_{12}=24[/tex]

[tex]\\ \rm\Rrightarrow A_{13}=-24[/tex]

[tex]\\ \rm\Rrightarrow A_{21}=3[/tex]

[tex]\\ \rm\Rrightarrow A_{22}=-9[/tex]

[tex]\\ \rm\Rrightarrow A_{23}=3[/tex]

[tex]\\ \rm\Rrightarrow A_{31}=-5[/tex]

[tex]\\ \rm\Rrightarrow A_{32}=-17[/tex]

[tex]\\ \rm\Rrightarrow A_{33}=19[/tex]

[tex]\\ \rm\Rrightarrow \left[\begin{array}{ccc}\rm 0&\rm 24&\rm -24\\ \rm 3&\rm -9&\rm 3\\ \rm -5&\rm -17&\rm 19\end{array}\right][/tex]

[tex]\\ \rm\Rrightarrow \left[\begin{array}{ccc}\rm 0&\rm 24&\rm -24\\ \rm 3&\rm -9&\rm 3\\ \rm -5&\rm -17&\rm 19\end{array}\right]^T[/tex]

[tex]\\ \rm\Rrightarrow \left[\begin{array}{ccc}\rm 0&\rm 3&\rm -5\\ \rm 24&\rm -9&\rm -17\\ \rm -24&\rm 3&\rm 19\end{array}\right][/tex]

[tex]\\ \rm\Rrightarrow \dfrac{1}{|A|}\times Adj.A[/tex]

[tex]\\ \rm\Rrightarrow \dfrac{1}{-24}\left[\begin{array}{ccc}\rm 0&\rm 3&\rm -5\\ \rm 24&\rm -9&\rm -17\\ \rm -24&\rm 3&\rm 19\end{array}\right][/tex]

Now

[tex]\\ \rm\Rrightarrow AX=B[/tex]

[tex]\\ \rm\Rrightarrow X=A^{-1}B[/tex]

[tex]\\ \rm\Rrightarrow X=\dfrac{1}{-24}\left[\begin{array}{ccc}\rm 0&\rm 3&\rm -5\\ \rm 24&\rm -9&\rm -17\\ \rm -24&\rm 3&\rm 19\end{array}\right]\left[\begin{array}{c}\rm 67\\ \rm 56\\ \rm 72\end{array}\right][/tex]

[tex]\\ \rm\Rrightarrow X=\dfrac{1}{-24}\left[\begin{array}{c}\rm -192\\ \rm -120\\ \rm -72\end{array}\right][/tex]

[tex]\\ \rm\Rrightarrow X=\left[\begin{array}{c}\rm 8\\ \rm 5\\ \rm 3\end{array}\right][/tex]

So

[tex]\\ \rm\Rrightarrow \left[\begin{array}{c}\rm x\\ \rm y\\ \rm z\end{array}\right]=\left[\begin{array}{c}\rm 8\\ \rm 5\\ \rm 3\end{array}\right][/tex]

We get

Answer:

Step-by-step explanation:

The problem statement gives expressions and relations for revenue, cost, and profit. Substitute and simplify or solve, as appropriate.

__

Given: r(x) = 20x; c(x) = 3600+4x; p(x) = r(x) -c(x)

The formula for p(x) is ...

  p(x) = (20x) -(3600 +4x) . . . . substitute for r(x) and c(x)

  p(x) = 16x -3600 . . . . . . . . simplify

__

  r(x) = 2·c(x) . . . . given relation for revenue and cost

  20x = 2(3600 +4x) . . . . substitute for each

  12x = 7200 . . . . . . . simplify and subtract 8x

  x = 600 . . . . . . . divide by 12

Revenue is twice the cost when x = 600 units.

__

  p(x) = 292 +1/3r(x) . . . . given relation for profit and revenue

  16x -3600 = 292 +1/3(20x) . . . . . substitute for each

  28/3x = 3892 . . . . . . . . add 3600 -20/3x

  x = 417 . . . . . . . . multiply by 3/28

Profit is $292 more than 1/3 the revenue earned for 417 units.

Answer:

The number is 740

Step-by-step explanation:

Hello!

Let the number that we want to solve for be x.

100% of x is x, but a decrease of 5% if 95% of x.

The number is 740.

The solution is correct.

Answer:

y = 10

Step-by-step explanation:

if the figure is to be a parallelogram, then

∠ ACB and ∠ DAC are alternate angles and are congruent , that is

5y - 13 = 7 + 3y ( subtract 3y from both sides )

2y - 13 = 7 ( add 13 to both sides )

2y = 20 ( divide both sides by 2 )

y = 10

To find the degrees of freedom in the given question, we have to take into consideration of the confidence interval as well as degrees of freedom. The critical t-value in this data set is 2.086

This is the range of values that we observe in our sample and for which we expect to find the value that accurately reflects the population.

We can also say that it is a range of values so defined that there is a specified probability that the value of a parameter lies within it.

Data;

At a 95% confidence level, the t is

α   =  1  -   0.95

The critical t-value in this data set is 2.086

Learn more on t-value here;

brainly.com/question/4079902

#SPJ1

Answer:

B: 12.5%

Step-by-step explanation:

You take the 20.000- 8.500 the number decreased with= 11.5.

You then round of your answer to the nearest 10th, the number 11,5 will change to 12,50.

Answer:

C.  -18

Step-by-step explanation:

Scalar Product (Dot Product) of two vectors

[tex]\displaystyle \vec{a} \cdot \vec{b}=\sum_{i=1}^na_ib_i[/tex]

[tex]\textsf{If }\: \vec{a}=a_1\hat{i}+a_2\hat{j}+a_3\hat{k} \quad \textsf{and } \quad \vec{b}=b_1\hat{i}+b_2\hat{j}+b_3\hat{k}[/tex]

[tex]\textsf{then }\quad \vec{a} \cdot \vec{b}=a_1b_1+a_2b_2+a_3b_3[/tex]

Given:

⇒ v₁ · v₂ = (3 · 2) + (-4 · 6)

⇒ v₁ · v₂ = 6 + (-24)

⇒ v₁ · v₂ = 6 - 24

⇒ v₁ · v₂ = -18

The probability of winning the game on your next turn is; 14%

The sample size of the two number cubes, when rolled is:

n = 36

The number of outcomes that give a sum of 2 or 5 is 5,

And the outcomes are (1, 1) (2, 3) (3, 2) (1, 4) (4, 1)

The probability is the quotient of the number of outcomes of the sum of 2 or 5 and the total outcomes.

Thus,

Probability = 5/36 * 100% = 13.89% ≈ 14%

Read more about Probability of winning at; https://brainly.com/question/24756209

#SPJ1

Answer:

[tex]\huge\boxed{\sf x(x + 4)}[/tex]

Step-by-step explanation:

Given expression:

x² + 4x

Take x common

x(x + 4)

[tex]\rule[225]{225}{2}[/tex]

Answer:

it's difficult , sorry

Step-by-step explanation:

ask easily one

HOPE IT HELP (≧▽≦)(≧▽≦)(≧▽≦)

Answer:

Step-by-step explanation:

the answer is wrong its  34.3

Answer: Total cost/month = 7 + 3x

Step-by-step explanation:

This is only the total cost per month that is why it is only 7 and 3x since the number of downloaded games is not given.

I'm not sure about my answer but I hope that it helps.

Answer:

x = 4

Step-by-step explanation:

x(x + 8) = 48

x² + 8x = 48

x² + 8x - 48 = 0

times into -48

add into 8

(x - 4)(x + 12) = 0

x - 4 = 0

x = 4

or

x + 12 = 0

x = -12

A length cannot be a negative number therefore x = 4