Answer:
AA+b Ac+b
Explanation:
When radium-226 experiences alpha decay, the relative mass of the particle released in amu is
Energy of a photon is equal to 4.655 (4.44 + 0.08).
=0.135MeV=135KeV
Nature contains the radioactive element Ra-226. In 1898, Pierre and Marie Curie were working with uranium ore when they made the discovery of radium.
Uranium-238 undergoes radioactive decay, resulting in Ra-226.
A light paint was also created by combining radium-226 with fluorescent zinc sulfide. During and after World War I, this luminescent paint was employed to decorate watches, compasses, and other equipment.
High radium levels can result in cancer (particularly bone cancer), anemia, a blood issue, shattered teeth and cavities, and cataracts, growths in the eyes.
Some of these medical issues take years to manifest. The majority are brought on by gamma radiation, which can spread widely through the atmosphere.
The mineral uraninite contains the highest concentrations of radium 226 in nature, while it can be found in different proportions in almost all types of rocks and soils that contain naturally occurring uranium.
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How many valence electrons are in the outermost shell of all noble gases except helium?
Answer:
8
Explanation:
All noble gases have 8 electrons in their outermost shell and are in an octet state.
Consider the reaction below Which species is/are) the Bronsnsted-Lowry base(s)?HCO₃⁻ (aq) + F⁻ (aq) = CO₃²⁻ (aq) + HF (aq)A) F-,HFB) HCO3-, F-C) CO32-, HFD) CO32-, F-
Answer
D) CO₃²⁻, F⁻
Explanation
A Brønsted-Lowry acid is a compound that supplies a hydrogen ion in a reaction. A Brønsted-Lowry base, conversely, is a compound that accepts a hydrogen ion in a reaction. Thus, the Brønsted-Lowry definitions of an acid and a base focus on the movement of hydrogen ions in a reaction, rather than on the production of hydrogen ions and hydroxide ions in an aqueous solution.
HCO₃⁻ (aq) + F⁻ (aq) = CO₃²⁻ (aq) + HF (aq)
Therefore, in the reaction above, the species that is/are Bronsnsted-Lowry base(s) are CO₃²⁻ and F⁻
Thus, the correct answer is: D) CO₃²⁻, F⁻
Where is visible light located on the EM spectrum?A. Right in the middleB. It isn’t on the EM spectrumC. All the way to the rightD. All the way to the left
explanation - Visible light sits in the region with ultraviolet (UV) to the left of the spectrum.
see picture below :
• The picture shows exactly where the visible light is located in the electromagnetic spectrum .
• That is to the left of the ultraviolet radiation, and to the right of infrared (IR).
calculate the percentage oxygen in aluminum phosphate
To determine the percentage of oxygen in the molecule we must first know its structure and how many oxygen atoms are contained in it. The structure of aluminum phosphate is AlPO4.
It means that there are 4 oxygen atoms, 1 Aluminum atom, and 1 phosphate atom.
Now we will determine the weight of the molecule AlPO4 by adding the atomic weights of the elements as follows:
Element Atomic mass # of atoms Mass
Al 26.9815 1 26.9815
P 30.9738 1 30.9738
O 15.999 4 63.996
Total mass of AlPO4 = 26.9815+30.9738+63.996 = 121.9513 g/mol
Now we will determine the mass percentage with the following equation:
[tex]\text{Mass percentage = }\frac{Oxygen\text{ mass}}{\text{Total mass of the molecule }}\times100[/tex]We replace the known terms:
[tex]\begin{gathered} \text{Mass percentage = }\frac{63.996}{\text{121.9513 }}\times100 \\ \text{Mass percentage = }52.477 \end{gathered}[/tex]So, the percentage of oxygen in aluminum phosphate is 52.477%
Which of the following is an example of only a physical change? (1 point)Odry ice becoming vaporthe green color of the Statue of Libertythe creation of table saltO the smell of rotten eggs
Answer:
Dry ice becoming vapor.
Explanation:
In a physical change, the substance is the same, but in this case, it changes state from solid to vapor.
Please I need answer to this question
Answer:
What??
I dont understand the questii
Please I need answer to my question
Calcium carbonate (CaCO3) is not an organic substance since it only contains one of the two elements—carbon or hydrogen.
To identify whether a compound is organic, it is important to check:
if the compound contains carbon, hydrogen, and other non-metals altogetherthere should be no metal in the compoundIf a compound contains one of two elements, that is Carbon or Hydrogen, then it is not an organic compound.
Carbohydrates are a common type of organic compound. Carbohydrates contain the chemical formula (CH2O)n.
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19) A sample of metal ore is reacted according to the following reaction:Fe(s) +2HCL (aq) --> FeCl2(aq) + H2(g)If 24.06 mL of 5.6 M HCL are used, what mass of Fe was in the ore? Keep the answer with 2 decimal places
Assuming all the HCl presend in the 24.06mL reacted, we can follow the steps:
1 - Use the concentration and the volume to calculate the number of moles of HCl that reacted
2 - Apply the stoichiometry ratios to calculate the number os moles of Fe that reacted
3 - Use the tomic weight of Fe to calculate the mass of that amount of number of moles of Fe.
1 - The concentration is given by the equation:
[tex]C=\frac{n_{\text{solute}}}{V_{\text{solution}}}[/tex]The number of moles of solute is the same as the number of moles o HCl, because it is the solute in this case:
[tex]\begin{gathered} C=\frac{n_{HCl}}{V_{\text{solution}}_{}} \\ n_{HCl}=C\cdot V_{\text{solution}} \end{gathered}[/tex]So, we have:
[tex]\begin{gathered} C=5.6mol/L \\ V_{\text{solution}}=24.06mL=24.06\times10^{-3}L \\ n_{HCl}=5.6mol/L\cdot24.06\times10^{-3}L=0.134736mol \end{gathered}[/tex]2 - The coefficients of Fe and HCl are 1 and 2, respectively, so we have the following relation between their number of moles:
Fe --- HCl
1 --- 2
[tex]\begin{gathered} \frac{n_{Fe}}{1}=\frac{n_{HCl}}{2} \\ n_{Fe}=\frac{n_{HCl}}{2}=\frac{0.134736mol}{2}=0.067368mol \end{gathered}[/tex]3 - The atomic weight of Fe can be checked on a periodic table:
[tex]M_{Fe}=55.845g/mol[/tex]So, we have:
[tex]\begin{gathered} M_{Fe}=\frac{m_{Fe}}{n_{Fe}} \\ m_{Fe}=n_{Fe}M_{Fe}=0.067368mol\cdot55.845g/mol=3.76216\ldots g\approx3.76g \end{gathered}[/tex]So, there was approximately 3.76 g of Fe.
How many molecules of n2o4 are in 76.3 g n2o4 ? The molecular mass of n2o4 is 92.02g/mol
Help please 30 POINTS!!!!
if you have 4.0 moles of nitrogen and 5.0 moles of hydrogen, what is the maximum amount of ammonia that you can produce?
Answer:
Explanation:
Here, we want to get the maximum amount of ammonia that can be produced
From the question, we have it that:
1 mole nitrogen gave 2 moles ammonia
Thus:
4 mole nitrogen will give 8 moles ammonia
Furthermore:
3 moles of hydrogen gave 2 moles of ammonia
5 moles of hydrogen will give:
[tex]\frac{5\times2}{3}\text{ = }\frac{10}{3}[/tex]The maximum amount of ammonia that can be produced is thus 8.0 moles
In the earth's mantle and core, how do the mass and density compare?
The core is denser than the mantle.
The Earth is partitioned into three primary layers. The hot inner core, the molten outer core, the mantle, and where the thin crust, support all life within the known universe. Most of the Earth's insides are made up of the mantle, the layer of molten rock underneath the strong outside, and the hot, dense core. As the mass and the volume of the mantle are greater than the core's mass which leads the mantle of having a low density. as a result the core is considered to be having more density than the mantle in spite of the mantle having more mass.
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Samples of two metals of equal mass but with different heat capacities are originally at the same temperature. Il the same amounto1'heat is added to both samples, for which metal will the final temperature be lower (assume that no phase change, such as meltng, occurs).
The heat capacity corresponds to the energy needed to raise one degree of temperature for one gram of substance. That is, the greater the heat capacity, for the same mass, the greater the energy required to raise the temperature of the material.
Therefore, between the two metals with the same mass, the same initial temperature, and the same heat added, we can say that the one with the higher heat capacity will present a lower final temperature.
b) Given the following standard enthalpy changes at 298 K, calculate the standard enthalpy change for the reaction given below. S(s) + O2(g) → SO2 (g) AH = -296.8 kJ mol-1 SO2(g) + 3/2 O2(g) → SO3 (g)AH = -98.9 kJ mol-¹ S(s) + 3/2 O2(g) → SO3 (g) AHr = ?
−791.4 kJ is the standard enthalpy change for the reaction.
Given,
SO2(g) → S(s) + O2(g)
ΔH° = +296.8 kJ
2SO2(g) + O2(g) → 2SO3(g)
ΔH° = −197.8 kJ
Modified equation:
S(s) + 2O2(g) → 2SO2(g)
ΔH° = −593.6 kJ, multiply by 2 and flip
2SO2(g) + O2(g) → 2SO3(g)
ΔH° = −197.8 kJ here no change
The 2SO2 will balance out by canceling it when the equations are added. Add the enthalpies for the final answer:
−593.6 + (−197.8) = −791.4 kJ
The change in enthalpy of a compound when one mole of the compound is generated from all components of the same constituent is known as the standard enthalpy of formation, also known as the standard heat of formation.
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Please HELP!!!?! Describe competitive and noncompetitive in inhibitors describe how mutations can lead to resistance with non-competitive inhibitors
A competitive inhibitor physically mimics the substrate for a specific enzyme and engages in binding competition with the substrate at the enzyme's active site.
A noncompetitive inhibitor can bind to either the free enzyme or the enzyme-substrate complex and binds at a location different from the active site.
What are inhibitors that are competitive and noncompetitive? How do they function?The substrate cannot attach to the active site because the competitive inhibitor is bound there. The noncompetitive inhibitor attaches to a different spot on the enzyme.
The inhibitor binds at an allosteric location apart from the active site of substrate binding in noncompetitive inhibition. Therefore, in noncompetitive inhibition, the inhibitor can attach to its target enzyme even if a bound substrate is present.
Inhibitors that are non-competitive can bind to both the enzyme and the enzyme-substrate complex. Uncompetitive inhibitors only bind to the complex of the enzyme and substrate.
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What ions are present in Fe(NO3)3 (aq) solutions?
Explanation:
Iron (III) nitrate is a soluble salt. When dissolved in water it will dissociate into its ions: Iron (III) and nitrate.
Fe(NO₃)₃ (aq) ----> Fe³⁺ (aq) + 3 NO₃⁻ (aq)
Answer: Fe³⁺ and NO₃⁻.
2.04 x 10^23 atoms of carbon to grams
Answer
Mass of carbon = 4.069 g
Explanation
Given:
Number of atoms = 2.04x10^23 atoms
Required: Mass of carbon
Solution
Step 1: Find the number of moles of carbon
1 mole = 6.022x10^23 atoms
x moles = 2.04x10^23 atoms
Solve for x
x = (2.04x10^23 atoms x 1 mole)/6.022x10^23 atoms
x = 0.339 mol
Step 2: From the moles, calculate the mass of carbon
m = n x M where m is the mass, n is the moles and M is the molar mass of carbon
m = 0.339 mol x 12,011 g/mol
m = 4.069 g
What Mass of Lithium nitrate would have to be dissolved in 30.0g of water in order to make an 18%. Solution?
The mass of lithium nitrate that needs to de dissolved in 30.0g of water in order to make 18% solution is 6.58 grams.
The Percentage Concentration of a solution is the calculation of concentration of an element in a solution using the masses of solute/solvent and solution. It can be defined by the formula:
=> Percentage = (Mass of solute/Mass of solution)*100
The density of water is 1 gm/cm³, so the mass of 30.0g of water is 30ml. 18% concentration is given. The formula for percentage of concentration is given as
Percentage = (Mass of solute/Mass of solution) × 100
Here, Mass of solute is m, Mass of solution is m+30, and percentage is 18, So we get
=> 18 = (mass of solute/Mass of solution) × 100
=> 18 = (m/m+30)*100
=> 18(m+30) = m
=> 18m + 540 = 100m
=> 82m = 540
=> m = 6.58
Hence, the mass of lithium nitrate dissolved in 30g water to make 18% solution is 6.58g.
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CS₂(l) + 3O₂(g) → CO₂(g) + 2SO₂(g) 13. What volume of O₂(g) is required to react with excess CS₂(l) to produce 4.0 L of CO₂(g)? (Assume all gases are measured at 0°C and 1 atm.)
The volume of a substance at STP for one mole is 22.4 L. The volume of oxygen required to react with excess of carbon sulphide to produce 4 L of carbon dioxide 4.0 L is 12 L.
What is volume?Volume of a substance is the space occupied by the particles of the substance. As the temperature increase, volume also increases. The volume of one mole of every substance at standard temperature and pressure is 22.41 L
According the balanced reaction given, 3 moles of O₂ is required to produce one mole carbon dioxide. One mole of O₂ is 22.4 L. Thus volume of 3 moles of oxygen is calculated as follows:
Volume of O₂= 3×22.41 =67.2 L.
Thus, 67.2 L of O₂ produces one mole or 22.4 L of carbon dioxide.
The volume O₂ required to produce 4 L of carbon dioxide is calculated as follows:
Volume of O₂ = (67.2 L × 4 L) / 22.41 L
= 12 L.
Therefore, the volume of oxygen molecule required to produce 4 L of carbon dioxide on the reaction with excess of carbon sulphide is 12 L.
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Given the decomposition reaction:2SI3(g)->2SO2(g) + O2(g)According to Le Châtelier’s principle, what will happen when the volume of the container is increased for the chemical reaction that had reached equilibrium? A)Increasing volume, increases pressure and favors the products. B) Increasing volume, decreases pressure and favors the products.C)Increasing volume, increases pressure and favors the reactants.D) Increasing volume, decreases pressure and favors the reactants.
To analyze the equilibrium and how it shifts aaccording to Le Châtelier’s principle, we have to see how the system reacts to the change.
The change is an increase in the volume of the container. Since all the compounds on equilibrium are in gaseous state, their volume is the same as its container, so an increase in the volume of the container increase the volume of the compounds.
The reactant is SI₃, but we have 2 of them for each reaction.
The products are 2 molecules of SO₂ and one molecule of O₂.
In total for each reaction, we have 2 molecules in the reactant part and 3 molecules in the product part.
Since they are all in gaseous form, this means that the products occupy more space than the reactants, that is, an increase in the volume will favor the products, because this increase will left more space for them to occupy.
Thinking in preassure, an increase in the volume will decrease pressure, because, by the Boyle's Law, they are inversely proportional (assuming ideal gas). Since there are more molecules per reaction on the products side, this will favor the products, since more molecules make more pressure and now it has been decreased.
Thus:
Increase in volume -> decrease in pressure -> favors the products.
This matches alternative B.
What is the minimum temperature at which 59 g of NH4Cl would completely dissolve in 100 grams of water?
1) Identify the curve of the solute.
2) Look for the grams of solute in the vertical axis.
3) Go down looking for the temperature
The minimum temperature at which 59 g of NH4Cl would completely dissolve in 100 g H2O is 70ºC.
1. Which of the following elements are metals, nonmetals and metalloids?
As, Xe, Fe, Li, B, Cl, Ba, P, I, Si.
Answer:
Aluminium, Thorium, Barium and Strontium. Nonmetals will be : Fluorine, Phosphorus and Krypton. Metalloids will be : Gallium and Tellurium.
I need help with solving this problem
Which of the following substances dissolves most readily in water?a. CHb. NH3c. BaSO4d. CaCO3
BaSO₄. Option C is correct
ExplanationsThe substances that dissolve readily in water are ionic compounds and polar covalent compounds. Examples of ionic compounds that dissolve in water are salts, oxides, hydroxides, sulfides, and the majority of inorganic compounds.
The molecules in a polar solvent have a dipole, like water, one side is more negative and one is more positive.
Ionic compounds are composed of a positive ion, normally a metal, and a negative ion, normally a nonmetal, so their forces are attracted to their charge difference.
Thus, a polar solvent dissolves each ion with its corresponding parts, dissociating the two ions of the ionic compound.
Since sulfides are ionic compounds hence the substance that will dissolve most readily in water is BaSO₄. The molecule is formed by one barium cation Ba2+ and one sulfide anion S2-. The two ions are bound through an ionic bond.
Which of the following are SI units? Select all that apply.gLs
INFORMATION:
We have the following options
g
L
s
And we must select the options that are SI units.
STEP BY STEP EXPLANATION:
The SI units are:
- For mass: Kg
- For volume: cm^3
- For time: s
- For length: m
Finally, we can see that from given options, s is the unique that belongs to the SI units.
ANSWER:
s
.A voltaic cell consists of a Ni electrode in 1.0M Ni(NO3
)2
and an Fe electrode
in 1.0M Fe(NO3
)2
.
Calculate E°
cell for the spontaneous cell reaction at 25°C
The standard electrode potential value of a cell can be calculated from the reduction potentials of the electrodes. The standard electrode potential E⁰ of the voltaic cell with Ni electrode and iron electrode is 0.19 V.
What is standard electrode potential?The reduction potential of an electrode at standard conditions that is at 298 K and 1 bar pressure is called standard electrode potential.
There are two types of electrodes in a cell called cathode and anode. Cathode is the electrode at which reduction occur where as the electrode which undergo oxidation is called anode.
The standard electrode potential of a cell can be measured as follows.
[tex]E^{0} _{cell} = E^{0} _{cathode} - E^{0} _{anode}[/tex]
Here, the anode is Fe electrode with a standard electrode potential of -0.44 V and the anode is Ni electrode having -0.25 V reduction potential.
Thus the standard electrode potential of the voltaic cell can be calculated as follows:
[tex]E^{0} _{cell} = E^{0} _{Ni^{2+}/Ni} = E^{0} _{Fe/Fe^ {2+}}[/tex]
= (-0.25 v) - (-0.44 v)
= 0.19 V.
Hence, the standard electrode potential of the cell E⁰ containing Ni electrode and Fe electrode is 0.19 V.
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i need help on question 2For each of the reactions below, write the (i)equilibrium constant expression, (ii) find its value,and (iii) determine if it’s reactant-favored, product-favored, or neither.(a) N 2 (g) + 3 H 2 (g) -----> 2 NH 3 (g)[N 2 ]eq = 1.50 M [H 2 ]eq = 2.00 M[NH 3 ]eq = 0.01 M(b)HF(aq) -----> H + (aq) + F – (aq)[HF] eq = 0.55 M [H + ] eq = 0.001 M[F – ] eq = 0.001 M(c) Fe 3+ (aq) + SCN – (aq) -----> FeSCN 2+ (aq)[Fe 3+ ] eq = 0.55 M [SCN – ] eq = 0.001M[FeSCN 2+ ] eq = 0.001 M
Answer
Explanation
Part A
Given:
a) N₂ (g) + 3H₂ (g) -----> 2NH₃ (g)
[N₂ ]eq = 1.50 M, [H₂ ]eq = 2.00 M, [NH 3 ]eq = 0.01 M
Solution:
i. The equilibrium constant expression for the reaction is
[tex]Kc=\frac{[NH_3]^2}{[N_2][H_2]^3}[/tex]Determine whether the bond between each of the following pairs of atoms is purely covalent, polar covalent, or ionic.
- I and Cl
-C and O
- Ca and F
- P and P
The kind of bonds that can be formed between each of the atoms is;
I and Cl - ionic bondC and O - polar covalent bond Ca and F - ionic bond P and P - covalent bondWhat is the Ionic bond?The ionic bond is the kind of bond that is formed between two atoms in a compound when there is a complete transfer of electrons between the atoms in the compound.
A covalent bond is said to be formed between two atoms when there is a sharing of the electrons that can be found between two atoms. We know that a bond is ionic when the difference in the electronegativity of the atoms is high.
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Density
Which of the following do you think is more dense?
Water
Ping Pong Ball
Which is more dense a drop of water or ping pong ball
A drop of water is denser than a ping-pong ball.
Usually, water is made of particles that are firmly pressed together. In differentiation, plastic (the material ping pong balls are made of) may be a lightweight fabric and the particles are not as firmly stuffed together.
The thickness of a ping pong ball is 0.0840 g/cm³, though water’s thickness is 997 kg/m³. Subsequently, ping pong balls aren’t about as thick as water and will continuously coast and surface greatly quickly.
The ping pong ball appears to oppose gravity and coast within the air.
Ping-pong balls drift within the water since they are amazingly lightweight, empty, and filled with air. Too, the water’s surface pressure makes it simple for the ping pong ball to drift.
In expansion, water is denser than ping pong balls, making them look for the most noteworthy point of water.
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