Which equations have the same value of x as 5/6x + 2/4 = -9? Select three options.
6(5/6x + 2/3)= -9
6(5/6x + 2/3)= -9(6)
5x+4-54
5x4-9
5x=-13
5x=-58

A correlation coefficient between number of miles driven and number of gallons of gas remaining is most likely to be 0 to -1. Then the correct option is A.

A mathematical indicator of the degree of the association seen between fluctuation of 2 factors is the correlation coefficient.

A correlation coefficient between number of miles driven and number of gallons of gas remaining is most likely to be 0 to -1.

Then the correct option is A.

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Probability helps us to know the chances of an event occurring. The correct option is D, not picking a circle.

Probability helps us to know the chances of an event occurring.

[tex]\rm Probability=\dfrac{Desired\ Outcomes}{Total\ Number\ of\ outcomes\ possible}[/tex]

For the theoretical probability to be 3/4, the number of desired outcomes must be 6. Therefore, let's check the number of desired outcomes,

Not picking a triangle = 4

Picking a square = 3

Picking a shape with only straight edges = 0

Not picking a circle = 6

Not picking a square = 5

Hence, the correct option is D, not picking a circle.

The group of the shape is given in the below image.

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The value of line AL is 21. 51cm

To find line AL,

Using

Sin α = opposite/ hypotenuse to find line AB

Sin 90 = x/ 24

1 = x/24

Cross multiply

x = 24cm

Now, let's find line AC

Sin angle B = line AC/24

Note that to find angle B

angle A + angle B + angle C = 180

But angle B = 2 Angle A

x + 2x + 90 = 180

3x + 90 = 180

3x = 180-90

x = 30°

Angle B = 2 × 30 = 60°

Sin 60 = x/ 24

0. 8660 = x/24

Cross multiply

x = 24 × 0. 8660

x = 20. 78cm

We have the angle of A  in the given triangle to be divide into two by the bisector, angle A = 15°

To find line AL, we use

Cos = adjacent/ line AL

Cos 15 = 20. 78/ line AL

Line AL = 20. 78/ cos 15

Line AL = 20. 78 / 0. 9659

Line AL = 21. 51 cm

Thus, the value of line AL is 21. 51cm

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The probability of winning the lottery with one ticket is mathematically given as

P(W)=2.99484408*10^{−8}

Generally, the equation for the probability is  mathematically given as

P(1st ball)=1/34

one ball drawn remain

34-1=33

P(2nd ball)=1/33

In conclusion, the probability of winning the lottery with one ticket is

P(W)=1/34*1/33*1/32*1/31*1/30

P(W)=2.99484408*10^{−8}

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The value of the quotient is  [tex]\frac{45\cos(\frac{\pi}{4}) i\sin(\frac{\pi}{4})}{\cos(\frac{\pi}{12}) i\sin(\frac{\pi}{12})} = 45(\cos(\frac{\pi}{6}) + i\sin(\frac{\pi}{6}))[/tex]

The expression is given as:

[tex]\frac{90\cos(\frac{\pi}{4}) i\sin(\frac{\pi}{4})}{2\cos(\frac{\pi}{12}) i\sin(\frac{\pi}{12})}[/tex]

Divide 90 by 2

[tex]\frac{45\cos(\frac{\pi}{4}) i\sin(\frac{\pi}{4})}{\cos(\frac{\pi}{12}) i\sin(\frac{\pi}{12})}[/tex]

As a general rule, we have:

[tex]\frac{\cos(\frac{\pi}{A}) i\sin(\frac{\pi}{A})}{\cos(\frac{\pi}{B}) i\sin(\frac{\pi}{B})} = \cos(\frac{\pi}{2B/A}) + i\sin(\frac{\pi}{2B/A})[/tex]

The above means that:

A = 4 and B = 12

So, we have:

2B/A = 2 * 12/4

Evaluate

2B/A = 6

So, the equation becomes

[tex]\frac{\cos(\frac{\pi}{4}) i\sin(\frac{\pi}{4})}{\cos(\frac{\pi}{12}) i\sin(\frac{\pi}{12})} = \cos(\frac{\pi}{6}) + i\sin(\frac{\pi}{6})[/tex]

Substitute [tex]\frac{\cos(\frac{\pi}{4}) i\sin(\frac{\pi}{4})}{\cos(\frac{\pi}{12}) i\sin(\frac{\pi}{12})} = \cos(\frac{\pi}{6}) + i\sin(\frac{\pi}{6})[/tex] in [tex]\frac{45\cos(\frac{\pi}{4}) i\sin(\frac{\pi}{4})}{\cos(\frac{\pi}{12}) i\sin(\frac{\pi}{12})}[/tex]

[tex]\frac{45\cos(\frac{\pi}{4}) i\sin(\frac{\pi}{4})}{\cos(\frac{\pi}{12}) i\sin(\frac{\pi}{12})} = 45(\cos(\frac{\pi}{6}) + i\sin(\frac{\pi}{6}))[/tex]

Hence, the value of the quotient is  [tex]\frac{45\cos(\frac{\pi}{4}) i\sin(\frac{\pi}{4})}{\cos(\frac{\pi}{12}) i\sin(\frac{\pi}{12})} = 45(\cos(\frac{\pi}{6}) + i\sin(\frac{\pi}{6}))[/tex]

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Complete question

What is the quotient of [tex]\frac{90\cos(\frac{\pi}{4}) i\sin(\frac{\pi}{4})}{2\cos(\frac{\pi}{12}) i\sin(\frac{\pi}{12})}[/tex]

The equation of the parabola is y = 0.015x^2 + 0.06x + 1

A parabola is represented as:

y = ax^2 + bx + c

The points are given as:

(-4,1), (-2,0.94) and (0,1)

When these points are substituted in y = ax^2 + bx + c, we have the following linear equations

16a - 4b + c = 1

4a - 2b + c = 0.94

c = 1

In (a), we have:

16a - 4b + c = 1

4a - 2b + c = 0.94

c = 1

Remove the variables (leaving the coefficients)

a      b       c

16    -4      1        1

4      -2     1        0.94

0      0     1          1

So, the matrix representation of the system of equations is:

[tex]\left[\begin{array}{ccc}16&-4&1\\4&-2&1\\0&0&1\end{array}\right] \left[\begin{array}{c}1&0.94&1\end{array}\right][/tex]

Using a graphing calculator, we have the inverse of the coefficient matrix to be

[tex]\left[\begin{array}{ccc}0.125&-0.25&0.125\\0.25&-1&0.75\\0&0&1\end{array}\right][/tex]

Using a graphing calculator, we have the solution to the system of equations to be

a = 0.015

b = 0.06

c = 1

Recall that:

y = ax^2 + bx + c

So, we have:

y = 0.015x^2 + 0.06x + 1

Hence, the equation of the parabola is y = 0.015x^2 + 0.06x + 1

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The events are not mutually exclusive.

Two events that cannot occur at the same time are called Mutually exclusive event.

It is given that

A sample of 75 books is selected from a library.

Event A:  At least 10 of the authors are female

Event B : At least 10 of the books are fiction.

Both can happen simultaneously

Therefore the events are not mutually exclusive.

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The student, who suggests that if we do half and half of each bag, we will be giving them at least 60%, is correct.

The phrase "at least" means the minimum that is true or possible.

Mathematically, by "at least," we mean 'equal to or greater than.'

Since each bag of nuts contain 16 ounces,

The 1st bag contains x/2 ounces (50%) of plain nuts and x/2 ounces (50%) of chocolate-covered nuts.

The 2nd bag contains x/5 ounces (20%)of plain nuts and 4x/5 ounces (80%) of chocolate-covered nuts.

If half of the 1st bag is mixed with half of the 2nd bag, each bag will contain only 65% (that is, 25% (50%/2) from the 1st bag and 40% (80%/2) from the 2nd bag).

Thus, the student, who suggests that if we do half and half of each bag, we will be giving them at least 60%, is correct since they will not be given less than 60% of chocolate-covered nuts inside.

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Answer:

x = - 1

Step-by-step explanation:

[tex]\frac{3}{4}[/tex] (8x + 12) = 3 ( multiply both sides by 4 to clear the fraction )

3(8x + 12) = 12 ( divide both sides by 3 )

8x + 12 = 4 ( subtract 12 from both sides )

8x = - 8 ( divide both sides by 8 )

x = - 1

Using the z-distribution, with a critical z-score of z = 1.645, the 90% confidence interval is (-16.4%, -9.66%).

For each sample, the mean and the standard error are given as follows:

Hence, for the distribution of differences, they are given as follows:

The interval is:

[tex]p \pm zs[/tex]

In this problem, we have a 90% confidence level, hence[tex]\alpha = 0.9[/tex], z is the value of Z that has a p-value of [tex]\frac{1+0.9}{2} = 0.95[/tex], so the critical value is z = 1.645.

Then the bounds of the interval are:

As a percentage, the 90% confidence interval is (-16.4%, -9.66%).

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The net present value of machine is $5982

An investment is an asset or item acquired with the goal of generating income or appreciation.

As, 4th Year Cash Flow

= Salvage Value + Expected End Year Net Cash Flow

= $1,200 + $12,500

= $13,700

Year     Cash flow ($)             PVF at 8%             Present value ($)

0               37,500                         1.000                     -36,300

1                  12,500                      0.9259                 11573.75

2                 12,500                      0.8573                 10716.25

3                  12,500                      0.7938                 9922.5

4                  13,700                      0.7350                  10069.5

Net value                   5982

Hence, net present value of machine is $5982

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Answer: [tex]p=7, q=3[/tex]

Step-by-step explanation:

The midline of the function is

[tex]\frac{10-4}{2}=3 \implies q=3[/tex]

This means that to obtain a maximum of 10, when [tex]\sin x[/tex] reaches it's maximum, 1, [tex]g(x)=p+q=10 \implies p=7[/tex]

Answer:

81m + 27t

Step-by-step explanation:

Using distributive property, this expression can be solved.

So 9(9m + 3t) has operations in it.

9 would be multiplied by whatever is in the parenthesis followed by the variable.

So 9 * 9 = 81.

9 * 3 = 27.

So putting it together with the variables.

It would be:

⇒ 81m + 27t  

The solution to the given linear equation are -4 and 2

Quadratic equations are equations that has a leading degree of 2. Given the expression below

(x-3)(x+1)=5

Expand

x^2+x - 3x - 3 = 5

x^2 - 2x - 8 =0

Factorize

x^2 + 4x - 2x - 8= 0

x(x+4)-2(x+4) = 0

x = -4 and 2

Hence the solution to the given linear equation are -4 and 2

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Answer:

y = (-2/3)x + 5/6

Step-by-step explanation:

The general structure of a line in slope-intercept form is:

y = mx + b

In this form, "m" represents the slope and "b" represents the y-intercept. You have been given the value of "m". To find the value of "b", you can plug the slope and the values from the point (2, -1/2) into the general equation.

m = -2/3

Point (2, -1/2):

x = 2 and y = -1/2

y = mx + b                                  <----- Slope-intercept form

y = (-2/3)x + b                            <----- Insert -2/3 in "m"

-1/2 = (-2/3)(2) + b                      <----- Insert "x" and "y" values from point

-1/2 = -4/3 + b                            <----- Multiply -2/3 and 2

-3/6 = -8/6 + b                           <----- Give the fractions common denominators

5/6 = b                                      <----- Add 8/6 to both sides

Thus, the equation of the line is:

y = (-2/3)x + 5/6

Answer:

y = 3x - 13

Step-by-step explanation:

We are given the points (7,8) and (3,-4)

We want to write an equation of the line that passes through those 2 points.

There are 3 ways to write the equation of the line:

Although while any one of these options work, the most common way is to use slope-intercept form, so let's do it that way.

First, we need to find the slope of the line.

The slope (m) can be found using this formula: [tex]\frac{y_2-y_1}{x_2-x_1}[/tex], where [tex](x_1, y_1)[/tex] and [tex](x_2,y_2)[/tex] are points.

Even though we already have 2 points, let's label their values to avoid any confusion.

[tex]x_1=7\\y_1=8\\x_2=3\\y_2=-4[/tex]

Now substitute these values into the formula.

m=[tex]\frac{y_2-y_1}{x_2-x_1}[/tex]

m=[tex]\frac{-4-8}{3-7}[/tex]

Subtract.

m=[tex]\frac{-12}{-4}[/tex]

Divide.

m = 3

The slope of the line is 3.

Here is the equation of the line so far:

y = 3x + b

We now need to find b.

As the equation passes through  (7,8) and (3,-4), we can use either one of the points to help us solve for b.

Taking (7,8) for instance:

Substitute 7 as x and 8 as y in the equation.

8 = 3(7) + b

Multiply

8 = 21 + b

Subtract 21 from both sides

-13 = b

Substitute -13 as b in the equation.

y = 3x - 13

Topic: finding the equation of the line

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A line is a one-dimensional shape that is straight, has no thickness, and extends in both directions indefinitely. The equation of the line that passes through the points (7,8) and (3,-4) is y=3x-13.

A line is a one-dimensional shape that is straight, has no thickness, and extends in both directions indefinitely. The equation of line is given by,

y =mx + c

where,

x is the coordinate of the x-axis,

y is the coordinate of the y-axis,

m is the slope of the line, and

c is the y-intercept.

The slope of the equation will be,

Slope, m = (-4-8)/(3-7) = -12/-4 = 3

Substitute one of the points in the equation of the line,

-4 = 3(3) + C

C = -13

Hence, the equation of the line that passes through the points (7,8) and (3,-4) is y=3x-13.

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The total time spent on his/her cell phone in a year’s time is less than the total time spent waiting in line when shopping in a lifetime.

x= 1825 hrs

z=4929.4 hrs.

This is further explained below.

let's say on average a person spends 5 hours on a mobile phone.

Individual annual mobile phone use time.

x=  5x365

x= 1825 hrs

let's consider an average every day a person, spent 5 minutes in the queue when shopping.

Take the average person. 70-year life for a person.

Hence in a year, he spent

y=365x5 mints

y=1825 min

y=30.42 hrs

Hence lifetime time spent on line

z = 70 x 30.42

z=4929.4 hrs.

In conclusion, we estimate that the typical individual will spend z=4929.4 hours waiting in line for merchandise throughout the course of their lifetime.

z=4929.4 hrs.

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When x = 64 and y = 3, we will have:

z = 3,313.21

First, we know that z varies directly with x and inversely with y², then we can write:

z = k*x/y^2

Where k is a constant.

We know that z = 182 when x = 25 and y = 8, replacing that we can find the value of k.

182 = k*25/(8²)

k = 182*8²/25 = 465.92

Now, we just need to evaluate the function in x = 64 and y = 3.

z = (465.92)*64/3² = 3,313.21

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Answer: b.) 40

Given that:

f(x) = 5 × 2ˣ

To find f(3), simplify insert [x = 3] in the given equation:

f(3) = 5 × 2³

f(3) = 5 × 2 × 2 × 2

f(3) = 40

Answer: B. x^2 + 3

Step-by-step explanation:

2x^2 + 2 -(x^2 - 1)

2x^2 + 2 - x^2 + 1

x^2 + 3

Answer:

(x-2)/(x-1)

Step-by-step explanation:

(x-2)/(x-1)

The values of a and b are 1/4 and 1/5 respectively

The function is given as:

16x^2 - 25y^2 = 1

The above function is a horizontal hyperbola.

A horizontal hyperbola that passes through the origin is represented as:

[tex]\frac{x^2}{a^2} - \frac{y^2}{b^2} = 1[/tex]

Rewrite 16x^2 - 25y^2 = 1 as

[tex]\frac{x^2}{1/16} - \frac{y^2}{1/25} = 1[/tex]

By comparison, we have:

[tex]a^2 = \frac{1}{16}[/tex]

[tex]b^2 = \frac{1}{25}[/tex]

Solve for  a and b

[tex]a = \frac{1}{4}[/tex]

[tex]b = \frac{1}{5}[/tex]

Hence, the values of a and b are 1/4 and 1/5 respectively

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Using complementary angles, it is found that a solution to the given equation is:

D. x = 16, sin 38° = cos 52°.

Two angles are called complementary if the sum of their measures is of 90º. If two angles A and B are complementary, we have that:

cos(A) = sin(B) and sin(A) = cos(B).

In this problem, the expression is:

cos(3x + 4) = sin(2x + 6).

Hence:

3x + 4 + 2x + 6 = 90

5x = 80

x = 16.

Then:

Which means that option D is correct.

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Answer:

1.33 repeating

Step-by-step explanation:

you just do 4 divided by 3.

Please mark as brianliest if i got it right

Hello !

    3y + 12 =2(y + 30)

⇔ 3y + 12 = 2y + 60

⇔ y + 12 = 60

⇔ y = 60 - 12

⇔ y = 48

Answer:

y = 48

Step-by-step explanation:

the exterior angle of a triangle is equal to the sum of the 2 opposite interior angles.

3y + 12 is an exterior angle of the triangle , so

3y + 12 = y + 30 + y + 30 ( base angles of an isosceles Δ are congruent )

3y + 12 = 2y + 60 ( subtract 2y from both sides )

y + 12 = 60 ( subtract 12 from both sides )

y = 48

The  last day for taking the cash discount is May 5  and discount is taken is: $12,398.6.

Since the invoice was dated April 12, the last day for taking the cash discount is May 5.

Cash discount

Using this formula

Amount paid =Invoice amount × (1-rate)

Let plug in the formula

Amount paid=$13,190 ×(1-6%)

Amount paid=$13,190×0.94

Amount paid=$12,398.6

Therefore the  last day for taking the cash discount is May 5 and the amount to be paid is: $12,398.6.

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Answer: [tex]\frac{25\pi}{4}[/tex]

Step-by-step explanation:

The area of the entire circle is [tex]\pi(5^2)=25\pi[/tex].

The area of a quarter of the circle is thus [tex]\frac{25\pi}{4}[/tex]

The function will go somewhere between x = 4 and x = 5

The function is given as:

y = 2^x

The question implies that:

If the maximum y value on a graph is x = 20; What is the maximum x value on the graph of y = 2^x

To do this, we start by setting y to 20.

So, we have:

2^x = 20

Take the logarithm of both sides

x log(2) = log(20)

Divide by log(2)

x = 4.32

4.32 is between 4 and 5

Hence, the function will go somewhere between x = 4 and x = 5

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