The equation that represents they function f(x) = (1.6)^x after it has been translated 5 units up and 9 units to the right is;
g(x) = [(1.6)^(x - 9)] + 5
We are given the function;
f(x) = (1.6)^x
Now,when we translate a function 9 units to the right, it means that we will subtract 9 from the x unit to give;
g(x) = (1.6)^(x - 9)
Now, when we translate it 5 units upwards, it means we are adding 5 to f(x). Therefore, we now have;
g(x) = [(1.6)^(x - 9)] + 5
Read more on translation of graphs at; https://brainly.com/question/11468584
Gravitational force acts on all object in proportion to their masses. Why then, a heavy object does not fall faster than a light object?
Answer:
[tex]\huge\color{pink}\boxed{\colorbox{black}{Answer♡}}[/tex]
The reason that a heavy body doesn't fall faster than a light body is because the greater gravitational force on the heavier body (its weight), acts on a correspondingly greater mass (inertia). The ratio of gravitational force to mass is the same for every body—hence all bodies in free fall accelerate equally.
hope helpful~
~Be Brainly!~ExhaustedZombieWhat is the simplest form of ^4sqrt324x^6y^8
[tex]\rm{\green{Answer \: is:-}}[/tex]
[tex]3xy \sqrt[24]{ {4x}^{2} } [/tex](3xy^2 4 sqrt 4x^2)
Step-by-step explanation:
Hope it's helpful to youLet's see
[tex]\\ \rm\Rrightarrow \sqrt[4]{324x^6y^8}[/tex]
[tex]\\ \rm\Rrightarrow \sqrt{4}{18^2x^6y^8}[/tex]
m√a^n=a^n/m[tex]\\ \rm\Rrightarrow 18^{2/4}x^{6/4}y^{8/4}[/tex]
[tex]\\ \rm\Rrightarrow \sqrt{18}x^{3/2}y^2[/tex]
[tex]\\ \rm\Rrightarrow \sqrt{18}\sqrt[2]{x^3}y^2[/tex]
What is the distance between (7, 1) and (-4, -5)?
Answer:
The distance between [tex](7,1)[/tex] and [tex](-4,-5)[/tex] is [tex]\sqrt{157}[/tex] units
Step-by-step explanation:
Use the distance formula [tex]d=\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}[/tex] where [tex]d[/tex] is the positive distance between [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex]:
[tex]d=\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}[/tex]
[tex]d=\sqrt{(-5-1)^2+(-4-7)^2}[/tex]
[tex]d=\sqrt{(-6)^2+(-11)^2}[/tex]
[tex]d=\sqrt{36+121}[/tex]
[tex]d=\sqrt{157}[/tex]
Therefore, the distance between [tex](7,1)[/tex] and [tex](-4,-5)[/tex] is [tex]\sqrt{157}[/tex] units
Answer: The distance between (7,1), and (-4, -5) is 12.53.
if f(x) = 2x-7 and g(x)= x2-5, find g[f(5)]
Answer:
4x-12
Step-by-step explanation:
2x-5[2x-7(5)}=2x+2x-7-5
4x-12
negative integers are added to each other
Bus route A arrives at its stop every 15 minutes. Bus route B arrives at its stop across the street every 30 minutes. If both buses are currently arriving at their stops, how many hours will pass before both buses arrive at the same time?
Answer:
2 stops, 30 min
Step-by-step explanation:
to figure this out we have to divide B's time by A's time. 30÷15 is 2.
Multiply. −5/6⋅27
A. −67 1/2
B. −32 1/4
C.−22 1/2
D.−18 1/2
Two parallel lines are crossed by a
transversal.
Answer:
h = 60˚
Step-by-step explanation:
Look at where it shows the 120˚, and its verticle angle. Verticle angles are congruent, or the same meaning it's also 120˚.
Then go to its corresponding angle, which is next to the h. Corresponding angles are also congruent, or the same. I'll call this angle m to save time and hopefully confusion.
Now, h and m are supplementary angles, meaning they add up to 180˚.
180˚ - 120˚, or 60˚ is your answer.
h = 60˚
The solution is, the value of h is, h = 60˚
What is an angle?In Plane Geometry, a figure which is formed by two rays or lines that shares a common endpoint is called an angle. The two rays are called the sides of an angle, and the common endpoint is called the vertex.
here, we have,
from the given figure, we get,
Look at where it shows the 120˚, and its vertical angle.
Vertical angles are congruent, or the same meaning it's also 120˚.
now, we have,
Then go to its corresponding angle, which is next to the h. Corresponding angles are also congruent, or the same.
We call this angle m to save time and hopefully confusion.
Now, h and m are supplementary angles,
meaning they add up to 180˚.
so, we have,
180˚ - 120˚,
or 60˚ is your answer.
i.e.
h = 60˚
Hence, The solution is, the value of h is, h = 60˚
To learn more on angle click:
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Let f(x)=root2x. If the rate of change of f at x=c is four times its rate of change at x=1 then c=?
Answer:
[tex]c=\frac{1}{16}[/tex]
Step-by-step explanation:
[tex]f(x)=\sqrt{2x}[/tex]
[tex]f'(x)=\frac{\sqrt{2x}}{2x}[/tex]
[tex]f'(1)=\frac{\sqrt{2}}{2}[/tex]
[tex]f'(c)=\frac{\sqrt{2c}}{2c}[/tex]
[tex]f'(c)=4f'(1)[/tex]
[tex]\frac{\sqrt{2c}}{2c}=4(\frac{\sqrt{2}}{2})[/tex]
[tex]\frac{\sqrt{2c}}{2c}=2\sqrt{2}[/tex]
[tex]\sqrt{2c}=4c\sqrt{2}[/tex]
[tex]2c=32c^2[/tex]
[tex]2=32c[/tex]
[tex]\frac{1}{16}=c[/tex]
A group of friends wants to go to the amusement park. They have $180.50 to spend on parking and admission. Parking is $19.50, and tickets cost $23 per person, including tax. Write and solve an equation which can be used to determine pp, the number of people who can go to the amusement park.
equation:
answer p:
a.
The required equation is 23p + 19.50 = 180.50
Let p represent the number of people who can go to the amusement park.
Since the ticket costs $23 per person, the total amount paid for ticket is rate × number of person = $23 × p = 23p.
Since we pay $19.50 for parking, the total amount spent is T = 23p + 19.50
Since the total amount equals $180.50. T = 180.50
So, 23p + 19.50 = 180.50
The required equation is 23p + 19.50 = 180.50
b.
Solving 23p + 19.50 = 180.50, we have
23p = 180.50 - 19.50
23p = 161
p = 161/23
p = 7
So, the number of people who can go to the amusement park is 7.
Learn more about linear equations here:
https://brainly.com/question/24307397
Can someone please help?
Answer:
Well a midpoint makes the cutter segment or Line in exactly in half. So the two lines cutted are equal. In this case t is the midpoint. PT and TQ are equal. So you have two expressions, make then equal to each other since they are congruent.
6x+4=8x-8
12=2x
x=6
Now PT is 6x+4
So we subsitute x for 6 since x=6
6*6+4
40
PT is 40
Pls help as I will give a 5 star rating thanks!!!!! :)
Answer:
Scale is 1/2
Step-by-step explanation:
5*1/2=5/2
12*1/2=6
An online furniture store sells chairs and tables. Each day, the store can ship at most 55 pieces of furniture. Write an inequality that could represent the possible values for the number of tables sold, t, and the number of chairs sold, c, that would satisfy the constraint.
Answer:
t+c ≤ 55
Step-by-step explanation:
t+c is the total pieces of furniture and it must be at most (less than or equal to) 55 so t+c ≤ 55 is the equality that represents the possible values.
The sum of 6 consecutive integers is 387. What is the sixth number in this sequence.
Answer:
67!
Step-by-step explanation:
A way to look at it is, since the number is 387, it can be broken into 6 parts. 50x6 is about 300. That leaves 87 to be left over. So it's safe to assume each number will be around 50-60, so I started to add up six consecutive numbers together until I reached my final set of numbers to reach 387.
My numbers were 62+63+64+65+66+67=387
I hope this makes sense!
How do I find the inverse?
g(x) as given has no inverse because there are instances of two x values giving the same value of g(x). For instance,
x = -1 ⇒ g(-1) = 4 (-1 + 3)² - 8 = 8
x = -5 ⇒ g(-5) = 4 (-5 + 3)² - 8 = 8
Only a one-to-one function can have an inverse. g(x) is not one-to-one.
However, if we restrict the domain of g(x), we can find an inverse over that domain. Let [tex]g^{-1}(x)[/tex] be the inverse of g(x). Then by definition of inverse function,
[tex]g\left(g^{-1}(x)\right) = 4 \left(g^{-1}(x) + 3\right)^2 - 8 = x[/tex]
Solve for the inverse:
[tex]4 \left(g^{-1}(x) + 3\right)^2 - 8 = x[/tex]
[tex]4 \left(g^{-1}(x) + 3\right)^2 = x + 8[/tex]
[tex]\left(g^{-1}(x) + 3\right)^2 = \dfrac{x + 8}4[/tex]
[tex]\sqrt{\left(g^{-1}(x) + 3\right)^2} = \sqrt{\dfrac{x + 8}4}[/tex]
[tex]\left| g^{-1}(x) + 3 \right| = \dfrac{\sqrt{x+8}}2[/tex]
Recall the definition of absolute value:
[tex]|x| = \begin{cases}x & \text{if }x\ge0\\-x&\text{if }x<0\end{cases}[/tex]
This means there are two possible solutions for the inverse of g(x) :
• if [tex]g^{-1}(x) + 3 \ge 0[/tex], then
[tex]g^{-1}(x) + 3 = \dfrac{\sqrt{x+8}}2 \implies g^{-1}(x) = -3+\dfrac{\sqrt{x+8}}2[/tex]
• otherwise, if [tex]g^{-1}(x)+3<0[/tex], then
[tex]-\left(g^{-1}(x) + 3\right) = \dfrac{\sqrt{x+8}}2 \implies g^{-1}(x) = -3-\dfrac{\sqrt{x+8}}2[/tex]
Which we choose as the inverse depends on how we restrict the domain of g(x). For example:
Remember that the inverse must satisfy
[tex]g\left(g^{-1}(x)\right) = x[/tex]
In the first case above, [tex]g^{-1}(x) + 3 \ge 0[/tex], or [tex]g^{-1}(x) \ge -3[/tex]. This suggests that we could restrict the domain of g(x) to be [tex]x \ge -3[/tex].
Then as long as [tex]x \ge -3[/tex], the inverse is
[tex]g^{-1}(x) = -3+\dfrac{\sqrt{x+8}}2[/tex]
write the equation in slo
pe intercept form -1=-2x+y
Answer:
y = -2x - 1
Step-by-step explanation:
Put y on the left and everything else on the right
Find a pair of positive integers for and b in these questions
18 + 65 = 1865
23 + 7 = 2314
Answer:
a=100
b=1
Step-by-step explanation:
18a+65b=1865
23a+7b=2314
We need to make one of the variables equal to the other
So...
The LCM for 65 and 7 is 455
So multiply 7 with 18a+65b=1865
and Multiply 65 with 23a+7b=2314
7 times 18a+65b=1865 is 126a+455b=13055
65 times 23a+7b=2314 is 1495a+455b=150410
So Subtract 126a+455b=13055 and 1495a+455b=150410
So 1369a=137355
Divide:
Which is about 100 (The actual value is 100.3323594)
Thus a=100
Substitute:
b=1
Hope this helps!
(The answer is rounded)
anybody help please again •_•
Answer:
i am not to sure but i think its 5/13 or 5/40
please help ASAP! What is the area of this figure?
Answer:
The answer is 75ft. Hope this helps.
Help please
I provided screenshots of the problem below.
Answer:
This is the graph of a sine function
The y-intercept of the graph is the function value y=0
The smallest positive x-intercept of the graph is located at x=pi/2
The greatest value of y is y=2
For x between x=-pi and x=pi/2, the function value y=>0
Step-by-step explanation:
(3-5i)^2
i know the answer I’m just confused on how to get to that point. Please and thank you!
[tex](3-5i)^2\\\\=3^2-2(3)(5i) + (5i)^2\\\\=9-30i +25i^2\\\\=9-30i +25(-1)~~~~;[i^2=-1]\\\\=9-30i-25\\\\=-16-30i[/tex]
Please help me with this
Answer:
A and F
Step-by-step explanation:
Which equation has a unite rate of 0.5
Answer:
r=0.5d
Step-by-step explanation:
please help me asap
ty..
Answer:
Y = 10x + 20
Step-by-step explanation:
sorry if im wrong
Answer:
y = 2x - 4
Step-by-step explanation:
10x - 5y = 20
Subtract 10x both sides
-5y = 20 + (-10x)
Divide by -5
y = -4 + 2x
y = 2x + (-4)
Given m=-2/3, b=-7 give the point in slope form, slope intercept form, standard form, ;general form. HELP IS NEED ASAP PLEASE!!!
Answer:
Step-by-step explanation:
m=-2/3
b=-7
First, find the slope-intercept form.
y=mx+b
You know what the m and b values are, so simply plug them into the equation.
Slope-Intercept Form
y=-2/3x-7
From there, let's find the point-slope equation.
An easy way to find a coordinate point that the line crosses is to set one of the x or y variables equal to 0.
So let's set the x to 0.
y=-2/3x-7
y=-2/3(0)-7
y=-7
Therefore, when x is 0, y is equal to -7. We can now write our point. (0,-7)
Use the point-slope formula to write the point-slope equation.
y-y1=m(x-x1)
Point-Slope Equation
y-(-7)=-2/3(x-0)
Now, to find the standard form equation, let's find it using our slope-intercept equation. The formula to find standard form is
ax+by=c
y=-2/3x-7
Standard Form Equation
2/3x+y=-7
4) If foxes to deer are in a 1:3 ratio, then if there are 112 deer, how many foxes would there be?
Please help this is due tomorrow and I can’t think straight :((
need help on this one
Answer:
[tex]g(x)=\frac{1}{8} x^{3} -\frac{3}{2} x^{2} +6x-5[/tex]
Step-by-step explanation:
[tex]x=2\sqrt[3]{y-3} +4[/tex]
switch the x and y, then use order of opperations
Please help 10 points
Solve the system by substitution
8x + y = 4
-2x - 8 =y
(answer as an ordered pair)
Can someone help me with this? Last one is -1/4 btw
What is the name give to the angle pair 3 and 5?