Answers
Answer:
☝ Some of the properties of sedimentary rocks
Related Questions
A microwave oven operates at 2.00 GHz . What is the wavelength of the radiation produced by this appliance?
Answers
Answer:
Wavelength = 0.15 m
Explanation:
The frequency of a microwave oven is 2.00 GHz or [tex]2\times 10^9\ Hz[/tex].
We need to find the wavelength of the radiation produced by this appliance. We know that the relationship between the frequency and wavelength is given by :
[tex]c=f\lambda[/tex]
Where,
[tex]\lambda[/tex] is the wavelength
So,
[tex]\lambda=\dfrac{c}{f}\\\\\lambda=\dfrac{3\times 10^8}{2\times 10^9}\\\\=0.15\ m[/tex]
So, the wavelength of the radiation produced by this appliance is 0.15 m.
My question is on the picture
Answers
Answer:
Measure change in temperature after long call
Explanation:
Compact fluorescent bulbs are much more efficient at producing light than are ordinary incandescent bulbs. They initially cost much more, but last far longer and use much less electricity. According to one study of these bulbs, a compact bulb that produces as much light as a 100 W incandescent bulb uses only 23.0 W of power. The compact bulb lasts 10000 hours, on the average, and costs $ 12.00, whereas the incandescent bulb costs only $ 0.76, but lasts just 750 hours. The study assumed that electricity cost $ 0.090 per kilowatt-hour and that the bulbs were on for 4.0 h per day.
Required:
a. What is the total cost (including the price of the bulbs) to run each bulb for 3.0 years?
b. How much do you save over 3.0 years if you use a compact fluorescent bulb instead of an incandescent bulb?
c. What is the resistance of a "100-W" fluorescent bulb?
Answers
Answer:
a
[tex]The \ price \ for \ Compact\ fluorescent\ bulbs \ is \ C_T = \$ 21.067\\The \ price \ for \ incandescent\ bulb \ is \ C_t = \$ 43.98[/tex]
b
[tex]The \ amount \ saved \ is \ C_S = \$ 22.913[/tex]
c
[tex]The \ resistance \ is \ R = 626.1 \Omega[/tex]
Explanation:
From the question we are told that
The power used by incandescent bulb [tex]P_r = 23.0 W[/tex]
The power used by Compact fluorescent bulb [tex]P_p = 100W[/tex]
The life span of Compact fluorescent bulb is [tex]t = 1000 \ hours[/tex]
The prices of Compact fluorescent bulb is [tex]C_c = \$ 12 [/tex]
The prices of incandescent bulb is [tex]C_i = \$ 0.76 [/tex]
The life span of incandescent bulb is [tex]t_k = 750 \ hours[/tex]
The cost of electricity is [tex]C_e = \$ 0.090/ kilowatt-hour = \frac{0.090}{1000} = \$0.00009 / W / h[/tex]
The duration of daily bulb usage is [tex]t_d = 4 \ hours[/tex]
Generally 3 years of bulb usage in hours is mathematically evaluated as
[tex]t_3 = 3 * 365 * t_d[/tex]
=> [tex]t_3 = 3 * 365 * 4[/tex]
=> [tex]t_3 = 4380 \ h [/tex]
Generally the cost to power a 23W bulb for the above duration is mathematically represented as
[tex]Z = 23 * t_3 * C_e[/tex]
=> [tex]Z = 23 * 4380 * 0.00009[/tex]
=> [tex]Z = \$ 9.0667[/tex]
The number of Compact fluorescent bulbs required to achieve this about of time is mathematically represented as
[tex]N = \frac{t_3}{ t}[/tex]
=> [tex]N = \frac{4380}{1000}[/tex]
=> [tex]N = 0.438 [/tex]
=> [tex]N \approx 1 [/tex]
The total cost of usage for the Compact fluorescent bulb is mathematically represented as
[tex]C_T = Z +C_c[/tex]
=> [tex]C_T = 9.0667 +12[/tex]
=> [tex]C_T = \$ 21.067 [/tex]
The number of incandescent bulbs required to achieve this about of time is mathematically represented as
[tex]M = \frac{t_3}{ t_k}[/tex]
=> [tex]M = \frac{4380}{750}[/tex]
=> [tex]M = 6 [/tex]
Generally the cost to power a 100W bulb for the above duration is mathematically represented as
[tex]Z = 100 * t_3 * C_e[/tex]
=> [tex]Z = 100 * 4380 * 0.00009[/tex]
=> [tex]Z = \$ 39.42[/tex]
The total cost of usage for the incandescent bulbs is mathematically represented as
[tex]C_t = C_e + [6 *C_i][/tex]
=> [tex]C_t = 39.42 + [0.76 * 6][/tex]
=> [tex]C_t = \$ 43.98[/tex]
Generally the total amount saved is mathematically represented as
[tex]C_S = C_t - C_T[/tex]
=> [tex]C_S = 43.98 - 21.067[/tex]
=> [tex]C_S = \$ 22.913[/tex]
Generally the resistance of the Compact fluorescent bulb is
[tex]R = \frac{V^2}{P}[/tex]
[tex]R = \frac{120^2}{23}[/tex]
[tex]R = 626.1 \Omega[/tex]
A hammer drives a nail into a piece of wood. Which of the following correctly
identifies the pair of equal and opposite forces involved.
A. The hammer exerts a force on the nail: the nail exerts a force on the wood
B. The hammer exerts a force on the nail: the wood exerts a force on the nail.
C. The nail exerts a force on the hammer: the hammer exerts a force on the wood.
D. The hammer exerts a force on the nail: the nail exerts a force on the hammer.
Answers
Answer:
D
Explanation:
The statement which correctly describes the pair of equal and opposite forces involved is that the hammer exerts a force on the nail: the nail exerts a force on the hammer. Thus, the correct option for this question is D.
What is Force?Force may be defined as the process that significantly involves the pulling and pushing of an object with mass which stimulates itself to change its velocity accordingly. It is a type of vector quantity because it has both magnitude and direction.
According to Newton's third law of motion, if object A exerts a force on object B, then object B must significantly exert a force of equal magnitude and opposite direction on object A. Here, object A is a hammer, and object B is a nail.
Therefore, the hammer exerts a force on the nail: the nail exerts a force on the hammer is the statement that correctly describes the pair of equal and opposite forces. Thus, the correct option for this question is D.
To learn more about Newton's third law of motion, refer to the link:
https://brainly.com/question/25998091
#SPJ2
PLZ HELP!!!!!!! ILL GIVE U BRAINLIEST
Answers
Answer:
Claim: Heart Rate for Sarah and Matt (this would be the homeostasis AT REST and throughout the graph time)
Evidence: The Graph and the HR/S and its evidence towards the heart rate/beats every 15 seconds, due to the homeostasis being a specific time limit and due to the specific heart rate of Matt and Sarah ONLY.
Explanation: A/B Checkpoint throughout the homeostasis (this would be heart rate/trial throughout the time of the graph)
Conclusion: Matt was further away ONLY BECAUSE Sarah has a higher Heart Rate during the time on the graph, which can represent how long they did something to increase/decrease from and where the homeostasis would be located.
Answer:
Claim: Heart Rate for Sarah and Matt (this would be the homeostasis AT REST and throughout the graph time)
Evidence: The Graph and the HR/S and its evidence towards the heart rate/beats every 15 seconds, due to the homeostasis being a specific time limit and due to the specific heart rate of Matt and Sarah ONLY.
Explanation: A/B Checkpoint throughout the homeostasis (this would be heart rate/trial throughout the time of the graph)
Conclusion: Matt was further away ONLY BECAUSE Sarah has a higher Heart Rate during the time on the graph, which can represent how long they did something to increase/decrease from and where the homeostasis would be located.
2 physical properties for manganese
Answers
Are these bones axial, appendicular
or both?
Answers
Answer:
Axial and Appendicular Skeletons The axial skeleton forms the central axis of the body and consists of the skull, vertebral column, and thoracic cage. The appendicular skeleton consists of the pectoral and pelvic girdles, the limb bones, and the bones of the hands and feet. Figure 6.41.
Explanation:
A mountain biker is climbing a steep 20° slope at a constant speed. The cyclist and bike have a combined weight of 800 N. What can you say about the magnitude of the normal force of the ground on the bike?
Answers
Answer:
Normal force = 751.75 N
Explanation:
It is given that,
The combined weight of the cyclist and the bike is 800 N
We need to find the magnitude of the normal force of the ground on the bike. It can be given by the formula as follows :
[tex]N=mg\cos\theta[/tex]
mg = W, combined weight of cyclist and bike
[tex]N=W\cos\theta\\\\N=800\times \cos(20)\\\\N=751.75\ N[/tex]
So, the magnitude of the normal force of the ground on the bike is 751.75 N.
The magnitude of the normal force of the ground on the bike is 751.752 N
The formula for that will be used to calculate the normal force of the ground on the bike is expressed as:
[tex]N= Fcos \theta[/tex]
F is the combined weight
[tex]\theta[/tex] is the angle of inclination
Given the following paramters
F = 800 N
[tex]\theta[/tex] = 20 degrees
Substitute the given parameters into the formula:
[tex]N=800 \times cos20^0\\N=800 \times 0.9397\\N=751.752N[/tex]
Hence the magnitude of the normal force of the ground on the bike is 751.752 N
Learn more here: https://brainly.com/question/12408868
I need helpppppppppppppppppp!
Answers
Answer:
i think its B
Explanation:
but check it before do it
Answer:
A
Explanation:
Hope it helps I tried looking for think I found it hit the heart pls
In a car's suspension system, each wheel is connected to a vertical spring; these springs absorb shocks when the car travels on bumpy roads. In one car, each spring has a spring constant of 4.6 × 10⁴ N/m.
If this 1300 kg car is driven at 23 m/s through the bottom of a circular dip in the road that has a radius of 600 m, by how much do these springs compress compared to when the car is driven on a flat road?
Answers
Answer:
6.23 mm
Explanation:
The vertical acceleration at the bottom of the dip (in addition to that required to counter gravity) is ...
a = v²/r = (23 m/s)²/(600 m) = 529/600 m/s²
Then the force on the car (in addition to that required to counter gravity) is ...
F = Ma = (1300 kg)(529/600 m/s²) = 1146 1/6 N
The additional force supplied by each of the 4 springs is 1/4 of this, so the additional spring compression is ...
((1146 1/6 N)/4)/(4.6×10^4 N/m) ≈ 0.00623 m = 6.23 mm
The springs are compressed an additional 6.23 mm to provide the required vertical acceleration.
_____
We have to assume that the path followed by the car's center of mass has a radius of 600 m. We're also assuming that the rotational motion of the car about its center of mass does not require any differential force between front and back springs, as it will be at a constant rate for a constant speed through the dip. And, we assume that the mass of the car is evenly among the four springs (often not the case).
Answer:
Explanation:
Given this 1300 kg car is driven at 23 m/s through a circular dip in the road of radius of 600m,
its centrifugal acceleration = speed^2 / radius
= 23^2 / 600
= 0.8817 m/s^2
The centrifugal force in turn = mass * acceleration
= 1300 * 0.8817
= 1146.17 N
This force is absorbed by suspension springs of the four wheels.
Given spring constant of 4.6 x 10^4 N/m and 4 springs total,
the extra compression = Force / number of springs / spring constant
= 1146.17 / 4 / 4.6 x 10^4
= 0.006229 m
= 6.23 mm
Note that this is the extra compression on springs during drive-through of the dip compared to when the car is driven on a flat road. There is a constant compression on springs due to weight of the car which is the same whether the car is driving through a dip or on a flat road.
If I kick a ball off the top of a mountain cliff, will it take longer to hit the ground than if I just drop it? Explain your answer. Your answer:
Answers
Answer:
they will drop at the same time
Explanation:
projectile motion consists of two components, horizontal and vertical, which are independent of one another. That means that if you drop a ball and kick another one straight out, they will both hit the ground at the same time so long as they have the same initial drop height .
are there really dead stars in the sky?
Answers
Answer:
Yes
Explanation:
The star would have died over thousands of years ago but the light takes a long time for it to reach us on Earth.
What is the rate of acceleration of a hammer whose head goes from moving -2 m/s (downward) to +0.5 m/s (upward) when it hits and bounces off a hard rock ? The actual bounce takes 0.025 seconds
Answers
Answer:
[tex]a=100\ m/s^2[/tex]
Explanation:
Given that,
Initial velocity, u = -2 m/s
Final velocity, v = =.5 m/s
Time, t = 0.025 s
We need to find the rate of acceleration of a hammer. Acceleration is equal to the change in velocity divided by the time taken.
[tex]a=\dfrac{v-u}{t}\\\\a=\dfrac{0.5-(-2)}{0.025}\\\\a=100\ m/s^2[/tex]
So, the acceleration of the jet is [tex]100\ m/s^2[/tex].
An archer shoots an arrow with vertical velocity of 10 m/s and horizontal velocity of
30m/s. What is the maximum height the arrow reaches?
Answers
Answer:
5.1 m
Explanation:
Given in the y direction:
v₀ = 10 m/s
v = 0 m/s
a = -9.8 m/s²
Find: Δy
v² = v₀² + 2aΔy
(0 m/s)² = (10 m/s)² + 2 (-9.8 m/s²) Δy
Δy = 5.1 m
1) Which of the following is considered an effective treatment for someone with hearing loss based on nerve damage?
TAD
Cochlear implant
Hearing aid
OBI
No treatment available
2) Sylvester is dealing with hearing loss. The doctor informs him that his basilar membrane is damaged. What type of hearing loss is Sylvester experiencing?
Nerve deafness
Conduction hearing loss
Cochlear hearing loss
Conduction deafness
Sensory hearing loss
Answers
Answer:
For number 1 no treatment available , number 2 cochlear hearing loss
Explanation:
nerve damage is permanent
When the force applied to an object increases, the motion of the object
Answers
Answer:
Semen is the most important thing in the life cycle of life
2.9030 has 4 significant digits.
TRUE OR FALSE
Answers
Question 5 of 10
Two hockey pucks, each with a mass of 0.15 kg, slide across the ice and
collide. Before the collision, puck 1 is moving 14 m/s to the west and puck 2
is moving 10 m/s to the east. After the collision, puck 1 is moving at 10 m/s
to the east. What is the velocity of puck 2?
A. 14 m/s east
B. 10 m/s west
C. 10 m/s east
D. 14 m/s west
Answers
Answer: D. 14 m/s west
Explanation:
I just did it on A p e x
A boy and a girl are pulling a heavy crate at the same time with 7 units of firce each. What is the net force acts on the ibject? Is the object balanced or unbalanced?
Answers
Answer:
Net force= 14 units
The object is unbalanced
Explanation:
The net force refers to the sum of all forces applied to an object. However, the direction of force applied determine the net force. In this question, a boy and girl is pulling a heavy crate at the same time.
This means that the force is in the same direction, hence, the net force will be:
F(N) = 7 + 7 = 14 unit
However, since the pull is occuring at the same direction. This means that the object has a net force, therefore, will move in a particular direction. This means that the OBJECT IS UNBALANCED
1)
You travel east at 50 km/hr and then north at 75 km/hr. What is your Resultant Velocity in km/h?
(Remember the angle) (5pts)
Answers
Answer:
15
Explanation:
A helpful association method like remembering the Allies during World War II as BAR
(Britain, America, and Russia) is called
O an acronym
O the DAP flashcard method
O a visual image
O a mind map
Answers
Answer:
an acronym because it is shorted to remember like mvemjsun it's the planet
Which of the following is not a part of the appendicular skeleton
a. femur
b. scapula
c.phalanges
d.hyoid
Answers
Answer:
Hyoid
Explanation:
The hyoid is located in the neck area, not the limbs.
Please help me if you know physics
Answers
Answer:
19. down
20. True
Explanation:
The examples I saw were projectiles launched at different angles and speeds. In each case, the only acceleration was ...
19: down
20: due to gravity (true)
Greg paid $3.60 for a package of 8 nails at the home store. John paid $3.18 for a package of 6 nails at the hardware store. How much more did John pay per nail than Greg?
(PLS HELP ( . *)^( . *)
Answers
Answer:
8 cents extra.
Explanation:
First find out how much one nail is for each of them. So, divide.
3.60 divided by 8 is 0.45.
3.18 divided by 6 is 0.53.
Subtract 0.45 from 0.53 and voila you have 0.08.
Answer:
5
Explanation:
76789967
The particle model shows the image of the moving object.
TRUE OR FALSE
ANSWER AND I WILL GIVE YOU BRAINILIEST
Answers
Answer:
it does show the objects position
15)
The Celsius temperature equal to 86° Fahrenheit is:
T(F) = 9/5T(C) + 32
T(C) = 5/9 ( T(F) - 32)
A)
16°C
B)
30°C
C)
212°C
D)
190°C
Answers
Answer:
letter b
Explanation:
30 degrees Celsius equals 86 degrees Fahrenheit add me plesse mark brainiest
Question 7
(01.01 MC)
What is the difference between a hypothesis and a theory?
Answers
A proposed space station includes living quarters in a circular ring 58.0 m in diameter. At what angular speed should the ring rotate so the occupants feel that they have the same weight as they do on Earth
Answers
Answer:
The angular speed [tex]w = 0.5813 \ rad/s[/tex]
Explanation:
From the question we are told that
The diameter is d = 58.0 m
Generally for the occupants feel that they have the same weight as they do on Earth then the centripetal acceleration of the circular ring must be equal to the acceleration due to gravity this can be mathematically represented as
[tex]a_c = g[/tex]
Here [tex]a_c[/tex] is the centripetal acceleration which is mathematically represented as
[tex]a_c = w^2 * r[/tex]
Here r is the radius of the circular ring
=> [tex]w^2 * r = g[/tex]
=> [tex]w = \sqrt{\frac{g}{r} }[/tex]
=> [tex]w = \sqrt{\frac{9.8}{ \frac{d}{2} } }[/tex]
=> [tex]w = \sqrt{\frac{9.8}{ \frac{58.0 }{2} } }[/tex]
=> [tex]w = 0.5813 \ rad/s[/tex]
When light waves hit ice, most of them bounce off and radiate back into space. Because of this, ice is best described as which kind of surface?
Answers
Answer:
Reflective surface
Explanation:
Ice is a reflective surface because most the of the light waves that hits on it bounces off.
When a surface is smooth and polish, it acts a reflector. When a surface is jagged and not smooth light does not readily reflect. Reflection is through the incident angle of the light waves.Therefore, snow is a reflective surface.
7. A 2kg block is acted on by two forces F1 and F2 as shown in the diagram. If the magnitude of F1 = 13N and F2 = 11N. If the coefficient of kinetic friction is .23, find (A) The normal force exerted on it by the floor. (2 pts) (B) The acceleration on of the block (2 pts)
Answers
Answer:
A.) 17.04 N
B.) 10.76 m/s^2
Explanation:
Given that a 2kg block is acted on by two forces F1 and F2 as shown in the diagram. If the magnitude of F1 = 13N and F2 = 11N. If the coefficient of kinetic friction is .23,
A.) To find the normal force exerted on it by the floor, we need to first calculate the vertical forces of the ropes.
The vertical force on F1 = 13 sin 30
F1 = -6.5 N
The vertical force on F2 = 11 sin 21
F2 = 3.94
The resultant force = - 6.5 + 3.94
Resultant force = - 2.56
The normal force = mg - 2.56
The normal force = 2 × 9.8 - 2.56
The normal force = 19.6 - 2.56
The normal force = 17.04 N
(B) The acceleration on of the block will be achieved by first calculating the horizontal force.
For F1 = 13Cos 30
F1 = 11.26N
For F2 = 11 cos 21
F2 = 10.27
the resultant force = 11.26 + 10.27
Horizontal force = 21.53N
Force = mass × acceleration
21.53 = 2 × a
a = 21.53 / 2
Acceleration a = 10.76 m/s^2