Answer:
k
Step-by-step explanation:
An exponential growth function represents a quantity that has a constant doubling time true or false
False, An exponential growth function represents a quantity that has a constant doubling time.
It might always be having time, Or 13 times, where I would not double but be unable to receive 2/3. Because the quantity is bigger than one, exponential growth would have a constant time between doublings. The halving time for any exponential decay function is A = Ao * kt1/2 x = x * kt1/2 = ktln(1/2) = t * ln kt = ln(1/2) / ln k.Because the quantity is bigger than one, exponential growth would have a constant time between doublings.What does an exponential growth function represent?
The base b is a constant when describing an exponential function. When the domain is the collection of real numbers, the exponent x is the independent variable. Exponential growth and decay are the two different kinds of exponential functions. When b > 1, the function f (x) = bx represents exponential development.Learn more about exponential growth function brainly.com/question/11811611
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[tex]x + 6 = 10 \\ x = 10 - 6[/tex]
simultaneous equations
Answer:
False.
These are not simultaneous equations.
Step-by-step explanation:
Simultaneous equations are equations involving two or more unknowns that are to have the same values in each equation. In the equations given there is only one unknown value.
Let g(x) = f(x+3) for some function f(x). Is g(x) a function? From the previous problem, let the domain of f(x) be [1, 4). What is the domain of g(x)?
The domain of g(x) is [4, 7)
How to determine the domain of g(x)?The function is given as:
g(x) = f(x + 3)
Since f(x) is a function, then g(x) is also a function
The domain of f(x) is given as:
[1, 4)
The equivalent of these values in g(x) are
x = 1 + 3 = 4
x = 4 + 3 = 7
Hence, the domain of g(x) is [4, 7)
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A triangle is shown. One side has a length of 16, another side has a length of 20, and the length of the longest side is unknown.
Janice examines the given triangle and estimates that the longest side has a length of 25 units―if it is a right triangle. How does her estimate compare to the actual length?
It is exactly correct.
It is under by approximately 0.6 units.
It is over by approximately 0.6 units.
It is over by 13 units.
Janice estimate is under by approximately 0. 6 units. Option B
How to determine the estimateThe longest part is called the hypotenuse
The formula for finding the hypotenuse, we use the Pythagorean theorem
Hypotenuse = square root of both opposite square and adjacent square
We have that,
Hypotenuse = [tex]\sqrt{16^2 + 20^2}[/tex]
Hypotenuse = [tex]\sqrt{256+ 400}[/tex]
Hypotenuse = [tex]\sqrt{656}[/tex]
Find the square root
Hypotenuse = 25. 6
The length of the longest part = 25. 6
Janice estimated it to be 25
Comparing her estimate with the actual length = Actual length - estimate
⇒ 25. 6 - 25
⇒ 0. 6
Therefore, Janice estimate is under by approximately 0. 6 units. Option B
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Answer: B. It is under by approximately 0.6 units.
Step-by-step explanation: Just did it on edge 2023
1. How could you figure out the coordinates of a reflection over the x-axis? What would the coordinates of that reflected point be?
2. Then also tell how you could determine the coordinates when (-8,2) is reflected over the y-axis, and tell the coordinates of that new point.
The reflection of a point over the x axis is given by the equation (x, y) ⇒ (x, -y).
If the point (-8,2) is reflected over the y-axis, the new point would be (8, 2)
What is a transformation?Transformation is the movement of a point from its initial location to a new location. Types of transformation are reflection, translation, rotation and dilation.
The reflection of a point over the x axis is given by the equation (x, y) ⇒ (x, -y).
If the point (-8,2) is reflected over the y-axis, the new point would be (8, 2)
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Writing Exercises
587. When you convert a number from decimal notation to scientific notation, how do you know if the exponent will be positive or negative?
Answer:
Therefore, we can say that the exponent will be negative if the number is less than 1 and vice versa.
Step-by-step explanation:
We are asked to explain that when we convert a decimal number to scientific notation how will we know whether the exponent is negative.
If the given number is greater than 1 then the exponent is positive and if less than 1 the exponent is negative.
The fit line equation for the scatterplot is y = -2.61x+152.51, where x is variable 1 and y is variable 2. according to the equation, what is the expected value of y when x-value is 45?
The expected value of y when x-value is 45 is 35.06
Any equation which can be put in the form ax + by + c = 0, where a, b and c are real numbers, and a and b are not both zero, is called a linear equation in two variables. For example, y = 2x+3 and 2y = 4x + 9 are two-variable linear equations.
In the given question value of x is given and value of y is asked.
The given equation : y = -2.61x+152.51 Such questions can be solved by substituting the given value of variable in the equation which will help us find the unknown.
Substituting x = 45 in the given equation , we get
y = -2.61 x 45 + 152.51
y = -117.45 + 152.51
y = 35.06
Thus the expected value of y when x-value is 45 is 35.06
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Mathew rolls a number cube labeled with the numbers 1−6. he then flips a fair coin. what is the probability that he rolls a 4 and flips a head? write your answer as a fraction.
The probability that he rolls a 4 and flips a head is 1/12
What is the probability?Probability determines odds that a random event would happen. The odds of the random event happening lie between 0 and 1.
The probability that he rolls a 4 and flips a head = (number of sides that is a 4 / total number of sides) x (number of sides that is a head / total number of sides)
(1/6) x (1/2) = 1/12
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Answer: 1/12
Step-by-step explanation:
just say the answer
Identify the 8th term of the given geometric sequence. 1/2, 2, 8, 32,...
A geometric sequence goes from one term to the next by always multiplying or dividing by the constant value except 0. The constant number multiplied (or divided) at each stage of a geometric sequence is called the common ratio (r).
We have:
[tex]a_1=\dfrac{1}{2}\\\\a_2=2\\\\a_3=8\\\\a_4=32\\\vdots[/tex]
Find the common ratio:
[tex]\boxed{r=\dfrac{a_n}{a_{n-1}}}\Rightarrow r=\dfrac{2}{\frac{1}{2}}=\dfrac{8}{2}=\dfrac{32}{8}=...\\\\\boxed{r=4}[/tex]
The formula of the n-th term of a geometric sequence:[tex]\boxed{a_n=a_1\cdot r^{n-1}}[/tex]
Substitute:
[tex]a_1=\dfrac{1}{2},\ r=4,\ n=8\\\\a_8=\dfrac{1}{2}\cdot4^{8-1}=\dfrac{1}{2}\cdot4^7=\dfrac{1}{2}\cdot16384\\\\\huge\boxed{a_8=8192}[/tex]
Method step by step:[tex]a_4=32,\ r=4\\\\a_5=a_4\cdot r\Rightarrow a_5=32\cdot4=128\\\\a_6=a_5\cdot r\Rightarrow a_6=128\cdot4=512\\\\a_7=a_6\cdot r\Rightarrow a_7=512\cdot4=2048\\\\a_8=a_7\cdot r\Rightarrow a_8=2048\cdot4=8192[/tex]
8 times the number is 200. What is 80 times the number?
Answer:
2,000
Step-by-step explanation:
⇒ 200/8 = 25
⇒ 25 * 80 = 2,000
Answer:
2000.
Step-by-step explanation:
8 * x = 200
x = 200/8
80x = 80 * 200/8
= 10 *200
= 2000.
Which properties are necessary to claim that the two prisms are congruent? Check all that apply.
Answer:
1. The volumes are equal.
2. The base areas are equal.
3. The prisms have the same height.
Step-by-step explanation:
I don't see no answered to check all that apply but here is the answers about properties and two prisms
HEEEELPPP MEEEEEEE FRRRRRR!!!!!!! 30POINTS!!!!!
[tex]\huge\text{Hey there!}[/tex]
[tex]\huge\textbf{Circumference of a circle: }[/tex]
[tex]\bullet\ \large\boxed{\mathsf{2\pi r}}}\\\rightarrow\large\boxed{\textsf{Whereas, } \pi \large\textsf{ is your pi and it is approximately equal to 3.14}}\\\rightarrow\large\boxed{\textsf{ And \underline{r} is the radius of the circle.}}[/tex][tex]\huge\textbf{Area of a triangle:}[/tex]
[tex]\bullet\ \large\boxed{\mathsf{\dfrac{1}{2}bh}}\\\\\rightarrow\large\boxed{\textsf{Whereas, }\mathsf{\dfrac{1}{2}} \large\textsf{ is half your triangle, \underline{b} is your \underline{b}ase, and b is your \underline{h}eight}}[/tex]
[tex]\huge\textbf{Surface area of a rectangular prism: }[/tex]
[tex]\bullet \ \large\boxed{\textsf{2(wl + hl + hw)}}\\\rightarrow\large\boxed{\textsf{Whereas, l is your \underline{l}ength, h is your \underline{h}eight, and w is your \underline{w}idth.}}[/tex]
[tex]\huge\textbf{Volume of a rectangular prism:}[/tex]
[tex]\bullet\ \large\boxed{\textsf{whl = v}}\\\rightarrow\boxed{\large\textsf{Whereas, v is your \underline{v}olume, w is your \underline{w}idth, h is your \underline{h}eight, l is}}\\ \ \large\boxed{\textsf{your \underline{l}ength}}[/tex]
[tex]\huge\text{Good luck on your assignment \& enjoy your day!}[/tex]
~[tex]\frak{Amphitrite1040:)}[/tex]
The table and Circle Chart display proportions of the expenditure of a local government. Which statement describes how the Circle Chart misrepresents the data?
A. The sum of the percentages in the sections is not 100.
B. The size of each section does not correspond to the percent expenditure for each category given in the table.
C. One of the categories in the table is not represented in the circle chart.
D. The size of the section representing highways is greater than the size of the section representing education.
This exercise refers to the identification of statistics that is misleading or erroneous. In this case, a circle graph and a table are involved.
What is a circle graph?A circle graph is simply a pie chart. It is used to depict information in percentages. An example is attached.
Although charts and tables are very useful descriptive and or illustrative statistics, they can be misleading.
This can happen when:
The sum of the percentages in the sections is not 100;The size of each section does not correspond to the percent expenditure for each category given in the table; andOne of the categories in the table is not represented in the circle chart.This answer is general in nature due to the limited information provided.
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Answer:
C
Step-by-step explanation:
Find the probability for the experiment of drawing two marbles at random (without replacement) from a bag containing three green, three yellow, and four red marbles.
The marbles are different colors.
Answer:
[tex]\frac{11}{15} =0.733333333333[/tex]
Step-by-step explanation:
• Here The sample space S is the set of possible outcomes (ordered pairs of marbles) that we can draw at random (without replacement) from the bag.
Then
[tex]\text{cardS} =P^{2}_{10}=10\times 9=90[/tex]
……………………………………………
Drawing two marbles where the marbles are different colors
means
drawing (1green ,1 yellow) or (1green ,1 red) or (1yellow ,1 red)
Remark: the order intervene
=========================
•• Let E be the event “Drawing two marbles where the marbles are different colors”.
CardE = 2×3×3 + 2×3×4 + 2×3×4 = 66 (2 is for the order)
Conclusion:
[tex]p\left( E\right) =\frac{66}{90} =\frac{11}{15} =0.733333333333[/tex]
Method 2 :
[tex]p\left( E\right) =2\times \frac{3}{10} \times \frac{3}{9} +2\times \frac{3}{10} \times \frac{4}{9} +2\times \frac{3}{10} \times \frac{4}{9} =0.733333333333[/tex]
Answer:
[tex]\sf \dfrac{11}{15}[/tex]
Step-by-step explanation:
The bag of marbles contains:
3 green marbles3 yellow marbles4 red marbles⇒ Total marbles = 3 + 3 + 4 = 10
Probability Formula
[tex]\sf Probability\:of\:an\:event\:occurring = \dfrac{Number\:of\:ways\:it\:can\:occur}{Total\:number\:of\:possible\:outcomes}[/tex]
First draw
[tex]\implies \sf P(green)=\dfrac{3}{10}[/tex]
[tex]\implies \sf P(yellow)=\dfrac{3}{10}[/tex]
[tex]\implies \sf P(red)=\dfrac{4}{10}[/tex]
Second draw
As the first marble is not replaced there are now 9 marbles in the bag.
If the first marble was green, the probability of drawing a yellow is now 3/9 and the probability of drawing a red is now 4/9.
If the first marble was yellow, the probability of drawing a green is now 3/9 and the probability of drawing a red is now 4/9.
If the first marble was red, the probability of drawing a green is now 3/9 and the probability of drawing a yellow is now 3/9.
To find the individual probabilities of picking 2 different colors, multiply the probability of the first draw by the probability of the second draw:
[tex]\implies \sf P(green)\:and\:P(red)=\dfrac{3}{10} \times \dfrac{4}{9}=\dfrac{12}{90}[/tex]
[tex]\implies \sf P(green)\:and\:P(yellow)=\dfrac{3}{10} \times \dfrac{3}{9}=\dfrac{9}{90}[/tex]
[tex]\implies \sf P(yellow)\:and\:P(green)=\dfrac{3}{10} \times \dfrac{3}{9}=\dfrac{9}{90}[/tex]
[tex]\implies \sf P(yellow)\:and\:P(red)=\dfrac{3}{10} \times \dfrac{4}{9}=\dfrac{12}{90}[/tex]
[tex]\implies \sf P(red)\:and\:P(green)=\dfrac{4}{10} \times \dfrac{3}{9}=\dfrac{12}{90}[/tex]
[tex]\implies \sf P(red)\:and\:P(yellow)=\dfrac{4}{10} \times \dfrac{3}{9}=\dfrac{12}{90}[/tex]
To find the probability of drawing two marbles at random and the marbles being different colors, add the individual probabilities listed above:
[tex]\begin{aligned}\implies \sf P(2\:different\:color\:marbles) &=\sf \dfrac{12}{90}+\dfrac{9}{90}+\dfrac{9}{90}+\dfrac{12}{90}+\dfrac{12}{90}+\dfrac{12}{90}\\\\ & = \sf \dfrac{66}{90}\\\\ & =\sf \dfrac{11}{15}\end{aligned}[/tex]
Find the circumference and the area of a circle with diameter 6 ft.
Answer:
Circumference = 18.84 ft
Area = 28.26 ft squared
Step-by-step explanation:
C(circumference) = 2 x [tex]\pi[/tex] x r(radius)
radius = 1/2 circumference
1. divide circumference by two to get the radius, which would be three ft.
2. multiply the radius by pie (3.14) and then multiply that by two and you have your circumference, which is 18.84 ft
area = [tex]\pi[/tex] x r(radius)^2
1. find the radius squared, which would be 9 because 3^2 = 3 x 3 which = 9
2. multiply 9 by pie (3.14) and you get the area which = 28.26
find the value of 7 + 15 + 23 +...+ 767 + 775 + 783
Answer:
38,710.
Step-by-step explanation:
This is an arithmetic series with common difference 8 , first term a = 7 and last term L = 783.
The number of terms n = (783 - 7) / 8 + 1 = 98
Sum of 98 terms = (n/2)[a + L)
= (98/2)(7 + 783)
= 49 * 790
= 38,710.
I need your help :))
Question is:
Make a pattern and explain the rule the pattern follows. Use a minimum of 3 terms within your pattern.
The pattern {1, 3, 5, ...} is an arithmetic sequence with the following rule:
[tex]a_n = 1 + 2(n - 1)[/tex].
What is an arithmetic sequence?In an arithmetic sequence, the difference between consecutive terms is always the same, called common difference d.
The nth term of an arithmetic sequence is given by:
[tex]a_n = a_1 + (n - 1)d[/tex]
In which [tex]a_1[/tex] is the first term.
The pattern {1, 3, 5, ...} has first term and common difference given, respectively, by:
[tex]a_1 = 1, d = 2[/tex]
Hence the rule for the pattern is given by:
[tex]a_n = 1 + 2(n - 1)[/tex].
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porfaaaaaaa ayudaaaaaaa
Determine el dominio y el rango de la siguiente función.
f(x)=-25-x+50
The domain and the range of f(x) = -25x + 50 are the set of all real numbers
How to determine the domain and the range?The function is given as:
f(x) = -25x + 50
The above function is a linear function.
All linear functions have their domain and range to be the set of all real numbers
Hence, the domain and the range of f(x) = -25x + 50 are the set of all real numbers
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In triangle xyz, m∠z > m∠x m∠y. which must be true about △xyz? m∠x m∠z < 90° m∠y > 90° ∠x and∠y are complementary m∠x m∠y < 90°
m∠X + m∠Y < 90° is true.
How to solve it?XYZ is a triangle.
We have to find the option that is true about △XYZ.
By angle sum property of a triangle,
The sum of all the interior angles of a triangle is always equal to 180°.
So, ∠X + ∠Y + ∠Z = 180°
Given, m∠Z > m∠X + m∠Y.
This implies that ∠Z is greater than the sum of the angles ∠X and ∠Y.
so, ∠X + ∠Y must be less than 90°.
Hence, we can say that ∠X + ∠Y < 90°
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Answer: Option 4 or D. m∠x + m∠y∠90°
Step-by-step explanation: Trust Me! It is correct on Edge!
Q: In triangle xyz, m∠z > m∠x m∠y. which must be true about △xyz?
A: D. m∠x + m∠y∠90°
4. Use the triangle congruence postulates to prove congruence.
Part I: Fill in the blanks to name each triangle congruence postulate.
a. SSS:
b. SAS:
c. ASA:
AAS:
In the triangle
The triangle congruence postulate is illustrated below
How to illustrate the triangle?It should be noted that two triangles are congruent if they have the same shape and size.
AAS: The angle-angle-side theorem illustrates that two triangles are congruent if the two angles and a side note between the two angles are identical to that of another triangle.
SSS: This illustrates that the three sides of a triangle are congruent to the corresponding three sides of the other triangle.
ASA: This illustrates that the triangles are congruent when the two angles and the side are the same as the corresponding angles and sides of the other triangle.
SAS: When two sides and the included angle of a triangle are congruent to the corresponding sides and the included angle if a second triangle then it follows the side-angle-side theorem.
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An approximate solution to an equation is found using this iterative process.
(x₂)³-1
and x₁ = -1
4
Xn+1 =
4/34
a) (i) Work out the value of x₂
(ii) Work out the value of x3
b) Work out the solution to 6 decimal places.
Answer:
a) i) -0.5
ii) -0.28125
b) -0.254102 (6 d.p.)
Step-by-step explanation:
Given iteration formula:
[tex]x_{n+1}=\dfrac{\left(x_n\right)^3-1}{4} \quad \textsf{and} \quad x_1=-1[/tex]
Part (a)(i)
Substitute the value of x₁ into the formula and solve for x₂ :
[tex]\begin{aligned}\implies x_2 & =\dfrac{\left(x_1\right)^3-1}{4}\\\\& =\dfrac{\left(-1\right)^3-1}{4}\\\\ & = \dfrac{-1-1}{4}\\\\ & = \dfrac{-2}{4}\\\\ & = -0.5\end{aligned}[/tex]
Part (a)(ii)
Substitute the value of x₂ into the formula and solve for x₃ :
[tex]\begin{aligned}\implies x_3 & =\dfrac{\left(x_2\right)^3-1}{4}\\\\& =\dfrac{\left(-0.5\right)^3-1}{4}\\\\ & = \dfrac{-0.125-1}{4}\\\\ & = \dfrac{-1.125}{4}\\\\ & = -0.28125\end{aligned}[/tex]
Part (b)
To find the solution to 6 decimal places, keep substituting each new value into the iteration formula until the answers are the same when rounded to the required level of accuracy.
[tex]\implies x_4=-0.2555618286...[/tex]
[tex]\implies x_5=-0.2541728038...[/tex]
[tex]\implies x_6=-0.2541051331...[/tex]
[tex]\implies x_7=-0.2541018552...=-0.254102\:\: \sf (6 \:d.p.)[/tex]
[tex]\implies x_8=-0.2541016964...=-0.254102\:\: \sf (6 \:d.p.)[/tex]
[tex]\implies x_9=-0.2541016888...=-0.254102\:\: \sf (6 \:d.p.)[/tex]
Therefore, the solution is -0.254102 (6 d.p.).
Pete drive 50 miles in 4 hours work out his average speed in miles per hour
Answer:
Pete's average speed is 12.5 miles per hour
Step-by-step explanation:
Miles per hour means how many miles were driven in 1 hour so :
50 miles in 4 hours = ? miles in 1 hour
4 ÷ x = 1
4/x = 1
x = 4
50÷4 = ?
50/4 = ?
? = 12.5
Pete's average speed is 12.5 miles per hour
Hope this helped and have a good day
30 points plus brainliest if answered right!
Answer:
The second choice.
Step-by-step explanation:
The length of AC must be equal to 5, since it is horizontally five units. We can rule out the first option.
Length BC cannot be the square root of 16, since that would be exactly 4 units. BC is slanted and does not represent a completely vertical line, so it is not a whole number. We can rule out the fourth option.
Length AB cannot be a whole number, being a slanted line that crosses a total of more than four units. Option three can be ruled out.
Therefore, we are left with the second option.
Answer:
AC = 5, BC = √17, AB = √32
Explanation:
Given points: A(-3, -2), B(1, 2), C(2, -2)
Use distance between two points formula:
[tex]\sf Distance \ between \ two \ points = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}[/tex]
AC length:
[tex]\sf d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} = \sqrt{(2-(-3))^2 + (-2-(-2))^2} = \sqrt{25+ 0} = 5[/tex]
BC length:
[tex]\sf d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} = \sqrt{(2-1)^2 + (-2-2)^2} = \sqrt{1 + 16} = \sqrt{17}[/tex]
AB length:
[tex]\sf d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} = \sqrt{(-3-1)^2 + (-2-2)^2} = \sqrt{16 + 16} = \sqrt{32}[/tex]
Please help ill give whoever answers the best the brainliest answer :)))
Answer:
3rd graph from the top.
Step-by-step explanation:
It can't be the top one because the kids shoulder doesn't start at the ground.
It can't be the second or fourth because it shows him not waiting in line.
Therefore it must be the 3rd!
Answer: 3rd option
Step-by-step explanation:
Because the description says that it starts not at 0(from the kid's shoulder), the 1st and 4th options are out.
2nd option is incorrect because the kid had to stand in line so the shoulder height doesn't change(unless he was picking stuff up or something)
That leaves the 3rd option.
GIVING BRAINLEST!
Linda collected 1/2 of a stamp album. Becky collected 7 1/3 times as many stamps as Linda. How many
stamp albums were collected by Becky?
O 3 1/3
O 2 1/3
O 3 2/3
O 1 1/3
*
Answer:
3 2/3
Step-by-step explanation:
To do this question, you would need to multiply 7 1/3 with 1/2. The answer is 3 2/3.
Answer:
3 2/3 albums
Step-by-step explanation:
Let's say that the stamp album has 12 stamps (12 is just an arbitrary number used to make calculation easier). If Linda collects half of the album, it means she has 6 stamps. If that is the case, Becky has 6 * 7 1/3 stamps. Since 7 1/3 is equivalent to 22/3, we can determine that Becky has collected 44 stamps (6*22/3). There are 12 stamps in one album, which means there are 44 stamps in 3 2/3 (11/3) albums:
[tex]\frac{12}{1}=\frac{44}{y} \\12y=44\\y=11/3[/tex]
Since the ratio of stamps to albums is constant, the calculation above demonstrates that the number of albums it takes to have 44 stamps is 3 2/3. Please note that the numbers I used are arbitrary. If you substitute 12 for a variable x, you will get the same result.
How is copying segment similar to copying an angle ?
Answer:
Copying a line segment or angle is an illustration of transformation. Both are similar, because they are both rigid transformation.
When an angle is copied to a new angle, the new angle and the old angle will have the same measure
Similarly;
When a line segment is copied to a new segment, the new line segment and the old line segment will have the same measure
This type of transformation is referred to as a rigid transformation.
Hence, copying a line segment is similar to copying an angle, because they are both rigid transformations
Step-by-step explanation:
Checking number 2( Solving inequalities)
1. x < 20
x - 7 < 13
x < 20
2. x > -7
-3(x + 4) < 9
-3x - 12 < 9
-3x < 21
x > -7
Hope this helps!
write the equation for the graph given below
Answer: Option (1)
Step-by-step explanation:
The slope of the line is
[tex]\frac{9-6}{4-(-4)}=\frac{3}{8}[/tex]
This eliminates all the options except for (1).
Kevin earned $80. Out of his earnings, he spent $68/5 on shopping, $51/2 on food, and $22/5 for taxi. Find the remaining amount.
The amount remaining out the money earned is $37.5
Sum of values and proportionGiven the following parameters
Amount earned by kevin = $80
If he spent $68/5 on shopping, $51/2 on food, and $22/5 for taxi, the total money spent is given as;
Total money spent = 51/2 + 68/5 + 22/5
Total money spent = 51/2 + 90/5
Total money spent = 25.5 + 18
Total money spent = 43.5
Amount remaining = 80. - 43.5
Amount remaining = 37.5
Hence the amount remaining out the money earned is $37.5
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Explain why statistical acceptance sampling is not an effective method for monitoring process quality.
Acceptance sampling is a statistical method used to monitor the quality of purchased parts and components. To ensure the quality of incoming parts, a purchaser or manufacturer normally samples 20 parts and allows one defect.
a) Concerned with inspection of products
b) Concerned with decision making regarding products
c) One of the oldest aspects of quality assurance
The Acceptance sampling procedure is necessarily a lot sentencing procedure. It cannot be used to estimate the lot quality or lot conformity to the standard specifications.
The acceptance sampling is used when the test is destructive, or the cost of 100% inspection is quite high, or when we need a continuously monitoring program
The Acceptance sampling procedure is used for decision making of either acceptation or rejection of a lot. It can’t be used as a lot quality estimator
As Acceptance sampling is just a lot sentencing process, it can’t estimate the quality of products in the lot. But designed experiments ensure good quality of the process output before even production
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