Question in pic plz help! ~
Im gonna label the long side of a rectangle a and the smaller side b.
For the perimeter, 2a + 2b = 34
For the area, a x b = 66
if a is 11 and b is 6, the equation for perimeter would be 22 + 12 = 34.
So a = 11 and b = 6
Answer:
Longer side = 11
Shorter side = 6
Step-by-step explanation:
L x W = 66, then W = 66/L
2L + 2W = 34
substitute for W:
2L + 2(66/L) = 34
2L + 132/L = 34
multiply both sides of the equation by L:
2L² + 132 = 34L
divide both sides by 2:
L² + 66 = 17L
L² - 17L + 66 = 0
factor:
(L - 11)(L - 6) = 0
L = 11 or L = 6
if L = 11, then W = 6
if L = 6 then W = 11
2. You were 22 inches tall at birth, and 48 inches tall on your 8th birthday.
2a) On average, how many inches did you grow per year? (Hint: in 8 years 2 points
you grow a total of 26 inches) include units!!
Answer:
3.25
Step-by-step explanation:because you have to divide the years with the inches so in each year i would grow about 3.25 inches
Is 41.77 a integer?
Answer:
nope, an integer must be a whole number, no fractions / decimals
Step-by-step explanation:
Answer:
No
Step-by-step explanation:
An integer is a whole number or a number that is not a fraction or decimal. So, since 41.77 is a decimal it cannot be an integer. Examples of integers are 41 or -2.
A boy who is on the second floor of their house watches his dog lying on the ground. The angle between his eye level and his line of sight is 32º. a. Which angle is identified in the problem, angle of elevation or depression? b. If the boy is 3 meters above the ground, approximately how far is the dog from the house? c. If the dog is 7 meters from the house, how high is the boy above the ground?
As per the given details, the dog is approximately 0.6249 * 3 = 1.8747 meters from the house.
The angle recognized in the problem is the angle of depression. The angle of depression is the attitude between the horizontal line and the line of sight from an observer looking downward.
To calculate approximately how a ways the canine is from the residence, we are able to use trigonometry.
Since the angle of despair is given as 32º and the boy is 3 meters above the floor, we will use the tangent characteristic to find the space.
tan(32º) = (dog's distance / boy's height)
tan(32º) = d / 3
3 * tan(32º) = d
The dog is approximately 0.6249 * 3 = 1.8747 meters from the house.
To calculate how high the boy is above the floor, we are able to again use trigonometry. Since the canine is 7 meters from the residence and the attitude of melancholy is given as 32º, we are able to use the tangent characteristic to discover the peak of the boy.
tan(32º) = (boy's height / dog's distance)
tan(32º) = h / 7
7 * tan(32º) = h
Therefore, the boy is approximately 0.6249 * 7 = 4.3743 meters above the ground.
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Consider the following algorithm that takes inputs a parameter 0
function integer X(p,n)The algorithm described simulates a random variable with a binomial distribution of parameters p and n.
The given algorithm involves generating random numbers and incrementing a variable X based on certain conditions. The variable X represents the number of successes or "1" outcomes in a sequence of n independent Bernoulli trials, where each trial has a probability of success equal to p.
In each iteration of the loop, the algorithm generates a random number between 0 and 1 (denoted as RND) and compares it to the probability parameter p. If the generated random number is less than or equal to p, the variable X is incremented by 1.
This process is repeated for a total of n trials, resulting in the count of successes, which follows a binomial distribution. The binomial distribution represents the number of successes in a fixed number of independent Bernoulli trials, where each trial has the same probability of success, given by parameter p. Therefore, the algorithm simulates a random variable with a binomial distribution of parameters p and n.
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1. Chester has a par value $500 bond issued by Harris County. The bond pays 6. 2% yearly interest, and has a current market rate of 98. 626. If Harris County bonds had a market rate of 101. 760 when Chester bought it, what is the current yield on Chester’s bond?
a.
0. 061
b.
0. 062
c.
0. 063
d.
0. 031
2. Much of Ann’s investments are in Cilla Shipping. Ten years ago, Ann bought seven bonds issued by Cilla Shipping, each with a par value of $500. The bonds had a market rate of 95. 626. Ann also bought 125 shares of Cilla Shipping stock, which at the time sold for $28. 00 per share. Today, Cilla Shipping bonds have a market rate of 106. 384, and Cilla Shipping stock sells for $30. 65 per share. Which of Ann’s investments has increased in value more, and by how much?
a.
The value of Ann’s bonds has increased by $45. 28 more than the value of her stocks.
b.
The value of Ann’s bonds has increased by $22. 64 more than the value of her stocks.
c.
The value of Ann’s stocks has increased by $107. 81 more than the value of her bonds.
d.
The value of Ann’s stocks has increased by $8. 51 more than the value of her bonds.
3. Stock in Ombor Medical Supplies earns a return of 5. 3% annually, while bonds issued by Ombor Medical Supplies earns a return of 4. 1% annually. If you invest a total of $2,400 in Ombor Medical Supplies, $1,400 of which is in bonds and $1,000 of which is in stocks, which side of the investment will show a greater return after six years, and how much greater will it be?
a.
The stocks will earn $55. 60 more than the bonds.
b.
The stocks will earn $118. 60 more than the bonds.
c.
The bonds will earn $82. 00 more than the stocks.
d.
The bonds will earn $26. 40 more than the stocks.
4. Maria owns four par value $1,000 bonds from Prince Waste Collection. The bonds pay yearly interest of 7. 7%, and had a market value of 97. 917 when she bought them. Maria also owns 126 shares of stock in Prince Waste Collection, each of which cost $19. 33 and pays a yearly dividend of 85 cents. Which aspect of Maria’s investment in Prince Waste Collection offers a greater percent yield, and how much greater is it?
a.
The bonds have a yield 3. 466 percentage points greater than that of the stocks.
b.
The bonds have a yield 7. 863 percentage points greater than that of the stocks.
c.
The stocks have a yield 6. 75 percentage points greater than that of the bonds.
d.
The stocks have a yield 9. 01 percentage points greater than that of the bonds
1. Current Yield on Chester's bond Chester has a par value of $500 bond issued by Harris County, which pays 6.2% yearly interest. When Chester bought it, the market rate of Harris County bonds was 101.760. As the bond is purchased at a premium, the bond's price is above the par value. It is trading above the face value of $500 per bond.Using the current market rate formula, C = (I/PV) + (FV/PV)n
Where ,C = Current YieldI = Yearly Interest PV = Current Market RateFV = Par Value ($500)n = Number of Years Then,
98.626 = (6.2/ PV) + (500 / PV)101.760
[tex](PV) = $498.70PV = $4.90[/tex]
Therefore, the current market price of the bond is $4.90.Using the current yield formula, Current Yield = (Yearly Interest/Current Market Price) x 100Current
Yield [tex]= (6.2/4.90) x 100 = 126.53[/tex]
Therefore, the current yield on Chester's bond is 126.53%.2. Investment with a greater return after six years After six years, the return on stocks and bonds investment will be calculated as: Stocks
Return = [tex]1,000(1 + 0.053)^6 = $1,385.94[/tex]
Bonds Return = [tex]1,400(1 + 0.041)^6 = 1,734.69[/tex]
Therefore, the return on bonds investment is $1,734.69, and the return on stocks investment is $1,385.94. The bonds investment will show a greater return after six years, and the difference is $348.75.3. Greater percent yield of Maria's Investment Maria owns four par value $1,000 bonds and 126 shares of stock in Prince Waste Collection. The bonds pay a yearly interest of 7.7%, and Maria bought them when the market value was 97.917.The cost of one stock = $19.33 and the yearly dividend per stock is 85 cents.
Maria's total investment in stocks = [tex]126\times$19.33 = $2,439.18[/tex]
Maria's total investment in bonds = $1,000 x 4 = $4,000 When Maria bought bonds, the market value of the bond was [tex]979.17 ($1,000 x 0.97917).[/tex][tex]= (Yearly Interest / Purchase Price) \times 100= (7.7 / 979.17) \times 100 = 0.786%[/tex]
The stock's annual yield[tex]= (Dividend / Purchase Price) \times100= (0.85 / 19.33) \times 100 = 4.4%[/tex]
Therefore, the percent yield on stocks is greater, and the difference is 3.61%.
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Charles and Lisa were having a apple eating contest. They ate eighteen apples between the two of them. Lisa ate two more apples than Charles. How many apples did Lisa eat?
Answer: She ate 12 apples
Step-by-step explanation: 18 divided by 2 is 9 add 2 of 9 to the other 9 and you get 12 hope I helped
Answer:
she ate 10 apples
Step-by-step explanation:
I thought of it because there is only 18 apples all together
1. Write an equation for the circle whose graph is shown.
y
5
3
2
-5 -4 -3 -2 -1
1 2 3 4 5 x
2
3
-4
-5
O (3-1)2 + (y + 2)2 = 2
O (3-1)2 + (x + 2)2 = 4
O (2+1)2 + (y – 2)2 = 4
O (2+1)2 + (y-2)2
Answer:
325
Step-by-step explanation:
got it right on edg
The required equation of the circle that shown in the graph is,
(x + 1)² + (y - 2)² = 4 where (-1 , 2) is the center of the circle and 2 unit is the radius of the circle. Option C is correct.
A graph of the circle is shown, It is to determine the equation of the circle.
The circle is the locus of a point whose distance from a fixed point is constant i.e center (h, k). The equation of the circle is given by
(x - h)² + (y - k)² = r²
where h, k is the coordinate of the circle's center on the coordinate plane and r is the circle's radius.
From the graph, the center is ( -1, 2) and the radius is 2. Now put these values in the standard equation of the circle.
(x - (-1))² + (y - 2)² = 2²
(x +1 )² + (y - 2)² = 4
Thus, the required equation of the circle that shown in the graph is,
(x + 1)² + (y - 2)² = 4 where (-1 , 2) is center of the circle and 2 unit is the radius of the circle. Option C is correct.
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What is the answer with explanation?
The value of arc ABD is determined as 236⁰.
Option C.
What is the measure of arc ABD?The value of arc ABD is calculated by applying intersecting chord theorem, which states that the angle at tangent is half of the arc angle of the two intersecting chords.
Also this theory states that arc angles of intersecting secants at the center of the circle is equal to the angle formed at the center of the circle by the two intersecting chords.
arc BA = 2 x 48⁰ (interior angles of intersecting secants)
arc BA = 96⁰
arc BD = 2 x 70⁰ (interior angles of intersecting secants)
arc BD = 140⁰
arc ABD = arc BA + arc BD
arc ABD = 96⁰ + 140⁰
arc ABD = 236⁰
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Sketch two periods of the graph of the function h(x)=4sec(π4(x+3)). Identify the stretching factor, period, and asymptotes.
Enter the exact answers.
Stretching factor = ____________
Period: P=
__________
Enter the asymptotes of the function on the domain [−P,P].
To enter π, type Pi.
The field below accepts a list of numbers or formulas separated by semicolons (e.g. 2;4;6 or x+1;x−1). The order of the list does not matter.
Asymptotes: x=
__________
Select the correct graph of h(x)=4sec(π4(x+3)).
(a) (b) (c) (d)
The function h(x) = 4sec(π/4(x+3)) represents a graph with a stretching factor of 4 and a period of 8π/4 = 2π. The correct graph representation of h(x) = 4sec(π/4(x+3)) needs to show these characteristics. The correct answer would be (b).
The function h(x) = 4sec(π/4(x+3)) has a stretching factor of 4, which means that the amplitude of the function is multiplied by 4, causing the graph to be vertically stretched.
The period of the function is given by P = 2π/π/4 = 8π/4 = 2π. This means that the graph will complete two periods within the interval [-P, P], which in this case is [-2π, 2π].
The asymptotes of the function occur at x = -P/2 and x = P/2. Substituting the value of P = 2π, the asymptotes are x = -π and x = π. These vertical asymptotes indicate where the graph approaches infinity or negative infinity as x approaches these values.
To determine the correct graph representation of h(x) = 4sec(π/4(x+3)), you would need to choose the graph option that shows the stretching factor of 4, a period of 2π, and vertical asymptotes at x = -π and x = π.
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Which exponential equation is equivalent to the logarithmic equation below?
log 300 = a
A. 3000 = 10
B. a10 = 300
C. 100 = 300
D. 30010 = a
Answer:
[tex]\implies\boxed{ 10^a = 300 }[/tex]
Step-by-step explanation:
We are provided logarithmic equation , which is ,
[tex]\implies log_{10}^{300}= a [/tex]
Here we took the base as 10 , since nothing is mentioned about that in Question .Say if we have a expoteintial equation ,
[tex]\implies a^m = n [/tex]
In logarithmic form it is ,
[tex]\implies log_a^n = m [/tex]
Similarly our required answer will be ,
[tex]\implies\boxed{ 10^a = 300 }[/tex]
Use the standard normal distribution or the disebution to constructa confidence interval for the popolnoma Antly you decided why the In a random sample of 45 people, the mean body mass index (BMI) 27 B and the standard devion was 616 Which distribution should be used to contact the condence interval? Choose the correct below O A Use a normal distributor because the sample is rondom the population and on OB. Use anomal distribution because the same is random na 30 known OC Uldistribution because the sales and the population is not an unknown OD Use adidinotion because the sample random and unknown OE. Neither a normal dishon nordisbution can be because the samples and and the now to becoma
A confidence interval for the population mean (BMI) based on a
random
sample of 45 people, a normal distribution should be used because the sample is random and the population is known.
In this scenario, the sample size is sufficiently large (n = 45), and the population standard
deviation
(σ = 6.16) is known. When these conditions are met, the appropriate distribution to construct a confidence interval for the population mean is the normal distribution. The central limit theorem states that when the sample size is large, the distribution of the sample mean approaches a
normal
distribution regardless of the shape of the population distribution.
Using the normal distribution, we can calculate the
standard
error of the mean (SEM) by dividing the population standard deviation by the square root of the sample size: SEM = σ / √n. In this case, the SEM would be 6.16 / √45. The confidence
interval
can then be calculated by multiplying the SEM by the appropriate critical value for the desired level of confidence (e.g., 95%) and adding/subtracting it to/from the sample mean.
Therefore, to construct a confidence interval for the population mean BMI, we would use a normal
distribution
because the sample is random, and the population standard deviation is known.
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a cone has a height of 7ft and a radius 4ft. Which equation can find the volume of the cone?
PLEASE I ACTUALLY NEED HELP
Answer:
B
Step-by-step explanation:
equation for volume of a cone = [tex]V=\frac{1}{3}\pi r^2h[/tex]
plug in - [tex]V=\frac{1}{3} \pi (4)^2(7)[/tex]
Answer:
we have
volume of cone =1/3 πr²h=1/3×π×4²×7ft³
so
v=1/3 π(4²)(7)ft³
The value of the Australian dolar (A$) today is $0.73. Yesterday, the value of the Australia dollar was $0.69.
The Australian dollar _______ by ______ %.
a.
appreciated; 5.80
b.
appreciated; 5.48
c.
depreciated; 5.80
d.
depreciated; 4.00
This indicates that the Australian dollar appreciated by 5.80%. the correct answer is (a) appreciated; 5.80.
To determine whether the Australian dollar appreciated or depreciated and by what percentage, we can calculate the percentage change in value between today and yesterday.
The formula for calculating the percentage change is:
Percentage Change = (New Value - Old Value) / Old Value * 100
Using this formula, we can calculate the percentage change:
Percentage Change = (0.73 - 0.69) / 0.69 * 100
Percentage Change = 0.04 / 0.69 * 100
Percentage Change ≈ 5.80
The percentage change is approximately 5.80%. This indicates that the Australian dollar appreciated by 5.80%.
Therefore, the correct answer is (a) appreciated; 5.80.
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1. John is currently watching 9 different television shows.
a) If John watches one episode of each of these shows, how many orders of shows can he watch?
b) If John wants to download 5 random episodes of these 9 shows, how many combinations exist? (He only downloads 1 episode from any given show.)
c) Out of a group of 12 students competing on the Gymnastics team, how many different ways can a captain, equipment manager, and sound manager be selected at random if no person can hold two positions
a) There are 9! (9 factorial) orders of shows John can watch if he watches one episode of each of the 9 different television shows.
b) There are 126 combinations for John to download 5 random episodes from the 9 shows.
c) There are 1,320 different ways to select a captain, equipment manager, and sound manager from a group of 12 students without any person holding two positions.
a) If John watches one episode of each of the 9 different television shows, the number of orders of shows he can watch is 9!.
b) If John wants to download 5 random episodes of these 9 shows, the number of combinations is given by the binomial coefficient:
C(9, 5) = 9! / (5!(9-5)!) = 126
c) To select a captain, equipment manager, and sound manager from a group of 12 students without any person holding two positions, the number of different ways is given by the product of the choices for each position:
12 * 11 * 10 = 1,320
Therefore, there are 1,320 different ways to select a captain, equipment manager, and sound manager in this scenario.
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I=7 m, w=4 m, h= 3 m
The volume of the room with the given dimensions is 84 cubic meters.
The volume of a room can be calculated by multiplying its length, width, and height. In this case, the given dimensions are:
Length (L) = 7 m
Width (W) = 4 m
Height (H) = 3 m
To find the volume, we can use the formula:
Volume = Length × Width × Height
Substituting the given values:
Volume = 7 m × 4 m × 3 m
Simplifying:
Volume = 84 m³
Therefore, the volume of the room with the given dimensions is 84 cubic meters.
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Jamal has a new business as a financial consultant. He uses the formula y = 1,500x + 500 as a starting point for new customers. Y is the total amount of money and x is the number of years of investments. What is the total amount of money a dient would have after 7 years?
Answer:
11,000
Step-by-step explanation:
You would multiply 1,500 by 7 and then add 500.
1. 2
given that c = 2πr an, write an expression
for r.
Answer:
r = c / 2π
Step-by-step explanation:
c = 2πr is the formula for the circumference of a circle of radius r.
We can solve this for r:
r = c / (2pi)
or
r = c / 2π
If there are 520 grams of radioactive material with a half life of 12 hours how much of the radioactive material will be left after 72 hours? Is the radioactive decay modeled by a linear function or an exponential function
Answer:
16.25 grams are left
exponential
Step-by-step explanation:
Half the material will decay every 12-hour period (the other half will remain).
Initial amount (at time t = 0): 520 grams
Time t = 12: 260 grams are left
Time t = 24: 130 grams are left
Time t = 36: 65 grams are left
Time t = 48: 32.5 grams are left
Time t = 72: 16.25 grams are left
Radioactive decay is modeled by an exponential function. The function can't be linear because for them, equal time steps would produce equal reductions in the amount of material.
Each unit of food A contains 120 milligrams of sodium, 1 gram of fat, and 5 grams of protein. Each unit of food B contains 60 milligrams of sodium, 1 gram of fat, and 4 grams of protein. Suppose that a meal consisting of these two types of food is required to have at most 480 milligrams of sodium and at most 6 grams of fat. Find the combination of these two foods that meets the requirements and has the greatest amount of protein. 1) Define your variables. 2) Create an organizational chart of information. 3) Create an objective equation (what is to be maximized or minimized). 4) Write constraint inequalities. Don't forget the non-negative restrictions if applicable. 5) Graph the constraints in order to identify the feasible region. 6) Find the vertices of the feasible region. 7) Test all vertices in the objective equation to identify the point of optimization. 8) Write the complete solution with clear and concise language.
The combination of food A and food B that meets the requirements and has the greatest amount of protein is 2 units of food A and 1 unit of food B, with a total of 30 grams of protein.
We can approach the problem of finding the combination of food A and food B that meets the requirements and has the greatest amount of protein using linear programming.
1) Variables:
Let x be the number of units of food A.
Let y be the number of units of food B.
2) Organizational chart:
Food A:
Sodium: 120 mg/unit
Fat: 1 g/unit
Protein: 5 g/unit
Food B:
Sodium: 60 mg/unit
Fat: 1 g/unit
Protein: 4 g/unit
Meal requirements:
Sodium: ≤ 480 mg
Fat: ≤ 6 g
Objective: Maximize protein
3) Objective equation:
Maximize z = 5x + 4y
4) Constraint inequalities:
120x + 60y ≤ 480 (sodium constraint)
x + y ≤ 6 (fat constraint)
x ≥ 0, y ≥ 0 (non-negative constraint)
5) Graph the constraints:
To graph the constraints, we can first graph the boundary lines.
120x + 60y = 480
x + y = 6
Then we can shade the feasible region, which is the region that satisfies all the constraints.
The feasible region is a polygon with vertices at (0,0), (4,2), (6,0), and (3,3).
6) Find the vertices:
The vertices of the feasible region are (0,0), (4,2), (6,0), and (3,3).
7) Test the vertices:
We can test each vertex by substituting its coordinates into the objective equation and finding the maximum value.
(0,0): z = 0
(4,2): z = 30
(6,0): z = 30
(3,3): z = 27
The maximum value of the objective function is 30, which occurs at the points (4,2) and (6,0).
8) Write the complete solution:
To maximize protein while satisfying the sodium and fat constraints, we need to use 4 units of food A and 2 units of food B, or 6 units of food A and 0 units of food B. Both of these combinations have a total of 30 grams of protein.
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In Exercises 7-12, complete the square in order to put the equation into standard form. Identify the center and the radius or explain why the equation does not represent a circle.
7. x ^ 2 - 12x + y ^ 2 + 6y = - 9
9. x ^ 2 + y ^ 2 + 14x - 20y - 20 = 0
x ^ 1 - 2x + y ^ 1 + 3/2 * y = - 1
8- 3x ^ 2 - 3y ^ 2 + 27y + 61 = 0
10. x ^ 2 + y ^ 2 - 7x - 3y - 1 = 0
12. 4x ^ 2 - 16x + 4y ^ 2 + 16 = 0
Here are the solutions to each problem, which include the center and radius for each circle:7. Center: (6, -3); Radius: 6.9. Center: (-7, 10); Radius: 13.11. Center: (1, -2); Radius: 1/2.8. Center: (0, 9); Radius: 3/2.10. Center: (7/2, 3/2); Radius: 5/2.12. Center: (2, 0); Radius: 1.
The solution is given as follows;7. x² - 12x + y² + 6y = - 9.
We start by grouping the x and y terms separately, then completing the square by adding half of the coefficient of the respective variable and squaring the result. x² - 12x + y² + 6y = - 9(x² - 12x + __) + (y² + 6y + __) = - 9 + __ + __
Now, we'll fill in the blanks in the parentheses so that the trinomials are perfect squares: (x² - 12x + 36) + (y² + 6y + 9) = - 9 + 36 + 9.
This simplifies to: (x - 6)² + (y + 3)² = 36.
The center of the circle is (6, −3), and its radius is 6.9. x² + y² + 14x - 20y - 20 = 0.
First, we group the x terms and the y terms separately:x² + 14x + y² - 20y = 20.
Now, we'll complete the square in both x and y. x² + 14x + y² - 20y = 20(x² + 14x + __) + (y² - 20y + __) = 20 + __ + __.
We'll fill in the blanks so that the trinomials are perfect squares.
To find the terms to add, we take half of the coefficient of the variable and square it. (x² + 14x + 49) + (y² - 20y + 100) = 20 + 49 + 100
Simplifying, we get (x + 7)² + (y - 10)² = 169.
The center of the circle is (-7, 10), and its radius is 13.x - 2x + y + 3/2y = -1
We first rearrange the terms. x - 2x + y + 3/2y = -1-x - 1/2y = -1
We then complete the square in x and y as follows. x - 2x + y + 3/2y = -1(x - 1) - (1/2)(y + 2) = -1/2(x - 1)² - 1/4(y + 2)² = 1/2
The center of the circle is (1, -2) and its radius is 1/2.8. - 3x² - 3y² + 27y + 61 = 0
We rearrange and group the terms. - 3x² - 3y² + 27y = -61
We then complete the square. - 3x² - 3(y² - 9y + 81/4) + 27(81/4) = -61 - 3(81/4)(x² + (y - 9/2)² = 405/4
The center of the circle is (0, 9) and its radius is 3/2.10. x² + y² - 7x - 3y - 1 = 0
We rearrange and group the terms. x² - 7x + y² - 3y = 1
We then complete the square. x² - 7x + 49/4 + y² - 3y + 9/4 = 1 + 49/4 + 9/4(x - 7/2)² + (y - 3/2)² = 25/4
The center of the circle is (7/2, 3/2), and its radius is 5/2.12. 4x² - 16x + 4y² + 16 = 0
We rearrange and group the terms. 4x² - 16x + 4y² = -16
We then complete the square. 4(x² - 4x + 4) + 4y² = 0(x - 2)² + y² = 1
The center of the circle is (2, 0), and its radius is 1.
Completing the square is a method used to turn quadratic expressions in standard form into perfect squares. It’s often used to find the center and radius of circles.
Here are the solutions to each problem, which include the center and radius for each circle:7. Center: (6, -3); Radius: 6.9. Center: (-7, 10); Radius: 13.11. Center: (1, -2); Radius: 1/2.8. Center: (0, 9); Radius: 3/2.10. Center: (7/2, 3/2); Radius: 5/2.12. Center: (2, 0); Radius: 1.
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A large group of mice is kept in a cage having compartments A, B and C Mice in compartment A move to B with probability O2 and to C with probability 04 Mice in B move to A or with probabilities 0 25 and 045, respectively Mice in C move to A or B with probabilities 04 and 0.3 respectively. Find the long-range prediction for the fraction of mice in each of the compartments The long range prediction for the fraction of mice is in compartment A __ , in compartment B __ , and in compartment C ___.
The long-range prediction for the fraction of mice in each compartment is approximately 40% in Compartment A, 30% in Compartment B, and 30% in Compartment C.
To determine the long-range predictions, we can set up a system of equations based on the probabilities of mice moving between compartments. Let's denote the fraction of mice in compartment A as x, in compartment B as y, and in compartment C as z.
For compartment A, the fraction of mice in the next step will be 0.2x (moving to B) and 0.4x (moving to C). Similarly, for compartments B and C, the fractions in the next step will be 0.25y + 0.4z and 0.45y + 0.3z, respectively.
Setting up the equations, we have:
x = 0.2x + 0.4z
y = 0.25y + 0.4z
z = 0.45y + 0.3z
Simplifying and solving the equations, we find:
x = 0.4
y = 0.3
z = 0.3
Therefore, the long-range prediction for the fraction of mice in compartment A is 0.4, in compartment B is 0.3, and in compartment C is 0.3. This means that over time, approximately 40% of mice will be in compartment A, 30% in compartment B, and 30% in compartment C.
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explain how to graph the circle by hand on the coordinate plane (3 points)
First find the center, then graph all the points that are at a distance of R units from that center.
How to graph a circle by hand?A circle of radius R is the set of all points that are at a distance R from a given point (the center of the circle).
So to graph it, we need to know these two things, radius and center.
Once we do, first we graph the center on the coordinate plane.
Once we find the center, we can find all the poiints that are at a distance of R units from our center, so we need to graph these. Once we do, we will have the graph of our circle on the coordinate plane.
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Each side of a square is increased 3 inches. When this happens, the area is multiplied by 25. How many inches in the side of the original square?
Answer:
s = 0.75 inches
Step-by-step explanation:
Let s = side length of the original square
s + 3 = side length of the new square
Area of a square = s²
A = s²
A = (s+3)²
A = s² + 6s + 9
Area multiplied by 25 = 25 * s²
So,
s² + 6s + 9 = 25s²
25s² - s² - 6s - 9 = 0
24s² - 6s - 9 = 0
8s² - 2s - 3 = 0
a = 8
b = -2
c = -3
s = -b ± √b² - 4ac / 2a
= -(-2) ± √(-2)² - 4(8)(-3) / 2(8)
= 2 ± √4 - (-96) / 16
= 2 ± √100 / 16
= 2 ± 10/16
s = 2 + 10/16 or 2-10/16
= 12/16 or -8/16
= 0.75 or -0.5
side length can not be negative
Therefore, s = 0.75
A = s²
A = (0.75)²
= 0.5625
A = (s+3)²
= (0.75+3)²
= 3.75²
= 13.95
4.) Select ALL equivalent expressions to 5x – 5.5. a) 5x -55 c) 5(x - 1.1) b) 2x - 3 + 3x - 2.5 ) 5.5(x - 1)
Answer:
1. (-125 a - 5.75) x + b c (605 x - 550 x^2) + 10.75
2. -125 a x + x (-550 b c x + 605 b c - 5.75) + 10.75
3. 0.25 (-500 a x - 220 b c (10 x - 11) x - 23 x + 43)
Step-by-step explanation:
Tucker purchased $4,600 in new equipment for a catering business. He estimates that the value of the equipment is reduced by approximately 40% every two years. Tucker states that the function V(t)=4,600(0.4)2t could be used to represent the value of the equipment, V, in dollars t years after the purchase of the new equipment. Explain whether the function Tucker stated is correct, and, if not, determine the correct function that could be used to find the value of the equipment purchased.
show work
Answer:
The function stated by Tucker is incorrect.
V(t) = 4600(0.8)^t
Step-by-step explanation:
Given the function :
V(t)=4,600(0.4)2t
The initial value of equipment = 4600
Decay rate = 40% of very 2 years
The value of equipment t years after purchase
The exponential decat function goes thus :
V(t) = Initial value * (1 - decay rate)^t
The Decay rate per year = 40% /2 = 20% = 0.2
V(t) = 4600(1 - 0.2)^t
V(t) = 4600(0.8)^t
a railroad crew can replace 450 meters of rails in 3 days
how many kilometers of rail can they repair in 24 days?
find an example of a commutative ring R with 1 in R, and a prime ideal P (of R) with no zero divisors but R is not an integral domain.
An example of a commutative ring R with 1, a prime ideal P, and no zero divisors but R is not an integral domain is the ring R = Z/6Z, where Z is the set of integers and 6Z is the ideal generated by 6.
The ring R = Z/6Z consists of the residue classes of integers modulo 6. The elements of R are [0], [1], [2], [3], [4], and [5], where [a] denotes the residue class of a modulo 6.
In this ring, addition and multiplication are performed modulo 6. For example, [2] + [3] = [5] and [2] * [3] = [0].
R has a multiplicative identity, which is the residue class [1]. It is commutative since addition and multiplication are performed modulo 6.
The ideal P = 2R consists of the elements [0] and [2]. P is a prime ideal since R/P is an integral domain, which means there are no zero divisors in R/P. However, R itself is not an integral domain because [2] * [3] = [0] in R, showing that zero divisors exist in R.
Therefore, the ring R = Z/6Z, with the prime ideal P = 2R, satisfies the given conditions.
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ILL MARK BRAINLIESTTTTT
Answer:
0.075 inches per year
Step-by-step explanation:
The average rate of change is measured as
( difference in diameter ) ÷ ( difference in years )
= ( 251 - 248 ) ÷ ( 2005 - 1965 )
= 3 inches ÷ 40 years
= 0.075 inches per year
g a tank contains 90 kg of salt and 1000 l of water. a solution of a concentration 0.045 kg of salt per liter enters a tank at the rate 8 l/min. the solution is mixed and drains from the tank at the same rate what is the concentration of our solution in the tank initially?
The final concentration in the tank is 0.045 kg/L, which is the same as the concentration of the incoming solution.
To solve the problem, we can use the formula:
C1V1 + C2V2 = C3V3
where C1 is the initial concentration, V1 is the initial volume, C2 is the concentration of the incoming solution, V2 is the volume of the incoming solution, C3 is the final concentration, and V3 is the final volume.
We know that the initial volume of the tank is 1000 L and it contains 90 kg of salt. To find the initial concentration, we need to convert the mass of salt to concentration by dividing it by the total volume:
90 kg / 1000 L = 0.09 kg/L
This means that initially, the concentration of salt in the tank is 0.09 kg/L.
Next, we need to calculate how much salt enters and leaves the tank during a given time period. Since the incoming solution has a concentration of 0.045 kg/L and enters at a rate of 8 L/min, it brings in:
0.045 kg/L x 8 L/min = 0.36 kg/min
The outgoing solution has the same concentration as the final concentration in the tank, so we can use this formula to find it:
C1V1 + C2V2 = C3V3
(0.09 kg/L)(1000 L) + (0.045 kg/L)(8 L/min)(t min) = C3(1000 L + 8 L/min)(t min)
Simplifying and solving for C3, we get:
C3 = (0.09 kg/L)(1000 L) + (0.045 kg/L)(8 L/min)(t min) / (1000 L + 8 L/min)(t min)
At steady state, when the amount of salt entering and leaving the tank is equal, we can set the incoming and outgoing terms equal to each other:
0.36 kg/min = C3(8 L/min)
Solving for C3, we get:
C3 = 0.045 kg/L
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