When you cook a marshmallow on a metal poker tool over an open flame, energy is transferred. Identify the three different ways thermal energy is transferred in this situation. Be sure to name the specific places or phenomenon in this system where each of the types of thermal energy transfer is occurring and the direction the energy is being transferred (from what to what).

Answer:

friction, should be correct i think!

Answer:

Anything that isn't moving

Answer:

If we forget about drag for a second then any object will accelerate at 9.8 m/s/s. The distance traveled is (9.8 m/s)/2 * (x seconds)^2, so solving for 45 meters the no-air fall will take 3.06 seconds and reach 30 m/s or 108 kph or 67.1 mph

Explanation:

Answer:

The thread will experience a force on it .

Explanation:

When thread is tied to pen it will experience force. Because the pen is Abit heavy , there is a force that is applied to it which will cause it to elongate , after a while the thread will stretch, elongate and can later experience deformation. When it experience that, the thread can break after deformation and it has losses it elasticity.

Answer:

it is A

Explanation:

because energy can neither be created nor destroyed - only converted from one form of energy to another.

Answer:

i put cereal first

Explanation:

cereal

Answer:

Driveway across the street ([tex]\theta = 6^{\circ}[/tex]) is the only choice for a safe parking.

Explanation:

Let suppose that car is represented by a particle, then we proceed to construct its free body diagram and corresponding equations of equilibrium:

[tex]\Sigma F_{x'} = f - W\cdot \sin \theta = 0[/tex] (Eq. 1)

[tex]\Sigma F_{y'} = N-W\cdot \cos \theta = 0[/tex] (Eq. 2)

Where:

[tex]f[/tex] - Static friction force, measured in newtons.

[tex]N[/tex] - Normal force on the car from the ground, measured in newtons.

[tex]W[/tex] - Weight of the car, measured in newtons.

[tex]\theta[/tex] - Driveway inclination, measured in sexagesimal degrees.

By applying definitions of maximum static friction force and weight, we expand the system of equations presented above:

[tex]\mu_{s}\cdot N -m\cdot g\cdot \sin \theta = 0[/tex] (Eq. 1b)

[tex]N - m\cdot g \cdot \cos \theta = 0[/tex] (Eq. 2b)

Where:

[tex]\mu_{s}[/tex] - Static coefficient of friction, dimensionless.

[tex]m[/tex] - Mass of the car, measured in kilograms.

[tex]g[/tex] - Gravitational acceleration, measured in meters per square second.

Then, we substitute normal force and simplify the resulting expression:

[tex]\mu_{s}\cdot m\cdot g \cdot \cos \theta -m\cdot g \cdot \sin \theta = 0[/tex]

[tex]\mu_{s} = \tan \theta[/tex]

[tex]\theta = \tan^{-1}\mu_{s}[/tex] (Eq. 3)

Based on such result, we can conclude that if driveway inclination is greater than value reported, then car shall not be safe in case of parking. Our reference angle is: ([tex]\mu_{s} = 0.15[/tex])

[tex]\theta = \tan^{-1} 0.15[/tex]

[tex]\theta \approx 8.531^{\circ}[/tex]

By direct comparison, we find that driveway across the street ([tex]\theta = 6^{\circ}[/tex]) is the only choice for a safe parking.

Answer:

The quantization of energy refers to the fact that at subatomic levels, energy is best thought of as occurring in discreet "packets" called photons. Like paper money, photons come in different denominations. ... Each photon contains a unique amount of discreet energy

Answer:

The total displacement of the object is 20 m

Explanation:

Velocity vs Time Graph

It shows the behavior of the velocity as time increases. If the velocity increases, then the acceleration is positive, if the velocity decreases, the acceleration is negative, and if the velocity is constant, then the acceleration is zero.

The distance covered by the car can be calculated as the area behind the graph.

The total area can be calculated in two parts: One triangle from t=0 sec to t=2 sec, and one rectangle from t=2 sec to t=3 sec.

The area of a triangle is

A1= B*H/2, where B is the length of the base, and H is the length of the Height. The base is B=2 seconds, and the height is H = 10 m/s, thus:

A1= (2 sec)*(10 m/sec)/2=10 m

The area of a rectangle is

A2=W*L, where W is the width, L is the length. W=1 sec, L=10 m/s, thus:

A2=(1 sec)*(10 m/sec) = 10 m

Total displacement= 10 m + 10 m = 20 m

The total displacement of the object is 20 m

Answer: is  13

Explanation:

=====================================================

Explanation:

At 4 seconds, the distance is 8 meters. Note the point (4,8)

At 8 seconds, the distance is 10 meters. The point here is (8,10)

Find the slope of the line through (4,8) and (8,10)

m = (y2-y1)/(x2-x1)

m = (10-8)/(8-4)

m = 2/4

m = 1/2

m = 0.5

The average speed on this interval is 0.5 m/s

-----------------

Another way to look at it:

We've gone from 8 meters to 10 meters, so that's a change of y = 2 meters.

During this, the time has changed from 4 seconds to 8 seconds, which is a difference of x = 4 seconds.

The velocity is the rate of change of distance over time

velocity = (change in distance)/(change in time) = y/x = 2/4 = 0.5 m/s

Answer:

science is the intellectual and practical activity encompassing the systematic study of the structure and behaviour of the physical and natural world through observation and experiment.

Explanation:

Answer:

Point A is the same distance below 0 as Point B is above 0.

Point B is a positive integer.

Since a number and its opposite are the same distance from 0 in opposite directions, Point B is the opposite of Point A.

Explanation:

Answer:

Sample Response: Because Point A is negative and the same distance below 0 on the number line as Point B is above it, Point B is both positive and the opposite of Point A.

Explanation:

Answer:

73.1 m/s

Explanation:

Given:

Δx = 160 m

v = 6.9 m/s

t = 4 s

Find: v₀

Δx = ½ (v + v₀) t

160 m = ½ (6.9 m/s + v₀) (4 s)

v₀ = 73.1 m/s

Option D) 1.5 m/s² is the correct answer.

The magnitude of the acceleration of the car is 1.5 m/s².

given the data in the question;

record of the observation;

Time(s)      Speed(m/s)

3.0                4.0

5.0                7.0

6.0                8.5

Since its undergoing constant acceleration, we can make use any two from the three data recorded.

So, lets consider motion between t₁ = 3.0s and t₂ = 5.0s

Initial velocity at t₁ ; u = 4.0 m/s

final velocity at t₂; v = 7.0 m/s

Now, Time Elapsed; [tex]t = t_2 - t_1 = 7.0s - 5.0s = 2.0s[/tex]

To determine the magnitude of acceleration "a", we use the first equation of motion which says;

[tex]v = u + at[/tex]

we make "a" the subject of the formula

[tex]a =\frac{v - u}{t}[/tex]

so we substitute in our values;

[tex]a = \frac{(7.0m/s) - (4.0m/s)}{2.0s}[/tex]

[tex]a = \frac{3.0m/s}{2.0s}[/tex]

[tex]a = 1.5 m/s^2[/tex]

Therefore, the magnitude of the acceleration of the car is 1.5 m/s².

Option D) 1.5 m/s² is the correct answer.

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Answer:

Alkali metals are the chemical elements found in Group 1 of the periodic table. The alkali metals include: lithium, sodium, potassium, rubidium, cesium, and francium.

Explanation:

Answer:

alkali metals

Explanation:

Answer:

15 cm

Explanation:

using the thin lens formula for convex lens

                            [tex]\frac{1}{f} = \frac{1}{p} + \frac{1}{q}\\ \\where f = focal length \\ p = object distance \\ q = image distance\\[/tex]

 so,

         [tex]\frac{1}{q} = \frac{1}{f} - \frac{1}{p} \\\\\frac{1}{q} = \frac{1}{10} - \frac{1}{30} \\\frac{1}{q} = \frac{2}{30}\\\frac{1}{q} = \frac{1}{15cm}[/tex]

so,

    q = 15 cm

Answer:

W = 1590 J

Explanation:

We could use the formula of potential energy to find work as both have the same units,

                    W = mgh

since weight = mg so,

                     Work = weight x height

                               = 530 x 3

                               = 1590 J

Answer:

The work will be 1590 J

since the formula is W = F x D so I cancel the time

Explanation:

Given:

(Force) F = 530N

(Distance)D = 3m

Unknown:

W or Work

Formula and Solution:

W = F x D

W = (530N) (3m)

Final Answer:

W = 1 590 N·m or simplify as 1590 J

Answer:Electrones

Explanation:Because its building up static

Answer:

B) Electrons

Explanation:

When William slides down the slide, the rubbing action between William and the slide causes electrons to be transferred to William and stored as a negative charge.

When he touches a piece of metal, the negative charge (i.e the build up of excess electrons), is released (discharged) into the metal causing what we know as a static shock.

Answer: the answer is A.

Explanation:

brainliest please?

Answer:

A.

Cognition helps determine if a consequence is influential enough to control behavior.

Explanation:

This is right on edg. 2020

A stone dropped from a 26 m bridge, takes 2.3 s to reach the water.

A stone is dropped from a bridge and it experiences a uniformly accelerated rectilinear motion. It takes 2.3 s for the stone to reach the water.

We can calculate the height of the bridge, which is equal to the displacement of the stone, using the following kinematic equation.

[tex]s = ut + \frac{1}{2} a t^{2} = (0m/s)(2.3 s) + \frac{1}{2} (9.8m/s^{2} ) (2.3s)^{2} = 26 m[/tex]

where,

A stone dropped from a 26 m bridge, takes 2.3 s to reach the water.

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Answer:

Yes.

Explanation:

There is potential energy in your leg that once comes in contact with the ball turns into kinetic energy.

Complete Question

The complete question is shown on the first uploaded image

Answer:

The kinetic energy for particle a is  [tex]K_a  =  \frac{9}{2}  mr^2 w^2[/tex]

The kinetic energy for particle b is   [tex]K_b  =  m w^2r^2 [/tex]

Explanation:

From the question we are told that

   The mass of particle a  is  [tex]m[/tex]  

   The mass of particle b is  [tex]2 m[/tex]  

Generally the kinetic energy for  particle a is mathematically represented as  

       [tex]K_a  =  \frac{1}{2} m v^2[/tex]

Here [tex]v_a[/tex] is the linear velocity of particle a which is mathematically represented as

         [tex]v_b  =  w *  3r[/tex]

So

      [tex]K  =  \frac{1}{2} m {w *  3r}^2[/tex]

=>   [tex]K_a  =  \frac{9}{2}  mr^2 w^2[/tex]

Generally the kinetic energy for  particle a is mathematically represented as  

    [tex]K_b  =  \frac{1}{2} 2m v_b^2[/tex]

Here [tex]v_b[/tex] is the linear velocity of particle a which is mathematically represented as

         [tex]v_b  =  w *  r[/tex]

So

      [tex]K_b  =  m (wr)^2[/tex]

=>    [tex]K_b  =  m w^2r^2[/tex]

The kinetic energy of the particle in terms of angular speed (ω), mass of the object (m) and the radius of the path is [tex]\frac{1}{2} m \omega ^2 r^2[/tex].

The given parameters;

The kinetic energy of the of the particle in terms of the angular velocity is calculated as follows;

[tex]K_b = \frac{1}{2} m (\omega r)^2\\\\K_b = \frac{1}{2} m \omega ^2 r^2[/tex]

where;

Thus, the kinetic energy of the particle in terms of angular speed (ω), mass of the object (m) and the radius of the path is [tex]\frac{1}{2} m \omega ^2 r^2[/tex].

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Answer:

i would want to be a dog or a cat

Explanation:

there just funny