when processing an invoice what account is credited
a. accounts receivable
b. cash
c. accounts payable
d. the answer depends on the transaction

The graph of y is a straight line parallel to the x−axis through the point (0,1)

Now, According to the question:

Let's know:

What is slope and example?

Whenever the equation of a line is written in the form y = mx + b, it is called the slope-intercept form of the equation. The m is the slope of the line. And b is the b in the point that is the y-intercept (0, b). For example, for the equation y = 3x – 7, the slope is 3, and the y-intercept is (0, −7).

The equation is Y = 1

A straight line in slope (m) and intercept (c) form is:

y = mx + c

y is a straight line of slope 0 and y- intercept of 1

y = 0.x + 1

y = 1

Hence, the graph of y is a straight line parallel to the x−axis through the point (0,1)

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There are two steps of solving the equation -3(2x+6)=12.

The steps are given below.

Two algebraic expressions having same value and symbol '=' in between are called as an equation.

Given equation:

-3(2x+6)=12

The first step:

Solving the parenthesis first,

-6x -18 = 12

Adding 18 to both sides,

-6x = 30

Divide by -6,

x = -5

The alternate step:

-3(2x+6)=12

Divide by -3,

2x + 6 = -4

2x = -10

x = -5

Therefore, x = -5 is the solution of the equation.

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A numerical equation using addition as the only operator, for instance, is 2 + 17.

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the distance it will cover before coming to rest is 75m. Solved using the concept of velocity.

Simply said, velocity is the rate of movement in a certain direction. such as the speed of a car driving north on a highway or the pace at which a rocket takes off.

Due to the fact that it includes both magnitude and direction, velocity is a vector quantity. Since acceleration is only the rate at which velocity changes, acceleration is likewise a vector quantity.

Given that,

initial velocity (u) = 30 m/s

acceleration (a) = - 6 m/s²

As we know,

v² = u² + 2as

or, 0 = (30)² + 2 × (-6) × s

or, s = 75 m

Hence, the distance it will cover before coming to rest is 75m

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By solving the given factorial question we get a+b=2538.

In mathematics, the term "factorial" refers to the sum of all positive integers that are less than or equal to a specific positive integer, which is followed by an exclamation point. Thus, factorial seven is denoted by the symbol 7!, which stands for 1 2 3 4 5 6 7. Factorial 0 is equal to 1 by definition.

Solution:-

1! + 2! = 1! ( 1 + 2 )

2! + 3! = 2! ( 1+ 3 )

3! + 4! = 3! ( 1 + 4 )

4! + 5! = 4! ( 1 + 5 )

5! + 6! = 5! ( 1 + 6 )

6! + 7! = 6! ( 1 + 7 )

7! + 8! = 7! ( 1 + 8 )

8! + 9! = 8! ( 1 + 9 )

Once again:

1! + 2! = 1! ( 3 )

2! + 3! = 2! ( 4 )

3! + 4! = 3! ( 5 )

4! + 5! = 4! ( 6 )

5! + 6! = 5! ( 7 )

6! + 7! = 6! ( 8 )

7! + 8! = 7! ( 9 )

8! + 9! = 8! ( 10 )

The LCM of 1!, 2!, 3!, ... , 8! is 8!

The LCM of 3, 4, 5, ... , 10 is 2520

The LCM is 2520 * 8!

a = 2520

b = 8

a + b = 2528

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Answer: x = a/b - c

Step-by-step explanation:

First divide by b on each side to get the x by itself.

Then subtract c from both sides to make x the subject of the formula.

Step-by-step explanation:

a = bx + c

the goal is to get to a form with "x = ...".

a - c = bx

(a - c)/b = x

done.

The fractions is simplified to 8ac²/ 5

A fraction can be described as the part of a whole element, number or variable.

There are different types of fractions, which includes;

Examples of improper fractions; 5/3, 7/5

Examples of proper fractions; 3/4, 5/6

Examples of mixed fractions; 3 1/2, 4 5/6

Examples of simple fractions; 1/2 , 1/ 4

From the information given, we have that;

[tex]\frac{32a^2bc^3}{20abc}[/tex]

This is simplified to;

32 × a × a × b × c × c × c/ 20 × a × b × c

Divide the common terms

8ac²/ 5

Hence, the fractions is 8ac²/ 5

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The value of x is 14.7224.

There are three commonly used trigonometric identities.

Sin x = 1/ cosec x

Cos x = 1/ sec x

Tan x = 1/ cot x or sin x / cos x

Cot x = cos x / sin x

We have,

Sin 60° = x/17 ____(1)

Sin 60° = √3/2 _____(2)

From (1) and (2) we get,

√3/2 = x/17

x = 17√3/2

x = 17 x 1.73205 / 2

x = 14.7224

Thus,

The value of x is 14.7224.

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The length of the field for the missing width is 350 ft. and the function (w) to represent the length of the field is w = (l-50)

A function is a relation from a set of inputs to a set of possible outputs where each input is related to exactly one output.

Given that a table for showing the relation between length and width of a field;

                Width (w)                                     Length (l)

                       0                                                   50

                     100                                                 150

                     200                                                250

                     300                                                350

We see, that, width is 50 less than the length.

Therefore, the function (w) to represent the length of the field will be =

w = l-50

Hence, the length of the field for the missing width is 350 ft. and the function (w) to represent the length of the field is w = (l-50)

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In the given pairs of polygons the scale factor of figure A to figure B is  2:4.

The scale factor is calculated using the following fundamental formula: Scale factor = Dimension of the new shape Dimension of the old shape. The formula for calculating the scale factor is expressed as Scale factor = Larger figure dimensions Smaller figure dimensions in the event that the original figure is magnified.

The ratio of a smaller figure's side to its corresponding side in the bigger figure is the scale factor between the two figures.

As a result, the smaller figure's side length of 4 units and its side length of 10 units are equivalent.

Therefore:

Scale factor = 4:10

i.e. 2:5

Simplify

Scale of the smaller figure to the larger is equal to 2:4.

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The measure of the angle of the shaded sector with an area of 65 cm² is 74.5°

An equation is used to show the relationship between numbers and variables.

The area of a two dimensional shape is the amount of space it occupies.

The area of a sector in a circle is given by:

Area = (Ф/360) * π * radius²

Where Ф is the sector angle

Given that sector area is 65 cm², radius is 10 cm, hence:

Area = (Ф/360) * π * radius²

Substituting gives:

65 = (Ф/360) * π * 10²

Ф = 74.5°

The measure of the angle is 74.5°

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The sum of first 20 terms of the AP will be -206.25

As in AP, let us assume that the "a" be the first term and 'd' be the common difference.

So, the value of nth term can be determined by using formula: a_n=a+(n-1)d, where, n = number of terms, and d = common difference.

So, the value of 19th terms = a+(19-1)d = a+18d = -5 -----(i)

And the value of 15th term = a+(15-1)d = a+14d = -7(1/2) ----(ii)

Now subtracting (ii) from (i),

We will get,

4d = 2(1/2)

=>4d = 2.5

=>d = (2.5/4) = 0.625

Now putting value of "d" in (i)

We will get,

a+(18*0.625) = -5

a=-5-11.25 = -16.25

We have, the formula for finding the sum of terms:

Sum of terms can be determined by using formula:

Sum = (n/2) × [2a + (n-1)d]

Here, n = 20, a = -16.25, d = 0.625

We will get sum of first 20 terms as:

[tex](n/2)\times [2a + (n-1)d]\\(20/2) \times [2 \times -16.25+(20-1)0.625]\\[/tex]

10[-32.5+11.875]

=10(-20.625) =-206.25

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Answer:

Step-by-step explanation:

Based on the fact that Ms. Michaels surveyed her class on whether they preferred free time at the beginning of class or at the end of class and found that students who prefer free time at the end of class are 12 over 19, the thing which the ratio 12 over 19 represents is C. 12 students prefer free time at the beginning of class, and 19 students prefer free time at the end of class.

What is a Ratio?

This refers to the quantitative relation that is used to show the relation between two variables, which shows the number of times one is contained in the other.

Hence, it can be seen that based on the result of the survey by Ms. Michaels about the preference of the students about free time at the beginning of class or at the end of class, the meaning of the ratio is that 12 students prefer free time at the beginning of class, and 19 students prefer free time at the end of class.

Answer:

Step-by-step explanation:

the ratio 13 over 17 represents how many students preferred free time at the beginning of class to how many students preferred free time at the end of class.a little extra: more people want free time at the end of class than at the beginning

Answer: The odds against an event occurring are the ratio of the probability that the event will not occur to the probability that the event will occur. To find the odds against an event, you can use the formula:

Odds against = (1 - probability of event occurring) / probability of event occurring

In this case, the event is that exactly 5 cars will pass over the bridge in a 4-minute period. The probability that this event will occur is 0.16. Therefore, the odds against this event occurring are:

Odds against = (1 - 0.16) / 0.16

= 0.84 / 0.16

= 5.25

So, the odds against exactly 5 cars passing over the bridge in a 4-minute period are 5.25 to 1.

It means that there are 5.25 times more likely that it will not happen compare to happen.

Step-by-step explanation:

The function in the attached graph is nonlinear

The function is negative where x < 0 and where x > 0.

There is an extrema.

The maximum is located at x = 0.

As the x-value decreases the y-value decreases for x < 0

As the x-value increases the y-value decreases for x > 0

The function is not a straight line graph, because of this, it is a non linear function

The extrema refers to points of maximum or minimum values. The function on the graph has a maximum value at (0, 0)

The end behavior of the function is described as

x ⇒ ∞ f(x) ⇒ - ∞

x ⇒ -∞ f(x) ⇒ -∞

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Answer:

96

Step-by-step explanation:

5 x 6 = 30

78 - 12 = 66

5 x 6 + 78 - 12

= 30 + 66

= 96

Answer:96

Step-by-step explanation:

The tasks that Keith can delegate to the assistant are List the account balances from the general ledger in the Trial Balance columns of the end-of-period spreadsheet, Add the Debit and Credit columns of the trial balance and Type the formal financial statements using the data from the Income Statement and Balance Sheet columns of the spreadsheet.

List the account balances from the general ledger in the Trial Balance columns of the end-of-period spreadsheet: Keith should delegate this task to his assistant. This is a relatively straightforward task that does not require a deep understanding of accounting principles. The assistant can be provided with clear instructions on how to pull the account balances from the general ledger and list them in the trial balance columns of the spreadsheet.

Add the Debit and Credit columns of the trial balance: Keith should delegate this task to his assistant. This is a simple arithmetic task that the assistant can perform with clear instructions.

Make the adjusting entries on the spreadsheet: Keith should retain this task. Adjusting entries involve more complex accounting knowledge and require a deeper understanding of accounting principles. It would be difficult for the assistant to complete this task without proper training.

Complete the spreadsheet: Keith should retain this task. This task requires a deep understanding of accounting principles and an understanding of how the various accounts and transactions relate to each other. It would be difficult for the assistant to complete this task without proper training.

Type the formal financial statements using the data from the Income Statement and Balance Sheet columns of the spreadsheet: Keith should delegate this task to his assistant. The assistant can be provided with clear instructions on how to organize the data from the spreadsheet into formal financial statements. It does not require a deep understanding of accounting principles.

Journalize and post the adjusting entries: Keith should retain this task. This task requires a deep understanding of accounting principles and an understanding of how the various accounts and transactions relate to each other. It would be difficult for the assistant to complete this task without proper training.

--The question is incomplete, answering to the question below--

"Keith Martin is the controller for Daniels Printing Service. Keith has been putting in a lot of overtime; therefore, Mr. Daniels has allowed Keith to hire an assistant. Keith's assistant is a bright, high school graduate, but he has never taken an accounting class. Keith is trying to decide which accounting activities could be delegated to his assistant. Keith is willing to give the assistant a few simple instructions on how to complete each task, but he doesn't have the time to teach the assistant to be an accountant.

For each task listed, state whether Keith should continue to do the work or delegate the task to his assistant. Explain each answer.

1. List the account balances from the general ledger in the Trial Balance columns of the work sheet.

2. Add the Debit and Credit columns of the trial balance.

3. Make the adjusting entries on the work sheet.

4. Complete the work sheet.

5. Type the formal financial statements using the data from the Income Statement and Balance Sheet columns of the work sheet.

6. Journalize and post the adjusting entries."

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Answer:

sorry beacuse I don't know anything

Answer: 110% of 120 minutes is equal to 132 minutes.

Step-by-step explanation:

To calculate percentiles:

The values of k are 3 and −1.

Note: The equation taken here is 4x^2 −2(k+1)x+(k+1)=0

Given: Equation 4X^2−2(k+1)x+(k+1)=0 has real and equal roots i.e., its discriminant is zero.

⇒b2−4ac=0

[An expression that can be produced from the square of a binomial equation is a perfect square trinomial. A perfect square trinomial is a formula that has the elements ax^2 + bx + c and satisfies the condition b^2 = 4ac. The roots of the quadratic equation ax2 + bx + c = 0 are real and equivalent if the discriminant is equal to zero (b2 - 4ac = 0), a, b, and c are real values, and a0.]

For given equation, a=4,  b=2(k+1),c=(k+1)

(2(k+1))^2 −4.4(k+1)=0

⇒(2k+2)^2−16(k+1)=0

⇒4k2+8k+4−16k−16=0

⇒4k2−8k−12=0

⇒4(k2−2k−3)=0

⇒k2−2k−3=0

⇒k2−3k+k−3=0

⇒k(k−3)+1(k−3)=0

⇒(k−3)(k+1)=0

⇒k−3=0   and   k+1=0

⇒k=3   and  k=−1

So, the values of k are 3 and −1.

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Answer: So the positive solution is:

ANSWER:    X = 5

(x = 5 ),  (x = - 2 )

Step-by-step explanation:

when 10 is subtracted from the square of a number the result is 3 times the number.

Find the positive solution.

Let:   x = number

Let x^2 = square of a number.

x^2 - 10x = 3x transpose

x^2  -  3x - 10 = 0

Apply Factoring: Fractions of  10  are   5  and 2

( - 5)(2)  =   - 10

- 5  + 2  =  - 3

( x - 5 )(x + 2) = 0

x - 5 = 0      x + 2 = 0

x = 5             x   =  - 2

So the positive solution is:

ANSWER:    X = 5

I hope that helps!!!!

Answer:c/π=d

Step-by-step explanation: the d and π was multiply with the d and if we want separate with it, we need to use the opposite way to get it.

Answer:

Step-by-step explanation:

a.Scale factor = distance on the plot / actual distance

b.3 feet = 12 inchs.

so scale factor = 5/12

A right cone is a cone whose apex is located along its center axis and whose axis is perpendicular to its base.

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Using graphical method, the solution to the system of linear inequality (x, y) are (1, 5)

A mathematical statement called a linear inequality depicts the relationship between two different variables, typically on a graph. A line or border that divides the area of all the points that fulfill the inequality from the areas of the points that do not constitutes the graph of a linear inequality. A set of lines in the coordinate plane that represent the equations of a system of linear inequalities is called a graph. The region of the coordinate plane where each of the inequalities holds can be seen by joining these lines to create a graph.

The inequality given are;

This can be solved using a graphing calculator;

The point of intersection shows the solution to the graph

The solution to the linear inequalities (x, y) are (1, 5)

The broken lines in the graph is from the greater than inequality, while then straight unbroken lines is the inequality with greater than or equal to sign.

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The correct equation which represent an identity will be;

⇒ 4(5x+2) = 20x+8

Mathematical expression is defined as the collection of the numbers variables and functions by using operations like addition, subtraction, multiplication, and division.

Given that;

All the equations are,

1) 2x + 1 = 3x + 4

2) 4x - 3 = 2(2x + 7)

3) 6x + 3 = 2x + 10

4) 4(5x + 2) = 20x + 8

Now,

Solve each equation and find an identity as;

1) 2x + 1 = 3x + 4

⇒ 1 - 4 = 3x - 2x

⇒ - 3 = x

⇒ x = -3

Thus, It is not represent an identity.

2) 4x - 3 = 2(2x + 7)

⇒ 4x - 3 = 4x + 14

⇒ - 3 ≠ 14

Thus, It shows no solution.

3) 6x + 3 = 2x + 10

⇒ 6x - 2x = 10 - 3

⇒ 4x = 7

⇒ x = 7/4

Thus, It is not represent an identity.

4) 4(5x + 2) = 20x + 8

⇒ 20x + 8 = 20x + 8

⇒ 20x - 20x = 8 - 8

⇒ 0 = 0

Clearly, '0' is an additive identity.

Thus, This equation shows an identity.

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Answer:

2

Step-by-step explanation:

look at where it intersects the line that goes straight up

Answer:I know why your father never came back

Step-by-step explanation: So when he got the milk he got stuck in traffic for a long time which caused the milk to expire and so he went back to grab new milk and on his way home he was stuck in traffic again and the milk got expired so he repeats the process and the same thing happens over and over and over, so hes stuck in an infinite loop until he passes away.

Ramona’s mistake was she just substituted the 8.5 for the wrong variable.

From given conditions:

Ramona used the regression equation y = 444x - 21.29,  

where x represents height and y represents shoe size,

According to Romana her answer is incorrect as a man who is -17.52 inches tall does not predict the approximate height of a man.

The 8.5 refer to shoes size, not height.

So substituting 8.5 for the x-variable is wrong, because x refers to height and y represents shoe size.

Therefore, Ramon just substituted the 8.5 for the wrong variable. She must replace 8.5 for y-variable, because that's the right one for shoe size.

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