When of glycine are dissolved in of a certain mystery liquid , the freezing point of the solution is lower than the freezing point of pure . On the other hand, when of ammonium chloride are dissolved in the same mass of , the freezing point of the solution is lower than the freezing point of pure . Calculate the van't Hoff factor for ammonium chloride in .

Answers

Answer 1

The given question is incomplete. The complete question is:

When 282. g of glycine (C2H5NO2) are dissolved in 950. g of a certain mystery liquid X, the freezing point of the solution is 8.2C lower than the freezing point of pure X. On the other hand, when 282. g of ammonium chloride are dissolved in the same mass of X, the freezing point of the solution is 20.0C lower than the freezing point of pure X. Calculate the van't Hoff factor for ammonium chloride in X.

Answer:  the van't Hoff factor for ammonium chloride is 1.74

Explanation:

Depression in freezing point is given by:

[tex]\Delta T_f=i\times K_f\times m[/tex]

[tex]\Delta T_f=T_f^0-T_f=8.2^0C[/tex] = Depression in freezing point  

[tex]K_f[/tex] = freezing point constant = ?

i = 1 ( for non electrolyte)

m= molality

[tex]8.2^0C=1\times K_f\times \frac{\text{mass of solute}}{\text{molar mass of solute}\times \text{weight of solvent in kg}}[/tex]

Weight of solvent (X)= 950 g = 0.95 kg

Molar mass of solute (glycine) = 75.07 g/mol

Mass of solute (glycine) = 282 g

[tex]8.2^0C=1\times K_f\times \frac{282g}{75.07g/mol\times 0.95kg}[/tex]

[tex]K_f=2.07[/tex]

ii) [tex]20.0^0C=i\times \times \frac{\text{mass of solute}}{\text{molar mass of solute}\times \text{weight of solvent in kg}}[/tex]

Weight of solvent (X)= 950 g = 0.95 kg

Molar mass of solute (ammonium chloride) = 53.49 g/mol

Mass of solute (ammonium chloride) = 282 g

[tex]20.0^0C=i\times 2.07\times \frac{282g}{53.49g/mol\times 0.95kg}[/tex]

[tex]i=1.74[/tex]

Thus the van't Hoff factor for ammonium chloride is 1.74


Related Questions

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Answer:

600

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2) Choose the best answer. Which type of reaction is this? NaOH + H2O → Na+ + OH strong base dissociation strong acid dissociation weak base dissociation neutralization weak acide dissociation​

Answers

Answer:

strong Base Dissociation

Explanation:

NaOH is baseNaOH is strong base that means strong acids ionizes almost completely when dissolved in water.

Consider the energy diagram below.
AY
B
Free Energy
Reaction Progression
Which line indicates a higher reaction rate?
A because it has a lower activation energy.
B because it has a lower activation energy.

Answers

It is A because it has a lower activation emery than like B

Answer:

B because it has a lower activation energy.

Explanation:

Just took the test

Students are asked to design an experiment with cookies to demonstrate their understanding of the scientific method. One group has decided to determine the amount of time it will take for a cookie to "dissolve" in a glass of milk.

Which variable would most likely NOT affect the time it takes for the cookie to dissolve?

a) the size of the cup of milk
b) the type of cookie
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d) the temperature of the milk
e) the type of milk​​

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I'm gonna guess E on this one, but I think you should choose either E or A

Which particles appear in equal numbers in all uncharged atoms? Proton, Neutron, Electron, None

Answers

Answer:

In an uncharged atom, the number of protons is always equal to the number of electrons. Apr 24, 2017

Explanation:

Neutron: An uncharged particle found in the nucleus of an atom.

There is only one stable atom that does not have neutrons. It is an isotope of the element hydrogen called protium. Protium, which contains a single proton and a single electron, is the simplest atom.

pls help i need asap will mark brainlest

Answers

Answer:

B. 50%

Explanation:

2H₂ + CO → CH₃OH

First we convert the given masses of the reactants into moles, using their respective molar masses:

4 g H₂ ÷ 2 g/mol = 2 mol H₂25 g CO ÷ 28 g/mol = 0.893 mol CO

0.893 moles of CO would react completely with (0.893 * 2) 1.786 moles of H₂. As there are more H₂ moles than that, H₂ is the reactant in excess and CO is the limiting reactant.

Now we calculate how many CH₃OH moles would have been formed if all CO would have been consumed:

0.893 mol CO * [tex]\frac{1molCH_3OH}{1molCO}[/tex] = 0.893 mol CH₃OH

Then we convert 0.893 moles of CH₃OH into grams, using its molar mass:

0.893 mol CH₃OH * 32 g/mol = 28.57 g

Finally we calculate the percent yield:

14 g / 28.57 g * 100% = 49%

Which of the following does NOT represent a balanced reaction? ​

Answers

Answer:

letter D i think

Explanation:

correct me if im wrong

What're the differences between oxidation and reduction​

Answers

Answer:

Oxidation:Oxidation is the loss of electron or Hydrogen atoms or gain of Oxygen atomsRemoval or loss of electrons

A ⟶ A⁺ + e⁻

Removal of Hydrogen

AH + B ⟶ A + BH

Addition of Oxygen

A + BO ⟶ AO + B

All the above reactions release energy

Reduction:Reduction is the gain of electron or Hydrogen atoms or loss of Oxygen atomsAddition or gain of electrons

A + e⁻ ⟶ A⁻

Addition of Hydrogen

A + BH ⟶ AH + B

Removal of Oxygen

AO + B ⟶ A + BO

All the above reactions stores energy

-TheUnknownScientist

A mixture of fuel and is injected into a cylinder fitted with a piston. The initial volume is 0.37 L. After the mixture is ignited, gaseous products are formed and 1885 J of energy is released by the reaction. 311 J of the released energy is lost as heat to the surroundings. To what volume would the gases expand against a constant pressure of 1.036 atm, if the remainig energy is converted to work to push the

Answers

Answer:

The gases will expand to a volume of 2.37 L

Explanation:

Gases are able to do work when they expand or compress against an external constant pressure.

This work done by gases when they expand or compress against a constant external pressure is known as pressure-volume work or PV work.

The formula for calculating the work done by gases when they compress or expand against a constant pressure is given as W = PΔV

Where ΔV is change in volume given as V2 - V1

Where V2 is final volume, V1 is initial volume

By convention, W can either be negative or positive. When work is done by the system (ΔV > 0), W is negative and when work is done on the system (ΔV < 0), W is positive.

In the gas mixture above, W = PΔV

Remaining energy, W = (1885 - 311) J = 1574 J

P = 1.036 atm = 1.036 × 760 mmHg = 787.36 mmHg

ΔV = V2 - V1

ΔV = V2 - 0.37

1574 = 1.036 (V2 - 0.37)

V2 - 0.37 = 1574/787.36

V2 - 0.37 = 1.999 L

V2 = 1.999 + 0.37

V2 = 2.369 L

Therefore, the gases will expand to a volume of 2.37 L


True or False: A higher vapor pressure (evaporates easily) corresponds to strong intermolecular forces.

Answers

the answer prob false

Which statement would indicate the presence of an acid?
It tastes bitter..
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It reacts with active metals to form a gas.
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Answers

Hey, it would not chnage the color and it wouldn’t react with metals so it’s between those two options. Sorry, I don’t want to say something and it’s my wrong. That’s my best guest .

Answer:

hey the answer is that it reacts with active metals to form a gas.

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156 grams of calcium fluoride, CaF2, is dissolved in 2000 mL of solution. Determine the molarity (M).

Answers

Answer:

1 M

Explanation:

We'll begin by calculating the number of mole of in 156 g of CaF₂. This can be obtained as follow:

Mass of CaF₂ = 156 g

Molar mass of CaF₂ = 40 + (19×2)

= 40 + 38

= 78 g/mol

Mole of CaF₂ =?

Mole = mass /molar mass

Mole of CaF₂ = 156 / 78

Mole of CaF₂ = 2 moles

Next, we shall convert 2000 mL to L. This can be obtained as follow:

1000 mL = 1 L

Therefore,

2000 mL = 2000 mL × 1 L / 1000 mL

2000 mL = 2 L

Finally, we shall determine the molarity of the solution. This can be obtained as follow:

Mole of CaF₂ = 2 moles

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Place the following in order of increasing entropy at 298 K.
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C) Ar < He < Ar < Ne < Kr.
D) Ar < Ne < Xe < Kr < He.
E) He < Ne < Ar < Kr < Xe.

Answers

Answer:

E

Explanation:

The simple rule of thumb is that as the atomic or molar mass of an atom increases, the entropy increases. This means that more the mass more will be entropy.

The atomic mass of various elements is as follows

Ne = 20 g/mol

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He = 4 g/mol

Ar = 40 g/mol

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He<Ne<Ar<Kr<Xe.

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What mass of gold is produced when 15.0A of current are passed through a gold solution for 15.0min ?

Answers

Answer:

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Explanation:

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⟰ ANSWER ⟰

U R ANS IS IN THE PIC

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Answers

Answer:

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Example - HCl

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Answers

Explanation:

A matter can be present in different states like solid, liquid or gas. When we write a chemical equation then states of species involved are also mentioned.

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Answer:

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Answers

A.

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PLZ ANSWER QUICK I AM IN TIMER HELP WILL GIVE BRAINLIEST
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the moon's revolution period around Earth

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Explanation:

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write a story of your life when you were hurted by someone whom you trusted blindly...​

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Answer:

Sis I think it happened with me but I am not able to remember if u want u can share if it happened with u

ACTIVITY NO.3
DIRECTIONS: Read each item carefully. Choose the letter of your answer.
1. Light travels in a
line when is passes through a single medium.
a. curve
b. straight
C. crooked
d. dotted
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?
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a. Person receiving it
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c. The nature of materials
d. Loudness of the sound
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a. From hot to cold
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c. From bottom to top
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Be more specific I just need points

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Answers

the answer would be A
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