When comparing voltaic cells to electrolytic cells, oxidation occurs at the.

Electrical engineers are the scientists that study the production of electricity more efficient.

Electrical engineers are the type of scientist that would most likely study how electricity could be produced more efficiently because they produced new technologies which are cost efficient as well as produce high amount of electricity.

So we can conclude that electrical engineers are the scientists that study the production of electricity more efficient.

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Answer:

V H2SO4=30 ml=0.03 l

Cm=16M

CM=n/V

n=CM×V

n= 0.48 moles H2SO4

Cm=0.48/0.3

CM=1.6M

Answer B

Answer:

Incisors: These are the teeth at the front of the mouth and the most visible ones when we smile. Bicuspids: Also called premolars, the bicuspids come after the canines and are flatter than the canines and incisors. Molars: At the back of your mouth, you'll find wide, flat molars.

Explanation:

give me a heart and star txs

Answer: 0.66 M

Explanation:

[tex]M_{A}V_{A}=M_{B}V_{B}\\(80.0)M_{A}=(36.2)(1.45)\\M_{A}=\frac{(36.2)(1.45)}{80.0} \approx \boxed{0.66 \text{ M}}[/tex]

Answer:

go with the fourth one because I did that one

The insecticides could kill the owls but not the grasshopper or mice due to no resistance in owls as compared to grasshopper and owl.

The insecticides could kill the owls but not the grasshopper or mice because the active ingredients in that insecticide is harmful for owls while on the other hand, the grasshopper and mice are tolerant to that insecticide.

So we can conclude that the insecticides could kill the owls but not the grasshopper or mice due to no resistance in owls as compared to grasshopper and owl.

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Answer:

Chemical bonds

Explanation:

Because it has an image of atoms being held together by chemical bonds.

Answer: C

Explanation:

So, the formula mass of aluminum chloride is 26.98154+3(35.453)=133.34054 g/mol.

This means that 42.3 grams of aluminum chloride are 42.3/133.34054=0.31723285356426 moles.

From the equation, we know that for every 3 moles of bromine consumed, 2 moles of aluminum chloride are consumed.

This means that (0.31723285356426)(3/2)=0.47584928034639 moles of bromine are needed.

So, the formula mass of a bromine molecule is 2(79.904)=159.808 g/mol, and thus the answer is (159.808)(0.47584928034639), which is about 76.1 g

Answer:

3 grams

Explanation:

14 g of N2   is 1/2 mole

  If you halve the N2   in the balanced equation , you have to halve the H2 down to 1.5 moles of H2    which is 3 grams

Answer:

see below

Explanation:

When a substance goes from a solid to a gas without going through a liquid stage .     Mothballs is an example.

Answer:

1) K and Rb

2) 20 protons, 20 neutrons, and 20 electrons.

Explanation:

1) If it's in the same column, it has the same # of valence electrons (e- on the outer shell), therefore similar chemical properties.

2)

1) atomic #, 20, is the number of protons

2) subtract the mass number from # of protons, which you get 20 neutrons

3) Number of electrons in a neutral atom = number of electrons, which is 20. You can also check yourself by looking at electron configuration on a full periodic table.

Answer:

¿Cuál será el pH de una disolución saturada de hidróxido de cinc?.

Explanation:

Dato: Kps (Zn(OH)2) = 1,8 x 10-14. Solución: 9,52.

The molar solubility in water of Ag₂CrO₄ is 2.52 * 10⁻⁴ M .

The measure of the degree to which a substance gets dissolved in a solvent to become a solution.

The formula for determination of molar solubity is

[tex]\rm K_{sp} = [A^+]^a [B^-]^b[/tex]

[tex]\rm K_{sp}[/tex]          = solubility product constant

[tex]\rm [A^+]^a[/tex]  =     cation in an aqueous solution

[tex]\rm [B^-]^b[/tex]  = anion in an aqueous solution

a, b          = relative concentrations of a and b

We have the data given as

[tex]\rm K_{sp}[/tex] for Ag₂CrO₄ is 8 x 10⁻¹²

For Silver chromate , the solubility would be only one-half of the Ag⁺ concentration.

We denote the solubility of Ag₂CrO₄ as S mol L⁻¹.

Then for a saturated solution, we have

[Ag⁺]=2S

[CrO₂⁴⁻]=S

the relation between the solubility and the solubility product constant depends on the stoichiometry of the dissolution reaction

(2S)²(S)=4S³ = 8 * 10⁻¹²

S=∛ (2*10⁻¹²)

S= 1.26 * 10⁻⁴ M

2S = 2.52 * 10⁻⁴ M

Therefore the molar solubility in water of Ag₂CrO₄ is 2.52 * 10⁻⁴ M .

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Answer:

A- c7h6br2

Explanation:

i just got it right :)

Answer:

83.69 gm

Explanation:

molar weight of N2 = 28

Find the number of moles then multiply by this

1.8 x10^24/ (6.022x10^23)   * 28 =83.69 gm

Answer:

200 torr

Explanation:

because it have 250ml when we subtract the 50 we get answer

Answer:

When a substance is cooled, its internal energy decreases: the movement of its particles decreases. bonds between particles form when a substance condenses or freezes, or sublimes to form a solid from a gas. What is called energy? Energy is the capacity of a physical system to do work.

Explanation:

Addition of water to an alkyne gives a keto‑enol tautomer product and that is the product changed into 2-pentanone, then the alkyne need to had been 1-pentyne. 2-pentyne might have given a combination of 2- and 3-pentanone.

They carries a carbonyl bond even as enol implies the presence of a double bond and a hydroxyl group. The keto-enol tautomerization equilibrium is depending on stabilization elements of each the keto tautomer and the enol tautomer.

The reaction:

C2H4 + H2 = C2H6

what is the maximum mass of ethane (c2h6) that can be formed?

The amount of hydrogen:

n(H2) = m(H2) / M(H2) = 5.28 / 2 = 2.64 mol

The amount of ethylene:

n(C2H4) = m(C2H4) / M(C2H4) = 9.91 / 28 = 0.354 mol

We see that the hydrogen is an excess reagent

The maximum mas of ethane is:

m(C2H6) = n(C2H4) * M(C2H6) = 0.354 * 30 = 10.62 g

what is the formula for the limiting reagent? - C2H4

what mass of the excess reagent remains after the reaction is complete? grams

The amount of hydrogen after reaction:

n2(H2) = 2.64 - 0.354 = 2.286 mol

m2(H2) = 2.286 * 2 = 4.572 g

Answer: m(C2H6)=10.62 g; C2H4; m2(H2)=4.572 g

An E2 mechanism is not followed because an anti periplanar E2 elimination is impossible due to the lack of beta hydrogen.

The term elimination has to do with the removal of a proton from the substrate by a base.

This question is incomplete and the complete question showing the options have been shown in the image attached to this answer.

This elimination  results in an alkene being formed. For the substrate alkyl halide shown in the question, an E2 mechanism is not followed because an anti periplanar E2 elimination is impossible due to the lack of beta hydrogen.

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The relation between the volume of the gas and the temperature is established by Charles's law. With a decrease in the temperature, the volume decreases by 45.7 mL. Thus, option c is correct.

Charle's law states the direct relation present between the temperature and the volume of the gas. The law is given as:

V₁ ÷ T₁ = V₂ ÷ T₂

Given,

V₁ = 50 mL

T₁ = 303.15 K

T₂ = 277.15 K

Substituting the value the final volume is calculated as:

50 ÷ 303.15 = V₂ ÷ 277.15

V₂ = (50 × 277.15) ÷ 303.15

= 45.71 mL

Therefore, option c. 45.7 mL is the final volume.

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Answer:

1.034 L

Explanation:

P1 V1 = P2 V2

P1 V1 / P2 = V2

2.4 (2.5) / 5.8 = V2 = 1.034 L

The molarity of a solution prepared by dissolving 3.11 grams of NaOH in

enough water to make 300 milliliters of solution is 0. 256 mol/ L

Explanation:

Molarity (M) is the amount of a substance in a given volume of solution. It is otherwise known as the number of moles of solute in a certain amount of solution.

The unit of molarity is mol/L

Molarity = number of moles of solute divided by the volume of the solution\

Molarity = ?

Number of  moles is calculated using :

Mass of the solute = 3.11 grams of NaOH

Molar mass of the solute = Na + O + H

Let's input the atomic numbers of the elements: Na (23) , O (16) , H (1)

Molar mass of NaOH = 23 + 16 + 1 = 40 g/ mol

Number of moles = 3.11 ÷ 40 = 0.077 mol

Volume of the solution is measured in Liters

Let's convert 300 milliters to liters = 300 divided by 1000 = 0.3 Liters

Molarity = 0.077 ÷ 0.3 = 0. 256 mol/ L

Therefore, the Molarity of the solution is 0. 256 mol/ L

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Answer:

mass and height of the object.

Answer:

50g of MgO

Explanation:

2Mg +O2 -----------> 2MgO

2moles of Mg needs 1mole of O2 for complete reaction ie

48g/mol of Mg --------- 32g/mol of O2

Xg of Mg --------- 30g of O2

X=45g of Mg

30g of O2 needs 45g of Mg, but only 30g of Mg is available, thus Mg is the limiting reagent.

2mole of Mg produces 2moles of MgO

ie 48g/mol of Mg ---------- 80g/mol of MgO

==> 30g of Mg -------------- Xg of MgO

X= 50g of MgO.

Answer:

Latent heating

Explanation:

As this occurs, liquid water absorbs energy, causing it to evaporate and form water vapor. The process of evaporation absorbs tremendous amounts of incoming solar energy.

Answer:

Homogeneous solutions are solutions with uniform composition and properties throughout the solution.

Explanation:

For example a cup of coffee, perfume, cough syrup, a solution of salt or sugar in water, etc. Heterogeneous solutions are solutions with non-uniform composition and properties throughout the solution.

Answer:

A homogeneous mixture is a mixture in which the composition is uniform throughout the mixture. Example: The salt water  is homogeneous because the dissolved salt is evenly distributed throughout the entire salt water sample. Another examples are wine, blood, vinegar

Explanation:

#1

You used red pen highlight which made things messier

The correct name should be.

As a methyl group attached with 9th carbon

#2

methyl group at 4

double bond at 2

#3

Three methyl groups are present

Double bond at 2

#4

#5

2,5-Dimethyl Hex-3-ene

Answer: B - 0.0098 moles

Explanation:

<3

The volume of water that will be produced from the reaction will be 6.3 mL

From the equation of the reaction:

[tex]H_2SO_4 + 2NaOH --- > Na_2SO_4 + 2H_2O[/tex]

The mole ratio of hydrogen sulfate to sodium hydroxide is 1:2.

Mole of hydrogen sulfate = 0.50 x 350/1000 = 0.175 moles

Mole of 15 grams sodium hydroxide = 15/40 = 0.375 moles

Thus, hydrogen sulfide is the limiting reagent.

Mole ratio of hydrogen sulfide to water = 1:2.

Equivalent mole of water = 0.175 x 2 = 0.35 moles

Mass of 0.35 moles of water = 0.35 x 18 = 6.3 grams.

1 gram of water = 1 ml.

Thus, 6.3 grams of water will be equivalent to 6.3 mL

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