When butane burns completely, only water and carbon dioxide gas are produced. If 11.6 g of butane and 40.0 L of oxygen at 22.0o C and 102 kPa react, what volume of carbon dioxide gas also at 22.0o C and 102 kPa can be collected over water. The vapour pressure of water at 22.0o C is 2.24 kPa.

2C4H10(g) + 13O2(g) --> 10H2O(g) + 8CO2(g)

Answer:

0.10 moles H₂O

Explanation:

The unbalanced equation:

NH₃ (g) + O₂ (g) ----> NO (g) + H₂O (g)

Reactants: 1 nitrogen, 3 hydrogen, 2 oxygen

Products: 1 nitrogen, 2 hydrogen, 2 oxygen

The balanced equation:

4 NH₃ (g) + 5 O₂ (g) ----> 4 NO (g) + 6 H₂O (g)

Reactants: 4 nitrogen, 12 hydrogen, 10 oxygen

Products: 4 nitrogen, 12 hydrogen, 10 oxygen

Now that the reaction is balanced, you can use the coefficients of the desired molecules to construct the mole-to-mole ratio. This ratio should be multiplied by the given value (0.085 moles). It is important to arrange the ratio in a way that allows for the cancellation of units (the desired unit should be in the numerator). The final answer should have 2 sig figs to match the given value.

0.085 moles O₂          6 moles H₂O
-------------------------  x  ------------------------  =  0.10 moles H₂O
                                      5 moles O₂

Answer:

it helps in respiration

Answer:

2.61 L

Explanation:

p1v1 = p2v2

p1v1 / p2 = v2

98 * 2 / 75 = v2 = 2.61 L

Answer:

HBr + KOH = KBr + H2O

3 HF + Fe(OH)3 = FeF3 + 3 H2O

2 HCl + Ca(OH)2 = CaCl2 + 2 H2O

Explanation:

0.03154 mol H₂O is formed from 0.0636 g of hydrogen if we consider that  O₂ is a limiting reagent.

The balanced equation is

[tex]2H_{2} (g)[/tex] + [tex]O_{2} (g)[/tex] → [tex]2H_{2} O (l)[/tex]

Here, we are calculating the moles  [tex]H_{2}O (l)[/tex] from the moles of H₂ if we consider O₂ is a limiting reagent:

Given:

The mass of  H₂ = 0.0636 g

We know that,

The moles of  H₂ = (0.0636 g of  H₂) × [tex]\frac{1.0 mol H_{2} }{2.016 g H_{2} }[/tex]

                             = 0.03154 mol  H₂

Moles of  H₂O (l) from  H₂ = ( 0.03154 mol  H₂) × [tex]\frac{2.0 mol of H_{2} O (l)}{2.O mol H_{2} }[/tex]

                                          = 0.03154 mol H₂O

Therefore,  0.03154 mol H₂O is formed from 0.0636 g of hydrogen if we consider that  O₂ is limiting reagent.

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Answer:

The answer is C2H4O2

Oxidizing acids can explode when mixed with incompatible chemical such as alcohols, turpentine, charcoal, organic refuse.

Oxidizing acids reacts violently with combustible such as alcohols, turpentine, charcoal, organic refuse because when it reacts with most metals, it release hydrogen gas in the air.

So we can conclude that Oxidizing acids can explode when mixed with incompatible chemical such as alcohols, turpentine, charcoal, organic refuse.

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Answer:

C3 H6 O2

Explanation:

first divide their mass by their respective molar mass, we get:

30.4 moles of C

61.2 moles of H

20.25 moles of O

now divide everyone by the smallest one of them then we get

C= 1.5

H= 3

O= 1

since our answer of C is not near to any whole number so we will multiply all of them by 2

so,

C3 H6 O2 is our answer

Answer:

[tex]\fbox {(2) 4.9}[/tex]

Explanation:

Applying the Ideal Gas Equation :

[tex]\boxed {PV = nRT}[/tex]

Finding n :

Solving for P :

∴ The pressure inside the flask in bar is 4.9.

Moles of oxygen

Temperature=273+27=300K

Apply ideal gas equation

Answer:

12,500 L

Explanation:

Because you are dealing with volume and temperature, you need to Charles' Law to find your missing value. The equation looks like this:

V₁ / T₁ = V₂ / T₂

In this equation, "V₁" and "T₁" represent the initial volume and temperature. "V₂" and "T₂" represent the final volume and temperature. You can plug the given values into the equation and simplify to find the final volume of the gas.

V₁ = 10,000 L                 V₂ = ? L

T₁ = 20 °C                       T₂ = 25 °C

V₁ / T₁ = V₂ / T₂                                             <----- Charles' Law equation

(10,000 L) / (20 °C) = V₂ / (25 °C)                <----- Insert values

500 = V₂ / (25 °C)                                        <----- Divide 20 from 10,000

12,500 = V₂                                                 <----- Multiply both sides by 25

The reaction is an addition reaction.

Addition reactions are chemical reactions involving 2 or more reactants reacting to produce a single product.

Addition reactions are different from decomposition reactions. In the latter, a single reactant decomposes to give two or more products.

In the illustrated reaction, Cl₂O5 and H₂O react together to form a single product, HCIO3.

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The volume of 0.8 M solution of citric acid required would be 75mL.

Given:

Concentration of citric acid =0.8M

Mass of baking soda = 15 g

Balanced chemical equation for the reaction of baking soda(NaHCO₃ ) with citric acid (C₆H₈O₇) is:

C₆H₈O₇ + 3NaHCO₃ -----> 3H₂O + 3CO₂ + Na₃C₆H₅O₇

Therefore, 1 mole of citric acid needs 3 moles of baking soda

Molar mass of baking soda = 84g/mol

No. of moles of baking soda = mass of baking soda / molar mass of baking soda = 15g ÷ 84g/mol = 0.178 moles

Thus no. of moles of citric acid required = (1 ÷ 3) × 0.178mole =0.06mole

Molarity = no. of moles of  / volume (in mL) x 1000

Volume of citric acid solution required= (0.06mole ÷ 0.8M) × 1000ml

                                                                =75ml

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The vital capacity will be 4600ml.

The highest amount of air a person can inhale following their maximal exhalation is known as their vital capacity. It is equivalent to the total of the inspiratory, tidal, and expiratory reserve volumes. It roughly corresponds to Forced Vital Capacity. A wet or conventional spirometer can assess a person's vital capacity.

Normal people have a 3 to 5-liter vital capacity.

It enables simultaneous inhalation of the greatest possible volume of clean air and exhalation of the greatest possible volume of stale air. So, by increasing gaseous exchange between the body's various tissues, it improves the amount of energy available for bodily function.

VC = TV₊IRV₊ERV

where,

VC = Vital capacity

TV = Tidal volume

IRV = inspiratory reserve volume

ERV = expiratory reserve volume

VC = 500 ₊ 3000 ₊ 1100

VC = 4600ml

Therefore, the vital capacity will be 4600ml.

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Answer:

62.5 mg

Explanation:

Just multiply the original amount by  1/2   three times:

500 mg  x  1/2  x  1/2  x  1/2 = 62.5 mg

Mass of liquid present in the container:

Yes, the liquid will be present, and of 1.2481 g

Calculation:

Given:

Volume = 1.5L

Temperature = 25 + 273 = 298K

P = 23.76 torr = 0.0312 atm

Using the ideal gas equation:

PV = nRT

Where:

making n subject of formula:

n = [tex]\frac{PV}{RT}[/tex]

By putting all the values in the given equation, we get,

n = 0.0312 x 1.5 / 0.0821 x 298

n = 0.0019 moles

So, 0.00189 are moles of water in the vapor

Now, subtract  1.25g of water from moles of water vapor, and we will get the mass of the liquid left,

1.25 - 0.0019 = 1.2481 g

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In an electrolytic cell, the electrode that acts as a source of electrons to the solution is called the cathode; the chemical change that occurs at this electrode is called reduction.

An electrolyte is a material that separates into charged ions when it is in contact with water. Cations are positively charged ions. Anions are ions that are negatively charged. A substance that may conduct an electric current when melted or dissolved in water is known as an electrolyte.

There are three main categories of electrochemical cells. the galvanic cell, the concentration cell, and the electrolytic cell. These cells all share the same four fundamental components. These are the elements

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The two elements have the same number of dots around their chemical symbols in their electron dot diagrams are: (C). P and As

Chemical symbol can be defined as a representation of an element using letters.

Chemical symbol are given to each element distinctively and this is an easier way to represent an element.

Some examples of chemical symbols are; O for oxygen, Zn for zinc, and Fe for iron etc.

In conclusion, The two elements have the same number of dots around their chemical symbols in their electron dot diagrams are: (C). P and As

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Answer:

6.627 x10^26    electrons

Explanation:

Each Na atom has 11 electrons

Mole weight = 22.989 gm/mole  

2300gm /22.989 gm/mole * 6.022 x 10^23  atoms/mole  * 11 electrons/atom

     = 6.627 x 10 ^26   electrons  

Answer:

mass increase!

Explanation:

<3

Answer:

b.distance between the objects

Explanation:

If you pull objects apart from each other they don't have as strong of a gravitational pull. think of it like a magnet the heavier the magnets the more power they can hold, the bigger they are the more surface area they have, and when you pull 2 magnets apart they slowly come weaker to each other.

Protons Ha and Hb in the compound given are enantiotopic.

Enantiotopic protons can be defined as those protons that can be replaced by another groups like deuterium.

A compound is a substance which contains two or more elements chemically combined together.

So therefore, Protons Ha and Hb in the compound given are enantiotopic.

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Answer:

1.) Physical

2.) Physical (probably)

3.) Chemical

Explanation:

Physical changes are changes to substances in which the intramolecular structure does not change. The intermolecular bonds (bonds between molecules) may change, but the actual chemicals involved are not altered.

Chemical changes occur when intermolecular bonds are broken/formed, changing the old substance into something new. Chemical reactions are taking place and the ratio of the elements in molecules are changing.

1.) Melting is an example of a physical change. When melting occurs, the intermolecular bonds between molecules are breaking in response to the introduction of more heat. However, the substance is still the same substance (ex. ice melting is still water as H₂O has not been changed). In this example, scientists are most likely calculating velocity.

2.) Because the original substance is able to be completely removed from the water in the flask, this is probably just a physical change. I say probably because no changes are really occurring here. It is unclear but not probably that any reactions are taking place between the water and the sample as they are easily separated. This may be an example of (can't decide) depending on how must they want you to assume. The property being measured is probably density.

3.) While dissolving the sample was an example of a physical change because just the state of matter changed, when it reacts with sodium hydroxide, a chemical change occurs. Most likely, new bonds are being formed between the elements in the original sample and the elements in sodium hydroxide. This is what allows scientists to measure the pH of a solution.

The partial pressure of Xe is 2.60atm

The sum of the partial pressures is equal to the total pressure. Ptotal = P1 + P2 + P3... .To calculate the partial pressure of one of the components of a mixture, subtract the sum of known partial pressures of the other components from the total pressure.

Given the values of

PHe=0.20 atm

PAr=0.20 atm

Ptotal=3.00 atm

We need to find  PXe

Solution: Determine the sum of the partial pressures of helium and argon, then subtract the sum from the total pressure.

PHe+PAr =0.20 atm + 0.20=0.400 atm

PXe=3.00atm−0.400=2.60 atm

Each gas that makes up a mixture of gases has a partial pressure, which is the notional pressure of that gas as if it alone filled the original combination's complete volume at the same temperature.

According to Dalton's Law, a perfect gas mixture's total pressure equals the sum of its constituent gases' individual partial pressures.

The thermodynamic activity of a gas's molecules is gauged by its partial pressure.

Gases react, disperse, and dissolve based on their partial pressures rather than the concentrations they have in liquids or other gas combinations.

This general characteristic of gases holds true in biological chemical interactions involving gases.

Hence the partial pressure of Xe is 2.60atm

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Net Product formed:

The conversion of 1 mol of fructose 1,6-bisphosphate to 2 mol of pyruvate by the glycolytic pathway results in a net formation of  2 mol of NADH and 4 mol of ATP.  

Glycolysis:

The energy-intensive stages also known as the first half of glycolysis. It divides the six-carbon sugar molecule evenly into two three-carbon molecules. The energy-releasing stages, or the second half of glycolysis, draw energy from the molecules and store it as ATP and NADH, the reduced form of NAD.

Two pyruvate molecules form the final product of glycolysis, which begins with glucose and two ATP molecules and two NADH molecules are gained by the cell as a net result.

The first half of the process requires the utilization of two ATP molecules to set up the six-carbon ring for cleavage. But since this pathway is starting from fructose 1,6-bisphosphate, the utilization step is omitted thus four molecules of ATP and two molecules of NADH are produced in total.

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ΔG° = -RT ln K

ΔG° = -RT ln 1/Ksp (reverse reaction, solid (Al(OH)₃ not count for equilibrium constant-K)

ΔG° = -RT ln 1/Ksp

ΔG° = -8.314 x 10⁻³ x 298 ln 1/(2 x 10⁻³¹)

ΔG° = -175.132 kJ/mol

The function of Y would be to keep oxygen-rich blood and oxygen-poor blood separate. The last option is the correct one.

Y is the septum

The septum is a structure of the heart that separates the left atrium from the right atrium as well as the two ventricles.

Thus, the structure prevents oxygenated blood from mixing with deoxygenated blood.

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Answer:

[tex]\huge\boxed{\sf Alkene}[/tex]

Explanation:

The molecule shown is an Alkene, since:

[tex]\rule[225]{225}{2}[/tex]

Answer:

[tex]\huge\boxed{\sf 3 \ electrons}[/tex]

Explanation:

[tex]1s^22s^22p^1[/tex]

The outermost/valence shell is the second one, seeing from the electronic configuration.

= 2 + 1 = 3 (electrons are raised to the power in the electronic configuration)

Since, the valence shell here is 2, the electrons of second shell will be counted as valence electrons.

[tex]\rule[225]{225}{2}[/tex]

Answer:

room

Explanation:

because it'd in your house and u go there everyday and sleep and live there

Answer:

3.0395m

Explanation: