When are two triangles similar? Select all that apply.

All three of their corresponding angles have the same measure.
Two of their corresponding angles are the same angle measure.
Only one of their angles match.
All ratios of corresponding sides are proportional.
Two of their corresponding sides are in the same ratio.

Answer:

2

Step-by-step explanation:

-3 (4 - 7) + (2 x 5 - 17)

 -3 (4 - 7) + (10 - 17)

 -3 x (-3) + (-7)

   9 + (-7)

 9 - 7

   =2

Answer:

A. Red/Line C

Step-by-step explanation:

Answer:

C.  -18

Step-by-step explanation:

Scalar Product (Dot Product) of two vectors

[tex]\displaystyle \vec{a} \cdot \vec{b}=\sum_{i=1}^na_ib_i[/tex]

[tex]\textsf{If }\: \vec{a}=a_1\hat{i}+a_2\hat{j}+a_3\hat{k} \quad \textsf{and } \quad \vec{b}=b_1\hat{i}+b_2\hat{j}+b_3\hat{k}[/tex]

[tex]\textsf{then }\quad \vec{a} \cdot \vec{b}=a_1b_1+a_2b_2+a_3b_3[/tex]

Given:

⇒ v₁ · v₂ = (3 · 2) + (-4 · 6)

⇒ v₁ · v₂ = 6 + (-24)

⇒ v₁ · v₂ = 6 - 24

⇒ v₁ · v₂ = -18

opposite sides and diagonals of a parallelogram are equal

+ diagonals of a parallelogram meet eachother in the middle so:

10x+14=x+77

10x-x=77-14

9x=63

x=63÷9

x= 7

y+8=4y-19

y-4y=-19-8

-3y=-27

y=-27÷-3

y=9

2z+3=37

2z=37-3

2z=34

z=34÷2

z=17

To find the degrees of freedom in the given question, we have to take into consideration of the confidence interval as well as degrees of freedom. The critical t-value in this data set is 2.086

This is the range of values that we observe in our sample and for which we expect to find the value that accurately reflects the population.

We can also say that it is a range of values so defined that there is a specified probability that the value of a parameter lies within it.

Data;

At a 95% confidence level, the t is

α   =  1  -   0.95

The critical t-value in this data set is 2.086

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Answer:

2 15/28

Step-by-step explanation:

First we will convert both mixed fractions into improper fractions.

5 1/4 becomes 21/4

2 5/7 becomes 19/7

21/4 - 19/7 does not work, so we must make the denominator the same

147/28 - 76/28 = 71/28

Now we convert back to a mixed number:

2 15/28

Answer: [tex]-11\frac{15}{28}[/tex]

Step-by-step explanation:

Convert to Improper fractions

[tex]5\frac{1}{4} = \frac{21}{4} \\2\frac{5}{7} = \frac{19}{7} \\[/tex]

Find a lowest common multiple

lcm(4,7) = 28 (7 * 4)

since they are just multiplying each other, we can cross multiply

[tex]\frac{(21*7) - (19*4)}{4*7} = \frac{147-76}{28} \\= \frac{71}{28} \\=2\frac{15}{28}[/tex]

Answer:  C) add 12 to both sides

Reason:

We add 12 to the left side to undo the -12, which will get y by itself.

We must do the same thing to both sides to keep things balanced.

Answer:

Step-by-step explanation:

A: Not a Rhombus. Adjacent sides are unequal

B: True. Opposite sides are parallel

C: True. Adjacent sides are unequal in length but it has two sets of parallel lines and at least 1 right angle.

D: Not a square. Not all 4 sides are of equal length

E: It is a quadrilateral. A quadrilateral only requires 4 sides.

F: Not true. It does not have the properties of a trapezoid.

HOPE IT HELP (≧▽≦)(≧▽≦)(≧▽≦)

Answer:

Step-by-step explanation:

the answer is wrong its  34.3

Answer:

[tex]D)~(x+3)^2 = 16[/tex]

Step-by-step explanation:

[tex]~~~~~~x^2 +6x -7 = 0\\\\\implies x^2+6x = 7\\\\\implies x^2 +2 \cdot 3 \cdot x +3^2 -3^2 = 7\\\\\implies x^2 +2 \cdot 3 \cdot x+3^2 = 7+3^2\\\\\implies (x+3)^2 = 7+9\\\\\implies (x+3)^2 = 16[/tex]

Answer:

From the diagram you can see that we have constructed a right triangle, with height A and base 15.Length of shadow = 15 feet.Height of flagpole = A.We know the angle of elevation is 40∘. Using this angle and the tangent ratio, we can find A.tan(40∘)=oppositeadjacent=A15∴tan(40∘)=A15Rearranging:A=15tan(40∘)By calculator:A=12.59 feet.  ( 2 d.p.)

The probability of winning the game on your next turn is; 14%

The sample size of the two number cubes, when rolled is:

n = 36

The number of outcomes that give a sum of 2 or 5 is 5,

And the outcomes are (1, 1) (2, 3) (3, 2) (1, 4) (4, 1)

The probability is the quotient of the number of outcomes of the sum of 2 or 5 and the total outcomes.

Thus,

Probability = 5/36 * 100% = 13.89% ≈ 14%

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Answer:

One, since the lines are not parallel (you can tell by either the graph, or the coefficient of the x term, called "slope", and it's (3;4)

Multiply the moduli and add the arguments:

√2/6 cis(3π/5) × √6/4 cis(2π/3)

= (√2/6 × √6/4) cis(3π/5 + 2π/3)

= √3/12 cis(19π/15) … [A]

Answer:

9/1000

Step-by-step explanation:

When writing decimals into fractions, you first take the last digit, (in this case 9), and place it as your numerator, then count how many decimal places there are after 0. <---- in our case we have 3 decimal places which means our denominator has 3 zeros. Hence it is 1000.

Answer:

x=1/2 or x=-1/3

Step-by-step explanation:

6x^2-x-1=0

6x^2+2x-3x-1=0

(6x^2+2x)+(-3x-1)=0

2x(3x+1)-1(3x+1)=0

2x(3x+1)-1(3x+1)=0

(2x-1)(3x+1)=0

(2x-1)(3x+1)=0

2x-1=0

or

3x+1=0

x=-1/3

x=1/2

Answer:

Its 1/3 and -1/2

Step-by-step explanation:

Answer:

9.42

Step-by-step explanation:

Since the angle shown is 90 degrees we can deduce that the rest of the arc is 270 degrees therefore we can make the fraction:

270/360; 360 being the total angle measurement of a circle

270/360 simplifies to 3/4

The fraction represents how much of the circle that arc covers

Now we have to find the circumference which would be

2(3.14)r

r = 2 therefore: 2(3.14)2 = 12.56

Now that we have the circumference of the WHOLE circle we multiply it by 3/4 to find out the arc length

Which gives us  9.42

Answer:

115 and 1/2

Step-by-step explanation:

B•W•H

Hope this helps! ;-)

Thanks for correcting my mistake!!!

Answer:  The answer is 115 1/2

Explanation: Just multiply all the dimensions

Answer:

8x^2 2y^3

Step-by-step explanation:

The equations are

Lets solve them through matrix

Let

[tex]\\ \rm\Rrightarrow A=\left[\begin{array}{ccc}\rm 5&\rm 3&\rm 4\\ \rm 2&\rm 5&\rm 5\\ \rm 6&\rm 3&\rm3\end{array}\right][/tex]

[tex]\\ \rm\Rrightarrow X=\left[\begin{array}{c}\rm x\\ \rm y\\ \rm z\end{array}\right][/tex]

[tex]\\ \rm\Rrightarrow B=\left[\begin{array}{c}\rm 67 \\ \rm 56\\ \rm 72\end{array}\right][/tex]

Let solve

Determinant of A

[tex]\\ \rm\Rrightarrow |A|[/tex]

[tex]\\ \rm\Rrightarrow 5\left|\begin{array}{cc}\rm 5&\rm 5\\ \rm 3&\rm 3\end{array}\right|-3\left|\begin{array}{cc}\rm 2&\rm 5\\ \rm 6&\rm 3\end{array}\right|+4\left|\begin{array}{cc}\rm 2&\rm 5\\ \rm 6&\rm 3\end{array}\right|[/tex]

[tex]\\ \rm\Rrightarrow 5(15-15)-3(6-30)+4(6-30)[/tex]

[tex]\\ \rm\Rrightarrow 72-96[/tex]

[tex]\\ \rm\Rrightarrow -24[/tex]

[tex]\\ \rm\Rrightarrow A_{11}=0[/tex]

[tex]\\ \rm\Rrightarrow A_{12}=24[/tex]

[tex]\\ \rm\Rrightarrow A_{13}=-24[/tex]

[tex]\\ \rm\Rrightarrow A_{21}=3[/tex]

[tex]\\ \rm\Rrightarrow A_{22}=-9[/tex]

[tex]\\ \rm\Rrightarrow A_{23}=3[/tex]

[tex]\\ \rm\Rrightarrow A_{31}=-5[/tex]

[tex]\\ \rm\Rrightarrow A_{32}=-17[/tex]

[tex]\\ \rm\Rrightarrow A_{33}=19[/tex]

[tex]\\ \rm\Rrightarrow \left[\begin{array}{ccc}\rm 0&\rm 24&\rm -24\\ \rm 3&\rm -9&\rm 3\\ \rm -5&\rm -17&\rm 19\end{array}\right][/tex]

[tex]\\ \rm\Rrightarrow \left[\begin{array}{ccc}\rm 0&\rm 24&\rm -24\\ \rm 3&\rm -9&\rm 3\\ \rm -5&\rm -17&\rm 19\end{array}\right]^T[/tex]

[tex]\\ \rm\Rrightarrow \left[\begin{array}{ccc}\rm 0&\rm 3&\rm -5\\ \rm 24&\rm -9&\rm -17\\ \rm -24&\rm 3&\rm 19\end{array}\right][/tex]

[tex]\\ \rm\Rrightarrow \dfrac{1}{|A|}\times Adj.A[/tex]

[tex]\\ \rm\Rrightarrow \dfrac{1}{-24}\left[\begin{array}{ccc}\rm 0&\rm 3&\rm -5\\ \rm 24&\rm -9&\rm -17\\ \rm -24&\rm 3&\rm 19\end{array}\right][/tex]

Now

[tex]\\ \rm\Rrightarrow AX=B[/tex]

[tex]\\ \rm\Rrightarrow X=A^{-1}B[/tex]

[tex]\\ \rm\Rrightarrow X=\dfrac{1}{-24}\left[\begin{array}{ccc}\rm 0&\rm 3&\rm -5\\ \rm 24&\rm -9&\rm -17\\ \rm -24&\rm 3&\rm 19\end{array}\right]\left[\begin{array}{c}\rm 67\\ \rm 56\\ \rm 72\end{array}\right][/tex]

[tex]\\ \rm\Rrightarrow X=\dfrac{1}{-24}\left[\begin{array}{c}\rm -192\\ \rm -120\\ \rm -72\end{array}\right][/tex]

[tex]\\ \rm\Rrightarrow X=\left[\begin{array}{c}\rm 8\\ \rm 5\\ \rm 3\end{array}\right][/tex]

So

[tex]\\ \rm\Rrightarrow \left[\begin{array}{c}\rm x\\ \rm y\\ \rm z\end{array}\right]=\left[\begin{array}{c}\rm 8\\ \rm 5\\ \rm 3\end{array}\right][/tex]

We get

Answer:

84cm

Step-by-step explanation:

Given that;

1cm = 7m

12cm = x

Cross Multiply

x = 12×7

x = 84m

Answer:

x = 4

Step-by-step explanation:

x(x + 8) = 48

x² + 8x = 48

x² + 8x - 48 = 0

times into -48

add into 8

(x - 4)(x + 12) = 0

x - 4 = 0

x = 4

or

x + 12 = 0

x = -12

A length cannot be a negative number therefore x = 4

Answer:

110

50+50=100

5+5=10

100+10=110

(thats how i do mental math)

Answer:

Step-by-step explanation:

The problem statement gives expressions and relations for revenue, cost, and profit. Substitute and simplify or solve, as appropriate.

__

Given: r(x) = 20x; c(x) = 3600+4x; p(x) = r(x) -c(x)

The formula for p(x) is ...

  p(x) = (20x) -(3600 +4x) . . . . substitute for r(x) and c(x)

  p(x) = 16x -3600 . . . . . . . . simplify

__

  r(x) = 2·c(x) . . . . given relation for revenue and cost

  20x = 2(3600 +4x) . . . . substitute for each

  12x = 7200 . . . . . . . simplify and subtract 8x

  x = 600 . . . . . . . divide by 12

Revenue is twice the cost when x = 600 units.

__

  p(x) = 292 +1/3r(x) . . . . given relation for profit and revenue

  16x -3600 = 292 +1/3(20x) . . . . . substitute for each

  28/3x = 3892 . . . . . . . . add 3600 -20/3x

  x = 417 . . . . . . . . multiply by 3/28

Profit is $292 more than 1/3 the revenue earned for 417 units.

Answer:

-3/4

Step-by-step explanation:

ΔY / ΔX, or change in y divided by change in x
(-4,3) and (0, 0)
x increases by 4
y decreases by 3
-3/4

Answer:

It is -3/4

Step-by-step explanation:

Answer:

the difference in their ages is 31/2

Step-by-step explanation:

151/2=2x15+1/2=31/2

Step-by-step explanation:

reduce -28<4w-8

-7<w-2

add +2

-7+2<w-2+2

-5<w

w>-5

Answer:

See below ~

Step-by-step explanation:

Solving the inequality :

Evaluating the given numbers :

-5

5

-9

-1