The refrigerant trace gas that should be used to identify a leak is the HCFC-22. Nitrogen gas should also be used along with trace gas.
HCFC-22, also known as chlorodifluoromethane, is a colorless gas that is used as a propellant and refrigerant. It was the most commonly used refrigerant for air-conditioning systems in buildings, but if it leaks, it may cause ozone depletion. Nowadays, it is still used but only when recovered and recycled.
One use of HCFC-22 is to detect a leak in a system. To do that, the system is pressurized with a trace quantity of HCFC-22 to a certain pressure, then dry nitrogen is used to further increase the system pressure. The trace refrigerant is enough to be detected by a leak detector.
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cumulus clouds often indicate a. a dry adiabatic lapse rate. b. a temperature inversion. c. possible turbulence.
Cumulus clouds often indicate Optiion C. possible turbulence.
Turbulence, associated with thunderstorms, may be extremely risky, having the ability to motivate overstressing of the aircraft or lack of manipulation. Thunderstorm vertical currents can be sturdy sufficient to displace a plane up or down vertically as plenty as 2000 to 6000 ft.
Turbulence is only one type of alternate in the air around your aircraft. Air is not nothingness; it's a fluid, like water. Currents of airflow up and down, ripple out, trade direction, and change speed. some of the things that reason turbulence are simpler to expect.
Turbulence is an unexpected and every-so-often violent shift in airflow. the ones irregular motions within the atmosphere create air currents that may purpose passengers on an aircraft to enjoy stressful bumps throughout a flight, or it is able to be extremely sufficient to throw an airplane out of manage.
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How do we learn about what is going on in the center of our own galaxy (the Milky Way)?
A) We have learned it only recently, thanks to the great photographs obtained by the Hubble Space Telescope.
B) We cannot see the galactic center with visible or ultraviolet light, but radio and X rays from the center can be detected.
C) The gas and dust in the Milky Way prevent any type of direct observation of the galactic center, but theoretical models allow us to predict what is happening there.
D) We must look at the centers of other galaxies and hope that ours is just like others.
The things which are going on in the centre of our own galaxy (the Milky Way), We cannot see the galactic centre with visible or ultraviolet light, but radio and X-rays from the centre can be detected.
Milky Way GalaxyThe galaxy that contains our Solar System is known as the Milky Way, and its name refers to how it appears to us on Earth: a hazy strip of light in the night sky made up of stars that are too close together to be seen individually. The phrase Milky Way is a translation from Greek (galaktikos kklos), which means "milky circle," into Latin via lactea. The Milky Way is a disk-shaped structure, yet when viewed from Earth, it seems like a band. In 1610, Galileo Galilei used his telescope for the first time to separate the band of light into individual stars. Most astronomers believed that the Milky Way held all of the universe's stars until the early 1920s.
Observations by Edwin Hubble proved that the Milky Way is only one of many galaxies after the 1920 Great Debate between the astronomers Harlow Shapley and Heber Curtis.
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arrange the colors of the visible spectrum in order from highest to lowest energy.- Violet - Indigo - Blue- Green- Yellow- Orange- Red
From lowest energy to highest energy, the hues of the spectrum are violet, indigo, blue, green, yellow, orange, and red. Can the visible spectrum be divided up into the several hues that make up visible light?
590–620 nm for orange Red: 620-750 nm (400–484 THz frequency) The violet spectrum of light has the maximum frequency and energy because it has the shortest wavelength. Red has the highest energy, the longest wavelength, and the lowest frequency. the hues that make up the visible light spectrum, including blue, green, red, yellow, orange, violet, and indigo. Actually, these are the hues of the rainbow. How many colours are there in the visible spectrum of light? They are all. A visible light spectrum is the name given to a rainbow of colours. What's the name of the
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about how often is it estimated that an asteroid or comet impacts earth with sufficient energy to cause mass extinction?
It is estimated that an asteroid or comet impacts the Earth with sufficient energy to cause mass extinction about once every few hundred million years.
Mass extinction is an event in which a rapid and widespread decrease is happening to the biodiversity on Earth. In it, all or at least 75% of the world's species died at a much faster rate than they are replaced in less than 3 million years.
There are several things that can cause a mass extinction event, ranging from anoxia, climate change, and volcanism, human activity, to an impact caused by another celestial body, such as an asteroid or comet. Each cause has its own probability of happening.
It is most likely that the latest mass extinction, the Cretaceous-Paleogene extinction where most of the dinosaurs went extinct, was caused by a meteoric impact. It happened around 66 million years ago.
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using the z table, determine the critical values for a two-tailed test when α = 0.03.
The critical value is ± 2.17 for a two-tailed test when α = 0.03.
As per the details share in the above question are as bellow,
The given details are as follow,
The two tailed test when the value of α = 0.03.
Use the z table.
We have to determine the critical value.
A mathematical table for the values of, implying the values of the normal distribution's cumulative distribution function, is known as a standard normal table. The Z-score, commonly referred to as the standard score, expresses how far away from the mean an object.
A crucial value is a point on the distribution of the null hypothesis' test statistic that designates a range of values that demand the null hypothesis be rejected. The critical or rejection zone refers to this collection. One-sided tests often have a single critical value, whereas two-sided tests typically have two critical values.
Now two tailed,
[tex]\alpha[/tex] =0.03
[tex]\alpha / 2[/tex] = 0.03 / 2 = 0.015
[tex]Z\alpha/2[/tex] = Z0.015 = ± 2.17( Using z table )
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A solar cell is charging a battery what is the energy
A solar cell is charging a battery, here electrical energy is converted into chemical energy.
What is solar cell?Solar cells are semiconductor devices that utilize sunlight to generate energy. They go through the same manufacturing and processing steps as computer memory chips. The main component of solar cells is silicon, which absorbs the photons that the sun's beams emit. The method was first identified in 1839.
A photoelectric cell is a type of device whose electrical properties, such as current, voltage, or resistance, change in response to light. The foundation of photovoltaic modules, sometimes referred to as solar panels, are solar cells.
The photovoltaic effect, which underpins solar cell operation, states that when light of a specific wavelength is shone on semiconductors, free electrons are generated.
Here in the case of solar cell for charging the battery electrical energy is converted into chemical energy.
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Howard i moving a 90 kg wooden crate from one ide of hi office to the other. To accomplih thi, he tie a rope around hi wait and begin to walk, o that the crate i dragged horizontally acro the floor. If the coefficient of friction between the crate and the floor i 0. 159, what force mut Howard apply to to the rope to move at a contant peed?
The force exerted by Howard on the rope to make it move at a constant speed is 140.24 N.
The force that Howard must exert on the rope to move at a constant speed is calculated by applying Newton's second law of motion as follows:
F - Ff = ma
F: the applied force
Ff: the frictional force
m: the mass of the crate's mass
a: the acceleration of the crate (at a constant speed, acceleration: a = 0)
F = Ff
F = μmg
Given in question
Friction coefficient: μ = 0.159Gravity speed: g = 9.8 m/sCrate mass : m = 90 kgF = μmg
F = 0.159 x 90 x 9.8
F = 140.24 N
Then the force Howard exerts on the rope to move at a constant speed is 140.24 N
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Two people, one having twice the mass of the other, play tug of war with a 12 meter rope on frictionless ice. After a brief time, they meet. The heavier person slides a distance of?
A) 6m
B) 4m
C) 5m
D) 3m
Answer:
In a tug of war, the forces applied by the two people on the rope must be equal in magnitude but opposite in direction. Therefore, if one person has twice the mass of the other, the person with the larger mass will experience twice the acceleration of the person with the smaller mass.
If the heavier person has twice the mass of the lighter person, and the two people meet after a brief time, it follows that the heavier person will have traveled twice as far as the lighter person. Since the rope is 12 meters long, and the two people meet at the center of the rope, the lighter person will have traveled half the length of the rope, or 12 / 2 = 6 meters. Therefore, the heavier person will have traveled twice this distance, or 2 * 6 = <<2*6=12>>12 meters.
Since the heavier person started from the same position as the lighter person, the distance that the heavier person slid is equal to half the total distance traveled, or 12 / 2 = <<12/2=6>>6 meters. Therefore, the correct answer is (A) 6 meters.
a graph of v(t) is shown for a world-class track sprinter in a 100-m race. (see figure below).
The average acceleration of the world class track sprinter is 3.66 m/s².
Initial distance = h₀ = 0 m
Final Distance = h = 19 m
Initial speed = u = 0 m/s
Final speed = v = 11.8 m/s
We use the kinematic equation of motion, to calculate the average acceleration;
= v² = u² + 2a ( h - h₀)
= a = v² - u² / 2 ( h - h₀)
= a = 11.8² - 0² / 2 ( 19 - 0 )
= a = 3.66 m/s²
Thus, the average acceleration of the sprinter is 3.66 m/s².
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The complete question:
a graph of v(t) is shown for a world-class track sprinter in a 100-m race. (see figure below). It can reach a top speed (of about 11.8 m/s ) in the first 19.0 m of a race. what is the average acceleration of this sprinter
Imagine aliens landed on earth. If the aliens learned English, from their perspective,
what would Earth be?
An interior planet
An exoplanet
An outsider planet
An irregular and planet
From aliens perspective, Earth would be an exoplanet in English language.
What is exoplanet?Any planet outside of our solar system is an exoplanet. The majority of exoplanets orbit other stars, while rogue planets—free-floating exoplanets that are unattached to any star—orbit the galactic centre.
The majority of the exoplanets found so far are in the Milky Way, which is a rather tiny area of our galaxy. The Kepler Space Telescope of NASA has revealed that the galaxy has more planets than stars.
We can determine the sizes (diameters) and weights (weights) of exoplanets and determine their compositions, which range from extremely stony (like Venus and Earth) to extremely gas-rich (like Jupiter and Saturn). Exoplanets contain elements that are comparable to those found in our solar system, but their compositions of those elements may vary.
If aliens arrived on earth. Earth would be considered an exoplanet in the language of them.
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what is b(r) , the magnitude of the magnetic field inside the toroid and at a distance r from the axis of the toroid?
the strength of the magnetic field within the toroid and at a distance of r from the toroid's axis
the magnitude of the magnetic field inside the toroid be
B(r)=[tex]\frac{\mu IN}{2\pi r}[/tex]
when only in [tex]r^{\cap}[/tex] any [tex]k^{\cap}[/tex] direction
B=[tex]\frac{\mu_{0} I }{2R}[/tex]
A magnetic field is a vector field that explains the magnetic influence on moving electric charges, electric currents, and magnetic materials. A force perpendicular to the charge's own motion and the magnetic field acts on it while the charge is traveling through a magnetic field. The magnetic field of a permanent magnet pulls on ferromagnetic elements like iron and attracts or repels other magnets. The three other magnetic effects of paramagnetism, diamagnetism, and antiferromagnetism also exert minute forces on "nonmagnetic" materials in a nonuniform magnetic field, albeit these forces are often so minute that they can only be measured by laboratory equipment. Electric currents, like those utilized in electromagnets, and electric fields that change over time produce magnetic fields that surround magnetized things.
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what change in entropy occurs when a 27.9 g ice cube at -12°c is transformed into steam at 115°c?
Upon calculation the change in entropy is found to be 244 J/K.
Entropy is a generic phrase that describes the trend toward disorder as well as the spontaneous changes that take place in everyday situations. Entropy is not only a term used in academia; it is also frequently characterized as a physical feature connected to uncertainty.
For a reversible process the change in entropy is given by:
S= [tex]\frac{dQ}{T}[/tex]
dQ= heat
T= temperature
The change in entropy when the temperature of ice comes to 273 K is:
S= [tex]\int\limits^{273}_ {261} \, \frac{dQ}{T}[/tex]
dQ= mcdT
m= mass of ice= 27.9 gm= 0.0279 kg
c= specific heat capacity= 2090 J/kg C
T= temperature
S=[tex]mc\int\limits^{273}_{261} \, \frac{dT}{T}[/tex]
S= 0.0279× 2090×㏑[tex]\frac{273}{261}[/tex]
S= 2.62 J/K
For conversion of ice into water dQ= mL
m= mass of ice
L= latent heat of fusion= 3.33 ×10⁵
S= [tex]\frac{mL}{T} =\frac{3.33* 100000*0.0279}{273}[/tex]
S= 34 J/K
Change in entropy when the water turns into steam is given by
S= [tex]\int\limits^{373}_{273} \, \frac{mcdT}{T} =mc ln\frac{373}{273}[/tex]
c= heat capacity of water= 4186
S= 0.0279× 4186×㏑[tex]\frac{373}{273}[/tex]
S= 36.5 J/K
Change in entropy at 373 K for steam is given by
S= [tex]\frac{dQ}{T} = \frac{mL}{T}= \frac{2.26*1000000*0.0279}{373} -=169 J/K[/tex]
Here L= 2.26×10⁶
Change in entropy for steam when it rises to a temperature 115 degree Celsius= 388K
S= [tex]\int\limits^{388}_{373} \, \frac{dQ}{T} =\int\limits^{388}_{373} \, \frac{mcdT}{T} =mc\int\limits^{388}_{373} \, \frac{dT}{T} = 0.0279*2010*ln\frac{388}{373} =2.21 J/K[/tex]
Adding all the entropies obtained in the cases we get
Total entropy= 2.62+34+36.5+169+2.21
S= 244J/K
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A 1300kg truck is pulling a 600kg trailer to the right by generating a 420N force. The truck is experiencing a 600N drag and the trailer experiences 340N drag. Neglect any friction impeding the motion and the mass of the cable.
How many forces are acting on the trailer?
How many forces are acting on the truck?
Are the forces on the system balanced?
What is the mass of the system?
What is the magnitude of the net force on the system?
What is the magnitude of the system's acceleration?
Describe the system's speed:
(increasing/decreasing/constant)
The number of forces acting on the trailer is 2.
The number of forces acting on the truck is 2.
The forces on the system are not balanced
The mass of the system is 1,900 kg.
The magnitude of the net force on the system is 520 N.
The magnitude of the system's acceleration is 0.27 m/s².
The speed of the system is decreasing towards to the left.
How many forces are acting on the trailer?The number of forces acting on the trailer is calculated as follows;
force of the truckdrag force of the trailerThe number of forces acting on the truck is calculated as follows;
the drag force of the truckthe force of the truckThe net force of the system is calculated as follows;
F (net) = 420 N - (600 N + 340 N)
F (net) = - 520 N
The mass of the system = 1300 kg + 600 kg = 1,900 kg
The acceleration of the system is calculated as follows;
F (net) = ma
where;
m is the total mass of the systema is the accelerationa = F (net) / m
a = -520 / 1900
a = -0.27 m/s²
Thus, since the acceleration of the system is negative, the speed of the system is decreasing towards to the left.
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Two objects attract each other with a gravitation force of magnitude 3.80 x 10-8 n when separated by a distance of 0.350 m. if the difference in mass of the objects is 7.50 kg, what is the mass for each of these objects?
Two objects attract each other with a gravitation force of 3.80 x 10-8N when separated by a distance of 0.350 m. if the difference in masses is 7.50 kg, the mass of these objects is 2.1kg and 5.4kg
Given the mass of first object = m1
the mass of second object = m2
Gravitational force (Fg) = 3.80 x 10-8N
Objects separated by a distance (d) = 0.350m
Difference in mass of objects (m1-m2) = 7.50kg
Let mass of first object (m1) = 7.50+m2
The formula for gravitational force of attraction between two bodies is:
F = Gm₁m₂/d²
here G is the gravitational force constant and is equal to 6.67 * 10⁻¹¹ Nm²Kg⁻²
3.80 x 10-8N = 6.67 * 10⁻¹¹ Nm²Kg⁻² x (7.50+m2) x m2/( 0.350m)^2
46.55 x 10-10 / 6.67 * 10⁻¹¹ = m2^2+7.50m2
m2^2+7.50m2-69.7 = 0
m2 = 5.4 then m1 = 7.5-5.4 = 2.1
Hence the mass of first object is 2.1kg
The mass of second object = 5.4kg
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All of are following are same process. EXCEPT
A.Condensation
B.Freezing
C.Crystallization
D.Solidification
Condensation, freezing, solidification are same process while crystallization is different from condensation, freezing and solidification.
A. Condensation - It is the process of conversion of water vapours or gas to liquid. For example conversion of steam into water. Condensation occurs at 100 degree celcius.
B. Freezing - It is the phase when liquid gets converted into solid. For example conversion of water into ice. It starts at 0 degree celcius for water.
C. Crystallization - It is the process of forming Crystals. For example evaporation of salt water.
D. Solidification - The process of conversion of liquid into solid. For example formation of snow and solidification of melted candle wax.
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Condensation, freezing and solidification are same process of phase transformation whereas Crystallization is different from others.
What is phase transformation?The physical process of changing a medium's state from one to another is known as a phase transition (or phase change) in the domains of chemistry, thermodynamics, and other related sciences. The phrase is frequently used to describe transitions between the three fundamental states of matter—solid, liquid, and gas—and, in rare instances, plasma.
The physical characteristics of a phase of a thermodynamic system and the states of matter are constant. Certain properties of a given medium change during a phase transition as a result of a change in the environment, such as temperature or pressure. This change can be discontinuous. The phase transition point is identified by the external circumstances in which a change takes place.
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which function can be used to find the velocity at the bottom of the pendulum released from the same angle for any period, p?
The function that can be used to find the velocity at the bottom of the pendulum released from the same angle for any period, p is v = π√(L/g). The correct option is B.
This equation can be used to calculate the velocity at the bottom of a basic pendulum (when it hits its lowest point). In the equation, v stands for velocity, L for pendulum length, and g for gravitational acceleration.
The length of the pendulum and the acceleration brought on by gravity both affect the velocity at the bottom of the pendulum.
We may determine the link between these variables by taking the square root of the ratio L/g, which leads to the right equation v = π√(L/g).
The velocity at the bottom of a pendulum launched from the same angle can be determined using this equation for any period, p.
Thus, the correct option is B.
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Your question seems incomplete, the probable complete question is:
which function can be used to find the velocity at the bottom of the pendulum released from the same angle for any period, p?
A) v = 2π√(L/g)
B) v = π√(L/g)
C) v = (2π√L)/p
D) v = (π√L)/p
Please help me I have no idea
The fraction of kinetic energy which is transferred to the atomic nucleus is 30.3% and the final kinetic energy of the neutron is 2.93*10^-13.
What is kinetic energy?An object's kinetic energy refers to the energy it has as a result of motion. After the job is finished, the object will be traveling at a new, constant speed because energy has indeed been transferred to it.
Briefing:let the mass of neutron =m
Mass of neucleus= M
given: M=11.1m
by conservation of kinetic energy:
fraction of energy that will be transferred to the nucleus = [tex]\frac{4mM}{(M+m)^{2} }[/tex]
= 44.4/146.41
=0.303
let u be the initial velocities of neutron and nucleus
and v be the final velocities of neutron and nucleus
By conservation of linear momentum,
mu+Mu=mv+Mv
v(nucleus)=2*v(neutron)/12.1
the initial kinetic energy of neutron= 4.2*10^-13
so on solving the final kinetic energy of neucleus=1.27*10^-13
so,
final k.e.of neutron=4.2*10^-13 - 1.27*10^-13
= 2.93*10^-13
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the distance to the cosmological horizon depends on (a) the age of the universe. (b) the number of galaxies in the universe. (c) the location of the outer edge of the universe.
The distance to the cosmological horizon depends on:
A. The age of the universe.
Distance is the numerical or every so often qualitative size of how some of the distance aside items or factors are. In physics, the distance may check with the physical duration or an estimation primarily based on other criteria.
The space between the two factors in the physical space is the period of an immediate line among them, that's the shortest feasible course.
It reduces the entire or a part of the arena to a small sheet of paper. At the same time of making a map, cartographers have to pay attention to properly constitute the distance between two locations.
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how does the internal energy of the ice and water mixture change if the temperature does not rise while the ice is melting?
a. It decreases, because you need to use energy to make freezer run; but ice melts spontaneously
b. no enough information to determine
c. it increases, because it takes more energy for water molecules to be disordered than to be ordered
d. it remains the same because both are at the same temperature
Option-d). it remains the same because both are at the same temperature. If the temperature does not increase while the ice melts, the internal energy of the ice and water mixture changes.
A temperature is a unit of hotness or coldness that can be described in terms of a variety of arbitrary scales. It also indicates the direction in which heat energy will naturally flow, i.e., from a hotter body to a colder body (one at a lower temperature). Temperature is not the same as the energy of a thermodynamic system; for instance, an iceberg has a considerably higher temperature than a burning match, but it has a far larger total heat energy than a match. As opposed to extensive qualities like mass or volume, which are reliant on the amount of stuff being studied, the temperature is an intensive attribute, just like pressure or density.
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a lateral chest technique calls for 110 kvp, 10 mas and result in an x-ray intensity of 0.32 mgy. what will be the intensity if the kvp is increased to 125 kvp and the mas remains fixed.
If the kvp is increased to 125 kvp then the intensity becomes 41.32 mR.
We know the relation between kvp and intensity as,
I₁ / I₂ = kvp₁²/ kvp₂²
where, I is intensity in mR
kvp is kilovoltage peak
Given that, kvp₁ = 110 kvp
kvp₂ = 125 kvp
I₁ = 0.32 mgy
To convert mgy to mR, we know 1 mgy = 100 mR
I₁ = 0.32 mgy = 0.32* 100 = 32 mR
Substituting the values in the above equation, we have
32 / x = 110²/ 125²
32 * 125² = x * 110²
x = (32 * 125²) / 110² = 41.32 mR
Thus, the new intensity becomes 41.32 mR.
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a gas is enclosed in a cylinder fitted with a light frictionless piston and maintained at atmospheric pressure. when 254 kcal of heat is added to the gas, the volume is observed to increase slowly from 12.0 m3 to 16.2 m3 . Calculate the work done by the gas and the change in internal energy of the gas.
Upon absorbing 254 kcal of heat, a gas contained in a cylinder kept at atmospheric pressure sees a rise in volume from 12.0 m3 to 16.2 m3. The work performed by the gas is -1.01 × 10⁵ Kcal, and the internal energy has changed by -1.01 × 10⁵ Kcal
The volume of a gas contained in a cylinder at atmospheric pressure (P = 101325 Pa) increases from 12.0 m³ to 16.2 m³.
The following phrase can be used to determine the work (w) that the gas has performed.
w = -P × ΔV = -101,325 Pa × (16.2 m² - 12.0 m²) = -4.26 × 10⁵ J × 1kcal/4181J = -1.02 × 10⁵ Kcal
The gas receives 254 kcal of heat, making q equal to 254 kcal. The following phrase can be used to determine how the internal energy (E) has changed.
ΔE = q + w = 254 Kcal + (-1.02 × 10⁵ Kcal) = -1.01 × 10⁵ Kcal
When a gas is contained in a cylinder that is kept at atmospheric pressure, it absorbs 254 kcal of heat, increasing its volume from 12.0 m³ to 16.2 m³. The gas expends -1.02 × 10⁵ kcal of effort, and the internal energy changes by -1.01 × 10⁵ kcal.
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What minimum work is required to get the cylinder rolling without slipping at a rotational speed of 20 s^−1?
The minimum work required to get the cylinder rolling without slipping at a rotational speed of 20 s-1 is 1.04 kg-m2/s2.
The torque required to rotate a solid cylinder without slipping is given by:
τ = Iα
Where I is the moment of inertia of the cylinder, and α is its angular acceleration.
The moment of inertia of a solid cylinder is given by:
I = mr2
Where m is the mass of the cylinder, and r is its radius.
Plugging in the values, we get:
I = (52 kg)(0.1 m)2 = 0.052 kg-m2
The angular acceleration is given by:
α = ω/t
Where ω is the angular velocity and t is the time taken to reach the desired angular velocity.
Plugging in the values, we get:
α = (20 s-1)/t
Since we do not know the time taken to reach the desired angular velocity, we will assume that it is 1 second.
Plugging in the values, we get:
α = (20 s-1)/1 s = 20 rad/s2
Now, we can calculate the torque required to rotate the cylinder without slipping:
τ = Iα = (0.052 kg-m2)(20 rad/s2) = 1.04 kg-m2/s2
Finally, we can calculate the minimum work required to get the cylinder rolling without slipping:
W = τθ
Where θ is the angular displacement. Since we do not know the angular displacement, we will assume it to be 1 radian.
Plugging in the values, we get:
W = (1.04 kg-m2/s2)(1 rad) = 1.04 kg-m2/s2
Hence, the minimum work required to get the cylinder rolling without slipping at a rotational speed of 20 s-1 is 1.04 kg-m2/s2.'
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Complete question:
A solid 52-kg cylinder has a radius of 0.10 m.What minimum work is required to get the cylinder rolling without slipping at a rotational speed of 20 s^−1?
1) A 2.0 kg steel block is placed on a steel table as shown below. Force F is applied to the block to the right.
a) Determine the normal force acting on the block.
Answer:
if g=-10m/s² then the normal force is 20N
if g=-9.8m/s² then the normal force is 19.6N
Explanation:
The force due to gravity (or weight) is mass times the acceleration due to gravity.
I am going to define up as positive so gravity will be negative.
On earth the acceleration due to gravity is -9.8m/s²
We sometimes round this to -10m/s² to make the math easier.
I will do it both ways.
so we have a mass of 2kg
2kg(-10m/s²)
so the force due to gravity is -20N
because the block is not falling through the table, the table must be pushing back with the same amount of force, but in the opposite direction so we change the sign.
using -10m/s² for g, we get a normal force of 20N (Newtons)
if we use -9.8m/s², we have 2kg(-9.8m/s²)
and a force due to gravity of -19.6N
and when we flip the sign we get a normal force of 19.6N
Hope this helps!
which of the following is fundamentally different from the others? a. sound waves b. x-rays c. gamma rays d. green light waves e. radio waves
Sound waves are fundamentally from the other waves.
A sound wave is a pattern of disruption brought on by the movement of energy moving through a medium as it propagates away from the source of the sound (such as air, water, or any other liquid or solid matter).
Sound waves are fundamentally from the other waves.A sound wave is a configuration of disruption brought on by an energy flow moving through a medium.Unlike electromagnetic waves, which do not require any medium for propagation, the medium can be air, water, liquid, or any other solid material.Electromagnetic waves include X-rays, radio waves, and light waves.Electric and magnetic waves combine to form electromagnetic waves.Know more about Sound waves at:
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a 0.450 kg mass suspended from a spring oscillates with a period of 1.50 s. how much mass must be added to the object to change the period to 2.00 s?
The m" = 0.389 Kg mass must be added to the object to change the period to 2.00 s
By applying the time period formula, it is possible to calculate that 0.389 kg of mass must be added to the item in order to shift the period to 2.00 s.
A mass hung from a spring and weighing 0.500 kg oscillates with a 1.50 s period.
where K is the spring constant and m is the mass.
where K is the spring constant, and m' is the final total mass following the addition. Subtract equation (1) from equation (2).
Now change the above statement with the known terms.
To find the value of m', simplify the statement above.
m' = 0.889 Kg
Now, we can calculate the mass that must be added to the object to make the period 2.00 s:
m" = 0.889 - 0.500
m" = 0.389 Kg
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in amps. a constant voltage of 77 volts is put across a resistance that is increasing at a rate of 0.20.2 ohms per second when the resistance is 55 ohms. at what rate is the current changing?
A constant voltage of 77 volts is put across a resistance that is increasing at a rate of 0.202 ohms per second when the resistance is 55 ohms. The current is changing at a rate of 0.0051amps per sec
Given voltage (V) = 77v
Resistance (R) = 55ohms
The relation among voltage (V), resistance (R) and current (I) is given as
I =V/R
The increasing rate of resistance is = dR/dt = 0.2ohms per second
By derivating the current to get rate of change in current
dI/dt = Vxd/dt(1/R) [ Because V is a constant ]
dI/dt = V x d/dt(R −1)
dI/dt = V(-1/R^2 x dR/dt) = 77x (-1/55x55) x 0.202 = -0.005amp per second
Hence the current is changing at a rate of 0.0051amps per sec
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when is the angle at which a ray of light strikes glass not the same as the angle it exits?
Answer:
Explanation:
Assuming the light travels through air, hits the glass and is then reflected back into air (in other words, the medium is the same), the only reason the angle of incidence would NOT equal the angle of reflection is if the surface of the glass is not smooth (is rough, scratched, etc.)
a car increases its speed, changing its kinetic energy from 60,000 j to 80,000 j. assuming no friction, how much work is done by the car’s engine to cause this change?
The work required by the car's engine to raise its speed and change its kinetic energy from 60,000 J to 80,000 J is 2000 J.
Force multiplied by distance equals work done.
Joules are the unit used to measure work.
The difference between the car's starting and final kinetic energies is the result of the engine's work, which increased the vehicle's speed and increased its kinetic energy from 60,000 j to 80,000 j.
Final kinetic energy minus beginning kinetic energy is the formula for the work the car engine performs.
The car's engine produces work at a rate of 80000 J - 60000 J.
The car's engine generates 20,000 J worth of work.
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in a cathode ray tube, electrons flow from the negatively charged cathode to the positively charged anode. cathode ray tubes may be small and compact, but they typically must be plugged in to function. the flow of electrons within this tube is:
They are little, but they usually need to be charged in to work. Within this tube, the flow of electrons occurs on its own.
Is being impulsive a good thing?The advantages of spontaneity. Instead of racing from one planned process to the next, it can be highly healthy for our mental health to be open to unplanned happenings and give our minds space to think.
Is spontaneity a quality of the personality?People with spontaneous personalities tend to be somewhat unpredictable at work and like to act or say whatever feels right at the time. A stand-up comedian is a great example of someone who always seems to be able to take the punches and handle whatever come their way.
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A grocery shopper tosses a(n) 8.5 kg bag of
rice into a stationary 17.4 kg grocery cart.
The bag hits the cart with a horizontal speed
of 5.5 m/s toward the front of the cart.
What is the final speed of the cart and bag?
Answer in units of m/s.
Answer:
3.1 m/sec
Explanation:
The contained in the flying bag of rice is applied to the stationary cart. Lets calculate the kinetic energy of the flying bag of rice. Kinetic energy (KE) is given by KE = (1/2)mv^2, where m is the mass and v is the velocity.
[Note: a kg*m^2/s^2 is 1 Joule]
KE(rice bag) = (1/2)(8.5kg)(5.5m/s)^2
KE(bag) = 129 Joules
When the bag hits the shopping cart, some of the energy tis transferred to the cart. We aill assume no energy in lost in the collision (conservation of energy). The kinetic energy is now contained in a body with a total mass of 25.9 kg (rice bag plus cart).
Use the kinetic energy expression again, using the same KE from the rice bag, but with a new mass.
KE = (1/2)mv^2
129 Joules = (1/2)(26.9 kg)v^2
129 kg*m^2/s^2 = (1/2)(26.9 kg)v^2
v^2 = (129 kg*m^2/s^2)/(12.95 kg)
v^2 = 9.96 m^2/s^2
v = 3.12 m/s (3.1 m/2 with 2 sig figs)
3.12 m/s will be the velocity of the grocery cart and rice bag. [That's 6.7 miles/hr, for the non-metric inclined]