When a golf club hits a 0.0459 kg ball at rest, it exerts a 2380 N force for 0.00100 s. What is the speed of the ball afterwards? (Unit = m/s)

When A Golf Club Hits A 0.0459 Kg Ball At Rest, It Exerts A 2380 N Force For 0.00100 S. What Is The Speed

Answers

Answer 1

Answer:

51.85m/s

Explanation:

Given parameters:

Mass of ball  = 0.0459kg

Force  = 2380N

Time taken  = 0.001s

Unknown:

Speed of the ball afterwards  = ?

Solution:

To solve this problem, we use Newton's second law of motion:

   F = m x [tex]\frac{v - u}{t}[/tex]  

F is the force

m is the mass

v is the final velocity

u is the initial velocity

t is the time taken

        2380  = 0.0459 x [tex]\frac{v- 0}{0.001}[/tex]  

        0.0459v  = 2.38

                   v = 51.85m/s

Answer 2

Answer:

2.38

Explanation:

F = dp/dt  --> dp = F*dt ---> p = F*t if F is constant over time so

p = 2380N* 0.001 s = 2.38 kg-m/s


Related Questions

Nistu is cooking rice in a pot. When she leaves the pot on the stove for a while, the temperature of the rice increases. What happens to the molecules of the rice when the temperature of the rice increases?

Answers

They start heating up and vibrating vigorously

Answer:

Nistu is cooking rice in a pot. When she leaves the pot on the stove for a while, the temperature of the rice increases. What happens to the molecules of the rice when the temperature of the rice increases? The energy of the molecules in the rice increases.

Explanation:

(b) The cabin and passengers have a total mass of 800 kg. The vertical distance between
B and C is 50 m.
Calculate the increase of gravitational potential energy of the cabin and passengers when they
move from B to C.
energy =

Answers

Answer:

392 kJ

Explanation:

Given that,

The total mass of the cabin and the passengers = 800 kg

The vertical distance between  B and C is 50 m.

We need to find the increase of gravitational potential energy of the cabin and passengers when they  move from B to C. It can be given by the relation as follows :

[tex]E=mgh\\\\E=800\times 9.8\times 50\\\\E=392000\ J\\\\\text{or}\\\\E=392\ kJ[/tex]

So, the increase in gravitational potential energy is 392 kJ.

I’ll give brainliest and 10 points

Answers

Answer:

what's these its D okkkk

PLEASE SOMEONE HELP!!! ANSWER IF YOU KNOW PLEASE!!! LOTS OF POINTS!!!

Answers

Answer:

i think that magnet can cause kinetic because

it is made of iron or steel that attract other magnetic things

#CarryOnLearning

What is the downward pull on an object due to gravity?
mass
weight
acceleration
velocity

Answers

Answer:

Weight

Explanation:

WEIGHT - downward pull to the center of earth due to gravity

ACCELERATION - the rate of change of velocity

VELOCITY - rate of change if displacement in time

The major difference between the mass and weight is that mass of an object can never be zero but weight can be zero. The downward pull on an object due to gravity is called the weight. The correct option is B.

What is weight?

The measure of the force of gravity acting on a body is defined as the weight. Actually weight is a force and its SI unit is Newton (N). The weight of an object depends on the mass and acceleration due to gravity.

The formula used to calculate the weight is:

w = mg

m = Mass of an object

g = Acceleration due to gravity

Weight is found to be a vector quantity. Because it has both magnitude and direction. It is directed towards the center of the earth or other gravity well.

When objects fall to the ground, it is the gravity which accelerates them. So the force of gravity which pulls the object downward is called the weight.

Thus the correct option is B.

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A horizontal net force F is exerted on an object at rest. The object starts at x= 0 m and has a speed of 4.0 m/s after moving 6.0 m along a horizontal frictionless surface. The net force F as a function of the object's position x is shown below.

what is the mass of the object?

Answers

A horizontal net force f is exerted on a 4.0 kg object at rest. The object starts at x = 0 m and travels 6.0 m along a horizontal frictionless surface. The net force F as a function of the object's position x is shown below.

What is the velocity of the object?

Answer: 6.7 m/s

A car accelerates northwest from 35 to 62 m/s in a time of 14 seconds. What is the acceleration?
a = Vf - Vi / t
A) 27 m/s2 northwest
B) 1.9 m/s2 northwest
C) -1.9 m/s2 northwest
D) 61 m/s

Answers

Answer:

B) 1.9 m/s2 northwest

Explanation:

Given parameters:

Initial velocity  = vi  = 35m/s

Final velocity  = vf  = 62m/s

Time  = 14s

Unknown:

Acceleration  = ?

Solution:

Acceleration is the rate of change of velocity with time.

   Acceleration  = [tex]\frac{Vf - Vi}{t}[/tex]  

Vf is the final velocity

Vi is the initial velocity

t is the time taken

   Acceleration  = [tex]\frac{62 - 35}{14}[/tex]   = 1.93m/s² northwest

The variable plotted on the horizontal or x-axis is called the

Answers

Answer:

Independent Variable

Explanation:

The variables that are plotted on X-axis, the horizontal line of the graph are termed as independent variables. The variables plotted on Y-axis which is vertical side of the graph are dependent variables.

What is the definition of endothermic and exothermic?


pls help on a timer will give brainlist

Answers

Answer:

An exothermic process releases heat, causing the temperature of the immediate surroundings to rise. While an endothermic process absorbs heat and cools the surroundings

Explanation:

Answer:

Basically, endothermic feels cooler to touch than exothermic.

Explanation:

Endothermic reactions are just reactions that emit energy (in form of heat) to its surroundings. Exothermic ones, on the other hand, draw energy from its surroundings to occur.

Always think - "Endothermic is cool. Exothermic is not cool."

what is the velocity at 11 seconds

Answers

Answer:

should be A

Explanation:

there isn't a 3, so it must be his deceleration, which would be 5-3=2

Which of the following employees derives their income from a fee for the items sold?
a commission
b. piece rate
c.salaried
d. tip

Please select the best answer from the choices provided

Answers

Answer:

i think its b because i learned this before if im wrong sorry it could be a or d

Explanation:

A 2.5 –g bullet traveling at 350 m/s hits a tree and slows uniformly to a stop while penetrating a distance of 12 cm into the tree’s trunk. What force was exerted on the bullet in bringing it to rest?

Answers

Answer:

A 2.5 g bullet traveling at 350 m/s hits a tree and slows uniformly to a stop while penetrating a distance of 12 cm into the tree's trunk. What is the initial kinetic energy of the bullet? 153.125 J Correct: Your answer is correct.Jan 8, 2020

Explanation:

Why are force fields necessary to describe electric force? 0 A. Electric force acts at a distance. O B. Electric force can only attract objects. C. Electric force is a form of gravity. D. Electric force attracts two poles.​

Answers

Answer:

A. Electric force acts at a distance.

Explanation:

"Electric force," just like gravitational force is a "non-contact force." This means that even at a distance, two objects with no physical contact will create movement with the help of electric force. This leads to the concept of "force fields or field force" that explains why a charge object alters the region surrounding it. Once an object enters the region, it immediately experiences its force. An example of this is holding out one's hand near a "Van de Graaff generator." The electric force compels the hair strands to stand up.

What happens to objects in space when they no longer have force accelerating them?

Answers

Answer:An object thrown in space will move according to the forces on it in space. For instance, if you threw it in space near the Earth, it would accelerate due to the Earth's gravity. ... If there are no forces on the object, then it will move at a constant speed and direction.

Explanation:

3.5 x 10^-3 as a regular number (convert from scientific notation to a real number)

Answers

Answer:   0.0035

============================================

Explanation:

The exponent is -3, so we move the decimal point 3 spots to the left to go from 3.5 to 0.0035

If the exponent was positive, then we would move the decimal point to the right that amount of spaces.

FILL IN THE BLANKS here on earth, the pull of gravity on a mass of 1 kg is ......... newtons​

Answers

Answer:

9.8 Newton

Explanation:

At average gravity on earth (conventionally, g=9.80665m/s2),

a kilogram mass exerts a force of about 9.8 newton

I hope this answer helps you

Make a prediction that answers the question in the purpose:

“How does time affect the temperature of water?”

(Ex-“If we use a ramp, then the ball will roll faster down the ramp because gravity has more time to do work on the ball.”)



Im not good at these, please help quickly.

Answers

As heat always flows from a higher temperature to a lower temperature, this transfer can go both ways .When the air is cold, warm water will transfer energy to the air and cool off. ... If the air is hot, cold water will receive the energy and warm up.

The electromagnetic spectrum has waves of varying levels of energy. Which
wave has the least energy?

Answers

Answer:

Radio waves, I believe

Explanation:

Answer:

radio yes yup yup yup yup

What is the magnetosphere, and how does it help the earth?
can someone plss help me???​

Answers

What is the magnetosphere, and how does it help the earth?

The magnetosphere shields our home planet from solar and cosmic particle radiation, as well as erosion of the atmosphere by the solar wind - the constant flow of charged particles streaming off the sun. ... It is generated by the convective motion of charged, molten iron, far below the surface in Earth's outer core.

Explanation:

A rescue pilot drops a survival kit while her plane is flying at an ultitude of 2500m with a forward velocity of 95m. If the air friction is disregarded, how far advance of the starving explorer’s drop zone should she release the package?

Answers

Answer:

Approximately [tex]2.1\; \rm km[/tex], assuming that [tex]g = -9.8\; \rm m \cdot s^{-2}[/tex].

Explanation:

Let [tex]t[/tex] denote the time required for the package to reach the ground. Let [tex]h(\text{initial})[/tex] and [tex]h(\text{final})[/tex] denote the initial and final height of this package.

[tex]\displaystyle h(\text{final}) = \frac{1}{2}\, g\, t^2 + h(\text{initial})[/tex].

For this package:

Initial height: [tex]h(\text{initial}) = 2500\; \rm m[/tex].Final height: [tex]h(\text{final}) = 0\; \rm m[/tex] (the package would be on the ground.)

Solve for [tex]t[/tex], the time required for the package to reach the ground after being released.

[tex]\displaystyle t^{2} = \frac{2\, (h(\text{final}) - h(\text{initial}))}{g}[/tex].

[tex]\begin{aligned} t &= \sqrt{\frac{2\, (h(\text{final}) - h(\text{initial}))}{g} \\ &\approx \sqrt{\frac{2\times (0\; \rm m - 2500\; \rm m)}{(-9.8\; \rm m \cdot s^{-2})}} \approx 22.588\; \rm s\end{aligned}[/tex].

Assume that the air resistance on this package is negligible. The horizontal ("forward") velocity of this package would be constant (supposedly at [tex]95\; \rm m \cdot s^{-1}[/tex].) From calculations above, the package would travel forward at that speed for about [tex]22.588\; \rm s[/tex]. That corresponds to approximately:[tex]95\; \rm m \cdot s^{-1} \times 22.588\; \rm s \approx 2.1 \times 10^{3}\; \rm m = 2.1\; \rm km[/tex].

Hence, the package would land approximately [tex]2.1\; \rm km[/tex] in front of where the plane released the package.

Billy is driving a bumper car for 5 minutes. In this time, Billy crashes into three other cars.

The first car is carrying another small child, the second is carrying a large adult, and the third is empty. Each car is sitting still when Billy hits it at full speed. Place the crashes in order of how much force Billy feels, from smallest to largest.

empty car
large adult
small child
<

Answers

Answer:Its empty car, small child, and then adult.

Explanation:

i took it

Answer:

Its empty car, small child, and then adult.

1. A heat engine has a cold reservoir that is 285 degrees Kelvin which accepts 370 J of heat, and a hot reservoir that is 371 degrees Kelvin which gives off 425 J of heat. Calculate the maximum and actual efficiencies of this engine.


2. A system that has a total change in entropy of 675 J/K and has received 243 J of heat energy will be at what temperature?


3. Assume that the above system maintains a constant pressure, and increases in volume by 2.5 m 3 while doing this work. What is the pressure of the system?

Answers

I can't help with this one.

The maximum efficiency of the heat engine is 23%.

The actual efficiency of the heat engine is 13%.

The temperature of the system is 273.36 ⁰C.

The pressure of the system is 607.5 Pa.

The given parameters:

Cold reservoir temperature, Tc = 285 KHeat, qc = 370 JHot reservoir temperature, Th = 371 KHeat of the hot reservoir, qh = 425 J

The maximum efficiency of the heat engine is calculated as follows;

[tex]\eta = 1- \frac{T_c}{T_h} \\\\ \eta = 1 - \frac{285}{371} \\\\ \eta = 0.23\\\\ \eta = 23 \ \%[/tex]

The actual efficiency of the heat engine is calculated as follows;

[tex]\eta = 1 - \frac{q_c}{q_h} \\\\ \eta = 1 - \frac{370}{425} \\\\ \eta = 0.13\\\\ \eta = 13\ \%[/tex]

The temperature of the system is calculated as follows;

[tex]\Delta S = \frac{\Delta H}{T} \\\\ T = \frac{\Delta H}{\Delta S}\\\\ T = \frac{243}{675} \\\\ T = 0.36 \ K\\\\ T = 273.36 \ ^0C[/tex]

The pressure of the system is calculated as follows;

[tex]W = P \Delta V\\\\ P = \frac{W}{\Delta V} \\\\ P = \frac{243}{2.5} \\\\ P = 607.5 \ Pa[/tex]

Learn more about efficiency of heat engine here: https://brainly.com/question/10955336

a sprinter starts from rest and accelerates at a rate of 0.16 ms ^-2 over a distance of 50.0 meters . How fast is the athlete traveling at the end of the 50.0 meters?

Answers

Answer:

Final velocity v = 4 m/s

Explanation:

Given:

Initial velocity u = 0 m/s

Acceleration a = 0.16 m/s²

Distance s = 50 m

Find:

Final velocity v

Computation:

Using; v² = u² + 2as

v² = (0)² + 2(0.16)(50)

v² = 16 m/s

v = 4 m/s

Final velocity v = 4 m/s

A badminton player hits a 0.010 kg shuttlecock that is initially at rest in his hand. The net force on the shuitlecock over time is shown below. What is the shuttlecock's speed at t = 30ms ?

Answers

Answer: 10 m/s

Explanation: I got the answer wrong, then it showed it to me

From where does the penny that is launched into the air get its energy

Answers

When the elastic potential energy in the ruler was released it gave energy to the coin thus launching into the air. The coin got its kinetic energy from the ruler

please please help me please help me please help me please help me please help me please help me please help me please help me please help me​

Answers

Explanation:

cookies

HOPE IT HELPS U....

List these things in order of size, starting with the smallest thing:
Universe, Earth, Galaxy, Moon, Solar System, Sun

Answers

Moon, earth, sun solar system, galaxy, universe

Calculate the momentum of a boat with a mass of 95kg moving at 2m/Ss

Answers

Answer:

190 kg m/s

Explanation:

Momentum = Velocity × Mass

→ Substitute in values

2 × 95 = 190 kg m/s

The momentum of the boat of mass 95 Kg moving at 2 m/s will be 190 Kg m/s.

What is Momentum?

Momentum is defined as the product of mass of velocity. Momentum is a vector quantity. Mathematically, we can write momentum as -

p = mv

It is also the measure of the impact force imparted by any moving object, when it comes in contact with some other body.

Given is a boat with a mass of 95 Kg moving at 2 m/s.

Mass [m] = 95 Kg

Velocity [v] = 2m/s

We can write the momentum as -

p = mv

Substituting values, we get -

Momentum [p] = 95 x 2 = 190 Kg m/s

p = 190 Kg m/s

Therefore, the momentum of the boat of mass 95 Kg moving at 2 m/s will be 190 Kg m/s.

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What are 3 main ways to improve the Cardiovascular system???
Worth 100 points

Answers

I hope you get your answer

The bottom of a ladder must be placed 4 feet from a wall. The ladder is 12 feet long. How far above the ground does the ladder touch the wall? Estimate your answer to the nearest tenth.

Answers

Answer:

Height of wall (Perpendicular) = 11.31 ft (Approx)

Explanation:

Given:

Base Distance (Base) = 4 feet

Height of ladder (Hypotenuse) = 12 feet

Find:

Height of wall (Perpendicular)

Computation:

Perpendicular = √Hypotenuse² - Base²

Height of wall (Perpendicular) = √12² - 4²

Height of wall (Perpendicular) = √144 - 16

Height of wall (Perpendicular) = √128

Height of wall (Perpendicular) = 11.31 ft (Approx)

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